Answer:
The answer is 50 watts
Explanation:
The formula of power is work done over elapsed time
P= W/t
P= 550 J / 11 sec
P= 50 watts
A rectangular beam 200 mm deep and 300 mm wide is simply supported over a span of 8 m. What uniformly distributed load per metre the beam may carry, if the bending stress is not to exceed 120N/mm2.
The uniformly distributed load per meter the beam may carry will be 1.275 × 10 ⁶ N/mm.
What is bending stress?When an object is subjected to a heavy load at a specific spot, it often experiences bending stress, which causes the object to bend and tire.
The given data in the problem is;
Bending stress, σ = 120 N/mm2
Moment of inertia, I = 8.5 × 106 mm⁴
Depth of beam, y = d/2 = 200/2 = 100 mm
Length of beam, L = 8 m = 8000 mm
Width of beam, W = 300 mm
The maximum bending moment of the beam with UDL;
[tex]\rm W = \frac{wL^2}{8}[/tex]
From the bending equation;
[tex]\rm M = \frac{\sigma I}{y_{max}} \\\\ M = \frac{120 \ N / mm^2 \times 8.5 \times 10^6 }{100 \ mm } \\\\ M = 10.2 \times 10^6 \ N - mm[/tex]
The maximum bending moment of the beam with UDL;
[tex]\rm M = \frac{wL^2}{8} \\\\ 10.2 \times 10^6 = \frac{w \times 8^2}{8} \\\\ w = 1.275 \times 10^6 \ N/mm[/tex]
Hence the uniformly distributed load per meter the beam may carry will be 1.275 × 10 ⁶ N/mm.
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1. A football is kicked with a velocity. of 20m/s at an angle of 45° with the horizontal i. Find the time taken by the ball to strike the ground ii. Find the maximum height 11. How far from the kick does it hit the ground Take gravity = 10 m/s
(a) The maximum height reached by the projectile is 10.2 m and
(b) The horizontal distance traveled by the projectile is 40.8 m.
Maximum height reached by the projectile
H = u²sin²θ/2g
H = (20²(sin(45))² / (2 x 9.8)
H = 10.2 m
Time of motionT = (2u sinθ)/g
T = (2 x 20 x sin(45) )/(9.8)
T = 2.886 s
Horizontal distance traveled by the projectilex = (v cos(45) x t
x = (20 x cos(45)) x 2.886
x = 40.8 m
Thus, the maximum height reached by the projectile is 10.2 m and the horizontal distance traveled by the projectile is 40.8 m.
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16. What was the purpose of the first personality tests?
O A. To determine jobs for people
O B. To match individuals for relationships
O C. To place people in jobs
O D. To determine which soldiers during WWI would be more prone to PTSD, or "sh
O Mark for review (Will be highlighted on the review page)
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Answer:
A. To determine jobs for people
What is the difference in the weight of a 117 kg person as measured at sea level and at the top of the Vinson Massif, the highest peak in Antarctica? The product GMEarth = 3.99 x 10^14 N x m2 x kg-1, the radius of the Earth is 6.38 × 10^6 m, and the height above sea level of the Vinson Massif is 5.14 × 10^3 m. Neglect the flattening of the Earth at the poles.
The difference in weight of a 117 kg person as measured at sea level and at the top of the Vinson Massif, the highest peak in Antarctica is -1.847 N
How to find the difference in weight?
To find the difference in weight, we find the change in acceleration due to gravity.
What is acceleration due to gravity?
