What is the magnitude of the force that must be applied for the system below to be balanced?



Group of answer choices

20 N

0 N

80 N

30 N

What Is The Magnitude Of The Force That Must Be Applied For The System Below To Be Balanced?Group Of

Answers

Answer 1
I believe that it is 20 N

Related Questions

A track & field jumper goes into the long jump with a speed of 5.0 m/s at an angle of 20⁰ above the horizontal. what is the jumper's horizontal speed as they jump? what is their vertical speed?

Answers

Answer: Horizontal Speed = 4.6 m/s

              Vertical Speed = 1.7 m/s

Explanation:

Jumper's velocity = 5 m/s

Angle = 20 degrees

the angle is theta, so theta = 20 degrees

Theta is the angle between the hypothenuse and the adjacent side.

The horizontal side will be the adjacent side, and the vertical side will be the opposite side.

The hypothenuse = 5 m/s

First, let's calculate the adjacent side (horizontal speed)

We have cosine of theta, which is equal to adjacent side / hypothenuse

So, [tex]cos(20) = adjacent/5[/tex]

Multiply 5 on both sides, to get the 5 on the right side canceled.

5cos(20) = adjacent side.

4.6 = adjacent side

Horizontal Speed = 4.6 m/s

Now, let's calculate the vertical speed.

To do that, we need to calculate the opposite side.

We can calculate the opposite side with the help of sin.

The sin of theta equals to opposite side / hypothenuse

[tex]sin(20)=opposite/5[/tex]

We do the same thing, multiply 5 on both sides.

5sin(20) = opposite

1.7 = opposite

Vertical Speed = 1.7 m/s

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A uniform mixture consist of 30cm3 of water and 40cm3of ethanol. if the densities of water and ethanol are 1g/cm3 and 0.85g/cm3 respectively. determine the densities of the mixture.

Answers

The total density of the mixture is 0.485 g/cm^3

What is density:

The density, of a substance is its mass per unit volume. Density is denoted with symbol ρ

The formula of density:

ρ = m / v

here,

volume of water, v1 = 30 cm^3

volume of ethanol, v2 = 40 cm^3

density of water, ρ1 = 1 g/cm^3

density of ethanol, ρ2 = 0.85 g/cm^3

so, according to formula,

for water

ρ1 = m1 / v1

m1 = ρ1 * v1

m1 = (1) * (30)

m1 = 30 grams

for ethanol

ρ2 = m2 / v2

m2 = ρ2 * v2

m2 = (0.85) * (40c)

m2 = 34 grams

total mass, M= m1 + m2

M= 30 + 34

M= 64 grams

total volume, V= v1 + v2

V= 30 + 40

V= 70 g/cm^3

Density of the mixture:

ρ = M / V

ρ = 34 / 70

ρ = 0.485 g/cm^3

Hence The total density of the mixture is 0.485 g/cm^3

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You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In joules, how much elastic potential energy is stored in the spring

Answers

The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

[tex]E= \frac{1}{2} kx^2[/tex]

where;

k is the spring constant

x is the compression/stretching of the string

In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

[tex]E=\frac{1}{2} (150) (0.3)^2[/tex]

[tex]E=6.75J[/tex]

Therefore. the elastic potential energy stored in the spring is 6.75J .

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A small girl applies a horizontal force of 2 Newtons to a 10-Newton box which slides across the floor with a constant speed of 3 m/s. What is the frictional force, in Newtons, by the floor on the box

Answers

2N is the frictional force by the floor on the box.

According, Newton's 2nd law

[tex]F=mA[/tex]

where,

F = Horizontal force

m = Mass

a = Acceleration

But, a = 0 as Constant speed = 0 acceleration.

       v = constant

Hence, there should be no net force. The frictional force is opposing the girl's force and should be equal to one another.

Frictional force = 2N

Therefore, the horizontal force applied by a small girl on the box is equal to the frictional force by the floor on the box.

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what are effects of high gravity on blood pressure, blood circulatory system, size of lungs, bone fragility and density​

Answers

Answer:

Explanation:

On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.

