Mount Everest is 29,029 feet high. What is
the height of Mount Everest in kilometers?
Answer:
8.849 kilometres
Explanation:
this is the height in kilometers
100 Points PLZ HELP!
Using the ideal Gas Law (PV=nRT), solve for the missing variable. R=0.08206 atm*L/mol*k
At what temperature will 0.654 moles of neon gas occupy 15.66 liters and 0.899 atmospheres?
Answer:
C
Explanation:
Which is an example of a chemical reaction?
A) Tearing up your last science test.
B) Eating a antacid to calm your upset stomach. C) Rubbing your hands together to warm them. D) Pouring water on a cut to wash off the germs.
Answer:
B) Eating a antacid to calm your upset stomach.
Explanation:
Priscilla was building a circuit that used copper wires to connect a battery to a light bulb. As she connected the final wire from the light bulb back to the battery, the light bulb turned on. Priscilla knew that current was now flowing through her closed circuit. What makes the current in the circuit flow? pls help !!!
Answer:
The voltage or potential difference
Explanation:
What makes current flow in a circuit is the voltage or the potential difference.
This force is supplied by the battery or the mains electrical circuit.
Every circuit requires the voltage to drive current through When a circuit is complete, the battery is able to overcome any resistance by the generating enough voltage which is the force to drive the current through.dicyclopropyl ether?
Answer:
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Explanation:
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Select the correct number of valence electrons, in order, for groups 13-18.
13, 14, 15, 16, 17, 18
5, 6, 4, 3, 8,7
3,4,5,6,7,8
18, 13, 15, 16, 17, 14
Answer:
3,4,5,6,7,8
Explanation:
Groups 13 - 18 are the main group on the periodic table
The group number corresponds the number of valence electrons they contains.
Valence electrons are the number of electrons in the outermost shell of an atom.
So group 13 - 18 corresponds to a valency of 3,4,5,6,7,8.
Groups with a valency of 8 are the noble gases.
Kp/Kc for reaction for the equilibrium, A(g) ⇌ C(g)+B(g), is _______.
(Kc is the equilibrium constant in terms of concentrations, Kp is the equilibrium constant in terms of pressures, R is the gas constant, T is the temperature)
Select one:
(RT)2
(RT)-1
(RT)-2
(RT)-1.5
RT
RT
by using relation between Kp and Kc we get the above answer
What kind of intermolecular forces act between a hydrogen cyanide molecule and a potassium cation?
If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force.
(dipole, hydrogen-bonding, dispersion, ion-dipole)
Answer:
ion-dipole
Explanation:
Let us remember that the potassium cation is an ion, a positive ion to be precise.
There is a dipole existing in the hydrogen cyanide molecule. The positive end of the dipole is on hydrogen while the negative end of the dipole is on the cyanide moiety.
The only possible interaction between the potassium cation and the hydrogen cyanide is an ion dipole interaction. The cation interacts with the cyanide moiety having a partial negative charge in the molecule.
Many organisms have adaptations which allow them to live in certain environments.
Which structural adaptation would an organism living in a pond most likely develop
if it adapted to a land environment?
A.lungs
B.wings
C.webbed feet
D.sharp eyesight
Answer:
Webbed Feet
Explanation:
Webbed Feet Benefits:
Most animals with webbed feet are aquatic animals who live in, on, or near the water. Webbed feet help them move quickly through the water when they're chasing food or trying to escape from predators.
When fat comes in contact with sodium hydroxide, it produces soap and glycerin. Determine whether this is a physical change or a chemical change. Explain your
Answer: Chemical change
Explanation:
Physical change is a change where there is a change in size , shape etc and no new products are formed.
Chemical change is a change where there is a change in chemical composition as new products are formed.
Example: Formation of soap and glycerin from fat and sodium hydroxide is a chemical change as the chemical bonds are getting rearranged to form new products.
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The diagram below shows a beaker with two compartments separated by a semipermeable membrane.
The membrane does not allow salt particles to pass through.
What will most likely be observed in the beaker?
Water level will rise in compartment X.
Water level will rise in compartment Y.
Water level remains same as water cannot pass through.
Water level remains same as there is no difference in the concentration gradient.
Answer: D
Explanation: I took the quiz! Module 04.06! Have a good day!
Answer: Water level remains same as there is no difference in concentration gradient.
