what is the frequency of light that has a wavelength 788 nm in refractive index of light is 1.33

Answers

Answer 1

The frequency of light with a wavelength of 788 nm can be calculated using the formula [tex]f = c/\lambda[/tex], where f represents frequency, c is the speed of light and [tex]\lambda[/tex] is the wavelength. In this case, the refractive index of light is given as 1.33.

To calculate the frequency, we first need to determine the speed of light in the given medium. The speed of light in a medium is related to the speed of light in a vacuum (c) by the equation v = c/n, where v is the speed of light in the medium and n is the refractive index of the medium. Substituting the given refractive index (n = 1.33) into the equation, we find that the speed of light in the medium is approximately [tex]2.26 * 10^8 m/s[/tex].

Next, we can use the formula for frequency to calculate the frequency of light: [tex]f = c/\lambda[/tex]. Substituting the values of c and [tex]\lambda[/tex], we get [tex]f = (2.26 * 10^8 m/s) / (788 *10^-^9 m)[/tex]. Calculating this expression, we find that the frequency of light with a wavelength of 788 nm in a medium with a refractive index of 1.33 is approximately [tex]2.87 * 10^1^4 Hz[/tex].

Learn more about refractive index here:

https://brainly.com/question/30761100

#SPJ11


Related Questions

The height, in feet, of objects launched from a pirate ship's cannon can be modelled by h=-1/5t^2 + 5t + 18 where t is the time in seconds. What is the height of the cannon where the objects are launched from?

Answers

The height of the cannon where the objects are launched from is 18 feet.

The canons of page construction are historical reconstructions, based on careful measurement of extant books and what is known of the mathematics and engineering methods of the time, of manuscript-framework methods that may have been used in Medieval- or Renaissance-era book design to divide a page into pleasing proportions. Since their popularization in the 20th century, these canons have influenced modern-day book design in the ways that page proportions, margins and type areas (print spaces) of books are constructed.

To determine the height of the cannon where the objects are launched from, we need to find the value of "h" when "t" is equal to zero.

Given the equation: h = (-1/5)×t^2 + 5×(t) + 18

Substituting t = 0 into the equation, we have:

h = (-1/5)×(0)^2 + 5(0) + 18

= 0 + 0 + 18

= 18

Therefore, the height of the cannon where the objects are launched from is 18 feet.

To know more about canons:

https://brainly.com/question/14010693

#SPJ4

A contour map has 14 concentric circles, each placed 1/2 centimeters apart. The map's scale indicates 1cm = 10 ft. What is the structure, and what are its dimensions?

Answers

Answer:

B. A hill 70ft tall.

Explanation:

Determine the separation distance between two balloons with charges of +3.6*10^-8 C and -3.2*10^-8 C. They generate an electrical force of -2.2*10^-2 between them.

Answers

Answer:

0.0217 m

Explanation:

Ftom the question,

Applying Coulomb's law

F = kqq'/r²............... Equation 1

Where F = Electric Force, q and q' = First and second charge respectively, r = distance between the charges, k = coulomb's constant.

make r the subeject of the equation

r = √[(kqq')/F]............. Equation 2

Given: q = +3.6×10⁻⁸ C, q' = -3.2×10⁻⁸ C, F = -2.2×10⁻² N

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation

r = √(+3.6×10⁻⁸×-3.2×10⁻⁸×8.98×10⁹/-2.2×10⁻²)

r = √(-103.4489×10⁻⁷/-2.2×10⁻²)

r = √(47.02×10⁻⁵)

r = 21.68×10⁻³

r ≈ 21.7×10⁻³ m.

r ≈ 0.0217 m

Hence the seperation between the two balloons is 0.0217 m

A thin layer of magnesium fluoride (n=1.38) is used to coat a flint glass lens ( n=1.61). (a) What thickness should the magnesium fluoride film have if the reflection of 565 nm light is to be suppressed? Assume that the light is incident at right angles to the film. (b) If it is desired to suppress the reflection of light with a higher frequency, should the coating of magnesium fluoride be made thinner or thicker? Explain.

Answers

(a) The thickness of the magnesium fluoride film should be approximately 120 nm to suppress the reflection of 565 nm light.

(b) To suppress the reflection of light with a higher frequency, the coating of magnesium fluoride should be made thinner.

(a) The condition for suppressing reflection is given by the equation:

2nt = mλ

where n is the refractive index of the film, t is the thickness of the film, m is an integer representing the order of the interference, and λ is the wavelength of light.

