The prescribed minimum water pressure in a water distribution system is not less than option C: 20 psi at ground level, at any time, including fire flow conditions.
However, the minimum pressure shouldn't be less than 25 psi when there is a maximum instantaneous demand. The distribution system's typical working pressure shouldn't be lower than 35 psi. Pressure reduction devices should be used to control pressures that could be higher than 90 psi.
In order to keep pressure within a desirable range across a distribution system, which may have different terrain and water demand, pressure control is necessary. Effective pressure control can reduce main breaks, maintain excellent water quality, and reducing water waste and increasing energy efficiency.
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What is the volume, in cubic inches, of a brick that is 4.0 in × 2.7 in × 8.0 in?A) 15 in3 B) 51 in3 C) 78 in3 D) 87 in3 E) 150 in3
The closest answer choice is D) 87 in3, which is only 0.6 cubic inches more than the actual volume.
To find the volume of the brick, we need to multiply its length, width, and height.
V = l x w x h
Plugging in the given dimensions, we get:
V = 4.0 in x 2.7 in x 8.0 in
V = 86.4 cubic inches
Therefore, the volume of the brick is 86.4 cubic inches.
The closest answer choice is D) 87 in3, which is only 0.6 cubic inches more than the actual volume.
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a u-shaped tube with both arms open to the air has a 35.0 cm column of liquid of unknown density in its right arm. beneath this liquid and not mixing with it is glycerin that extends into the left arm of the tube. the surface of the glycerin in the left arm is 12.0 cm below the surface of the unknown liquid in the right arm. what is the density of the unknown liquid?
The density of the unknown liquid is 1.52 times the density of glycerin.
The pressure at the surface of the glycerin in the left arm of the u-shaped tube is equal to the pressure at the surface of the unknown liquid in the right arm. Since both arms are open to the air, the pressure at the surface of the glycerin is atmospheric pressure. Therefore, the pressure at the surface of the unknown liquid is also atmospheric pressure.
Using the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is height, we can set up two equations:
P = ρ₁gh₁ (for the unknown liquid in the right arm)
P = ρ₂gh₂ (for the glycerin in the left arm)
Since the pressure is the same in both arms and g is the same for both liquids, we can set the two equations equal to each other:
ρ₁gh₁ = ρ₂gh₂
We are given that h₂ - h₁ = 12.0 cm. Substituting h₂ - h₁ for h₁ in the equation above, we get:
ρ₁g(h₂ - 12.0) = ρ₂gh₂
Simplifying, we get:
ρ₁ = (ρ₂gh₂) / (g(h₂ - 12.0))
We are given that the height of the unknown liquid in the right arm is 35.0 cm. Substituting the given values, we get:
ρ₁ = (ρ₂ x 9.81 x 35.0) / (9.81 x (35.0 - 12.0))
Simplifying, we get:
ρ₁ = (35.0/23.0)ρ₂
So, the density of the unknown liquid is 1.52 times the density of glycerin.
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what is the energy of a 0.051 kg tennis ball moving at 9.7 m/s
Answer: 2.390 J (joules).
Explanation:
Given:
Mass of tennis ball = 0.051 kg
Velocity of tennis ball = 9.7 m/s
To find:
Kinetic energy of the tennis ball
Solution:
Using the formula for kinetic energy:
Kinetic energy = (1/2) * mass * velocity^2
Plugging in the values:
Kinetic energy = (1/2) * 0.051 kg * (9.7 m/s)^2
Kinetic energy = (1/2) * 0.051 kg * 94.09 m^2/s^2
Kinetic energy = 2.390 J
Therefore, the kinetic energy of a 0.051 kg tennis ball moving at 9.7 m/s is 2.390 J (joules).
Assertion
The compressive strength of a typical brittle material is significantly higher than its tensile strength.
Reason
In compression force between the molecules increases.
The compressive strength of a typical brittle material is significantly higher than its tensile strength.a. Both Assertion and Reason are correct and Reason is the correct explanation for Assertionb. Both Assertion and Reason are correct but Reason is not the corect explanation for Assertionc. Assertion is correct but Reason is incorrectd. Both Assertion and Reason are incorrect
The Assertion mentioned in the question is that the compressive strength of a typical brittle material is significantly higher than its tensile strength.
