What volume (in mL) of 0.108 M aluminum hydroxide is required to neutralize 30.00 mL of 0.175 M nitric acid

Answers

Answer 1

The volume of aluminum hydroxide required for neutralization is 24.30 mL.

Acid and base:

The compounds which gives H+ ions in the aqueous solution are called acids while those which gives OH- ions are called base.

Neutralization reaction:

It is a chemical reaction that involves a reaction between the equal molar amount of acid and base and form a solution that has pH = 7.

Calculations:

The reaction between aluminum hydroxide and nitric acid is expressed as:

Al(OH)2 + 2HNO3 ----> Al(NO3)2 + 2H2O

The number of moles of nitric acid is calculated as:

Moles of HNO3 = 0.175 M x (30.00/1000) L = 0.00525 mol

The number of moles of Al(OH)2 required for the neutralization is:

Moles of Al(OH)2 = 0.00525 mol/2 = 0.002625 mol

The volume of Al(OH)2 is calculated as:

Volume = 0.002625 mol/0.108 M = 0.0243 L = 24.30 mL

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Related Questions

Identify the reactant, reagent, and solvent to synthesize the Grignard reagent. An unknown reactant is treated with an unknown reagent in an unknown solvent to give a grignard reagent. The product is a carbon bonded to two methyls, a hydrogen and magnesium chloride. The best reactant is: The best reagent is: The best solvent is:

Answers

The best reactant is: iPrCl

The best reagent is: Mg

The best solvent is: CH3CH2OCH2CH3

Grignard reagent or Grignard compound

A chemical molecule with the general formula RMgX, where X is a halogen and R is typically an alkyl or aryl group, is known as a Grignard reagent or Grignard compound. Methylmagnesium chloride (ClMgCH3) and phenylmagnesium bromide (C6H5)-Mg-Br, respectively, are two prominent examples. They fall within the category of organomagnesium compounds.

Why does the Grignard reagent include mg?

Typically, magnesium ribbon is needed for the reaction that results in the synthesis of Grignard reagents. A magnesium oxide passivating coating protects the whole magnesium, preventing interactions with organic halides. As an initiator, Grignard's prepared reagent can also be applied.

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The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?

Answers

answer

Please add answer choice

Explanation:

Answer:

Explanation:

.........................................................      

If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.2% isotope C (mass number 22), the atomic weight of the element measured from the sample will be:

Answers

If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.3% isotope C (mass number 22), the atomic weight of the element measured from the sample will be greater than 21 amu.

To calculate the average atomic mass, multiply the fraction through the mass number for every isotope, then add them together. Whenever we do mass calculations concerning elements or compounds (combos of elements), we usually use average atomic loads.

For instance, carbon-14 is a radioactive isotope of carbon that has six protons and 8 neutrons in its nucleus. We name it carbon-14 because the overall range of protons and neutrons within the nucleus also called the mass number, provides up to fourteen (6+8=14).

Together, the quantity of protons and the range of neutrons determine an detail's mass variety. Due to the fact, that an element's isotopes have barely unique mass numbers, the atomic mass is calculated by obtaining the suggested mass numbers for its isotopes.

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7. If you start with 3.20 mol of Li3N and 9.0 mol water, how many moles of NH3 will be formed?
Li3N + 3H2O ----> NH3 + 3LiOH

Answers

Taking into account the reaction stoichiometry, 3 moles of NH₃ will be formed.

Reaction stoichiometry

In first place, the balanced reaction is:

Li₃N + 3 H₂O → NH₃ + 3 LiOH

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Li₃N: 1 moleH₂O: 3 molesNH₃: 1 mole LiOH: 3 moles

Limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

Limiting reagent in this case

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Li₃N reacts with 3 moles of H₂O, 3.20 moles of Li₃N reacts with how many moles of H₂O?

[tex]moles of H_{2} O=\frac{3.2 moles of Li_{3}Nx 3 moles of H_{2} O}{1 mole of Li_{3}N}[/tex]

moles of H₂O= 9.6 moles

But 9.6 moles of H₂O are not available, 9 moles are available. Since you have less moles than you need to react with 3.20 moles of Li₃N, H₂O will be the limiting reagent.

