The change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.
How to calculate change in temperature?The change in temperature of a substance can be calculated using the following formula:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperature500 = 23 × 0.24 × ∆T
500 = 5.52∆T
∆T = 500/5.52
∆T = 90.58°C
Therefore, the change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.
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Endler's Guppies Experiment on Natural Selection
1. Identify the following elements of hypothesis-based science in this example: (a) question, (b) hypothesis, (c) prediction, (d) control group, and (e) experimental group. 2. (a) Explain how the types of data the researchers chose to collect enabled them to test their prediction. (b) What additional questions might you ask to determine the strength of these conclusions?
In conclusion, an experiment about Natural Selection includes mechanisms, explanation, estimation of the frequency of the trait and comparisons.
What is the scientific method?The scientific method is a series of step used to validate evidence and thus formulate theories.
Darwin used the scientific method to draw conclusions about the main mechanism of evolution, i.e., natural selection.
The scientific method involves making a question, providing an explanation of the hypothesis, making observations/experiments (which include experimental and control groups), and drawing conclusions.
The empirical data serve to test a hypothesis (either confirm or reject it) by contrasting its results with predictive outcomes.
The strength of the conclusions can be enhanced by using supporting evidence from other research fields (in this case, for example, the fossil record).
In conclusion, an experiment on Natural Selection includes mechanisms (question), explanation (hypothesis), estimation of the frequency of the trait in the population (prediction) and comparisons (control group).
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Tin is used to coat tin cans for food storage. If the tin is scratched and the iron of the can exposed, will the iron corrode more rapidly or less rapidly? Explain
The scratched tin can with the iron will more rapidly corrode the iron than the tin.
What is corrosion?The corrosion can be given as the process of the oxidation of the metal into the more stable metal oxide. The chemical oxidation of the metal is attained with the surrounding available oxygen or the water vapors.
The reactivity of the Iron for the oxidation is more as compared to the tin from the reactivity series. Therefore if both tin and iron are exposed to corrosion, iron will be more rapidly corroded.
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Consider the following reaction:
2KI (aq) + Pb(NO3)2(aq) -> 2 KNO3(aq) + Pbl2(s)
What minimum volume of 0.200 M Kl(aq) is required to completely react with 155.0 mL of a 0.112 M Pb(NO3)2 solution?
A. 174 mL
B. 43.4 mL
C. 86.8 mL
D. 348 mL
Answer:
B. 43.40 mL
Explanation:
We are required to determine the volume of 0.200 M Kl(aq).
We have; 155.0 mL of a 0.112 M Pb(NO3)2 solution.
We know that molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.
Hence,
0.112 M Pb(NO3)2 is contained in 1000 mLx mol Pb(NO3)2 is contained in 155.0 mL[tex]x \: mol \: = \frac{155 \times 0.112}{1000} \\ = 0.01736 \: moles[/tex]
= 0.01736 moles of Pb(NO3)2
We have a mole ratio of 2: 1 (KI : Pb(NO3)2).
To obtain the number of moles of KI; we divide by half the moles of Pb(NO3)2 (aq);
(0.01736)/2
= 0.00868 moles KI
0.20 moles KI is contained in 1000 mL
0.00868 moles KI is contained in x mL
[tex]x \: ml \: = \frac{0.00868 \times 1000}{0.20} [/tex]
= 43.40 mL
Therefore the volume of KI required to react completely with 0.112 M Pb(NO3)2 is 43.40 mL
Hi all, if anyone could please help me on this question it would be appreciated, tysm!!
Answer: 69.92 Celsius
Explanation:
Enthalpy change = mass of water * specific heat * change in temperature
400g water * 4.18 J/g*celsius * 1.5K = 2.508kJ
2508 J/(138.3g*0.38 J/g*celsius) = 47.72 K
So the copper temperature was lowered by 47.72K/C when placed in water, so 22.2+47.72 = 69.92 Celsius
Hope this helps(and is correct)!
please helpWhat’s the pH of a solution of ammonia that has a concentration of 0.335 M? The Kb of ammonia is
1.8 × 10–5
. First complete the ICE chart.