This statement is correct because brittle materials are those materials that break easily upon the application of a force. Brittle materials do not have any plastic deformation region and have a limited range of elasticity.
Due to this, when a compressive force is applied to a brittle material, it tends to resist the force and does not break easily.
On the other hand, when a tensile force is applied to a brittle material, it tends to break easily as it does not have the ability to stretch.
However, the Reason mentioned in the question, which is not correct, states that the compressive forces act more uniformly across the cross-section of a brittle material than tensile forces.
This statement is not true because the distribution of compressive and tensile forces across the cross-section of a brittle material is similar.
Therefore, the correct option is C, where the Assertion is correct, but the Reason is incorrect.
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The assertion in the question is that a typical brittle material has a compressive strength that is much greater than its tensile strength.
This assertion is true because brittle materials are ones that shatter easily when pressure is applied. Materials that are brittle have a small elastic range and no plastic deformation zone.
Because of this, brittle materials have a tendency to resist compressive forces and do not break easily.
A brittle material, on the other hand, is incapable of stretching, thus when a tensile force is applied to it, it tends to break quickly.
The Reason given in the question, which is incorrect, claims that compressive forces behave more evenly across a brittle material's cross-section than tensile forces do.
This is untrue because brittle materials have similar distributions of compressive and tensile forces across their cross-sections.
The right response is therefore C, where the Assertion is true but the Reason is false.
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2.) Convert 200 degrees to radians
A.) (9/10)Ï
B.) Ï
C.) (10/9)Ï
D.) 10Ï
The answer is C.) (10/9)Ï.
To convert degrees to radians, we use the formula: radians = (pi/180) * degrees
Plugging in 200 degrees, we get: radians = (pi/180) * 200
Simplifying, we get: radians = (10/9) * pi
Therefore, the answer is C.) (10/9)Ï.
To convert 200 degrees to radians, use the formula:
Radians = (Degrees × π) / 180
So, for 200 degrees:
Radians = (200 × π) / 180
Radians = (20 × π) / 18
Radians = (10/9)π
Your answer: C.) (10/9)π
Radians are a unit of measurement used to measure angles in the context of mathematics and physics. One radian is defined as the angle subtended at the center of a circle by an arc that is equal in length to the radius of the circle.
More specifically, if we have a circle with radius r, and we draw an arc that is the same length as r, then the angle formed by the two radii extending to the endpoints of the arc is 1 radian. This angle is equivalent to approximately 57.3 degrees.
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A bat strikes a 0.050-kg baseball so that its velocity changes by +32 m/s in 0.080 s. With what average force was the ball struck?
The average force with which the ball was struck is 20 N.
We can use the impulse-momentum theorem to solve this problem. The impulse-momentum theorem states that the force acting on an object is equal to the change in momentum of the object divided by the time interval over which the change occurs:
F = Δp / Δt
where F is the average force, Δp is the change in momentum, and Δt is the time interval.
In this case, the change in momentum of the baseball is:
Δp = mΔv = (0.050 kg)(32 m/s) = 1.6 kg m/s
The time interval over which this change occurs is:
Δt = 0.080 s
Therefore, the average force acting on the baseball is:
F = Δp / Δt = (1.6 kg m/s) / (0.080 s) = 20 N
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julia performs an experiment to measure the wavelength of four different waves and records her data in the table below.a 2-column table with 4 rows titled julia's waves. the first column labeled wave has entries 1, 2, 3, 4. the second column labeled information has entries this wave has 3 centimeter amplitude, the distance from the midpoint to the crest is 6 centimeters, the distance from the midpoint to the trough is 12 centimeters, this wave has a 4 centimeter amplitude.which accurately ranks the waves from the lowest energy wave to the highest energy wavehow has the change in media affected the frequency of the wave?
A wave's frequency varies when it moves from one medium to another. This is due to the fact that a wave's wavelength doesn't change when it enters a different medium, but its speed does. This is referred to as the frequency-wavelength relationship of the wave.
Based on the information provided in the table, the waves can be ranked from lowest energy to highest energy as follows: wave 1, wave 2, wave 3, and wave 4.