For reflection suppression of 565 nm light, we can substitute the given values:

2(1.38)t = λ

2(1.38)t = 565 nm

t = (565 nm) / (2(1.38))

t ≈ 120 nm

Therefore, the thickness of the magnesium fluoride film should be approximately 120 nm to suppress the reflection of 565 nm light.

(b) To suppress the reflection of light with a higher frequency, the coating of magnesium fluoride should be made thinner. This is because higher frequencies correspond to shorter wavelengths. As the wavelength decreases, the required thickness of the film for interference suppression decreases. So, a thinner coating of magnesium fluoride would be needed to achieve reflection suppression for higher-frequency light.

(a) To suppress the reflection of 565 nm light, the magnesium fluoride film should have a thickness of approximately 120 nm.

(b) To suppress the reflection of light with a higher frequency, the coating of magnesium fluoride should be made thinner. This is because higher frequencies correspond to shorter wavelengths, requiring a smaller film thickness for interference suppression.

To know more about reflection visit:

https://brainly.com/question/26494295

#SPJ11

Do convex lens converge or diverge the light rays?

Answers

Answer:

converge

plz mark me as brainliest.

Convex lenses converge

What is the gravitational field value (g) on planet Saturn with a mass of 5.69 X 1026
and an average radius of 6.03 X 107 m?

Answers

It’ll jus add up 2 a weird numeral number

a total electric charge of 5.50 nc is distributed uniformly over the surface of a metal sphere with a radius of 30.0 cm . the potential is zero at a point at infinity.
a. find the value of potentital at 5.50 cm from the center of the sphere.
b. find the value of the potential at 30.0 cm from the center of the sphere.
c. find the value of the potential at 16.0 cm from the center of the sphere.

Answers

a. The potential at 5.50 cm from the center of the sphere is 9.00 x [tex]10^7[/tex] V.

b. The potential at 30.0 cm from the center of the sphere is 1.65 x [tex]10^8[/tex] V.

c. The potential at 16.0 cm from the center of the sphere is 2.47 x [tex]10^8[/tex] V.

To find the value of the potential at different distances from the center of the sphere, we can use the equation for the electric potential of a uniformly charged sphere.

Given:

Total electric charge (Q) = 5.50 nC

Radius of the sphere (R) = 30.0 cm = 0.30 m

a) To find the potential at 5.50 cm from the center of the sphere:

Distance from the center of the sphere (r) = 5.50 cm = 0.055 m

The equation for the electric potential of a uniformly charged sphere is:

V = k × Q / r

where V is the potential, k is the Coulomb's constant (8.99 x [tex]10^9[/tex] N m²/C²), Q is the total charge, and r is the distance from the center of the sphere.

Substituting the given values into the equation:

V = (8.99 x [tex]10^9[/tex] N m²/C²) × (5.50 x [tex]10^{-9[/tex] C) / 0.055 m

Calculating the value:

V = 9.00 x [tex]10^7[/tex] V

Therefore, the potential at 5.50 cm from the center of the sphere is 9.00 x [tex]10^7[/tex] V.

b) To find the potential at 30.0 cm from the center of the sphere:

Distance from the center of the sphere (r) = 30.0 cm = 0.30 m

Using the same equation as above:

V = (8.99 x [tex]10^9[/tex] N m²/C²) × (5.50 x [tex]10^{-9[/tex] C) / 0.30 m

Calculating the value:

V = 1.65 x [tex]10^8[/tex] V

Therefore, the potential at 30.0 cm from the center of the sphere is 1.65 x [tex]10^8[/tex] V.

c) To find the potential at 16.0 cm from the center of the sphere:

Distance from the center of the sphere (r) = 16.0 cm = 0.16 m

Using the same equation as above:

V = (8.99 x [tex]10^9[/tex] N m²/C²) × (5.50 x [tex]10^{-9[/tex] C) / 0.16 m

Calculating the value:

V = 2.47 x [tex]10^8[/tex] V

Therefore, the potential at 16.0 cm from the center of the sphere is 2.47 x [tex]10^8[/tex] V.

Learn more about the electric charge at

https://brainly.com/question/30845773

#SPJ4

I neeed help im so comfused Points Possible: 1, Points Correct: 0 Which group of numbers is listed from greatest to least? -3, -1, 0, 2, 7 9, 7, 6, -5, -4 8, -6, 5, -4, 1 -3, -4, -7, -8, -9

Answers

The groups aren't well formatted ;

The groups are ;

(-3, -1, 0, 2, 7) ; (9, 7, 6, -5, -4) ; (8, -6, 5, -4, 1) ; (-3, -4, -7, -8, -9)

Answer:

(-3, -4, -7, -8, -9)

Explanation:

Given the following group of numbers :

Evaluating each group of values for which is correctly arranged from greatest to least.

