What would be the acceleration of gravity (in m/s2) at the surface of a world with nine times Earth's mass and three times its radius?

Multimeter conducts like a big resistor. Since current will be very low due to the very high resistance, the circuit's overall current won't be impacted in the slightest. It will transmit the appropriate voltage

A passive electrical device known as a resistor adds resistance to the flow of electric current. They can be discovered in virtually all electrical networks and electronic circuits. One ampere of current (A) and a one volt (V) drop across a resistor's terminals produce an ohm, which is the resistance that results. The voltage at the terminal ends determines the current in a direct proportion. Ohm's law demonstrates how to calculate this ratio. Multiple applications exist for resistors. Among some examples are voltage division, heat generation, matching and loading circuits, current limiters for electric current, gain control, and time constant setting. With resistance values spanning a range of more than nine orders of magnitude, they are readily available on the market. Units of resister is omhs.In the International System of Units, the ohms serves as the reference unit for electrical resistance.

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The acceleration of each block is 1.225m/s^2

The string exerts 2.315N on 210g block, and 2.976N on 270g block

It will take 1.28s for each block to traverse

Part a

Acceleration, a of the block:

m1=270g

m2=210g

g=9.8

Acceleration=(m1-m2)*g/(m1+m2)

                    =(270-210)*9.8/(270+210)

                    =1.225m/s^2

Part b

Force that the string exerts on each block:

Force, T1 on smaller block:

T1=m2(g+a), where m2=0.21kg, g=9.8, and a=1.225m/s^2

T1=0.21(9.8+1.225)

T1=2.315N

Force exerted on smaller block=2.315N

Force, T2 on larger block

Here, m1=0.27kg, g=9.8, and a=1.225m/s^2

T2=0.27(9.8+1.225)

    =2.976N

Force exerted on larger block=2.976N

Part c

How long it will take each block to traverse 1.0m

h=1.0m

a=1.225m/s^2

[tex]t=\sqrt{\frac{2h}{a} }[/tex]

[tex]t=\sqrt{\frac{2*1}{1.225} }[/tex]

t=1.28s

The question was incomplete, complete question is given below:

A person holds a 210-g block that is connected to a 270-g block by a string going over a light pulley with no friction in the bearing (an Atwood machine). After the person releases the 210-g block, it starts moving upward and the heavier block descends. Part A: What is the acceleration of each block? Part B: What is the force that the string exerts on each block? Part C: How long will it take each block to traverse 1.0 m?

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ANSWER:

1. C. Wave X and Wave Y share the same speed.

2. D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

STEP-BY-STEP EXPLANATION:

The amplitude of a wave does not affect the speed at which the wave travels. Both wave A and wave B travel at the same speed. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.

Therefore, in the first art the correct answer is C. Wave X and Wave Y share the same speed.

If the medium is uniform (does not change), the speed of the wave will be constant.

Therefore, the correct answer is: D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.

2. The box will not move if a 50 N force us applied to the left.

For  Balanced, B or Unbalanced forces, U the correct option are:

Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.

Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.

Considering the boxes:

1. Net force = 50 N

Forces to the left = 25 N + x

Forces to the right = 50 N

Net force = Force to the left + force to the right

50 N = 25 N + x - 50

x = 75 N

2. Net force = 0 N

Forces to the left = 75 N + x

Forces to the right = 125 N

Net force = Force to the left + force to the right

0 N = 75 N + x -125

x = 50 N

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Given:

Speed of the toy car max speed = 15 m/s

Time taken before the battery dies = 30 minutes.

Let's find how far the car went.

To find the distance the car travelled, aply the formula:

Where:

Speed = 15 m/s

time = 30 min

Convert the speed to meters per hour

Convert the time to hour.

Where:

1 hour = 60 mins = 3600 seconds

Thus, we have:

• Speed in m/h:

• Time in hour:

To find the distance, we have:

Therefore, the toy car travelled 27000 meters.

ANSWER:

27000 meters.

Here, a length of 20 go copperware is provided for us. Having a right-handed tiny dilates diameter of.8118 millimeters, it is shaped into a circular loop with a 17 centimeter radius.

Assume that the capital r is 17 centimeters, or.107 met, and that the magnetic field is growing from 0 to so that 1 is equal to 0 and b 2 is equal to 11 milli tesla, or 10 to the power of 11 minus 3 tesla, in time of.24 seconds. Okay, so you need to figure out the average power lost during this procedure. In addition, copper has a resistivity of 1.72 times 10 to the minus 8 right meter. Therefore, in this case, we first determine the induced emf in the loop.

