Answer: 10x2π:36x2
Explanation: So the area of the circle is πr2=10x2π. So the ratio of the area of the circle to the area of the square is 10x2π:36x2, which is equivalent to 5π:18, as required.
ORDER OF OPERATIONS.
Simplify each expression using the order of operations.
Answer:
PEMDAS.
1. PARENTHESIS
2. EXPONENTS
3. MULTIPICATION
4. DIVISION
5. ADDITION
6. SUBTRACTION
Follow the steps of BEDMAS:
B = Brackets
E = Exponents
D = Division
M = Multiplication
A = Addition
S = Subtraction
Let's try 1) with these steps.
5 - 6 + 2(3)
We can see there are brackets. When a number is placed near a bracket, it means we need to multiply.
2 x 3 = 6
Let's check our expression.
5 - 6 + 6
We can see that there is addition and subtraction. When we have addition and subtraction together we can solve left to right. The same applies to multiplication and division.
So let's solve the rest of it.
5 - 6 = -1
-1 + 6 = 5
5 is the answer to 1).
Now I hope you can solve the rest accordingly with my help. If you are in a time constraint or genuinely don't feel like doing math, understandable. In that case, simply use any online scientific calculator :)
Good Luck!!!
13 × (11 + 11) - (4 × 17) - 6 = X
Answer: 212
Step-by-step explanation:
13 * 22 - 68 - 6 = X
286 - 68 - 6 = X
286 - 74 = X
X = 212
A store manager wants to estimate the proportion of customers who spend money in this store. How many customers are required for a random sample to obtain a margin of error of at most 0.075 with 80% confidence?
The 73 customers who spend money in this store if a MOE of at most 0.075 with 80% confidence.
What is the margin of error(MOE)?MOE is an error that provides an estimate of the percentage of errors in real statistical data.
The formula for finding the MOE:
MOE = z x s/√n
Where ,
Z = the z-score at the confidence interval
s = the standard deviation
n = the number of samples.
We have p = 0.50 MOE = 0.075
Z = 1.282 at 80% confidence
0.075 = 1.282 x √0.50(1- 0.50)/ n
After solving,
n = (0.5)(0.5)/(0.0585)²
n = 73
Thus, the 73 customers who spend money in this store if a MOE of at most 0.075 with 80% confidence.
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A number is doubled, then decreased by $13.7$. The result is greater than $125.28$. What is the smallest integer that satisfies this condition?
let's say the number is "a", so
[tex]\stackrel{doubled}{2a}~~ \stackrel{decreased}{-} ~~\stackrel{by~this~much}{13.7} ~~ \stackrel{greater~than}{ > } ~~ 125.28 \\\\\\ 2a > 125.28-13.7\implies 2a > 111.58\implies a > \cfrac{111.58}{2}\implies a ~~ > ~~ 55.79[/tex]
Answer:
56
Step-by-step explanation:
Which of the following linear functions have a y-intercept of 4? Select all that apply.
y = 4
x=4
Ug=2z 8
y=x+4
y=-2 +4
Answer:
y=4
y=x+4
y=-2+4
Step-by-step explanation:
the trick is to consider x as 0.
what’s 826,125 to the nearest ten thousand ?
Answer:
830000.
Step-by-step explanation:
Given number is 825125
The number at the thousands place is 5 which is equal or above 5. So, round up the value.
rounded value of 825125 is 830000.
Therefore, 825125 rounded to the nearest Ten Thousands is 830000.
Answer:
830,000
Step-by-step explanation:
bbbvxxbbbdhdhdvdvshdbsbskzi99999999
please please help! i need to submit in 15 minutes!!!
Answer:
Step-by-step explanation:
I need the question to answer please :)
3 quick questions 28 points
For the first image, I would recommend using Desmos; it is an online graphing calculator. You can find it on online and it is free; I use it all the time for my school work
I would input each function and sees which one matches the image on the test.
As for the second image, I believe the answer is C; x is greater than or equal to -1.
For the third and last image, I believe the answer is A; x is less than -1.
I hope this helps .
nth term for 300,250,200
The nth term of the arithmetic sequence 300,250,200 is 350-50n if the common ratio is -50
What is a sequence?It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
We have an arithmetic sequence:
300,250,200
The first term a = 300
Common difference d = 250-300 = -50
nth term:
A(n) = a + (n-1)d
A(n) = 300 + (n-1)(-50)
A(n) = 300 -50n + 50
A(n) = 350—50n
Thus, the nth term of the arithmetic sequence 300,250,200 is 350-50n if the common ratio is -50
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what is circumference?
The distance/measurement around a circle.
