What is the balanced equation of
H2 + Cl2 —-> HCl

Answers

Answer 1

Answer:

The balanced equation of H2 + Cl2 —-> HCl is 2H2 + 2Cl2 —-> 2HCl.

Explanation:

In a chemical reaction, the number of atoms of each element must be the same on both sides of the equation. In this case, there are two atoms of hydrogen on the left side and two atoms of chlorine. On the right side, there is one atom of hydrogen and one atom of chlorine. In order to balance the equation, we must add another chlorine atom to the right side so that there are two atoms of chlorine on both sides of the equation. The final balanced equation is 2H2 + 2Cl2 —-> 2HCl.


Related Questions

electronic configuration of organic compounds

Answers

The electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

What is electronic configuration?

The expression 'electronic configuration' makes reference to the spacial arrangement of electrons in distinct energy orbitals of an atom/molecule.

The orbitals are designed with numbers and letters, whereas the amount of electrons in each orbital is expressed as superscripts (e.g., 1s² 2s² 2p² in the C atom that form glucose).

In conclusion, electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

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A student performs the following lead extraction to test the stoichiometric method and to determine the efficiency of the reaction. In the reaction 49.5 g of lead(II) nitrate is reacted with excess zinc in a single displacement reaction.

a. Calculate the theoretical yield of lead in the experiment.
b. After separating the lead by filtration and allowing it to dry, the student obtains 19.8g of lead. What is the percent yield of the experiment?

Answers

Theoretical yield produced is 31.8 gram and the percentage yield is 62.27%.

The zinc (Zn) is more reactive than lead (Pb). So that zinc loses electrons more easily than lead .

And the electrons of Zn are transfer to lead in this reaction .

This question is a limiting reactant question .

And For limiting reactant questions so that we need to determine that how much product can be produced by all reactant .

Zinc and Lead (II) nitrate react to form Zinc Nitrate and Lead.

Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb

Now we have- Weight of Pb(NO₃)₂ = 49.5 g

molar mass of Pb(NO₃)₂ = 331.2 g

now moles of Pb(NO₃)₂ = 49.5 ÷ 331.2 = 0.15 moles

Moles of Pb consumed = 1 × 0.15 = 0.15

moles mass of Pb consumed = 0.15 × 207.2 = 31.8 gm

Here Zn is in excess so that lead(II) nitrate is a limiting reactant.

(a) Theoretical yield of lead -  

moles of Pb produced = 0.15 × 1  = 0.15 moles

molar mass of Pb = 207.2g

mass of Pb produced in reaction = 0.15 × 207.2   = 31.08 g

theoretical yield = 31.8 gram

(b) After separating the lead by filtration -

obtained lead = 19.8gm

Percentage yield = 19.8 ÷ 31.8 ×100 = 62.27%

so that after separating the lead the percentage yield is 62.27%.

So, After applying the concepts of stoichiometric method the theoretical yield produced came out to be 31.8 gram and the percentage yield came out to be 62.27%.

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How many atoms are there in 65.89 g of lead?

Answers

Answer:

1.915 x 10²³ atoms Pb

Explanation:

To find the amount of atoms, you need to (1) convert grams to moles (via atomic mass of lead) and then (2) convert moles to atoms (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 4 sig figs to match the given value (65.89 g).

Atomic Mass (Pb): 207.20 g/mol

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

65.89 g Pb           1 mole             6.022 x 10²³ atoms
------------------  x  ----------------  x  -------------------------------  =  1.915 x 10²³ atoms Pb
                            207.20 g                  1 mole

What is hypotheses
?

Answers

Answer:

is an assumption , in an idea that is proposed for the sake of argument so that it can be tested to see if it might be true.

아 이거 끝이 없어

it’s an assumption or prediction for the experiment before you do it

Consider the reaction below.

Upper N a superscript plus, plus upper C subscript 2 upper H subscript 3 upper O subscript 2 superscript minus (a q) plus upper H superscript plus, plus upper C l superscript minus right arrow upper N a superscript plus, plus upper C l superscript minus plus upper H upper subscript 2 upper H subscript 3 upper O subscript 2.

Which is the net ionic equation for the reaction?