In other words, emf will equal the change in magnetic flux, which is fi 2 minus pi 1 by t, right, and fight will equal b 2 a minus b 1 an area over here, b. 2 is we have got 11 times of 10 to the power of minus 3 times the area of the loop will be, so let me just show you here area will be equal to pi r square, which is equal to pi times of 0.17 square. We can therefore multiply it here by 10 to the power of.17 square right b, where 1 is 0.

As a result, we can plug it in here by times 10 to the power of.17 square right b. 1 is 0. Thus, the other period is not taken into account, and the time is.24 seconds, correct voltages. So let me assess how much you're getting and see. It is 4.16 x 10 to the minus 3 volt power to the right. The induced m f is therefore this.

This will be squared right in meters, and this is where home is. In order to determine the electrical power dissipated, which is equal to v squared by r right, the resistance, and v, let me evaluate and see how much we're getting. This is 0.035 right now. We already have a resistance of 0.035 radius and 4.16 times 10 to the power of -3 entire squared, and this will be in what way. The amount you receive is approximately 4.9 times 10 to the power of negative 4.

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Alyssa mixed 12 mL of a salt solution with 9mL of a 39% salt solution, to make a 56% salt solution. The percent salt concentration of the first solution will be 78.08 %.

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.)

let x = percentage of 12ml of solution

12x + 0.39 (9) = 0.56 (12 + 11)

12x + 3.51 = 12.88

x = 0.7808

The percent salt concentration of the first solution will be 78.08 %

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Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

(a) The impulse-momentum theorem (Eq. 9-31) results in (a) when m=0.30 kg.  (b) Applying Eq. The force exerted by the wall on the ball is 935.

J /Δt=(1.8/0.010) j ^ =(180N) j ^.

According to Newton's third law, the ball's force on the wall is (180N) j, meaning that it is 180N in magnitude and is directed directly at the wall.

Let the momentum ball go.

m = 0.37 k g

contacts the vertical wall at an incidence angle while traveling at v mph.

= 22 with the positive x-axis direction and it bounces back at the same speed and angle.

The velocity of hitting the wall can be expressed vectorially as v s = v cos I + v sin j.

Then the rebounce's velocity will be given by v b = v cos I + v sin j.

Here, the vertical component is unchanged, the horizontal component is reversed, and the effect of gravity is not taken into account.

The mass ball's impulse or change in momentum

m = 370 g = 0.37 k g

is

= m (=> v b − => v s) = − 2 m v cos θ ˆ i= − 2 × 0.37 × 3.9 × cos 22 ˆ i kgm/s

= − 2.675 ˆ I kgm/s

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Explanation:

Force = mass x accelaration

Force = 2230 x 14

Force = 31,220 N or 31.22 kN

31.64 m/s with velocity fast is it moving 1.8 s after it was thrown vertically downwards at a speed of 14 m/s from the top of a tall building.

V= u + gt= 14 + 9.8×1.8 = 14 + 17.64 = 31.64 m/s

When a body is travelling in a straight line, its estimated "rate of change of displacement in relation to time" is referred to as its velocity.

Speed is a scalar number since it lacks a direction and the value it receives from the distance-to-time ratio simply indicates its magnitude. It doesn't provide any guidance information. Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.

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If the spring is constant at 68.0 n/cm, the energy he has transferred to the spring is 2028 N.

Hooke's law, which asserts that, must be applied,

F = k x

The spring constant in N/cm is k.

The extension in centimeters is x.

By incorporating x = 35.7 cm and k = 56.8 N / c m, we obtain the force, which is equivalent to

F = 56.8 N/cm 35.7 cm = 2027.76 N

2028 N, rounded to the next whole value.

The spring's shape, which was created by coiling a metal wire into tight loops pressed up against one another, gives it elastic properties. When an external force is applied to a spring, a restoring force always acts in the direction of the spring's equilibrium state. The spring stores mechanical energy.

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Answer:

Explanation:

here you need to draw a distance time graph for the car
like put 1-5 which indicates hours on x axis and
you need to covert the km into m by using the unitary method as we know 1km-1000m
then 40km=40000m and 20km=20000km like this 10-50 you need to convert in metres, then write them in y axis.

then you draw a graph  for motion with constant speed in  that distance time graph and plot them

then you will get your answer

We can see that the collision of the objects is an elastic collision.

