What is the slope of the graph of y = -3x? need answer now asap

-3
3
-1/3
1/3

The best description of the shape of the sampling distribution is C. Approximately normal.

The sampling distribution of the sample proportion of those who will be cured with the skin cream is approximately normal.

A sampling distribution is the distribution of a statistic calculated from a random sample of data. In this case, the statistic is the sample proportion of those who will be cured with the skin cream.

The Central Limit Theorem states that the sampling distribution of a statistic will be approximately normal if the sample size is large enough, regardless of the shape of the underlying distribution.

Since the sample size of 100 people is large enough, the sampling distribution of the sample proportion of those who will be cured with the skin cream is approximately normal.

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The question is -

Certain skin cream is 80 percent effective in curing a common rash. A random sample of 100 people with the rash will use the cream. Which of the following is the best description of the shape of the sampling distribution of the sample proportion of those who will be cured? А. Bimodal B. Uniform C. Approximately normal D. Strongly skewed to the left E. Strongly skewed to the right.

The range of the function will be  0 ≤ y ≤ 960

The range of a function is the set of all its outputs. Example: Let us consider the function f: A→ B, where f(x) = 16x and each of A and B = {set of natural numbers}. Here we say A is the domain and B is the co-domain. Then the output of this function becomes the range. The range = {set of even natural numbers}.

Generally, the range of a function is the possible values of y in the that function and can be from -negative infinity to positive infinity.

In the given question, the function y = 16x models the situation and the capacity of the the container is 960 ounces

The range will fall between 0 ≤ y ≤ 960

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The linear equation and the definition of the parts of the equation  of the motion of the balloon are as follows;

A. The equation is; h = 800 - 100·m

B. The rate of change is 100 ft/min. The rate of change represents the height the balloon descends in one minute

C. The y-intercept is 800 (feet). The y-intercept represents the initial height of the balloon

D. The x-intercept is 8 (minutes). The x-intercept represents the time it takes the balloon to reach the ground

A linear equation is one that has a straight line graph.

The initial height of the balloon = 800 feet

Height of the balloon after 1 minute = 700 feet

A. The change in height of the balloon in one minute = 100 feet

The rate of change of the height of the balloon = -100 feet per minute (the height reduces by 100 feet after each minute)

The linear equation for the balloon, can therefore be obtained from the following details;

The initial height of the balloon = The y-intercept of the linear equation, c = 800 feet

The rate of change of the height of the balloon = The slope of the linear equation, m = -100 ft/min

The linear equation in the form, y = m·x + c, that can be used to find the  height of the balloon is therefore;

h = -100·m + 800

B. The rate of change is the rate at which the height of the balloon changes, which is 100 feet per minute

C. The y-intercept is the point at which the linear equation intersects the y-axis which is the point at which the input variable, m, is zero, indicating the height at which the balloon started its descent.

D. The x-intercept is the point at which the graph intersects the x-axis, and at which the y-value (value of the output variable) is zero, and the x-intercept can be specified by the x-value at the point of the intersection.

At the x-intercept, therefore, h is zero, which is the ground level, and m is the time it takes the balloon to reach the ground.

At the x-intercept, therefore, we het;

h = 0 = 800 - 100·m

100·m = 800

m = 800 ÷ 100 = 8

The x-intercept is m = 8 minutes

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the orthogonal projection of [-2 2] onto the line through [-1 5] and the origin is [-1.25 3.75] using unit vector.

First, we need to calculate the unit vector of the line. This can be done by subtracting the two given points and dividing the result by the magnitude of the vector:

[-1 5] - [0 0]

= [-1 5]

|[-1 5]| = sqrt(1^2 + 5^2) = sqrt(26) = 5.1

Unit vector = [-1/5.1 5/5.1] = [-0.196 0.980]

Next, we need to calculate the dot product of the vector [-2 2] and the unit vector [-0.196 0.980]. This will give us the scalar projection.

(-2)(-0.196) + (2)(0.980) = -0.392 + 1.960 = 1.568

Finally, we can calculate the orthogonal projection by multiplying the scalar projection by the unit vector.

