What mirror diameter gives 0.1 arc second resolution for infrared radiation of wavelength 2 micrometers?

Answers

Answer 1

Answer:

The diameter of mirror [tex] 5\times10^{-6}\ m[/tex]

Explanation:

Given that,

Wavelength = 2 μm

Resolution = 0.1

We need to calculate the diameter of mirror

Using formula of resolution

[tex]resolution=0.25\times\dfrac{wavelength}{diameter}[/tex]

[tex]diameter =0.25\times\dfrac{wavelength}{resolution}[/tex]

Put the value into the formula

[tex]diameter=0.25\times\dfrac{2\times10^{-6}}{0.1}[/tex]

[tex]diameter = 0.000005\ m[/tex]

[tex]diameter = 5\times10^{-6}\ m[/tex]

Hence, The diameter of mirror [tex] 5\times10^{-6}\ m[/tex]


Related Questions

Bacteria vary somewhat in size, but a diameter of 1.9 m is not unusual.A. What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical?
B. What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?

Answers

Answer:

Volume = 3.6 x 10^-12 cm^3

Area = 1.1 x 10^-5 mm^2

Explanation:

The diameter of the bacteria that is in the shape of spherical = 1.9 m  

Now we have to find the volume of the bacteria. So, use the below formula to find the volume of bacteria.

Volume = (4πr^3) / 3

Volume = (4/3)* π*(1.9*10^-6 / 2)^3  

Volume = 3.6 x 10^-18 m^3  

Volume = 3.6 x 10^-12 cm^3

Now find the surface area.

The surface area = 4πr^2

Area = 4  π  (1.9/2)62  

Area = 1.1 x 106-11 m^2  

Area = 1.1 x 10^-5 mm^2

Calculate the angle θ between the radius-vector of the point and the positive x axis (measured counterclockwise from the positive x axis, within the limits of −180◦ to +180◦ ). Answer in units of ◦

Answers

The point obviously is in the 3rs quadrant

So

စ= tan^-1( y/x)-180

စ= -89.7°

The angle θ between the radius-vector of the point and the positive x axis is -89.7°

What is radius vector?

Radius vector is defined as the length of the line that connects a stationary point to a moving point.

It can be defined as a line connecting a circle's center to a particle's location on its circumference.

It can also be defined as the straight line connecting two bodies moving in relative orbits, such as the path a planet takes to reach the sun at any given point along its orbit.

It is also known as position vector or location vector.

The unit vector pointing radially outward from the origin is the gradient of the position vector's length. It is typical for the spheres that are centered on the origin to have level surfaces.

Evidently, the location is in the third quadrant.

So, θ= tan⁻¹ (y / x) - 180

θ= - 89.7°

Thus, the angle θ between the radius-vector of the point and the positive x axis is -89.7°

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.A full length image of a distance tall building can definitely be seen by using

Answers

Answer:

a full length of image of a distance tall building can definitely be seen by using telescope

PLEASE HELP! BRAINLIEST! The three main areas of science each contribute to forensic science in unique ways. Using your own words, write a paragraph (five or more sentences) to describe how biological sciences, chemical sciences, and physical sciences can contribute to the analysis of a crime scene. Please provide specific examples for each. Proper grammar, spelling, and sentence structure are expected.

Answers

Explanation:

Explanation:Those interested in working with trace evidence, such as glass, hairs, and gunshot residue, should focus on instrumentation skills and take courses in geology, soil chemistry, and materials science. If forensic biology, such as DNA analysis, is preferred, take microbiology, genetics, and biochemistry courses. Those interested in the toxicological aspects of this work, such as obtaining and interpreting toxicology reports, should study physiology, biochemistry, and chemistry.

change-22^0f to kelvin?​

Answers

Answer:

The formula is kelvin = (tempature in farenheit-32) ÷ 1.8 +273.15

So it will be (-22-32) ÷ 1.8 +273.15= 243.15 kelvin

Answer:

T(K) = (T(°F) + 459.67)× 5/9

answer is 243.15

A cross-country skier can complete a 7.5 km race in 45 min. What is the skier’s average speed?