This is because wave energy is directly proportional to its amplitude and frequency, and in this case, the amplitude of wave 1 is the lowest, followed by wave 2, wave 3, and wave 4.
When a wave travels from one medium to another, its frequency changes.
This is because the speed of the wave changes when it enters a different medium, while its wavelength remains constant. This is known as the wave's frequency-wavelength relationship.
When the wave enters a denser medium, its speed decreases, and its frequency decreases as well. On the other hand, when the wave enters a less dense medium, its speed increases, and its frequency increases as well. Therefore, the change in media can affect the frequency of the wave.
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A force of 30 N stretches a spring 0.73 m from equilibrium. What is the value of the spring constant? A) 41 N/m B) 22 N/mC) 34 N/m D) 46 N/m
In the Biot-Savart relation to find the magnetic field at point P, 0 2 ˆ ( ) 4 Ids r B P r , the integral is over:
The Boit-Savart Law provides us with a way to find the magnetic field at an empty point in space, let’s call it point Pdue to current in wire. The idea behind the Boit-Savart Law is that each infinitesimal element of the current-carrying wire makes an infinitesimal contribution to the magnetic field at the empty point in space.
The Bito-Savart relation to find the magnetic field at point P, the integral is over the current-carrying element Ids that generates the magnetic field, and the integration is performed along the path from the current-carrying element to the point P. So, the integral in the Boit-Savart relation is over the path of the current-carrying element that generates the magnetic field. The idea behind the Boit-Savart Law is that each infinitesimal element of the current-carrying wire makes an infinitesimal contribution to the magnetic field at the empty point in space. Once you find each contribution, all you have to do is add them all up.
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for the image below, the focal length is 1/2 of the radius of curvature, object distance is 247 cm. the size of the object is 46 cm. what is the image size equal to in cm? remember that it could be positive or negative.
The image of the object is 12.4 cm.
Using the given values, we can use the lens formula: 1/f = 1/[tex]d_{0}[/tex] + 1/[tex]d_{i}[/tex], where f is the focal length, [tex]d_{0}[/tex] is the object distance, and di is the image distance. Rearranging the formula to solve for di, we get: [tex]d_{i}[/tex]= 1/(1/f - 1/[tex]d_{0}[/tex]).
Substituting the given values, we get:
[tex]d_{i}[/tex] = 1/(1/(2r) - 1/247)
[tex]d_{i}[/tex] = -65.34 cm (negative sign indicates that the image is formed on the opposite side of the lens)
To find the image size, we can use the magnification
formula: m = [tex]h_{i}[/tex]/[tex]h_{0}[/tex] = -[tex]d_{i}[/tex]/[tex]d_{0}[/tex], where [tex]h_{i}[/tex] is the image size and [tex]h_{0}[/tex]is the object size.
Substituting the given values, we get:
m = [tex]h_{i}[/tex]/[tex]h_{0}[/tex] = -(-65.34)/247
m = 0.264
Rearranging the formula to solve for hi, we get:
[tex]h_{i}[/tex]= m * [tex]h_{0}[/tex]
[tex]h_{i}[/tex] = 0.264 * 46 cm
[tex]h_{i}[/tex] = 12.14 cm
Therefore, the image size is equal to 12.14 cm (rounded to two decimal places).
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1. Explain how it is possible for a large force to produce a small torque, and how it is possible for a small force to produce a large torque.
A large force can produce a small torque when the force is applied perpendicular to the point of rotation, resulting in a shorter lever arm.
Conversely, a small force can produce a large torque when it is applied perpendicular to the point of rotation but at a greater distance from the pivot point, resulting in a longer lever arm. The torque produced by a force is calculated by multiplying the force by the distance from the pivot point, or lever arm. Thus, the amount produced depends on both the magnitude of the force and the distance from the pivot point. When a large force is applied perpendicular to the pivot point but at a short distance, the resulting torque is relatively small. Similarly, when a small force is applied perpendicular to the pivot point but at a greater distance, the result can be relatively large.
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(340-12) Type UF cable shall not be used where subject to physical damage. When this cable is subject to physical damage, it shall be protected by a suitable method such as a raceway.(True/False)
The given statement, type UF cable shall not be used where subject to physical damage. When this cable is subject to physical damage, it shall be protected by a suitable method such as a raceway, is true because it can cause damage to the insulation or conductors of the cable, leading to electrical hazards such as short circuits, electrical shocks, or fires.