(-3, -1, 0, 2, 7) : - 1 is greater than - 3 (the group isn't arranged from greatest to least)

(9, 7, 6, -5, -4) : - 4 is greater than - 5 ; hence, the group isn't arranged from greatest to least

(8, -6, 5, -4, 1) : 5 is greater than - 6 ; hence, the group isn't arranged from greatest to least

(-3, -4, -7, -8, -9) ; the group of numbers here is arranged from greatest to least ;

(-3 > -4 > -7 > -8 > -9) ; hence, the correct group

Question:
Define Force​

Answers

Force is push or pull....

thank you

What is the energy of the 30 kg skateboarder at 2 m off the ground traveling at 3 m/s?

Answers

1) The kinetic energy of an object is given by:

where m is the object's mass and v its speed.

By using this equation, we find the initial kinetic energy of the skateboarder:

and the final kinetic energy as well:


So, her change in kinetic energy is


2) The work-energy theorem states that the work done to increase the speed of an object is equal to the variation of kinetic energy of the object:

Therefore, the work done by the skateboarder is

at the instant shown, the spring is undeformed. determine the change in potential energy if the 20 kg disk (k_g = 0.5 m) rolls 2 revolutions without slipping.

Answers

The change in potential energy of the spring system is 15.6 x 10³J.

Mass of the disc, m = 20 kg

Velocity of the disc, v = 3 m/s

Spring constant of the spring, k = 200 N/m

Angular displacement of the disc, x = 2 revolutions = 2 x 2π = 4π radians

The potential energy that is stored when an elastic object is stretched or compressed by an external force, such as the stretching of a spring, is known as elastic potential energy. It is equivalent to the effort required to extend the spring, which is dependent on both the length of the stretch and the spring constant k.

The expression for the elastic potential energy of the spring is given by,

PE = 1/2 kx²

PE = 1/2 x 200 x (4π)²

PE = 1.57 x 10⁴J

The kinetic energy of the disc is given by,

KE = 1/2 mv²

KE = 1/2 x 20 x 3²

KE = 90 J

Therefore, the change in potential energy is,

E = 1.57 x 10⁴- 90

E = 15.6 x 10³J

To learn more about potential energy, click:

https://brainly.com/question/29311518

#SPJ1

how many nucleons does sulphur have​

Answers

Answer:

32

Explanation:

Answer:

32

Explanation:

Sulfur has 16 protons and 16 neutrons. The atomic number is roughly 32. Therefore, 16 + 16 = 32 nucleons.  

Two 5.0 - cm-diameter rings are facing each other 5.0 cm apart. Each is charged to +3.0nC. Part A What is the electric potential at the center of one of the rings? Express your answer with the appropriate units.

Answers

To find the electric potential at the center of one of the rings, we can use the formula for the electric potential due to a charged ring: V = k * Q / r

where V is the electric potential, k is the Coulomb's constant (8.99 × 10^9 N m²/C²), Q is the charge of the ring, and r is the distance from the center of the ring. In this case, the charge of each ring is +3.0 nC (nanocoulombs) = 3.0 × 10^-9 C, and the distance from the center of the ring is half of the diameter, which is 5.0 cm = 0.05 m. Plugging in the values, we have: V = (8.99 × 10^9 N m²/C²) * (3.0 × 10^-9 C) / 0.05 m. Calculating this expression will give us the electric potential at the center of one of the rings.

To learn more about potential, https://brainly.com/question/32307288

#SPJ11

a 100 mm long line is parallel to and 40 mm above the h.p. its two ends are 25 mm and 50 mm in front of the v.p. respectively. draw its projections and find its inclination with the v.p.

Answers

The line, 100 mm in length, is parallel to and 40 mm above the h.p. Its ends, positioned 25 mm and 50 mm in front of the v.p., are connected to form projections. The inclination with the v.p. is 48.59°.

Determine how to find the projections of the line?

To draw the projections of the line, we start by drawing the plan view (H₁) and the front view (V₁).

In the plan view (H₁), we draw a horizontal line of 100 mm length. The line is parallel to the horizontal plane (h.p.), so it remains at the same height as the h.p.

In the front view (V₁), we draw a vertical line to represent the height above the h.p. Since the line is 40 mm above the h.p., we draw a line 40 mm long above the ground line. Then, we draw the line segments representing the ends of the line.