The box resting on the inclined plane above has a mass of 20kg. The incline sits at a 30o angle. Find the friction force between the box and the incline if the box does not slide down the incline.

Answers

The friction force between the box and the incline if the box does not slide down the incline will be 0.577

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.

Given the box resting on the inclined plane above has a mass of 20kg and the The incline sits at a 30 degree angle

We have to find the friction force between the box and the incline if the box does not slide down the incline

Since the frictional force F₁ must equal or exceed gravitational force F₂ down the incline:

F₁ = F₂

μmgcosΘ = mgsinΘ

μ = (mgsinΘ)/(mgcosΘ)

μ = tanΘ

μ = 0.577

Hence the friction force between the box and the incline if the box does not slide down the incline will be 0.577

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:The resistance created by the box's friction with the incline The slope will be 0.577 if the box doesn't descend.

Friction is the force that prevents solid surfaces, fluid layers, and material constituents from sliding past one another. Different types of friction exist. Dry friction opposes the relative lateral motion of two touching solid surfaces.

Given that the 20-kg box lying on the inclined plane above and the incline's 30 degree inclination

If the box does not slide down the incline, we must determine the friction force between them.

Given that the gravitational force F2 down the gradient must be equal to or greater than the frictional force F1,

F₁ = F₂

If mgcosx = mgsinx

equals (mgsinx)/(mgcosx)

μ = tanx

μ = 0.577

Therefore, if the box does not slide down the incline, the friction force between the box and the incline will be 0.577.

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A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the lowest constant acceleration needed for takeoff from a 1.80 km runway

Answers

The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

To find the answer, we need to know about the Newton's equation of motion.

What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aSV= final velocity, U= initial velocity, S= distance and a= accelerationWhat's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/sSo, 100²-0= 2×a×1800

=> 10000= 3600a

=> a= 10000/3600 = 2.8 m/s²

Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

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Two vertical parallel straight wires carry currents upward and are separated by 8.2 cm. Wire 1 exerts a force on the other wire of 7.7 X 10-5 N/m and is carrying a current of 23.0 A. What is the current in the other wire

Answers

The current in the second wire is 1.37 A.

Current in the second wire

The current in the second wire is calculated from the magnetic force between the two wires.

F/L = (μI₁I₂)/(2πr)

where;

μ is permeability of free spaceI₂ is current in the second wireF/L is force per unit lengthr is the distance between the two wires

μI₁I₂ = (F/L 2πr)

I₂  = ((F/L 2πr) / (μI₁)

I₂  = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)

I₂  = 1.37 A

Thus, the current in the second wire is 1.37 A.

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Why is a white car an example of a poor blackbody radiator?
A. It reflects most of the light that hits it.
B. It absorbs most frequencies of electromagnetic radiation.
C. It emits more light when it is heated up.
D. It gives off only one frequency of electromagnetic radiation.

Answers

A white automobile is a bad example of a blackbody radiator since it reflects the majority of the light that strikes it.

Why is a white car a bad example of a radiator in a black body?

The same colour as an ideal absorber, an ideal radiator, sometimes known as a blackbody, absorbs all radiation that strikes it. White, on the other hand, is a poor radiator and absorber. Like a mirror, a white object reflects all radiation.

What does a subpar blackbody radiator look like?

Certainly, a red laser pointer is a poor choice for a black body, for the following reasons: A heated object, like a chunk of red-hot metal from a furnace, produces a black body spectrum.

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A generator produces 30 pulsesin 5 second. its frequency is?

Answers

Answer:

6 pulse per second

Explanation:

if,

5 secs = 30 pulse

1 sec = 30/5

1 sec = 6

Boxes A and B are being pulled to the right on a frictionless surface. Box A has a larger mass than B. How do the two tension forces compare

Answers

Answer:

Tension T1 is less than tension T2.

T1 < T2

Explanation:

According to given data,

mass of box A ( mA) is grater than mass of box B (mB)

we can write,

m(A) > m(B)

Newton's second law states that:

Tension of object is directly proportional to the mass of the system.