The acceleration due to gravity is the acceleration exerted by the force of gravity on an object. It is given by
g = GM/r² where
GM = 3.99 × 10¹⁴ Nm²/kg and r = radius of earth = 6.38 × 10⁶ mThe change in acceleration due to gravityNow, to find the change in g, we differentiate g with respect to r,
So, dg/dr = d(GM/r²)
= -2GM/r³
So, the change in acceleration due to gravity, Δg is
Δg = dg/dr × Δr
= -2GM/r³ × Δr
Now, Δr = height above sea level of Vinson Massif = 5.14 × 10³ m
Substituting the values of the variables into the equation, we have
Δg = -2GM/r³ × Δr
Δg = [(-2 × 3.99 × 10¹⁴ Nm²/kg)/(6.38 × 10⁶ m)³] × 5.14 × 10³ m
Δg =[ (-7.98 × 10¹⁴ Nm²/kg)/259.69 × 10¹⁸ m³] × 5.14 × 10³ m
Δg = -0.03073 × 10⁻⁴ N/mkg × 5.14 × 10³ m
Δg = -0.1579 × 10⁻¹ N/kg
Δg = -0.01579 N/kg
The difference in weight of the 117 kg personSince weight W = mg where
m = mass of person and g = acceleration due to gravityThe difference in weight is dW = mdg
Since
m = 117 kg and dg = -0.01579 N/kgdW = mdg
= 117 kg × -0.01579 N/kg
= -1.847 N
So, the difference in weight of a 117 kg person as measured at sea level and at the top of the Vinson Massif, the highest peak in Antarctica is -1.847 N
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20. What is the meaning of intuition?
A. Using facts and observations to make a conclusion
B. Quickly understanding something without needing mental reasoning
C. Praising others instead of criticizing
D. Making decisions with strict requirements
Answer:
B) Quickly understanding something without needing mental reasoning
Answer:
[tex]\huge\boxed{\sf Option \ B}[/tex]
Explanation:
Intuition means:Taking quick decisions.Understanding quickly without using the conscious mind.Instinct.So, Intuition actually means quickly understanding something without needing mental reasoning.
[tex]\rule[225]{225}{2}[/tex]
6. A student travels 4.0 m east, 8.0 m south, 4.0 m west, and finally 8.0 m north. What is her
displacement?
What distance did she travel?
The student's path traces out a rectangle and she ends up at the same spot, so her displacement is 0 m.
On the other hand, she travels a total distance equal to the perimeter of that rectangle,
4.0 m + 8.0 m + 4.0 m + 8.0 m = 24 m
What does newtons 2nd law explain?
Answer asap for brainlist
Answer:
B. why you must push harder to move a car farther.
Explanation:
acceleration (gaining speed) happens when a force acts on a mass (object). FORCE=MASSxACCELERATION
A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure. The mass of the treasure chest is 75.6 kg.
What is the tension in rope A?
How much tension does rope B carry?
And what is the tension in rope C?
The tension in rope A is 740.88 N, the tension carried by rope B is 751.4 N and the tension carried by rope C is -124 N.
Angle made by B with respect to horizontaltan θ = Δy/Δx
tan θ = (10 - 4)/(5 - 4)
tan θ = 6
θ = arc tan (6) = 80.53
Net force in vertical directionC sin(0) + B sin(80.53) = A sin(90)
C sin(0) + B sin(80.53) = (75.6 x 9.8)
0 + 0.986 B = 740.88
0.986 B = 740.88
B = 740.88/0.986
B = 751.4 N
Net force in horizontal directionC cos(0) + B cos(80.53) = (75.6 x 9.8) cos(90)
C + 0.165 B = 0
C + 0.165(751.4) = 0
C + 124 = 0
C = - 124 N
Thus, the tension in rope A is 740.88 N, the tension carried by rope B is 751.4 N and the tension carried by rope C is -124 N.
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2. A transformer has 300,000 windings in its primary coil and uses 12,000V AC input. Show your work!
A) (4 points) How many windings would be needed to produce at output of 110V AC? Is this a step down or step up transformer?
B) (3 points) Explain why a transformer only works with AC and not DC currents.
The number of windings that would be needed to produce an output of 110V AC will be 2750.
What is induced voltage?
Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
The relation between the primary and the secondary winding is;
[tex]\rm \frac{V_s}{V_p}= \frac{N_s}{N_p} \\\\ \frac{110}{12000}= \frac{N_S}{300000} \\\\ N_s = 2750 \[/tex]
Transformers can only operate on AC current, since a flux shift is required for the induction process.