HA H3O+ AInitial
Change
Equilibrium
iii. Calculate the pH. Please show all work.
From the calculation, the pH of the solution is 4.85.
What is the pH?
The pH is defined as the hydrogen ion concentration of the solution. We have the ICE table as;
HA + H2O ⇔ H3O^+ + A^-
I 0.335 0 0
C -x +x +x
E 0.335 - x x x
Ka = 1 * 10^-14/Kb
Ka = 1 * 10^-14/1.8 × 10^–5
Ka = 5.56 * 10^-10
Ka = [H3O^+] [A^-]/[HA]
But [H3O^+] = [A^-] = x
5.56 * 10^-10 = x^2/ 0.335 - x
5.56 * 10^-10(0.335 - x ) = x^2
1.86 * 10^-10 - 5.56 * 10^-10x = x^2
x^2 + 5.56 * 10^-10x - 1.86 * 10^-10 = 0
x=0.000014 M
Now;
pH = -log 0.000014 M
pH = 4.85
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Which example involves phase change in which heat energy is released by the substance?
Answer:
Example that involves phase change in which heat energy is released by substance:
Explanation:
If heat is removed from a substance, such as in freezing and condensation, then the process is exothermic. In this instance, heat is decreasing the speed of the molecules causing them move slower (examples: liquid to solid; gas to liquid). These changes release heat to the surroundings.3 days ago
Solid → Liquid: Melting or fusion
Gas → Liquid: Condensation
Liquid → Gas: Vaporization
Liquid → Solid: Freezing
For the decomposition of nitrosyl bromide at 10 °C
2 NOBr(g)2 NO(g) + Br2(g)
the average rate of disappearance of NOBr over the time period from t = 0 s to t = 25.7 s is found to be 7.36×10-4 M s-1.
What is the average rate of appearance of Br2 over the same time period?
M s-1.
From the calculation, the rate of appearance of Br2 is 1.472 * 10^-3 M s-1
What is the rate of reaction?The rate of reaction refers to how fast or slow that reactants disappear or the products are formed .
Now;
We know that;
-d[NOBr]/dt = 1/2 d[Br2]/dt
Hence;
d[Br2]/dt = 2[-d[NOBr]/dt ]
d[Br2]/dt = 2 (7.36×10-4 M s-1)
d[Br2]/dt = 1.472 * 10^-3 M s-1
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I need to answer this one quick
Answer:
Electrochemical
Combustion
Photosynthesis
Respiration
Explanation:
How many moles of of ZnCl2 are in 1.5 L of a 0.2 M solution? Report your answer with one significant figure. Provide your answer below:
The moles of ZnCl₂ in 1.5 L of the 0.2 M solution is 0.3 moles.
What moles of ZnCl₂ is present in in 1.5 L of a 0.2 M solution?The moles of ZnCl₂ is present in in 1.5 L of a 0.2 M solution is calculated using the formula below:
moles = molarity x volumeMoles of ZnCl₂ = 1.5 x 0.2
Moles of ZnCl₂ = 0.3 moles
In conclusion, the moles of ZnCl₂ in the given volume of solution is determined from the molarity of the solution and the volume of solution.
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What are the noble gases
Answer:
Noble gases are rare elements (gases) with extreme stability and a very low reactivity rate.
Some examples are neon, argon, helium etc.
Hope it helps!!
Answer:
Helium, neon, argon, krypton, xenon, and radon.
Explanation:
The chemical elements in group 18 of the periodic chart are the noble gases. They have the most valence electrons that their outer shell can support, making them the most stable. As a result of their inherent stability, they rarely interact with other components.
Other characteristics of the noble gases are that they all conduct electricity, fluoresce, are odorless and colorless, and are used in many conditions when a stable element is needed to maintain a safe and constant environment. These are the 6 noble gases:
HeliumNeonArgonKryptonXenonRadonAlthough the phrase "inert gases" was once used to describe the noble gases, it is not entirely true given that some of them do participate in chemical processes.
