From the calculation, there are 1.5 g of water produced in the reaction.
What is an equation?An equation shows the chemical transformation that takes place in a reaction vessel. In this case, the equation is; C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O.
Now;
Number of moles of glucose = 2.5g/180 g/mol = 0.014 moles
Since 1 mole of glucose produces 6 moles of water
0.014 moles of glucose produces 0.014 moles * 6 moles/ 1 mole
= 0.084 moles
Mass of water produced = 0.084 moles * 18 g/mol = 1.5 g of water
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if 185 g of wax c22h44 burns how many litres of oxygen gas were used up assume the conditions in the lab are 101kpa and 25 degree celcius
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 101kpa =0.996792 atm
V= ?
R=[tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=25 +273 =298 K
Moles =?
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{185 g }{308.6}[/tex]
Moles =0.56
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]0.56= \frac{0.996792\;atm\; X \; V }{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
13.73 L =V
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
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13. Use mole ratios to identify the limiting reagent in the following reaction: 3.10 mol of sodium mixes with 4.17 mol of water to form sodium hydroxide and hydrogen gas.
14. Determine the number of excess moles of the excess reagent in the following reaction: 4.80 mol of calcium mixing with 3.55 mol of oxygen gas, making calcium oxide.
13) The limiting reagent is water.
14) Oxyge is in excess by 1.15 mol
Limiting reagent13) According to the equation of the reaction:
[tex]2Na + 2H_2O --- > 2NaOH + H_2[/tex]
The mole ratio of the reactants is 1:1.
But 3.10 mol of sodium and 4.17 mol of water were reacted. Thus, water is in excess while sodium is limiting.
14) [tex]2Ca + O_2 --- > 2CaO[/tex]
Mole ratio of reactants = 2:1
4.80 mol Ca and 3.55 mol oxygen were reacted. Thus, oxygen is in excess.
Excess oxygen = 3.55 - 4.80/2 = 1.15 mol
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A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section be? *
Each section would be 230 centimeters or 2.30 meters long.
Sectional divisionThe original wood pole is 12 meters long.
12 meters = 12 x 100 = 1200 centimeters
It is to be cut into 5 equal sections: 1200/5 = 240 centimeters
But each cut wastes 10 cm of the pole.
240 - 10 = 230 centimeters.
Thus, each section would be 230 centimeters or 2.30 meters long.
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What mass of carbon dioxide is produced by the complete combustion of 48.0 g of hexane?
The mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.
How to calculate mass?The mass of a substance can be calculated by using the stoichiometry approach.
The balanced equation of the complete combustion of hexane is as follows:
2C6H14(g) + 19O2(g) → 12CO2(g) + 14H2O(g)
48g of hexane to moles is calculated as:
48g ÷ 86g/mol = 0.56 mol
2 moles of hexane produces 12 moles of CO2
0.56 mol of hexane will produce 0.56 × 12/2 = 3.35 mol
Next, we convert 3.35 moles of CO2 to mass as follows:
3.35 moles × 44g/mol = 147.35g
Therefore, the mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.
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A mineral sample has a mass of 75 g. When the sample is dropped
into a graduated cylinder with a volume of 20mL, the volume of the
graduated cylinder rises to 40 mL. What is the density of the
sample?
Answer:
3.75 g/mL
Explanation:
Density can be calculated using the following formula:
Density = mass (g) / volume (mL)
You have been given the mass of the mineral sample (75 g). To find the volume, you need to determine the amount of space that the sample takes up when it is placed in the water. This can be done by subtracting the initial water volume from the final water volume.
Volume = Final - Initial
Volume = 40 mL - 20 mL
Volume = 20 mL
Now, you can calculate the density of the mineral sample.
Density = mass / volume
Density = 75 g / 20 mL
Density = 3.75 g/mL
Answer:
Explanation:
Givens
The volume is the tricky part of this question. You are using the graduated cylinder to measure volume. The rise in the reading of the graduated cylinder = the volume of the sample.