Type UF cable is an underground feeder cable commonly used for outdoor wiring applications. According to the National Electrical Code (NEC), Type UF cable should not be used where it is subject to physical damage, such as being exposed to impact, compression, or penetration.
If the cable is installed in an area where it is likely to be subject to physical damage, it must be protected by a suitable method such as a raceway. The use of a raceway can provide an additional layer of protection to prevent damage to the cable, ensuring that it remains safe and functional for its intended use.
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Which student is doing work? Sara exerts a 20 N force forward on a bowling ball that rolls forward 1.0 m. Jane exerts a 45 N force upward while holding a ball above the ground. Jim exerts a 65 N force to hold a ball while spinning in a circle. Amy exerts a 55 N force to hold up a bowling ball as she walks toward the bowling lane.
Sara is doing work by exerting a 20 N force forward on a bowling ball that rolls forward 1.0 m.
Work is defined as the product of force and distance when the force is applied in the direction of motion. In this case, Sara exerts a 20 N force forward on a bowling ball that rolls forward 1.0 m. Since the force and the direction of motion are in the same direction, Sara is doing work.
Jane exerts a 45 N force upward while holding a ball above the ground. Since the ball is not moving, Jane is not doing any work.
Jim exerts a 65 N force to hold a ball while spinning in a circle. Although the ball is moving, Jim is not doing any work because the force he exerts is perpendicular to the direction of motion.
Amy exerts a 55 N force to hold up a bowling ball as she walks toward the bowling lane. Since the force and the direction of motion are perpendicular, Amy is not doing any work.
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if one atmosphere of pressure is equal to 760 torr, a pressure of 687 torr is equal to what value in atmospheres (atm)?
To convert 687 torr to atmospheres (atm), you can use the given relationship:
1 atm = 760 torr.
To find the value in atmospheres, simply divide the pressure in torr by the conversion factor:
687 torr ÷ 760 torr/atm ≈ 0.904 atm
So, a pressure of 687 torr is approximately equal to 0.904 atmospheres.
To explain this, we can say that one atmosphere (atm) of pressure is defined as the pressure exerted by the weight of the earth's atmosphere at sea level. Torr is another unit of pressure, named after the Italian physicist Evangelista Torricelli. It is defined as the pressure exerted by a column of mercury 1 millimeter high at 0 °C.
Since 760 torr is equal to one atmosphere of pressure, we can use this conversion factor to convert between the two units. In this case, we are given a pressure of 687 torr, and we use the conversion factor of 760 torr/atm to convert it to atmospheres.
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properties of a thermal radiator include group of answer choices the power radiated is proportional to the temperature raised to the fourth power. hotter objects emit more light for a given area. hotter objects look redder hotter objects look bluer hotter objects emit less light for a given area. the power radiated is inversely proportional to the temperature.
The properties of a thermal radiator include the fact that the power radiated is proportional to the temperature raised to the fourth power. This means that as the temperature of the thermal radiator increases, the amount of power radiated increases exponentially.
The hotter objects emit more light for a given area, which means that the brightness of the thermal radiator will increase as it gets hotter. However, as the temperature increases, the color of the radiation will also change. Specifically, hotter objects will look redder, while cooler objects will look bluer. Finally, it is important to note that the power radiated by a thermal radiator is directly proportional to its temperature, not inversely proportional. Here is an answer incorporating the requested terms The power radiated by a thermal radiator is proportional to the temperature raised to the fourth power, according to the Stefan-Boltzmann Law. This means that hotter objects emit more light for a given area. hotter objects look bluer, as the peak wavelength of their emitted radiation shifts towards the shorter blue end of the spectrum, while cooler objects look redder as their peak wavelength shifts towards the longer red end of the spectrum.
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what is the initial angular momentum of the ball, in newton seconds, right before the collision relative to the pivot point of the rod?
To calculate the initial angular momentum of the ball right before the collision relative to the pivot point of the rod, we need some information about the ball and the system, such as the mass of the ball, its velocity, and the distance from the pivot point to the collision point.