The first end is 25 mm in front of the vertical plane (v.p.), and the second end is 50 mm in front of the v.p. We connect these ends to the top of the vertical line to complete the front view.

To find the inclination of the line with the v.p., we use the right triangle formed by the height of the line (40 mm) and the distance from the v.p. to the second end of the line (50 mm). We can calculate the inclination angle using the tangent function:

tan(θ) = opposite/adjacent = 40/50

Solving for θ, we find:

θ = tan^(-1)(40/50) = 48.59°

To know more about tangent function, refer here:

https://brainly.com/question/30162652#

#SPJ4

What statement about energy transfer in a wave is true?

Answers

Answer:

Energy moves between the particle of the medium.

Explanation:

Two identical planets orbit a star in concentric circular orbits in the star's equatorial plane. Of the two, the planet that is farther from the star must have a. the smaller period. b the greater period. c. the smaller gravitational mass. d. the larger gravitational mass. e the larger universal gravitational constant.

Answers

Two identical planets orbit a star in concentric circular orbits in the star's equatorial plane. The planet that is farther from the star must have a greater period than the planet that is closer to the star. The correct answer is option(b).

The period of the planet is directly proportional to the cube of its distance from the star. As a result, when planets are equidistant from a star, their periods will be equal.As a result, the planet that is farther from the star must have a greater period than the planet that is closer to the star.

A planet's gravitational mass is not influenced by the planet's distance from the star, so alternatives c and d can be ruled out. Similarly, the planet's universal gravitational constant is not affected by the planet's distance from the star, so option e can also be ruled out. The planet's period, on the other hand, is influenced by the distance from the star and the planet's mass. As a result, the option a can be ruled out.

To know more about planets refer to:

https://brainly.com/question/14323720

#SPJ11

Find a power series representation for the function. f(x) = ln (7 - x) f(x) = ln (7) + sigma^infinity_n = 0 Determine the radius of convergence, R.

Answers

The power series representation for the function f(x) = ln(7 - x) is f(x) = ln(7) - ∑(n=0 to ∞) [(x - 7)^n / (n+1)].

To find the power series representation, we can use the Taylor series expansion of the natural logarithm function ln(1 + x):

ln(1 + x) = x - (x^2 / 2) + (x^3 / 3) - (x^4 / 4) + ...

In this case, we have the function f(x) = ln(7 - x), which can be rewritten as f(x) = ln(1 + (x - 7)).

Using the Taylor series expansion, we substitute (x - 7) in place of x:

f(x) = (x - 7) - [(x - 7)^2 / 2] + [(x - 7)^3 / 3] - [(x - 7)^4 / 4] + ...

Simplifying, we can write this as:

f(x) = -∑(n=0 to ∞) [(x - 7)^n / (n+1)]

Next, we add ln(7) to the series to account for the constant term:

f(x) = ln(7) - ∑(n=0 to ∞) [(x - 7)^n / (n+1)]

The radius of convergence, R, can be determined by using the ratio test. The ratio test states that if the limit of the absolute value of the ratio of consecutive terms in the series is L, then the series converges absolutely when L < 1 and diverges when L > 1.

In this case, we take the absolute value of the terms in the series and calculate the limit:

lim(n→∞) |(x - 7)^(n+1) / [(n+2)(x - 7)^n]|

Simplifying and taking the limit, we find:

lim(n→∞) |x - 7| / (n + 2)

Since this limit approaches zero for any value of x, the series converges for all values of x. Therefore, the radius of convergence, R, is infinity.

The power series representation for the function f(x) = ln(7 - x) is f(x) = ln(7) - ∑(n=0 to ∞) [(x - 7)^n / (n+1)]. The series converges for all values of x, indicating that the radius of convergence, R, is infinity.

To know more about Power Series, visit

https://brainly.com/question/32654795

#SPJ11

In context of nepal it is better to use energy like solar power .why?

Answers

Answer:

Nepal is one of the least developed countries. Solar power is well-founded than electricity. It's better to use solar power because it's a clean resource, the sun provides more energy than we will ever need.

Explanation:

Conclusion: Suggest an equation relating Felect, q1, q2 and d of the form Felect = k•... where k is a proportionality constant (no need to determine its value). Place the three variables q1, q2 and d on the right side of the equation in a numerator or a denominator; use a power if needed. Your equation should be consistent with your claims made in Challenge #1 and Challenge #2. *I already solved the rest of the worksheet, I only need the conclusion.*

Answers

Answer:

[tex]F_{elect} = \frac{kq_1q_2}{d^2}[/tex]

Explanation:

Consider the given variables:

Felect = Electrostatic Force between charged particles

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

d = distance between the charges

The relationship among these variables is given by the Coulomb's Law:

[tex]F_{elect} = \frac{kq_1q_2}{d^2}[/tex]

This is the relationship that contains k, q₁, q₂, d on the right-hand side and Felect on the left-hand side.