Answers

Answer:

D.) C₂H₃O₂⁻ (aq) + H⁺ ---> HC₂H₃O₂

Explanation:

The net ionic equation shows the compounds/elements that directly involved in the reaction. These substances can be determined depending on where and how many times they appear in the equation. If the compounds/elements appear on both the reactants and products side of the equation, they will not be found it the net ionic equation.

Expanded Equation:

Na⁺ + C₂H₃O₂⁻ (aq) + H⁺ + Cl⁻ ---> Na⁺ + Cl⁻ + HC₂H₃O₂

Net Ionic Equation:

C₂H₃O₂⁻ (aq) + H⁺ ---> HC₂H₃O₂

Therefore, since Na⁺ and Cl⁻ are located on both sides, they are eliminated. This leaves only the C₂H₃O₂⁻ (aq), H⁺, and HC₂H₃O₂ left in the net ionic equation.

In a constant‑pressure calorimeter, 55.0 mL of 0.310 M Ba(OH)2 was added to 55.0 mL of 0.620 M HCl.
The reaction caused the temperature of the solution to rise from 24.25 ∘C to 28.47 ∘C. If the solution has the same density and specific heat as water ( 1.00 g/mL and 4.184J/g⋅°C,) respectively), what is Δ for this reaction (per mole H2O produced)? Assume that the total volume is the sum of the individual volumes.

Answers

The enthalpy change (ΔH) for the reaction (per mole H₂O produced) is 56.96 KJ/mol

How to determine the mass of the solutionVolume = 55 + 55 = 110 mLDensity = 1 g/mLMass = ?

Mass = density × volume

Mass = 1 × 110

Mass = 110 g

How to determine the heat Mass (M) = 110 gInitial temperature (T₁) = 24.25 °C Final temperature (T₂) = 28.47 °CChange in temperature (ΔT) = 28.47 – 24.25 = 4.22 °C Specific heat capacity (C) = 4.184 J/gºC Heat (Q) =?

Q = MCΔT

Q = 110 × 4.184 × 4.22

Q = 1942.2128 J

How to determine the mole of H₂O produced

Ba(OH)₂ + 2HCl --> BaCl₂ + 2H₂O

Since the reaction occurs in a constant‑pressure calorimeter, it means both reactants are sufficient enough for the reaction.

Mole of Ba(OH)₂ = molarity × volume

Mole of Ba(OH)₂ = 0.310 × (55 / 1000)

Mole of Ba(OH)₂ = 0.01705 mole

From the balanced equation above,

1 mole of Ba(OH)₂ reacted to produce 2 moles of H₂O.

Therefore,

0.01705 mole of Ba(OH)₂ will react to produce = 0.01705 × 2 = 0.0341 mole of H₂O.

How to determine the enthalpy change ΔH per mole of H₂O producedHeat (Q) = 1942.2128 JMole of H₂O (n) = 0.0341 moleEnthalpy change (ΔH) =?

ΔH = Q / n

ΔH = 1942.2128 / 0.0341

ΔH = 56956.29 J/mol

Divide by 1000 to express in KJ/mol

ΔH = 56956.29 / 1000

ΔH = 56.96 KJ/mol

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In the preparation of the soap above, a student dissolved 5 g of NaOH in 25 mL water and added 10 mL palm kernel oil (density: 0.997 g/cm3). The mixture was heated and boiled with 20 mL of water, followed by addition of NaCl to the soap solution. At the end of the experiment, the student obtained 6.2 g of soap What is the percentage yield of the soap?

Answers

The  Percent yield of  soap is 17.8%

What is the percent yield of soap?

Percent yield is given as follows:

Percent yield = actual yield/expected yield * 100%

The actual yield of soap = 6.2 g

The expected yield is determined from the equation of the reaction.

The equation of the reaction is given as follows:

NaOH + CH₃(CH₂)₁₄COOH ----> CH₃(CH₂)₁₄COONa + H₂O

Molar mass of (palm kernel oil) CH₃(CH₂)₁₄COOH = 256 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of (soap) CH₃(CH₂)₁₄COONa = 278 g/mol

Mass of palm kernel oil = 9.9 g

Expected mass of soap = 5/40 * 278 = 34.75 g

Percent yield = 6.2/34.75 * 100 = 17.8%

Therefore, the Percent yield of  soap is 17.8%

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How much does 2.3 moles of Mg(NO2)2 weigh?

