what is the minimum mass of ethylene glycol that must be dissolved in 14.5 kg of water to prevent the solution from freexing at -14.2

Answers

Answer 1

Answer:

The minimum mass of ethylene glycol = 6.641 Kg

Explanation:

[tex]\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f[/tex]

Where T_f = freezing point of pure solvent water, 0°C

T_f'= Freezing point of solvent after mixture

K_f = Freezing point depression constant = 1.86 °C/m

Moecular weight of ethylene glycol = 60 g/mol

Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g

molality of ethylene glycol

[tex]m = \frac{weight}{mol.wt} \times\frac{1000}{V}[/tex]

Substitute the values to calculate m

[tex]m = \frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]

by formula

[tex]0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]

calculating we get w = 6641.93 g

Therefore, The minimum mass of ethylene glycol = 6.641 Kg


Related Questions

why did researchers at the university of Antwerp study high speed videos of the black woodpecker​

Answers

here's your answer..

What volume of 0.686 M HCl would contain 0.037 moles of solute?

Answers

Given :

Molarity of HCl solution, M = 0.686 M.

Number of moles, n = 0.037 moles.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]

Hence, this is the required solution.

A heavy brick weighs more than a fluffy cushion, but the cushion takes up more space. Which object has more matter?

Answers

Answer:

The brick has more matter because it has more mass.

Explanation:

The brick has more matter because the cushion has less mass than the brick

What
is the major engine driving the planet's constant evolution and contains a geological record of much of the Earth's history

1. Mantle
2. Crust
3. Inner Core
4. Outer Core

Answers

Mantle I’m pretty sure
The mantle or inner core Is the answer

Butane C4H10, is an easily liquedfied gaseous fuel. calculate the density of butane gas at 0.897 atm and 24°C. give the answer in grams per litre​

Answers

Answer:

Density = 2.137 gram per liter (Approx.)

Explanation:

Given:

Gaseous fuel Butane C4H10

Pressure = 0.897 atm

Temperature = 24°C = 24 + 273 = 297 k

Find:

Density of butane gas

Computation:

We know that molar mass of butane = 58.12 g/mol

Density = [molar mass x pressure] / Rt

Density = [58.12 x 0.897] / [0.0821 x 297]

Density = [52.13] / [24.3837]

Density = 2.137 gram per liter (Approx.)

Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.

Answers

Explanation:

[tex] = 2.5\% \times 2000 \\ = \frac{2.5}{100} \times 2000 \\ = 50 \: g[/tex]

A chemist adds of a magnesium fluoride solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to significant digits.

Answers

The given question is incomplete, the complete question is:

A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to

3 significant digits.

Answer:

The correct answer is 1.35 microgram.

Explanation:

Based on the given information,

The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.

Now the moles of MgF₂ can be determined by using the formula,

Moles = Concentration × Volume

Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂

= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml

= 217 × 10⁻⁷ mmol

The molecular mass of magnesium fluoride is 62.3 gram per mole

Thus, the mass of MgF₂ is,

= 217 × 10⁻⁷ mmol × 62.3 g/mol

= 13500 × 10⁻⁷ mg

= 1.35 microgram

How many grams of O2 can be produced from 3 moles KCIO3-

Answers

Answer:

In the question the mass has two significant figures; thus the mass of O2 released would be 4.0 g (two significant figures). 122.55 g of KClO3 yields 3*32 g of O2

Explanation:

El butano, C4H10, se quema en presencia de oxígeno gas, O2, y se produce dióxido de carbono, CO2, y agua. ¿Cuántos kg de CO2 se obtendrán al quemarse 12 kg de butano?

Answers

Answer:

don't know really and don't know at alll

in any chemical reaction each type of atom is conserved​

Answers

Answer:

Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction. The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.

Positive or negative , guys?

Answers

I think it’s positive

which functional group does the molecule below contain

Answers

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

If the temperature decreases, then the pressure will​

Answers

then the temperature decreases.

Write a balanced chemical equation for the reaction. Na2CO3Na2CO3 and AgNO3AgNO3 Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Na = 2[tex]CO_{3}[/tex] = 1Ag = 1[tex]NO_{3}[/tex] = 1

Number of atoms present on product side are as follows.

Na = 1[tex]CO_{3}[/tex] = 1Ag = 2[tex]NO_{3}[/tex] = 1

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

I need help with my chemistry but you can only choose one correct answer​

Answers

Answer:

Explanation:

photosynthesis

the given chemical reaction is photosynthesis.

During photosynthesis carbon dioxide absorbed by plants reacts with water in presence of sunlight to give glucose and oxygen.

It’s double replacement

About how long did it take for this population to reach the carrying capacity of this habitat

Answers

Answer:100

Explanation:

How are the stratosphere and the mesosphere similar

Answers

Answer:

stay safe healthy and happy...

Construct a Lewis structure for hydrogen peroxide, H2O2, in which each atom achieves a stable noble-gas electron configuration. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.

Answers

Answer:

See explanation and image attached

Explanation:

Hydrogen peroxide is made up of two atoms of hydrogen and two atoms of oxygen as shown in the image attached.

The two oxygen atoms are joined together by a single covalent bond and each of the oxygen atoms are bonded to one hydrogen atom each.

There are two lone pairs on each of the oxygen atoms.

The Lewis(dot) structure for hydrogen peroxide is shown in the image attached to this answer.

Explain why the ability of PLP to catalyze an amino acid transformation is greatly reduced if the OHOH substituent of pyridoxal phosphate is replaced by OCH3OCH3.