Additionally, since there won't be any flux change phenomena in the DC supply, the induction process can't take place. Transformers are utilized in AC supplies because of this.
Hence, the number of windings that would be needed to produce an output of 110V AC will be, 2750 and a transformer only works with AC.
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What do we call fixed point around which a lever pivots?
A. A fulcrum
B. A whell and axle
c. A wedge
D. A cylinder
Answer asap for beainlist
Answer:
A
Explanation:
ggtytryofttytrtuuyytyuygy
Need help in showing how to get the final velocity
I don't think the provided solution is correct because it's not dimensionally consistent. The quantity [tex]8h-1[/tex] in particular doesn't make sense since it's mixing a distance with a dimensionless constant.
Here's how I think the proper answer should look:
The net force on the box acting perpendicular to the ramp is
[tex]\sum F_\perp = F_{\rm normal} - mg \cos(\theta) = 0[/tex]
where [tex]F_{\rm normal}[/tex] is the magnitude of the normal force due to contact with the ramp and [tex]mg\cos(\theta)[/tex] is the magnitude of the box's weight acting in this direction. The net force is zero since the box doesn't move up or down relative to the plane of motion.
The net force acting parallel the ramp is
[tex]\sum F_\| = mg\sin(\theta) - F_{\rm friction} = ma[/tex]
where [tex]mg\sin(\theta)[/tex] is the magnitude of the parallel component of the box's weight, [tex]F_{\rm friction}[/tex] is the magnitude of kinetic friction, and [tex]a[/tex] is the acceleration of the box.
From the first equation, we find
[tex]F_{\rm normal} = mg \cos(\theta)[/tex]
and since [tex]F_{\rm friction} = \mu F_{\rm normal}[/tex], we get from the second equation
[tex]mg\sin(\theta) - \mu mg\cos(\theta) = ma[/tex]
and with [tex]\mu = 0.25[/tex] and [tex]\theta=60^\circ[/tex], we get
[tex]a = g\sin(60^\circ) - 0.25g \cos(60^\circ) = \left(\dfrac{\sqrt3}2 - \dfrac18\right) g[/tex]
Let [tex]x[/tex] be the length of the ramp, i.e. the distance that the box covers as it slides down it. Then the box attains a final velocity [tex]v[/tex] such that
[tex]v^2 = 2ax[/tex]
From the diagram, we see that
[tex]\sin(\theta) = \dfrac hx \implies x = \dfrac h{\sin(60^\circ)} = \dfrac{2h}{\sqrt3}[/tex]
and so
[tex]v^2 = \dfrac{4ah}{\sqrt3} = \left(2 - \dfrac1{2\sqrt3}\right) hg = \dfrac14 \left(8 - \dfrac2{\sqrt3}\right) hg[/tex]
[tex]\implies v = \dfrac12 \sqrt{\left(8 - \dfrac2{\sqrt3}\right) hg}[/tex]
To win the game, a place kicker must kick a
football from a point 28 m (30.6208 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 18 m/s at
an angle of 47.3
◦
from the horizontal.
The acceleration of gravity is 9.8 m/s
2
.
By how much vertical distance does the ball
clear the crossbar?
The answer to the question is that the vertical distance the ball clear the cross bar is 1.465 metres.
We have horizontal distance as 28 m, and velocity as 18 m/s and the angle of projection 46.8 degree.
so, we can say that
In horizontal direction,
28 = (18 cos 46°) t
t = 2.2723 seconds
Now, in vertical direction,
Let be the height of the ball
h = (18 sin 46°)t - (1/2)gt²
h = (18 sin 46°)t - 4.9t²
h = ( (13.1214) × (2.2723) ) - ( (4.9) × (2.2723)² )
h = 4.5154 metre
Vertical distance the ball clear the cross bar = h - 3.05
Vertical distance the ball clear the cross bar = 4.5154 - 3.05
Vertical distance the ball clear the cross bar = 1.465
Thus, we can conclude that after solving and applying the concepts of projectile motion we find out the vertical distance the ball will clear the cross bar is 1.465 metres.
