What is the balanced form of the chemical equation shown below?
N2(g) + H2(9) ► NH3(9)
O A. N2(9) + H2(9) ► NH3(9)
B. N2(9) + H2(g) → 2NH3(9)
)
O C. N2(g) + 3H2(g) → 2NH3(9)
O 9
D. N2(9) + H2(g) → 2NH(9)

What Is The Balanced Form Of The Chemical Equation Shown Below?N2(g) + H2(9) NH3(9)O A. N2(9) + H2(9)

Answers

Answer 1

Answer:

C

Explanation:

2 N on left so we put a 2 on the right which makes 6 H so we need 6H on the left to do that we add a coef. of 3 to make 6 H and balance the equation


Related Questions

Need ASAP will give brainlist

Answers

Answer:

A.

The answer is A :)

The person who answerers this will get 100 points pls answer all the question's

Answers

Answer:

I think that is the literal answer

Fe3+ and S2- write the formula for the compound that would be formed

Answers

The answer is Fe2S3

Two substances both exhibit hydrogen bonding. Substance A has a boiling point of 78.4ºC. Substance B has a boiling point of 100ºC. Which statement correctly compares the substances?(1 point)
A) Substance A has stronger bonds, and it takes more energy to undergo a phase change.
B)Substance B has stronger bonds, and it takes more energy to undergo a phase change.
C) Substance B has stronger bonds, and it takes less energy to undergo a phase change.
D) Substance A has stronger bonds, and it takes less energy to undergo a phase change.

Answers

Answer:

The answer is C

Explanation:

Just took the test

Hydrogen bonding is the intermolecular interaction that occurs due to electronegativity differences. Substance B has stronger bonds and requires more energy. Thus, option B is correct.

What is hydrogen bonding?

Hydrogen bonding is present in the water molecules that is because of the electronegativity differences and the dipole-dipole interaction. The hydrogen of the water molecule is bonded to the oxygen molecule.

The hydrogen bonding affects the boiling and the melting point of the substances as more energy are required to change the phase of the matter. So when substance B requires 100ºC than substance A (78.4ºC) it shows strong hydrogen bonding.

Therefore, option B. substance B has a strong hydrogen bond is correct.

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what is science explain​

Answers

Science can be defined as the study of nature, its behaviors and the

interactions between the various components.

Science is divided into three main branches which are

PhysicsChemistryBiology

Science can also be referred to as the gaining of knowledge through various

methods and verifiable by experiments to ensure it is valid.

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How Does being a doormat help a tree survive winter

Answers

Answer: Trees, like all plants, are alive and require nutrients to survive. ... This dormancy is what allows trees to survive the cold winter. During dormancy, a tree's metabolism, energy consumption, and growth all slow down significantly in order to endure the harsh season of winter when water and sunlight are more scarce

Explanation: mark me brainlest plz if this helped only !

2 FeCl2
+ 13 KClO4
+ H2
SO4
→ 2 Fe(ClO3
)3
+
K2
SO4
+ 11 KClO3
+ H2
O
Calculate the grams of KClO3
arising from the
reaction of 2.50 g of KClO4
with 150 mg of FeCl2
in excess of H2
SO4
.

Answers

Taking into account the reaction stoichiometry and limiting reagent, 0.7977 grams of KClO₃ are formed from the  reaction of 2.50 g of KClO₄  with 150 mg of FeCl₂  in excess of H₂SO₄.

In first place, the balanced reaction is:

2 FeCl₂ + 13 KClO₄ + H₂SO₄ → 2 Fe(ClO₃)₃ + K₂SO₄ + 11 KClO₃ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

FeCl₂: 2 molesKClO₄: 13 moles H₂SO₄: 1 moleFe(ClO₃)₃: 2 moles K₂SO₄: 1 mole KClO₃: 11 moles H₂O: 1 mole

The molar mass of the compounds is:

FeCl₂: 126.75 g/moleKClO₄: 138.55 g/mole H₂SO₄: 98 g/moleFe(ClO₃)₃: 306.2 g/moleK₂SO₄: 174.2 g/moleKClO₃: 122.55 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:  

FeCl₂: 2 moles× 126.75 g/mole= 253.5 gramsKClO₄: 13 moles× 138.55 g/mol= 1801.15 grams H₂SO₄: 1 mole× 98 g/mole= 98 gramsFe(ClO₃)₃: 2 moles× 306.2 g/mole= 612.4 gramsK₂SO₄: 1 mole× 174.2 g/mole= 174.2 gramsKClO₃: 11 moles× 122.55 g/mole= 1348.05 gramsH₂O: 1 mole× 18 g/mole= 18 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction and a simple rule of three as follows: if by stoichiometry 1801.15 grams of KClO₄ reacts with 253.5 grams of FeCl₂, if 2.50 grams of KClO₄ react how many mass of FeCl₂ will be needed?

