What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)

Answers

Answer 1

Answer:

Step 1 of 6

(a)

The mass of benzene is  , so calculate the moles of benzene as follows:

The mass of toluene is, so calculate the moles of toluene as follows:

Now, calculate the mole fraction as follows:

Therefore, the mole fraction of benzene and toluene is  and  respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:

Here,  is the partial pressure of benzene,  is the vapour pressure of pure benzene and  is the mole fraction of benzene.

Vapour pressure of pure benzene at  is.

Substitute the values in the equation as follows:

Therefore, the partial pressure is  .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is  .

When the total pressure of the vapour pressure of the mixture is  at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at  as follows:

Since, the total pressure is less than the atmospheric pressure, the solution will not boil at  .

Calculate the total pressure of the solution at  as follows:

Since, the total pressure is greater than the atmospheric pressure, the solution will boil at  .

Therefore, the boiling point of the solution is  .

Step 4 of 6

(d)

Mole fraction of benzene at  is calculated as follows:

Mole fraction of toluene at  is calculated as follows:

Therefore, the mole fractions of benzene and toluene are  and  respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at  is  .

Partial pressure of benzene is calculated as follows:

Vapor pressure of toluene at  is  .

Partial pressure of toluene is calculated as follows:

Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:

Explanation:

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Answer 2
Total mol = (3.9 g * 1 mol C6H6 / 78.11 g = 0.0499 mol) + (4.6 g * 1 mol C7H8 / 92.14 = 0.0499 mol) =0.0798 mol.
Mole fraction benzene = 0.0499 / 0.0798 = 0.5.
Mole fraction toluene = 0.0499 / 0.0798 = 0.5

Related Questions

A 1,500 kg truck is towed sideways out of a mud-hole with a force of 15,000 N. What acceleration of the tow truck is needed to move this vehicle?

Answers

Yes because without movement the tow truck will not be moved with 15,000 N

Redox reactions stand for oxidation/reduction reactions. True or false: an oxidation reaction is always paired with a reduction reaction.

Answers

Answer:

The answer is: true

Explanation:

In redox reactions, the half-reactions of oxidation and reduction always occur simultaneously in pair.

The oxidation half-reaction involved the lost of electrons from a reduced substance (A) to form a oxidized substance (A⁺):

A ⇒ A⁺ + e-

In contrapossition, during the reduction half-reaction the oxidized substance (B⁺) gains electrons to form the reduced subtance (B):

B⁺ + e- ⇒ B

The overall redox reaction is obtained by the addition of the two half-reactions:

A ⇒ A⁺ + e-

B⁺ + e- ⇒ B

-----------------

A + B⁺⇒ A⁺ + B

The electrons gained by B are provided by A, which lost the same number of electrons. Thus, the oxidation/reduction reactions are paired.

Use the image to complete the sentences.

At left a grid labeled A of regularly arranged orange balls with small movement lines near each. At right a grid labeled B of regularly arranged orange balls with large movement lines near each.

Two different substances, Substance A and Substance B, are in direct contact with each other and are at different temperatures.

The particles in Substance B are vibrating
the particles in Substance A. This means Substance B is
Substance A and conduction will
.

Answers

Answer:

1. FASTER THAN- #2

2. WARMER THAN #1

3. OCCUR FROM SUBSTANCE B TO SUBSTANCE A- #3

Explanation:

I did the assignment On edg And got it right

Answer:

Use the image to complete the sentences.  

At left a grid labeled A of regularly arranged orange balls with small movement lines near each. At right a grid labeled B of regularly arranged orange balls with large movement lines near each.

Two different substances, Substance A and Substance B, are in direct contact with each other and are at different temperatures.

The particles in Substance B are vibrating

✔ faster than

the particles in Substance A. This means Substance B is

✔ warmer than

Substance A and conduction will

✔ occur from Substance B to Substance A

.

Explanation:

I know im late

Why can’t you ice skate on a lake when it is not frozen?

Answers

Because you’ll fall in the water.

For at least the last century Florida has experienced a hurricane season every year, from June to November. Which of the following describes this occurrence the BEST?
A. Florida's precipitation
B. Florida's global pattern
C. Florida's climate
D. Florida's weather ​

Answers

Answer:

Florida's Global Pattern.

Explanation:

Because of where Florida sits, the weather in the Gulf of Mexico actually blows enough water to Create tidal waves, and also hurricanes. at least that's what I was told cause I live here :>

what is the molecular geometry of c atom in ch3nh2

Answers

Answer:

compound is sp3.