Let us note that a collision could be elastic or in elastic. We can say that a Collison could be judged or said or designated to be an elastic collision when the kinetic energy and the momentum of the system that is undergoing the collision is conserved.

Let us recall that the principle of the conservation of the linear momentum states that the momentum before collision is equal to the total momentum after Collison. In other words, the momentum of the system does not change. Hence, the momentum of one of the objects must be transferred to the other object when they collide in a closed system

With that said, we can see that the two bocks move in opposite directions thus it is an elastic collision as we can see from the description in this answer.

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Answer:

Speed 5 m/s , velocity 0 m/s

Explanation:

s= d/t = 25/5 = 5 m/s

υ= Δx/Δt = 0/5 = 0 m/s

Current passing through his body is 1.67 A. power dissipated in his body is 27.8 kW and internal resistance is 20.0 MΩ .Low enough voltage levels allow the power supply to work with low resistance devices.

Voltage is the pressure from the power source of an electrical circuit that drives charged electrons (current) through a conducting loop, allowing them to perform tasks like lighting a lamp.

Briefly stated, voltage equals pressure and is measured in volts (V). The phrase honours Italian physicist Alessandro Volta (1745–1827), who developed the voltaic pile, the predecessor of the modern household battery. Voltage was first referred to as electromotive force in the early days of electricity (emf). Voltage is therefore represented by the letter E in equations like Ohm's Law, and the terms "voltage" and "potential difference" are sometimes used interchangeably. A better way to define potential difference is as the difference in potential energy between two places in a circuit. A simple indicator is the potential difference or voltage.

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The net power output for this heat engine will be 50 MW. The thermal efficiency for this heat engine will be 0.55 percent. The temperature of the furnace will be 15°c.

A heat engine is a device that generates power by rejecting some of the heat it receives from a source at high temperatures to a sink at low temperatures, such as the atmosphere. A Carnot engine is a reversible heat engine that operates between the two temperatures with optimal efficiency.

The heat engine's efficiency is always lower than the Carnot engine's. There are presented the heat transfer rates to and from a heat engine. Both the thermal efficiency and the net power output must be determined.

There is very little heat loss through the pipes and other parts.

This heat engine uses the river as the low temperature reservoir and the furnace as the high temperature reservoir. Keep in mind that the heat engine uses 37.5% of the heat it receives to produce work.

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The component of the forces and the frictional force of the bodies are as follows

6. The frictional force is approximately 37°

7. The frictional force is 0, while the force holding the mass is approximately 49.05 N

8. Please find attached the drawing showing the three forces acting on the block and their direction.

The forces are; [tex]F_{fr}[/tex] = [tex]F_{W}[/tex] ≈ 33.55 N, [tex]F_{N}[/tex] ≈ 92.18 N

9. The steepest angle of the slope is approximately 37.6°

Frictional force is the force that is generated and serves to prevent the relative motion of two bodies in contact.

6. The angle made by the rope with the horizontal = 37°

The tension in the rope = 10 N

Velocity of the crate = Constant

Given that the velocity of the crate is constant:

The frictional force = The horizontal component of the tension in the rope

Which gives: Frictional force = 10 N × cos(37°) ≈ 7.99 N

7. The frictional force is given by the formula: [tex]F_{fr} = m\cdot g \cdot cos(\theta)\cdot \mu[/tex]

Given that the plane is frictionless, we have: μ = 0

Therefore: Frictional force, [tex]F_{fr} = m\cdot g \cdot cos(\theta)\times 0 = 0[/tex]

The force holding the mass, F = m·g·sin(θ)

Where:

θ = 30.0°
g = The acceleration due to gravity ≈ 9.81 m/s²

∴ F ≈ 10.0 kg × 9.81 m/s² × sin(30°) = 49.05 N

8. Please find attached the drawing showing the weight, the friction force and the normal reaction of the block.

Given that the block slides down at a constant speed, the frictional force is equivalent to the weight component down the incline

The weight components of the block are:

Frictional force, [tex]F_{fr}[/tex] = Weight component down the incline, [tex]F_{W}[/tex], which gives;

Frictional force, [tex]F_{fr}[/tex] = 10.0 kg × 9.81 m/s² × cos(20) × μ = 10.0 kg × 9.81 m/s² × sin(20) ≈ 33.55 N