Mass of NH₃ formed

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 3 moles of H₂O form 1 mole of NH₃, 9 moles of H₂O form how many moles of NH₃?

[tex]molesof NH_{3} =\frac{9 moles H_{2} Ox1 mole of NH_{3}}{3 moles H_{2} O}[/tex]

moles of NH₃= 3 moles

Finally, 3 moles of NH₃ will be formed.

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What is the symbol of the species with 23 protons and 21 electrons?

Answers
V^2-
V^2+
Na^2+
Sc^2+
Na^2-
Sc^2-

Answers

[tex]V^{2+}[/tex]is the symbol of the species with 23 protons and 21 electrons.

Hence, option F is correct.

What is a proton?

Electrons are a type of subatomic particle with a negative charge. Protons are a type of subatomic particle with a positive charge.

If it has 23 protons, then its proton number (also know as its atomic number) is 23. You can look that symbol up in your periodic table.

If it has 21 electrons then it has a net charge of 23(+) - 21. So we know the ionisation state of the species, and we can record that as a superscript after the symbol for the species.

Hence, [tex]V^{2+}[/tex] is the symbol of the species with 23 protons and 21 electrons.

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In a __________ elimination, the base extracts a proton and the leaving group leaves simultaneously. In a __________ process, the leaving group leaves ___________ the base abstracts a proton. g

Answers

In a Base catalyst elimination, the base extracts a proton and the leaving group leaves simultaneously. In a Concentrated process, the leaving group leaves  the base abstracts a proton.

Just as there are two mechanisms of substitution (SN2 and S N1), there are two

mechanisms of elimination (E2 and E1).

E2 mechanism bimolecular elimination

E1 mechanism unimolecular elimination

The E2 and E1 mechanisms differ in the timing of bond cleavage and bond formation, analogous to the SN2 and S N1 mechanisms.

E2 and S N2 reactions have some features in common, as do E1 and SN1 reactions.

Base removes a proton from the β-carbon atom,

while the halogen atom leaves from the α-carbon resulting in the formation of a π-bond. Such eliminations are also called β-eliminatione liminations are also called β elimination reactions

In a base-catalyzed elimination reaction, the base takes away a proton from the β position of the leaving group (the group that goes away with the bonding pair of electrons) and a double bond is formed. When the base is bulky it prefers to take away the proton from the less hindered position.

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A 2.65 g sample of a salmon colored powder contains 0.70 g of chromium, 0.65 g of sulfur, and 1.30 g of oxygen. The molar mass is 392.2. What is the formula of the compound

Answers

The molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

Given:

Mass of Cr = 0.70 g

Mass of S = 0.65 g

Mass of O = 1.30 g

Molecular mass = 392.2 g

Moles of Cr = [tex]\frac{0.70}{52.0}[/tex]

                  = 0.01346 mol

Moles of S = [tex]\frac{0.65}{32.06}[/tex]

                  = 0.02025 mol

Moles of O = [tex]\frac{1.30}{16.0}[/tex]

                   = 0.08125 mol

Dividing both sides with lower quantity ;

[tex]Cr_{\frac{0.01346}{0.01346} } S_{\frac{0.2025}{0.01346} } O _{\frac{0.08125}{0.01346} }[/tex]≅ [tex]CS_{1.5} O_{6}[/tex]

And [tex](empirical formula )_{n} = molecular formula[/tex]

                        392.2 = n (52.0 + 6 × 16.0)

                                  n = 2

Therefore, the molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

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What is the concentration of ammonia in a solution if 24.4 mL of a 0.117 M solution of HCl are needed to titrate a 100.0 mL sample of the solution

Answers

Answer: The concentration of ammonia is 0.0286M.

Explanation:

The diluted equation is presented as: [tex]M_{s} V_{s} =M_{d} V_{d}[/tex].

~M= Molarity (labeled as M)

~V= Volume (labeled in L)

~s= stock solution (what you started with)

~d= diluted solution (what you now have)

Now that we have our definitions, we can knowingly plug the information into the formula shown above.