T ∝ m

here Boxes A and B are being pulled to the right on a frictionless surface,

so Tension T1 generates due to the mass of box A m(A)

and Tension T2 arises due to mass of the system m(A) + m(B)

Thus tension T1 will be less than tension T2

T1 < T2

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A converging lens of focal length 15cm is used to obtain a real image magnified 1½ times. calculate the distance of the image from the lens
a. 37.5cm
b. 22.5cm
c.15.0cm
d.7.5cm
e.3.3cm​

Answers

Answer:

don't know the answers sorry

A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic energy Kair did the air molecules gain from the falling coffee filter? Start from the Energy Principle, and choose as the system the coffee filter, the Earth, and the air.

Answers

The kinetic energy gained by the air molecules is 0.0437 J                

Given:

Mass of a coffee filter, m = 1.5 g

Height from which it is dropped, h = 3 m

Speed at ground, v = 0.7 m/s

Initially, the coffee filter has potential energy. It is given by :

[tex]P =mgh[/tex]

P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m

P = 0.0441 J

Finally, it will have kinetic energy. It is given by :

[tex]E= \frac{1}{2} mv^{2}[/tex]

[tex]E= \frac{1}{2}[/tex]×[tex]1.4[/tex] × 10⁻³ × (0.7)²

E = 0.000343 J

The  kinetic energy Kair did the air molecules gain from the falling coffee filter is :

E = 0.000343 -  0.0441

  = 0.0437 J

So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

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A baseball outfielder throws a 0.150-kg baseball at a speed of 40.0 m/s and an initial angle of 30.08 to the horizontal. What is the kinetic energy of the baseball at the highest point of its trajectory

Answers

The kinetic energy of the ball at the highest point of its motion is equal to 90.2 Joules.

Given the following data:

Mass of baseball = 0.150 kg

Speed of baseball = 40.0 m/s

V = v Cos(θ)

V= v cos 30

V= 40 x 0.867

V=34.68 m/s

K.E =1/2 MV^2

K.E= 1/2 x 0.150 x 34.68^2

K.E= 90.2 Joules.

Kinetic energy is a type of energy that an object or particle has due to its motion. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy.

Kinetic energy has three subcategories: vibration, rotation, and translation. Naturally, the oscillating kinetic energy is caused by a vibrating object. Rotational kinetic energy is generated by moving an object, and translational kinetic energy is caused by the collision of an object.

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What must the amplitude of a traveling wave of frequency 72.0 Hz be in order for the average power carried by the wave to be 0.363 W

Answers

The amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.

Amplitude of the wave

The amplitude of the wave travelling at the given frequency and power is calculated as follows;

U = (¹/₂)(T/v²)(ω²)(A²)(v)

U = (¹/₂)(T/v)(ω²)(A²)

U = (¹/₂)(T/v)(2πf)²(A²)

where;

U is the average power of the waveT is the tension in the wireω angular frequency of the waveA is amplitude of the wavev is the speed of the wavef is frequency of the wave

Thus, the amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.

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A person has a choice of either pushing or pulling a book of ice with a mass of 50kg at a constant velocity. Assuming a coefficient of friction on 0.2 and pushing or pulling at the angle depicted, calculate the applied force needed for situations (a) and (b).

Answers

The applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.

How to determine the applied force

We have that the force for situation 'a' is on an angle of inclination of 25° with the book of ice.

Thus,

Applied force = mg × sine of angle of inclination

Where mass, m = 50kg

g = acceleration due to gravity = 10m/s^2

Applied force = 50 × 10 × sin 25

Applied force = 50 × 10 × 0. 4226

Applied force = 211. 31 Newton

For situation 'b', the mass of block is adjacent to the book of ice, thus

Applied force = mg × cos of angle of inclination

Applied force = 50 × 10 × cos 25

Applied force = 50 × 10 × 0. 9063

Applied force = 453. 15 Newton

Thus, the applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.