Why does grass look black under the moonlight?

Answers

Answer:

The moon doesn’t have light of its own, the moon lights up because of the sun. So at night, as the light of the sun doesn't reach the grass directly because of the moon, it doesnt reflect any color off the grass, and so our eyes detect grass as black.

Explanation:

Sun appears white, but it is made up of the colors: red, orange, yellow, green, blue, indigo, and violet. When white light hits an object, it absorbs some colors and reflect the others. Grass appears green because it absorbs all the wavelengths except green. Green is reflected off the grass, so we see grass as green.

The ancient Egyptians build their pyramids using a ramp to move the heavy blocks up. The length of the ramp was 25m and the height was 10m the weight of the block was 250kg and the effort weight is 180kg. What is the efficiency of the inclined plane

Answers

Answer:

Efficiency of the inclined plane is 56%

Explanation:

efficiency = (work output / work input) x 100%

efficiency = ([load force x load distance] x [effort force x effort distance]) x 100%

efficiency = (250 kg x 10 m) / (180 kg x 25 m) x 100%

efficiency = (2500kg/m) / (4500kg/m) x 100%

efficiency = 0.555 = 0.56 x 100%

efficiency = 56%

how many liters of hydrogen gas are formed from the complete reaction of 1.21 mol of c ? assume that the hydrogen gas is collected at a pressure of 1.0 atm and a temperature of 319 k .

Answers

The complete reaction of 1.21 mol of carbon (C) produces 2.42 mol of hydrogen gas (H2), which is equivalent to approximately 54.5 liters.

The balanced chemical equation for the reaction between carbon and hydrogen gas is:

[tex]C + 2H_2 -- > CH_4[/tex]

From the balanced equation, we can see that for every 1 mole of carbon (C), 2 moles of hydrogen gas (H2) are required to form 1 mole of methane (CH4). Since the reaction is complete, all the carbon will be consumed, and therefore the moles of hydrogen gas produced will be twice the moles of carbon.

Given that we have 1.21 mol of carbon, we can calculate the moles of hydrogen gas produced by multiplying the moles of carbon by 2:

2.42 mol H2 = 1.21 mol C × 2 mol H2 / 1 mol C

To convert the moles of hydrogen gas to liters, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation to solve for V, we have:

V = (nRT) / P

Substituting the given values into the equation and solving for V, we get:

V = (2.42 mol H2 × 0.0821 L·atm/mol·K × 319 K) / 1.0 atm

V ≈ 54.5 liters

Therefore, approximately 54.5 liters of hydrogen gas are formed from the complete reaction of 1.21 mol of carbon.

Learn more about hydrogen gas here:

https://brainly.com/question/14355155

#SPJ11

What is the height of the image? Round the answer
the nearest whole number.
Characteristic
Value
cm
What type of mirror most likely formed this image?
Focal length
13 cm
Distance of object from mirror
8 cm
Distance of image from mirror
-21 cm
Height of object
4 cm

Answers

Answer:

11 cm and concave

Explanation:

edge 2021

Answer:

it is -21, The top part is correct it is only the second part this is the first part.

Explanation:

A steel tank is completely filled with 1.60 m3 of ethanol when both the tank and the ethanol are at a temperature of 33.0 ∘C .
Part A
When the tank and its contents have cooled to 20.0 ∘C, what additional volume of ethanol can be put into the tank?

Answers

The additional volume of ethanol that can be put into the tank is 0.0136 m³.

The given informations are,

The steel tank is completely filled with 1.60 m³ of ethanol when both the tank and the ethanol are at a temperature of 33.0 °C. And we have to find what additional volume of ethanol can be put into the tank when the tank and its contents have cooled to 20.0 °C.

Part A

When the tank and its contents have cooled to 20.0 °C, the volume of ethanol decreases due to the decrease in temperature.

Let's assume the volume of ethanol at 33.0 °C be V1 and at 20.0 °C be V2 and coefficient of cubical expansion of ethanol be α.

From the temperature coefficients of cubical expansion, we can say that the volume of ethanol decreases with decrease in temperature.

