The force of gravity between the two cars is 1.14 x 10⁻⁷ N.
What is force of gravity?
The force of attraction on a body by earth or force of gravity is defined the gravitational pull of the earth on every object on earth.
Mathematically, the gravitational force between two object is given by;
F = Gm₁m₂/r²
where;
G is universal gravitation constantm is mass of the objectsr is the distance of separation of the objects.F = (6.67 x 10⁻¹¹ x 1039 x 1039)/(25.15)²
F = 1.14 x 10⁻⁷ N
Thus, we can conclude that the force of attraction between two objects in the universe increases with decrease in the distance of separation.
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The attached doc is my question.
Gravitational, elastic, and chemical energy are forms of potential energy.
Both kinetic and potsential energy increases with mass.
Ball on the edge of the cliff
A ball is thrown up into the air and rises until it begins to fall
Can be transformed into other form of energy.
When graphic scores first evolved, what were they often used in combination with?
A. Traditional music notation
B. Numerical systems
C. Bar charts
When graphic scores first evolved, what were they often used in combination with (A) Traditional music notation .
A graphic score makes use of uses images, shapes and snap shots rather than notes. Composers use image scores because they allow them to explicit musical ideas that couldn't be described by way of traditional notation.
They advanced a new manner of visualizing song called image scores or picture notation. Photo rankings frequently appearance very specific to traditional musical rankings. In preference to strains and dots on a musical stave, photograph ratings can use all sorts of special pictures and logos to tell the performer what to play.
Graphic notation in its present day shape first appeared in the 1950s as an evolution of movement of Indeterminacy as pioneered by using John Cage.
Divide a large piece of paper into four sections and draw a motif in every. Ensure the motifs are as contrasted as possible. The score works with someone to factor on the sections. whilst they're touching a segment, a corresponding sound is played.
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A plastic rod is rubbed with wool, producing a distribution of positive and negative surplus charge that is concentrated in two locations on the rod and two on the wool. This distribution can be approximated as two pairs of small balls of charge as shown in The distance d is 30.0 mm, and the magnitude of the charge on each ball is 6.00 μC . The initial state of the system is the neutral rod and wool before the rubbing.
If 34.0 J of work went into thermal energy as the rod and wool heated up, how much work was done on the system?
The work that was done on the system is 326 J.
What is the work done in moving the charge?
The work done in moving the charge over the distance is calculated as follows;
W = Fr
W = (kq²)/r
where;
k is Coulomb's constantq is magnitude of the charger is the distance of the chargeW is the work doneF is the electric forceW = (9 x 10⁹) x (6 x 10⁻⁶)² / (30 x 10⁻³)
W = 360 J
The total work done on the system is calculated as follows;
Wt = Wc - We
where;
Wt is the total work doneWc is the work done in moving the chargeWe is the work that went into thermal energyWt = 360 J - 34 J
Wt = 326 J
Thus, we can conclude that the net work done on the system is obtained by subtracting the work done that went into thermal energy from the work done in moving the charge.
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The scientific method is?
A) A way to use scientific measurements
B) A group of logical science questions
C) A method used to answer scientific question
D) A series of random science discoveries
How would the intensity of a sound wave change if you were to move 2 time closer to the source?
The intensity increased by a factor of 4 if the distance from the source dropped by a factor of 2.
Does distance affect intensity?Light intensity and distance are inversely correlated; as the distance grows, light intensity decreases.
What is the name for a sound wave's intensity?Sound intensity, also known as acoustic intensity, is the force carried by sound waves per unit area in a direction perpendicular to that region. The watt per square meter (W/m2) is the SI unit of intensity.
How can you gauge intensity?I = P/A, where I stands for intensity, P for power, and A for area, is the standard formula for intensity.
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A proton is at the origin and an electron is at the point x = 0.36 nm , y = 0.40 nm
Find the electric force on the proton.
The electric force on the proton is 7.9 x 10⁻²² N.
What is electric force?
Electric force is defined as the force between two charged objects. According Coulombs law, this force is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.
F = kq₁q₂/r²
where;
q₁ is charge of protonq₂ is charge of electronr is the distance between the chargesK is Coulomb's constantThe distance between the two charges is calculated as follows;
r = √(y² + x²)
r = √(0.36² + 0.4²)
r = 0.54 mm
F = (9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹) / (0.54 x 10⁻³)²
F = 7.9 x 10⁻²² N
Thus we can conclude that a proton is at the origin and an electron is at the point x = 0.36 nm , y = 0.40 nm will experience a force of 7.9 x 10⁻²² N.
