what is the sample size need to reduce the margin of error to 3.1% for a 95% confidence interval given that the proportion is unknown.

The supplementary angle means the sum of angles will be 180°. Hence the supplementary angle (or supplement) to a 55º angle is 125°.

When adding two or more angles, the result is 180°, and such pairs of angles are called linear pairs. The word 'linear' means 'straight', and 180° is also referred to as a straight angle. That is why a linear pair is always 180°.

Given angle is 55°.

To find the supplementary angle or supplement of 55º we must subtract 55º from 180°.

That is Supplement = 180 - 55 = 125°.

This is because supplementary angle means sum of two angles results in 180°.

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Ms. Roberts will pay $9.375 for the grapes.

We have,

To calculate the cost of the grapes, you can multiply the weight of the grapes by their price per pound.

Weight of grapes = 4 3/4 pounds

Price per pound = $2.50

Total cost of grapes = (4 3/4 pounds) x ($2.50/pound)

First, we need to convert the mixed number 4 3/4 to an improper fraction:

= 4(3/4)

= (4 x 4 + 3)/4

= 19/4

Now, we can multiply:

Total cost of grapes = (19/4) x ($2.50/pound)

Simplifying the fractions:

Total cost of grapes = $9.375

Therefore,

Ms. Roberts will pay $9.375 for the grapes.

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Using the top number line, p + q and p + (-q) can be located as shown in the attached image.

A number line is a line on which numbers are marked at intervals, used to illustrate simple numerical operations. It is also a pictorial representation of the real numbers.

Since point p has a value of 2 and point q has |q| = 5. We can say:

p + q = 2 + 5 = 7

p + (-q) = 2 + (-5) = -3

Therefore, using the top number line, we can then locate p + q and p + (-q) with their calculated values (Check the green dot in the attached image).

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Complete Question

Check the attached image

Answer: 12

Step-by-step explanation:

Using Phytagorean theorem

[tex]r^{2} = \sqrt{} y^{2} +x^{2}[/tex]

given: r=20 and y=16

[tex]20^{2} =\sqrt16^{2} +x^{2} \\400=\sqrt{256+ x^{2} \\[/tex]

move x to the other side (when x is moving to the other side the sign change)

x²= √400-256       subtract  

x= √144      take the square root

x=  12

The value of x is given as follows:

x = 12.25

Similar triangles are triangles that share these two features listed as follows:

The proportional relationship for the side lengths in this problem is given as follows:

x/7 = 3.5/2

Applying cross multiplication, the value of x is obtained as follows:

2x = 7 x 3.5

x = 7 x 3.5/2

x = 12.25.

The triangle is given by the image presented at the end of the answer.

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According to the equation, Carmine used 4.7 pounds of almonds in the mixture.

To represent this relationship mathematically, we can use an equation. Let's use "a" to represent the weight of the almonds in pounds. Then, we can write:

2.8 + a = total weight of the trail mix

We can then solve for "a" by subtracting 2.8 from both sides of the equation:

a = total weight of the trail mix - 2.8

We also know that the trail mix is divided into 5 equal portions, each weighing 1.5 pounds. Therefore, the total weight of the trail mix is:

total weight of the trail mix = 5 * 1.5

total weight of the trail mix = 7.5

Substituting this value into the equation we derived earlier, we get:

a = 7.5 - 2.8

a = 4.7

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Answer:

16286.01632

Step-by-step explanation:

V=πr2h=π·122·36≈16286.01632

Answer:

(x+2)^2+(y-5)^2=81

Step-by-step explanation:

standard form equation is (x-h)^2+(y-k)^2=r^2

so, input the values:

(x+2)^2+(y-5)^2=9^2

simplify:

(x+2)^2+(y-5)^2=81

       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Answer:

∠PQT and ∠TQR.

Step-by-step explanation:

If you're still confused about which angles are supplementary, let me give you a hint. Imagine that RP←→ is a giant ruler that you can use to measure the angles. Now, if you place the ruler on ∠PQT and ∠PQS, you'll see that they are too small to fit the whole ruler. They only cover half of it, which means they add up to 90 degrees. That's not what we want, we want 180 degrees!

