What is the value of 15 + x2 when the value of x is 3? also there's a tiny 2 above the 15

Answer:

Step-by-step explanation:

1. The first ski was valued at $850 but was then given a 50% discount. The sales price will therefore be:

= 850 * ( 1 - 50%)

= 850 * 50%

= $425

2. The first one was first discounted by 30% so the sales price was:

= 850 * ( 1 - 30%)

= 850 * 70%

= $595

It was then marked down by a further 20%:

= 595 * ( 1 + 20%)

= $476

3. The first ski is a better option because the discount makes it cheaper than the second ski even after the second ski had been discounted twice.

Step-by-step explanation:

4) d = √(3-1)²+(7-(-1))²

=√2²+8² = √4+64 =√68

5) AD=29

AB =2x+4,BC=2x,CD=x

AD = 2x+4+2x+x

29=2x+4+2x+x

29=5x+4

29-4=5x

x=25/5

x=5

AB =2x+4

=2(5)+4 =14

BD = BC +CD

= 2x+x

=2(5)+5 =15

Answer:

C. corresponding angles

Step-by-step explanation:

I think this because 1 and 5 are on the same side and they're angles formed by the transversal line that cuts across

Answer:

B

Step-by-step explanation:

Given:

The expression is

[tex]2x-5y+3[/tex]

To find:

The equivalent expressions.

Solution:

We have,

[tex]2x-5y+3[/tex]

In option 1,

[tex]x+x-y+1+1+1-y-y-y-y[/tex]

[tex]=(x+x)+(-y-y-y-y-y)+(1+1+1)[/tex]

[tex]=2x-5y+3[/tex]

So, the expression in option 1 is equivalent to the given expression.

Similarly,

In option 2,

[tex]-2+2x+3+(-2y)-y[/tex]

[tex]=2x-3y+1\neq 2x-5y+3[/tex]

So, the expression in option 2 is not equivalent to the given expression.

In option 3,

[tex]-5y-x-x+2+1[/tex]

[tex]=-2x-5y+3\neq 2x-5y+3[/tex]

So, the expression in option 3 is not equivalent to the given expression.

In option 4,

[tex]y+y+y+y+y-2x-1-1-1[/tex]

[tex]=-2x+5y-3\neq 2x-5y+3[/tex]

So, the expression in option 4 is not equivalent to the given expression.

In option 5,

[tex]2+1+x-y+x-2y[/tex]

[tex]2x-3y+3\neq 2x-5y+3[/tex]

So, the expression in option 5 is not equivalent to the given expression.

In option 6,

[tex]x-y+x+1-y-3y+2[/tex]

[tex]=2x-5y+3[/tex]

So, the expression in option 6 is equivalent to the given expression.

Therefore, the correct options are 1 and 6.

Answer:

Weight of Mohib package = 4 pounds

Weight of Rajesh package = 11 pounds

Step-by-step explanation:

Let

Weight of Mohib package = x

Weight of Rajesh package = 2x + 3

Total weight = 15

Total weight = Weight of Mohib package + Weight of Rajesh package

15 = x + (2x + 3)

15 = x + 2x + 3

15 - 3 = x + 2x

12 = 3x

x = 12/3

x = 4 pounds

Weight of Mohib package = x

= 4 pounds

Weight of Rajesh package = 2x + 3

= 2(4) + 3

= 8 + 3

= 11 pounds

Answer:

A. They are now a significant part of communication

Step-by-step explanation:

take care

Answer:

10

Step-by-step explanation:

Answer:

the answer is C

Step-by-step explanation:

Answer:

5x+6= 10x-8

14= 5x

x= 2.8

Step-by-step explanation:

9514 1404 393

Answer:

  100°

Step-by-step explanation:

Angle AKC is a vertical angle with angle BKD, so has the same measure. Since K is the center of the circle, arc AC has the same measure as angle AKC: 100°.

__

A diagram may help.

Answer:A=452.16

Step-by-step explanation:

A=π·r²

A=3.14·12²

A=3.14·144

A=452.16

Answer: 3x60=180x2=360+6/2=83 but you have to factor that she will sometimes fly backwards . Then after you that into count the answer is (2x6=42=54) now that you take "x" and turn it to 6 yoy get (5,4)

Step-by-step explanation:

The two ordered pairs are (0.05, 0.1) and (0.1, 0.2).

The graph is shown below.

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

y = 4x

y = number of miles

x = number of hours

4 miles per hour.

Now,

The rate is 2 miles per hour.

This means,

y = 2x

Now,

x = 3 minutes = 3/60 hour = 1/20 hour = 0.05 hour

y = 2 x 1/20 = 1/10 miles = 0.1 miles

The ordered pair is (0.05, 0.1)

x = 6 minutes = 6/60 hour = 1/10 hour = 0.1 hour

y = 2 x 1/10 = 1/5 miles = 0.2 miles

The ordered pair is (0.1, 0.2)

Thus,

The ordered pairs are (0.05, 0.1) and (0.1, 0.2).