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A stuntman drives a car with a mass of 1800 kg on a drawbridge. The car
accelerates resulting from a constant force of 8200 N. While he is driving, the
drawbridge is raised to an incline of 30°. What is the car's new acceleration
on this incline, ignoring the force due to air resistance? (Recall that g = 9.8
m/s²)
30⁰
Force accelerating car
Weight
A. 0.3 m/s²
B. 1.2 m/s2
C. -2.5 m/s²
D. 4.0 m/s²
Halp
The acceleration of the car is now found to be 0.3 m/s². Option A
What is the acceleration?We have to recall that the acceleration is the rate at which the velocity is changed with respect to time. We know that we must take into account that the car is now moving on an inclined plane as we can see in the image attached to the question above for our scrutiny.
Now;
The force that pushes the car forward is the 8200 N force that have been stated in the question.
The component of the weight of the car that can be seen to be effective along the inclined plane is; 1800 Kg * 9.8 m/s^2 * sin 30
= 8820 N
Then we know that;
F - Wp = ma
F = constant force
Wp = effective component
m = mass
a = acceleration
Then;
a = F - Wp/m
a = 8200 N - 8820 N/1800 kg
a = 0.3 m/s²
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explain why water comes out more slowly from a tap on the first floor than from a tap on the ground floor
Answer:
It is because of the pressure exerted by water. As the depth of water increases, the pressure also increases.
Explanation:
If you dropped a ball on the surface of Katar, what rate would it accelerate toward the ground
Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point travelling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.
The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using metres per second squared (m/s²), you can gauge how quickly velocity varies.
Acceleration due to gravity on earth = 9.8 m/s²
Therefore, the rate at which the ball will fall on the Katar is 9.8m/s²
Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.
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An object travels 5m/s in 2 seconds. How far did it travel?
Answer:
3
Explanation:
because half I think is the answer
Answer:
10 m
Explanation:
5 m/s * 2 s = 10 meters ( see how the ' s ' cancels out?)
What is the period of a wave traveling at a rate of .100 Hz?
The period of a wave traveling at a rate of 0.100 Hz is 10 seconds.
How to calculate period?Period in physics is the time required for one complete cycle of vibration to pass a given point. The period is denoted by T and is measured by seconds (s).
The period of a wave and the frequency are inversely related to one another i.e. as the frequency of a wave increases, the period of the wave decreases.
The time it takes for one complete vibration is called the period (T). For example, if the period of a vibration is 0.1 second (it means one vibration takes 0.1 second), the frequency of the vibration is 10 vibrations per second or 10 hertz
The relationship between them can be given in an equation as follows:
T = 1/f
According to this question, a wave is traveling at a rate of 0.100 Hz. The period can be calculated as follows:
T = 1/0.100
T = 10s
Therefore, the period of a wave traveling at a rate of 0.100 Hz is 10 seconds.
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A piston releases 18 J of heat into its surroundings while expanding from0.0002 m2 to 0.0006 m at a constant pressure of 1.0 * 105 Pa. What are thecorrect values for heat and work for the piston?A. Q = -18 J, W = +40 JB. Q = +18 J, W = +40 JC. Q = +18 J, W = -40 JD. Q = -18 J, W = -40 J
It's important to know that when a system releases heat to the surroundings, the net value of heat is negative by convention, it's exothermic.
On the other hand, when a system does work then the work done is negative, that is, the system is exerting work.
Therefore, the correct answer is D.beginning with earth summarize the structure of the universe
Beginning with earth, the structure of the universe is Earth ← Planetary system ← Galaxy ← Universe.
An universe is made up of billons of galaxies. A galaxy is made up of thousands of planetary systems. A planet always orbit a star. In a planetary system there may be there is one planet orbiting the star or a hundreds of planets orbiting the star.
From the point of Earth, Earth is planet orbiting a star called as Sun. Hence the name of our planetary system was called a solar system. The galaxy in which our solar system is present is called as Milky way galaxy.
Therefore, beginning with earth, the structure of the universe is Earth ← Planetary system ← Galaxy ← Universe.
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How much work is done by the force if the object moves from x = 0.15 m to x = 0.60 m ?