Answers

Answer:

mass = 266.8 g

Explanation:

mass = no. of moles  x   molar mass ([tex]M_r[/tex])

[tex]M_r \space\ \space\ of[/tex] [tex]Mg(NO_2)_2[/tex]   = 24 + 2[14 + 2(16)]

                                 = 116

∴ mass = 2.3  x  116

            = 266.8 g

Uric acid can collect in joints, giving rise to a medical condition known as gout. If the pKa of uric acid is 3.89, what is the pH of a 0.0140 M solution of uric acid?

Answers

Answer:

The pH of the solution is 2.873

Explanation:

Given:

Pka = 3.89pH of a 0.0140 M

Let the solution of the uric acid be HA. We have to set up the ICE table as follows;

        HA(aq) + H20(l)  ⇄ H3O^+(aq)  + A^-

I         0.0140                       0                 0

C       -x                                +x                +x

E    0.0140 - x                      x                   x

Ka = 10^-(pka)

    = 10^-3.89

    = 1.28 x 10^-4

Ka = [H+] * [A-]/[HA]

=> 1.28 x 10^-4 = [H+]^2 / 0.0140

=>[H+]^2 = 1.28 x 10^-4 x 0.014

=> [ H+] = 1.338656 x 10^-3

so pH = - log [ H+ ] =  - log  1.338656 x 10^-3

= 3 - log 1.338656

= 2.87333101111

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A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held constant, to what temperature must the He be raised to cause the container to expand to a final volume of 1.50 L?

Answers

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C

percent composition of Mg(OH)2​

Answers

Answer:

The composition of Mg(OH)2 is

41.67 % Mg,

54.87 % O

3.457 % H

Explanation:

Thats the percent composition for each one in your question

Answer:

Hello! The answer to your question is:

Mg: 41.68%

O2: 54.86%

H2: 3.46%

Explanation:

We need to find the percent composition of each element, so first, we need to find the molar mass. This is calculated by using the number underneath the element. The "2" outside of the parentheses is distributed to Oxygen and Hydrogen as well-meaning that you multiply the number by 2:

Mg: 24.31 g/mol

O2: 16.00 × 2 = 32.00 g/mol

H2: 1.01 × 2 = 2.02 g/mol

Now, we have to add up the molar mass of each element:

24.31 g/mol + 32.00 g/mol + 2.02 g/mol = 58.33

To find the percent composition of each element, you have to divide the molar mass of each element by the total molar mass:

Mg: [tex]\frac{24.31 g/mol}{58.33 g/mol} \\= 41.68 percent[/tex]

O2: [tex]\frac{32.00 g/mol}{58.33 g/mol} \\= 54.86 percent[/tex]

H2: [tex]\frac{2.02 g/mol}{58.33 g/mol} \\= 3.46 percent[/tex]

The percent composition of each element is:

Mg: 41.68%

O2: 54.86%

H2: 3.46%

The compound HgO can be decomposed to form Hg and O2. This can be represented at the atomic level by a chemical equation:
2HgO 2Hg + O2

According to the law of conservation of mass, if 23.5 grams of HgO decomposes and 21.8 grams of Hg is formed, how many grams of O2 must simultaneously be formed?

Answers

According to the law of conservation of mass 1.7 grams of [tex]O_2[/tex] will be formed.

What are moles?

A mole is defined as 6.02214076 × 1[tex]0^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]2HgO[/tex]→ [tex]2Hg + O_2[/tex]

According to the laws of conservation mass of reactants should be equal to the mass of products.

23.5 grams - 21.8 grams

1.7 grams of [tex]O_2[/tex] will be formed.

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Discuss why the solubility of CaCO33(s) would be greater in distilled water than in tap water that contains 50 mg/L of calcium ions (Ksp CaCO3 = 8.7x10-9).