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A leaf fell from a tree branch. The path it followed is shown in the diagram below.
Which of these best describes why the leaf fell in a crooked path instead of straight down?

Answers

The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.

What is an air current?

An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.

When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.

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A worker pushing a 35.0-kg wooden crate at a constant speed for 12.0 m along a wood floor does 350 J of work by applying a constant horizontal force of magnitude F on the crate. (a) Determine the value of F. (b) If the worker now applies a force greater than F, describe the subsequent motion of the crate. (c) Describe what would happen to the crate if the applied force is less than F.

Answers

If the force is increased, the crate will become accelerated while if the force is decreased, the crate will decelerate.

How do we obtain the force?

Recall that the force is the product of mass and acceleration. Now we know that work is done when the force applied moves a distance. Since the velocity is constant;

W = Fs

F= W/s

F = 350 J/ 12.0 m

F = 29.2 N

If the force is increased, the crate will become accelerated while if the force is decreased, the crate will decelerate.

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Metal a has acofficient of linear expantion that is four times the cofficient of linear expantion of meta b. how does their cofficient of areal expantion of metalb, compare?

Answers

The coefficient of aerial expansion for metal b is one-fourth of the coefficient of aerial expansion for metal a.

Note: Most probably your question was to find the relation between the coefficient of aerial expansion for metal a and metal b.

Coefficient of linear expansion:

The ratio of the change in length of a solid to its original length when there is a unit change in temperature at constant pressure is called the coefficient of linear expansion. It is given by the formula,

α=ΔL/(Lo*ΔT)

where α is the coefficient of linear expansion,  ΔL is the change in length Lo is the original length, and ΔT is the change in temperature.

Coefficient of aerial expansion:

The ratio of the change in surface area of a solid to its original surface area when there is a unit change in temperature at constant pressure is called the coefficient of aerial expansion. It is given by the formula,

β=ΔA/(Ao*ΔT)

where β is the coefficient of aerial expansion,  ΔA is the change in surface area, Ao is the original surface area, and ΔT is the change in temperature.

Relation between α and β:

The relation between the coefficient of linear expansion and aerial expansion is given by the formula,

β=2α

Given that metal a has a coefficient of linear expansion four times that of  metal b. It can be written.

α₁=4α₂

where α₁ is the coefficient of linear expansion for metal a and α₂ is the coefficient of linear expansion for metal b.

Then from the above relation, the ratio of the coefficient of aerial expansion β₁ and β₂ for metal a and metal b respectively is,

β₁/ β₂ = 2*(α₁)÷(2*(α₂))

β₁/ β₂= 2*(4α₂)÷(2*(α₂))

β₁/ β₂=4

β₂= β₁/4

Therefore, the coefficient of areal expansion of metal b is one-fourth of the coefficient of aerial expansion of metal a.

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What is a standard drink measurement

Answers

The standard drink measurement should contain 14 grams of pure alcohol in United States of America.

What is standard drink measurement?

Standard drink measurement can be defined as the measurement of alcohol that is expected by an individual to consume daily without having a bad health effect.

In the United States of America, an amount of 14 grams of pure alcohol which can be found in 12 ounces of beer is regarded as normal.

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As you stand near a railroad track, a train passes by at a speed of 34.7 m/s while sounding its horn at a frequency of 215 Hz. What frequency do you hear as the train approaches you

Answers

When the train is approaching then the frequency is 239.2 Hz.

What is the frequency?

This is the total number of times a periodic event happens within a given period of time. Wavelengths are used to measure periodic phenomena, which are frequently waves like sound waves. The frequency is the total number of wavelengths throughout time.

given,

speed of train = 34.5 m/s

Frequency of sound = 215 Hz

speed of sound = 341 m/s

when the train is approaching:

 [tex]f1 = f[/tex]ₓ [tex]\frac{V}{V-Vt}[/tex]

[tex]f1 = 215[/tex]ₓ [tex]\frac{341}{341 + 34.5}[/tex]

f₁ = 239.2 Hz                                

Hence, when the train is approaching then the frequency is 239.2 Hz.