Answers

Answer:

Speed = 10 km/hr

Explanation:

Speed = Distance / Time

Since we have to convert it into minutes to hours ( because it is km/hr )

45 minutes = 0.75 hours

Therefore,

Speed = 7.5 / 0.75

           = 10 km/hr

Hope it helps!

Answer:

10

Explanation:

In a ballistic pendulum experiment, suppose the digital timer shows 0.02 s for the time of flight of the projectile. The manufacturer information about the precision of the timer is nowhere to be found. What error would you quote on your measurement

Answers

Answer:

The  value is  [tex]\Delta t  =  0.01 \ s[/tex]

Explanation:

From the question we are told that

   The time of flight is  [tex]T  =  0.02 \  s[/tex]

Given that the value of the time of flight is in three decimal place then the error quote is

     [tex]\Delta t  =  0.01 \ s[/tex]

What do you think is the
difference between
speed and acceleration?
What do you think is the
difference between mass
and weight?

Answers

I believe speed is how fast your going and acceleration is how fast your going in a amount of time don’t know if I’m right but I think it’s correct. Don’t know about the next question though sorry

A sailboat took 25 hours to cover 1/4 of a journey. Then, it
covered the remaining 144 miles in 3.5 hours. What was the
average speed for the whole journey?
mph

Answers

Answer:

32

Explanation:

The average speed of the car for the remaining is  32 miles/h.

What is average speed?

The average speed of any moving object is the ratio of the total distance covered and the total time taken to cover that distance.

Average Speed S= distance /time

Given is a sailboat took 2.5 hours to cover 1/4 of a journey. Then, it covered the remaining 144 miles in 3.5 hours.

If x be the total distance covered during journey, then

3/4 x = 144

x = 192 miles

The total time taken for journey is 2.5 +3.5 = 6 h

The average speed for the whole journey is

Avg speed S= 192 / 6

S = 32 miles/h

Thus, the average speed of the car for the remaining is  32 miles/h.

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all digits shown on the measuring device, plus one estimated digit. are consided what

Answers

Answer:

The significant figures in a measurement consist of all the certain digits in that measurement plus one uncertain or estimated digit. In the ruler illustration below, the bottom ruler gave a length with 2 significant figures, while the top ruler gave a length with 3 significant figures.

Explanation:

A cylindrical flask is fitted with an airtight piston that is free to slide up and down. A mass rests on the top of the piston. The initial temperature of the system is 313 K and the pressure of the gas is held constant at 137 kPa. The temperature is now increased until the height of the piston rises from 23.4 cm to 27.0 cm.What is the final temperature of the gas?

Answers

Answer:

T2 = 361.15 K

Explanation:

Since pressure is held constant, then we'll use Charles law

Charles law gives that V1/T1 = V2/T2

We are given;

Initial temperature; T1 = 313 K

Initial height; h1 = 23.4 cm

Final height; h2 = 27.0 cm

Now, formula for volume of a cylinder is V = πr²h

V1 = πr²h1 and V2 = πr²h2

Now, since V1/T1 = V2/T2 and we are looking for T2, let's make T2 subject;

T2 = (V2 × T1)/V1

Plugging in the relevant values gives;

T2 = (πr²h2 × 313)/πr²h1

πr² will cancel out to give;

T2 = (h2 × 313)/h1

Putting 23.4 for h1 and 27 for h2 gives;

T2 = (27 × 313)/23.4

T2 = 361.15 K

1. A signal source has an open-circuit voltage of 1V, and a short-circuit current of10mA. What is the source resistance

Answers

Answer:

100 Ω

Explanation:

Given that

Open circuit voltage, V = 1 V

Short circuit current, I = 10 mA

Source resistance R, = ?

This is rather a straight forward question. Remember Ohms Law? Current being directly proportional to the voltage and inversely proportional to the resistance?

Yeah, that's the formula we'd be using.

Ohms Law states that V = IR, and thus, if we make R subject of the formula, we have

R = V / I, on substituting the values, we have

R = 1 / 10*10^-3

R = 1 / 0.01

R = 100 Ω

Kassie is 7. She completes exactly two of the 15 arithmetic problems she has been assigned for homework
before starting a video game. Kassie's behavior BEST exemplifies:

Answers

Answer: Procrastination, Defiance, Laziness

Explanation:

Answer: impulsiveness

Explanation:

i NED HELP i’m so confused

Answers

i need points to skip the video i’m sry

Consider a metal rod of uniform temperature. Is it possible that heat spontaneously flow from one end of the rod to the other end so that they end up in different temperatures? Why?

