What is the quotient of startfraction negative 8 x superscript 6 baseline over 4 x superscript negative 3 baseline endfraction?

The blanks can be filled with definitions of property bisector,  Substitution property of equality, and Distributive property, respectively.

When two straight lines or rays intersect at a shared endpoint, an angle is generated. An angle's vertex is the common point of contact. Angle is derived from the Latin word angulus, which means "corner."

The given blanks can be filled as,

Hence, the blanks can be filled with definitions of property bisector,  Substitution property of equality, and Distributive property, respectively.

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SOLUTION :-

AREA of sector = ( ∆/360° ) × πr²

∆ = given angle , r = radius

hence ,

AREA of sector for given angle

= ( 120°/360° ) × π 12² mi²

= ⅓ × π × 144 = 150.79 mi² = 151 mi² ( rounded off )

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Answer:

Sector area = 151 mi²

Step-by-step explanation:

We can use the formula for sector area:

Area = [tex]\frac{\theta}{360} \pi\ r^2[/tex]

where:
θ = central angle (120°),

r = radius of circle (12 mi) .

Substituting these values into the formula:

Area = [tex]\frac{120}{360} \pi\ \times (12)^2[/tex]

        ⇒ 48 π

        ⇒ 150.796

        ≈  151 mi²   (rounded to the nearest whole number)

Answer:

534 = R + 211

Step-by-step explanation:

So the amount of texts Riley received can be expressed as a variable, and in this case I'll use "R". So we know Bella received 534 texts. and that's 211 MORE than riley. So R+211 should be the as 534. This gives you the equation: 534 = R + 211. and if you want to solve for R, you can subtract 211 from both sides to solve for R

Answer:

assume X dollar is $100

If so then,

$100-10% =$90

Thus,

$90x125%=$112.5

The value of the composition of functions f(g(3)) is given by (A) -1.

Here given that the functions are,

f(x) = 3x-7

g(x) = (x+1)/(x-1)

To find the value of g(3) we have to first substitute the value x = 3 in the given function g(x), doing that we get,

g(3) = (3+1)/(3-1) = 4/2 =2

Thus the value of g(3) = 2

Now in order to find the value of composition of functions f(g(3)) we have to substitute the value of x = g(3) = 2 in the given function f(x), doing that we get,

f(g(3)) = f(x = g(3)) = f(x = 2) = f(2) = 3*2-7 = 6-7 = -1

Thus the value of the required composition of functions f(g(3)) is given by -1.

Hence the correct option is given by (A).

The question is incomplete. Find the full content below.

Consider these functions:

f(x) = 3x-7

g(x) = (x+1)/(x-1)

What the value of f(g(3))?

(A) -1

(B) 0

(C) 3

(D) 5

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By taking the quotient between the money that they make and the time spent to make that money, see can see that Amy earned more profit.

Here we can define profit as the ratio between the money that they make, and the number of hours that they worked to make that money.

Matt earned $125, and spent $50 on shoes for his work, so he earned $75.

And worked 120 hours for these $75, so his profit per hour is:

M = $75/120 = $0.625

Amy worked for 110 hours, won $230 and spent $30 on clippers, then she won a total fo $200.

Her profit per hour is:

A = $200/110h = $1.82

We can see that Amy earned more profit.

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Answer:

This is true.

Step-by-step explanation:

Congruence means the same shape and size. So if they line up, they will line up perfectly.

By the way, is there any question you need help with, or do you just need to see if this is true or false?

Using it's concept, the domain of the function in interval notation is given by:

(-4,2).

The domain of a function is the set that contains all possible input values for the function. In a graph, it is the set that contains the values of x.

For this function, x varies between -4 and 2, with an open circle, meaning that -4 and 2 are not part of it, hence the domain is:

(-4,2).

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Answer:

[tex][0, \infty)[/tex]

Answer:

Step-by-step explanation:

Area of trapezoid = ½ (a + b) h

½ (22 + 10) 8 =

½ 32 × 8 =

16 × 8 =

128 cm²

The distance between the home plate and the second base is 127.3 feet

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the distance between the home plate and the second base. Using Pythagoras theorem:

x² = 90² + 90²

x = 127.3 feet

The distance between the home plate and the second base is 127.3 feet

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The distance between home plate and second base is  2√4050 feet.

In a square, all sides are equal in length.

If the distance between each pair of bases is 90 feet, it means that each side of the square (representing the distance along the edge) is also 90 feet.

Since home plate and second base are opposite corners of the square, they are connected by the diagonal of the square.

In a square, the diagonal forms a right triangle with the sides of the square.

Using the Pythagorean theorem, we can find the length of the diagonal (the distance between home plate and second base):

diagonal² = side² + side²

diagonal² = 90² + 90²

diagonal²= 8100 + 8100

diagonal² = 16200

diagonal =√16200

diagonal = 2√4050 feet.