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Part A
How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?
Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.
How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's thinks that these objects do not fall due to gravity. According to Einstein, these objects and Earth just freely move in a curved spacetime
So we can conclude that Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.
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A force F1 of magnitude 5.90 units acts on an object at the origin in a direction = 36.0° above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.
The magnitude and direction of the resultant force will be 7.65 units and 40.2°.
What is force?Force is explained as the multiplication of mass and acceleration. Its unit is N. It is the external agent which helps to change the shape and size of an object.
Force is used to push and pull the object and sometimes changes the direction of motion. The net force acting on an object is equal to the sum of all forces acting upon it.
F = F1 + F2 + F3
Given data;
Megnitude of force 1, F₁ = 5.90 units
Megnitude of force 2, F₂ = 5.00 units
α is the angle between the two forces=36.0°
Θ is the angle of the resultant force
The megnitude of the resultant force is;
[tex]\rm F =\sqrt{ F_{1}+F_{2}+2F_{1}F_{2}cos \alpha }\\\\ F = \sqrt{5.90 + 5.00 +2 \times 5.90 \times 5 \times cos 36^0 } \\\\ F = 7.65 \ units[/tex]
The direction of the resultant force is;
[tex]\rm \theta = tan^{-1}(\frac{F_{2}}{F_{1}} )[/tex]
[tex]\rm \theta = tan^{-1}(\frac{5.00}{5.90})\\\\ \theta = 40.2 ^0[/tex]
Hence the magnitude and direction of the resultant force will be 7.65 units and 40.2°.
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A mass of 2kg is attached to the end of a vertical wire of length 2m and diameter 2mm extend the wire by 1mm. Calculate the young modulus of the wire
3. a) (4 points) Compare and contrast magnetic and electric fields. Your answer should include at least 2 ways they are similar and 2 ways that they differ.
b) (4 points) Include a diagram of an electric field for a positive test charge and a diagram for a typical bar magnet. Make sure you show the field lines (including direction) and label the charges and poles.
A magnetic field is a field explaining the magnetic influence on an object in space.
A electric field is a field defined by the magnitude of the electric force at any given point in space.
What are magnetic field and electric fields?A magnetic field is a field explaining the magnetic influence on an object in space.
A electric field is a field defined by the magnitude of the electric force at any given point in space.
The difference between magnetic fields and electric filed are:
Electric Filed
Magnetic fields creates an electric charge in surrounding.It is measured as newton per coulomb, volt per meter.An electric field is measured using an electrometer.It is proportional for the electric charge.Magnetic Filed:
Magnetic filed creates an electric charge around moving magnets.It is measured as gauss or tesla.The magnetic field is measured using the magnetometer.It is proportional to the speed of electric chargeSimilarities between Electric and Magnetic Field
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Two football players collide head-on in midair while chasing a pass. The first player has a 92.5 kg mass and an initial velocity of 5.50 m/s, while the second player has a 116 kg mass and initial velocity of -6 m/s. What is their velocity (in m/s) just after impact if they cling together? (Indicate the direction with the sign of your answer.)
Their velocity (in m/s) just after impact if they cling together is -0.9 m/s.
Final speed of the two players
Apply the principle of conservation of linear momentum;
Pi = Pf
where;
Pi is initial momentum of the playersPf is final momentum of the players(92.5)(5.5) + (116)(-6) = v(92.5 + 116)
508.75 - 696 = v(208.5)
-187.25 = 208.5v
v = -187.25/208.5
v = -0.9 m/s
Thus, their velocity (in m/s) just after impact if they cling together is -0.9 m/s.
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A pan-galactic gargle (an alien) whose mass is 85 kg exploring a large asteroid. What is the force of
gravity holding it down?
The acceleration due to gravity of the asteroid is 833.85 N.