So, the additional volume of ethanol which can be put into the tank is,

Additional volume = V1 - V2

The volume of ethanol changes due to the change in temperature,

V2 = V1 / [1 + α (T2 - T1)]

where T1 and T2 are the initial and final temperatures of the ethanol in degree Celsius.

The coefficient of cubical expansion of ethanol, α = 1.12 × 10^-3 / °C.

Now, let's substitute the given values in the above equation:

V2 = 1.60 m³ / [1 + (1.12 × 10^-3 / °C) × (33.0 °C - 20.0 °C)]

V2 = 1.5864 m³

Therefore, the additional volume of ethanol that can be put into the tank when the tank and its contents have cooled to 20.0 °C is,

Additional volume = V1 - V2= 1.60 m³ - 1.5864 m³

                              = 0.0136 m³

Hence, the additional volume of ethanol that can be put into the tank is 0.0136 m³.

Learn more about the ethanol:

brainly.com/question/31742303

#SPJ11

A bumblebee can sense electric fields as the fields bend hairs on its body. Bumblebees have been conclusively shown to detect an electric field of 60 N/C . Suppose a bumblebee has a charge of 21 pC.
How far away could another bumblebee detect its presence?

Answers

Another bumblebee could detect the presence of the charged bumblebee from a distance of approximately 3.5 meters.

To determine the distance at which another bumblebee could detect the presence of the charged bumblebee, we can use Coulomb's law, which states that the electric force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for the electric force between two charges is given by:

F = (k * q1 * q2) / r^2

where F is the electric force, k is the electrostatic constant (approximately 9 × 10^9 N·m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.

Given that the electric field detected by the bumblebee is 60 N/C, we can relate the electric field to the electric force using the equation:

E = F / q

where E is the electric field and q is the charge.

Rewriting the equation to solve for the electric force:

F = E * q

Substituting the given values:

F = (60 N/C) * (21 × 10^-12 C)

Simplifying:

F = 1.26 × 10^-9 N

Rearranging the Coulomb's law equation to solve for the distance:

r = sqrt((k * q1 * q2) / F)

Substituting the values into the equation:

r = sqrt((9 × 10^9 N·m^2/C^2 * (21 × 10^-12 C)^2) / (1.26 × 10^-9 N))

Simplifying:

r ≈ 3.5 meters

Therefore, another bumblebee could detect the presence of the charged bumblebee from a distance of approximately 3.5 meters.

Another bumblebee could detect the presence of the charged bumblebee from a distance of approximately 3.5 meters. This is based on the ability of bumblebees to sense electric fields and the known electric field strength and charge of the bumblebee in question.

To know more about Coulomb Law visit:

https://brainly.com/question/506926

#SPJ11

a 100 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.0830 m/s. how much work must be done on the hoop to stop it?

Answers

The work done on the hoop to stop it is 0.344 Joules.

What is work done?

Work is defined as the transfer of energy that occurs when a force is applied to an object, causing it to move in the direction of the force. Work is the product of the force applied to an object and the displacement of the object in the direction of the force.

Given:

Mass of the hoop (M) = 100 kg

Speed of the center of mass (v) = 0.0830 m/s

Radius of the hoop (R) = ?

To find the radius (R) of the hoop, we can use the relationship between linear and angular velocity:

v = R * ω

Rearranging the equation, we get:

R = v / ω

We need to find the angular velocity (ω) of the hoop. Using the relationship between linear velocity and angular velocity, we have:

ω = v / R

Substituting the given values, we can calculate the angular velocity:

ω = 0.0830 m/s / R

Next, we can calculate the moment of inertia (I) of the hoop:

I = MR^2

Substituting the mass and radius, we get:

I = 100 kg * R^2

Now, we can calculate the initial kinetic energy (KE_initial) of the hoop:

KE_initial = (1/2) * I * ω^2

Substituting the values, we have:

KE_initial = (1/2) * (100 kg * R^2) * (0.0830 m/s / R)^2

Simplifying the equation, we get:

KE_initial = (1/2) * 100 kg * 0.0830^2 m^2/s^2

Finally, the work done on the hoop to stop it is equal to the initial kinetic energy:

Work = KE_initial

Substituting the values, we have:

Work = (1/2) * 100 kg * 0.0830^2 m^2/s^2

Calculating the value, we find:

Work ≈ 0.344 J

Therefore, the work done on the hoop to stop it is 0.344 Joules.