Answers

Answer:

mitxtitsixitdkgxgxmhhxlyfuldyooyddryodyoodyyodroydgodydout70r9ryiryogiustoydotsixulslysrluhsro6rh zpyrqujs7t7wiyidiey9ye9yd96d9ydoydoydodyoydoydoyydgkxyodigggoydyoydyyo

Explanation:

uodigdoydoydohhxoydoydodkgdyodisirs85ssto toutuset8itgxotteotsmvtieksititsgie8e85t8upfgtjwdujhftisnfvoyxuvfgkrtj57lhmdkhflfheogkhptufsjfxocljhflhfoydllbxoydoggsigxitieoyurreifosuuluprohgsjtgjzffgfhcpzfjchzjfcg gsjiggdoydogxlhd6oxhx9yfljf

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater.

What is solubility?

The capability of a substance, the solvent, to combine with another substance, the solvent, has been known as solubility. Insolubility, or just the solute's inability to create that kind of a solution, would be the opposite attribute.

How does solubility depend on the ionic compound?

Ionic chemicals dissolve readily in just about any liquid that has the ability to rupture the ionic link present in them. Since water itself has a stronger ionic bond and is still polar in nature, water disrupts the ionic link by hydrogen bonding. Several other solvents, like kerosene and gasoline, are unable to dissolve the ionic bond.

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater in distilled water than in tap water that contains 50 mg/L of calcium ions

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How much would a 55 kg person weigh on venus

Answers

Answer:

109.988623 Pounds or 49.89kg

Explanation:

49.73 kg!

Weight on Venus= (Weight on Earth/9.81m/s2) * 8.87m/s2

2FeCl + 3Na2CO2= Fe2 (CO3)3 + 6NaCl
If you begin a reaction with 127.490 g of Na2CO3, how many moles of NaCl can you theoretically produce, assuming an excess of FeCl3 is present?
I need help

Answers

Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

Reaction stoichiometry

In first place, the balanced reaction is:

2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

FeCl: 2 moles Na₂CO₂: 3 molesFe₂(CO₃)₃: 1 moleNaCl: 6 moles

The molar mass of the compounds is:

FeCl: 91.3 g/moleNa₂CO₂: 106 g/moleFe₂(CO₃)₃: 291.7 g/moleNaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

FeCl: 2 moles ×91.3 g/mole= 182.6 gramsNa₂CO₂: 3 moles ×106 g/mole= 318 gramsFe₂(CO₃)₃: 1 mole ×291.7 g/mole= 291.7 gramsNaCl: 6 moles ×58.45 g/mole= 350.7 grams

Mass of NaCl produced

The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?

[tex]moles of NaCl=\frac{127.49 grams of Na_{2} CO_{2} x6 moles of NaCl }{318grams of Na_{2} CO_{2} }[/tex]

moles of NaCl= 2.405 moles

Then, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

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1. Balance the equation below: Fe(s) + Cl₂(g) → FeCl3(aq) 2. Calculate the moles of FeCl3 that will form if 2.0 moles of Fe react with sufficient Cl₂. 3. Calculate the moles of FeCl3 that will form if 1.0 moles of each reactant mix together. 4. How many grams of FeCl3 that will form if 1.0 g of each reactant mix?​

Answers

Answer:

1.) 2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

2.) 2.0 moles FeCl₃

3.) 0.67 moles FeCl₃

4.) 1.5 g FeCl₃

Explanation:

1.)

The unbalanced reaction:

Fe (s) + Cl₂ (g) ---> FeCl₃ (aq)

Reactants: 1 iron, 2 chlorine

Products: 1 iron, 3 chlorine

The balanced reaction:

2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

Reactants: 2 iron, 6 chlorine

Products: 2 iron, 6 chlorine

2.)

To find moles FeCl₃, you need to multiply the given value by the mole-to-mole ratio of Fe to FeCl₃. This ratio is constructed via the coefficients from the balanced equation.

2.0 moles Fe          2 moles FeCl₃
---------------------  x  ------------------------  = 2.0 moles FeCl
                                 2 moles Fe

3.)

To determine how much FeCl₃ is produced, you need to identify the limiting reagent. To find it, you need to convert both reactants to the product then identify which reactant gives you the smallest amount of product. This reactant is the limiting reagent and will give you your actual answer.

