What is the de-Broglie wavelength of a 70kg person jogging at the rate of 2.70m/s. the mass of an electron is 9.11 x 10-28g, the speed of light is 3.00 x 108m/s, planks constant is 6.63 x 10-34js.

Answers

Answer 1

The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.

What is de-Broglie wavelength?

De-Broglie wavelength is the ratio of Planck's constant  h to the momentum of the electron p.

Momentum p = mass m x velocity v

Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s

De- Broglie wavelength λ= h/mv

λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)

λ = 3.5 x 10⁻³² m

Thus the wavelength is 3.5 x 10⁻³² m.

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Related Questions

When the ultrasound beam strikes the surface at or nearly at right angles, the fraction of sound energy that is reflected (R) at the interface between two materials of acoustic impedance Z1 and Z2, respectively, is given by:​

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Explanation:

the expression of x= -4t+2t^2 where x is displecement?

BRAINLIEST IF ITS CORRECT HEPL​

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Answer: C.

Explanation: They describe the direction of the magnetic force on a north monopole at any given position.

which vector has an x component with a length of 3?

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Answer:

A) b.

Explanation:

all the details are in the attached picture.

Conservation efforts have been effective in _______.
a.
increasing the number of endangered species
b.
reducing all the negative impacts of human activity
c.
preserving wildlife habitats
d.
all of the above

Answers

Answer:

The answer is D. All of the above.

Explanation:

All of these were efforts and been effective.

Answer:

c

Explanation:

What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?

Answers

The energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.

Energy of photon at level f and level b

The energy of a photon at level F is given as -268 eV and the energy photon at level b is given as -5.52 eV.

Energy emitted by a photon when it falls from level f to energy level b is calculated as follows;

ΔE = -2.68 eV - (-5.52 eV)

ΔE =  -2.68 eV + 5.52 eV

ΔE = 2.84 eV

Thus, the energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.

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5 postulates of neil bohr atomic model​

Answers

Answer:

What is Bohr’s Model of an Atom?

The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.

A satellite with a mass of 150 kg fires its engines to increase velocity, thereby
increasing the size of its orbit about Earth. As a result, it moves from a
circular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What is
the approximate change in gravitational force from Earth as a result of this
change in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kg
and G = 6.67 x 10-11 N-m²/kg².)
OA. -113 N
OB. -148 N
O C. -216 N
D. -54 N

Answers

The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N

What is the universal law of gravitation?

The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the  product of their masses and inversely proportional to the square of the distance between them.

It is written thus;

F = G MIM2÷ r∧2

Where

F = Gravitational force

G = Gravitational constant

M1 and M2 are the masses of the object

r = radius

How to calculate the gravitational force

Formula:

F = G MIM2 ÷ r∧2

Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G =  6.67 x 10-11 N-m²/kg²

For the first orbit, substitute the values

F = 6.67 x 10∧-11 × 150 ×  5.97 x 10∧24 ÷ (7.5 x 10∧6)²

F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 =  105.77 N

For the second orbit of radius 7.7 x 106 m

F =  6.67 x 10∧-11 × 150 ×  5.97 x 10∧24 ÷ (7.7 x 10∧6)²

F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N

The approximate change = 105. 77 - 100.42 = 5. 35N

Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N

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Please help!! Look at pic

Answers

Answer:

Explanation:

Voltage and Current relation is given by V=IR
I=9A

R=4Ohm

V=IR
V=9x4=36Volts

Resistance = 4 Ohm

Current = 9 Ampere

Voltage = 36 Volts

Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is

Answers

B because I had it before

An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitational potential energy of this object at this position?

Answers

Answer:

1600 joules

Explanation:

Potential Energy = m * g * h

                           = 20 kg  *  10 m/s^2  * 8 m = 1600 J

Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m Determine the x coordinate of the CM

Answers

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.

How to determine the coordinates of the center of mass of a compound figure

Let suppose that the entire construction has a uniform mass, then the coordinates of the center of mass can be determined by definition of weighted average:

[tex]\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex]     (1)

[tex]\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex]     (2)

If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:

[tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex]

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.

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The magnetic field lines of a bar magnet spread out from the
A. north end to the south end.
B. south end to the north end.
C. edges to the center.
D. center to the edges.

Answers

Answer:

I think the letter B. But I'm not sure pero I try mo Lang po baka Yan po ang tamang sagot kac Yan po Yung nilagay na sagot saakin e Kaya try mo Lang po

Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reactions are uncontrolled for maximum energy output. all of the products are fed back into the reaction to keep it going. all of the products are immediately removed to inhibit more reactions.

Answers

Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output

Nuclear energy generation

Nuclear energy is a clean energy source which has a zero-emission, nuclear energy is used to generate electricity/power following a controlled reaction known as fission of uranium atoms to produce heat energy required to drive a turbine to produce electricity

Hence we can conclude that Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output.

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Answer:

option A

Explanation:

calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high​

Answers

Answer:

529.2 joules

Explanation:

Work done = force x distance = mass x gravity x distance

= 36x9.8 x1.5 =529.2 joules

A copper atom has an atomic number of 29 and an atomic mass of 64. What
is the structure of this atom?
OA. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
OC. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
D. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.

Answers

Answer:

It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons

Explanation:

Atoms Composition:

A atom is mainly composed of a centrally-placed nucleus. A nucleus consists of protons and neutrons with a cloud of electrons surrounding the outside.  A proton is a nuclear particle having a positive charge equal to that of an electron and a mass more than 1800 times the electron. A neutron is a nuclear particle having a mass almost identical to that of an electron, but no electric charge.