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Energy released by the sun results from the process where atomic nuclei

a) none of these

b) combine

c) both of these

d) break apart

Answers

Answer:

b) combine

Explanation:

The energy from the sun is due to Nuclear Fusion where lighter nuclei combine to form heavier and stable nuclei this releasing a lot of energy in this process.

The current in a wire is 3 a . calculate the charge that flows through the wire in 1 minute

Answers

The charge of the wire is 180 C.

What is a charge?

The term charge is defined as the product of the current and the time taken. Thus we can write that;

Q = It

Q = charge

I = current

t = time

Hence;

Q = 3 A * 1 * 60 s = 180 C

Thus the charge of the wire is 180 C

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An object is launched upwards at an initial speed of 3 m/s. What is the maximum height reached by the object from where it was launched

Answers

Answer:

the maximum height reached by the object from where it was launched is 0.4591 m

Explanation:

initial speed of the object, u= 3 m/s

The velocity at the maximum height will always be 0.

Therefore,  final velocity, v= 0 m/s  

Using the Newton's  equation of motion,

v^2 - u^2 = 2*g*h(max)

0 - u^2= 2*g*h(max)

h(max) = -u^2 /2* g

where g is the gravitational acceleration.

g= - 9.8 m/s^2

substituting the values in equation,

h(max)= - (3*3) / 2*(-9.8)

h(max) =  0.4591 m

the maximum height reached by the object from where it was launched is 0.4591 m

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A current magnetic relay is often used to assist in the starting of the compressor, but most new appliances use a(n) ____________________ device.

Answers

A current magnetic relay is often used to assist in the starting of the compressor, but most new appliances use positive temperature coefficient (PTC) device.

What is a compressor?

A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.

According to heating, ventilation, and air conditioning (HVAC), a current magnetic relay is mostly used to assist in the starting of the compressor, but many new electrical appliances use positive temperature coefficient (PTC) device.

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What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subscript of 1, e.i. I1 = ) What is this value of the moment of inertia when the person is on the edge of the merry-go-round?

Answers

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

the quantity expressed by the body resisting angular acceleration.It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

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give the phases into which matter can be classified, and an example of each​

Answers

Explanation:

there are 4 phases in which matter could be classified.

1. Solid: an example of this would be the metal copper.

2. Liquid: an example of this would be H2O or water.

3. Gas: an example of this would be oxygen gas or O2

4. Plasma: an example of this would be lightning.

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PLEASE HELP! Place these bodies of our solar system in the proper order of formation.
(THIS NOT PHYSICS THIS IS ASTRONOMY)

- solar nebula
- inner planets
- outer planets
- the sun
- planetesimals

Answers

Answer:

1. Solar Nebula

2. The Sun

3. Planetesimals

4. Inner planets

5. Outer planets

Explanation:

A star is formed in a molecular cloud of gas and dust, mainly composed of hydrogen and helium. The Nebular Theory establishes, for the formation of the solar system, that the cloud starts to collapse under its own gravity when it receives a shock wave from a near event, for example, a supernova explosion. That results in the cloud breaking in small pieces, and those pieces constitute a possible future star.

Then it begins to accrete and rotate as a consequence of the angular momentum. In the center of that disk when it reaches the necessary temperature and pressure a protostar will born.

Around the star, in this case the Sun, fragments of dust combine until they get a meaningful size (planetesimals). According with chemical distribution on the disk of the future solar system, rocky and iron were closer to the Sun and gasses and ice were in the outer part of disk. That may explain why the inner planets are terrestrial and the outer planets are giant gasses.

. A pilot diverted a fighter jet 20.0 km [S 38.0° E] to avoid thunderstorm, and then flew 60.0 km [S 55.0° W] to get back on track. If the diversion lasted a total of 2.00 minutes, what was the average velocity of the jet during the diversion?

Answers

The average velocity of the jet during the diversion is 518.75 m/s.