Weight component down the incline, [tex]F_{W}[/tex] ≈ 33.55 N

The normal reaction, [tex]F_{N}[/tex] = m·g·cos(θ)

Therefore: Normal reaction, [tex]F_N[/tex] ≈ 10.0 kg × 9.81 m/s² × cos(20°) ≈ 92.18 N

9. When the crate moves at a steady speed, the required horizontal force = The frictional force = m·g·μ

Given that m = 79.4 kg, μ = 0.2, we have;

Friction force = Required force = 79.4 × 9.81 × 0.2 = 155.7828

The required horizontal force = 155.7828 N

10. Given that the coefficient of static friction, μ = 0.77, we have:

When the car slips; friction force = weight of the car acting on the incline

m·g·cos(θ)·μ = m·g·sin(θ)

[tex]\mu = \dfrac{m \cdot g\cdot sin(\theta)}{m\cdot g\cdot cos(\theta)} = tan(\theta)[/tex]

The steepest angle, θ = arctan(μ)

Which gives;

Steepest angle, θ = arctan(0.77) ≈ 37.6°

The steepest angle is, θ ≈ 37.6°

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Answer: coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

Explanation:

At the top of his path, he comes to rest for a moment but he will not be in equilibrium at this point.

No, the boy is not in equilibrium. At the moment at which the boy is released from his father's grip, he is not in equilibrium.

Being in equilibrium means that the net force on the body is zero. When we talk about net force, it means that the net acceleration should be zero. But when the boy is released into the air, the boy's velocity will become zero at the highest point, but the acceleration is never zero. The velocity of the body has nothing to do with the equilibrium of the body.

The earth is constantly applying gravitational force to the body.

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A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A. The period is the amount of time T needed to finish one oscillation.

Simple harmonic motion, or SHM, is a specific type of repetitive or periodic motion that describes the oscillation of the pendulum. The oscillating object's position changes sinusoidally throughout time. Many things go back and forth. A youngster swinging can be thought of as basic harmonic motion since the motion is approximatively sinusoidal. Simple harmonic motion does not include some complex motions, such as turbulent ocean waves.

When an item is in simple harmonic motion, it is simple to calculate both its position in relation to time and the rate at which it oscillates back and forth. In this lab, you will examine two simple harmonic motion examples: a simple pendulum and a spring-mass system.

A particle in simple harmonic motion that vibrates vertically goes up and down between two extremes when y = A. The amplitude is the largest displacement, A.

A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A.

The period is the amount of time T needed to finish one oscillation. The frequency f, or number of vibrations the system makes per unit of time, is a related quantity. The unit of measurement for frequency is Hertz (abbreviated as Hz), with 1 Hz equal to one second. Frequency is the reciprocal of time.

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The weight of a person on the planet Pluto with mass 85 kg is 52.36 N.

What is Pluto?

Pluto is a dwarf planet in the Kuiper belt, a ring of planets beyond Neptune's orbit. The ninth-largest and tenth-most massive object known to exist, it orbits the Sun directly. The largest trans-Neptunian object by volume, it is only slightly larger in mass than Eris. Like other Kuiper belt objects, Pluto is substantially smaller than the inner planets and is primarily made of ice and rock. The moon of Earth is only one-sixth the mass and one-third the volume of Pluto.

At first, lets calculate the acceleration due to gravity at Pluto:

The formula to calculate the acceleration due to gravity is:

[tex]a_g = G \times \frac{m}{r^2}[/tex]

where, a = acceleration due to gravity, m = mass, r = radius, G = gravitational constant

The mass is 1.303 x 10^22 kg

The radius is 1.1883 x 10^6 m

G is 6.67408 x 10^-11 m^3/kg•s²

So

a = 6.67408 x 10^-11 m^3/kg•s^2 • 1.303 x 10^22 kg / (1.1883 x 10^6 m)^2

a = 8.69632624 x 10^11 m^3/s^2 / 1.41205689 x 10^12 m^2

a = 6.1586 x 10^-1 m/s² or 0.616 m/s²

Now, lets calculate the weight:

w = ma

where, w = weight, m = mass

putting the values in question, we get,

w = 85 (0.616)  

w = 52.36 N

Note: Some correction in the value of mass and radius needs to be done in the question.