The work done by the force if the object moves from x = 0.15 m to x = 0.60 m is 0.24 J
What is work done by a force?The work done by a force is defined as the product of force and distance traveled.
Work done = force * distanceWork done between 0.15 m to 0.25 m = 0.6 * (0.25 - 0.15)
Work done between 0.15 m to 0.25 m = 0.6 * (0.10)
Work done between 0.15 m to 0.25 m = 0.06 J
Work done between 0.25 m to 0.50 m = 0.4 * (0.50 - 0.25)
Work done between 0.25 m to 0.50 m = 0.4 * (0.25)
Work done between 0.25 m to 0.50 m = 0.1 J
Work done between 0.50 m to 0.60 m = 0.8 * (0.60 - 0.50)
Work done between 0.50 m to 0.60 m = 0.8 * (0.10)
Work done between 0.50 m to 0.60 m = 0.08 J
Total work done = 0.06 + 0.08 + 0.1
Total work done = 0.24 J
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The Eiffel Tower in Paris weighs 9,000 tons and stands on an area of 450 m2. Find the pressure it exerts on the ground.
Answer: The question asks us to find the pressure exerted by the Eiffel Tower on the ground. To answer this question we use the formula
pressure=Force/Area
and obtain the answer Pressure exerted by Eiffel Tower on the ground =[tex]196000 Pa[/tex]
Explanation: To find the pressure exerted by the Eiffel Tower on the ground we use the formula
[tex]pressure = \frac{force}{area}[/tex]
Given in the problem, the weight of the Eiffel Tower= 9000 tons= 9000000 kg. Ton or kilogram(kg) is a unit of mass and we have to convert it into force
[tex]force = mass * acceleration[/tex]
acceleration due to gravity [tex]g[/tex] =9.8 m/[tex]s^{2}[/tex]
mass = 9000 tons = 9000[tex]*[/tex]1000 kg[tex]= 9000000 kg[/tex] ∵[tex](1 ton = 1000 kg)[/tex]
∴ [tex]force =[/tex] [tex]9000000* 9.8[/tex] = 88200000 N [tex](1 N(newton) = 1 kg.m/s^{2})[/tex]
Given [tex]area = 450 m^{2}[/tex]
∴[tex]pressure =\frac{force}{area}= \frac{88200000}{450} =196000 N/m^{2} = 196000 pascal= 196000 Pa[/tex]
Thus the pressure exerted by the Eiffel Tower on the ground is 196000Pa
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Explain the concept of an inverse squared relationship?
The concept of an inverse squared relationship explains the behavior of intensity of light and distance of the light source. As the distance of the light source increases, the intensity of light decreases.
What is concept of an inverse squared relationship?The law of inverse square law says that intensity equals the inverse of the square of the distance from the source.
Mathematically, the formula for the inverse square law is given as;
I ∝ 1/r²
where;
I is the intensity of lightr is the distance from the light sourceWhat is intensity of light?The intensity of light can be defined as the measure of the amount of power emitted by a given surface or reflected by the surface.
Thus, the inverse square law is all about the inverse relation between the intensity of light or power output of a given surface to the distance of the light source.
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A toaster oven ( 1500 w), an large AC unit ( 1700 w), and 100 watt bulb are connected in parallel with a 120 volt. Determine the total energy used by these appliances in a day in kwh. The time of usage for the toaster over is 1 hour. ac 12 hours, and 100 w bulb 10 hours
In order to calculate the energy used per day by each appliance, let's multiply the power by the amount of time used in a day:
[tex]E=W\cdot t[/tex]For the toaster oven, we have:
[tex]E_1=1500\cdot1=1500\text{ Wh}=1.5\text{ kWh}[/tex]For the AC, we have:
[tex]E_2=1700\cdot12=20400\text{ Wh}=20.4\text{ kWh}[/tex]For the bulb, we have:
[tex]E_3=100\cdot10=1000\text{ Wh}=1\text{ kWh}[/tex]So the total energy used in a day is:
[tex]\begin{gathered} E=E_1+E_2+E_3 \\ E=1.5+20.4+1 \\ E=22.9\text{ kWh} \end{gathered}[/tex]calculate the net force acting on the box in the following. refer to the screenshot below.
Here the two force 3N and 3N acting on same direction, so
net force = 3N + 3N
= 6N
Forces that are balanced are those that are opposite in direction and equal in size, but here the equal forces acts in same direction so it is unbalanced
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Riders on the power tower are launched skyward with an acceleration of 4g, after which they experience a period of free fall. what is a 60 kg rider's apparent weight during the launch?