[tex]mass of FeCl_{2}=\frac{2.50 grams of KClO_{4} x253.5 grams of FeCl_{2}}{1801.15 grams grams of KClO_{4}}[/tex]

mass of FeCl₂=0.35 grams

But 0.35 grams of FeCl₂ are not available, 150 mg= 0.150 grams (being 1000 mg= 1 grams) are available. Since you have less mass than you need to react with 1801.15 grams of KClO₄, FeCl₂ will be the limiting reagent.

Then the following rule of three can be applied: if by reaction stoichiometry 253.5 grams of  FeCl₂ form 1348.05 grams of KClO₃, 0.150 grams of FeCl₂ form how much mass of KClO₃?

[tex]mass of KClO_{3}=\frac{0.150 grams of FeCl_{2}x1348.05 grams of KClO_{3} }{253.5grams of FeCl_{2} }[/tex]

mass of KClO₃= 0.7977 grams

Then, 0.7977 grams of KClO₃ are formed from the  reaction of 2.50 g of KClO₄  with 150 mg of FeCl₂  in excess of H₂SO₄.  

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The lab stockroom has a bottle of Sulfuric acid labeled 15.5M. How many mL of water will you need to add to 5.41mL of the acid solution in order to get a concentration of 0.175M?

Answers

The volume of water needed to make the solution is 473.76 mL

We'll begin by calculating the volume of the diluted solution.

Molarity of stock solution (M₁) = 15.5 MVolume of stock solution needed (V₁) = 5.41 mL Molarity of diluted solution (M₂) = 0.175 MVolume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

15.5 × 5.41 = 0.175 × V₂

83.855 = 0.175 × V₂

Divide both side by 0.175

V₂ = 83.855 / 0.175

V₂ = 479.17 mL

Finally, we shall determine the volume of water needed.

Volume of stock solution needed (V₁) = 5.41 mLVolume of diluted solution (V₂) = 479.17 mLVolume of water =?

Volume of water = V₂ – V₁

Volume of water = 479.17 – 5.41

Volume of water = 473.76 mL

Therefore, the volume of the water needed is 473.76 mL

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Nitrogen H2 has :

a)Double bonds

b)Bounded by 6 electrons

c) The bond is ionic

d) Can forms der Waals bonds

e) B& d​

Answers

Answer:

the bond is ionic

Explanation:

How many valence electrons are there in the molecule CH3OCH2CH3.

Answers

Answer:

There are 27 Valence electrons : )

4+1+1+1+6+4+1+1+4+1+1+1 is 27

Explanation:

There are a total of [5×1]+[2×4]+[7]=21[5×1]+[2 × 4 ] + [ 7]=21 valence electrons

can some vitamins be considered water-soluble and others fat soluble?​

Answers

Answer:

Vitamins are classified as either fat soluble (vitamins A, D, E and K) or water soluble (vitamins B and C). This difference between the two groups is very important. It determines how each vitamin acts within the body.

Calculate the mass percentage of each element in aluminum oxide.

Answers

Answer:

So, Percentage Composition of Aluminium = 2778×100%=34.62% (approx.) Percentage Composition of Oxygen = 3×1678×100%=61.54% (approx.)

What volume of 0.826 MKOH solution do you need to make 3.74 L of a solution with a pH of 12.500?

