What is the area of a quadrilateral with vertices at (1,6),(7,6),(1,12),(7,12)?

Answers

Answer 1

Answer:

Let us consider the quadrilateral ABCD shown below. 

Let us consider the quadrilateral ABCD shown below. 

In the above quadrilateral, A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) are the vertices.

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. 

Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

(x1y2 + x2y3 + x3y4 + x4y1) -----(1)

Add the diagonal products x2y1, x3y2, x4y3 and x1y4 are shown in the dotted arrows.

(x2y1 + x3y2 + x4y3 + x1y4) -----(2)

Subtract (2) from (1) and multiply the difference by 1/2 to get area of the quadrilateral ABCD.

So, area of the quadrilateral ABCD is

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

Problem :

Find the area of the quadrilateral whose vertices are

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Solution : 

Let A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Plot A, B, C and D in a rough diagram and take them in counter-clockwise order.

Then,

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area of triangle ABC is 

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So, area of the given quadrilateral is 28 square units.

In the above quadrilateral, A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) are the vertices.

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. 

Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

(x1y2 + x2y3 + x3y4 + x4y1) -----(1)

Add the diagonal products x2y1, x3y2, x4y3 and x1y4 are shown in the dotted arrows.

(x2y1 + x3y2 + x4y3 + x1y4) -----(2)

Subtract (2) from (1) and multiply the difference by 1/2 to get area of the quadrilateral ABCD.

So, area of the quadrilateral ABCD is

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

Problem :

Find the area of the quadrilateral whose vertices are

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Solution : 

Let A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Plot A, B, C and D in a rough diagram and take them in counter-clockwise order.

Then,

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area of triangle ABC is 

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So, area of the given quadrilateral is 28 square units.

Answer 2

The area of the given quadrilateral with vertices at (1,6),(7,6),(1,12),(7,12) is 28 square units.

Let the quadrilateral be ABCD.

What is a quadrilateral?

Any closed figure made by 4 line segments joined end to end in series is called a quadrilateral.

We need the area of the quadrilateral whose vertices are;

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Let; A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Then, we have;

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area =  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So,

The area of the given quadrilateral with vertices at (1,6),(7,6),(1,12),(7,12) is 28 square units.

Learn more about quadrilaterals here:

https://brainly.com/question/1365755

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The regression equation for change in temperature, y, to amount of rain, r, is given by ŷ = 0.2 − 1.4r. On Monday, the observed amount of rain was 0.4 inches and the temperature change was 2.3 degrees. Find and interpret the residual.

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Answers

Given:

The regression equation for change in temperature, y, to amount of rain, r, is given by

[tex]\hat{y}=0.2-1.4r[/tex]

The observed amount of rain was 0.4 inches and the temperature change was 2.3 degrees.

To find:

The residual and interpret it.

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According to the question, the observed amount of rain was 0.4 inches and the temperature change was 2.3 degrees.

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[tex]\hat{y}=0.2-1.4(0.4)[/tex]

[tex]\hat{y}=0.2-0.56[/tex]

[tex]\hat{y}=-0.36[/tex]

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