1.0 mole Fe         2 moles FeCl₃
-------------------  x  -----------------------  = 1.0 moles FeCl
                               2 moles Fe

1.0 mole Cl₂         2 moles FeCl₃
-------------------  x  ------------------------  = 0.67 moles FeCl
                              3 moles Cl₂

4.)

Because Cl₂ is the limiting reagent, we need to convert grams Cl₂ to grams FeCl₃. This can be done using the molar masses of both compounds and the mole-to-mole ratio.

Molar Mass (Cl₂): 2(35.453 g/mol)

Molar Mass (Cl₂): 70.906 g/mol

Molar Mass (FeCl₃): 55.845 g/mol + 3(35.453 g/mol)

Molar Mass (FeCl₃): 162.204 g/mol

1.0 g Cl₂          1 mole             2 moles FeCl₃         162.204 g
-------------  x  -----------------  x  -----------------------  x  ------------------  =  1.5 g FeCl
                      70.906 g            3 moles Cl₂              1 mole


Identify the nitrogen compound represented by the formula NO2.
Nitrous oxide
Nitrite
ammonia
nitrate

Answers

Answer:

Nitrite

Explanation:

Nitrous Oxide = N₂O

Nitrite = NO₂

Ammonia = NH₃

Nitrate = NO₃⁻

Perform the calculation to the correct number of significant figures. (8.81 - 7.50)/0.0020

Answers

Answer:

655

Explanation:

using bodmas, (bracket first), 8.81-7.50=1.31

1.31÷0.0020=655

a compound with a molar mass of 92g/mol contains 0.3955g of nitrogen and 0.904g of oxygen. Determine the empirical and molecular formula

Answers

Answer:

Empirical: NO2. Molecular: N2O4

Explanation:

In order to determine the empirical formula, we divide each element's mass by their respective molar mass:

N: 0.3955g/14.01 g/mol = 0.02823 mol

O: 0.904g/16.00 g/mol = 0.0565 mol

Next, we take the smallest value and multiply it till it is close enough to an integer:

0.02823 x 40 = 1.12 Close enough to 1.

0.0565 x 40 = 2.26. Close enough to 2.

Therefore, the Empirical Formula is: NO2

Next, we determine how much the Empirical formula weighs and see if it matches 92g/mol:

14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol

We can assume this is roughly half of 92 g/mol so we can multiply each subscript by 2 to match the weight.

Therefore, the Molecular formula is N2O4

Hope this helped!

How many kilojoules of heat would be required to fully melt a 0.834 m³ block of ice , provided that the density of ice is 917 kg / m³ ? H₂O ( s ) → H₂O ( 1 ) AH = 6.01 kJ

Answers

2.54 × 10⁵ kJ of heat are required to fully melt a 0.834 m³ block of ice, with a density of 917 kg / m³.

What is melting?

Melting is a physical change in which solids turn into liquids.

Step 1. Calculate the mass of ice.

We have a block of 0.834 m³ of ice with a density of 917 kg/m³.

0.834 m³ × 917 kg/m³ = 765 kg = 7.65 × 10⁵ g

Step 2. Convert 7.65 × 10⁵ g to moles.

We will use the molar mass of water.

7.65 × 10⁵ g × (1 mol/18,02 g) = 4.24 × 10⁴ mol

Step 3. Calculate the heat required to melt 4.24 × 10⁴ moles of water.

According to the thermochemical equation, 6.01 kJ are required to melt 1 mol of water.

4.24 × 10⁴ mol × (6.01 kJ/mol) = 2.54 × 10⁵ kJ

2.54 × 10⁵ kJ of heat are required to fully melt a 0.834 m³ block of ice, with a density of 917 kg / m³.

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The table shows the thermodynamic data for a reaction.

Thermodynamic Data
Energy of the Reactants Energy of the Products Activation Energy
−420 kJ −240 kJ −310 kJ


Which of the following statements explains if the reaction is endothermic or exothermic?

Answers

The true statement about this chemical reaction is that: D. the change in enthalpy is +180 kJ, so it is an endothermic reaction.

How to determine the type of reaction?

In order to determine whether this chemical reaction is endothermic or exothermic, we would determine the change in enthalpy as follows:

The change in enthalpy = The energy of products - the energy of reactants

Substituting the given parameters into the formula, we have;

The change in enthalpy = -240 - (-420)

The change in enthalpy = -240 + 420

The change in enthalpy = 180 kJ.

