Please help with Question 4 :(
Answer:
cf4, ch20,vhjuyu8hc hi l bro tap
kinetic energy is proportional to what
Answer:
mass and the square of the magnitude of velocity.
Explanation:
(GIVING BRANLYEST) John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Which of the following is the best way to explain why the clouds have formed? O The temperature of the air is below zero. O There is a low amount of moisture in the air. O The warm, wet air in a low pressure system has risen up and cooled down. O The wind is traveling at a slow speed.
John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.
Hence, Option C is correct answer.
How are Clouds formed ?Clouds are formed by the process of evaporation and which is followed by condensation. Clouds are small droplets of water crystallization which float in the air. When the moist air rises upwards then the formation of clouds take place because when air rises upwards it becomes colder.
Thus from the above conclusion we can ay that John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.
Hence, Option C is correct answer.
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Answer: Answer would be C I read the assignment and got it correct
Explanation:
Which group on the periodic table has the most reactive metals?
A.
group 1
B.
group 3
C.
group 18
D.
group 17
Answer:
A group 1
Explanation:
Group 1
reactivity decreases as you go from L to R or downward on the periodic table
If you know that lithium reacts strongly with oxygen in a 2:1 ratio, which of
the following properties would you predict about cesium
Answer:
Same as lithium
Explanation:
Lithium and Ceaseum both are group one elements i.e alkali metals
So they have same chemical properties almost
Hence Ceaseum would react with oxygen in 2:1 ratio
For this same exercise, if 2.5 liters of this solution (2,500 ml) are administered in a 24-hour interval, what amount in grams of glucose did the patient receive in one day? the glucose to dissolve is 50 grams
Answer:
j
Explanation:
becaisdbyhe wrl is so not goood
How much heat will be absorbed by a 66.3 g
piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?
Q=mcΔt
Q=66.3 x 0.93 x (67-23)
Q=2712.996 J
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]
[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]
[tex] \textsf{m = mass in gram = 66.3 g} [/tex]
[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]
[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]
[tex] \large\textsf{Find Q : } [/tex]
[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]
[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]
[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
The rate law for the reaction 3A --> 2B is rate = k[A] with a rate constant of 0.0447 hr-1.
What is the half-life of the reaction?
A) 0.0224 hr
B) 0.0645 hr
C) 15.5 hr
D) 22.4 hr
E) 44.7 hr
The half-life of the reaction is determined as 22.4 hr.
Half life of the reaction
The half life of the reaction is calculated as follows
rate of reaction, k = Δ[A]/3t = Δ[B]/2t
t = Δ[A]/3k = Δ[B]/2k
where;
k is rate constant = 0.0447/hrt = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr
Thus, the half-life of the reaction is determined as 22.4 hr.
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Show all work:
A saturated solution of the Ca(OH)2 is prepared and allowed to equilibrate at 25°C. A 32.40ml
sample of the solution is titrated with 0.050M HCL solution. 14.90mL of the HCI solution are
required to fully react with the sample.
Write the balanced equation for the reaction of the salt with HCl
The equation of the reaction is;
Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)
What is neutralization?The term neutralization has to do with the process in which an acid reacts with a base to form salt and water only. A neutralization reaction is known by the fact that water is obtained by the reaction of hydrogen and hydroxide ions.
The equation of the reaction is;
Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)
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Cellular Respiration is the process of what? A. Producing oxygen at the cellular level. B. The release of energy from food. C. Breathing. D. The creation of food, powered by the energy of the sun.
Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.
What is cellular respiration?Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.
Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.
Hence, option B is correct.
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I NEED HELP! A rigid cylinder contains 3.00 liters of gas at a temperature of 25°C. If the pressure of this gas is changed from
0.500 atmospheres to 1.50 atmospheres, what will be the new temperature of the gas? (R= 0.0821 Latm/mol K)
O 612 °C
894 °C
99.3 °C
885 °C
O 75.0 °C
Gay Lussac's Law
P₁/T₁=P₂/T₂
25°C = 25+273 = 298 K
0.5/298 = 1.5/T₂
T₂ = 894 K = 621 °C
A gas law known as Gay-Lussac's law asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. The new temperature is 612 °C and the correct option is A.
When the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas. In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-Lussac's law can be expressed mathematically as follows:
P₁ / T₁ = P₂ / T₂
25°C = 25 + 273 = 298 K
0.5 / 298 = 1.5 / T₂
T₂ = 894 K
T₂ = 894-273
T₂ = 621 °C
Thus the correct option is A.