[-0.196 0.980] (1.568) = [-0.301 1.527]

Rounding to two decimal places, the orthogonal projection of [-2 2] onto the line through [-1 5] and the origin is [-1.25 3.75].

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Answer:

y = x - 15

Step-by-step explanation:

y-2 = 1(x-17)

y-2 = x - 17

y = x -17 + 2

y = x - 15

In the proof, The reason for (5) ΔVWX ≅ ΔXYZ is ASA

Two triangles are congruent when their three angles and three sides are equal to each other. The two triangles need to be of the same size and shape to be congruent. Both the triangles under consideration should superimpose on each other.

There are 4 property we use to congruent two triangles ( ASA , RHS , SSS and SAS)

According to the question,

Given = V W║Z Y

W X=Y X

We have to prove :  ΔVWX ≅ ΔXYZ

Proof =>

It is given that V W║Z Y ,

Using parallel line property ,

(1) ∠W = ∠Y (interior alternate angles )

(2) ∠V = ∠Z ( Interior angle property)

(3) W X=Y X (given)

Therefore , By using ASA property

ΔVWX ≅ ΔXYZ

Hence , In the proof, the reason for (5) is ASA

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Answer:

Below

Step-by-step explanation:

I'll do the first one....you can then do the second one

-4x-2y = -12

4x+8y = -24       add these two equations together ( this will eliminate 'x')

    6y = -36

       y = - 6      use this value in either equation to compute x = 6

HINT: On the next one....multiply either equation by -1    then add together

The direct framed(mapped) cache in the given hexadecimal has all the miss.

Given cache parameters

b block size( given no. of words)

Cache capacity 16 words

( a) Direct mapped cache with b = 1 word

Address mapping = Total = 8 bits

Index = 4 bits

Offset = 0 bit

Tag(Label) = remaining bits = 4 bits

illustration of mapping = 74---> 01110100

where 0111 is the label and the rest is the index

Sequencing of law addressing = 0 * 74 to binary = 01110100

Then, word offset = log₂( b) = log₂( 1) = 0 bit

Line offset = log₂(16/1) = 4

Label(tag) is the remaining bit

b) completely associative cache with b = 2 words

# of lines = 16/2 W = 8

Address mapping Offset = log ₂( 2) = 1 bit

Remaining bit = 01110100

where 0 is offset and the rest is a label

In this cache design, line no. isn't needed to map the data as we directly compare CPU- generated markers with existing markers in the cache controller.

Still, apply the LRU algorithm, if the cache is full.

c) Two- way set associative cache with b = 2 words

#sets = #lines/ p- way = (16/2)/ 2 = 4

Address mapping

Set offset = log₂( 4) = 2

Word offset = log₂( 2) = 1

Tag(label) = remaining bits

ADDRESS       INDEX         OFFSET       HIT/MISS

74                       10                    0                MISS

A0                      00                    0               MISS

78                      00                    0               MISS

38C                    10                    0               MISS

AC                      10                    0               MISS

84                       10                    0               MISS

88                       00                    0               MISS

8C                       00                    0               MISS

7C                       00                    0               MISS

34                        00                    0               MISS

38                        00                    0               MISS

13C                      00                    0               MISS

388                      00                    0               MISS

18C                       00                    0               MISS

Replacement policy(which is default) LRU

( d) Direct planned or mapped cache with b = 4 words( each instruction size = AW)

Line offset = log₂( 4) = 2 bit

Word offset = log₂( 4) = 2 bit

Tag(Label) = remaining bits

# lines = 16/ W = 4

0 * 74-----> 01110100

where,

01 is the line offset

00 is the word offset

0111 is the tag(label).

Therefore, the tag, line offset and line offset of the hexadecimal is given to be in a binary number.

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The sum of the first 15 terms of the geometric sequences will be 76,456.33.

The aggregate to boundless GP implies, the number of terms in a limitless GP.

Let a₁ be the first term, n be the total number term, and r be a common ratio.

Then the sum of the geometric sequence will be

Sₙ = [a₁ (1 - rⁿ)] / (1 - r)

The geometric sequence is given below.