The rider's apparent weight during the launch is 2940 N.
When the rider is rest, the forces acting on the skyward (y-direction) are mg towards earth and F_N opposite to mg. Total force will be,
F = F_N - mg
The mass of the rider is 60 kg. When riders are launched skyward with an acceleration of 4g, the force
F = ma = m*4g
F_N - mg = m*4g
F_N - 60*9.8 = 60*4*9.8
F_N - 588 = 2352
F_N = 2352 + 588 = 2940 N
The rider's apparent weight during the launch is 2940 N.
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2 students push on a box in the same direction and a 3rd student pushes in the opposite direction. What is the net force on the box if each push with a force of 50 N?
The net force on the box after the applied force is 50N.
What is Force?A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces. As a vector quantity, a force has both magnitude and direction. Newton is the unit of measurement.
Additional units include dyne, pound-force, poundal, kip, and kilopond.
Deriving values from other quantities: F = ma (previously P = mf)
Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.
Original force of box = 0 N
Force applied by 2 student
Adding them because they are pushing it from the same side
50 N + 50 N
= 100N
Subtracting 50 N because the 3rd student is pushing the box from the opposite side
100N - 50N
= 50 N
The net force on the box after the applied force is 50N.
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These are all different questions. (Physics)
A: If a 2,000 kilograms truck is moving at 35 m/s, what is its momentum?
B: An impulse of 24 Ns acts on a baseball from a bat. What is the force applied to the ball from bat if the ball is in contact with the ball for only 0.0007s.
C: An 8 kilogram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg·m/sec, how fast is it traveling?
D: A beach ball is rolling in a straight line toward you at a speed of 0.5 m/s. Its momentum is 0.25 kg·m/sec. What is the mass of the beach ball?
The momentum of truck is 70,000kg.m/s
Newtonian mechanics, the linear momentum is the product of the mass and velocity of an object. It is a vector quantity, having a magnitude and a direction. If m is an object's mass and v is its velocity, then the object's momentum p is given as,
p = mv
We are given here,
Mass of the truck = m = 2000kg
Velocity of the truck = v = 35m/s
Therefore , to get the value of momentum p using the above equation ,
p = (2000kg) × (35m/s)
p = 70000 kg. m/s
Thus , the momentum of the truck can be given as 70,000kg.m/s
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The ship motion compared with which reference point?
Since the cruise ship makes its way from one island to another. The ship is in motion is compared with the reference point of option C. a lighthouse on a nearby island.
What is the motion of the cruise ship about?Sine the cruise ship from one Island is relocating, the lengthy duration by the passengers within the ship makes it simple to detect the ship motion.
The skipper is the only one who is aware of the ship's direction and speed. Even though the cargo loads are stable and related to the ship's course, we cannot take them into account when calculating the traveling distance of the ship.
Since it is in the sea and relatively close to it, the lighthouse on the island can be used to calculate the distance traveled by ships. Due to its stability, we can use it as a reference point in the water that can be seen from a great distance.
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See full question below
A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?
A.
the passengers on the ship
B.
the captain of the ship
C.
a lighthouse on a nearby island
D.
the cargo inside the hull of the ship
The same monochromatic light passes through the interface between two other unknown materials. This time the transmitted wave is observed to be farther from the normal to the interface than the incident wave. What can be said about these two materials and the light traveling through them?
Since the same monochromatic light passes through the interface between two other unknown materials. The option that can be said about these two materials and the light traveling through them is option B and C:
B)The second material through which the light propagates has a lower index of refraction.C)As the light passes into the second material, its speed increases.What is the monochromatic light above about?Regarding the question Snell's law tells us that light at an interface bends toward a more dense or higher index of refraction.
The second material has a lower index of refraction than the first material because the light is bending away from the normal since it is farther from the normal. As a result, for the second question, the second and third boxes are checked.
The refracted ray bends away from the normal to the interface when a light ray enters a material with a lower index of refraction and a higher wave speed, and it will look closer to the interface than the incident ray.
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See full question below
The same monochromatic light passes through the interface between two other unknown materials. This time the transmitted wave is observed to be farther from the normal to the interface than the incident wave. What can be said about these two materials and the light traveling through them?
