What is the wavelength associated with an electron with a velocity of 4.8x10*5 m/s?
(mass of the electron is 9.1 X 10-*31kg)

Answer:

Approximately [tex]281.25\; \rm m[/tex]. (Assuming that the drag on this ball is negligible, and that [tex]g = 10\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Assume that the drag (air friction) on this ball is negligible. Motion of this ball during the descent:

The horizontal velocity of this ball is constant during the descent. The horizontal distance that the ball has travelled during the descent is also given: [tex]x(\text{horizontal}) = 30\; \rm m[/tex]. Combine these two quantities to find the duration of this descent:

[tex]\begin{aligned}t &= \frac{x(\text{horizontal})}{v(\text{horizontal})} \\ &= \frac{30\; \rm m}{4\; \rm m \cdot s^{-1}} = 7.5\; \rm s\end{aligned}[/tex].

In other words, the ball in this question start at a vertical velocity of [tex]u = 0\; \rm m \cdot s^{-1}[/tex], accelerated downwards at [tex]g = 10\; \rm m \cdot s^{-2}[/tex], and reached the ground after [tex]t = 7.5\; \rm s[/tex].

Apply the SUVAT equation [tex]\displaystyle x(\text{vertical}) = -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t[/tex] to find the vertical displacement of this ball.

[tex]\begin{aligned}& x(\text{vertical}) \\[0.5em] &= -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t\\[0.5em] &= - \frac{1}{2} \times 10\; \rm m \cdot s^{-2} \times (7.5\; \rm s)^{2} \\ & \quad \quad + 0\; \rm m \cdot s^{-1} \times 7.5\; s \\[0.5em] &= -281.25\; \rm m\end{aligned}[/tex].

In other words, the ball is [tex]281.25\; \rm m[/tex] below where it was before the descent (hence the negative sign in front of the number.) The height of this cliff would be [tex]281.25\; \rm m\![/tex].

Answer:

[tex]T_d=2.8*10^-^6\%[/tex]

Explanation:

From the question we are told that

Distance b/w Earth and the moon [tex]d_e=3.84×10^8 m[/tex]

Thickness of Earth's atmosphere[tex]d_t=30km[/tex]

Constant index of refraction [tex]n = 1.000293.[/tex]

Generally the equation for percentage of time delay [tex]T_d[/tex] is mathematically given as

[tex]T_d=\frac{d(n-1)}{rm}*100\%[/tex]

[tex]T_d=\frac{(35*10^3)(1.000293-1)()100)}{3.674*10^8} *\%[/tex]

[tex]T_d=2.8*10^-^6 \%[/tex]

Therefore the general percentage correction needed because of tym deley is given as

[tex]T_d=2.8*10^-^6\%[/tex]

Answer:

250w

Explanation:

W=Fd

W= 250 x 4= 1000J

P=E/t=1000/4s=250w

Answer:

Explanation:

they trade velocities... so the Satellite now is going 5000 m/s  

Answer moderate alcohol can be good for you health

Explanation: but I wouldn't do none of those things to be honest

SMARTEST

Answer:

none of the above

Explanation:

its an easy question haha

Solution :

We know that the time period of oscillation of a spring mass system is given by :

[tex]$T = 2 \pi \sqrt{\frac{m}{k}}$[/tex]     , where m is mass and k is the spring constant

∴ [tex]$T_A = 2 \pi \sqrt{\frac{m}{k}}$[/tex]    .........(i)

  [tex]$T_B = 2 \pi \sqrt{\frac{2m}{k}}$[/tex] ..........(ii)

  [tex]$T_C = 2 \pi \sqrt{\frac{3m}{6k}} = 2 \pi \sqrt{\frac{m}{2k}}$[/tex]   ..........(iii)

  [tex]$T_D = 2 \pi \sqrt{\frac{m}{4k}}$[/tex]   ...............(iv)

Comparing the equations (i), (ii), (iii) and (iv)

We get

[tex]$T_B > T_A > T_C > T_D$[/tex]

So in increasing order of time period, we get

[tex]$T_D < T_C < T_A < T_B$[/tex]

Answer:

c.an electron or positron

Answer:

your answer would be c

Explanation:

Answer:

a) [tex](v_1)=0.3989m/s[/tex]

b) [tex]\theta_1=80.5 \textdegree[/tex]

c) [tex]K.E=0.036J[/tex]

Explanation:

From the question we are told that:

Initial speed of 1st ball [tex]u_{1}=0 m/s[/tex]

Mass of 1st ball [tex]m_1=0.585kg[/tex]

Mass of 2nd ball [tex]m_2=0.420kg[/tex]

Initial speed of 2nd ball [tex]u_{2}=0.270 m/s[/tex]

Final speed of 2nd ball [tex]v_{2}=0.220 m/s[/tex]

Angle of collision [tex]\angle=36.9 \textdegree[/tex]

a)

Generally the equation for law of conservation is mathematically given by

[tex]m_1u_1+m_2u_2=m_1v_1^2+m_2v_2^2[/tex]