[tex]0.117M*24.4mL=M_{d} *100mL[/tex]

We have the information plugged in, but the volume must be measured into liters, not milliliters. We can fix that by converting it. To convert milliliters to liters, you divide the milliliters by 1000.

[tex]24.4mL/1000=0.0244L[/tex]     [tex]100mL/1000=0.1L[/tex]

Now that the volumes are in liters, let's plug that into the equation.

[tex]0.117M*0.0244L=M_{d} *0.1L[/tex]

We are now ready to solve the concentration with this equation!

[tex]M_{d} =\frac{0.117M*0.0244L}{0.1L}[/tex]      [tex]M_{d} =0.0286M[/tex]

With all of the steps shown above, we can conclude that the new concentration of ammonia is 0.0286M.

I hope this helps! Pls mark brainliest!! :)

PLEASE HELP ASAP! very much appreciated

Answers

Answer:

-Unknown

Explanation:

Questions is not seen properly bro

How is a compound different than a
mixture?
a. A compound can be separated by physical
means.
b. A mixture can be separated by physical
means.
c. A mixture is made of only one type of
atom.
d. A compound is made of only one type of
atom

Answers

B

A mixture can be separated by a physical means because there is no chemical bond between the constituents

Hana fills a cup with sandy ocean water. She pours the mixture through a filter. What does she collect that passes through the filter?

a sample of pure water
a solution of salt in water
a suspension of sand in water
a colloid of salt in water

Answers

Answer:-
A Solution of salt in Water
Hope It helps!

Answer: B) a solution of salt in water

Explanation:

Have a wonderfullll day :)

Give three examples of environmental, industrial and bio-chemistry.

Answers

Three examples of environmental, industrial and bio-chemistry are listed below:

Environmental chemistry: Contamination, Atmospheric Deposition, and Soil Pollution.industrial chemistry:  industrial inorganic chemicals, industrial organic chemicals, and agricultural chemicalsbio-chemistry: genetic, immunology, and enzymology

Meaning of Chemistry

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

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For the reaction, Cl2(g)+3F2(g)→2ClF3(g) , determine the rate of change of ClF3 if the concentration of F2 decreases from 0.950 M to 0.865 M over 15 seconds.

Answers

3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

What is the rate of change?

The rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable.

[tex]Cl_2(g)+3F_2(g)[/tex]→[tex]2ClF_3(g)[/tex]

Rate of change of [tex]F_2[/tex] = [tex]\frac{Change \;in \;concemtration}{Time}[/tex]

Rate of change of[tex]F_2[/tex] = [tex]\frac{0.950 M-0.865 M}{15 seconds}[/tex]

Rate of change of [tex]F_2[/tex] = 5.6 x [tex]10^{-3}[/tex]

[tex]\frac{Rate of change of F_2}{3}[/tex] =[tex]\frac{Rate \;of c\;hange \;of\;ClF_3}{2}[/tex]

[tex]\frac{5.6 X 10^{-3}}{3}[/tex]=[tex]\frac{Rate \;of \;change \;of \;ClF_3}{2}[/tex]

Rate of change of [tex]ClF_3[/tex] =1.866666667 x2 x[tex]10^{-3}[/tex]

Rate of change of [tex]ClF_3[/tex]= 3.73 x [tex]10^{-3}[/tex]

Hence, 3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

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What is the strongest type of intermolecular force between solute and solvent in each solution? (a) CH3OCH3(g) in H2O(l)

Answers

The strongest type of intermolecular force between solute and solvent in CH3OCH3(g) in H2O(l) is H-bond and ion-induced dipole.

What is H-bond?

Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom.

It comes about as a result of the attraction between a hydrogen atom that is covalently attached to a very electronegative atom, like an N, O, or F atom, and another extremely electronegative atom.

Hydrogen is covalently joined to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.

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A key element to successful response to a chemical, biological, or radiological incident is the rapid identification of the hazard and immediate:

Answers

A key element to a successful response to a chemical, biological, or radiological incident is the rapid identification of the hazard and immediate control over all responding units.