Chemical properties:
Under normal circumstances, the noble gases are nonflammable, tasteless, colorless, and odorless. Because it was earlier thought that they had a valence of zero, or that their atoms couldn't mix with those of other elements to create compounds, they were originally given the group 0 designation in the periodic table. However, it was eventually determined that some do in fact combine to create compounds, which led to the label's demise. Full valence electron shells are present in noble gases. The only electrons that often take part in chemical bonding are valence electrons, which are an atom's outermost electrons. Due to their great stability, complete valence electron shell atoms have little to no inclination to gain or lose electrons and do not frequently establish chemical bonds. But unlike lesser noble gases like helium, larger noble gases like radon are bound together by electromagnetic force less tightly, making it simpler to remove outside electrons from hefty noble gases. The noble gases can be combined with the electron configuration notation to create the noble gas notation as a consequence of a complete shell.
To do this, the electron configuration is written starting with the nearest noble gas that comes before the element in issue, and then it is carried from there. For instance, the noble gas notation is [Ne] 3s2 3p3, whereas the electron notation for phosphorus is 1s2 2s2 2p6 3s2 3p3. In addition to being shorter than writing down the whole notation of atomic orbitals, this more condensed notation makes it simpler to identify elements.
Of all the noble gas compounds that have been created, xenon compounds are the most prevalent. [33] Most of them consist of a xenon atom in the +2, +4, +6, or +8 oxidation state coupled to an extremely electronegative element, such fluorine or oxygen, as in xenon difluoride (XeF).
2), xenon tetrafluoride (XeF
4), xenon hexafluoride (XeF
6), xenon tetroxide (XeO
4), and sodium perxenate (Na
4XeO
6). Xenon reacts with fluorine to form numerous xenon fluorides according to the following equations:
Xe + F2 → XeF2
Xe + 2F2 → XeF4
Xe + 3F2 → XeF6
Some of these compounds have found use in chemical synthesis as oxidizing agents; XeF
2, in particular, is commercially available and can be used as a fluorinating agent.
Which of these safety features aims to keep nuclear radiation contained
The safety feature aimed at keeping nuclear radiation contained is steel-reinforced concrete.
What is nuclear power plant?A nuclear power plant is a building with reactors that contain controlled nuclear reactions to produce energy.
Nuclear power plants are able to generate warm water by using atomic properties of matter (i.e.,m the process of nuclear fission), which is in turn converted into steam to move turbines.
The walls of nuclear power reactors are composed of steel-reinforced concrete in order to avoid radiation release.
In conclusion, the safety standard property that maintains nuclear radiation contained is steel-reinforced concrete.
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At what temperature does sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm?
At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 0.0721 atm
[tex]n=\frac{mass}{molar \;mass}[/tex]
[tex]R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=?
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}[/tex]
[tex]0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}[/tex]
T = 365.2158727 K= 365 K
Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
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In the above reaction, how many moles of nitrogen gas can theoretically be produced by 2.177 moles of N2H4, assuming there is an excess of N2O4?
The number of moles of nitrogen that can be produced theoretically will be 3.2655 moles.
Stoichiometric problemThe equation of the reaction is as follows:
[tex]2N_2H_4 + N_2O_4 --- > 3N_2 + 4H_2O[/tex]
The mole ratio of [tex]N_2H_4[/tex] reacted to that of [tex]N_2[/tex] produced is 2:3.
Thus, with 2.177 moles of [tex]N_2H_4[/tex] , the theoretical number of moles of [tex]N_2[/tex] can be calaculated as:
3/2 x 2.177 = 3.2655 moles
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You drink part of your bottle of water, leaving 160 g in the bottle. When you purchased the water, it had a temperature of 10oC. After carrying the bottle around for awhile, you take a sip and find that the water is an unpleasantly warm 35oC. How much heat energy did the water left in the bottle absorb? Water has a specific heat capacity of 4.2 J/(g * oC).
The energy that the water in the bottle absorbed is obtained as 16800 J.