The final velocity [tex]v_1[/tex] is given as

[tex]0+(0.420)(0.270)=(0.585)(v_1)^2+(0.420)(0.220)^2[/tex]

[tex](v_1)^2=\frac{(0.420)(0.270)-(0.420)(0.220)^2}{0.585}[/tex]

[tex](v_1)^2=0.1591[/tex]

[tex](v_1)=0.3989m/s[/tex]

b)

Generally the equation for law of conservation is mathematically given by

[tex]m_1u_1+m_2u_2=m_1v_1cos\theta_1+m_2\theta_2[/tex]

[tex]0+(0.420)(0.270)=(0.585)(1.511)cos\theta_1+(0.420)(0.220)cos36 \textdegree[/tex]

[tex]cos\theta_1= \frac{(0.420)(0.270)-(0.420)(0.220)cos36 \textdegree}{(0.585)(0.3989)}[/tex]

[tex]cos\theta_1=0.1656[/tex]

[tex]\theta_1=80.5 \textdegree[/tex]

c)

Generally the equation for kinetic energy is mathematically given by

[tex]K.E=\frac{1}{2} mv^2[/tex]

1st Ball

[tex]K.E=\frac{1}{2} (0.585)(0.3989)^2[/tex]

[tex]K.E=0.0465J[/tex]

2nd ball

[tex]K.E=\frac{1}{2} (0.420)(0.220)^2[/tex]

[tex]K.E=0.101J[/tex]

Therefore the  change in the total kinetic energy of the two balls as a result of the collision is

[tex]0.101-0.0465[/tex]

[tex]K.E=0.036J[/tex]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. The correct form is: A [tex]+10\,\mu C[/tex] charge and a [tex]-10\,\mu C[/tex] at a distance of 0.3 meters.

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)

Where:

[tex]F[/tex] - Electrostatic force, in newtons.

[tex]\kappa[/tex] - Electrostatic constant, in newton-square meters per square coulomb.

[tex]|q_{A}|,|q_{B}|[/tex] - Magnitudes of electric charges, in coulombs.

[tex]r[/tex] - Distance between charges, in meters.

If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]|q_{A}| = |q_{B}| = 10\times 10^{-6}\,C[/tex] and [tex]r = 0.3\,m[/tex], then the magnitude of the electrostatic force is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]

[tex]F = 9.987\,N[/tex]

In consequence, correct answer is B.

Answer:

32km per hour

Explanation:

Explanation:

In first case v = a t

==> a t = 40 km p h

Now distance covered S1 + S2 + S3

S1 = 1/2 a t^2 and S3 = 1/2 a t^2

But S2 = 3t * 40 = 120 t km

Hence total distance = at^2 + 120 t

Time taken (total) = t + 3t + t = 5 t

Hence average speed = at^2 + 120 t / 5 t

Cancelling t we have at + 120 / 5 = 40 + 120 / 5 = 160/5 = 32 km per hour

Explanation:

lol ....you are right.......

Answer:

the speed of an object is 9.42 m/s

Explanation:

The computation of the speed of an object is given below:

v = 2πr ÷ t

where

v denotes the speed

r denotes the radius

r denotes the time

So,

= 2 × 3.14 × 0.75 ÷ 0.50

= 9.42 m/s

Hence, the speed of an object is 9.42 m/s

the same would be considered and relevant too

Answer: True!

Explanation: The force is proportional to the square of the distance between 2 point masses

Complete question is;

Shoveling snow can be extremely taxing since the arms have such a low efficiency in this activity. Suppose a person shoveling a sidewalk metabolizes food at the rate of 800 W. (The efficiency of a person shoveling is 3%.)

(a) What is her useful power output? (b) How long will it take her to lift 3000 kg of snow 1.20 m? (This could be the amount of heavy snow on 20 m of footpath.) (c) How much waste heat transfer in kilojoules will she generate in the process?

Answer:

A) P_out = 24 W

B) t = 1470 s

C) Q = 1140.72 KJ

Explanation:

We are given;

Input Power; P_in = 800 W

Efficiency; η = 3% = 0.03

A) Formula for efficiency is;

η = P_out/P_in

Making P_out the subject, we have;

P_out = η•P_in

P_out = 0.03 × 800

P_out = 24 W

B) We know that;

Power = work done/time taken

Thus;

P_out = mgh/t

We are given;

m = 3000 kg

h = 1.20 m

Thus, time is;

t = (3000 × 9.8 × 1.2)/24

t = 1470 s

C) amount of heat wasted is calculated from;

Q = (P_in - P_out)t

Q = (800 - 24) × 1470

Q = 1,140,720 J

Q = 1140.72 KJ

Answer:

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Explanation:

Let's start by calculating each force.

Gravitational force

             F =[tex]G \frac{m_1m_2}{r^2}[/tex]  

let's calculate

             F = 6.67 10⁻¹¹  1  1 / 1²

             F = 6.67 10⁻¹¹ N

Electric force

             F = [tex]k \frac{q_1q_2}{r^2}[/tex]  

indicates that the charge is q = 10 C

            F = 9 10⁹ 10 10 / 1²

            F = 9 10¹¹ N

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Answer:

The work done will be "763 J". A further explanation is given below.