Explanation: When concentration inside and outside of the cell membrane is the same, no transport takes place and the levels will remain the same.
what is the mole fraction of cation in 1M of aluminium sulphate
The mole fraction of cation (Al)=0.4
Further explanationGiven
1 M of Aluminium sulphate
Required
The mole fraction of cation
Solution
Ionization of the Aluminum sulfate solution( assume 1 L solution ) :
mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol
Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻
1 mol 2 mol 3 mol
From this equation, total mol in solution = 2+3 = 5 moles
Mol fraction Al(as a cation) :
= 2/5=0.4
Does a ticking clock involves energy?
Answer:
yes
Explanation:
How many grams of Fe3+ are present in 2.56 grams of iron(III) iodide?
Answer:
436.55841 grams.
Explanation:
The molecular formula for Iron(III) Iodide is FeI3. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Iron(III) Iodide, or 436.55841 grams.
You use the 1 / 436.55841 conversion rate. This is different for each element, according to the stoichiometry tables. Iron(II) oxide would be 2/3 of the 1/436.55841 conversion rate, that is, multiplying the fraction to denominator.
Kp/Kc for reaction for the equilibrium, A(g) ⇌ C(g)+B(g), is _______.
(Kc is the equilibrium constant in terms of concentrations, Kp is the equilibrium constant in terms of pressures, R is the gas constant, T is the temperature)
Select one:
(RT)2
(RT)-1
(RT)-2
(RT)-1.5
RT
Kp/Kc = RT
Further explanationGiven
Reaction
A(g) ⇌ C(g)+B(g)
Required
Kp/Kc
Solution
For reaction :
pA + qB ⇒ mC + nD
[tex]\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}[/tex]
While the equilibrium constant Kp is based on the partial pressure
[tex]\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}[/tex]
The value of Kp and Kc can be linked to the formula '
[tex]\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}[/tex]
R = gas constant = 0.0821 L.atm / mol.K
Δn=moles products - moles reactants or
number of product coefficients-number of reactant coefficients
For reaction :
A(g) ⇌ C(g)+B(g)
number of product coefficients = 1+1=2
number of reactant coefficients = 1
Δn= 2 - 1 =1
So Kp/Kc = RT
FUСR THE WORLD SAY AND TO 4142-414=? HELPPPPPPPPPPPPP
Answer:
UMMMMMMMMMMM
Explanation:
Answer:
3729
Explanation:
A chemist adds of a potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask. Round your answer to significant digits.
Answer:
3.41 g
Explanation:
A chemist adds 260.0 mL of a 0.0832M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask. Round your answer to 3 significant digits.
Step 1: Given data
Volume of the solution (V): 260.0 mL (0.2600 L)
Concentration of the solution (C): 0.0832 M (0.0832 mol/L)
Step 2: Calculate the moles (n) of potassium permanganate added
We will use the following expression.
n = C × V
n = 0.0832 mol/L × 0.2600 L = 0.0216 mol
Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate
The molar mass of potassium permanganate is 158.03 g/mol.
0.0216 mol × 158.03 g/mol = 3.41 g
What is 0.000005670 written in proper scientific notation?
Red blood cells are constantly being produced in your body. Another body system cooperates with the cardiovascular system in the production of these cells. What is this system and how does it cooperate?
Explain how the biogeochemical cycle are essential for life.
Answer: Explain how the biogeochemical cycles are essential for life
Biogeochemical cycles are critical to the existence of life, transforming energy and matter into usable forms to support the functioning of ecosystems, as noted previously. ... Carbon is an essential element in the bodies of all living organisms and an essential source of energy for many organisms.
A student pours a 10.0mL sample of a solution containing HC2H3O2(pKa=4.8) and NaC2H3O2 into a test tube. The student adds a few drops of bromocresol green to the test tube and observes a yellow color, which indicates that the pH of the solution is less than 3.8 . Based on this result, which of the following is true about the relative concentrations of HC2H3O2 and NaC2H3O2 in the original solution?
Answer:
[HC2H3O2] > NaC2H3O2
Explanation:
The concentration of [tex]\rm HC_2H_3O_2[/tex] has been higher than the concentration of [tex]\rm NaC_2H_3O_2[/tex].
The pKa has been defined as the acid constant that has been used for the determination of the strength of the acid. The higher the pKa value, the weaker the acid has been.
The [tex]\rm HC_2H_3O_2[/tex] has the pka value 4.8 depicting the solution has been a pH 4.8. With the addition of [tex]\rm NaC_2H_3O_2[/tex], the pH has been shifted towards the acidic condition, thus the Hydrogen concentration has been higher.