Answers

Given that –

pH = 12.5

We know that –

pH + pOH = 14

Then –

[tex]\qquad[/tex][tex]\bf\longrightarrow pOH = 14 -12.5 [/tex]

[tex]\qquad[/tex][tex]\sf \longrightarrow pOH = 1.5[/tex]

[tex]\qquad[/tex][tex]\sf \longrightarrow [OH^- ] = 10^{-1.5 }[/tex]

[tex]\qquad[/tex][tex]\bf \longrightarrow [OH^-] = 3.16 × 10^{-2}[/tex]

Now the number of moles of KOH need to ensure that concentration of Hydroxide anions is equal to –

[tex]\qquad[/tex][tex]\bf \longrightarrow 3.74\: L \times \dfrac{3.16× 10^{-2}}{1 \: L }[/tex]

[tex]\qquad[/tex][tex]\bf \longrightarrow 1. 18 × 10^{-1 }M [/tex]

Volume of the solution contains the need number of moles of Hydroxide anions –

[tex]\qquad[/tex][tex]\sf \longrightarrow \dfrac{ 1.18×10^{-1} \: moles \: OH^-}{0.826 \: moles \: OH^-}[/tex]

[tex]\qquad[/tex][tex]\sf \longrightarrow 0.143 L [/tex]

[tex]\qquad[/tex][tex]\sf \longrightarrow 0.143 \times 1000[/tex]

[tex]\qquad[/tex][tex]\pink{\bf\longrightarrow 143 mL }[/tex]

______________________________________

Use the heat equation to find out how many joules of energy are needed
to raise the temperature of 67 grams of water form 20°C - 45°C. What is the
answer in kilojoules?
(specific heat of water is 4.2 J/gºC.)

Answers

Answer:

About 7.0 × 10³ J or 7.0 kJ

Explanation:

We want to determine the amount of energy needed to raise the temperature of 67 grams of water from 20°C to 45°C.

We can use the heat equation:

[tex]\displaystyle q = mC\Delta T[/tex]

Where C is the specific heat of water.

Substitute and evaluate:

[tex]\displaystyle \begin{aligned} q & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)\left(45^\circ \text{ C}- 20.^\circ\text{ C}\right) \\ \\ & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)(25^\circ \text{ C}) \\ \\ & = 7.0\times 10^3 \text{ J}\end{aligned}[/tex]

Recall that there are 1000 J in a kJ. Hence:

[tex]\displaystyle \begin{aligned} q & = 7.0\times 10^3 \text{ J} \cdot \frac{1\text{ kJ}}{1000\text{ J}} \\ \\ & = 7.0 \text{ kJ}\end{aligned}[/tex]

In conclusion, it will take about 7.0 × 10³ J or 7.0 kJ of energy to raise the temperature of 67 grams of water from 20 °C to 45 °C.

I need help with this question.

Answers

The London forces designated as A are much weaker than the dipole- dipole interaction designated as B.

The intermolecular forces are interactions that exists between molecules of a substance in a particular state of matter. The nature of intermolecular forces in a substance greatly affect the properties of the substance.

We can see that A represents weak London forces while B represents dipole - dipole interactions. The London forces are very much weaker than the dipole - dipole interactions.

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how many molecule are there in 24.0 L of oxygen gas at standard temperature and pressure

Answers

There are 6.44 × 10²³ molecules in 24.0 L of oxygen gas at standard temperature and pressure.

HOW TO CALCULATE NUMBER OF MOLECULES:

To calculate the number of molecules in a substance, we need the number of moles. The number of moles can be calculated using ideal gas law equation as follows:

PV = nRT

Where;

P = pressureV = volumen = number of molesT = temperatureR = gas law constant

According to this question, oxygen gas is at standard temperature (273K) and pressure (1 atm)

1 × 24 = n × 0.0821 × 273

24 = 22.4n

n = 24 ÷ 22.4

n = 1.07moles

To calculate the number of molecules, we multiply the no. of moles by Avogadro's number (6.02 × 10²³)

no. of molecules = 1.07 × 6.02 × 10²³

no. of molecules = 6.44 × 10²³

Therefore, there are 6.44 × 10²³ molecules in 24.0 L of oxygen gas at standard temperature and pressure.

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Select True or False: Consider the reaction N2(g) 3H2(g) 2NH3(g). The production of ammonia is an exothermic reaction. When heat is added to the equilibrium system it will shift to increase the amount of ammonia produced.

Answers

Answer:

False

Explanation:

As I like to think of it, equilibrium will shift either 'forwards' (to increase products) or 'backwards' (to increase reactants) to oppose any change in system;

If heat is added, the equilibrium will shift in the direction that reduces heat within the system;

In other words, it will shift in favour of the endothermic reaction, i.e. the reaction where heat is gained by the molecules/atoms and therefore taken out from the system;

If the 'forwards' reaction, producing NH₃, is exothermic (i.e. energy is released in the reaction), then the 'backwards' reaction is endothermic;

So the equilibrium will shift in this direction, which is the reaction of 2 NH₃ molecules producing N₂ and 3 H₂

Which of the compounds, C4H10, BaSO4, Zn(CN)2, Al(OH)3, contain an anion with a -1 charge?