Displacement of the pilot

The displacement of the pilot from the starting position is calculated as follows;

d² = 20² + 60² - 2(20)(60) x cos(θ)

where;

θ is the angle between 20 km and 60 km leg of triangle formed from the motion.

θ = (90 - 38) + (90 - 55) = 87⁰

d² = 20² + 60² - 2(20)(60) x cos(87)

d² = 3874.39

d = 62.25 km

Average velocity of the pilot

V = total displacement/total time

where;

time = 2mins = 0.033 hour

V = (62.25 km)/(0.033 hr)

V = 1,867.5 km/hr = 518.75 m/s

Thus, the average velocity of the jet during the diversion is 518.75 m/s.

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A cylindrical metal rod has a resistance R . If both its length and its diameter are tripled, its new resistance will be:

Answers

The new resistance will be 9R

A longer wire should have a higher electrical resistance than a wire with a bigger cross section, and vice versa. The electrical resistance of a wire should also be affected by the material from which it is formed.

The resistance of a wire is R = ρL/A. The volume of a wire is LA. If L increases by 3, then A must decrease by 3 in order for the volume to remain constant. If L increases by 3 and A decreases by 3, then L/A increases by 9 .

Hence the new resistance will be 9R    

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AB = 8x + 3, BC =2x + 7 and AC = 80 Find value of AB and BC When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. caco3(s) 2hcl(aq)cacl2(aq) h2o(l) co2(g) how many grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid? what is y= (x+2) ^2 vertex, axis of symmetry, direction of opening, max or min and y intercept which questions is best suited for researching and finding evidence to support the reason 5Select the correct answer.Which expression is equivalent to the given expression? Assume the denominator does not equal zero.4m5n2mnOA 64m9n3OB. 64m135OC. 12m6n4OD. 12m21n9 what are the hydrogen bonding atoms in melatonin? In your opinion, is the message of the painting warning us to beware of materialism? Why or why not? 4. A triangle has vertices A(4, 2), B(3, 7), and C(4, 5).a) Explain HOW you would draw the median of the triangle from vertex A. Then draw it on the grid provided. B). Calculate the length of the median from C to AB Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minutes. If the river flows at 5 km/hr, how fast can Kelli swim in still water?Choose the most logical value for the variable to represent.Let x = .3m = 159 + 15m = 12m 13m = 189 + 6 15 = 15m 12m two protons are released from rest when they are 0.750 nm apart (a)what is the maximum speed they will reach ? when does this speed occur? (b)what is the maximum acceleration they will achieve?when does this acceleration occur? Which of the following are geometric sequences? This homework assignment is confusing. A store sells 7 different types of envelopes and 6 different types of postage stamps. How many different combinations are tehre to buy an envelope and stamp? Which equation represents a line that passes through (2,-) and has a slope of 3?Oy - 2 = 3(x+2)Oy - 3 = 2(x+1)Oy+==3(x-2)Oy + = = 2(x 3)Save and Exit A bus can reach from Kathmandu to Lumbini in 15 hours when the speed is 40 km per hour. I how many hours it reaches when the speed of the bus is 50 km per hour. Use synthetic division to find the expression for the area of the base of a rectangular prism with height x 4 and volume x3 2x2 17x 36. Given the circle below, find QR. Hi you can help me? pls i dont know What are the responsibilities of an executor? Check all that apply.paying any taxes that are due on the estatetaking inventory of the property and belongingsappraising and distributing the deceased persons assetssettling any debts that are owed by the deceasedinheriting assets named in a will if the first choice cannotacting on someones behalf if he or she becomes sick or injured In 2011, the maximum amount that you could have contributed to your RRSP (Registered Retirement Savings Plan) wasthe lesser of $22,450 or 18% of your earned income from the previous year. How much income do you need to claim a$22,450 contribution in 2011? A yoyo with a mass of m = 150 g is released from rest as shown in the figure.The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is ICM = 1.0110-4 kgm2. 1. Determine the linear acceleration of the yoyo. 2. Determine the angular acceleration of the yoyo.3. What is the weight of the yoyo?4. What is the tension in the rope?5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?