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The error Giovanna made in her calculation is multiplying 7 by 2 and adding with 5/8(step 3)

Her calculation:

Her error was multiplying 7 by 2 and adding with 5/8(step 3)

Correct calculation:

7(2 + 5/8)

= 14 + 35/8

= (112+35) /8

= 147/8

= 18 3/8

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The transformations and their respective descriptions are:

A. (x, y) ⇒ (3x, y) implies horizontal stretch by a scale factor of 3

B. (x, y) ⇒ (x+3, y) implies translation 3 units right

C. (x, y) ⇒ (x, 3y) implies vertical stretch by a factor of 3

D. (x, y) ⇒ (x, y+3) implies  implies translation 3 units up

E. (x, y) ⇒ (3x, 3y) implies dilation with a scale factor 3

Translation is an algebraic transformation of a shape by moving the vertices some units along the x or y axis.

When a shape is translated it may move to a new position depending on the orientation of the translation.

Analysis:

For A, the x coordinate was transformed three times its initial value stretching it horizontally.

For B, the x coordinate moved 3 units further away from its initial value making the new value x+3 and y remaining the same.

For C, the y coordinated was transformed to a value three times what it was, making it to be stretched vertically, since the y-axis is a vertical axis.

For D, the y coordinate was moves 3 units away from its initial position making it to be translated up, since 3 is positive.

For E, both coordinates were stretched 3 units as much as their original value making the shape to dilate.

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Let the numerator be x & denominator be y then,

ATQ,

x+1/y-1=12/11

11x+11=12y-12

11x-12y+11+12=0

11x-12y+23=0....(1)

&

x+3/y-3=14/9

9x+27=14y-42

9x-14y+27+42=0

9x-14y+69=0....(2)

Multiplying eq . 1 by 9 & eq. 2 by 11

We get,

99x-108y+207=0....(3)

99x-154y+759=0....(4)

Subtracting eq. 4 by eq. 3

99x-108y+207=0

99x-154y+759=0

______________

0 + 46y - 552 =0

______________

46y= 552

________

y=552/46

________

y=12

____

putting the value of y in eq. 1,

11x-12y+23=0

11x-12*12+23=0

11x-144+23=0

11x-121=0

11x=121

x=121/11

x=11

So, y = 12 & x = 11 & the fraction is 11/12

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-lyricalblues

Answer:

3x

Step-by-step explanation:

2x is the name, there are 2 x's, you are adding an x to the 2 x's therefore making 3 x's or 3x

Answer:

[tex]3 \log 2[/tex]

Step-by-step explanation:

Given expression:

[tex]\log 2 + \log \left(\dfrac{3}{2}\right)+\log \left(\dfrac{4}{3}\right)+\log \left(\dfrac{5}{4}\right)+\log \left(\dfrac{6}{5}\right)+\log \left(\dfrac{7}{6}\right)+\log \left(\dfrac{8}{7}\right)[/tex]

[tex]\textsf{Apply the \underline{Log Product Law}}: \quad \log_ax + \log_ay=\log_axy[/tex]

[tex]\implies \log \left(2 \cdot \dfrac{3}{2} \cdot \dfrac{4}{3} \cdot \dfrac{5}{4} \cdot \dfrac{6}{5} \cdot \dfrac{7}{6} \cdot \dfrac{8}{7}\right)[/tex]

Cross out common factors:

[tex]\implies \log \left(\diagup\!\!\!\!2 \cdot \dfrac{\diagup\!\!\!\!3}{\diagup\!\!\!\!2} \cdot \dfrac{\diagup\!\!\!\!4}{\diagup\!\!\!\!3} \cdot \dfrac{\diagup\!\!\!\!5}{\diagup\!\!\!\!4} \cdot \dfrac{\diagup\!\!\!\!6}{\diagup\!\!\!\!5} \cdot \dfrac{\diagup\!\!\!\!7}{\diagup\!\!\!\!6} \cdot \dfrac{8}{\diagup\!\!\!\!7}\right)[/tex]

Therefore:

[tex]\implies \log 8[/tex]

Factor the number:  8 = 2³

[tex]\implies \log 2^3[/tex]

[tex]\textsf{Apply the \underline{Log Power Law}}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 3 \log 2[/tex]

The scale factor in the question given above is: 2 See the explanation below.

In math, the scale factor is the extent or ratio by which a geometrical shape is enlarged or reduced.

We know that:

Given the above, the distance from point Q to point A' is 2.50. This is double the distance from point Q to point A.

The scale factor is 2.

1.25 + 1.25 = 2.50

2.50 / 1.25 = 2

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Answer:

A

Step-by-step explanation:

The first picture shows the parent function,

A function assigns a x for only one y.

The inverse is opposite

The inverse assign a y for only one x.

So the answer is the table that swap x and y values.

