Answer:
1/4 of an hour is 15 minutes
Step-by-step explanation:
Answer: 1/4 of an hr
Step-by-step explanation:
15/60 is 1/4
Which data set is the most clustered around its mean?
A.4, 10, 8, 6
B.11, 3, 10, 4
C.2, 9 ,13, 4
D.11, 2, 9, 6
The data set is the most clustered around its mean is
A.4, 10, 8, 6
How to find the dataTo determine which data set is the most clustered around its mean, we can calculate the mean and the standard deviation for each data set.
calculate the mean and standard deviation for each data set
Data Set A: 4, 10, 8, 6
Mean: (4 + 10 + 8 + 6) / 4 = 28 / 4 = 7
Standard Deviation: √[(4-7)^2 + (10-7)^2 + (8-7)^2 + (6-7)^2] / 4 ≈ 1.58
Data Set B: 11, 3, 10, 4
Mean: (11 + 3 + 10 + 4) / 4 = 28 / 4 = 7
Standard Deviation: √[(11-7)^2 + (3-7)^2 + (10-7)^2 + (4-7)^2] / 4 ≈ 3.87
Data Set C: 2, 9, 13, 4
Mean: (2 + 9 + 13 + 4) / 4 = 28 / 4 = 7
Standard Deviation: √[(2-7)^2 + (9-7)^2 + (13-7)^2 + (4-7)^2] / 4 ≈ 4.27
Data Set D: 11, 2, 9, 6
Mean: (11 + 2 + 9 + 6) / 4 = 28 / 4 = 7
Standard Deviation: √[(11-7)^2 + (2-7)^2 + (9-7)^2 + (6-7)^2] / 4 ≈ 3.27
Comparing the standard deviations, we find that data set A has the smallest standard deviation of approximately 1.58. this indicates that the data points in Data Set A are the closest to the mean, making it the most clustered around its mean.
Therefore, the answer is A. 4, 10, 8, 6.
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This equation shows how the cost of a corporate team-building event depends on the number
of attendees d=5a + 3 the variable represents the number of attendees and the variable d represents the cost in dollars. If there are 3 attendees, how much will the corporate team-building event cost?
MY HEALTH TEACHER JUST DEFIED MATH APARENTLY 1+1=3 NOT 2
WHAT DOES SOMEONE SAY TO THAT
Answer:
I honestly am very confused
Step-by-step explanation:
Let U CC be a region containing D(0; 1) and let f be a meromorphic function on U, which has no zeros and no poles on aD(0; 1). If f has a zero at 0 and if Ref(z) > 0 for every ze aD(0; 1), show that f has a pole in D(0; 1).
It is proved that if f has a zero at 0 and if Ref(z) > 0 for every ze aD(0; 1), then f has a pole in D(0; 1).
The problem is based on Complex Analysis.
Let U CC be a region containing D(0; 1) and let f be a meromorphic function on U, which has no zeros and no poles on aD(0; 1).
If f has a zero at 0 and if Ref(z) > 0 for every ze aD(0; 1), we need to prove that f has a pole in D(0; 1).
We know that f is meromorphic function on U and we are given that it has a zero at 0. So, we can write the Laurent expansion of f around 0 as: f(z) = anzn+ ... + a1z + a0 + b1z + ... where an ≠ 0 and the expansion is valid in a deleted neighborhood of z=0. This implies that f(z) has a pole of order m at 0 where m is the largest non-negative integer such that am ≠ 0.
Suppose that m = 0 and f(z) has a removable singularity at 0 then by Riemann’s theorem f(z) is bounded in some deleted neighborhood of z = 0 which implies that Ref(z) ≤ M, a contradiction to Ref(z) > 0 for every ze aD(0; 1).
Hence, f(z) has a pole at 0. Therefore, f has a pole in D(0; 1). Hence, we have proved that if f has a zero at 0 and if Ref(z) > 0 for every ze aD(0; 1), then f has a pole in D(0; 1).
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use the image to answer the question.
A landscaper is building a triangular garden behind a house. The lot is bounded on one side by the house
that is 30 ft. long and on another side by a fence that is 50 ft. long. If the fence makes a 25° angle with the
house, how long is the third side of the garden? Round your answer to the nearest foot.
a. 26 ft.
b. 46 ft.
c. 69 ft.
d. 78 ft.
