what is the theory relativity by Einstein? ​

Developing Psychological Theories: Mastery Test

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Hope this helps :)

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Answer:

gravity

Explanation:

keeps the ball down on the surface

When dribbling a ball, the gravity should control the direction and downward motion of the ball.

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.

Two distinct rectilinear motions occur simultaneously in a projectile motion:

When a ball is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g).

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#SPJ2

The answer is in the picture.

Answer:

The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.

i dont know  Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you            Explanation:

Answer:

a).  The truck's distance covered for the trip is

                      (60) + (60 - 15)  =  105 kilometers .

b).  Its displacement for the whole trip is the distance

and direction from the start-point to the end-point.

                         15 kilometers east .

Explanation:

Answer: A

Explanation: An object in free fall only is affected by gravity, so the acceleration is 9.8 m/s²

Answer:

the answer is the rollar coster

Explanation:

because the rollar coster is

[tex]\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3[/tex]

[tex]\\ \sf\longmapsto 7(17)+8(-14)=(7+8)v3[/tex]

[tex]\\ \sf\longmapsto 119-112=15v3[/tex]

[tex]\\ \sf\longmapsto 15v3=7[/tex]

[tex]\\ \sf\longmapsto v3=7/15[/tex]

[tex]\\ \sf\longmapsto v3=2.1m/s[/tex]

Momentum is conserved, so

(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'

where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives

100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'

0 = (2 kg) v₁' + (4 kg) v₂'

v₁' = -2v₂'

Energy is also conserved, so

1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²

Simplifying yields

2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²

3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²

Substitute v₁' = -2v₂' and solve for v₂' :

3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²

3750 J = (6 kg) (v₂')²

(v₂')² = 625 J/kg = 625 m²/s²

v₂' = 25 m/s

Then the first block has final velocity

v₁' = -2 (25 m/s)

v₁' = -50 m/s

The pendulum bob slow down and eventually stop as it loses it energy due to friction or air resistance. All its kinetic energy has been transformed to potential energy. None of the options is correct

The to and fro movement of an object or particle is known as oscillatory motion. Such motion repeats itself. Examples are;

The given diagram shows a swinging pendulum. And the option which best explains what happens to the motion of the pendulum due to the law of conservation of energy is

The pendulum will slow down and eventually stop moving when it loses energy because of friction or air resistance as the kinetic energy transforms to potential energy

The mechanical energy involve are potential and kinetic energy. Both energies reduce as they gradually lost some of their energies due to air friction between the bob and the air. Some of the lost energies may be transformed to thermal energy.

The pendulum bob slow down and eventually stop because it loses its mechanical energy due to air resistance or friction.

Therefore, the option A which state that "The pendulum will slow down and eventually stop moving as the mechanical energy transforms to thermal energy" can be considered. But none of the option best explain what happens to the motion of the pendulum.

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Answer:

112.36 pounds

Explanation:

Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).

Answer:

69 meters

Explanation:

Answer:

Below in bold.

Explanation:

Newton's Second Law:

Force = mass * acceleration

So

Force = 24.5 * 2.3

= 56.35 Newtons.

The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge [tex]q[/tex] =  [tex]5\times 10^{-7}[/tex] C,

the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex]  m/sec,

the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,

angle between the direction of v and B [tex]\theta[/tex] = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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Hi there!

[tex]\large\boxed{10 m/s}}[/tex]

When a projectile is launched, the HORIZONTAL component remains constant.

The force of gravity only changes the vertical component of the velocity.

As the two components are completely independent of one another, the horizontal component is UNCHANGED.

Answer:

its true since i already did this last year, if i am wrong i apologize

Explanation:

The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:

The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:

Indicate in  the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.

Vector A.

         Aₓ = 100.0 m  

Vector B.

         B_y = -300.0 m  

The negative sign indicates that it goes in the negative direction of the y-axis

Vector C.

We use trigonometry.

The angle measured from the positive side of the x-axis counterclockwise is

        θ = 180 + 30 = 210

        sin 210 = [tex]\frac{C_y}{C}[/tex]

        cos 210 = [tex]\frac{C_x}{C}[/tex]

        C_y = C sin 210

        Cₓ = C cos 210

         C_y = 150.0 sin 210 = -75.0 m

         Cₓ = 150.0 cos 210 = -129.9 m

Vector D.