Volume = 40 mL - 20 mL = 20 mL
Mass = 75 grams
Formula
Density = mass / volume
Solution
Density = 75 / 20 = 3.75
Answer
Density = 3.75
Which statement is false for the balanced equation given below? (Atomic weights: N = 14.01, H = 1.008, O = 16.00). Explain your answer. 4 NH3 + 5 O2 → 4 NO + 6 H₂O a) The reaction of 4 molecules of NH3 requires 5 molecules 02 b) The reaction of one mole of NH3 requires 40 g of O2 c) The reaction of 4 moles of NH3 produces 30 g of NO d) The reaction of 17 glof NH3 will produce 27 g of water e) The reaction of 10 molecules of NH3 produces 15 molecules of H₂O
The false statement is that the reaction of 17 g of NH3 will produce 27 g of water. (Option D)
What is a balanced reaction equation?A balanced reaction equation is one in which the number of atoms of each element on the right hand side of the equation is equal to the number of atoms of the same element on the left and side of the reaction equation.
The equation of the reaction is 4 NH3 + 5 O2 → 4 NO + 6 H₂O. The number of atoms of each element on both sides are equal.
Hence, the statement that is false from the reaction equation is; "the reaction of 17 g of NH3 will produce 27 g of water".
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According to the article, puberty indicates the beginning of adolescence. How does nutrition influence the start of adolescence?
Answer:
adolescence begins according to your dietExplanation unhealthy diet brings about early or late commence of adolescence especially in girls
73 m is equal to how many dm?
It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 10^13 m³. How much heat was required
to melt the iceberg if 1 m³ of ice has a mass of 917 kg?
Answer:
3.1×10^13×917= 2842.7×10^13 kg
2842.7×10^13×334=949,461.8×10^13 KJ
Explanation:
First off you convert m³ to kg then convert Kg to Kj
The amount of heat required to melt the iceberg is [tex]9.58 * 10^{18}kJ[/tex]
Latent heat of fusion is the amount of heat required to melt an unit mass of ice.
Mass of iceberg is [tex]3.1*10^{13} m^{3} *917Kg =2.8427*10^{16} Kg[/tex]
Amount of heat required is calculated as:
[tex]2.8427* 10^{16} * 334 =9.58* 10^{18}kJ[/tex]
Hence, the amount of heat required to melt the iceberg is [tex]9.58*10^{18}kJ[/tex]
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Calculate the mass of water produced by metabolism 84.0 g of glucose
The amount of water that will be produced is 50.36 grams
Stoichiometric problemsThe metabolism of glucose is represented by the following equation:
[tex]C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)[/tex]
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
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What is the electron configuration for magnesium (Mg)?
The Periodic Table
O A. 1s²2s22p²3s6
OB. 3s 3p 304
O C. 1s²2s22p3s²
O D. 1s22s23s23p6
Magnesium has atomic no 12
Electronic configuration given by
1s²2s²2p⁶3s²Or
[Ne]3s²[tex]1s^22s^22p^63s^2[/tex] is the electron configuration for magnesium. Therefore, the correct option is option C.
The positioning of electrons within an atom is referred to as electron configuration. The distribution of electrons in each of their corresponding energy levels or orbitals is described in great detail. The notation known as the Aufbau principle is frequently used to represent the electron configuration of an atom. This theory states that electrons fill an atom's orbitals starting at the lowest energy level and moving up the energy scale. The energy level diagram, which can also be represented by a periodic table, serves as the foundation for this sequential filling. A maximum of two electrons can be held in the main level, the initial energy level, which is closest to the nucleus. [tex]1s^22s^22p^63s^2[/tex] is the electron configuration for magnesium.
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Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 30. ∘C , what is the new pressure, P2 , inside the container? Assume no change in the amount of gas inside the cylinder.
This is an exercise in the General Combined Gas Law.
To start solving this exercise, we obtain the following data:
Data:V₁ = 4.00 lP₁ = 365 mmHgT₁ = 20 °C + 273 = 293 KV₂ = 2,80 lT₂ = 30 °C + 273 = 303 KP₂ = ¿?We apply the following formula:
P₁V₁T₂=P₂V₂T₁ ⇒ General formulaWhere:
P₁=Initial pressureV₁=Initial volumeT₂=end temperatureP₂=end pressureT₂=end temperatureV₁=Initial temperatureWe clear for final pressure (P2)
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}[/tex]
We substitute our data into the formula:
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 } \end{gathered}$}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}[/tex]
Answer: The new canister pressure is 539.224 mmHg.