Answer: 26ft
Step-by-step explanation:
Recall that, fixed a set U (which we call the universe of discourse), we have certain operations on subsets of U so that, for all A, B, C CU the following equivalences and equalities hold. >> AC BUC, ABCC CCA⇒B >> CnACB, A" = A, (AUB)* = A*n B', (An B)* = A*UB*. ACB →B'CA, You can answer just one of the following parts, not both. You can support your answer with drawings of Venn diagrams, but you need to give an argument according to the specifications for full credit. (a) Prove that for any given sets A, BCU, we have that B\A= (AB)* using only the above equations and equivalences. (Hint: Notice that two sets X, Y CU are equal if and only if, for every CCU, we have XCC YCC.) (b) Prove that for any given sets A, BCU, we have that B* A* = (AB)* using the definitions of the operations (). \, and in terms of the elements of U, A, and B.
(a) To prove that B\A = (AB)* using only the above equations and equivalences, we need to show that B\A is equivalent to (AB)*.
First, we will show that B\A is a subset of (AB)*.
Let x be an element of B\A. Then, x is in B and x is not in A. Therefore, x is in AB and not in A. This means that x is in (AB)*. Thus, we have shown that B\A is a subset of (AB)*.
Next, we will show that (AB)* is a subset of B\A.
Let x be an element of (AB)*. Then, x is in AB or x is not in AB.
If x is in AB, then x is in B and x is in A. Therefore, x is not in B\A.
If x is not in AB, then x is not in A or x is not in B. Therefore, x is not in A and x is in B. This means that x is in B\A.
Thus, we have shown that (AB)* is a subset of B\A.
Since we have shown that B\A is a subset of (AB)* and (AB)* is a subset of B\A, we can conclude that B\A = (AB)*.
(b) To prove that B* A* = (AB)*, we need to show that B* A* is a subset of (AB)* and (AB)* is a subset of B* A*.
First, we will show that B* A* is a subset of (AB)*.
Let x be an element of B* A*. Then, x is in (B*) and x is in (A*).
If x is in B*, then x is in B or x is not in B.
If x is in A*, then x is in A or x is not in A.
If x is in B and x is in A, then x is in AB.
If x is not in B and x is not in A, then x is not in AB.
If x is in B and x is not in A, then x is in B\A.
If x is not in B and x is in A, then x is in A\B.
Therefore, we have shown that x is in (AB)*.
Next
Decide whether it is possible for a triangle to have the three angle measures or three side lengths given.
If it is possible, then decide whether all such triangles are congruent.
Answer:
Step-by-step explanation:
the first one cant be a triangle
im pretty sure the second one can
the third one can
im pretty sure the fourth one cant
- Which is the inverse or the funcion f(x)=x²-16?
Given:
The function is:
[tex]f(x)=x^2-16[/tex]
To find:
The inverse of the function.
Solution:
We have,
[tex]f(x)=x^2-16[/tex]
Step 1: Substitute [tex]f(x)=y[/tex].
[tex]y=x^2-16[/tex]
Step 2: Interchange x and y.
[tex]x=y^2-16[/tex]
Step 3: Isolate y.
[tex]x+16=y^2[/tex]
[tex]\pm \sqrt{x+16}=y[/tex]
[tex]y=\pm \sqrt{x+16}[/tex]
Step 4: Substitute [tex]y=f^{-1}(x)[/tex].
[tex]f^{-1}(x)=\pm \sqrt{x+16}[/tex]
Therefore, the inverse function of the given function is [tex]f^{-1}(x)=\pm \sqrt{x+16}[/tex].
What does this mean and how do I do it
Answer:
Step-by-step explanation:
The degree of f(x) is 0.
Its leading coefficient is 13 and the type is constant. Because the function is constant,
f(x = 13 when x --> -∞ and
f(x) = 13 when x --> ∞ .
(How? Because I'm smart like that!! :D)
Using a standard deck of 52 cards, what is the probability that a
randomly dealt 6-card hand contains all hearts?
The probability that a randomly dealt 6-card hand contains all hearts is approximately 0.0000844, or about 0.00844%.
To calculate the probability of a randomly dealt 6-card hand containing all hearts, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Favorable outcomes: A 6-card hand containing all hearts consists of 6 hearts from the deck.
There are 13 hearts in a standard deck of 52 cards, so we can choose 6 hearts from the 13 available. This can be calculated using combinations:
Number of favorable outcomes = C(13, 6) = 13! / (6! × (13 - 6)!) = 13! / (6! × 7!) = 1716
Total number of possible outcomes: The total number of 6-card hands that can be dealt from a standard deck of 52 cards is C(52, 6):
Number of possible outcomes = C(52, 6) = 52! / (6! × (52 - 6)!) = 52! / (6! × 46!) = 20358520
Therefore, the probability of a randomly dealt 6-card hand containing all hearts is:
Probability = Number of favorable outcomes / Number of possible outcomes = 1716 / 20358520 ≈ 0.0000844
So, the probability is approximately 0.0000844, or about 0.00844%.