Force of gravity holding the the alien down
F = mg
where;
m is mass of the alieng is acceleration due to gravityAssuming the acceleration due to gravity of the asteroid = 9.81 m/s²
F = 85 x 9.81
F = 833.85 N
Thus, the acceleration due to gravity of the asteroid is 833.85 N.
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HELP ASAP PLEASE!!!
When a 20-Ohms resistor is connected across the terminals of a 12V battery, the terminal voltage of the battery falls to 10V. What is the internal resistance of the battery?
A. 4-ohms
B. 2-ohms
C. 10-ohms
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall.
Calculate the tension in the cable.
The tension in the cable is mathematically given as
T =266.659 N
What is the tension in the cable.?Generally, the equation for the angle of the boom with horizontal is mathematically given as
A = tan-1(5 /10)
[tex]A= 26.57 \textdegree[/tex]
The angle of cable with horizontal
B = tan-1(4 / 10)
B= 21.80 degrees
Hence
175.5 * cos26.57 + 94.7 *cos26.57 * 1/2 = T (sin(26.57+21.80)) * 1
T =266.659 N
In conclusion, the tension in the cable.
T =266.659 N
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An archer shoots an arrow at a 74.0 m distant target, the bull's-eye of which is at same height as the release height of the arrow.
(a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 33.0 m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.)
°
(b) There is a large tree halfway between the archer and the target with an overhanging branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?
under
over
A. The angle at which the arrow must be released to hit the bull's-eye is 20.7 °
B. The arrow will go over the branch.
A. How to determine the angleRange (R) = 74 mInitial velocity (u) = 33 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = ?R = u²Sine(2θ) / g
74 = 33² × Sine (2θ) / 9.8
Cross multiply
74 × 9.8 = 33² × Sine (2θ)
725.2 = 1098 × Sine (2θ)
Divide both sides by 1098
Sine (2θ) = 725.2 / 1098
Sine (2θ) = 0.6605
Take the inverse of sine
2θ = Sine⁻¹ 0.6605
2θ = 41.3
Divide both sides by 2
θ = 41.3 / 2
θ = 20.7 °
B. How to determine if the arrow will go over or under the branchTo determine if the arrow will go over or under the branch situated mid way, we shall determine the maximum height attained by the arrow. This can be obtained as follow:
Initial velocity (u) = 33 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 20.7 °Maximum height (H) = ?H = u²Sine²θ / 2g
H = [33² × (Sine 20.7)²] / (2 ×9.8)
H = 6.94 m
Thus, the maximum height attained by the arrow is 6.94 m which is greater than the height of the branch (i.e 3.50 m).
Therefore, we can conclude that the arrow will go over the branch
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A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.
What is the period of the pendulum?
The time period of the pendulum is 0.65 second.
What is time period?The time period is a period of time during which a behavior takes place or a condition persists. Depending on the type of activity or condition under consideration, it may be expressed either in seconds or in millions of years.
The mass of the object is = 0.10 kg
Length of the string is = 0.10 m.
Acceleration due to gravity is = 9.8 m/s²
Hence, the time period of the pendulum is = 2π√(0.10/9.8) sec
= 0.65 second.
Hence, the time period of the pendulum is 0.65 second.
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(10 pts.) A car of mass m is on an icy driveway inclined at an angle .
(A)Find the acceleration of the car, assuming the driveway is frictionless.
(B) Suppose the car is released from rest at the top of the incline and the distance from the car’s front
bumper to the bottom of the incline is d. How long does it take the front bumper to reach the
bottom of the hill, and what is the car’s speed as it arrives there?