Similarly, if you place the ruler on ∠TQS and ∠SQR, you'll see that they are too big to fit the whole ruler. They overlap each other, which means they are equal. And if they are equal, they must be 90 degrees each, because that's the only way two angles can add up to 180 degrees. But we don't want two 90 degree angles, we want two different angles!

The only option left is ∠PQT and ∠TQR. If you place the ruler on them, you'll see that they fit perfectly on the whole ruler. They cover it from end to end, which means they add up to 180 degrees. That's exactly what we want! So the correct answer is ∠PQT and ∠TQR. Congratulations, you've just solved a tricky geometry problem with a simple tool!

Answer:

1 crown and 1 coin

Step-by-step explanation:

1 crown =10 cents

1 coin = 25 cents

10 +25 = 35

there were 28,800 handshakes that occurred at the meeting.

How to solve the question?

In order to calculate the number of handshakes that occurred, we can use the formula for the sum of the first n-1 positive integers. The reason we use n-1 is because each person shakes hands with n-1 other people (themselves excluded).

The formula is:

(n-1) + (n-2) + (n-3) + ... + 1

where n is the number of people in the group.

In this case, n = 240, so we plug in:

(240-1) + (240-2) + (240-3) + ... + 1

Simplifying:

239 + 238 + 237 + ... + 1

We can see that this is an arithmetic series with a common difference of -1 and a first term of 239. Using the formula for the sum of an arithmetic series, we get:

S = n/2 * (first term + last term)

S = 240/2 * (239 + 1)

S = 240/2 * 240

S = 28,800

Therefore, there were 28,800 handshakes that occurred at the meeting.

It's worth noting that this calculation assumes that each handshake is counted twice (once for each person involved). If we only counted each handshake once, then we would need to divide our final answer by 2, giving us 14,400 handshakes.

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The digit 5 in 89.059 is greater than the digit 5 in 78.365.

To compare the digit 5 in the numbers 89.059 and 78.365, we need to look at the place value of the digit 5 in both numbers. In 89.059, the digit 5 is in the thousandth place, while in 78.365, the digit 5 is in the hundredth place.

Since the digit 5 in the thousandth place has a greater place value than the digit 5 in the hundredth place, it means that the digit 5 in 89.059 is greater than the digit 5 in 78.365.

To understand this concept better, consider the place value system of decimal numbers, where each digit represents a specific place value. The rightmost digit represents the units, the next digit to the left represents the tens, and so on.

Moving leftwards, each digit's place value increases by a factor of 10. Thus, the digit 5 in the thousandth place has a place value of 0.001, which is greater than the place value of the digit 5 in the hundredth place, which is 0.01. Therefore, the digit 5 in 89.059 is greater than the digit 5 in 78.365.

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The remainder when p(x) = x^4 - 4x³ - 11x² + 66x - 72 is divided by x - 4 is given as follows:

16.

The Remainder Theorem is a theorem in algebra that provides a quick way to find the remainder of a polynomial division problem. The theorem states that when a polynomial f(x) is divided by (x - a), the remainder is equal to f(a).

Hence for this problem, the remainder is given by the numeric value at x = 4, which is calculated as follows:

p(4) = 4^4 - 4(4)³ - 11(4)² + 66(4) - 72

p(4) = 16.

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Answer:

6

Step-by-step explanation:

Half of six is 3. That would be 50%. 6 at 100% is simply 6.

The graph of this function would be a straight line passing through the point (0, c) with a slope of m.

What is the function?

A function is a relation between a set of inputs and a set of possible outputs, with the property that each input is related to exactly one output.

If the function increases at a constant rate of m and has a y-intercept of (0, c), then its equation can be written as:

f(x) = mx + c

The graph of this function would be a straight line passing through the point (0, c) with a slope of m.

Here's an example of the graph of f(x) = 2x + 3:

Attachment

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The nurse should administer 0.88 mL of the cefazolin solution for the 550 mg IM dose.

To determine the number of mL to administer for the 550 mg IM dose of cefazolin, follow these steps:
Determine the concentration of cefazolin per mL:
- You have a 2-g (2000 mg) vial of cefazolin that was diluted with 3 mL of diluent, yielding a total volume of 3.2 mL.
- Divide the total amount of cefazolin (2000 mg) by the total volume (3.2 mL) to find the concentration per mL: 2000 mg / 3.2 mL = 625 mg/mL.
Calculate the volume needed for the 550 mg dose:
- Divide the prescribed dose (550 mg) by the concentration per mL (625 mg/mL):

550 mg / 625 mg/mL = 0.88 mL.