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last question 100 pts pleasee
Sum of two interiors =Exterior
Use simple way
Angle beside x
180-(30+14)180-44136Measure of x
180-13644°Answer:
x = 44°
Step-by-step explanation:
According to the Exterior Angle Theorem of a triangle, the external angle is equal to the sum of the two interior opposite angles of a triangle.
This is because the interior angles of a triangle sum to 180° and angles on a straight line sum to 180°.
⇒ x = ∠CAB + ∠BCA
⇒ x = 14° + 30°
⇒ x = 44°
Proof
Interior angles of a triangle sum to 180°
⇒ ∠CAB + ∠ABC + ∠BCA = 180°
⇒ 14° + ∠ABC + 30° = 180°
⇒ ∠ABC = 180° - 14° - 30°
⇒ ∠ABC = 136°
Angles on a straight line sum to 180°
⇒ ∠ABC + x = 180°
⇒ 136° + x = 180°
⇒ x = 180° - 136°
⇒ x = 44°
Based on the graph below, what is the domain and range of the function?
Answer:
The f(x) domain is the set of all values for the function and the function spectrum is the set of all values for which f is defined.
Step-by-step explanation:
Answer:
Domain = all real numbers
Range = y ≥ -4
Step-by-step explanation:
Domain is the x-values, and for parabolas it is almost always all real numbers.
Range is the y-values, and the lowest it gets is -4.
Use the following graph to solve the equation 3n + 7 = 52
Answer:
[tex]3n + 7 = 52 \\ 3n = 52 - 7 \\ 3n = 45 \\ n = \frac{45}{3} \\ n = 15[/tex]
Graph is not inserted.
consider the points p such that the distance from p to as21, 5, 3d is twice the distance from p to bs6, 2, 22d. show that the set of all such points is a sphere, and find its center and radius.
The center of the sphere can be found by taking the average of the coordinates of points A and B, and the radius of the sphere is half the distance between points A and B.
Let's denote point A as (2, 1, 5) and point B as (6, 2, 22). We want to find the set of points P such that the distance from P to A is twice the distance from P to B.
We can express this condition mathematically as:
|PA| = 2|PB|
Using the distance formula, we can rewrite this equation as:
[tex]\sqrt{(x - 2)^2+ (y - 1)^2 + (z - 5)^2} = 2\sqrt{(x - 6)^2 + (y - 2)^2 + (z - 22)^2}[/tex]
Simplifying the equation, we have:
[tex](x - 2)^2 + (y - 1)^2 + (z - 5)^2 = 4((x - 6)^2 + (y - 2)^2 + (z - 22)^2)[/tex]
Expanding and combining like terms, we get:
[tex]3x^2 + 3y^2 + 3z^2 - 28x - 10y - 96z = 273[/tex]
This equation represents the equation of a sphere. The center of the sphere can be found by taking the average of the coordinates of points A and B, which gives us the center (4, 1.5, 13.5). The radius of the sphere is half the distance between points A and B, which is the square root of 273 divided by 2.
Therefore, the set of all points satisfying the given condition is a sphere with center (4, 1.5, 13.5) and radius √(273/2).
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Suppose you bought a sofa for a tota purchase price of $1,254.07. State taxes were 7%. What was the amount or the sales tax?
The amount of sales tax is $87.79.
Given a total purchase price of a sofa as $1,254.07 and state taxes of 7%.
We are required to calculate the amount of sales tax.
The amount of sales tax can be calculated by multiplying the purchase price by the sales tax rate.
Let's represent the sales tax rate by `r`.
Therefore, the sales tax formula is expressed as:
Sales tax = r * purchase price
In this case, the rate of the sales tax `r` is 7%.
Therefore, we have:r = 7% = 0.07
Now we substitute the values given into the formula:
Sales tax = 0.07 * $1,254.07= $87.79
Therefore, the amount of sales tax is $87.79.
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A family of 10 purchased tickets to the county fair. Tickets for adults cost $6 and tickets for children cost $3. If the total cost of the tickets was $42, how many family members were adults and children?
The family members were 3 adults and 2 children.