What is the specific heat capacity?The specific heat capacity of the water refers to the energy that is required to raise the temperature of 1Kg of the water by 1 degree.
Now we have the following;
mass (m) = 160 g
temperature change dT = ( 35oC - 10oC)
specific heat capacity (c)= 4.2 J/(g * oC).
Now;
H = mcdT
H = 160 g * 4.2 J/(g * oC) * ( 35oC - 10oC)
H = 16800 J
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Calculate the molarity of 29.9 g of MgS in 911 mL of solution??
0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.
Define the molarity of a solution.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
Given data:
Volume of solution = 911 mL=0.911L
Given the mass of MgS = 29.9 g
Molar mass of MgS = 56.38 g/mol
Moles of MgS = 0.5303299042
[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]
[tex]Molality = \frac{0.5303299042}{0.911L}[/tex]
Molality = 0.5821403998=0.58
Hence, 0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.
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A student analyzed a sample of sea water and found that it contained 2.3g of NaCi, 0.005g of MgSo4, 0.234g of CaCI2 and 60.12g of H2O. Total mass of the sample is
[tex]2.3+0.005+0.234+60.12=\boxed{62.659 \text{ g}}[/tex]
Allyl sulfide, C6H10S, is a compound that has the odor of garlic. How many moles of Allyl sulfide are in 125 g?
Considering the definition of molar mass, 1.096 moles of Allyl sulfide are in 125 g.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.
Molar mass of C₆H₁₀SIn this case, you know the molar mass of the elements is:
C= 12 g/moleH= 1 g/moleS= 32 g/moleSo, the molar mass of the compound C₆H₁₀S is calculated as:
C₆H₁₀S= 6× 12 g/mole + 10× 1 g/mole + 32 g/mole
Solving:
C₆H₁₀S= 114 g/mole
Moles in 125 g CH₂Cl₂Next, you can apply the following rule of three: If by definition of molar mass 114 grams of the compound are contained in 1 mole, 125 grams of the compound are contained in how many moles?
[tex]amount of moles=\frac{125 grams x 1 mole}{114 grams}[/tex]
amount of moles= 1.096 moles
Finally, 1.096 moles of Allyl sulfide are in 125 g.
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Please help!!!
Tysm!! Xxxx
1) The amount of PbS produced will be 16.27 grams
2: The amount of Fe produced will be 118.72 grams.
Stoichiometric problems1) The equation is balanced. The mole ratio of lead (II) acetate to the PbS is 1:1.
Mole of 22.11 lead acetate = 22.11/ 325.29 = 0.06797 moles
Equivalent mole of PbS = 0.06797 moles
Mass of PbS = 0.06797 x 239.3 = 16.27 grams
2) from the equation, the mole ratio of Al to Fe is 1:1.
Mole of 57.2 g Al = 57.2/26.98 = 2.12 moles
Equivalent mole of Fe = 2.12 moles
Mass of Fe = 2.12 x 56 = 118.72 grams.
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Determine the empirical formulas for compounds with the following percent compositions:
. 81.68% carbon and 18.32% hydrogen
The empirical formula of a compound that has the following percent composition; 81.68% carbon and 18.32% hydrogen is C2H5.
How to calculate empirical formula?The empirical formula is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.
The empirical formula of a compound that has 81.68% carbon and 18.32% hydrogen can be calculated as follows:
81.68% C = 81.68g 18.32% H = 18.32gFirst, we convert mass to moles;
C = 81.68g ÷ 12g/mol = 6.81mol H = 18.32 ÷ 1g/mol = 18.3molNext, we divide each mole value by the smallest (6.81mol)
C = 6.81 ÷ 6.81 = 1H = 18.32 ÷ 6.81 = 2.7We multiply each ratio by 5 to make an whole number:
C = 1 × 2 = 2H = 2.7 × 2 = 5.4 = 5Therefore, the empirical formula of a compound that has the following percent composition; 81.68% carbon and 18.32% hydrogen is C2H5.