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The nurse should administer 0.88 mL of the cefazolin solution intramuscularly to the client.

To determine the mL to administer for the 550 mg IM order of cefazolin, follow these steps:

1. Calculate the concentration of cefazolin in the solution:
  - 2,000 mg (2-g vial) of cefazolin is diluted with 3 mL of diluent, yielding a volume of 3.2 mL.
  - Concentration = (2,000 mg) / (3.2 mL) = 625 mg/mL

2. Determine the volume needed for the 550 mg prescribed dose:
  - Volume = (Prescribed Dose) / (Concentration)
  - Volume = (550 mg) / (625 mg/mL) = 0.88 mL

Cefazolin is an antibiotic used to treat various bacterial infections. The dosage of cefazolin depends on the type and severity of the infection, as well as the patient’s weight, age, and kidney function12. The usual adult dose for mild to moderate infections ranges from 250 mg to 1 g every 6 to 12 hours

The nurse should administer 0.88 mL of the cefazolin solution intramuscularly to the client.

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Based on the equation 441 + b² = 3011.81, the value of b is equal to 50.7032.

In Mathematics, an exponent is a mathematical operation that is typically used in conjunction with an algebraic expression in order to raise a quantity to the power of another.

This ultimately implies that, an exponent is represented by the following mathematical expression;

bⁿ

Where:

Based on the given equation, we have the following;

441 + b² = 3011.81

By subtracting 441 from both sides of the equation, we have the following:

441 + b² - 441 = 3011.81 - 441

b² = 3011.81 - 441

b² = 2570.81

b = √2570.81

b = 50.7032.

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Based on the information provided, a test-taker who scores at the 5th stanine is scoring:
C. within the average range.

To better understand this, let's break down the terms and concepts involved:
Stanine: Stanine (short for "standard nine") is a method used to scale test scores on a nine-point scale.

The stanine scores range from 1 (lowest) to 9 (highest).

This method is typically used in educational assessments to categorize students' performance.
Average: In the context of test scores, the average score refers to the middle range of scores that is typical for the majority of test-takers.

In the case of stanine scores, the average range falls between 4 and 6.

This means that students scoring in stanines 4, 5, and 6 are considered to be within the average range.
Now, to answer your question, a test-taker who scores at the 5th stanine is considered to be within the average range of performance.

This is because their score falls between the 4th and 6th stanines, which, as mentioned earlier, encompass the average range.

It's important to note that this doesn't mean the student is performing poorly; rather, their performance is on par with the majority of other test-takers.

Option C. within the average range is correct.  

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The area of the irregular polygon is equal to 30.5 square units.

In this problem we find the representation of an irregular pentagon, that is, a polygon of five sides of different length. Whose area can be found by adding the areas of rectangles and triangles:

Rectangle

A = b · h

Triangle

A = 0.5 · b · h

Where:

Now we proceed to determine the area of the irregular polygon:

A = 0.5 · 1 · 4 + 0.5 · 3 · 2 + 2 · 4 + 0.5 · 3 · 2 + 3 · 4 + 0.5 · 5 · 1

A = 2 + 3 + 8 + 3 + 12 + 2.5

A = 30.5

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The area of the composite shape are

1. Orange

2. Light blue

3. Purple

4. Green

5. Red

6. Yellow

7. Light green

8. Yellow

9. Dark blue

10. Pink

The area of the composite shapes are solved as follows

1. rectangles

= 7 * 3 + (15 - 7) * 1.5

= 21 + 12

= 33 square cm

2.

= 39 x 4 + 0.5(39 + 26) x (18 - 4)

= 156 + 455

= 611 square m

3.

= 12 * 15 + 0.5 x 15 x 10

= 180 + 75

= 255 square ft

4.

= 15 x 7 + 0.5 x π x 3.5 x 3.5

= 105 + 19.24

= 124.2 square cm

5.

= 0.5 x 10 x 22 - 0.5 x 6 x 12

= 110 - 36

= 74 square yd

6.

= 0.5 x π x 3 x 3 + 0.5 x 6 x 11

= 14.14 + 33

= 47.1 square m

7.