{ Pisces04 }What are the magnetic quantum numbers possible for a 6s subshell and for a 4f subshell? Drag the correct numbers into each of the columns.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
6s Subshell 4f Subshell
For the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
What is the magnetic quantum number?The magnetic quantum number takes on values between 0 to (n - l). It gives the orientations of the sublevels. The four types of quantum numbers are;
Principal quantum numberAzimuthal quantum numberMagnetic quantum numberSpin quantum numberFor the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
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What volume of carbon dioxide in liters could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
Do not type units with your answer
589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex])
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
[tex]C_5H_{12}(g) + 8 O_2(g)[/tex] --->[tex]5 CO_2(g) + 6 H_2O(g)[/tex]
To find the volume, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
P = pressure (atm)
V = volume (L)
n = number of moles
R = constant (0.0821 L*atm/mol*K)
T = temperature (K)
To find the volume of water vapour, you need to (1) convert grams C₅H₁₂ to moles C₅H₁₂ (via molar mass), then (2) convert moles C₅H₁₂ to moles H₂O (via mole-to-mole ratio from reaction coefficients), then (3) calculate volume H₂O (via Ideal Gas Law). The final answer should have 3 sig figs.
Molar Mass (C₅H₁₂) =72.151 g/mol
1 C₅H₁₂ (g) + 8 O₂ (g) -----> 5 CO₂ (g) + 6 H₂O (g)
228.85 g C₅H₁₂ 1 mole 6 moles H₂O
----------------------- x ---------------- x ----------------------- = 19.03 moles H₂O
72.151 g 1 mole C₅H₁₂
Moles of H₂O= 19.03
P =0.96 atm
R = 0.0821 L x atm/mol x K
V = ?
T = 362 K
n = 19.03 moles
PV = nRT
(0.96 atm)V = ( 19.03 moles)(0.0821 Latm/molK)(362K)
(0.96 atm)V = 565.575406
V = 589L
Hence, 589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex]).
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When 5ml of 30% H2O2 is decomposed into water and oxygen, how many grams of oxygen and how many grams of water are left?
The mas of the products are given below:
mass of oxygen produced = 0.7056 g of oxygenmass of water produced = 0.794 g of hydrogenHow many moles are there in 5 ml of 30% of hydrogen peroxide?The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:
Moles = concentration * volume
Molarity of 30% of hydrogen peroxide = 8.82 mol/L
Moles = 8.82 * 5/1000 = 0.0441 moles
The equation of the the decomposition of hydrogen peroxide is given as:
2 H₂O₂ -----> 2 H₂O + O₂
Based on the mole ratio;
mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen
mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen
Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.
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10. Suppose that 20.0 mL of 5.00 x 10-3 M aqueous sodium hydroxide (NaOH) is required to neutralize 10.0
mL of an aqueous solution of hydrochloric acid (HCI). Using the balanced chemical equation below,
find the molarity of the HCI solution?
NaOH (aq) + HCI (aq) → H₂O (1) + NaCl (aq)
A. 1.00 x 103 M HCI
B. 1.00 x 102 M HCI
C. 5.00 x 103 M HCI
D. 5.00 x 10-2 MHCI
Explanation:
B. 1.00 x 10^-2 M HCI
The question is asking us to find the molarity/concentration of the acid (HCl).
We have been provided with;
20.0 mL of 5.0 x 10^-³ M NaOH10.0 mL of HClWe know that molarity (M) of a solution is contained in 1 L or 1000 mL or 1000 cm³.
This means that;
5.0 x 10^-³ moles is contained in 1000 mL.
is contained in 1000 mL.X mol is contained in 20.0 mL
[tex]x \: mol \: = \frac{20 \times 5.0 \times {10}^{ - 3} }{1000} \\ = 0.0001 \: mol[/tex]
= 0.0001 moles
These 0.0001 moles is contained in 10 mL of HCl.