Rapid techniques commonly used for species identification consist of species-precise primer pairs and probes, randomly amplified polymorphic DNA (RAPD), amplified fragment period polymorphisms (AFLP), restriction fragment length polymorphisms (RFLP), and karyotyping.

Elements favoring fast identity kits are reduced time in getting ready, inoculating, incubating, and cleaning up; also a convenience, decreased area for trying out and garage, ease of operation, and saving of cloth and cash are many motives for the food industry to use rapid identification structures for ordinary.

A urine lifestyle test can discover micro organism or yeast causing urinary tract contamination (UTI). If microorganisms multiply, an antibiotic sensitivity take look at can discover the antibiotic most in all likelihood to kill those specific bacteria. Your healthcare issuer may additionally order a urine tradition if you get persistent or difficult-to-deal with UTIs.

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Mercury (Hg) is present in trace amounts in coal, ranging from 50.0 to 200.0 ppb. A typical power plant burns 1.49 million tons of coal per year. Calculate tons of mercury in the coal based on the lower (50.0 ppb) and higher (200.0 ppb) concentrations.

Answers

Answer and Explanation:

To calculate this, simply use an equality of proportions:

50 particles  :  1 billion particles = x tons  :  1.49 million tons

The value of x can be solved for by multiplying the ratio on the left by the value 1.49 million / 1 billion:

So, x = (50)(0.00149) tons = 0.0745 tons

Then, do the same thing for the larger concentration:

x = (200)(0.00149) tons = 0.298 tons

Complete each row of the table below by filling in the missing prefix or missing exponent.

Answers

The given question is based on the concept of conversion factor

1 KL = 10³ L, 1cL = 10⁻³ L, 1dL = 10⁻² L, 1 nL = 10⁻⁹ L

What is Conversion factor ?

A conversion factor is an expression for the relationship between units that is used to change the units of a measured quantity without changing the value.

A conversion ratio (or unit factor) always equals one (1), where the numerator and the denominator have the same value expressed in different units.

Hence, The complete filled table is given as follows ;

1 KL = 10³ L,

1cL = 10⁻³ L,

1dL = 10⁻² L,

1 nL = 10⁻⁹ L

Where,

KL is KilolitrecL is centilitredL is decilitrenL is nanolitre

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PLEASE HELP ASAP!! How many grams of AgNO3 would react with 24 grams of Mg?

Answers

Answer: [tex]340gAgNO_{3}[/tex].

Explanation:

You will need to create a stoichiometric equation with the information given. The formula is in the problem and so are the molar masses. I will add and plug in the data for you below.

[tex]24gMg*\frac{1molMg}{24gMg} *\frac{2molAgNO_{3} }{1molMg} *\frac{170gAgNO_{3}}{1molAgNO_{3}} =340gAgNO_{3}[/tex]

I plugged the numbers into my scientific calculator, which is how I got the answer. I also added the letters in the formula above because you have to be able to cancel them out so you can find your missing data.

Therefore, [tex]340gAgNO_{3}[/tex] would react with 24gMg.

I hope this helps! Pls give brainliest!! :)

[tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Create a stoichiometric equation with the information given.

[tex]24g Mg X \frac{1 mol of Mg}{24g Mg} X \frac{2 mol of AgNO_3}{1 mol of Mg} X \frac{170g AgNO_3 }{1 mol AgNO_3} = 340g AgNO_3[/tex]

[tex]340g AgNO_3[/tex]

Hence, [tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

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If a gas at 25.0 °C occupies 3.60 liters at a pressure of 1.00 atm, what will be its
volume at a pressure of 2.50 atm?

Answers

Answer:

the volume of the gas at 2.50 atm pressure is equal to 1.44 Litres.