Did you ever find yourself wishing for an angular momentum calculator. We think we have all wished, at some point in our lives, that we had a calculator which would come and solve our physics queries. Well, don t worry, your wish has been answered with this calculator that tells you how to calculate angular momentum. Our angular momentum calculator is a user-friendly tool that allows you to find angular momentum in two ways, so you can use it with all the data you have gathered. We will also talk about the conservation of angular momentum and some examples.
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Terminal Rating(110-14(c)(1): Equipment terminals rated 100 amperes or less (circuit breakers, fuses, etc.) and pressure connector terminals for No. 14 through No. 1 conductors shall have the conductor sized according to _____ degree temperature rating as listed in Table 310.15(a)(16)
The conductor for equipment terminals rated 100 amperes or less and pressure connector terminals for No. 14 through No. 1 conductors shall be sized according to the temperature rating listed in Table 310.15(a)(16), which is typically 60 degrees Celsius or 75 degrees Celsius depending on the type of insulation used for the conductor. This is specified in the Terminal Rating (110-14(c)(1)) section of the National Electrical Code (NEC).
According to NEC section 110-14(c)(1), equipment terminals rated 100 amperes or less and pressure connector terminals for No. 14 through No. 1 conductors should have the conductor sized according to the 60-degree Celsius temperature rating as listed in Table 310.15(a)(16).
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Water Heater: What size conductor and protection device is required for a 4500 VA, 240 Volt water heater(422.11(e)?
For a 4500 VA, 240 Volt water heater, you'll need a 12 AWG copper conductor and a 20 A circuit breaker for proper protection as per the NEC 422.11(e) guidelines.
To determine the size of the conductor and protection device needed for a 4500 VA, 240 Volt water heater, you'll need to follow these steps:
1. Calculate the current (Amperes) for the water heater:
Current (A) = Power (VA) / Voltage (V)
Current = 4500 VA / 240 V = 18.75 A
2. Select the appropriate conductor size based on the calculated current. In this case, using the National Electrical Code (NEC) guidelines, you can use a 12 AWG copper conductor, which has an ampacity of 20 A.
3. Choose the protection device for the water heater circuit. Since the calculated current is 18.75 A, a circuit breaker rated for 20 A should be used, according to the NEC.
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What is the recommended minimum water pressure in a distribution system at any time, including fire flow conditions?
a) Greater than Zero
b) 10 psi
c) 20 psi
d) 30 psi
The recommended minimum water pressure in a distribution system at any time, including fire flow conditions, is 20 psi. Therefore, the correct answer is option c) 20 psi.
According to industry standards, the minimum recommended pressure is greater than zero, meaning that there should always be some level of pressure present in the system. However, a pressure of at least 20 psi is typically required to ensure that water is able to flow effectively through the distribution network, even under high demand or fire flow conditions. This minimum pressure also helps to ensure that water is delivered at an adequate rate and volume to meet the needs of consumers, such as for cooking, cleaning, and other household uses.
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Methods of Physical Control:
Heat
•Elevated temperatures are____.
•Lower temperatures are_____.
•___ ___: hot water, boiling water, or steam between 60°C and 135°C
•______ ____: hot air or an open flame, which ranges from 160°C to thousands of degrees Celsius
Methods of Physical Control:
Heat
•Elevated temperatures are effective in killing microorganisms.
•Lower temperatures are effective in slowing down growth and reproduction.
•Moist heat: hot water, boiling water, or steam between 60°C and 135°C
•Dry heat: hot air or an open flame, which ranges from 160°C to thousands of degrees Celsius
Methods of physical control involve the use of various physical agents to control or eliminate microorganisms. Heat is one such agent that is commonly used. Elevated temperatures are effective in killing microorganisms, as they denature the proteins and nucleic acids that are essential for their survival. Lower temperatures, on the other hand, slow down their growth and reproduction.
Moist heat is more effective than dry heat, and some examples of moist heat include hot water, boiling water, or steam between 60°C and 135°C. These can be used to disinfect surfaces, equipment, and even food products.