7, -14, 28, -56, 112,...

The first term of the geometric sequence is 7 and the common ratio of the geometric sequence is given as,

r = - 14 / 7

r = - 2

Then the sum of the first 15 terms of the sequences will be given as,

S₁₅ = [7 (1 - (-2)¹⁵)] / (1 - (-2))

S₁₅ = [7(1 + 32,768)] / 3

S₁₅ = -229,369 / 3

S₁₅ = 76,456.33

The sum of the first 15 terms of the geometric sequences will be 76,456.33.

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The amount of money an account with simple interest at an annual rate of 4.2% would be $3738 after 1 month and 7476 dollar after 2 month.

Simple interest is a method of calculating the interest charge. Simple interest can be calculated as the product of principal amount, rate and time peroid.

Simple Interest = (Principal × Rate × Time) / 100

Given that loan Amy is 89000 monthly payment is 479.66 rate is 4.2

Amount = $89000

Rate = 4.2 %

Time =  1 month

Therefore, Simple Interest = (Principal × Rate × Time) / 100

Simple Interest = 89000 × 4.2% × 1

Simple Interest = 3738

Also,

Simple Interest = 89000 × 4.2% × 2

Simple Interest = 7476

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The whole match lasts for 45 minutes + 45 minutes + 30 minutes = 120 minutes. Answer: 120 min.

Answer:

Step-by-step explanation:

Given the points

   (4, 2)

   (3, 5)

We know that the slope-intercept form of the line equation is

where m is the slope and b is the y-intercept

substituting m=-3 and the point (4, 2) to get the y-intercept i.e. b

2=(-3)4 + b

2 = -12 + b

b = 2+12

b = 14

Now, substituting b=14 and m=-3 in the slope-intercept form to determine the equation of a line in the slope-intercept.

y=(-3)x+(14)

y=-3x+14

Thus, the equation of the line containing (4,2) and (3,5)  in the slope-intercept form will be:

   y=-3x+14

Answer:

First is option B)

Second is option B)

I hope my answer helps you.

40% percentage of your portfolio in the zero-coupon bond with a maturity of 5 years and 60% of your portfolio in the perpetuity. This would result in an overall duration of 10 years.

To achieve your target duration of 10 years, you would need to allocate your investments in a way that has an overall duration of 10 years. You could do this by investing 40% of your portfolio in the zero-coupon bond with a maturity of 5 years and 60% percentage of your portfolio in the perpetuity. This would result in an overall duration of 10 years.

Duration of zero-coupon bond = 5 years

Duration of perpetuity = infinity

Weighted duration of portfolio = (0.4 x 5) + (0.6 x infinity) = 10 years.

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The value of the equation A = ( 2/3 ) ( 2 - 6 ) is A = -8/3

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

A = ( 2/3 ) ( 2 - 6 )   be equation (1)

On simplifying the equation , we get

A = ( 2/3 ) ( 2 - 6 )

A = ( 2/3 ) ( -4 )

Multiply by -4 on the numerator , we get

A = ( 2 x -4 ) / 3

A = -8 / 3

Therefore , the value of A is -8/3

Hence , the value of the equation is -8/3

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In the graph B we can see that y intercept is 9 and zero is 3. So the graph b is the correct answer.

In the given question, linear function k has a zero at 3 and a y-intercept of 9.

We have to choose which graph best represents k.

As we know that;

A linear equation represent the relationship between the two unknown variable. The equation of linear equation is of one degree.

The simplest linear equation shows the correlation between (x,y), which may then be used to make a table or a graph on the coordinate plane or to assess at a specific x or y value.

We represent linear function in the form of y=mx+c.

where m is the slope of the line, c is the y intercept of the line, x is independent variable and y is the dependent variable.

As we see the y intercept in the graph crosses the y axis.

Here y intercept is 9.

The zeros of the linear function is that where y value is zero.

As in the graph B we can see that y intercept is 9 and zero is 3. So the graph b is the correct answer.

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The ordered pairs of the solution to the system of equation are (-5, -3).

System of equation can be solved using methods like substitution method, elimination method and graphical method.