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A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C. Use the chart to complete the multiple steps required to arrive at the final answer. Type in your answers below using 3 digits.
q1 = ___ kJ
q2 = ___ kJ
q3 = ___ kJ
qtot = ___ kJ
The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
Quantity heat required to convert the ice to liquid
The total quantity of heat required is calculated as follows;
q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)
q(tot) = mcΔθ₁ + mΔHf + mcΔθ₂
q(tot) = (100)(4.2)(0 - -45) + (334)(100) + (100)(4.2)(75 - 0)
q(tot) = 18,900 J + 33,400 J + 31,500 J
q(tot) = 18.900 kJ + 33.400 kJ + 31.500 kJ
q(tot) = 83,800 J = 83.8 kJ
Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
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Answer:
q1 9.42
q2 226
q3 31.4
qtot 267
Explanation:
hope this help
During quiet breathing, a person breathes in about
6 L of air per minute. If a person breathes in an
average of 6.814 L of air per minute, what volume
of air in liters does this person breathe in 1 day
Answer:
[tex]\huge\boxed{\sf 9812.16\ L\ of\ air}[/tex]
Explanation:
Given that,
A person breathes 6.814 L of air in a minute.
1 minute = 6.814 L
Minutes in a day:= 1 × 24 × 60 (24 hours in a day; 60 minutes in an hour)
= 1440 minutes
Volume of air that person breathes in a day:1 minute = 6.814 L of air
1440 minutes = 6.814 L × 1440
1 day = 9812.16 L of air
[tex]\rule[225]{225}{2}[/tex]
What is the half-life in minutes of a compound if 75.0 percent of a given sample decomposes in 40.0 minutes? Assume first-order kinetics.
Answer:
See below
Explanation:
.75 = 1/2^(40/h)
log .75 / ( log 1/2) = 40 / h
h = half life = 96.37683 min
To solve this type of question we must know the concept of rate law. The half-life of a compound is 23 years for 75% of a given sample of the compound decomposes in 40 minutes.
What is the expression for rate law for first order kinetics?There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law
The rate law for first order kinetics is
[tex]k=\frac{2.303}{t}log\frac{a}{a-x}[/tex]
Where
k - rate constant
t - time passed by the sample
a - initial amount of the reactant
a-x - amount left after the decay process
The expression for the half-life of the compound is
[tex]t_{1/2} = \frac{0.693}{K}[/tex]
Where k is the rate constant
t = 40 minutes
a = 100 g
a-x = 100 g - 75g = 25 g
(Since it is given that 75% of the given compound decomposes)
Then,
[tex]k=\frac{2.303}{40}log\frac{100}{25}[/tex]
=0.03years⁻¹
[tex]t_{1/2} = \frac{0.693}{0.03}[/tex]
=23 years
Therefore, the half-life of the given compound is 23years.
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The _______ effect means water can "climb" up thin tubes and water plants. This is due to the ______ nature of water.
The Capillary effect means water can "climb" up thin tubes and water plants. This is due to the surface tension nature of water.
Hope this helps:)
The capillary effect means water can "climb" up thin tubes and water plants. This is due to the adhesive nature of water.
The capillary effect is a phenomenon where liquids, like water, can rise against gravity in narrow tubes or spaces, such as the stems of plants. This effect is possible due to the adhesive nature of water, which allows it to stick to the walls of the tube or surface it comes into contact with.
The cohesive forces between water molecules create a sort of "pull" that allows the water to climb up the tube, defying gravity. This property is essential for plants, as it helps them transport water and nutrients from their roots to their leaves and other parts of the plant, supporting their growth and survival.
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Diamonds are composed of __________ in a ___________lattice. A. silicon, trigonal planar B. quartz, octahedral lattice C. carbon, tetrahedral D. diamond, trigonal bipyramid
Diamonds are composed of carbon in a tetrahedral lattice. That is option C.
What is a diamond?A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.
These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.
Therefore, Diamonds are composed of carbon in a tetrahedral lattice.
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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.
What are diamonds?Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.
Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.
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How does the study and understaning of the biological macromolecules impact your everday life?
The study and understanding of the biological macromolecules impact our everyday life by making us know what to eat and the different processes which occur in the body.
What are Biological macromolecules?These are cellular components of the body which are natural and vital for the growth and survival of organisms.
Examples include carbohydrates, protein etc which contain nutrients vital for our daily life.
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Which three words best describe the composition of the inner planets?solid, smooth, giantrocky, solid, densegiant, dense, gaseousgaseous, smooth, small
The three words which best describe the composition of the inner planets are rocky, solid, and dense.
What is an inner planet?A planet classified as an inner planet is one that is rocky, solid, and dense by nature, such as Mercury, Venus, Earth, and Mars. Inner planets are those that are nearest to the Sun.
There are two types of planets:
Based on astronomical information and records, there are two main types of planets :
Outer planetInner planetThe moons of the inner planets are either absent or limited to one (Earth) or two (Mars). The inner planets don't have any rings. The inner planets have shorter orbits around the Sun than the outer planets, but they all rotate more slowly.