Dry heat, such as hot air or an open flame, is less effective than moist heat but is still used in certain applications. This ranges from 160°C to thousands of degrees Celsius and can be used for sterilizing instruments, glassware, and other heat-resistant materials. Overall, the choice of heat treatment depends on the type of microorganism being targeted, the nature of the material being treated, and the desired outcome.
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the second screen has a total width of 20 m. what is the maximum order (the largest m) that will be observed
The maximum order (m) that can be observed is 19, because the total width of the second screen is 20 m, and the order (m) must always be one less than the total width.
What is width?Width is the distance across an object or space, measured in the linear direction perpendicular to its length. The width of an object is typically measured by its length, breadth, or depth. Width is one of the three dimensions of a physical object, the other two being length and height. When measuring an area, width is the minimum distance from one side of an object or space to the other side. For example, the width of a room is the minimum distance from one wall to the opposite wall. The width of a book is the shortest distance from one cover to the other cover.
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Who used scientific experiments to determine the relationship between speed and time?
Galileo Galilei used scientific experiments to determine the relationship between speed and time.
He conducted experiments by rolling balls down inclined planes at different angles and measuring the time it took for them to reach the bottom. He observed that as the angle of the incline increased, the time it took for the ball to roll down decreased, indicating that the speed of the ball was increasing. Galileo's experiments provided the foundation for the development of the laws of motion and the principles of modern physics.
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During the eighteenth and nineteenth centuries, attempts to precisely measure the astronomical unit relied largely on rare:
During the eighteenth and nineteenth centuries, attempts to precisely measure the astronomical unit relied largely on rare astronomical events like the transit of Venus across the Sun.
The method generally involve observing the transit of Venus from different points on the Earth. It also measure the slight differences in the timing of the transit.
By using trigonometry to calculate the angles between the lines of sight to Venus from the different observation points, astronomers could likely determine the distance between the Earth and the Sun.
This method was used in the 18th and 19th centuries and was very much instrumental in determining the value of the astronomical unit to a high degree of precision.
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an athlete completes one round of a circle track of diameter 70m in 30s. what will be the distance covered and the displacement at the end of 45s respectively
So, 2200 metres were travelled, and 200 metres were moved.
The athlete will be in the exact opposite posture after his motion is finished. That is, 200 m equals 200 x diameter.
How do you determine the length of a circled track?Multiplying the circle's diameter by (pi) yields the circumference of the circle. Additionally, the circumference may be determined by multiplying the 2radius by pi (=3.14).
Simply draw a vector from your beginning point to your destination location, solve for the length of this line, and you can determine displacement. If your beginning and finishing positions are identical, as they are if you are running a circular 5K course, your displacement is 0. Displacement in physics is symbolised by the symbol s.
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Radiation
•Energy emitted from atomic activities and dispersed at high velocity through matter or space:
3
The energy emitted from atomic activities and dispersed at high velocity through matter or space is radiation.
This energy can take many forms, including electromagnetic radiation (such as gamma rays or X-rays) or particle radiation (such as alpha or beta particles). Radiation can have both beneficial and harmful effects on living organisms, depending on the dose and duration of exposure. For example, radiation therapy can be used to treat cancer, but excessive exposure to radiation can cause radiation sickness or increase the risk of cancer. Various measures can be taken to minimize the risk of radiation exposure, including shielding, monitoring, and safe handling of radioactive materials.
Complete question:
Energy emitted from atomic activities and dispersed at high velocity through matter or space:
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5. A wheel with a 0.10-m radius is rotating at 35 rev/s. It then slows uniformly to 15 rev/s over a 3.0-s interval. What is the angular acceleration of a point on the wheel?
A) -2.0 rev/s2
B) 0.67 rev/s2
C) -6.7 rev/s2
D) 42 rev/s2
E) -17 rev/s2
A wheel with a 0.10-m radius is rotating at 35 rev/s. It then slows uniformly to 15 rev/s over a 3.0-s interval. The angular acceleration of a point on the wheel is C) -6.7 rev/s².