The coordinates for the parent function are

(0,0)

(2,1)

(4,2)

So the inverse should have

(0,0)

(1,2)

(2,4)

A shows that, so a is the answer

Answer: 3 units²

Step-by-step explanation: The area of a triangle is 1/2 (Bh); 1*1= 1 (1/2)= 1/2 units². For the other shape, I cut it into a square and another triangle. The square area is length times width; 1*1= 1 units². The final triangle is 3*1= 3*1/2= 1.5 units². Lastly you add all the areas together: 1.5+0.5+1= 3 units²

The relationship given in the graph is not function. Option C. is True.

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.

The relationship given in the system is not a function. because the values of y is repeating at certain values of x. And the curve has number of discontinuity.

Thus, from the options given only option c describe the relationship given in the graph is not a function because there more than one value of x corresponding yo y - 2.  

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The radius of the sector of the circle with the given area is: B. 3.

Area of sector of a circle = ∅/360 × πr².

Given the following:

Area of sector = 9/8 π cm².

∅ = 45 degrees

Plug in the values into the formula

9/8π = 45/360 × πr²

1.125 = 0.125 × r²

1.125/0.125 = r²

9 =  r²

r = 3 cm

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The solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3 and the solutions in part b hold for equation 4

There are three variables in the system

To solve the three variables, there must be at least three equations in the system of equations

Hence, the variables cannot be solved because the number of equations is not enough

We have:

3x + z + y = 8

5y - x = -7

3z + 2x - 2y = 15

Make x the subject in (2)

x = 5y + 7

Substitute x = 5y + 7 in (1) and (3)

3(5y + 7) + z + y = 8

15y + 21 + z + y = 8

16y + z = -13

3z + 2(5y + 7) - 2y = 15

3z + 10y + 14 - 2y = 15

3z + 8y = 1

Multiply 16y + z = -13 by 3

48y + 3z = -39

Subtract 3z + 8y = 1 from 48y + 3z = -39

48y - 8y + 3z - 3z = -39 - 1

40y = -40

Divide by 40

y = -1

Substitute y = -1 in x = 5y + 7

x = 5(-1) + 7

x = 2

Make z the subject in 16y + z = -13

z = -13 - 16y

Substitute y = -1

z = -13 - 16(-1)

z = 3

Hence, the solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3

We have:

4x + 5y - 2z = -3

Substitute x = 2, y = -1 and z = 3

4(2) + 5(-1) - 2(3) = -3

Evaluate

-3 = -3 --- this is true

Hence, the solutions in part b hold for equation 4

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Missing part of the question

The following equations are given:

Equation #1: 3x + z + y = 8

Equation #2: 5y - x = -7

Equation #3: 3z + 2x - 2y = 15

Equation #4: 4x + 5y - 2z = -3

Answer:

y=1/2x+1

Step-by-step explanation:

First use slope formula.

[tex]\frac{y2-y1}{x2-x1}[/tex]

Plug in the information needed.

[tex]\frac{1-3}{0-4}=\frac{-2}{-4}=\frac{1}{2}[/tex]

The slope is [tex]\frac{1}{2}[/tex].

Now, use point-slope formula.

y-y1=m(x-x1)

Plug in the information needed.

y-3=1/2(x-4)

y-3=1/2x-2

y=1/2x+1

The equation of the line in slope-intercept form is y=1/2x+1.

Hope this helps!

If not, I am sorry.

The angle congruent to ∠6 are ∠8, ∠3, ∠9 and ∠14

When parallel lines are cut by a transversal, angle relationships are formed. They include corresponding , alternate and many more.

L║m

n ║ q

Therefore, the angles congruent to ∠6 by alternate or corresponding relationship are as follows:

∠6≅∠8≅∠3≅∠9≅∠14

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Answer:

about 18.3 square meters

Step-by-step explanation:

Since the circle has radius 4 meters, the area of the circle is (4^2)π, or 16π square meters, The area of the square is (4√2)^2, or 32 square meters. Subtracting, we have 16π-32, or about 18.3 square meters, for the area of the shaded region.

1. 80 sheep when increase in the ratio 5:4 becomes 100 sheep.

2. The perimeter of the shape is : 26cm

Perimeter is the outside boundary of a shape.

It is usually calculated by summing up all the length of the sides of that shape.

Analysis:

1. if the sheep is increased in the ratio 5:4

 then new number of sheep becomes 5/4 x 80 = 400/4 = 100 sheep

2. The perimeter of the shape is the sum of all the sides of the shape = 7 + 4 + 10 +5 = 26cm

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Answer:

no because it would be flipped

Answer: 11

Step-by-step explanation:

By the secant-secant theorem,

[tex]5(5+7)=(JK)(15)\\\\60=(JK)(15)\\\\JK=4\\\\\implies IJ=15-4=11[/tex]

1) ray

2) line

3) line segment

4) adjacent angles

5) vertical angles

Answer:

1) RAY

2) LINE

3) LINE SEGMENT

4) VERTICAL ANGLES

5) VERTICAL ANGLES