Answers

Answer:

b

Explanation:

OH and CN both have -1 charges

Pressure is exerted in all directions when an object is in fluid/water. *


A. True
B. False

Answers

Answer:

False

Explanation:

Fluid pressure has no direction, being a scalar quantity, whereas the forces due to pressure have well-defined directions: They are always exerted perpendicular to any surface. The reason is that fluids cannot withstand or exert shearing forces.

This is false hope this helps

What kind of intermolecular forces act between two chloramine (NH2CI) molecules?

Answers

Explanation:

brain and heart froce acts between two chloramine

Answer:

Dispersion, Hydrogen-bonding, and Dipole forces act between two chloramine (NH2CI) molecules.

Explanation:

Dispersion is exerted between all molecules. Chloramine is polar, therefore dipole forces are present. The molecular geometry of chloramine (NH2Cl) is a trigonal pyramidal, therefore hydrogen-bonding forces are present.

. What mass of ammonium chloride must be added to 250. mL of water to give a solution with pH
4.85? [Kb(NH3) = 1.8 x 10-1
a. 4.7 g
b. 75 g
c.2.3 x 10-ºg
d. 19 g
e.10g

Answers

The mass of ammonium chloride that must be added is : ( A ) 4.7 g

Given data :

Volume of water ( V )  = 250 mL = 0.25 L

pH of solution = 4.85

Kb = 1.8 * 10⁻⁵

Kw = 10⁻¹⁴

Given that the dissolution of NH₄Cl gives NH₄⁺⁺ and Cl⁻ ions the equation is written as :

NH₄CI  +  H₂O  ⇄  NH₃ + H₃O⁺

where conc of H₃O⁺

[ H₃O⁺ ] = [tex]\sqrt{Ka.C}[/tex]   and Ka = Kw / Kb

∴ Ka = 5.56 * 10⁻¹⁰

Next step : Determine the concentration of H₃O⁺  in the solution

pH = - log [ H₃O⁺ ] = 4.85

∴ [ H₃O⁺ ] in the solution = 1.14125 * 10⁻⁵

Next step : Determine the concentration of NH₄CI in the solution

C = [ H₃O⁺ ]² / Ka

  = ( 1.14125 * 10⁻⁵ )² /  5.56 * 10⁻¹⁰

  = 0.359 mol / L

Determine the number of moles of NH₄CI in the solution

n = C . V

  = 0.359 mol / L  * 0.25 L =  0.08979 mole

Final step : determine the mass of ammonium chloride that must be added to 250 mL

mass = n * molar mass

         = 0.08979 * 53.5 g/mol

         = 4.80 g  ≈ 4.7 grams

Therefore we can conclude that the mass of ammonium chloride that must be added is 4.7 g

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A) Oxygen
B) Sulfur
C) nitrogen
D) no elements have that mass

Answers

Answer:

The answer would be oxygen.

A student was asked to determine the concentration of ammonia, a volatile substance used in the clinical setting as a respiretory stimulant to prevent fainting. First the student pipetted 25.00 mL of the cloudy ammonia solution into a 250.0 mL conical flask. 50.00 mL of 0.100 mol L' HCl(aq) was immediately added to the conical flask which reacted with the ammonia in solution. The excess (unreacted) HCI was then titrated with 0.050 mol L- Na2CO3(aq). 21.50 mL of Na2CO3(aq) was required. Calculate the concentration of the ammonia in the cloudy ammonia solution.​

Answers

This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.

First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

[tex]2HCl+Na_2CO_3\rightarrow 2NaCl+CO_2+H_2O[/tex]

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

[tex]V_{HCl}^{leftover}=\frac{2*0.050M*21.50mL}{0.100M} =21.5mL[/tex]

Next, we infer that the consumed volume of HCl by the ammonia solution was:

[tex]V_{HCl}^{consumed}=50.00mL-21.50mL=28.5 mL[/tex]

Then, we write the chemical equation that takes place between ammonia and HCl:

[tex]HCl+NH_3\rightarrow NH_4Cl[/tex]

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

[tex]M_{NH_3}=\frac{28.5mL*0.100M}{25.00mL}\\\\ M_{NH_3}=0.114M[/tex]

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An element's atomic number represents
the number of protons found in that element
the number of protons and electrons found in that element
the number of protons and neutrons found in that element
the number of electrons found in that element

Answers

the second options

the number of protons and electrons found in that element

The atomic number is the amount of protons in the atoms nucleus. The mass number is the amount of protons and neutrons in the atoms nucleus. Hope this helps! :)

the weak base ionization constant (ka) for h2c2o4 is equal to what?