Explanation:

Use the periodic table to identify the element indicated by each electron configuration by typing in the
chemical symbol for the element.
1s22s22p6:
1s22s22p63s23p3:
1s22s22p53s23p54s1:
1s22s22p53s23p64s2308:
1s?2s?2p53s23p54s23d104p65s24d3:

Answers

Answer:

1s22s22p6: Neon (Ne)

1s22s22p63s23p3: Phosphorous (P)

1s22s22p63s23p64s1: Potassium (K)

1s22s22p63s23p64s2(im not sure what 308 is supposed to be): Calcium (Ca)

1s22s22p63s23p64s23d104p65s24d3: there is no pure element that ends 4d3 that I know of so this can either be Zirconium(Zr) if it ends in 4d2 or Niobium (Nb) if it ends in 4d4

Explanation:

you can look at the periodic table and the trends to find the rough idea of where the electron configuration ends, there are helpful articles and images on these, i attached an image that may help. After that you can look at the atomic number to find the number of electrons for a pure element and use the electron subshell pattern thing to find the exact number

Explai how you would find out that carbondioxide and watervapor are formed when acandleburns.

Answers

Candle wax is made up of several hydrocarbons with the general formula [tex](CH_2)_n[/tex] , where n is a large number.

Hydrocarbon's on reaction with oxygen forms carbon-dioxide and water vapor. This is called combustion reaction.

                                   [tex](CH_2)_n + O_2 \rightarrow CO_2 + H_2O[/tex]

To find out that carbon-dioxide and water vapor are formed when a candle burns -With duct tape, you can secure the candle to the bowl's base.Water should be added to the bowl until it reaches the candle's top. Don't let the wick become submerged, please!Now you can cover the bowl with transparent lid.

After few minutes, you will observe that the transparent lid is now opaque and there are traces of water deposited on the surface of lid.

Conclusion -  the lid is opaque due to the carbon-dioxide formed and water vapors are condensed on the surface of lid.

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What scientist first developed an equation to calculate the wavelengths of lines in the emission spectrum of hydrogen atoms?.

Answers

Answer:

Swedish physicist Johannes Rydberg

Explanation:

If the number is not a proper coefficient, how would you make it one?

Answers

i’m pretty sure you add, multiply, subtract, & divide

What is one property of salts?
OA. They have a low pH.
O B. They are neutral.
O C. They have a high pH.
OD. They are very reactive.

Answers

B, but keep in mind the element sodium is very reactive (though table salts, on the other hand, are not).

0.546 g sample of pure oxalic acid (H2C2O4) crystals is dissolved in water and titrated with 22.40 mL of a potassium hydroxide solution. What is the molarity of the KOH(aq)

Answers

The molarity of KOH is 0.2678 moles/L.

What is the molarity(M)?The number of moles of solute per liter of solution is known as Molarity.The formula to find the molarity is;

           Molarity(M) = number of moles/ volume of solutions in liter.

Define mole?The amount of a substance that contains exactly [tex]6.02214076\times10^{23}[/tex]elementary entities of the given substance can be defined as a mole.The formula to find the number of moles of a substance is;

      Number of moles(n) = mass of the substance/Molar mass

The mass of Oxalic acid is 0.546g.

The molar mass of Oxalic acid [tex]H_{2}C_{2}O_{4}[/tex] is 90g (1*2+12*2+16*4=90)

The number of moles of Oxalic acid is,

n = 0.546/90

n = 0.006 moles

So, the number of moles of Oxalic acid is 0.006 moles.

The volume of KOH is 22.40mL = 22.40*1000 = 0.0224L

Therefore the molarity of KOH is,

M = number of moles/ volume of solutions in liter

M = 0.006/0.0224

M = 0.2678 moles/L

Therefore, the molarity of KOH is 0.2678 moles/L

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BRAINLIST ASAP!!! Acid catalyzed dehydration-condensation reactions of carboxylic acids and alcohols produce chemicals called esters.
i. Using carbon skeletal notation, write the dehydration-condensation reaction that occurs between ethanol and butanoic acid
ii. What is the name of this ester?

Answers

The dehydration-condensation reaction occurs between 'ethanol' and 'butanoic acid' giving an ester called as "ethyl butanoate".

What is an ester and how it is formed?

Esters are produced when carboxylic acids are heated with alcohols in the presence of an acid catalyst.

The catalyst is usually concentrated sulphuric acid.