Answers

Answer:

No its not possible in that yes heat flow is due to temperature different but with time equilibrium in temperature is reached hence there is no temperature difference at both ends at this time

An athlete completes a round of circular tract with diameter 150 m in 5 min. What is the average speed V of the athlete in m/s? Answer with two decimal places

Answers

Answer:

Explanation:

From the question we are told that

 The diameter is [tex]d = 150 \ m[/tex]

  The time taken is  [tex]t = 5 \ min = 300\ s[/tex]

   

Generally the circumference is mathematically represented as

     [tex]C =  d  *  \pi[/tex]

     [tex]C =  150 *  3.142[/tex]

     [tex]C =  471.3 \  m[/tex]

The average speed is mathematically represented as

      [tex]v  =  \frac{C}{ t}[/tex]

     [tex]v  =  \frac{471.3}{300}[/tex]

    [tex]v =  1.571 \  m/s[/tex]

Manganese-52 has a half-life of 6 days. How many days would a scientist have to wait for the radioactivity to be 12.5% the starting amount?

Answers

Answer:

Let N = N0 where N0 is the number of atoms originally present.

In 6 days    N = N0 / 2

In 12 days   N = N0 / 4

In 18 days   N = N0 / 8    = .125 N0

So it would take 18 days.

Manganese-52 has a half-life of 6 days. a scientist has to wait 18 days for the radioactivity to be 12.5% of the starting amount

What is radioactivity?

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity. This radiation is released when a nucleus undergoes radioactive decay and transforms into a different isotope that may be radioactive (unstable) or non-radioactive depending on the number of neutrons and protons in the nucleus (stable).

As given in the problem statement Manganese-52 has a half-life of 6 days. this means after 6 days Manganese-52 will reduce to its half value

similarly, after 12 days it further reduces to 50% of the previous value which would be 25 %

Similarly, after 18 days, it will reduce 50% from the previous value which comes out to be 12.5 %

Thus, The half-life of manganese-52 is 6 days. It takes 18 days for the radioactivity to drop to 12.5% of the initial level.

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the pressure of a gas is 100.0kpa and its volume is 500.0ml if the volume increase to 1000.0ml what is the new pressure of the gas

Answers

50Kpa

Explanation:

P1V1 = P2V2

Where;

P1= 100. P2= ?

V1 = 500. V2 = 1000

100 × 500 = P2 × 1000

50000 = 1000P2

50000/1000 = P2

50 = P2

P2 = 50Kpa

You are an engineer in charge of designing a new generation of elevators for a prospective upgrade to the Empire State Building. Before the state legislature votes on funding for the project, they would like you to prepare a report on the benefits of upgrading the elevators. One of the numbers that they have requested is the time it will take the elevator to go from the ground floor to the 102nd floor observatory. They are unlikely to approve the project unless the new elevators make the trip much faster than the old elevators. If state law mandates that elevators cannot accelerate more than 2.40 m/s2 or travel faster than 18.8 m/s , what is the minimum time in which an elevator can travel the 373 m from the ground floor to the observatory floor

Answers

Answer:

   t_total = 23.757 s

Explanation:

This is a kinematics exercise.

Let's start by calculating the distance and has to reach the limit speed of

v = 18.8 m / s

         v = v₀ + a t₁

the elevator starts with zero speed

         v = a t₁

         t₁ = v / a

         t₁ = 18.8 / 2.40

         t₁ = 7.833 s

in this time he runs

         y₁ = v₀ t₁ + ½ a t₁²

         y₁ = ½ a t₁²

         y₁ = ½ 2.40 7.833²

         y₁ = 73.627 m

This is the time and distance traveled until reaching the maximum speed, which will be constant throughout the rest of the trip.

           x_total = x₁ + x₂

           x₂ = x_total - x₁

           x₂ = 373 - 73,627

           x₂ = 299.373 m

this distance travels at constant speed,

           v = x₂ / t₂

           t₂ = x₂ / v

           t₂ = 299.373 / 18.8

           t₂ = 15.92 s

therefore the total travel time is

           t_total = t₁ + t₂

           t_total = 7.833 + 15.92

           t_total = 23.757 s

"Find the total weight of an 18-ft3 tank of oxygen if the oxygen is pressurized to 184 psia, the tank itself weighs 150 lbf, and the temperature is 95°F."