Explanation:

Sp3 it is because it is trust me

Using the equations
2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol
2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.6 kJ/mol
C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/mol

Determine the enthalpy (in kJ/mol) for the reaction
6 C (s) + 3 H₂ (g) → C₆H₆ (l).

Answers

The enthalpy : 49.1 kJ/mol

Further explanation  

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways  

Reaction

1. 2C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol

Reverse

12 CO₂ (g) + 6 H₂O (g) ⇒ 2C₆H₆ (l) + 15 O₂ (g) ∆H° = 6271 kJ/mol : 2

6CO₂ (g) + 3H₂O (g) ⇒ C₆H₆ (l) + 15/2 O₂ (g) ∆H° = 3135.5 kJ/mol

2. 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.6 kJ/mol  x 3/2

3H₂ (g) + 3/2O₂ (g) → 3H₂O (g) ∆H° = -725.4 kJ/mol

3. C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/mol x 6

6C (s) + 6O₂ (g) → 6CO₂ (g) ∆H° = -2361 k/j/mol

-------------------------------------------------------------------------------------

6 C (s) + 3 H₂ (g) → C₆H₆ (l) ∆H° = 49.1 kJ/mol

We add up and the same compound that is on different sides we eliminate

i really need help with the rest of this assignment. theres 10 pages of multiple choice questions, i can mark brainliest and pay money if you help me :)

Answers

Answer:

Hey! I'll help you.

Explanation:

I got your back.

What is the concentration of chloride ions in a solution that contains 0.375 g of aluminum chloride in 15.0 mL of solution?

Answers

Answer:

0.561 M

Explanation:

Step 1: Given data

Mass of aluminum chloride (m): 0.375 gMolar mass of aluminum chloride (M): 133.34 g/molVolume of the solution (V): 15.0 mL

Step 2: Calculate the molar concentration of aluminum chloride (C)

We will use the following expression.

[tex]C = \frac{m}{M \times V(L) } = \frac{0.375g}{133.34 g/mol \times 0.0150L } = 0.187M[/tex]

Step 3: Write the reaction of dissociation of aluminum chloride

AlCl₃(aq) ⇒ Al³⁺(aq) + 3 Cl⁻(aq)

Step 4: Calculate the concentration of chloride ions

The molar ratio of AlCl₃ to Cl⁻ is 1:3. The concentration of Cl⁻ is 3/1 × 0.187 M = 0.561 M

How would you synthesize 1-hexanol starting from 1-propanol, incorporating a Grignard reagent in the synthesis?

Answers

Answer:

hjhjhjhhhhh

Explanation:

Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is __________.a) C2b) N2c) F2d) O2e) Ne2

Answers

Answer:

B.

Explanation:

ive done this before trust

1. Change the following into correct scientific notation.
a) 0.03050 =
b) 0.256 x 10°=
c) 25.005 10 =​

Answers

Answer:

a) 0.03050 = 3.050 × 10-²

b) 0.256 x 10°= 2.56 × 10-¹

c) 25.005 10 =​ 2.500510 × 10¹

Explanation:

Scientific notations is a way of making very large or very small numbers more comprehensive or simplified. It involves the use of power of ten (10^). The numbers are represented to the power of ten. The following format is used:

a x 10^b

where; a is a number or decimal number between 1 and 10 i.e less than 10 but greater than 1

b is the power of ten

To write a number in scientific notation,

- we move the decimal point right or left depending on whether we're trying to reduce or increase the number

- we count the number of times the decimal point was moved. This serves as the b in the format above.

For example,

a) 0.03050 = 3.050 × 10-²

The decimal point was moved rightward twice. This caused the ^-2 power.

b) 0.256 x 10°= 2.56 × 10-¹

The decimal point was moved rightward once. This caused the ^-1 power.

c) 25.005 10 =​ 2.500510 × 10¹

The decimal point was moved leftward once. This caused the ^1 power.

Using the two models, compare the processes of nuclear fusion and nuclear fission. What do the two processes have in common?
Choose all that apply.
A)
Energy is released.
B)
Elements are created
0)
A chain reaction occurs.
D)
Besides energy, neutrons are released.
E)
Both processes begin with an unstable nucleus.

Answers

Answer:it’s A and B

Explanation:

Answer:

A and B

Explanation:

They’re both fusion.

Which of the following has a nonpolar bond? *
02
HCI
NH3
CH4

Answers

Answer: CH4

Explanation:

BRAINLESS PLEASE

Answer:

O₂

Explanation:

The example of the compound or the molecule that forms a non-polar bond is oxygen gas.