The change in the pH has been resulted in the reduction in the pH from the basic to acidic condition. Since the concentration of the [tex]\rm HC_2H_3O_2[/tex] has been higher than the [tex]\rm NaC_2H_3O_2[/tex] concentration, the pH has been shifted towards the more acidic condition.
Thus, the concentration of [tex]\rm HC_2H_3O_2[/tex] has been higher than the concentration of [tex]\rm NaC_2H_3O_2[/tex].
For more information about the pH of the solution, refer to the link;
https://brainly.com/question/11936640
How many moles of copper are in 1.51 x 1024 Cu atoms?
2.51 mol Cu
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
1.51 × 10²⁴ atoms Cu
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
Set up: [tex]\displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})[/tex]Multiply/Divide: [tex]\displaystyle 2.50747 \ mol \ Cu[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
2.50747 mol Cu ≈ 2.51 mol Cu
BRAINLLEST! Boiling water for mac and cheese is a physical change. Give 2 pieces of evidence to support this claim
Answer:
In explanation.
Explanation:
Physical changes are generally changes in states of matter. So, the water going from liquid to gas is a phase change and therefore physical. (It's still water, just in a different form). Im not sure about the second piece of evidence though. Unless you are talking about the Mac and Cheese which in that case is also a physical change as the two ingredients cheese and macaroni stay the same when cooked just become softer and edible.
A dolphin travels a distance 20 miles up the coastline in 153 minutes. If 1 mile is equal to
1609 meters, then what is the dolphin's average speed in meters/second rounded to the
nearest tenth?
+/-
HELP ME PLEASE
Answer:
3.51m/s
Explanation:
Given parameters:
Distance = 20miles
Miles to meters:
1 mile = 1609m
20miles = 20 x 1609 = 32180m
Time = 153minutes
1 min = 60s
153min = 60 x 153 = 9180s
Unknown:
Average speed = ?
Solution:
To solve this problem;
Average speed = [tex]\frac{distance }{time taken}[/tex]
Average speed = [tex]\frac{32180}{9180}[/tex] = 3.51m/s
If you have 2 moles of an element, how many particles do you have?
Answer:
1.204×10^24 particles of element
Explanation:
1mol=6.02×10^23 number of particles (in this case an element)
2mol=(6.02×10^23)×2 particles of the element
=1.204×10^24 particles of element
*be careful aware significant digits
A student collected a 1.28 g sample of Magnesium. How many atoms of Mg are in his sample?
A student did an experiment that called for 1.24 x 1024 molecules of CaO. What is the mass of her reactant?
A student reacted 0.0405 g of glucose (C6H12O6). How many molecules of glucose did he react?
Can I please Get Help with this question ♂️ ?
Answer:
Mg(NO4)2 is 180.3 g/mol
Explanation:
First find the substance formula.
Magnesium Nitrate.
Magnesium is a +2 charge.
Nitrate is a -1 charge.
So to balance the chemical formula,
We need 1 magnesium atom for every nitrate atom.
2(1) + 1(-2) = 0
So the substance formula is Mg(NO4)2.
Now find the molar mass of Mg(NO4)2.
Mg = 24.3 amu
N = 14.0 amu
O = 16.0 amu
They are three nitrogen and twelve oxygen atoms.
So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol
So the molar is mass is 180.3 g/mol.
The final answer is Mg(NO4)2 is 180.3 g/mol
Hope it helped!
The metal rhenium becomes superconducting at temperatures below 1.4 K. Calculate the temperature at which rhenium becomes superconducting in degrees Celsius.
Answer:
The temperature at which rhenium becomes superconducting is -271.6 ºC.
Explanation:
We can convert the temperature given in Kelvin, which is an absolute scale, into degrees Celsius. which is a relative scale, by a simple algebraic translation, that is:
[tex]T_{C} = T_{K} - 273[/tex] (1)
Where:
[tex]T_{C}[/tex] - Temperature, measured in degrees Celsius.
[tex]T_{K}[/tex] - Temperature, measured in Kelvins.
If we know that [tex]T_{K} = 1.4\,K[/tex], then the temperature given in degrees Celsius is:
[tex]T_{C} = 1.4\,K-273[/tex]
[tex]T_{C} = -271.6\,^{\circ}C[/tex]
The temperature at which rhenium becomes superconducting is -271.6 ºC.
How did the grandmother show her gratitude towards her granddaughter
answer this and in end please tell me how to mark answer as brainliest I will mark your answers as brainliest
Answer:
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Which of the following is an internal adaptation that enables birds to fly?
A. Feathers
B. Hollow bones
C. Sharp beaks
D. Sharp claws