What is the radius of a hemisphere with a volume of 839 cm", to the nearest tenth of a centimeter?​

Answer:

I think one tailed correct me if im wrong

Answer:

A triangular prism and a trapezoidal prism, if I understand the question

Step-by-step explanation:

There wound be a trapezoid and a triangle if you cut it horizontally. If you mean vertically, it would be a right triangular prism

Step-by-step explanation:

you need to find:

uw:

uv:

vw= 8(already known)

Measure of W= 35

Measure of u= 90

measure of v= 180-90+35= 55

finding uv:

sin(35)= uv/8

0.57=uv/8

4.56=uv

finding uw:

sin(55)= uw/8

0.82= uw/8

6.56= uw

Answer:

3.5h-3.1d-14

Step-by-step explanation:

6h+​(−8.1d​)−14+5d−2.5h

Combine like terms

6h -2.5h  -8.1d +5d  -14

3.5h-3.1d-14

220 cubic units.

Answer:

Solution given:

for small cylinder

r=1

and for large cylinder

R=5+1=6

height for both [h]=2

Now

Volume of solid=πR²h-πr²h=πh(R²-r²)

=3.14*2(6²-1²)=219.8 =220 units ³.

Small cylinder is r=1

Large cylinder is R= 5+1 =6

Height (h) =2

Volume of solid,

→ πR²h-πr²h

→ πh(R²-r²)

→ 3.14 × 2(6²-1²)

→ 219.8

→ 220 cubic units

Answer:

x = 9.7

Step-by-step explanation:

tan θ = opposite side / adjacent side

tan 37° = x / 13

multiply 13 on each side

13 × tan 37° = 13 × x /13

13 × tan 37° = x

Rewrite

x = 13 × tan 37°

multiply, we get

x = 13 × 0.75355..

x = 9.79620265

Round nearest tenth = 9.7

Answer:

For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.

Step-by-step explanation:

Fuel efficiency after x kg in mass:

y = 43.28 -0.011x

Thus, the slope is of -0.011 per x kg.

Increase of 100:

When x = 100, as the slope is negative, the efficiency will decay by:

-0.011*100 = -1.1

Decay of 1.1 miles per gallon, so the answer is:

For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.

Answer:

You should first make sure you explain what exactly is the question, before delete others answers.‍♀️‍♀️

Step-by-step explanation:

Answer: GIVEN : f(x)= -3x+1

f(x)= -5

REQUIRE:  x=?

CALCULATION:

f(x)= -3x+1

As, given f(x)= -5.

Hence,

-5= -3x+1

OR

-3x+1= -5

-3x= -5-1

-3x=-6

x= -6/-3

x= 2

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].

Now we will solve this expression with the help of law of exponents.

[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]

           [tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]

           [tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]

           [tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]

           [tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]

                [tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]

                [tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]

               [tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

Answer:

0.088 is the answer...

Answer:

0.64(x) = 30

Step-by-step explanation:

Hope that's correct.

Hello~

I used Cymath for this!

https://www.cymath.com/answer?q=(0.4%20*10%5E-6)%20(0.7%20*%2010%5E-2)

In short the answer is B.

The link has the step by step answers!

I highly recommend this sight by the way, its always correct!

Ary~

I believe its <ABF =<EDJ

Answer:

84 sq meters

Step-by-step explanation:

1. Approach

In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.

2. Area of Region 1

As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.

Length * width

6 * 3

= 18

3. Area of Region 2

In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.

Length * width

= 12 * (8 - 3)

= 12 * 5

= 60

4. Area of Region 3

In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.

Length * width

= 2 * 3

= 6

5. Total area

Now add up the area of each region to find the total rea,

(Region 1) + (Region 2) + ( Region 3)

= 18 + 60 + 6

= 84

Answer:

√53

Step-by-step explanation:

Distance between two points =  

√(4−6)^2+(−2−5)^2

√(−2)^2+(−7)^2  

= √4+49

=√53

= 7.2801

Hope this helps uwu

9514 1404 393

Answer:

  option 2: √53

Step-by-step explanation:

The distance formula is useful for this:

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)

  d = √53

The distance between the given points is √53.

Step-by-step explanation:

The given equation is :

y = 2x-7

We will first find the points,

x  0 , , 3.5, 1 , 2 , 3

y -7 , 0, -5, -3, -1

The graph of the above equation is as follows :

It is a linear equation.

Answer:

a) n and o

Step-by-step explanation:

by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .

l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel

Answer:

a) n and o

Step-by-step explanation:

Corresponding angles

Answer:

The correct answer is "2.660".