= 18 x 6 - 2 x π x 2 x 2

= 108 - 25.13

= 82.8 square m

8.

= 4 x 16 + 0.5 (16 + 10) x (8 - 4)

= 64 + 52

= 116 square cm

9.

= 18 x 8 - 4 * 0.5 x 4 x 4

= 144 - 32

= 112 square cm

10.

= [0.5 (7 + (9 + 3)) x (15 + 6 - 17)] + [(17 - 6) x (9 + 3)] + [6 x 9]

= 38 + 132 + 54

= 224 square cm

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For a loan of $24,000 at 6% interest over 60 months, the monthly payment is $466.47.

A monthly payment is the sum of money that is made towards a debt or loan on a regular basis; it normally consists of both the main and interest. It is a set sum that the borrower must consistently pay until the debt is repaid in full. Mortgages, auto loans, student loans, and personal loans all frequently include monthly installments. The loan amount, the interest rate, and the term of the loan all affect how much will be paid each month.

We can use the following calculation to determine a loan's monthly payment:

M = P * (r * (1 + r)ⁿ) / ((1 + r)ⁿ⁻¹)

where:

M = payment each month

P = Principal (the loaned amount)

r = (Divide the annual interest rate by 12 to get the monthly interest rate)

n = total payments (12 divided by the number of years)

By entering the specified values, we obtain:

P = 24000

r = 6% / 12 = 0.005

n = 60

M = 24000 * (0.005 * (1 + 0.005)⁶⁰) / ((1 + 0.005)^60 - 1)

M = $466.47 (rounded to the nearest cent)

So, $466.47 is the monthly payment for a $24,000 loan with a 6% interest rate over 60 months.

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Six semicircles lie in the interior of a regular hexagon with a side length of 2 so that the diameters of the semicircles coincide with the sides of the hexagon. The zone of the shaded locale is around 10.3923 square units.

 We will approach this problem by first finding the region of the hexagon and after that subtracting the zones of the six semicircles from it. The zone of a customary hexagon with side length 2 can be found utilizing the equation:

Region of hexagon = (3√3/2) x side[tex]^{2}[/tex]

Substituting the given esteem of side length, we get:

Area of hexagon = (3√3/2) x 2[tex]^{2}[/tex] = 6√3

The range of a crescent is half the region of the comparing circle. So, the zone of each crescent is:

Range of semicircle = 1/2 x π x radius[tex]^{2}[/tex] = 1/2 x π x 1^[tex]^{2}[/tex]= π/2

There are six semicircles, so the whole range of the semicircles is:

Add up to the zone of semicircles = 6 x π/2 = 3π At long last, able to find the zone of the shaded locale by subtracting the region of the semicircles from the range of the hexagon:

Zone of shaded locale = Range of hexagon - Add up to a range of semicircles

= 6√3 - 3π

≈ 10.3923 thus, the zone of the shaded locale is around 10.3923 square units. 

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Answer: 729

Step-by-step explanation:

3^2 is the same has 3 to the power of 2

9^2 is the same as 9 to the power of 2

When you see an expression like 3^2 x 9^2, it means you must raise 3 and 9 to the power of 2, multiply those numbers, and then do it again.

3 raised to the power of 2, often known as 3 times itself or 3 x 3, equals 9.

9 raised to the power of 2, often known as 9 times itself (9 x 9), equals 81.

As a result, when we change these values in the original expression, we obtain:

3^2 x 9^2 = 9 x 81

Now that we have these two integers, we can easily multiply them to obtain the result:

9 x 81 = 729

Therefore, 729 is the answer to the equation 3^2 x 9^2.

The length or value of d is 3m

What is meant by length?

Length is a measurement of how long something is, typically referring to the longest dimension of an object or space. It is a fundamental physical quantity and can be measured in various units, such as meters, feet, or inches. Length is important in many fields, including mathematics, science, and engineering.

According to the given information

In a right-angled triangle, the side opposite to the 90-degree angle is called the hypotenuse. The side opposite to the 60-degree angle is equal to the hypotenuse multiplied by the square root of 3 divided by 2. Since AC is the hypotenuse and its length is given as 2*(√(3))m, we can find the length of BC (d) as follows:

d = (AC * √(3)) / 2 d = (2 * √(3) * √(3)) / 2

d = 3m

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