To find the angular acceleration of a point on the wheel, we will follow these steps:
1. Convert the initial and final angular velocities from rev/s to rad/s.
2. Calculate the angular acceleration using the formula: α = (ω[tex]_{final}[/tex] - ω[tex]_{initial}[/tex]) / [tex]time_{interval}[/tex]
Step 1: Convert rev/s to rad/s
Initial angular velocity (ω[tex]_{initial}[/tex]) = 35 rev/s * (2π rad/rev) = 70π rad/s
Final angular velocity (ω[tex]_{final}[/tex]) = 15 rev/s * (2π rad/rev) = 30π rad/s
Step 2: Calculate angular acceleration (α)
Time interval = 3.0 s
α = (ω[tex]_{final }[/tex]- ω[tex]_{initial}[/tex]) / [tex]time_{interval}[/tex] = (30π - 70π) / 3 = -40π / 3 rad/s²
To convert the angular acceleration back to rev/s², divide by (2π rad/rev):
α = (-40π / 3) / (2π) = -20/3 rev/s² ≈ -6.7 rev/s²
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a current of 7.19 a in a solenoid of length 13.0 cm creates a 0.385 t magnetic field at the center of the solenoid. how many turns does this solenoid contain?
This solenoid contains approximately 155 turns.
To solve this problem, we can use the equation for the magnetic field inside a solenoid:
B = μ0 * n * I
where B is the magnetic field, μ0 is the permeability of free space (4π x 10^-7 T m/A), n is the number of turns per unit length of the solenoid, and I is the current.
We know that the current is 7.19 A, the length of the solenoid is 13.0 cm, and the magnetic field at the center is 0.385 T. We want to find the number of turns, n.
First, we need to convert the length of the solenoid to meters:
L = 13.0 cm = 0.13 m
Then, we can rearrange the equation for n:
n = B / (μ0 * I)
Plugging in the values we know, we get:
n = 0.385 T / (4π x 10^-7 T m/A * 7.19 A) ≈ 155
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When is the only time that any two objects dropped from the same height will land at the same time?
Any two objects dropped from the same height will land at the same time only if there is no air resistance.
When objects fall through a fluid medium, such as air or water, they experience a force known as air resistance or drag, which opposes their motion. This force depends on the shape, size, and velocity of the object, as well as the properties of the fluid it is falling through. In the absence of air resistance, the only force acting on an object is its weight, which is proportional to its mass. According to the law of universal gravitation, all objects near the surface of the Earth experience a gravitational force towards the center of the Earth, which is also proportional to their mass.
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Question 21
Sensitivity to radiation is probably highest:
a. Just prior to pregnancy
b. During fetal development
c. During puberty
d. During young adulthood
Sensitivity to radiation is probably highest during fetal development. Option b is correct.
Fetal tissues are rapidly dividing and have a higher metabolic rate compared to adult tissues, making them more vulnerable to the damaging effects of radiation. Exposure to ionizing radiation during fetal development can increase the risk of congenital abnormalities, and even cancer.
In contrast, the risk of radiation-induced cancer tends to increase with age due to accumulated exposure over time. While radiation exposure should be minimized during all stages of life, it is particularly important to take precautions during pregnancy to minimize the risk of harm to the developing fetus. Option b is correct.
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Assuming a serial runtime of 60s, a parallel runtime of 12s on six cores, and a fixed overhead (called "Toverhead" in the slides), what is the expected runtime in seconds with ten cores (do not include any units in the answer)?
The expected runtime with ten cores is 55.2 seconds.
To calculate the expected runtime with ten cores, we need to consider the fixed overhead and the parallel runtime.
First, we need to calculate the total overhead for the six-core parallel runtime. If the parallel runtime is 12s, we can assume that the fixed overhead is included in this time. Therefore, we can calculate the total overhead as follows:
Total overhead = Parallel runtime - Serial runtime
Total overhead = 12s - 60s
Total overhead = -48s
Note that the total overhead is negative, which means that the parallel runtime is faster than the serial runtime even when accounting for the fixed overhead.
Next, we can use the total overhead to calculate the expected runtime for ten cores. Assuming that the overhead remains constant regardless of the number of cores used, we can use the following equation:
Expected runtime = Serial runtime + (Parallel runtime - Serial runtime) / Number of cores
Plugging in the values we have:
Expected runtime = 60s + (-48s) / 10
Expected runtime = 60s - 4.8s
Expected runtime = 55.2s
Therefore, the expected runtime with ten cores is 55.2 seconds.
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