Learn more about coordinates here:

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quarters: 8

dime: 1

explanation: 8 quarters = 2$ and 1 dime = 10 cents

Answer:

8x = 136

Where: x = 17

Step-by-step explanation:

Joshua is writing a novel. He wrote the same number of pages each day for a 8 days. At the end of 8 days he had 136 pages complete. Write an equation relating x, the number of days, to y, the total pages.

Let the number of pages read per day = x

Hence, the number of pages after 8 days = 8 × x = 8x

Total number of pages = y= 136

Therefore:an equation relating x, the number of days, to y, the total pages.

= 136 = 8x

Solving for x

136/8 = x

x = 17

Answer:

(-1,3)

Step-by-step explanation:

count 9 up

Answer: -1,3 not sure

Step-by-step explanation:

Answer:

3x^2+6x

Step-by-step explanation:

the 3rd one

Answer:

ac ab bc

Step-by-step explanation:

Answer:

jk is longer than jl

Step-by-step explanation:

The distance between J and L is more than J and K hence, the correct option will be (A).

To find the distance between any two points first assign any one point by (1) whose coordinates will be (x₁, y₁) and assign the remaining point with (2) whose coordinates will be (x₂,y₂).

Now, use the below formula to find out the distance

[tex]\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]

Let's assign J by (1) whose coordinate (2,4) work like (x₁,y₁) and assign L by (2) whose coordinate (1,-1) work like (x₂,y₂).

Now by the distance formula, the distance JL is

⇒  [tex]\sqrt{(1-2)^2 +(-1-4)^2}[/tex]

⇒   [tex]\sqrt{(-1)^2+(-5)^2}[/tex]

⇒    [tex]\sqrt{26[/tex] = 2.236

Now again assign J by (1) whose coordinate (2,4) work like (x₁,y₁) and assign K by (2) whose coordinate (7,-8) work like (x₂,y₂).

Now by the distance formula, the distance JK is

⇒   [tex]\sqrt{(7-2)^2 +(8-4)^2}[/tex]

⇒   [tex]\sqrt{(5)^2 +(4)^2}[/tex]

⇒[tex]\sqrt{(41)}[/tex] = 6.403

Hence, it's clear that the JK is longer than JL.

For more information about the distance formula

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Step-by-step explanation:

Since 64 = 32 * 2 and 32 = 32 * 1,

64 + 32 = 32(2 + 1).

16(4 + 2) is wrong as 4 and 2 have a GCF of 2.

8(8 + 4) is wrong as 8 and 4 have a GCF of 4.

32(2) + 1 is the wrong application of the distributive property.

Answer:

64+32=32(2+1) is greatest common factor

Answer:

C. 60

Step-by-step explanation:

First we mjust know that area is length times width (this will be the key to help you)

To find the old area we must: 5*8=40

Then we must find the new area: 10*10 = 100

Now we must subtract the tiles to get the new from old: 100-40=60

Therefore, your answer is 60.

Please mark me brainliest.

Answer:

t = 6.031 seconds

Step-by-step explanation:

Roscoe hit a ball straight up at a speed of 96 ft/s.

His bat hit the ball at a height 3 ft above the ground.

We need to find how many seconds did the ball hit the ground.

Using equation of motion to find height of the ball.

[tex]h=-16t^2+96t+3[/tex]

When it hits the ground.

h = 0

[tex]-16t^2+96t+3=0[/tex]

It is a quadrctic equation where a = -16, b = 96 and c = 3

[tex]t=\dfrac{-96\pm \sqrt{96^2-4(-16)(3)} }{2(-16)}\\\\t=-0.031\ s, 6.031\ s[/tex]

Neglecting negative value.

So, after 6.031 seconds the ball will hit the ground.

Given :

Roscoe hit a ball straight up at a speed of 96 ft/s.

His bat hit the ball at a height 3 ft above the ground.

To Find :

After how many seconds did the ball hit the ground.

Solution :

When the ball reaches the same height from which it is thrown ( i.e. 3 ft ) its displacement will be zero.

So, using equation of motion :

[tex]s = ut + \dfrac{at^2}{2}\\\\96t - \dfrac{10t^2}{2} = 0\\\\5t^2 - 96t = 0\\\\t( 5t - 96 ) = 0\\\\t = \dfrac{96}{5}\\\\t = 19.2 \ s[/tex]

Now, time taken to reach ground from 3 feet of height is :

[tex]s = ut + \dfrac{at^2}{2}\\\\3 = 96t + 5t^2 \\\\5t^2 + 96t - 3 = 0[/tex]

t = 0.03 s

Therefore, time taken is T = 19.2 + 0.03  = 19.23 seconds.

9514 1404 393

Answer:

  reasonable range: 0 ≤ y ≤ 5.5

Step-by-step explanation:

Unless the balloons are being launched from a building or the edge of a cliff, we generally expect f(x) ≥ 0. This limits the "reasonable range" to ...

  0 ≤ y ≤ 5.5