The acceleration and time is mathematically given as
a=gsinθ
[tex]t=\frac{2d}{gsinθ}[/tex]
What is the acceleration of the car, assuming the driveway is frictionless, and how long does it take the front bumper to reach the bottom of the hill, and what is the car’s speed as it arrives there?Generally, the equation for the Force of the car is mathematically given as
[tex]N = mg cos\theta[/tex]
Therefore
[tex]ma=mgsin\theta[/tex]
a=gsinθ
The acceleration of the car is mathematically given as
a=gsinθ
Generally, the equation for the final velocity of the car is mathematically given as
[tex]v^2−u^2=2as[/tex]
Therefore
[tex]v 2 −(0) 2 =2(gsin\theta)d[/tex]
[tex]v= \sqrt {2gsin\theta.d}[/tex]
Generally, the equation for the motion of the car is mathematically given as
v−u=at
[tex]2gsin\thetad =(gsin\theta)t[/tex]
[tex]t=\frac{2d}{gsinθ}[/tex]
In conclusion, the time it takes the front bumper to reach the bottom of the hill is
[tex]t=\frac{2d}{gsinθ}[/tex]
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A long wire carries a current of 3.0 A along the axis of a long solenoid (radius = 3.0 cm, n = 900 turns/m, current = 30 mA). What is the magnitude of the magnetic field at a point 2.0 cm from the axis of the solenoid? Neglect any end effects.
Answer is 45uT, but how do you get this?
Hi there!
Let's break this problem up into two parts.
Part A: Solenoid
The magnetic field everywhere inside a solenoid is constant, and can be found using the equation:
[tex]B = \mu_0 nI[/tex]
B = Magnetic field strength (? T)
μ₀ = Permeability of Free Space (4π × 10⁻⁷ Tm/A)
n = number of turns/meter (900)
I = current (0.03 A)
We are given all of these values, so let's solve.
[tex]B = (4\pi \times 10^{-7})(900)(0.03) = 34\mu T[/tex]
However, we also have a long wire that produces a magnetic field perpendicular to that produced by the solenoid.
Part B: Long wire
The equation for the magnetic field produced by a long wire is found by:
[tex]B = \frac{\mu_0 I}{2\pi r}[/tex]
Where 'r' is the distance from the wire.
Plug in what we know:
[tex]B = \frac{(4\pi \times 10^{-7})(3)}{2\pi (0.02)} = \mu 30 T[/tex]
Now, we must do the vector sum of these two fields to find the total magnetic field. Since they are perpendicular (solenoid field points to the side, wire fire points in or out), we can use the Pythagorean Theorem.
[tex]B_T = \sqrt{B_s^2 + B_w^2}\\\\B_T = \sqrt{(34\mu T)^2 + (30\mu T)^2} \approx \boxed{45\mu T}[/tex]
And here's our answer!
The rms voltage is given by the following.
ΔVrms = ΔVmax/[tex]\sqrt{2}[/tex] = 0.707ΔVmax
Substituting the maximum voltage, we obtain
ΔVrms = ΔVmax/[tex]\sqrt{2}[/tex]
= 0.707ΔVmax = 0.707(165 V) = 117 V.
An rms voltage of 117 V corresponds to a maximum voltage of 165 V.
What is the maximum current Imax in the resistor?
The maximum current in the resistor is determined by dividing root mean square current by 0.7071.
Maximum current in the resistor
The maximum current in the resistor is calculated as follows;
I₀ = I(rms)/0.7071
where;
I₀ is the peak current or maximum current in the resistorI(rms) is the root mean - square currentThus, the maximum current in the resistor is determined by dividing root mean square current by 0.7071.
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A person throws a 0.21-kg ball straight up into the air. It reaches a height of
10 m. What is the force on the ball as it begins to fall? (The acceleration due
to gravity is 9.81 m/s².)
A. 2.06 N
B. 4.32 N
C. 1.18 N
OD. 4.67 N
Answer:
A
Explanation:
As it begins to fall
F = ma a = 9.81
F = .21 * 9.81 = 2.06 N
The definition of force in physics is the push or pull on a massed object that changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. The correct option is A.
Force is a physical factor that alters or has the potential to alter an object's state of rest or motion as well as its shape. Newton is the SI unit of force.
One of the most fundamental types of physical entities is the force. Due to the fact that force is a vector quantity, it possesses both a magnitude and a direction. Frictional force and contact force are the two categories under which all forces can be classified.