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Draw and name the isomers of c4h9NH2
Answer:
yhnjulllljjghbbjygbnk
Which of the following best describes the function of a plant's flowers?
A.
The flowers of a plant transport nutrients from the roots of a plant to the stems.
B.
The flowers of a plant make food for the rest of the plant.
C.
The flowers of a plant attract animals that are important for pollination.
D.
The flowers of a plant absorb water and nutrients from the soil.
Which statements about this area are true based on what you know about petrified fossils? Check all that apply.
The area was once a forest.
The area was uplifted.
The area was void of organic material.
The area was probably covered by water.
The area was covered by volcanic material.
On the basis of the area and petrified fossils, the following statements are true:
The area was once a forest.The area was probably covered by water.Thus, the correct options are A and D.
What are Petrified fossils?Petrified fossils may be defined as those which completely replace the organic form of fossils with mineral forms like stone.
The area was once a forest indicating that there must be a lot of death of organisms that are buried deep into the soil for millions of years.
This area also consists of a huge amount of water for the delocalization of dead organic matter to flow throughout the given area where the organic form is converted into mineral form.
Therefore, the correct options for this question are A and D.
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Which of the following is true of an effective scientific model
An effective scientific model must be testable and verifiable by using the scientific method.
What is a scientific model?A scientific model is any explanation of an observation of the real world that can be proved by the scientific method.
A scientific model must be testable, which means that we can confirm or reject its assumptions through experimental and/or observational procedures.
In conclusion, the effective scientific model must be proved with the scientific method.
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How much heat will be released (AH) if
0.1579 mol of NH3 are mixed with 0.20 mol of
O₂ in the following chemical reaction?
4 NH3(g) + O₂ (g) → 2 N₂H4 (g) + 2 H₂O(g)
AH = -286 kJ/mol
Answer:
11.29 kJ (to 4 sf)
Explanation:
Here, ammonia is the limiting reactant.
For the reaction to occur once, 4 moles of ammonia must be consumed.
Thus means that the reaction can occur 0.1579/4=0.039475 times.
Therefore, (286)(0.039475) = 11.29 kJ (to 4 sf)
14. What volume of water vapor in liters could be generated at 1.01 atm and 420. K by the combustion of 273.36 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
Do not type units with your answer
Answer:
776 L H₂O
Explanation:
To find the volume, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = number of moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
To find the volume of water vapor, you need to (1) convert grams C₅H₁₂ to moles C₅H₁₂ (via molar mass), then (2) convert moles C₅H₁₂ to moles H₂O (via mole-to-mole ratio from reaction coefficients), then (3) calculate volume H₂O (via Ideal Gas Law). The final answer should have 3 sig figs.
(Step 1 & Step 2)
Molar Mass (C₅H₁₂): 5(12.011 g/mol) + 12(1.008 g/mol)
Molar Mass (C₅H₁₂): 72.151 g/mol
1 C₅H₁₂ (g) + 8 O₂ (g) -----> 5 CO₂ (g) + 6 H₂O (g)
273.36 g C₅H₁₂ 1 mole 6 moles H₂O
----------------------- x ---------------- x ----------------------- = 22.7 moles H₂O
72.151 g 1 mole C₅H₁₂
(Step 3)
P = 1.01 atm R = 0.0821 L*atm/mol*K
V = ? T = 420 K
n = 22.7 moles
PV = nRT
(1.01 atm)V = (22.7 moles)(0.0821 L*atm/mol*K)(420 K)
(1.01 atm)V = 783.856
V = 776 L
Without units, your answer would be 776.
Hierarchies and schemes are important for?
Answer:
Hierarchies and schemes are important for organizing information. They provide a way to group related information together and to see the relationships between different pieces of information.
What are distinguishing features of animals? A) Generally an animal body exhibits a definite symmetry, form and shape. B) Growth of the body occurs proportionately. C) Reserved food is glycogen. D) All of the above.