Let's solve the system of equation by substitution method.

Therefore,

-3x + 2y = 9

x - 3y = 4

Hence,

x = 3y + 4

Substitute the value of x in equation(i)

-3x + 2y = 9

-3(3y + 4) + 2y = 9

-9y - 12 + 2y = 9

-7y = 9 + 12

-7y = 21

y = 21 / -7

y = -3

Let's find x using equation(ii)

x = 4 + 3y

x = 4 + 3(-3)

x = 4 - 9

x = -5

Hence, x = -5 and y = -3

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Answer: D its 50

Step-by-step explanation:

Answer:

Step-by-step explanation:

The set {x | x < 0 or x > 3 } can be written in interval notation as (-∞, 0) ∪ (3, ∞).

The set {x | x < 0 or x > 3 } consists of all real numbers that are either less than 0 or greater than 3. This set can be represented as the union of the set of all numbers less than 0, which can be written as (-∞, 0), and the set of all numbers greater than 3, which can be written as (3, ∞).

Therefore, the set {x | x < 0 or x > 3 } can be written in interval notation as (-∞, 0) ∪ (3, ∞).

The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate.

a) The equation of the estimated regression line is ŷ = - 16.592 + 0.1017x.

b) A point estimate is 1.9174 for true average efficiency ratio when tank temperature is 182.

c) The values of the residuals from the least squares line for the four observations for which temperature is 182 are -1.0774, -0.1874, 0.1226, 0.7826..

We have given the accompanying data on tank temperature (x) and efficiency ratio (y).

a) We have to find out the equation of the estimated regression line. Consider the calculations shown in the above table:

ΣΧ= 4308 ; ΣΥ= 39.99 ; ΣΧΥ = 7229.47 ;

ΣX² = 773790

Determine the slope and intercepts using the following formulas,

Slope b₁ = (n ΣΧΥ - ΣX ΣΥ)/(nΣΧ² - (ΣX)²)

=> b₁ = [24 (7229.47) - (4308) (39.99)]/(24(773790)-(4308)²)

=> b₁ = 1230.36/12096 = 0.10171626984

=> b₁ ≈ 0.1017

Intercept, b₀ = ΣY /n - b₁ΣΧ /n

=> b₀ = 39.99/24 - 0.1017×4308/24

= -16.592

Thus, the estimated regression equation of the form, ŷ = b₀ + b₁ x

ŷ = - 16.592 + 0.1017x

b) Calculate the point estimate for true average efficiency ratio when tank temperature is 182.

y = -16.592 + 0.1017x

=> y= -16.592 +0.1017 (182)

=> y= 1.9174

Therefore, the point estimate for true average efficiency ratio when tank temperature is 182 is 1.9174..

c)We have to find out the values of the residuals from the least squares line for the four observations for which temperature is 182.

From part (b), the value of ŷ is 1.9174.

The table below shows the residuals.

Vi ŷ e = y₁ - y

0.84 1.9174 -1.0774

1.73 1.9174 -0.1874

2.04 1.9174 0.1226

2.70 1.9174. 0.7826

Hence, we got all the required values.

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The ordered pair that is NOT a point on the graph of f(x) = (1/2)*x - 7 is  (2,8) , the correct option is (b)  .

In the question ,

it is given that ,

the function is given as ;

f(x) = (1/2)*x - 7 ,

Option(a) ,

the ordered pair is (1 , [tex]-6\frac{1}{2}[/tex] )

To satisfy the function f(x)  , on putting x = 1 , we should get y =  [tex]-6\frac{1}{2}[/tex] .

f(1) =  (1/2) - 7 = (1 - 14)/2 = -13/2 .

So , this point lies on graph of f(x) .

Option(b) ,

the ordered pair is (2,8) ,

f(2) = (1/2)*2 - 7 = 1 - 7 = -6 ≠ 8 .

So , this point does not lie on graph of f(x) .

Option(c) ,

the ordered pair is (-2,-8) ,

f(-2) = (1/2)*(-2) - 7 = -1 - 7 = -8 = -8 .

So , this point lies on graph of f(x) .

