Mathematics High School

What is the value of the expression x^3y^2/6 + x^2y^2 x = -2 and y = 3?
A -45
B -30
С 24
D 27

What Is The Value Of The Expression X^3y^2/6 + X^2y^2 X = -2 And Y = 3?A -45B -30 24D 27

Answers

Answer 1

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{(-2^3)(3^2)}{6}+(-2^2)(3^2)}[/tex]

[tex]\mathsf{(-2)^3=\bf -8}[/tex]

[tex]\mathsf{= \dfrac{-8(3^2)}{6}+(-2^2)(3^2)}[/tex]

[tex]\mathsf{3^2=\bf 9}[/tex]

[tex]\mathsf{= \dfrac{(-8)(9)}{6}+(-2^2)(3^2)}[/tex]

[tex]\mathsf{-8(9)= \bf -72}[/tex]

[tex]\mathsf{= \dfrac{-72}{6}+(-2^2)+(3^2)}[/tex]

[tex]\mathsf{\dfrac{-72}{6}=\bf -12}[/tex]

[tex]\mathsf{= -12+(-2)^2(3^2)}[/tex]

[tex]\mathsf{-2^2=\bf 4}[/tex]

[tex]\mathsf{= -12+4(3^2)}[/tex]

[tex]\mathsf{3^2=\bf 9}[/tex]

[tex]\mathsf{= -12+4(9)}[/tex]

[tex]\mathsf{4(9)= \bf 36}[/tex]

[tex]\mathsf{-12 + 36 = \bf 24}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \huge\bf Option C. 24}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

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Step-by-step explanation:

[tex]A=\frac{(bx_{1}+bx_{2} )h }{2}[/tex]

[tex]A=\frac{(7.7+14.3)(8.6)}{2}[/tex]

[tex]answer:- 94.6 ft^{2}[/tex]

[tex]---------[/tex]

hope it helps...

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Step-by-step explanation:

here's your solution

==> area of trapezium = 1/2*(sum of parrel side)*distance between them

==> area of trapezium = 1/2(7.7 + 14.3)*8.6

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