Answer:
A
Explanation:
Answer:
its D) all of the above
Explanation:
i learned this is like 6th grade
Scenario A
Julio was given the task to produce 59 grams of iron(III) oxide, 23
F
e
2
O
3
. They had one tank of oxygen gas, 2
O
2
and 54 grams of solid iron,
F
e
. They knew that if he heated the iron in the presence of the oxygen gas, they could produce the iron(III) oxide. Since they had such little amount of iron, they decided to use as little of the iron as they could to produce the 59 grams of iron(III) oxide. Julio measured out 41 grams of iron and heated it with excess oxygen. Assume Julio's reaction went 100%. Julio was very happy that their reaction produced the 59 grams.
Scenario B
Gretchen was given the task to produce 19 grams of aluminum fluoride, 3
A
l
F
3
. They had a tank of fluorine gas, 2
F
2
, and 7 grams of solid aluminum,
A
l
. They knew that if they heated the aluminum in the presence of excess fluorine gas, they could produce the aluminum fluoride. Since Gretchen had such little amount of aluminum, they decided to use as little of aluminum as they could to produce the 19 grams of aluminum fluoride. Gretchen measured out 5 grams of aluminum and heated it with excess fluorine gas. Assume Gretchen's reaction went 100%. Gretchen was very happy their reaction produced the 19 grams.
Question #1: Which scientist did the experiment incorrectly? (1 pt)
Question #2: Explain what the scientist did incorrectly. Be sure to include the balanced equation for each scientist. Show the stoichiometry and explain in complete sentences why one experiment is wrong and the other is not. (4 pts)
Question #3: Explain specifically what the scientist should do to make the experiment correct (use numbers to support your answer). Also, include the stoichiometry to show how the scientist can make the experiment correct. (3 pts)
As you answer the questions above, use complete sentences to explain the stoichiometry you show and use proper grammar and spelling (1 pt)
Based on the mole ratio of the balanced equation of the reactions;
Gretchen did the experiment incorrectlyGretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluorideGretchen needs to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃What mass of iron(III) oxide is produced from reacting 41 g of Fe with excess oxygen?The equation of the reaction is given below:
4 Fe + 3 O₂ → 2 Fe₂O₃Based on the reaction, mole ratio of Fe and Fe₂O₃ is 2 : 1
Moles of Fe reacted = 41/56 moles
Mass of Fe₂O₃ produced = 41/56 * 1/2 * 160 = 58.6 g
What mass of aluminum fluoride is produced from reacting 5 g of aluminum with excess fluorine?The equation of the reaction is given below:
2 Al + 3 F₂ → 2 AlF₃Based on the reaction, mole ratio of Al and AlF₃ is 1 : 1
Moles of Al reacted = 5/27 moles
Mass of AlF₃ produced = 5/27 * 84 = 15.5 g
This is less than the required mass of AlF₃
Moles of AlF₃ in 19 g = 19/84 = 0.2262 moles
Mass of Al required = 0.2262 * 27 = 6.1 g
Based on the results above;
Gretchen did the experiment incorrectlyGretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluorideGretchen need to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃In conclusion, the mole ratio of the reactions obtained from the equation are required to know the accurate masses of reactants required.
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QUESTION 2 1 POINT
A sample of a gas has a pressure of 248 mm Hg when the volume is 1.05 L. What is the pressure of the gas when the
volume is 3.98 L?
Answer:
65.4 mmHg
Explanation:
Using Boyle's Law,
(248)(1.05)=(pressure)(3.98)
pressure = 65.4 mmHg
13. A compound with a molar mass of 78.0 g/mol is found to contain 92.29%
carbon and 7.71% hydrogen, by mass. The molecular formula of the compound is
a. CH
b. C₂H3
c. C3H3
d. C5H₁
e. C6H6
The molecular formula of the compound is C6H6
Molecular formulaFirst, convert the percentages to moles
C = 92.9/12 = 7.74
H = 7.71/1 = 7.71
Thus, the empirical formula will be CH
[empirical formula]n = molecular formula
Empirical formula mass = 12 + 1 = 13
n = empirical formula mass/molar mass = 78/13 6
Thus, the molecular formula will be C6H6
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