To find the molarity of the acid;
0.0001 moles is contained in 10 mL
x mol is contained in 1000 mL
[tex]x \: mol \: = \frac{0.0001 \times 1000}{10} \\ = 0.01 \: mol[/tex]
= 0.01 M
Therefore the Concentration of the acid (HCl) is 0.01 M or 1.0 x 10^-2 M
Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)
Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.
The theoretical yield of [tex]SnS_2[/tex] will be 4.20 grams while the percent yield will be 7.93%
How is yield calculated?From the equation of the reaction, the mole ratio of [tex]SnBr_4[/tex] to [tex]Na_2S[/tex] is 1:2.
Mole of 48.1 mL, 0.478 M [tex]SnBr_4[/tex] = 0.478 x 48.1/100 = 0.023 mols
Mole of 48.8 mL, 0.160 M [tex]Na_2S[/tex] = 0.160 x 48.8/1000 = 0.0078 moles
[tex]SnBr_4[/tex][tex]Na_2S[/tex] is the limiting reactant.
Mole ratio of [tex]SnBr_4[/tex] and [tex]SnS_2[/tex] = 1:1
Equivalent mole of [tex]SnS_2[/tex] = 0.023 moles
Mass of 0.023 noles [tex]SnS_2[/tex]= 0.023 x 182.81 = 4.20 grams
With 0.0333 g of [tex]SnS_2[/tex] recovered, percent yield = 0.333/4.2 x 100 = 7.93%
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Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)
Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.
1) Calculate the theoretical yield of SnS2. ;
2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.
ssssssssssssssssssssssssssssss
Answer:
s
Explanation:
Anna stated that ionic compounds have high melting points and low boiling points. She said that this demonstrates that ionic compounds have strong bonds because a lot of energy is needed to break the electrical forces that hold the bonds together.
Which statement best describes Anna’s error?
Strong electrical forces will make ionic compounds have high boiling points.
Strong electrical forces will make ionic compounds have weak bonds.
A low amount of energy is needed to break the bonds in ionic compounds.
Gravitational forces hold the bonds together in ionic compounds.
The statement which best describes Anna’s error is: A. strong electrical forces will make ionic compounds have high boiling points.
The type of chemical bonds.In Chemistry, there are different types of chemical bonds and these include the following:
Metallic bondsHydrogen bondsCovalent bondsIonic bondsAn ionic bond is typically characterized by electrostatic attraction that is formed between oppositely charged ions or atoms of chemical elements with different electronegativities.
In conclusion, Anna was wrong to posit that strong electrical forces makes all ionic compounds to have high boiling points.
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Answer:
✔Strong electrical forces will make ionic compounds have high boiling points.
❌Strong electrical forces will make ionic compounds have weak bonds.
❌A low amount of energy is needed to break the bonds in ionic compounds.
❌Gravitational forces hold the bonds together in ionic compounds.
Explanation:
2. Calculate the pl of the following amino acids(use their Pka values) a. Arginine b. Glutamic acid of water an c. Asparagine d. Tyrosine
pl (25*C)
Arginine -----> 10.76
Glutamic -----> 3.08
Asparagine -----> 5.43
Tyrosine -----> 5.63
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How many moles of KF would need to be added to 2500 ml of water to make 1.2 M solution?
The number of moles of KF needed to prepare the solution is 3 moles
What is molarity?Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
How to determine the mole of KF Volume = 2500 mL = 2500 / 1000 = 2.5 L Molarity = 1.2 MMole of KF =?Molarity = mole / Volume
1.2 = mole of KF / 2.5
Cross multiply
Mole of KF = 1.2 × 2.5
Mole of KF = 3 moles
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Write the formula for methionine (red = O , gray = C , blue = N , yellow = S , ivory = H ).
Express your answer as a molecular formula. Enter the elements in the order: C , H , N , O , S .
Answer:
The molecular formula of methionine is C₅H₁₁NO₂S
a radioactive nuclide that is used for geological dating has an atomic number of 19 and mass 40. what is the symbol of this nuclide?
The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
Data obtained from the questionAtomic number = 19Mass number = 40Symbol of nuclide =?How to determine the nuclideFrom the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
How to determine the symbol of the nuclideAtomic number (Z) = 19Mass number (A) = 40Name of nuclide = Potassium (K)Symbol of nuclide =?The symbol of a nuclide is given as ᴬ₂X
Where
A is the mass number Z is the atomic numberX is the symbol of the elementThus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
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Determine which of the following statements is true.