Providing for doubtful accounts
At the end of the current year, the accounts receivable account has a debit balance of $844,000 and sales for the year total $9,560,000.
a. The allowance account before adjustment has a debit balance of $11,400. Bad debt expense is estimated at 1/4 of 1% of sales.
b. The allowance account before adjustment has a debit balance of $11,400. An aging of the accounts in the customer ledger indicates estimated doubtful accounts of
$36,500.
c. The allowance account before adjustment has a credit balance of $4,700. Bad debt expense is estimated at 1/2 of 1% of sales.
d. The allowance account before adjustment has a credit balance of $4,700. An aging of the accounts in the customer ledger indicates estimated doubtful accounts of
$39,000.
Determine the amount of the adjusting entry to provide for doubtful accounts under each of the assumptions (a through d) listed above.
Based on the account receivable balance and the adjustments, the adjusting entries for doubtful debt under various assumptions is:
a. $23,900b. $47,900c. $47, 800d. $34,300What are the entries for doubtful debt?a. Bad debt is 1/4 of 1% of sales:
= 9,560,000 x 0.25%
= $23,900
b. Debit balance of $11,400:
= Estimated doubtful accounts + Debit balance
= 36,500 + 11,400
= $47,900
c. Credit balance of $4,700 and 1/2 of 1% of sales:
= Sales x 0.50%
= 9,560,000 x 0.50%
= $47,800
d. Credit balance of $4,700 and estimated doubtful of $39,000:
= Estimated doubtful accounts - credit balance
= 39,000 - 4,700
= $34,300
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12(5-5)+3x5 evaluate the expression
Answer:
Using PEMDAS we can see that P or parenthesis is first so we would subtract 5 from 5 in the beginning. That would result in a 0 which would then get multiplied with 12 to still have 0.
[tex]12(5-5) + 3 * 5[/tex]
[tex]12(0) + 3 * 5[/tex]
[tex]0 + 3 *5[/tex]
Now that we completed that part, the only thing that we have left to do is to multiply the last two numbers, 3 and 5.
[tex]3*5[/tex]
[tex]15[/tex]
Therefore, our final solution is 15.
Hope this helps!
The perimeter of a rectangle with length l and width w is 44 inches. The area of the rectangle is at most 120.
Which of the following statements is true?
A. If w 12 inches, then l 10 inches
B. If w 12 inches, then l 10 inches
C. If w 12 inches, then l 10 inches
D. If w 12 inches, then l 10 inches
The true statement about the rectangle is A. If w is 12 inches, then l is 10 inches
How to determine the true statement?The given parameters are:
Perimeter, P = 44Area = 120 (at most)The perimeter of a rectangle is:
P = 2(L + W)
So, we have:
2(L + W) = 44
Divide by 2
L + W = 22
The area is calculated as:
A = LW
This gives
LW = 120
Express 120 as 12 * 10 and 10 * 12
LW =12 * 10 or LW = 10 * 12
By comparison, we have:
L = 12 and W = 10 or L = 10 and W = 12
When these values are substituted in L + W = 22, we have:
10 + 12 = 22 and 12 + 10 =22
This means that the dimensions of the rectangle are 10 by 12 inches or 12 by 10 inches
Hence, the true statement is A. If w is 12 inches, then l is 10 inches
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Answer: for short its a
Step-by-step explanation:
A patient has been prescribed 1 gram (g) of Drug A. The stock dose is available in 250 milligram (mg) tablets. How many tablets would you administer per dose?
The number tablets per dose of drug A to be administered on the patient is 4 tablets
Quantity conversion1 gram = 1000 milligram
Drug A provided = 1 gramDose = 250 milligramNumber of tablets to administer = Drug A provided / Dose
= 1 gram / 250 milligram
= 1000 milligram / 250 milligram
Number of tablets to administer = 4 tablets
Therefore, the number tablets per dose of drug A to be administered on the patient is 4 tablets
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What is the mass of 35 moles of CO₂?
7) $72.45 -28.98 Rounded estimate
Answer:
$43
Step-by-step explanation:
$72.45 can be rounded down to $72.00
$28.98 can be rounded up to $29.00
$72-$29= $43
Use long division method to solve & following.
5 on 8
Answer:
0.625
Step-by-step explanation:
Find the mean, μ, for the binomial distribution with n = 48 and p = 3/5. Round your answer to the nearest hundredth. A) μ = 29.7 B) μ = 3.4 C) μ = 48.6 D) μ = 28.8Find the mean, μ, for the binomial distribution with n = 48 and p = 3/5. Round your answer to the nearest hundredth.