Since the change in enthalpy for this chemical reaction, we can infer and logically conclude that it is an endothermic reaction because heat is absorbed.

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Complete Question:

The table shows the thermodynamic data for a reaction.

Thermodynamic Data:

Energy of the Reactants: -420 kJ

Energy of the Products: -240 kJ

Activation Energy: -310 kJ

Which of the following statements explains if the reaction is endothermic or exothermic?

The activation energy is lower than the change in enthalpy, so it is an exothermic reaction.

B. The activation energy is higher than the change in enthalpy, so it is an endothermic reaction.

C. The change in enthalpy is -180 kJ, so it is an exothermic reaction.

D. The change in enthalpy is +180 kJ, so it is an endothermic reaction.

How much pure alcohol is in a 316 mL bottle of a "wine cooler" that is 4.8 percent alcohol by volume?

Answers

Answer:

15.17 ml

Explanation:

4.8 % is .048 in decimal

316 ml  * .048 = 15.17 ml    ( about 1/2 ounce)

A space shuttle gaining speed as it travels through earth's atmosphere? A) 1st Law B) 2nd Law C) 3rd Law​

Answers

Answer is B) Newton’s second law
Reason - Acceleration. Newton's Second Law Equation.

Solve this whole experiment,
I'll be so glad . thanks
●do the above experiment
●give detailed answers
THANKS ​

Answers

Are you saying yes or no to this Bec it’s your prediction

Which of the following equations is correct for coffee-cup calorimeter?
q reaction = q calorimeter
q reaction = -q calorimeter

Answers

The equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter. Details about coffee-cup calorimeter.

What is a calorimeter?

A calorimeter is an apparatus for measuring the heat generated or absorbed by either a chemical reaction, change of phase or some other physical change.

A coffee-cup calorimeter is a specific type of calorimeter that involves the absorption of heat of a reaction by water when a reaction occurs.

The enthalpy change of the reaction is equal in magnitude but opposite in sign to the heat flow for the water:

qreaction = -(qwater)

Therefore, the equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter.

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If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

Answers

Answer:

4.27 L

Explanation:

STP = 0 C   and   1 atm  

P1V1/T1   = P2V2/T2       where T is in Kelvin

P1 V1 / T1   *T2/P2   = V2

.469 * 5 / ( 273.15-123)  *  273.15/1   = V2 = 4.27 L

Consider the following balanced chemical reaction: 2 H2(g) + CO (g) -> CH4O (1). If
6.12 g of H₂ reacts with excess CO, how many grams of CH4O can be produced?
Select one:
a. 16.5g
b. 27.29
c. 64.5g
d. 48.6 g
e. 75.8 g

Answers

Answer:

d

Explanation:

2H₂(g) +CO(g) → CH₄O (l)

Since H₂ was reacted with excess CO, H₂ is the limiting reagent. This means that the amount of product formed is dependent on the amount, i.e. the number of moles, of H₂.

The number of moles of H₂ can be calculated by taking the mass divided by its Mr (relative molecular mass).

Mr of H₂= 2(1)= 2

Moles of H₂ (g)

= 6.12 ÷2

= 3.06 mol

From the balanced equation, 2 moles of H₂(g) produces 1 mole of CH₄O(g).

Since we have 3.06 moles of H₂(g),

Moles of CH₄O (l) produced

= 3.06 ÷2

= 1.53 mol

Mr of CH₄O

= 12 +4 +16

= 32

Mass= mole ×Mr

Mass of CH₄O (l) produced

= 1.53(32)

= 48.96 g

Thus, d would be the best option.

when 1 mol of glucose is burned, 2802.5kj of energy is released. calculate rhe quantity of energy released to a person by eating 5.00g of glucose in a candy

Answers

77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

What are moles?

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{5.00g}{180.156 g/mol}[/tex]

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

Learn more about moles here:

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what is the frequency of a photon with an energy of 4.56 x 10-19J?

Answers

Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

Hope its helpful!

Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

Please provide a synthesis for the following molecules with the provided starting material.

Answers

Answer:

Attached Below

Explanation:

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