Answers

Answer:

Following are the responses to the given question:

Explanation:

In the given question the OH could be generated as the H-bond with both the N (nitrogen), which is used to place its N as the partially positive value(+). It is used to simplifies the addition for either its  AA with the imine C. In the above H-bond, the w N is not required as the possibility to use the OCH3

The pressure of a gas is 1.0 atm, the volume is 3.0 L, and the temperature is 200 K. A chemist changes one factor while keeping another constant so that the new pressure is 2.0 atm. Which of the following could be the new conditions?

The final volume is 6.0 L, while temperature is kept constant.
The final temperature is 100 K, while volume is kept constant.
The final volume is 4.0 L, while temperature is kept constant.
The final temperature is 400 K, while volume is kept constant.

Answers

The final temperature is 100k while volume is kept constant (second one)

Answer: The correct answer is actually: The final temperature is 400 K, while volume is kept constant.

Explanation: Got it right on test!

An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound.

Answers

Answer:

The molecular formula of the compound is C10H16O.

Explanation:

Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.

The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.

The formula of osmotic pressure is,

P = CRT

Now putting the values in the formula we get,

0.328 = C*0.0821*300

C = 0.013317

C = (mass/molecular mass) * (1000/volume of solution in ml)

0.013317 = (0.152/Molecular mass) * (1000/75)

Molecular mass = 152.186

C mass = 152.186 * 0.789 = 120.07 grams

C mole = 120.07/12 = 10

H mass = 152.186 * 0.1059 = 16.11 grams

H mole = 16.11/1 = 16

O mass = 152.186 - 120.07 - 16.116 = 16 grams

O mole = 16/16 = 1

Thus, the molecular formula of the compound will be,

C10H16O

When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light,motion,or electricity. This is called

Answers

Answer: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Explanation:

The chemical energy present in fuels actually releases when these fuels are burned or by combustion.

Hence when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

For example, gasoline present in vehicles burns and undergoes chemical change which is then converted into thermal energy. This thermal energy then converts into mechanical energy due to which car moves.

Thus, we can conclude that when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Find the concentration of Pb2 (aq) in ppm by mass of a 1.13 L sample of contaminated water that was assayed by adding NaI(s) and obtaining 55.1x10-3 g of PbI2(s) precipitate. Assume that Pb2 (aq) is completely precipitated as PbI2(s). The molar mass of PbI2(s) is 461.01 g/mol. Assume that the density of the solution is 1.00 kg/L. Give the answer with 3 or more significant figures.

Answers

Answer:

22.1 ppm

Explanation:

The equation of the reaction is;

Pb2+ (aq)  + 2NaI(s) ------>PbI2(s) + 2 Na^2+

Mass of precipitate =  55.1x10-3 g

Number of moles of precipitate =  55.1x10-3 g/461.01 g/mol = 1.2 * 10^-4 moles

1 mole of  Pb2+  yields 1 mole of PbI2

Hence 1.2 * 10^-4 moles of  Pb2+  also yields  1.2 * 10^-4 moles of PbI2.

Hence mass of Pb2+ present = 1.2 * 10^-4 moles * 207 g/mol = 0.025 g or 25 mg

Mass of solution = Density of solution * volume of solution

Mass of solution = 1.00 kg/L * 1.13 L

Mass of solution = 1.13 Kg

Concentration in mg/Kg(ppm) = mass of solute/mass of solution

= 25 mg/1.13 kg

= 22.1 ppm

7 grams of oxygen gas is reacted with excess C4H8. How many grams of CO2 gas at STP are produced?

Answers

i think 14 are produced because if you go up by that you get it

To double-check a chemical in lab before using it, sniff near the opening of the container, true or false?

Answers

The answers is false because you do not want to inhale unknown chemicals

can u pls help me i need the answer ASAP

Answers


The answer is c ( to disturbance heat

Brainiest and 10 points
Which has a HIGHER frequency?
A. Orange light
B. Blue light

Answers

Answer:

A. Orange light

Explanation:

According to the band spectrum of white light ( ROYGBIV )

Answer:

I think it blue light is higher

Acids and bases are chemical molecules with very different characteristics.

a. True
b. Fasle

Answers

Answer:

TRUE ,hope it helped you

Explanation:

How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?

Answers

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

A mixture of 0.224 g of H2, 1.06 g of N2, and 0.834 g of Ar is stored in a closed container at STP. Find the volume (in L) of the container, assuming that the gases exhibit ideal behavior.

Answers

Answer: The volume of given container is 3.83 L.

Explanation:

Given: Mass of [tex]H_{2}[/tex] = 0.224 g

Mass of [tex]N_{2}[/tex] = 1.06 g

Mass of Ar = 0.834 g

Since, moles is the mass of a substance divided by its molar mass. Therefore, moles of given substances present in the mixture are as follows.

Moles of  [tex]H_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.224 g}{2 g/mol}\\= 0.112 mol[/tex]

Moles of [tex]N_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.06 g}{28 g/mol}\\= 0.038 mol[/tex]

Moles of Ar are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.834 g}{40 g/mol}\\= 0.021 mol[/tex]

Total moles = (0.112 + 0.038 + 0.021) mol = 0.171 mol

Now, using ideal gas equation the volume is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]V = \frac{nRT}{P}\\= \frac{0.171 mol \times 0.0821 L atm/mol K \times 273 K}{1 atm}\\= 3.83 L[/tex]

Thus, we can conclude that the volume of given container is 3.83 L.

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