A) μ = 29.7 B) μ = 3.4
C) μ = 48.6 D) μ = 28.8
The mean of the binomial distribution is (d) μ = 28,8
How to determine the mean?The given parameters of the binomial distribution are given as:
n = 48 and p = 3/5
The mean is then calculated using:
μ = np
This gives
μ = 48 * 3/5
Evaluate
μ = 28,8
Hence, the mean of the binomial distribution is (d) μ = 28,8
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A chemist is using 354 milliliters of a solution of acid and water. If 19.8% of the solution is acid, how many milliliters of
acid are there? Round your answer to the nearest tenth.
milliliters
Need help with this question p
Answer:
4x² + 12x + 9
Step-by-step explanation:
Using identity:(a +b)² = a² + 2ab + b²
Here, a = 2x & b = 3
(2x +3 )² = (2x)² + 2*2x*3 + 3²
= (2x*2x) + 12x + 3*3
= 4x² + 12x + 9
Determine whether the two lines are parallel, perpendicular, or neither.
4x + 5y = 2
4x + 5y = 4
Answer:
Step-by-step explanation:
slope is same so they are parallel.
Among black respondents to the 2008 GSS, 167 had no small children at home, and 44 did have small children at home. Among those black respondents who had no small children at home, 62 of them had been to a zoo in the past year. Among those black respondents who did have small children at home, 23 of them had been to a zoo in the past year. Build a crosstab with these results, percentage it, run a chi-square test, and explain your results.
Answer:
Step-by-step explanation:
pls help
tomorrow exam that's why
Answer:
Step-by-step explanation:
a) Four points
A, T , B , U
b) A ray has a fixed starting point but no end point. It extends infinitely in one direction
PA ; PB ; QT ; QU
c) A line segment is a part of a line that is bounded by two distinct end points.
PQ , PR
d) Parallel lines are two lines in the same plane that are at equal distance from each other and they never intersect.
AP // TQ and PB // QU
e) Two or more lines which share exactly one common point are called intersecting lines.
AB & PQ
f) ∠QPB and ∠BPR
your grade.
Find y. Give your answer in
the simplest form.
X
60°
y = [?]
2√3
Enter the number that belongs in
the green box.
Answer:
y=3
Step-by-step explanation:
trust me bro
four points are always coplanar if they: check all that apply.
A. lie in the same plane
B. lie on different lines
C. lie on different planes
D. lie on the same line
Answer:
B. lie on different lines
Step-by-step explanation:
a teacher gets a bag of lollipops for her class. She buys a large bag of 84 lollipop. If she wants each child to have 3 lollipops how many students must be in her class?
Question 9 of 40
Factor this polynomial completely.
6x² + 7x-20
O A. (3x-4)(2x + 5)
OB. (6x- 5)(x+4)
O C. (2x-4)(3x + 5)
OD. (6x-4)(x+5)
Answer:
6x² + 7x-20
A. (3x-4)(2x + 5)
An internet cafe charges $3.75 to use a computer and $.45 per minute while accesing the internet. What function rule describes this situation?
Answer:
y = $3.75(x) + .45$
Step-by-step explanation:
Take the input and subsitute
Write the expression in standard form. (2 points) seven divided by quantity three minus fifteen i.
Answer:
[tex]\displaystyle \frac{7}{3-15i}=\frac{7}{78}+\frac{35}{78}i[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{7}{3-15i}\\\\\frac{7}{3-15i}*\frac{3+15i}{3+15i}\\\\\frac{21+105i}{9-225i^2}\\\\\frac{21+105i}{9+225}\\\\\frac{21+105i}{234}\\\\\frac{21}{234}+\frac{105}{234}i\\ \\\frac{7}{78}+\frac{35}{78}i[/tex]
Cos (pi/5) + cos (2pi/5)+ Cos (3pi/5)
+ Cos (4pi/5)
Answer:
0
Keys:
When going over functions like this, we must use these cosine rules:
[tex]\cos \left(s\right)+\cos \left(t\right)=2\cos \left(\frac{s+t}{2}\right)\cos \left(\frac{s-t}{2}\right)[/tex][tex]\cos \left(-x\right)=\cos \left(x\right)[/tex][tex]\cos \left(\frac{\pi }{2}\right)=0[/tex]Step-by-step explanation:
[tex]=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{2\cdot \frac{\pi }{5}+3\cdot \frac{\pi }{5}}{2}\right)\cos \left(\frac{2\cdot \frac{\pi }{5}-3\cdot \frac{\pi }{5}}{2}\right)+\cos \left(4\cdot \frac{\pi }{5}\right)\\=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{\pi }{2}\right)\cos \left(-\frac{\pi }{10}\right)+\cos \left(\frac{4\pi }{5}\right)\\=\cos \left(\frac{\pi }{5}\right)+2\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{\pi }{10}\right)+\cos \left(\frac{4\pi }{5}\right)[/tex]
[tex]cos\left(\frac{\pi }{5}\right) = \frac{\sqrt{5} + 1}{4}\\=\frac{\sqrt{5}+1}{4}+2\cdot \:0\cdot \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}-\frac{1+\sqrt{5}}{4}\\=0[/tex]