what is chemical name of ghee​

Answer:

Examples of chemical properties include flammability, toxicity, acidity, reactivity (many types), and heat of combustion.

A dry cell is one type of electric battery which is generally used for the home and portable electronic devices. A battery is a device which consists of one or more electrochemical cells. The site of oxidation occurs in solid zinc layer. The correct option is A.

A dry cell is defined as an electrochemical cell which consists of low moisture immobilized electrolytes in the form of a paste which restricts it from flowing. It is developed by the German scientist Carl Gassner which converts chemical energy into electrical energy.

A dry cell consists of a metal container in which a low moisture electrolyte paste covers the graphite rod or a metal electrode. Generally, the metal container will be zinc whose base perform as the negative electrode (anode).

For a dry cell battery to operate, oxidation  will occur from the zinc anode and reduction will take place in the cathode.

Thus the correct option is A.

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Explanation:

As I think Option C is correct i.e. NH4+.

Answer:

22.67 L of PH₃

Explanation:

The balanced equation is:

[tex]P_4 (s) + 6H_2(g) \to 4PH_3(g)[/tex]

From the equation:

[tex]34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}[/tex]

= 22.67 L of PH₃

Answer:

number of moles of (N) = 0.794 moles

Explanation:

From the given information:

no of moles of nitrogen (N) = (unknown)???

mass of nitrogen = 13.5 g

molar mass of NH3 = 14 +( 1 × 3) = 17 g/mol

To calculate the no of moles of N, we have:

number of moles of (N) = mass of N/molar mass

number of moles of (N) = 13.5 g/17 g/mol

number of moles of (N) = 0.794 moles

The sun is the source, and the change is damage

Answer:

M = 1.4 M

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to calculate the required molarity according to its definition:

[tex]M=\frac{n}{V}[/tex]

Whereas the n is mole and has a value of 0.7 mol, V the volume in liters, which is 0.5 L; therefore, the result is:

[tex]M=\frac{0.7mol}{0.5L} \\\\M=1.4 M[/tex]

Regards!

Answer:

Option C is the answer

Butene, also called Butylene, 4 isomeric compound belonging to the series of olefinic hydrocarbons. The chemical formula is C4H8, option c is correct.

Butene, also called Butylene, four isomeric Combinations belong to the series of olefinic hydrocarbons. The chemical formula is C4H8.

The isomeric forms are 1-butene, cis-2-butene, trans-2-butene, and isobutylene.

Thus, option "C" is correct. the chemical formula is C4H8.

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Answer:

six cookies?(1 cal _4.184 j; ALSO: 1 Calorie -1 kilocalorie)

Answer:

four

is the answer

Answer:

12000j

mass=1500kg

velocity=4m/s

Kinetic Energy (K E) = 1/2 mv^2

=1/2*1500(4^2)

=1*750*16

=12000j

Answer: The standard state refers to 1 atm and [tex]25^{o}C[/tex].

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of [tex]25^{o}C[/tex] then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and [tex]25^{o}C[/tex].

Answer:

400k

Explanation:

volume is constant

P1/T1=P2/T2

1.5/100=6/T2

T2=(100×6)/1.5

T2=400k

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45° Celsius

Formula (113°F − 32) × 5/9 = 45°C

Answer:

moles MgCl₂ = 5.97 moles

Explanation:

First, let0s write the overall reaction that is taking place here:

Mg(OH)₂ + HCl ----------> MgCl₂ + H₂O

Now, we need to balance this reaction:

Mg(OH)₂ + 2HCl ----------> MgCl₂ + 2H₂O

Now, the exercise already stated that the HCl is in excess, so we can assume the magnesium hydroxide is the limiting reactant. If this is true, then, to get the moles of MgCl₂ produced, all we need to do is calculate the moles of Mg(OH)₂ that reacted, using the following expression:

moles = mass / MM

The atomic weights for Mg, O and H are:

Mg: 24.305 g/mol;  H: 1 g/mol;  O = 15.999 g/mol

Let's determine the molar mass of Mg(OH)₂:

MM = 24.305 + (2 * 15.999) + (2 * 1) = 58.303 g/mol

Now, let's determine the moles:

moles = 348 g / 58.303 g/mol = 5.97 moles of Mg(OH)₂

As we can see in the overall reaction, there is a mole ration between Mg(OH)₂ and MgCl₂ of 1:1, that's why we can conclude that the moles of Mg(OH)₂ would be the same moles of MgCl₂:

Hope this helps

Answer:

[Your answer would be in this document of mine below] Thanks :D

Explanation:

Answer:

500J (joules)

Explanation:

since heat is is the product of mass, change in temperature, and specific heat, the solution can be found from the equation q = mcΔt, heat is 50 * .5 * 20 = 500J

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Definition:-

The organ of government that primarily looks after the function of implementation and administration is called the executive.

Function:-

Executive is the branch of government responsible for the implementation of laws and policies adopted by the legislature.

Answer:

W = 615.91 kJ

Explanation:

We need to use the following expression:

W = ΔG° * mol   (1)

But in order to determine the ΔG° we need the following expression:

ΔG° = -n * F * E°   (2)

Where F is a constant and is 96,500 J/V mol

n is the number of transferred electrons in the reaction. As we are passing from Al to Al³⁺ we can say that the number of electrons are 3.

Finally to get the moles, we need the the atomic weight of aluminum which is 26.98 g/mol, so the moles:

moles = m/MM   (3)

Let's calculate the moles of aluminum:

moles = 50 / 26.98 = 1.85 moles of aluminum

Now let's calculate the gibbs energy using (2):

ΔG° = -3 * 96,500 * 1.15

ΔG° = -332,925 J or simply -332.925 kJ/mol

Finally, using (1) we can determine the work done:

W = 332.925 * 1.85

Hope this helps

The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

The cell potential, Ecell, is the measure of the potential difference between two half cells in an electrochemical cell.

Expression for work done ;

W = ΔG° x mol   (1)

But, to determine the ΔG°

ΔG° = -n x F x E°   (2)

Where,

(As there is variation from Al to Al³⁺ the change in number of electrons are 3)

To get the moles,

moles = m/MM  (3)

moles = 50 / 26.98 = 1.85 moles of aluminum

Now,

ΔG° = -3 x 96,500 x 1.15

ΔG° = -332,925 J  

       = -332.925 kJ/mol

Now, using (1) we can determine the work done:

W = 332.925 x 1.85

W = 615.91 kJ

Hence, The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

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Plants!

No doubt the answer is plants they are one maintaining the temperature, responsible for rains too...

Answer:

190 L

Explanation:

Given that:

Number of moles = mass/molar mass

number of moles = 5.64

molar mass of aluminum chloride = 133.34 g/mol

∴

The balanced equation is:

2 Al + 3 Cl2 --> 2AlCl3.

From above reaction:

5.64 mole of  AlCl3 reacts with 3 mole Cl2  to give 2 mole AlCl3

i.e

[tex](5.64 \ mole \ AlCl3) \times (3 \ mole \ Cl2 \ / \ 2 \ mole \ AlCl3)[/tex]

= 8.46 mole Cl2 gas.

At Standard temperature and pressure:

= (22.4 L/1 mole gas) * (8.46 mole Cl2)

= 190 L chlorine gas

Answer:

Please find the solution in the attached file.

Explanation:

The two chairs of the confirmation of the alpha glucose were defined in the attached file.  

The correct answer is

C. -112.0 J/mol K