Step-by-step explanation:

Given that,

Sample size,

n = 61

t-distribution with,

t = 0.005

Now,

The degree of freedom will be:

= [tex]n-1[/tex]

= [tex]61-1[/tex]

= [tex]60[/tex]

hence,

⇒ [tex]t,df=t_{0.005}, 60[/tex]

           [tex]=2.660[/tex]

Answer:

Step-by-step explanation:

1)

[tex]cot x sec^4 x = cotx + 2tanx + tan^3 x[/tex]

[tex]RHS =[/tex]

           [tex]=\frac{cosx}{sinx} + 2 \frac{sinx }{cosx} + \frac{sin^3x }{cos^3x}\\\\[/tex]

          [tex]= \frac{cosx(cos^3x) + 2sinx(sinx \ cos^2x ) + sin^3x(sinx)}{sinx \ cos^3x}\\\\[/tex]        [tex][\ taking LCM \ ][/tex]

         [tex]=\frac{cos^4x + 2sin^2xcos^2x +sin^4x }{sinx cos^3x}[/tex]

         [tex]= \frac{(sin^2 x + cos^2x)^2 }{sin x \ cos^3 x}[/tex]                        [tex][ \ a^4 + 2a^2b^2 + b^4 = (a^2 + b^2 ) ^2 \ ][/tex]

        [tex]= \frac{1}{sinx \ cos^3 x}\\\\= \frac{1 \times cosx}{sinx \times cos^3x \times cosx}[/tex]                    [tex][ \ multiplying\ and \ dividing \ by \ cosx \ ][/tex]

        [tex]= \frac{cosx}{sinx} \times \frac{1}{cos^4x}\\\\=cot x \ sec^4 x[/tex]

        [tex]= LHS[/tex]

2)

[tex]sin x \ ( tanx \ cosx - cotx \ cosx) = 1 - 2cos^2x[/tex]

[tex]LHS =[/tex]

        [tex]=sinx( [ \frac{sinx}{cosx} \times cosx)] - [ \frac{cosx}{sinx}\times cosx] )\\\\= sinx (sinx - \frac{cos^2x}{sinx})\\\\=sin^2x - cos^2 x\\\\=(1 - cos^2x ) -cos^2 x[/tex] [tex][ \ sin^2x = 1 -cos^2 x \ ][/tex]

        [tex]= 1 -cos^2x - cos^2 x \\\\= 1 - 2cos^2x \\\\=RHS[/tex]

3)

[tex]1 + sec^2x \ sin^2x = sec^2 x[/tex]

[tex]LHS =[/tex]

       [tex]= 1 +sec^2x \sin^2x \\\\= 1 + (\frac{1}{cos^2x} \times sin^2x )\\\\= 1 + \frac{sin^2 x}{cos^2x}\\\\= 1 + tan^2x \\\\= sec^2 x\\\\=RHS[/tex]

4)

[tex]\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} = 2 \ cosec x[/tex]

[tex]LHS =[/tex]

[tex]=\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} \\\\= \frac{sinx(1 +cosx)}{(1-cosx)(1+cosx)} + \frac{sinx(1-cox)}{(1+cosx)(1-cosx)}\\\\= \frac{sinx +sinx\ cosx}{(1 - cos^2x)} + \frac{sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{sinx + sinx \ cosx + sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{2sinx}{sin^2x}\\\\=\frac{2}{sinx}\\\\=2 cosec\ x\\\\=RHS[/tex]

5)

[tex]- tan^2 + sec^2 x = 1\\\\[/tex]

        [tex]sin^2 x + cos^2 x = 1\\\\\frac{sin^2x }{cos^2x} + \frac{cos^2x}{cos^x} = \frac{1}{cos^2x}\\\\tan^2x + 1 = sec^2x \\\\1 = sec^2 - tan^2x \\\\-tan^2x + sec^2 x = 1[/tex]                

I think

x= -4, -1 and y=13, 8

(-4, 13) and (-1, 8)

Answer:

[tex]y = -\frac{1}{3}m + 41[/tex]

Step-by-step explanation:

Linear equation:

A linear function has the following format:

[tex]y = mn + b[/tex]

In which m is the slope and b is the y-intercept.

When she plants 30 stalks, each plant yields 31 oz of beans. When she plants 36 stalks, each plant produces 29 oz of beans.

This means that these two points belong to the line: (30,31), (36,29).

Finding the slope:

When we have two points, the slope is given by the change in the output divided by the change in the input.

Change in the output: 29 - 31 = -2

Change in the input: 36 - 30 = 6

Slope:

[tex]m = \frac{-2}{6} = -\frac{1}{3}[/tex]

Thus

[tex]y = -\frac{1}{3}m + b[/tex]

Finding b:

We take one of the points and replace on the equation.

(30,31) means that [tex]m = 30, y = 31[/tex]. Thus

[tex]y = -\frac{1}{3}m + b[/tex]

[tex]31 = -\frac{1}{3}(30) + b[/tex]

[tex]31 = -10 + b[/tex]

[tex]b = 41[/tex]

Thus

[tex]y = -\frac{1}{3}m + 41[/tex]

Answer:

-63

Step-by-step explanation:

9 - (2×3) × 12

9 - (6 × 12)

9 - 72

= -63

Answer:

-63

Step-by-step explanation:

r − ns × 12

Let n = 2, r = 9, and s = 3

9 - (2)*3 * 12

Multiply first

9 - 72

-63

Answer: [tex]30^{\circ}[/tex]

Step-by-step explanation:

[tex]\cos x=\frac{13}{15}\\\\x=\cos^{-1} \left(\frac{13}{15} \right)\\\\x \approx 30^{\circ}[/tex]

Answer:

it needs more information