Explanation:

The given values are:

[tex]Q_1=1000 \ J[/tex]

Temperature,

[tex]T_1=900^{\circ} C[/tex]

i.e,

    [tex]=1173[/tex]

[tex]T_2=5^{\circ}C[/tex]

i.e.,

    [tex]=278[/tex]

As we know,

⇒  [tex]\eta =1-\frac{T_2}{T_1}[/tex]

On substituting the values, we get

⇒     [tex]=1-\frac{278}{1173}[/tex]

⇒     [tex]=\frac{1173-278}{1173}[/tex]

⇒     [tex]=\frac{895}{1173}[/tex]

⇒     [tex]=0.763[/tex]

then,

⇒  [tex]W=\eta Q_1[/tex]

⇒       [tex]=0.763\times 1000[/tex]

⇒       [tex]=763 \ J[/tex]

Answer:

the current INCREASES.

Explanation:

In this experiment, the electrons are generated by a filament with very low speed, when they are subjected to a difference and potential ΔV they acquire the necessary speed to reach the regulation and the current can be measured.

Some electrons collide elastically with the atoms of the mercury gas that is much heavier and are scattered in any direction, so they do not reach the grid, by increasing the voltage this scattered electrons can acquire the necessary speed in the direction of grid to reach it and therefore are also measured, increasing the current.

Therefore, as the power difference increases, the current INCREASES.

Answer: I believe hydrogen cyanide, carbon monoxide, and ammonia are the three chemicals involved, but im not sure

Answer:

One degree unit on the Celcius scale is equivalent to one degree unit on the kelvin scale. The only difference between these two scales is the zero point. The zero point on the Celcius scale was defined as the freezing point of water, which means that there are higher and lower temperatures around it.

Explanation:

V= Current × Resistance

V= 400mA × 5kohms

V= 2000V

The release of infrared light from radioactive materials is what demonstrates light possessing wave characteristics.

This is defined as the propagation of disturbances from one place to another in an organized way.

The release of waves in a diffraction pattern is why option C was chosen as the most appropriate choice.

Read more about Wave here https://brainly.com/question/15663649

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

[tex]T = \frac{t}{n}[/tex]

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

[tex]T = \frac{135\ s}{98}[/tex]

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

[tex]T = 2\pi \sqrt{\frac{l}{g}}[/tex]

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

[tex](1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}[/tex]

g = 11.2 m/s²

Answer:

melting butter in a saucepan, as the butter cools it turns brown

Explanation:

although melting the butter is a physical change, but the butter being cooked and turning brown Is a chemical change, because due to the heat, its particles are being broken down, which is irreversible, and shows a chemical change.

Answer:

0.06

Explanation:

Working on the problem at hand i calculated and got my answer to around simplified at 0.06

Answer:

Either heat added or mechanical work done.

Explanation:

Since he found stirring rod on the desk and a cigarette lighter. This means that the beaker was probably either heated with the aid of fire from the lighter.

Also, the stirring rod could have been used to stir the water which will increase the kinetic energy which also means an increase in temperature.

Thus, it's either heat was added or mechanical work was done as a result of stirring.

Answer:

a. E = 900000 J = 900 KJ

b. ΔT = 8.18 °C

c. Cost = $ 7.2  

Explanation:

a.

The energy can be given by:

[tex]E = Pt[/tex]

where,

E = Energy = ?

P = Power = 500 W

t = time = (0.5 h)(3600 s/1 h) = 1800 s

Therefore,

[tex]E = (500\ W)(1800\ s)[/tex]

E = 900000 J = 900 KJ

b.

The change in temperature of room air is given by the following formula:

[tex]0.5E = mC\Delta T\\[/tex]   (since 50% of energy is used to heat air)

where,

m = mass of air = 50 kg

C = specific heat of air = 1.1 KJ/kg.°C

ΔT = Change in temperature of air = ?

Therefore,

[tex](0.5)(900\ KJ) = (50\ kg)(1.1\ KJ/Kg.^oC)\Delta T[/tex]

ΔT = 8.18 °C

c.

First, we will calculate the total energy consumed:

[tex]E = (0.5\ KW)(6\ h/d)(30\ d)\\E = 90\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(90\ KWh)[/tex]

Cost = $ 7.2

Answer:

1.33

Explanation:

For an optical instrument, the magnification ratio of the apparent diameter of the image to that of the object.

Mathematically, from the given information;

Magnification[tex]= \dfrac{n_{water}}{n_{air}}[/tex]

where;

[tex]n_{water} =1.33\\ \\ n_{air} = 1.00[/tex]

[tex]= \dfrac{1.33}{1.00} \\ \\= \mathbf{1.33}[/tex]

Answer:

The wavelength of a wave with the frequency of 330hz and a speed of 343m/s would be 1.04m

Explanation:

You can get the wavelength of a wave by dividing the speed of the wave by its frequency, which in this case would be:

343/300, which as a decimal number, it'd be 1.04.

I hope I helped you, and a "Brainliest" is always appreciated! ☺