We have given that the,
A family of 10 purchased tickets to the county fair.
Tickets for adults cost $6 and tickets for children cost $3
Total cost is $42.
We have to determine how many family members were adults and children
What is the next step from the given condition?
(3 x 10) + (2 x 6)
30+12=42
Therefore we get 3 adults and 2 children.
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Question 6 of 20 :
Select the best answer for the question
6. The solution to 2 x 27 will be what kind of number?
A. Even
B. Odd
C. Prime
D. Perfect square
Mark for review (Will be highlighted on the review page)
<< Previous Question
NexhQuestion >>
Answer:
The answer is A. (an even number)
Step-by-step explanation:
2 x 27 is equivalent to 54 and 54 is an even number.
I NEED HELP REALLY FAST AND EXPLAIN HOW YOU SOLVED IT PLEASE
Answer:
C
Step-by-step explanation:
All you do is take the number choices and plug it into the equation. For example if you take A and plug it in the equation would look like -5(-5) < 25 and -5 times -5 is 25 so you know 25 is equal to 25 not less than.
If you plug in C you get -5(-4) < 25 and -5 times -4 is 20 and 20 is indeed less than 25
what is the distance between (5, 1), (5.-6)
Can I get help with number 14
Answer:
A
Step-by-step explanation:
-y = -2x+5
y = 2x-5
3x+2(2x-5)= -3
A right rectangular prism has a length of 12 ft, width of 5 1/2 ft, and height of 10 1/2 ft. What is the volume of the prism? Enter the answer in the box.
Answer: The answer is: 693 ft^3 or 693ft cubed
trish wants to buy x oranges and y mangoes which she intends to carry in her bag. Her bag has space for only 6 fruits. Write an inequality to represent this information.
Answer:
x + y [tex]\leq 6[/tex]
Step-by-step explanation:
The amount of Oranges (x) and the amount of Mangoes (y) will add up to be less than or equal to 6.
This condition is represented by the inequality x + y ≤ 6
What is inequality?In mathematics, inequalities specify the connection between two non-equal numbers. Equal does not imply inequality. Typically, we use the "not equal sign ()" to indicate that two values are not equal. But several inequalities are utilized to compare the numbers, whether it is less than or higher than.
In this case, Trish wants to buy x oranges and y mangoes, and she intends to carry them in her bag.
Her bag can hold a maximum of 6 fruits.
Since she wants to buy both types of fruit, the total number of fruits must be less than or equal to 6.
The inequality to represent this situation is:
x + y ≤ 6
This inequality represents that the sum of the number of oranges and mangoes Trish buys should be less than or equal to 6, which is the maximum number of fruits her bag can hold.
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Which of the following has the greatest value.
Answer:
A.
Step-by-step explanation:
The first question equals 729 and it is the highest, I reccomend using photomath.
Anne picked out 3 board games from her cabinet to take to a game night with her friends. She still has more than 10 board games in the cabinet, so she thinks she could bring a few more. Let x represent how many board games were in Anne’s cabinet to start. Which inequality describes the problem?
Answer:
x - 3 > 10
There were more than
13
board games in Anne's cabinet to start.
Step-by-step explanation:
The variable x represents how many board games were in Anne's cabinet to start. Since she has already picked out 3 board games to bring, the expression x–3 represents how many board games are still in the cabinet.
And, since Anne has more than 10 board games still in her cabinet, x–3 must be greater than 10.
This inequality shows the relationship.
x–3>10
Now, solve for x.
x–3
> 10
x–3+3
> 10+3 Add 3 to both sides
x
> 13 Simplify
So, there were more than 13 board games in Anne's cabinet to start.
Find a formula for the nth term in this
arithmetic sequence
(picture is attached)
please help, thank you
Answer:
nth term: n+6
Step-by-step explanation:
a1 gives -7 and a2 gives -1. Let's compare these two numbers. From -7 to -1, we need a +6. Since -7 + 6 = -1.
a2 to a3, -1 + 6 = 5
a3 to a4, -5 + 6 = 11
A statue casts a shadow that is 9 ft long. A boy that is 4 ft tall casts a shadow that is 6 ft long. How tall is the statue?
Answer:
6 feet tall.
Step-by-step explanation:
The boy is 4 ft tall, but he casts a 6 ft long shadow. You need to find how long a shadow would be if a person/thing was just 1 ft tall.
To do this, you would need to divide 4 by 4, and 6 by 4 as well.
6/4 is 1.5, or 1 and a half.