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Answer:rocky soild and dense
Explanation:
A hurricane is a type of severe cyclone
A hurricane is a type of severe cyclone formed when winds rotate as the pressure between low and high-pressure areas increases.
What is a hurricane?A cyclone is a violent storm that occurs when cyclone winds exceeds a speed of 74 miles (119 kilometers) per hour.
Hurricanes are classified according to their strength and catastrophic potential on a scale ranging from 1 to 5 (more violent).
In conclusion, a hurricane is a cyclone formed when a it rotates as the low and high-pressure areas increases.
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Is it possible to use subatomic particles as an energy source?
Yes, Is it possible to use subatomic particles as an energy source.
What are subatomic particles?A subatomic particle is nothing but a particle which is smaller than an atom in size. Typically, an atom can be broken down into three subatomic particles, namely: protons, electrons, and neutrons.
Yes, Is it possible to use subatomic particles as an energy source.
There are instances when the protons and electrons in an atom's outermost shells are not strongly attracted to one another. It is possible to force these electrons out of their orbits.
They may move from one atom to another by exerting force. Electricity is made up of these moving electrons.
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It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was required
to melt the iceberg if 1 m³ of ice has a mass of 917 kg?
The amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?The heat required to melt a unit mass of ice is known as the latent heat of fusion.
The latent heat of fusion of ice of 1 kg= 334 kJ of heat
Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg
Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.
Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
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The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is __________ atm.
Answer: 0.42 atm
Explanation:
For this problem, we are going to use the ideal gas law for pressure, which is [tex]P=\frac{nRT}{V}[/tex]. If you do not know yet, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex]First, we must find the number of CH₄ moles.
[tex]6.022gCH_{4} *\frac{1molCH_{4} }{16.043gCH_{4} } =0.38molCH_{4}[/tex]
Next, we will plug in our given information to the ideal gas law for pressure.
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac{0.38mol*0.0821\frac{L*atm}{mol*K} *402K}{30.0L} =0.42 atm[/tex]
The answer to this, according to the work done above, is 0.42 atm.
I hope this helps! Pls mark brainliest!! :)
The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is 0.413 atm.
How do we calculate the pressure of gas?
Pressure of gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure of gas = ?
V = volume of gas = 30L
R = universal gas constant = 0.082 L·atm·K⁻¹·mol⁻¹
T = temperature of gas = 402 K
n is moles of gas & it will be calculated as:
n = W/M, where
W = given mass of CH₄ = 6.022g
M = molar mass of CH₄ = 16g/mol
n = 6.022 / 16 = 0.376mol
Now putting all these values on the above equation, we get
P = (0.376)(0.082)(402) / (30)
P = 0.413 atm
Hence required pressure of methane gas is 0.413 atm.
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Which of the following stars is a B class main sequence star?
The B class main sequence star from the given images is Star 3.
What are B class main sequence stars?B class main-sequence stars are of spectral type B and luminosity class V. They are very luminous and blue with surface temperatures between 10,000 and 30,000 K.
The stars that are blue as shown in the image are Star 1 and Star 3. However, Star is the one that has surface temperature between 10,000 and 30,000 K.
Therefore, Star 3 is a B class main sequence star.
In conclusion, stars are luminous objects with very high surface temperatures.
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Question 1 of 25 Hydrogen gas can be produced using this equilibrium reaction. Which change would drive this process toward the product side? C + H₂O CO + H₂ + energy A. Removing the H₂O as it forms B. Increasing the temperature C. Removing the C as it forms D. Removing the CO as it forms SUBMIT
What we need to do to drive the equilibrium to the products side is removing the CO as it forms.
What is the equilibrium position?The equilibrium position is dependent in the conditions of the reaction. We know that the direction to which the equilibrium is shifted can be altered by manipulating the parameters of the reaction.
Now the reaction is; C + H₂O -----> CO + H₂ + energy. The case in point here is to drive the equilibrium position towards the products side.
What we need to do to drive the equilibrium to the products side is removing the CO as it forms.
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The table describes how some substances were formed.
Substance
Description
P
Formed by boiling pure water
Q
Formed by combining three hydrogen atoms to every nitrogen atom
R
Formed by adding 5 g of sugar to 1 L of water
S
Formed by compressing carbon under high pressure
Based on the given descriptions, which substance is most likely a mixture?
P
Q
R
S
R is the mixture formed by adding 5 g of sugar to 1 L of water.
Which is a mixture?A mixture is an impure substance made up of two or more substances which are miscible or immiscible in each other.
Dissolving the sugar in the water makes a homogenous mixture and once dissolved a solution is made by the combination of a solute (sugar) and solvent (water).
Hence, R is the mixture formed by adding 5 g of sugar to 1 L of water.
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Which most likely describes results from their experiments? tristan and arya would exert more energy to overcome friction than anoush and keran. tristan and anoush would exert more energy to overcome friction than arya and keran. tristan and keran would exert less energy to overcome friction than arya and anoush. tristan and arya would exert less energy to overcome friction than anoush and keran.