Calculation:

Mass number = Proton + Neutron64 = 29 + NeutronCollect like termsNeutron = 64 – 29Neutron = 35

pleaseeee help mehhhh​

Answers

A

The answer is a .

Have a great day

when an Earthquake occurs energy radiates in all direction from its source called the

Answers

Answer:

[tex]\huge\boxed{\sf Focus}[/tex]

Explanation:

Focus:The point at which Earthquake occurs is called Focus.It is also called hypocenter.Epicenter:Epicenter is the point on the Earth surface which is just above the focus.

Most of the times, epicenter is confused with focus. However, epicenter lies on the Earth surface and focus is the exact point from where the Earthquake originates.

[tex]\rule[225]{225}{2}[/tex]

a toy car needs a source of energy to move. how could you give gravitational potential energy to a toy car so that it will move when you let it go?​

Answers

Answer:

wait one second im about to go get some milk im thirsty

Explanation:

do you want any chicken on your salad

If 20 coulombs of charge move past a given point in 4 s, what is the current?

Answers

Answer:

5A

Explanation:

[tex]=> Current (I) = \frac{q}{t} [/tex]

Here q = 20 C and t = 4sec

=> I = 20/4 = 5A


Which of the following is a physical change?
sawing a piece of wood in half
O burning a piece of wood
O a copper statue turning from red to green
Orust forming on an iron fence

Answers

Answer:

I think its 'sawing a piece of wood in half'

Explanation:

sry if its wrong

HELP MEEE!!!!!!!!!

A series circuit is made up of a battery and 4 Resistors.

The Resistors are:

R1 = 10 ohms

R2 = 20 ohms

R3= 5 ohms

R4= 10 ohms

What is the total resistance in the circuit is...
ohms

Answers

r2 i believe but lmk if i’m wrong

Using the formula below, determine how
many seconds it would take for a satellite
traveling at 4 miles per second to travel
11,000 miles across the Pacific Ocean.
speed=
A 27.5 seconds
B 45 seconds
C 2,750 seconds
D 3,000 seconds

Answers

Speed=distance /time
11,000/4 =2,750
Answer=C

When you are making cold calls while job hunting, be
o 20 minutes early
O on time
O prepared with a résumé and cover letter
O casual

Answers

Answer:

The answer is O prepared with a résumé and cover letter

Explanation:

That will get you very far if you are prepared with a résumé and cover letter

prepared with resume and cover letter

a) First write down what you see in the picture.

Answers

Answer:

which picture please,I don't get you

Before Schwarzschild, the understanding of relativity to gravitational force was unknown.

t or f

Answers

Answer:

False

Explanation:

Find the charge on the capacitor in an LRC-series circuit at t = 0.03 s when L = 0.05 h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A. (Round your answer to four decimal places.)
Determine the first time at which the charge on the capacitor is equal to zero. (Round your answer to four decimal places.)

Answers

The charge on the capacitor in an LRC-series circuit is 2.8907 C.

The first time at which the charge on the capacitor is equal to zero is 0.1409s.

What is capacitor?

The capacitor consists of two parallel plates used to store the charge when current flows through it, and provides energy when shuts off.

By the Kirchoff's second  law,

Lq'' +Lq' +q/C =E(t)

Where, L =0.05h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A.

Equations becomes q''+120q' +4000 =0

The auxiliary equation is m² +120m+4000 =0

Solving this quadratic equation, we have

m =-6± 20i

Then , q(t) = Ae^(-60t)cos 20t + Be^(-60t)sin 20t    where, A and B are constants.

At t=0, q(0) =7 =A

and q'(t) = A [ -20e^(-60t)sin 20t - 60e^(-60t)cos 20t ] +B  [ 20e^(-60t)cos 20t - 60e^(-60t)sin 20t ]

So, i(0)= q'(0) =0 =-60A +20 B

Putting the value of A=7 above, we have B =21.

So,  q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t  

The charge on the capacitor at time t =0.015

q(0.015) = 2.8907 C

Thus the charge on capacitor is  2.8907 C.

q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t  =0

Solve for t, we get

e^(-60t)cos 20t + 3e^(-60t)sin 20t\

-1/3 = sin 20t /cos20t

t =1/20 arctan(-1/3)

As, arctan is defined within -90 to +90,

So, 20t = -0.3218 +π =2.8197

t =0.1409s

Thus the first time at which the charge is zero is 0.1409s.

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.......................................

.

Answers

Explanation:

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Help
Light helps you in so many ways. But, if it is not used properly, it can also be harmful to you. How can you use light safely? Provide at least five (5) ways how you will protect yourself from light energy.

Answers

Answer
1.Limit screen time to reduce harmful blue light
2. Sunglasses and/or blue light reducing glasses to protect your eyes
3. Sunscreen
4. UV protectant clothing (SPF factor material)
5. Wear a hat
6. Check the UV Index before spending time outside
7. Avoid tanning beds
8. Chose shade during high sun hours
9. Use extra caution when near reflective surfaces, like water, snow, and sand

The Venus flytrap is known for which of these behaviors?

closing its flower buds at night
snapping a leaf shut around an insect
closing its leaves when touched by a finger
screeching when in danger

Answers

Snapping a leaf shut around an insect, I think.

What kind of object are the light rays interacting with in the model below?

Convex mirror
Convex lens
Concave mirror
Concave lens

Answers

Answer:

Concave lens

.............

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