Oxygen gas has a formula of O₂

Since this is a homonuclear molecule, the two bonding atoms have the same kind of electronegativity. The difference is therefore zero. In such a molecule, there is equal sharing of the electron pair between the atoms and no electrostatic charge on the molecule.

Which elements-O2, Rb, Sb, Pt, Y, Sm, Mn, Rh, Sn, Li-will react (a) with a solution of I to generate I2; (b) with a solution of Ag' to generate Ag; and (c) with a solution of Nat to generate Na?

Answers

Answer:

a) O2, Pt, Rh

b) Rb, Y, Sm, Mn, Sn, Li

c)Rb

Explanation:

We must consider the reduction potentials of each of the species in the question.

In (a) above, all the elements whose reduction potential is higher than the redox potential for the oxidation of I^- will react with a solution of I^- to generate I2 as shown above.

In (b) above, all the strong reducing agents can donate electrons to Ag^+ and reduce it to Ag as shown above.

In (c) Rb has a more negative reduction potential than sodium hence it can react with a solution of sodium salt to generate sodium metal.

Select the best answer from the choice below. When the wavelength decreases, the frequency:

Answers

Answer:

Increases

Explanation:

Frequency and wavelength of lights are inversely proportional to each other.

The wave of light having highest frequency have shortest wavelength and the light with the shortest frequency having highest wavelength.

Formula:

Speed of light = wavelength × frequency

c = λ × f

λ = c/f

This formula shows that both are inversely related to each other.

The speed of light is 3×10⁸ m/s

Frequency is taken in Hz.

It is the number of oscillations, wave of light make in one second.

Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.

What was the test or tests that made you decide if you compound was an aldehyde or a ketone and why?

Answers

Answer:

Tollen's test or silver mirror test is use to distinguish between ketone and aldehyde.

Explanation:

Tollen's test is use to distinguish aldehyde from ketone because Tollen reagent consist of silver nitrate and ammonia and it oxidized aldehydes to carboxylic acid and the silver Ag+ is reduced to solid silver Ag. It form a inner film wall on the tube that look like mirror. Ketone do not react with Tollen reagent and therefore does not form silver mirror on the tube wall.

2 or more forces that are not equal and opposite of one another can cause change in motion

A. Balanced force

B.friction

C.gravitational force

D.unbalanced force

Answers

Answer:

D unbalanced force

Explanation:

i think

The temperature of a sample of CH4 gas (10.34 g) in a 50.0 L vessel at 1.33 atm is ________ °C.

a.

984

b.

-195

c.

-1260

d.

-195

Answers

Answer:

option C is correct

Explanation:

Considering the ideal gas law and the definition of Avogadro's Number, the correct option is option a. The temperature of a sample of CH₄ gas (10.34 g) in a 50.0 L vessel at 1.33 atm is 984 °C.

In first place, you have to know that ideal gases are a simplification of real gases that is done to study them more easily.

It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T).

The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P×V = n×R×T

In this case, being the molar mass of CH₄ being 16 [tex]\frac{g}{mole}[/tex], that is, the mass present in one mole of an element or compound, the number of moles that 10.34 grams contains is calculated as:

[tex]10.34 g*\frac{1 mole}{16.04 g} = 0.645 moles[/tex]

So, you know:

P= 1.33 atmV= 50 Ln= 0.645 molesR=0.082 (atm×L)/ (mol×K)T= ?

Replacing:

1.33 atm × 50 L= 0.645 moles× 0.082 (atm×L)/ (mol×K) ×T

Solving:

T= [1.33 atm × 50 L] ÷ [0.645 moles× 0.082 (atm×L)/ (mol×K) ]

T≅ 1257 K

Being 273 K equivalent to 0 C, then:

T= 1257 K= 984 C

In summary, the correct option is option a. The temperature of a sample of CH₄ gas (10.34 g) in a 50.0 L vessel at 1.33 atm is 984 °C.

Learn more about the ideal gas law: brainly.com/question/4147359?referrer=searchResults

A weather balloon with a volume of 3.40774 L

is released from Earth’s surface at sea level.

What volume will the balloon occupy at an

altitude of 20.0 km, where the air pressure is

10 kPa?

Answer in units of L.

Answers

Answer: The volume at an altitude of 20.0 km is 34.5289 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]     (At constant temperature and number of moles)

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 101.325 kPa ( at sea level)

[tex]P_2[/tex] = final pressure of gas = 10 kPa

[tex]V_1[/tex] = initial volume of gas = 3.40774 L

[tex]V_2[/tex] = final volume of gas = ?