Option(d) ,

the ordered pair is (0,-7) ,

f(2) = (1/2)*0 - 7 = - 7 = -7 .

So , this point lies on graph of f(x) .

Therefore , the ordered pair (2,8) is not on the graph .

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Answer

P(A∩B) = 0.021

Step-by-step explanation:

For independent events P(A∩B) is the same as P(A)*P(B) so for this 0.42*0.05 = 0.021

As per the forecast, the updated forecast for the amazon sales accounting for trend, seasonality and adjusted for the serial correlation using the AR(1) model is 75.243.

In statistics, the term correlation defines the degree to which two variables move in coordination with one another.

Here we have Quarterly Amazon Sales (billion dollars) starting in Quarter 3 of 2013 through Quarter 2 of 2021 . And assume in Quarter 2 of 2021 the Amazon Sales were 96.6 billion dollars.

Now we have to use the output provided below to report the updated forecast for the Amazon Sales for Quarter 3 of 2021.

Here the variable time period is coded in the following way:

Start with

t=1 for Quarter 3 of 2013,

t=2 for Quarter 4 of 2013 .

Then the value of t will increase by 1 for each subsequent quarter.

Here in this example we have created indicator variables for Quarters 1, 2 and 3. Quarter 4 is the base level.

Now, by using the output here for the model accounting for trend and seasonality as well as the output for the AR(1) model report the updated forecast for Amazon Sales in Quarter 3 of 2021.

Here the subset of the output posted below: Response Revenues Bivariate Fit of Residual Revenues $2 By Lag residuals Parameter Estimates

Therefore, the Updated forecast for the Amazon Sales accounting for Trend, Seasonality and Adjusted for the Serial Correlation using the AR(1) model is 75.243

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Answer:

3.12

Step-by-step explanation:

1 number after the decimal - tenths place.

2 numbers after the decimal - hundredths place.

3 numbers after the decimal - thousandths place.

4 numbers after the decimal - ten thousandths place.

5 numbers after the decimal - hundred thousandths place.

Answer:

3.12

Step-by-step explanation:

3.122 rounds up to 3.12 because 2 is less than 5, so the number rounds down.

The amount Harry has in his account is $2,694.50

The amount Sally has in his account is $2,714.23.

Sally made the best investment.

It is the interest we earned on the interest.

The formula for the amount earned with compound interest after n years is given as:

A = P [tex](1 + r/n)^{nt}[/tex]

P = principal

R = rate

t = time in years

n = number of times compounded in a year.

We have,

Harry:

P = $2500

T = 3 years

r = 2.5%

n = 12

A = 2500 [tex](1 + 0.208)^{36}[/tex]

A = 2500 x [tex]1.208^{36}[/tex]

A = $2,694.50

Sally:

P = $2500

T = 3 years

r = 2.75%

n = 4

A = 2500 [tex](1 + 0.69)^{12}[/tex]

A = 2500 x [tex]1.69^{12}[/tex]

A = $2,714.23

Thus,

Harry has $2,694.50 in his account.

Sally has $2,714.23 in his account.

Sally made the best investment.

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The value of the other points in the number line for each case are;

a) M = -2¹/₂

N = -1

R = 4

b) M = -1

P = 1

R = 1.6

c) M = -125

P = 125

N = -50

d) N = -6

P = 15

R = 24

a) We are given that P = 2¹/₂

From the point 0 of the number line to point P is 5 units and as such;

Each unit = 2¹/₂/5 = ¹/₂

Thus;

M = -2¹/₂

N = -1

R = 4

b) We are given that N = -0.4

From the point 0 of the number line to point N is 2 units and as such;

Each unit = 0.4/2 = 0.2

Thus;

M = -1

P = 1

R = 1.6

C) We are given that R = 200

From the point 0 of the number line to point R is 8 units and as such;

Each unit = 200/8 = 25

Thus;

M = -125

P = 125

N = -50

D) We are given that M = -15

From the point 0 of the number line to point N is 5 units and as such;

Each unit = 15/5 = 3

Thus;

N = -6

P = 15

R = 24

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