Answers

Answer:

Explanation:

1 psi = 6894.76 Pa

P = 184 psi = 12.686 x 10⁵ Pa .

Temperature T = 95⁰F = 35⁰C= 308 K

volume V = 18 ft³ = 18 x 0.0283168 m³

= .51 m³

From the gas law

PV/RT = n where n is mole of gas

= 12.686 x 10⁵ x  .51  / 8.31 x 308

= 252.78 gm mole

= 252.78 x 32 gm

= 8.08896 kg

= 2.20462 x 8.08896 lb

= 17.833 lb

= 17.833 / 32 lbf

= .5573 lbf

weight of tank = 150 lbf

Total weight = 150 + .5573

= 150.5573 lbf .

3)What are the "bright stars" that seem to move against the sky? Are they really stars? What are they?

Answers

i think they’re called meteors?

1)Determine, in terms of unit vectors, the resultant of the five forces illustrated in the figure, Consider F1=20 N, F2= 12 N, F3=17 N. F4=15N and F5=9N

2)In the situation illustrated below, two blocks of Ma and Mb masses are suspended between two walls using ropes. If Ma=2kg, calculate the tension developed in the segments AB, BC and CD and the mass of block B for the equilibrium condition

3)In the figure below, the crane and its AB jib have together 390kg and center of mass in G1. If the 90kg BCD cage and the 80kg man have center of mass located in G2 and G3, respectively, (a) calculate the angle θ of inclination of the boom for which the crane is on the eminence of tumbling. (b) for which size the boom should be reduced (retracting its point B) so that it can be positioned horizontally (θ=0) and the crane does not tip over. Consider that the cage always stays in the horizontal position

4) A 1.7kg plate with center of mass in G is supported by a bar and three cables, as shown in the figure below. Determine the voltage developed in the AB, AC and DE cables and the reaction (there is only one) at point O for the equilibrium condition

Answers

Explanation:

1) F₁ lies in a plane perpendicular to the xy plane, 60° from the x axis.  The angle between F₁ and the +z axis is 30°.  Therefore, the vector is:

<F₁> = 20 (sin 30° cos 60° i + sin 30° sin 60° j + cos 30° k)

<F₁> = 20 (¼ i + ¼√3 j + ½√3 k)

<F₁> = 5 i + 5√3 j + 10√3 k

F₂ is in the xy plane.  Its slope is -24/7.  The vector is:

<F₂> = 12 (-⁷/₂₅ i + ²⁴/₂₅ j + 0 k)

<F₂> = -3.36 i + 11.52 j

F₃ is parallel to the +x axis.  The vector is:

<F₃> = 17 (i + 0 j + 0 k)

<F₃> = 17 i

F₄ is parallel to the -z axis.  The vector is:

<F₄> = 15 (0 i + 0 j − k)

<F₄> = -15 k

F₅ is in the xy plane.  It forms a 15° angle with the -y axis.  The vector is:

<F₅> = 9 (-sin 15° i − cos 15° j + 0 k)

<F₅> = -9 sin 15° i − 9 cos 15° j

The resultant vector is therefore:

<F> = (5 − 3.36 + 17 − 9 sin 15°) i + (5√3 + 11.52 − 9 cos 15°) j + (10√3 − 15) k

<F> = 16.31 i + 11.49 j + 2.32 k

2) Sum of forces at point B in the x direction:

∑F = ma

Tbc cos 40° − ¹⁵/₁₇ Tab = 0

Tbc cos 40° = ¹⁵/₁₇ Tab

Tbc = 1.15 Tab

Sum of forces at point B in the y direction:

∑F = ma

Tbc sin 40° + ⁸/₁₇ Tab − mAg = 0

Tbc sin 40° + ⁸/₁₇ Tab = (2 kg) (10 m/s²)

(1.15 Tab) sin 40° + ⁸/₁₇ Tab = 20 N

1.21 Tab = 20 N

Tab = 16.52 N

Tbc = 19.02 N

Sum of forces at point C in the x direction:

∑F = ma

Tcd sin 25° − Tbc cos 40° = 0

Tcd sin 25° = Tbc cos 40°

Tcd = 1.81 Tbc

Tcd = 34.48 N

3(a) When the crane is on the verge of tipping, the center of gravity is directly over point F.  Relative to point A:

3.7 m = [ (390 kg) (0.9 m) + (90 kg) (9 m cos θ + 1.7 m) + (80 kg) (9 m cos θ + 2.9 m) ] / (390 kg + 90 kg + 80 kg)

2072 kgm = 351 kgm + 810 kgm cos θ + 153 kgm + 720 kgm cos θ + 232 kgm

1336 kgm = 1530 kgm cos θ

θ = 29.17°

3(b) 3.7 m = [ (390 kg) (0.9 m) + (90 kg) (x + 1.7 m) + (80 kg) (x + 2.9 m) ] / (390 kg + 90 kg + 80 kg)

2072 kgm = 351 kgm + (90 kg) x + 153 kgm + (80 kg) x + 232 kgm

1336 kgm = (170 kg) x

x = 7.86 m

4) Find the lengths of the cables.

Lab = √((2 m)² + (3 m)² + (5 m)²)

Lab = √38 m

Lac = √((2 m)² + (3 m)² + (5 m)²)

Lac = √38 m

Lde = √((2 m)² + (3 m)²)

Lde = √13 m

Sum of forces in the x direction:

∑F = ma

-5/√38 Fab − 5/√38 Fac − 2/√13 Fde + Rx = 0

Sum of forces in the y direction:

∑F = ma

2/√38 Fab − 2/√38 Fac = 0

Fab = Fac

Sum of forces in the z direction:

∑F = ma

3/√38 Fab + 3/√38 Fac + 3/√13 Fde − mg = 0

Sum of moments about the y-axis:

∑τ = Iα

(3/√38 Fab) (5 m) + (3/√38 Fac) (5 m) + (3/√13 Fde) (2 m) − (mg) (2 m) = 0

Substitute Fab = Fac and simplify:

6/√38 Fab + 3/√13 Fde − mg = 0

30/√38 Fab + 6/√13 Fde − 2mg = 0

Double first equation:

12/√38 Fab + 6/√13 Fde − 2mg = 0

Subtract from the second equation:

28/√38 Fab = 0

Fab = 0

Fac = 0

Solve for Fde:

3/√38 Fab + 3/√38 Fac + 3/√13 Fde − mg = 0

3/√13 Fde = mg

3/√13 Fde = (1.7 kg) (10 m/s²)

Fde = 20.43 N

Solve for Rx:

-5/√38 Fab − 5/√38 Fac − 2/√13 Fde + Rx = 0

Rx = 2/√13 Fde

Rx = 11.33 N

A plastic wire is wind on a wheel on a radius 3 cm. The whole system is initially at rest. A force is applied on the plastic wire and the wire unwinds from the wheel from its axis of rotation. The wheel is given an angular acceleration of 92.00 rad/s2 for:______.

Answers

Answer:

The torque of the wheel is 0.92 N-m.

Explanation:

Given that,

Radius of wire = 3 cm

Angular acceleration = 92.00 rad/s²

Suppose, Mass of wheel is 4 kg and radius is 5 cm. find the torque of the wheel.

We need to calculate the torque of the wheel

Using formula of torque

[tex]\tau=I\alpha[/tex]

[tex]\tau=MR^2\times\alpha[/tex]

Where, M = mass of wheel

R = radius of wheel

[tex]\alpha[/tex] = angular acceleration

Put the value into the formula

[tex]\tau=4\times(5\times10^{-2})^2\times92[/tex]

[tex]\tau=0.92\ N-m[/tex]

Hence, The torque of the wheel is 0.92 N-m.