If a person (or a thing) is 1 foot tall, the statue will cast 1 and a half feet long shadow.
The statue casts a 9 ft long shadow.
Since we already figured out 1 ft = 1 and 1/2 ft shadow, and since the statue casts a 9 foot long shadow, you need to divide 9 by 1.5.
(You'll get 6.)
This means that the statue is 6 feet tall, and it casts a 9 foot long shadow.
If you buy one ticket in the Provincial Lottery, then the probability that you will win a prize is 0.11. If you buy one ticket every month for five months, what is the probability that you will win at least one prize?
The probability of winning at least one prize when buying one ticket each month for 5-months is (c) 0.44.
In order to calculate the probability of winning at least one prize when buying one ticket each month for five months, we use the complement rule. The complement of winning at least one prize is not winning any prize.
The probability of not winning any prize in a single month is 1 - 0.11 = 0.89 (because the probability of winning a prize is given as 0.11),
Since the events of not winning a prize in each month are independent, the probability of not winning a prize in all five months is (0.89)⁵,
So, the probability of winning at least one prize is 1 - (0.89)⁵ ≈ 1 - 0.5570 ≈ 0.443 ≈ 0.44,
Therefore, the correct option is (c).
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The given question is incomplete, the complete question is
If you buy one ticket in the Provincial Lottery, then the probability that you will win a prize is 0.11. If you buy one ticket each month for five months,
What is the probability that you will win at least one prize?
(a) 0.55
(b) 0.50
(c) 0.44
(d) 0.45
(e) 0.56
1. A caterer charges a flat fee plus $8.50 per
person. If the total cost for a party of 65 people
was $601.50, how much would they charge for
a party of 150 people?
Answer:
$1,324
Step-by-step explanation:
$8.50 * 65 = $552.50. $601.50 - $552.50 = $49. So the flat fee would be $49.
$8.50* 150 = $1,275. With the flat fee it would be $1,275+$49 = $1,324.
How does an online discussion group differ from one that is held face-to-face?
There is no need for group roles when holding online meetings.
Online discussion groups do not allow members to develop critical thinking skills.
Group members are more likely to bond together as a group online than they would when meeting face-to-face.
Facilitating an online conversation may require even more work, so that participants continue engaging with one
another online.
Answer: Online discussions have a better portrayal of other cultures
Step-by-step explanation:
Unless you are very antisocial then the only good thing that an online group shares is being able to stay safe from corona virus and the ability to speak with each other from different perspectives. Lets say hypothetically I was in a bear watching group where everybody took pictures and discussed bears. If I lived in North Michigan I would see black bears and brown bears. If I lived in more of an arctic region I would see polar bears. You can see how this would throw in a little more content to discuss. Which bears are bigger? Which bears live longer? Which bears have heavier coats? This obviously does not only apply to bears. Books, sports, video games, cars, and more all have different miniature cultures in different states or countries.
Answer:
Facilitating an online conversation may require even more work, so that participants continue engaging with one another online.
Step-by-step explanation:
Assume that C(x) is in dollars and x is the number of units produced and sold. For the total cost function C(x)=0.01x + 0.4x + 50, find AC and C'(x) when x = 90 and Ax=1 AC =$ 1 (Simplify your answer. Type an integer or decimal rounded to two decimal places as needed.) c'(x) when x = 90 is $ . (Type an integer or a decimal.)
The average cost AC when x = 90 is $1, and the derivative C'(x) when x = 90 is $0.41.
The average cost function AC and the derivative of the total cost function C'(x) can be found using the given total cost function C(x) = 0.01x + 0.4x + 50, where x represents the number of units produced and sold.
To find the average cost AC, we divide the total cost C(x) by the quantity x:
AC = C(x) / x
Substituting the given total cost function C(x) = 0.01x + 0.4x + 50, we have:
AC = (0.01x + 0.4x + 50) / x
Simplifying, we get:
AC = (0.41x + 50) / x
When x = 90, we substitute this value into the equation:
AC = (0.41 * 90 + 50) / 90
AC = (36.9 + 50) / 90
AC = 86.9 / 90
AC ≈ $0.97 ≈ $1 (rounded to two decimal places)
To find the derivative C'(x), we differentiate the total cost function C(x) with respect to x:
C'(x) = d/dx (0.01x + 0.4x + 50)
C'(x) = 0.01 + 0.4
C'(x) = 0.41
When x = 90, we substitute this value into the equation:
C'(90) = 0.41
Therefore, the derivative C'(x) when x = 90 is $0.41.
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