Dry hydrogen chloride gas is used in some cases, but these tend to involve aromatic esters (ones containing a benzene ring).

Esters are represented by the formula RCOOR', where R and R' are hydrocarbon groups.

The chemical reaction occurring in the formation of the ester is known as an esterification reaction.

The reaction that occurs between ethanol and butanoic acid:

Ethanol reacts with butanoic acid in the presence of an acid-catalyst and gives ethyl butanoate as ester and water as products. If an acid reacts with a base, salt and water are the products. But ester is not a salt.

i) The carbon skeletal notation for the given reaction is shown below.

ii) The ester is named "ethyl butanoate".

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in diamond carbon atoms are bonded together by extended covalent bonds? what type of solid is diamond?

Answers

Diamond is a network solid.

In diamond, carbon atoms are bonded together by extended covalent bonds. Each carbon atom forms four strong covalent bonds with its neighboring carbon atoms, creating a three-dimensional network of carbon-carbon bonds throughout the crystal lattice.

Diamond is a type of solid known as a covalent network solid. In covalent network solids, the atoms are held together by a network of strong covalent bonds, extending throughout the entire crystal structure. This results in a very rigid and hard material with high melting and boiling points.

Other examples of covalent network solids include graphite and quartz. Due to its strong and interconnected carbon-carbon bonds, diamond is renowned for its exceptional hardness and is one of the hardest known naturally occurring materials.

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How many individual oxygen atoms are contained in a sample of P2O5 that also
contains 0.620 moles of P? (Input your answer with scientific notation using "e-
notation and report your answer to two places past the decimal point. Moodle is
looking for a number only, no units.)

Answers

Answer:

Explanation:

Equation with given

P2O5      ====> 2P^5 + 5O-2

                          0.620     x

Solution

What you are going to do first is find the molar amount of oxygen. Use a proportion to do this

2/0.620 = 5/x                    Cross Multiply

2x = 0.620 * 5                   Divide both sides by 2

2x/2 = 0.620 *5/2

x = 0.310 * 5                      Combine

x = 1.55                              moles of oxygen.

Now comes the answer. How many atoms are there in 1.55 moles of oxygen?

1 mole of anything contains 6.02 * 10^23 items of  that mole

1.55 moles of oxygen contains x  atoms of oxygen

1/1.55 = 6.02 * 10^23 / x                  Cross multiply

1*x = 1.55 * 6.02*10^23                    Combine

x = 9.331 e 23

Answer

9.33e23

There are several ways to model a compound. One type of model is shown.

4 C's are connected in a line by 3 black lines. The C on the left has 3 H's attached to it each by a black line. The next C has 1 H attached by a black line and 1 O attached by 2 black lines. The next C has 2 H's attached to it by 1 black line each. The last C has 2 H's attached to it by 1 black line each and 1 O attached by a single black line. That O has an H attached to it by 1 black line.
What is the chemical formula for the molecule represented by the model?

CHO
C4H9O2
C4H8O
C3H8O2

Answers

The chemical formula will be  [tex]C_4H_9O_2[/tex].

Chemical formula

From the model, there are a total of 4 carbon atoms, 9 hydrogen atoms, and 2 oxygen atoms.

All the atoms are bonded to each other accordingly.

Thus, the only plausible chemical formula for the compound is [tex]C_4H_9O_2[/tex]

All other available options fall short in one way or the other as far as the number of atoms of each element in the compound is concerned.

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Calculate the work (KJ) done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

Answers

-31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

How to calculate the work done on or by a gas ?

It is represented by the equation

W = PΔV

where,

W = Work done

P = Pressure

ΔV = Change in volume (V₂ - V₁)

Now put the values in above formula we get

W = PΔV

    = 4.4 atm × (13 L - 83 L)

    = 4.4 atm × (-70 L)

    = -308 atm L

Now change L atm into J

= -308 × 101.3 J     [L × atm = 101.3 J]

= -31200.4 J

= -31200.4 × 10⁻³ kJ

= -31.2 kJ

Thus from the above conclusion we can say that -31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

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