Now put all the given values in the above equation, we get the final volume of gas.

[tex]101.325\times 3.40774=10\times V_2[/tex]

[tex]V_2=34.5289L[/tex]

Thus the volume at an altitude of 20.0 km is 34.5289 L

Therefore, the final pressure of the gas will be 3.75 atm

Each of the two different solids A and B melts at 133 o C. A sample of an unknown solid melts around 133 o C, and is either A or B. How will you determine the identity of the unknown solid

Answers

Answer:

See explanation

Explanation:

The melting point range of a pure compound is about 1-2ºC of the expected melting point. An impure solid melts within a range   that is both larger than that of the pure substance  (>1ºC) and begin at a  lower temperature because impurities decrease the meting point. A melting range of 5º or more  indicates that a compound is impure.

Since the melting points of A and B are estimated  at 133 o C, the melting point range for each pure substance must be slightly different from each other. The melting point of the unknown is measured and its range is compared with the melting point ranges of pure A and B then decision can  now be made about the identity of the unknown solid.

How would one use a Grignard-based synthesis to accomplish the following transformation? benzyl bromide (PhCH2Br) to 3-phenyl-1-propanol 1. Mg, Et20 2. ethylene oxide3. H3O+ 1. Mg, Et2O 2. Ethanol3. H3O+ 1. Mg, Et202. Ethylene 3. H3O+ None of the above.

Answers

Answer: ghfbg

Explanation: fgfghfg

Balance chemical equation hbr(aq)+o2(g) h20+br2

Answers

Answer:

2HBr + O2 = H20 +Br2

Explanation:

Answer:

4hbr(aq) + O2(g) = 2H2O + 2Br2

Explanation:

How many electrons does Sodium lose to become an ion

Answers

For Sodium would need to lose 11 electrons to become an ion.


How many more electrons are there in the last energy level of phosphorus, atomic
number 15, than there are in the last principal energy level of neon, atomic number 10?​

Answers

sorry but I need some three point so that's why I didn't

What is the work function of gold metal in kJ/mol if light with λ = 234 nm is necessary to eject electrons?

Answers

Answer

512kj/mole

Explanation:

What is the work function of gold metal in kJ/mol if light with λ = 234 nm is necessary to eject electrons?

The energy can be calculated using below expresion;

E = hc/λ

Where h= planks constant= 6.626 x 10^-34

c= speed of light= 3 x 10^

λ= wavelength

hc= (6.626 x 10^-34 x 3 x 10^ 8)

=

A student combines a sample of gas (2.0 L) at 3.5 atm with with another gas (1.5 L) at 2.8 atm pressure into an empty 7.0 L flask. Assuming the gases are combined at constant temperature, what is the total gas pressure (in atmospheres) in the 7.0 L flask?

Answers

Answer:

Total gas pressure is 1.60 atm

Explanation:

To solve this question we can use the Ideal Gases Law. We need to determine how many moles of each gas will be finally present at the flask of 7 L.

Let's asume the gas, are at Asbsolute T°, 273K

P. V = n . R . T

3.5 atm . 2L = n . 0.082 . 273K

(3.5 atm . 2L) / (0.082 . 273K) = 0.313 moles

(2.8 atm . 1.5L) / (0.082 . 273K) =  0.188 moles

Total moles = 0.313 mol + 0.188 mol = 0.501 mol

Let's calcualte the hole pressure

P . 7L = 0.501 moles . 0.082 . 273K

P = (0.501 moles . 0.082 . 273K) / 7L → 1.60 atm

What does this image represent?
Amine group
Carbonyl group
Ether group
Hydroxyl group

Answers

I don’t really have a clear answer for you but this might help

Answer:

ether group

Explanation: I looked it up

In frequency modulation, which wave property remains constant?

Answers

Answer:

The correct answer is - Amplitude.

Explanation:

Frequency modulation is a method or procedure that sends or transmits the signals such as radio broadcasting, telecommunication where the value of the transmitted signal is provided by the frequency of a high-frequency wave that carries the signal.

In this method of encoding the information, the amplitude of the carrier remains the same or constant but frequency varies in accordance with the modulating signal.

Answer:

The answer is C Amplitude

Explanation:

Because you can give me Brainiest  PLZZZZZZZZZZZZZZZZZZZZ

What happens when this match is struck against the side of the match box?

Answers

Answer:

It lights on fire

Explanation:

The friction sparks the match causing it to go on fire.

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