A. Larger ionic charges in a compound create stronger bonds and higher melting points.
B. Giant covalent structures have low melting and boiling points.
C. lonic bonds are weak and break easily.
D. Giant covalent structures are brittle and shatter when hit
Giant covalent structures are brittle and shatter when hit this statement is true.
Hence, Option D is correct answer.
What is Ionic Bond ?Ionic bonds is a chemical bond formed when one atom transfer its valence electron to another atom. Ionic bond is also called electrovalent bond. These bonds are stronger.
What is Giant Covalent structure ?The 3-D structure of atom which are joined by covalent bond is called giant covalent structure. Giant covalent substances are brittle and they shatter when hit because covalent bond break at once. Giant covalent structure have very high melting and boiling point.
What is Ionic charges ?A larger ionic charges in a compound makes a weaker ionic bond. The larger ions have high melting point.
Thus from the above conclusion we can say that Giant covalent structures are brittle and shatter when hit this statement is true.
Hence, Option D is correct answer.
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(ii) CH₂=C - CHCH3 Br,give the IUPAC name of the compound
Answer:
propene
Explanation:
According to the rules,the name of hydrocarbon:root word+suffix=prop+ene=propene
Hi, I am trying to calculate the dosage of mg i should be taking per night. I am 135 pounds 5’7.
I choose the lower limit 0.024 mg/kg/day
1 pound = 0.453592 kg
135 pounds = 61.235 kg
dosage/day = 0.024 x 61.235 = 1.47 mg
Answer:
See below
Explanation:
I will use the approximate AVERAGE
of the dosage range ~ .20 mg/kg/week
135 pounds = 61.23 kg
Now , for SEVEN days/week dosing:
61.23 kg * .20 mg/kg-wk / 7 days/week = 1.75 mg/day
if the rate of infusion
PLEASE HELP!!!
What is the correct net ionic reaction for Pb(NO3)2(aq) +2NaI(aq) → PbI2(s) + 2NaNO3(aq)?
The net ionic equation of the reaction is:
Pb²⁺aq) + 2 I(aq) → PbI2(s) What is a net ionic ionic equation?A net ionic equation is an equation which shows only the ions that are involved in the formation of a product in the reaction as well as the product of the reaction alone. Spectator ions are omitted.
The net ionic equation of the reaction is given below:
Pb²⁺aq) + 2 I(aq) → PbI2(s)
In conclusion, a net ionic equation does not show spectator ions.
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Answer: B
Explanation:
why bonding of water molecule called a pure
Answer:
A molecule of water has two hydrogen atoms. Both of these atoms can form a hydrogen bond with oxygen atoms of different water molecules. Every water molecule can be hydrogen bonded with up to three other water molecules
Polysaccharides are healthier for the body than mono- or disacxharides are. What choices could you make to increase your consumption of polysaccharides and decrease your consumption of mono- and disaccharides?
Polysaccharides are healthier for the body than mono- or disaccharides are as glucagon is a type of polysaccharide found in animal tissues and is usually found in small amounts in meat from poultry and diet.
What do you need for both monosaccharides and polysaccharides?The Importance of Monosaccharides and Polysaccharides Both are essential as the primary food and dietary energy sources for all living organisms. Cell-wall polysaccharides make up the fibers that humans eat, and monosaccharides add sweetness to food.
Glycogen – This is a type of polysaccharide found in animal tissues and is usually found in small amounts in meat from poultry and diet. Most of the glycogen is stored in the liver, not in the muscles unless you eat a lot of liver and meat, so I said it was a small amount. In general, you may not be consuming too much glycogen. Starch (amylose and amylopectin) – It is found primarily in plants and is composed of two structurally distinct polysaccharides called amylose and amylopectin. Amylose is a linear polysaccharide, but amylopectin has many branched chains. Fiber-This is primarily cellulose, also a linear polysaccharide, a major structural component of plant cell walls. Humans cannot digest this carbohydrate because they lack the digestive enzymes needed to digest it.Read more about carbohydrates:
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