F = m × a
F = 0.21 × 9.81
F = 2.06 N
Thus the correct option is A.
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Two straight long parallel wires, separated by a distance of 1.0 m, carry a current of 4.00
each. A third wire is arranged perpendicular to the two parallel wires. If the magnetic field at a point equidistant from all the wires is zero, find the current in the third wire.
The magnitude of the current in the third wire is 8 A.
Total magnetic fieldE₁ + E₂ + E₃ = 0
Equidistance from the two wires = 0.5 m
Apply Biot Savart rule to determine the magnitude of the magnetic field.
μI/2πr₁ + μI/2πr₂ + μI/2πr₃ = 0
(4π x 10⁻⁷ x 4)/(2π x 0.5) + (4π x 10⁻⁷ x 4)/(2π x 0.5) + (4π x 10⁻⁷ x I₃)/(2π x 0.5) = 0
4 x 10⁻⁷ I₃ = -3.2 x 10⁻⁶
I₃ = (-3.2 x 10⁻⁶)/(4 x 10⁻⁷)
I₃ = - 8 A
Thus, the magnitude of the current in the third wire is 8 A.
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A proton moves 0.10 m along the direction of an electric field of magnitude 3.0 V/m. What is the change in kinetic energy of the proton? (e = 1.60 × 10-19 C)
The change in kinetic energy of the proton is 4.8 x 10⁻²⁰.
Change in kinetic energy of the protonThe change in kinetic energy of the proton is calculated as follows;
ΔK.E = W = eV
where;
V is the potential differencee is charge of electronV = Ed
V = 3 V/m x 0.1 m = 0.3 V
ΔK.E = 1.6 x 10⁻¹⁹ x 0.3 = 4.8 x 10⁻²⁰ J
Thus, the change in kinetic energy of the proton is 4.8 x 10⁻²⁰ J.
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Which of the following most directly shows how society affects physics? A. Elected officials make decisions about what research is funded. B. Physicists work on projects that will get them nominated for Nobel prize. C. Citizens panel provide input on most research projects. D. Governments budget money for national science- funding agencies
The option above which most directly shows how society affects physics is that physicists work on projects that will get them nominated for Nobel prize.
Who is a physicist?A physicist is a person who who studies physics.
Physics is one of the branches of science which involves the study of matter, light, mechanics...
In conclusion: the option below which most directly shows how society affects physics is that physicists work on projects that will get them nominated for Nobel prize.
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A barber Wants to set up a salon in a measuring Length of 3m by 3m. He has a simple Woden Chair, 3 large mirror and one bulb. a) using the knowledge of shadows and reflection, advice the barber on how to arrange a good salon using the unly items he has. b) without acking more sources of light, how can he enhance the lighting System in his salon? S A barber Wants to set up a salon in a measuring Length of 3m by 3m . He has a simple Woden Chair , 3 large mirror and one bulb . a ) using the knowledge of shadows and reflection , advice the barber on how to arrange a good salon using the unly items he has . b ) without acking more sources of light , how can he enhance the lighting System in his salon ?
Two mirrors are arranged such that they are parallel to each and perpendicular to the third mirror.
Also, the light is placed at the center of the three mirrors to produce multiple images by reflection.
What is reflection of light?Reflection is the bouncing back of light waves of a reflective surface when light shines on that surface.
The knowledge of reflection of light can be used by the Barber to set up a good salon.
The mirrors are arranged in the salon such that two of the mirrors are parallel to each and perpendicular to the third mirror. Also, the light is placed at the center of the three mirrors.
The parallel arrangement of the mirror will ensure that the clients will be able to have a full frontal and back view of themselves.
The parallel and perpendicular arrangement of the mirrors will also ensure that the light placed at the center will produce reflected to produce infinite images thus lighting up the salon.
In conclusion, the reflective properties of the mirrors as well as the angle between mirrors is used to create a well-lit salon by the barber.
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