The angle from the positive side of the x-axis counterclockwise.

        θ = 180-60 = 120º

       sin 120 = [tex]\frac{D_y}{D}[/tex]  

       cos 120 = [tex]\frac{D_x}{D}[/tex]  

       D_y = D sin 120

       Dₓ = D cos 120

       D_y = 200.0 sin 120 = 173.2 m

       Dₓ = 200.0 cos 120 = -100.0 m

we add the component with algebraic sum.

       x = Aₓ + Cₓ + Dₓ

       y = B_y + C_y + D_y

       x = 100 - 129.9 -100 = -129.9 m

       y = -300 - 75.0 + 173.2 = -201.8 m

We construct the resulting vector.

We use the Pythagorean theorem for the Modulus.

       [tex]R+ \sqrt{x^2 +y^2}[/tex]  

       R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]  

       R = 239.99 m

We use trigonometry for the angle.

      tan  θ = [tex]\frac{y}{x}[/tex]

       θ = [tex]tan^{-1} \frac{y}{x}[/tex]  

       θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)

       θ = 57.2º

Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.

          θ = 270 - θ'

          θ = 270 - 57.2

          θ = 212.8º

In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:

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Answer:

5)

Solution

initial velocity = 15 m/s

acceleration = 3m/s^2

time = 4 s

final velocity = 15+3×4

=15+12

=27m/s

A car accelerates from 20m/s to 30m/s in 10 second

T9 be honest I think some part of the second question is missing

Answer:

Scientific investigation is a quest to find the answer to a question using the scientific method.

Explanation:

the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.

Answer:

concave lens focal length 2m

Answer:

D. a plane landing on an aircraft carrier

E. rain sticking to a window

F. two train cars coupling together

Explanation:

Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.

Explanation:

The correct option to the question is Matter.

Matter makes up everything. matter can be solid, liquid, or gas. matter is made up of atoms, or tiny particles that are the smallest unit of matter.

Moreover, Matter can be described as,

Matter is anything that has occupies space (has mass and volume).

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Answer:

Matter

Explanation:

I took the test Edge 2022

Answer:

  0.184 m/s

Explanation:

Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...

  m1v1+m2v2 = m3v3

  (0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)

  v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s

The speed of the combined masses is 0.184 m/s.

_____

Additional comment

The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.

Answer:

- 30 kW

Explanation:

IDEA:

Power of an object that does work(source) is given by:

[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]

where work done is mostly shown as the Force applied on an object to Displace it through some distance in the same direction as the Force.

[tex] \boxed{ \mathsf{ work = force \times displacement}}[/tex]

___________________

INFORMATION:

In the question,

The source of power is the crane, while the object is a load of 36000N.

Note, what's given is the force, not the mass. Since, the SI unit of mass is kg and that of Force is Newton(N).

[The weight of the load is represented in Newton, since weight of an object is the amount of Force with which the Earth attracts that object]

I) work done

So,

=> Work = 36000 × 50

= 1,800,000 J

(The SI unit of work is Joules(J)).

___________________

II) power

After getting the amount of work done, now we have to place it in the formula for power.

That is:

[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]

Note, During calculations, all quantities must be in their SI units.

SI unit for time is Seconds (s)

But the time we have is in minutes.

___________________

Converting time from minutes to Seconds:

1 minute = 60 Seconds.

Hence,

[tex] \implies \mathsf{power = \frac{1800000}{60} } \: [/tex]

=> power = 30,000 W

(SI unit of power is Watts(W))

To write four zeroes with a 3 and W is a lot of effort. So, we can look for simple expressions like kilowatts(kW) that can express bigger quantities in lesser terms.

1000 W = 1 kW

___________________

Direction and sign:

The crane displaces the load in an upward direction (from the term "lifts")

But, the Force is acting downwards, as the weight of the body is always towards the Earth.

Since, the directions of Force and displacement are opposite, a minus takes its place in front of both Work and power.

___________________

Therefore, the final answer will be:

The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is

∑ F = F[a] - F[f] - F[air] = ma

3100 N - 200 N - F[air] = (650 kg) (3 m/s²)

Solve for F[air] :

F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)

F[air] = 3100 N - 200 N - 1950 N

F[air] = 950 N