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The fact that both spools travel same distance over same period of time and have equal mass, both will reach the top of the ramp at same time.

The same tension inextensible threads are used to draw two identical spools of similar mass, A and B, from rest and up identical ramps. The thread is wrapped repeatedly around spool A, but it is secured to a fixed spot on spool B, preventing rotation of spool B. The ramps and the objects don't rub against each other. From the bottom of the ramp to the same spot at the top of the ramp, both spools are hauled.

The tension from the thread force and a part of the force of gravity are forces acting on both spools along the ramp. Due to the equal spool masses and tension forces, the net forces operating on both are also the same. As a result, both spools' centers move with the same acceleration. Both begin at zero speed, hence the speed of both spools at any one time is the same. The distance and duration of travel for both spools are the same. So, they both arrive at the ramp's top simultaneously.

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Will spool A reach the top of the ramp before, after, or at the same instant as spool B? If you do not have enough information, state so explicitly. Explain your reasoning.

If you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.

A velocity vector is the rate of change of an object's position. A velocity vector has both magnitude and direction. The magnitude of the velocity vector gives the speed of the object while the direction of the vector gives the direction of the object's velocity.

If a vector's size is longer than the other, it means that the vector has a magnitude higher than the other. If the magnitude is higher, the velocity will be higher.

Therefore, if you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.

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The most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

Stars are massive, hot, luminous bodies of gas that emit large amounts of radiation and derive their energy from nuclear fusion. A planetary system comprises of a star and all the objects that revolve around it.

Stars are born in nebulae. They are a cluster of gas and dust scattered throughout a galaxy. Gravitational attraction between the gas and dust particles causes turbulence, which gives rise to knots. When these knots acquire sufficient mass, they collapse, and when the reach a certain temperature, nuclear fusion of hydrogen atoms into helium atoms begins. At this point, star has been born.

Planets can be said to be formed as a by-product of star formation, through a process called accretion. Smaller objects stick together through gravity, forming bigger objects. Gravitational pull from the nearby star and the object's own momentum causes the object to revolve round the star. At this point, a planet has been born.

Thus, the most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

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Answer:

When it is dropping into the sand.

Answer:

reaction

Explanation:

Newtons third law states that for every action there is an equal but opposite reaction

and for that object (rocket, missile, jet,) as the engine is ignited the force of the burning fuel pushes backward while the rocket moves forward so the rate at which the fuel burns is equal to the rate at which the object moves forward

the force at which the burning fuel pushes backward is equal but opposite to the rate at which the object moves forward

When Solid iron(II) sulfate and a solution of barium chloride react together, they form solid barium sulfate and a solution of iron (II) chloride. Here, exchange of anions and cations took place and is an example of a double displacement reaction.

A double Displacement reaction is a type of reaction in which, the cations and anions of the two ionic compounds exchange with each other to form new compounds. The overall reaction of double displacement looks like this,

X⁺Y⁻ + A⁺B⁻ ---------------> X⁺B⁻ + A⁺Y⁻

Precipitation reactions and neutralization reactions are two common examples of Double displacement reactions. In the given question, the reaction of Iron sulfate and Barium Chloride reaction is as follows;

FeSO₄ + BaCl₂ -------------> FeCl₂ + BaSO₄

Here the cations Fe²⁺ and Ba²⁺ are exchanged with the anions Cl⁻ and SO₄²⁻.

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The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it. The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward.

As long as the crate accelerates at the same rate as the truck, it won't slide. The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it.

The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward. To cause a commensurate rise in the crate's acceleration, the truck's acceleration must likewise increase.

However, the static frictional force can only build up to a certain point, after which the crate and vehicle will accelerate to their maximum rate. The crate will slip if the acceleration is raised much further.

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(a) The force of friction increases as the applied force increases.

(b) The force of friction at each value of X (applied force ) can determined by subtracting the net force on the block from the  applied force.

The coefficient of static friction is the ratio of the maximum static friction force between the surfaces in contact before movement commences to the normal force.

Mathematically, the coefficient of static friction is given as;

μ = F/N

where;

Before the block start moving, the static friction must be overcame since it prevents the block from moving.

The net force on the block is determined by applying Newton's second law of motion.

F - Ff = ma

F = ma + Ff

where;

From the formula above, as the applied force increases the force of friction increases as well.

The force of friction at each value of X (applied force ) is calculated as follows;

Ff = F - ma

Ff = F - F(net)

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