What would be the absolute value of Point R shown on the number line?

Answer:

3.9mm

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

Angle measures of a triangle must add up to 180 and this only adds up to 87

Statistics are used to make estimates of population parameters. Therefore, the correct option is B.

Statistics are used for various purposes in data analysis. One important application of statistics is to make estimates of population parameters. Population parameters are characteristics or measures that describe an entire population. However, it is often impractical or impossible to collect data from the entire population, so statistics provide methods for estimating these parameters based on a sample of the population.

By collecting and analyzing data from a sample, statisticians can make inferences and draw conclusions about the larger population. These estimates help researchers understand the characteristics, patterns, and relationships within the population.

Additionally, statistics form the basis for analysis in many fields, including scientific research, business, social sciences, and more. They provide tools and techniques to summarize, interpret, and draw meaningful insights from data, enabling researchers and decision-makers to make informed choices and draw valid conclusions from their observations and experiments.

Therefore, the correct choice is option b. Statistics play a crucial role in estimating population parameters and providing insights for analysis and decision-making.

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Answer:

33/12 or 2.75

Step-by-step explanation:

6 1⁄6 - 3 5⁄12

37/6 - 41/12

74/12 - 41/12

33/12 or 2.75

10 and -6                                  

.....................................................

Answer:

7

Step-by-step explanation:

Answer:

Sam's is 7in shorter

Step-by-step explanation:

[tex]10-3=7[/tex]

Answer: $10

Step-by-step explanation:

Let Josie's money be x

Since Joe has half as much as Josie. Joe's money will be: x/2 = 0.5x

Bob has four times as much money as Joe. Bob's money will be = (4 × 0.5x) = 2x

Therefore, we add all the amount together and equate to $35. This will be:

x + 0.5x + 2x = 35

3.5x = 35

x = 35/3.5

x = 10

Josie has $10

the number of choices in each case is:

a. With no restriction: 10,000 choices.

b. No digit is repeated: 5,040 choices.

c. No digit is repeated, 2 and 5 must be present: 56 choices.

Let's calculate the number of choices in each case:

a. With no restriction:

For each digit in a 4-digit pin code, we have 10 choices (0-9). Since there are 4 digits in total, the number of choices is 10⁴ = 10,000.

b. No digit is repeated:

For the first digit, we have 10 choices (0-9).

For the second digit, we have 9 choices (any digit except the one chosen for the first digit).

For the third digit, we have 8 choices (any digit except the two chosen for the first and second digits).

For the fourth digit, we have 7 choices (any digit except the three chosen for the first, second, and third digits).

The total number of choices is 10 * 9 * 8 * 7 = 5,040.

c. No digit is repeated, and 2 and 5 must be present:

We have two fixed digits (2 and 5) that must be present in the pin code.

For the first fixed digit (2), we have only 1 choice.

For the second fixed digit (5), we have only 1 choice.

For the remaining two digits, we have 8 choices each (any digit except 2 and 5).

The total number of choices is 1 * 1 * 8 * 7 = 56

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Main Answer: The numerical value of y(2.0) rounded off to three figures is 1.279.

Supporting Explanation:

The student solved the initial-value problem and found that y(2.0) = 1.27977. The question asks to round off the value to three figures. Therefore, we have to keep only the first three digits after the decimal point, which are 279. The next digit after 9 is 7, which means we have to round up the last digit. Thus, the rounded off value of y(2.0) is 1.279.

The initial-value problem is a differential equation that has an initial condition given for a specific value of the independent variable. In this case, the initial condition is y(1) = 2. The solution of the initial-value problem gives the value of y for other values of x. Here, we are required to find the value of y for x = 2.0.

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Answer:

Angle A=68

Step-by-step explanation:

68+x+(x-24)=180

68+x+x-24=180

2x+44=180

2x=136

x=68

Answer:

B

Step-by-step explanation:

Its dominant because its brown hair.

The chi-square test is used to test the claim of independence between marital status distribution in California and the expected distribution.

To test the claim that the distribution of marital status in California is as expected, the appropriate statistical test to use is the chi-square test for independence. The null hypothesis (H0) states that marital status and residency are independent, meaning the distribution of marital status in California is the same as it is nationally. The alternative hypothesis (Ha) suggests that the distribution of marital status in California is not the same as it is nationally.

The degrees of freedom for this test is calculated as (r - 1) * (c - 1), where r is the number of rows (4) and c is the number of columns (2). In this case, the degree of freedom is 3.

Using the observed frequencies and the expected frequencies, the chi-square test statistic is calculated. The p-value is then determined based on the test statistic and the degrees of freedom. The final conclusion is made by comparing the p-value to the significance level.