Answers

The acid ionization constant is the quantitative measure of the acidic strength. For oxalic acid, Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

What is acid dissociation?

Acid dissociation (Ka) is the ratio of the concentration of the conjugate base and hydrogen ion to the concentration of the chemical.

Oxalic acid is a weak acid and gets dissociated as:

H₂C₂O₄ ⇌ H⁺ + HC₂O₄⁻

or

HC₂O₄⁻ ⇌ H⁺ + C₂O₄²⁻

The acid ionization constant for the reactant and the product is given as:

Ka = [H⁺] [A⁻] / [HA]

Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Therefore, the ionization constant for oxalic acid is given as Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

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If I place an egg in carbonated water will the egg gain or lose mass?

Answers

Answer:

The egg will gain mass.

Explanation:

Eggs soaked in distilled water will gain mass and appear dramatically swollen.

Answer:

Gain mass

Explanation:

Carbonated water will create a reaction inside the egg making the fluid inside the egg becoming more solid thus gaining mass

Hope this helps!

Why would other scientist want to see observations from your three trials

Answers

Answer:

When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events and are reliable. Multiple trials can be done at one time. E.g. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.

Hope that helped.x

A mixture of 0.384 M H2O, 0.384 M Cl2O, and 0.652 M HClO are placed in a vessel at 25 oC. Calculate the equilibrium concentration (in molarity) of HClO at the same temperature.

Answers

Equilibrium concentration of HOCl at 25°C is 0.140 M

The equation of the reaction at equilibrium is given below:

H₂O (g) + Cl₂O (g) ⇄ 2 HOCl (g)

Equilibrium constant, Kc = 0.0900 at 25°C

An ICE chart for the reaction is set up below

     H₂O (g)  +  Cl₂O (g)   ⇄  2 HOCl (g)

I     0.384        0.384             0.652

C     -x                -x                   + 2x

E    0.384 - x   0.384 - x       0.652 + 2x

The equation of the equilibrium constant is given as;

Kc = [tex]\frac{[HOCl]^2}{[H_{2}O][Cl_{2}O]}[/tex]

substituting the values into the equation:

Kc = [tex]\frac{(0.652 + 2x)^2}{( 0.384 - x)( 0.384 - x)}[/tex] = 0.0900

4x² + 2.608x + 0.425 = 0.0900 (0.147 - 0.768x + x²)

4x² - 0.09x² + 2.677x - 0.069x + 0.425 - 0.013 = 0

3.910x² + 2.677x + 0.412 = 0

Solving using the quadratic formula:

a = 3.910, b = 2.677, c = 0.412

x = [tex]\frac{-2.677\±\sqrt{2.677^2 - 4*3.910*0.412}}{2*3.910}[/tex]

x = -0.256 or -0.431

The negative sign indicates that equilibrium is to the left of the reaction

Since x cannot be greater than 0.384, x = -0.256.

Equilibrium concentration of HOCl = 0.652 + 2(-0.256)

Equilibrium concentration of HOCl at 25°C is 0.140 M

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hello guys what is good!

What are all the elements of the P block?

Answers

boron, carbon, nitrogen, oxygen and flourine families in addition to the noble gases.

_________________________________________________________

also to answer the 'hello guys what is good!':nothin u?

__________________________________________

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Heart, 5 stars, and Brainiest to first right answer!

(Explanation problem) Can you list two ways in which the biosphere would be impacted if there were no hydrosphere.

Answers

Answer:

Without the hydrosphere, the atmosphere will no longer be able to carry up the evaporated water, as well as pour down the water, leaving the biosphere to rot away. The hydrosphere works with the Biosphere to provide the requirement of water to the organisms needs, as well as the hydrosphere assisting in photosnythesis.

Explanation:

Answer:

The hydrosphere refers to the water on the earth crust. If there were no hydrosphere, we would not have lakes, oceans, rivers, or even a hose full of water. There would also be no life. Nothing can live without water, so nothing would have evolved.  

Explanation:

 

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