Daniel has a bill of 2750 on his credit card. If interest is charged at a rate of 15% p.a., calculate the amount of interest that Daniel must pay for the month?

Answers

Answer:

412.5

Explanation:

all you have to do is multiply .15

A softball player is testing her physics knowledge and tosses a softball upward from the top of a building. The building is 100 m tall and the ball starts with a velocity of 10 m/s.a. What is the maximum height the ball reaches and at what time? b. How much time does it take for the ball to go from h=50 m to h=0 m on the way down? c. What is the velocity when h=50 m?

Answers

Answer:

Explanation:

We shall apply newton's laws formula

a )

initial velocity in upward direction u = 10 m/s

acceleration due to gravity g = 9.8/ m .s²

Let h be the maximum height where v = o

v² = u² - 2gh

0 = 10² - 2 gh

h = 10² / 2g

= 10² /  2  x 9.8

= 5.10 m

Since the ball was thrown from height of 100 m , total maximum height of ball

= 100 + 5.10

= 105.10 m

Let t be the time taken

v = u - gt

0 = 10 - gt

t = 10 / 9.8

= 1.02 s

b )

when h = 50 on its way downwards , velocity

v² = u² + 2 g s  

v² = 0 + 2 x 9.8 x ( 105.10 - 50 )

[  distance travelled by ball at this point from top = 105.1 - 50 = 55.10 ]

v = 32.86 m / s

Let us find out final velocity of touching the ground . For it distance travelled = 105.10

v² = u² + 2gh

v² = 0 + 2 x 9.8 x 105.1

v = 45.39 m /s

Now velocity at h = 50 is 32.86

velocity at h = 0 is 45.39

time taken to travel fro h = 50 to h = 0

v = u + gt

45 .39 = 32.86 + 9.8 x t

t =  1.28 s .

What is the potential difference ΔVAB Δ V A B ? Express your answer with the appropriate units. problem 21.19

Answers

Answer:

30

Explanation:

A particle moves along the x-axis according to the equation
S = 4+6t-2t^2
where S is in meters and t is in seconds. At t = 3.0 s, calculate
(a) the position of the particle
(b) its instantaneous velocity
(c) its instantaneous acceleration.​

Answers

Answer :

◈ A particle is moving along the x-axis according to the equation

S = 4 + 6t - 2t²

____________________________

Position at t = 3s :

➝ S = 4 + 6t - 2t²

➝ S = 4 + 6(3) - 2(3)²

➝ S = 4 + 18 - 18

S = 4m

Instantaneous velocity at t = 3s :

➝ v = dx/dt = d(4 + 6t - 2t²)/dt

➝ v = 6 - 4t

➝ v = 6 - 4(3)

➝ v = 6 - [tex]\sf{12}[/tex]

v = -12m/s

Instantaneous acc. at t = 3s :

➝ a = dv/dt = d(6 - 4t)/dt

a = -4m/s²

[Acceleration does not depend on time]

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11 m.
A) Find the magnitude of the electric force exerted on each particle.B) If this force causes the centripetal acceleration of the electron, what is the speed of the electron?

Answers

Answer:

Explanation:

Force between two charged particle having charge q₁ and q₂ at distance r

F = k q₁ x q₂ / r²

Putting the values

F = 9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹ / 5.29² x 10⁻²²

= .823 x 10⁻⁷

= 823 x 10⁻¹⁰ N

This force will apply on both the charges and will be attractive in nature .

B )

Let speed of electron be v

centripetal force on electron = F

m v² / r = 823 x 10⁻¹⁰

putting the values for electron

9.1 x 10⁻³¹ x v² / 5.29 x 10⁻¹¹ = 823 x 10⁻¹⁰

v² = 478.42 x 10¹⁰

v = 21.87 x 10⁵ m /s

what is a hypothisis​

Answers

Answer:

a precise, testable statement of what the reseatcher predict will be the outcome of the study

Explanation:

Answer:

supposition or proposed explanation

Explanation:

its made on the basis of limited evidence as a starting point for further investigation.

The unknown vector v satisfies b - v = λ and b x v-c, where λ, b, and c are fixed and known. Find v in terms of λ, b, and c.

Answers

The conditions satisfied by the unknown vector.
Other Questions
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