A)The second material through which the light propagates has a higher index of refraction.
B)The second material through which the light propagates has a lower index of refraction.
C)As the light passes into the second material, its speed increases.
D)As the light passes into the second material, its speed decreases.
define scalar quantity
Answer:
Scalar quantities are physical quantities which have a magnitude and direction.
e.g. in 5 km, 5 is the magnitude(number) and km is the unit.
some scalar quantities are mass, length, distance, speed, power, energy, temperature etc.
Answer: Values with magnitude but without direction
Explanation:
Majorly there exists two types of quantities, Scalar and Vector.
Vectors: Quantities, with magnitude and direction.
Example: Force, Displacement
Scalars: Quantities, with magnitude but without direction.
Example: Weight, Length, Quantity
we do not need direction to define weight,
it is just 5 kilograms, and NOT 5 kilograms towards east.
What forces are at work on your body when skydiving
PLEASE HURRY DUE TODAY
Answer:
The physics behind skydiving involves the interaction between gravity and air resistance. When a skydiver jumps out of a plane he starts accelerating downwards, until he reaches terminal speed. This is the speed at which the drag from air resistance exactly balances the force of gravity pulling him down.
What is the frequency of a wave if the velocity is 449.4 m/s and the wavelength is 8.4 meters?
We will have the following:
First, we remember:
[tex]\lambda=\frac{v}{f}[/tex]Then we will have:
[tex]\left(8.4m\right?)=\frac{\left(449.4m/s\right)}{f}\Rightarrow f=\frac{\left(449.4m/s\right)}{\left(8.4m\right)}[/tex][tex]\Rightarrow f=53.5Hz[/tex]So, the frequency of the wave is 53.5 Hz.
6. What horizontal force is required to slide a 150 N crate with uniform motion across a
floor where the coefficient of kinetic friction is 0.20?
Horizontal force required to slide a 150 N crate with uniform motion across a floor where the coefficient of kinetic friction is 0.20 is calculated to be 30 N .
A force that is applied in parallel to the horizon is known as horizontal force. The force exerted on a body has two components, that is the horizontal component and a vertical component.
Two types of horizontal force are :
Static friction which is the maximum horizontal force that can be applied before an object starts to move. Kinetic friction which the horizontal force that acts in the opposite direction of the motion of an object.Given , force = 150 N
Coefficient of kinetic friction, μ = 0.20
Horizontal force, F = μmg
=0.20* 150
Horizontal force = 30 N
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how are the layers of Earth connected and affected by each other?
Answer:
Each layer has a unique chemical composition, physical state, and can impact life on Earth's surface. Movement in the mantle caused by variations in heat from the core, cause the plates to shift, which can cause earthquakes and volcanic eruptions.
An electron with a speed of 1.1 ✕ 107 m/s moves horizontally into a region where a constant vertical force of 5.1 ✕ 10−16 N acts on it. The mass of the electron is 9.11 ✕ 10−31 kg. Determine the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.
Answer:
Sv = 1/2 a t^2 equation describing vertical distance traveled
Sv = 1/2 F / m * t^2 need to find t
Sh = .029m horizontal distance traveled
.029 m = Vh t time to travel 29 mm
t = 29E-3 m / 1.1E7 m/s = 2.64E-9 s
Sv = 1/2 * 5.1E-16 / 9.11E-31 * (2.64E-9)^2 = 5.1 / 2 * 2.64^2 / 9.11 * 10^-3 m
Sv = .00195 m = 1.95 mm
A woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s (about 70 mph). Assume the speed of sound to be 343 m/s.
(a)
What frequency (in Hz) does the woman hear?
As the source moves toward the stationary observer, the frequency the woman will hear the sound from the siren will be 484.5 Hz
What is Doppler Effect ?Doppler effect is the frequency change due to the relative motion between a sound or light and an observer.
Given that a woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s. If the speed of sound is to be 343 m/s, the frequency the woman hear the sound can be calculated by using the formula
Fo = FsC/(C - V)
Where
Fo = Frequency of the observerFs = frequency of the siren = 440 HzV = speed of the car = 31.5 m/sC = speed of the sound = 343 m/sSubstitute all the parameters into the formula
Fo = (440 × 343) / (343 - 31.5)
Fo = 150920 / 311.5
Fo = 484.5 Hz
Therefore, the woman will hear the sound from the siren at the frequency of 484.5 Hz
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