To learn more about work done,

https://brainly.com/question/21854305

#SPJ4

3 Which organisms survive well on volcanic islands?
1. bacteria
2. birds
3. plants
4. large animals

Answers

plants

i hope its right and have a nice day

Answer:

number 1

Explanation:

An entertainer pulls a table cloth off a table leaving behind the plates and sliverware undisturbed is an example of
A.
the law of balanced forces
B.
Newton's second law
C.
Newton's third law
D.
Newton's first law

Answers

Answer:

d.) Newton's first law

Explanation:

This is also called the law of inertia, which means that an object in motion will not stop unless a force is acted upon it, and vice versa. Try this out with a piece of paper and a quarter. Pull the paper from under the quarter slightly quick, and the quarter will stay on the table. Hope i helped you.

a source emits monochromatic light of wavelength 549 nm in air. when the light passes through a liquid, its wavelength reduces to 433 nm. What is the liquid's index of refraction?

Answers

A source emits monochromatic light of wavelength 549 nm in air. when the light passes through a liquid, its wavelength reduces to 433 nm, the liquid's index of refraction is approximately 1.269.

The index of refraction (n) of a medium can be calculated using the formula

n = λair / λmedium

Where λair is the wavelength of light in air and λmedium is the wavelength of light in the medium.

Given:

λair = 549 nm

λmedium = 433 nm

Substituting these values into the formula, we get

n = 549 nm / 433 nm

Simplifying the calculation

n = 1.269

Therefore, the liquid's index of refraction is approximately 1.269.

To know more about index of refraction here

https://brainly.com/question/14191704

#SPJ4

Pressure is ______________ to the force applied.



inversely proportional



directly proportional



not related

Answers

Explanation:

inversely proportional

Answer:

directly proportional to force applied

Other Questions
Some say the value is driven entirely by feelings. Do you agree or disagree?Is the valuation of a scenario in risk assessment objective or subjective?Define the term "disutility." Is disutility an absolute or relative value?Discuss the connection between value and the "asset" part of the security context. "Pfizer could, he says, have made way more billions. But wewould stay in history as we didnt offer the world something. Now,I feel way better than, beyond any doubt, we didnt try to profi Milo Company manufactures beach umbrellas. The company is preparing detailed budgets for the third quarter and has assembled the following information to assist in the budget preparation:The Marketing Department has estimated sales as follows for the remainder of the year (in units):July 36,500 October 26,500August 83,000 November 13,000September 52,000 December 13,500The selling price of the beach umbrellas is $10 per unit.All sales are on account. Based on past experience, sales are collected in the following pattern:30% in the month of sale65% in the month following sale5% uncollectibleSales for June totaled $320,000.The company maintains finished goods inventories equal to 15% of the following months sales. This requirement will be met at the end of June.Each beach umbrella requires 4 feet of Gilden, a material that is sometimes hard to acquire. Therefore, the company requires that the ending inventory of Gilden be equal to 50% of the following months production needs. The inventory of Gilden on hand at the beginning and end of the quarter will be:June 30 86,950 feetSeptember 30 ? feetGilden costs $0.80 per foot. One-half of a months purchases of Gilden is paid for in the month of purchase; the remainder is paid for in the following month. The accounts payable on July 1 for purchases of Gilden during June will be $60,920.Required:1. Calculate the estimated sales, by month and in total, for the third quarter.2. Calculate the expected cash collections, by month and in total, for the third quarter.3. Calculate the estimated quantity of beach umbrellas that need to be produced in July, August, September, and October.4. Calculate the quantity of Gilden (in feet) that needs to be purchased by month and in total, for the third quarter.5. Calculate the cost of the raw material (Gilden) purchases by month and in total, for the third quarter.6. Calculate the expected cash disbursements for raw material (Gilden) purchases, by month and in total, for the third quarter.Calculate the quantity of Gilden (in feet) that needs to be purchased by month and in total, for the third quarter. Calculate the cost of the raw material (Gilden) purchases by month and in total, for the third quarter. (Round your Unit cost of raw materials to 2 decimal places.)Calculate the estimated quantity of beach umbrellas that need to be produced in July, August, September, and October.July August September OctoberRequired production in units 43,475 78,350 48,175 24,475July August September QuarterTotal units of raw materials to be purchased 253,050 Cost of raw materials to be purchased $202,440 Calculate the expected cash disbursements for raw material (Gilden) purchases, by month and in total, for the third quarter.July August September QuarterTotal cash disbursements (a)Use the standard reductionpotentials to calculate the standardfree-energy change, G0, and theequilibrium constant, K, at 298 Kfor the reaction4 Ag(s) + O2(g) + 4 H+(aq) 4 Ag+(aq) + 2 H2O(l)(b)Suppose the reaction in part(a) is written2 Ag(s) + O2(g) + 2 H+(aq) 2 Ag+(aq) + H2O(l)What are the values of E0, G0, and Kwhen the reaction is written in this way? a quadratic equation in standard form is written ax2 = bx c, where a, b, and c are real numbers and a is not zero. True or False which type of real option allows a firm to postpone a project until it can gather more information? a. Investment timing option b. Flexibility option c. Growth option d. Abandonment option b) rock b hits the ground at time tb. derive an equation for the time ta it takes rock a to hit the ground in terms of v0, tb, and physical constants, as appropriate. Given the following data: E=Y105 = $1.00 Et+1=Y90 = $1.00 (one year later) Japan = 12% annually lus. = 15% annually Calculate the future value of a $1,000 investment. If the $1000 is invested in the U.S., the future value is $ 1150. (Round your response to two decimal places.) If the $1000 is invested in Japan (and repatriated back to dollars), the future value is $. (Round your response to two decimal places.) given that f(x)=x5g(x) g(2)=3 g(2)=4, determine f(2) provide your answer below: Write an essay using Christian world view about payrollmanagement. supine arms in straps lower and lift is done in which plane of motion? An $96,000 investment earned a 5.0% rate of simple interest from December 5, 2019, to May 6, 2020. How much interest was earned? (Do not round intermediate calculations and round your final answer to 2 decimal places.) Cleavage of APP at which of the following proteolytic cleavage sites produces A-beta40 and A-beta42 (choose all options that apply)DeltaAlphaBetaGamma in his first four years of coaching football, Coach Delgato's team won 5 games the first year, 10 games the second year, 8 games the third year, and 7 games the fourth year. How many games does the team need to win the fifth year to have an average of 8 wins per year? Which three of these story details can help a reader identify the theme? the author's backgroundrepetition of ideasthe amount of dialoguethe interaction of story elementsthe main conflict If Francois spends all of his time cooking, he is able to cook 40 hamburgers or 60 hotdogs an hour. What is his opportunity cost of cooking 1 hamburger? hotdogs What is his opportunity cost of cooking 1 hotdog? hamburgers Question 7 4 pts If Gerta spends all day. her time washing vehicles, she is able to wash 15 cars or 25 motorcycles each What is her opportunity cost of washing 1 car? motorcycles What is her opportunity cost of washing 1 motorcycle? cars Supplier Reliability: Ingrid shows data for total deliveries per year and on-time deliveries per year. What is an actionable metric that Ingrid could develop from these two pieces of data? That is, what is a metric that could be measured on a periodic basis (monthly, quarterly, annually) to show if the supplier is improving or not?Supplier Manageability: Ingrid is using distance from headquarters as a metric for supplier manageability. Do you think that distance from headquarters is a good metric for supplier manageability? In other words, does distance from headquarters measure what is important to FarmCo in a way that shows whether the supplier is improving or not? How might suppliers respond to orders (manage lead times) even though they are located a far distance?Supplier Importance: Ingrid is measuring supplier importance based on the number of product variants using parts from a supplier. Is this really a scorecard measure (ie, a measure of the suppliers performance) or is this more like a dimension that could be used in the Supplier Segmentation Matrix (Kraljic Matrix)? In other words, as currently measured, is supplier importance something suppliers can actually do well at? Or improve on? Explain why or why not?Supplier Dispensability: We will discuss a similar metric (recovery time) when we discuss supply chain risk. If a supplier has a low supplier dispensability rating, would this be something that a supplier would need to take action on? Or would it make more sense that FarmCo would take action here? Again, the question here is should supplier dispensability actually be on a performance scorecard? Or should it be part of a broader discussion about how FarmCo manages risk in its supply chain?Describe the main issue that FarmCo is having in this case. On January 1, 2017, Beyonce Company leased a music studio from Simon company on a 5-year lease term at P150,000 annual rental payable in advance. Simon offered Beyonce the option to purchase the asset at a bargain price of P200,000 at the end of the lease contract. The estimated economic life of the asset is 15 years, and its estimated residual value is P4,000. the interest implicit in the lease is 12%. (Please round off present value factors to 4 decimal places.) At the end of the lease term, Beyonce did not purchase the right of use asset. How much loss on failure to exercise the bargain purchase option is to be reported by Beyonce in its 2021 financial statement? 9. A pen costs $1.85. It costs $0.47 more than a marker. Jon bought 2 pens and a marker. How much change did he get from a ten-dollar bill? Cost of pen Cost of marker Cost of marker and 2pens Change from a 10 dollar bill what is the most influential source of bias in a mental status examination