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Answer:

Step-by-step explanation:

Question 13.

By applying cosine rule,

cos(45°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{10}{y}[/tex]

y = 10√2

By applying sine rule,

sin(45°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{y}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{10\sqrt{2} }[/tex]

x = 10

Question 15.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{y}{32}[/tex]

y = 16√3

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{32}[/tex]

x = 16

Question 17.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{11\sqrt{3} }{y}[/tex]

y = 22

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{y}[/tex]

[tex]\frac{1}{2}=\frac{x}{22}[/tex]

x = 11

Answer:

I think it is A.

Step-by-step explanation:

I hope this helps.

Answer:

d . 19528

Step-by-step explanation:

maaf jika salah

Answer:

2.True

3. HGK

4. 17°

hope it helps

Answer:

The answer and work are in the pdf

Step-by-step explanation:

Answer: A. The majority of the math scores are greater than the median of the science scores

Step-by-step explanation:

I took the test!

Answer:

B ( -1, -8)

Step-by-step explanation:

A ( -7, -6)

midpt (-4, -7)

Equation:

(x + 3, y - 1)

Solve for B:

(-4, -7)

(x + 3, y - 1)

( -1, -8)

Answer:

28 i think

Step-by-step explanation:

Answer:

0.28

Step-by-step explanation:

Answer:

0.20

Step-by-step explanation:

i got it right on edge 2022

Answer: 10 points

Step-by-step explanation:

Answer:

$ 1.35

Step-by-step explanation:

9 times 0.15 is 1.35

Answer:

c

Step-by-step explanation:

The lem of 18675 and 20112340 is 2^2 * 3^2 * 5^2 * 7 * 83 * 143659.

(a) To find the greatest common divisor (GCD) of 18675 and 20112340, we can use the Euclidean algorithm. The algorithm involves repeatedly dividing the larger number by the smaller number until the remainder becomes zero.

Using the Euclidean algorithm:

20112340 = 1074 * 18675 + 12590

18675 = 1 * 12590 + 6095

12590 = 2 * 6095 + 4000

6095 = 1 * 4000 + 2095

4000 = 1 * 2095 + 1905

2095 = 1 * 1905 + 190

1905 = 10 * 190 + 15

190 = 12 * 15 + 10

15 = 1 * 10 + 5

10 = 2 * 5 + 0

Since the remainder is now zero, the GCD is the last non-zero remainder, which is 5.

Therefore, ged(18675, 20112340) = 5.

(b) To factor the numbers 18675 and 20112340, we can find their prime factorizations.

Prime factorization of 18675:

18675 = 3^2 * 5^2 * 83

Prime factorization of 20112340:

20112340 = 2^2 * 5 * 7 * 143659

(c) To find the least common multiple (LCM) of 18675 and 20112340, we can use the prime factorizations obtained in the previous step.

The LCM is the product of the highest powers of all the prime factors involved.

Prime factors in the LCM:

2^2 * 3^2 * 5^2 * 7 * 83 * 143659

Therefore, the lem of 18675 and 20112340 is 2^2 * 3^2 * 5^2 * 7 * 83 * 143659.

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The five-number summary for the given data is as follows: Minimum = 45, First Quartile (Q1) = 71, Median (Q2) = 89, Third Quartile (Q3) = 108, Maximum = 125.

The five-number summary provides key descriptive statistics that summarize the distribution of the data. It consists of the minimum value, the first quartile (Q1), which represents the lower 25% of the data, the    median (Q2), which represents the middle value or the 50th percentile, the third quartile (Q3), which represents the upper 25% of the data, and the maximum value.

To draw a boxplot based on this five-number summary, a box is drawn from Q1 to Q3, with a line indicating the median (Q2). Whiskers extend from the box to the minimum and maximum values. Outliers, if present, are represented as individual data points beyond the whiskers.

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The number of people who received fewer than 100 spam messages in the university department is calculated below:

Total number of messages tagged as spam = 6693

Total number of people = 12

Total number of people who received more than 100 spam messages = 11

Number of people who received fewer than 100 spam messages = 1

The number of people who received fewer than 100 spam messages can be calculated by subtracting the total number of people who received more than 100 spam messages from the total number of people in the department.

Thus, the other 1 person received a total of: 6693 - (1818 + 1358 + 442 + 416 + 399 + 389 + 304 + 251 + 251 + 178 + 158 + 103) = 474

Graph illustrating the data collected from students and faculty in the department. it is clear that the majority of students and faculty members in the department received more than 100 spam messages. One person received fewer than 100 spam messages. The number of spam messages received seems to decrease with time, which may indicate that the spam filter is effective.

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