The statement that most likely describes the results from their experiments is Tristan and Arya would exert more energy to overcome friction than Anoush and Keran. Thus, the correct option is A.
What is Friction?Friction may be characterized as the force that counters the proximate motion between two surfaces of objects when they reach to contact.
According to the question, Tristan is working with static friction and Arya is working with sliding friction; static friction operates on things when they are catnapping on a surface, whereas sliding friction functions on objects when they are gliding over a surface.
Sliding friction is much more fragile and weaker than static friction and is comparatively uncomplicated and utilizes less energy to drag the objects.
The complete question is as follows:
Four students are doing different friction experiments with a cylinder.
Tristan is working with static friction,Arya is working with sliding friction,Anoush is working with rolling friction,Keran is working with fluid friction.Therefore, the correct option for this question is A, i.e. Tristan and Arya would exert more energy to overcome friction than Anoush and Keran.
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For the decomposition of ammonia on a platinum surface at 856 °C
2 NH3(g)N2(g) + 3 H2(g)
the average rate of disappearance of NH3 over the time period from t = 0 s to t = 5.48×103 s is found to be 1.50×10-6 M s-1.
What is the average rate of appearance of H2 over the same time period?
M s-1.
[tex]\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}[/tex]
dt remains same for reaction[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}[/tex]
[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})[/tex]
[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}[/tex]
M is molarity here not metre
The average rate of appearance of H2 over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.
To find the average rate of appearance of [tex]\rm H_2[/tex], we can use the stoichiometry of the reaction to relate it to the rate of disappearance of [tex]\rm NH_3[/tex].
From the balanced equation: [tex]\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)[/tex]
We can see that for every 2 moles of [tex]\rm NH_3[/tex] that disappear, 3 moles of [tex]\rm H_2[/tex] appear.
Given that the average rate of disappearance of [tex]\rm NH_3\ is\ 1.50\times10^{-6} M/s[/tex], we can calculate the average rate of appearance of [tex]\rm H_2[/tex] as follows:
Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x (Average rate of disappearance of [tex]\rm NH_3[/tex])
Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x [tex]\rm (1.50\times10^{-6} M/s)[/tex]
Average rate of appearance of [tex]\rm H_2[/tex] = [tex]\rm 2.25\times10^{-6} M/s[/tex]
Therefore, the average rate of appearance of [tex]\rm H_2[/tex] over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.
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If a sample of Cl2 gas in a 1000 mL container is exerting a pressure of 14.2 atm, how many grams of chlorine are present? The temperature of the container is 256 K.
Taking into account the ideal gas law, the mass of chlorine present is 47.9284 grams.
Ideal gas lawAn ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Mass of chlorine presentIn this case, you know:
P= 14.2 atmV= 1000 mL= 1 LT= 256 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?Replacing in the ideal gas law:
14.2 atm× 1 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K
Solving:
(14.2 atm× 1 L)÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K)= n
0.676 moles= n
Being the molar mass of chlorine Cl₂ 70.9 g/mole, the mass of the compound can be calculated as:
0.676 moles× 70.9 g/mole= 47.9284 grams.
Finally, the mass of chlorine present is 47.9284 grams.
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You have prepared an aqueous solution of a monoprotic acid (formula mass = 153.483g/mol) by dissolving 26.816g of the acid in sufficient water to make 500.0mL of solution. The pH of the resulting solution is 4.274. What is Ka for this acid?
The Ka of the solution is 8.1 * 10^-9.
What is the pH?The pH of a solution is the concentration of hydrogen ions in the solution.
Number of moles of the acid = 26.816g/153.483g/mol = 0.175 moles
Concentration of the acid = 0.175 moles/0.5 L = 0.35 M
Now we know that the acid reacts with water as follows;
HA(aq) + H2O(l) ------> H3O^+(aq) + A^-(aq)
[H3O^+] = Antilog (-4.274)
[H3O^+] = 5.32 * 10^-5 M
Since;
[H3O^+] = [A^-] = x
Ka = x^2/[HA]
Ka = (5.32 * 10^-5)^2/( 0.35)
Ka = 8.1 * 10^-9
Hence, the Ka of the solution is 8.1 * 10^-9.
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Which of the following ions is formed when an acid is dissolved in a solution?
OH+
0-
OH-
OSO4²+
Answer:
The ion that is formed when an acid is dissolved in a solution is OH-.
Explanation:
An acid is a molecule that donates hydrogen ions, or protons, to another molecule. In solution, the acid dissociates, or breaks apart, to form hydrogen ions and the negatively-charged anion of the acid. The anion of a typical acid is the molecule minus the hydrogen ions, so it is OH- for hydrochloric acid, HCl.