What equation(s) could represent the volume of the cylindrical barrel when completely filled with
water?

Answer:

x + 11

x = 6

6 + 11

17

Step-by-step explanation:

Answer: X+11=6+11=17 #5

Step-by-step explanation:

Hope this helps! Have a good day! :)

Answer:57

Step-by-step explanation:

(7 x 9) - (-3 x -2) = 57

Answer:

4b - a = 15

Step-by-step explanation:

if you replace the variables with their equivalent counterparts you get the equation 4(7) - 12 = __ when you do the math make sure to do the parentheses first then subtract, just like in elementary school remember pemdas parentheses, exponents, multiplication, division, addition, subtraction. I hope this helps.

good luck:)

Brainliestttt Plssssssss:)

Answer:

4b - a = 15

Step-by-step explanation:

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Triangles.

Since there is a linear pair with 40° , the another angle will be 140° ,

also the triangle newly formed is a isosceles one,

hence x = 20°

===> x = 20°

Now apply angle sum property of a triangle on, the other one,

we get as, 70+40+y=180

hence, y = 180-110

y = 70°

Hence angle y ==> 70°

Answer:

$282

Step-by-step explanation:

Answer:

Step-by-step explanation:

1) 5a - 2b² + 1

Degree of the polynomial = 2

2) 4x²-3x³ + 2x + 12

-3x³ + 4x² + 2x + 12

Degree of the polynomial = 3

To find the degree of the polynomial, arrange it in descending as per the power of the variables.

The highest power of the variable is the degree of the polynomial.

Answer:

● First part = 2×x = 2x

● Second part= 8×x = 8x

● Third part= 6×x = 6x

Now,

2x+8x+6x = 144

or, 16x= 144

or, x=144/6

or, x=9

therefore, x=9

Answer:

-3r < 33, 3r> -33 and  -r < 11

Step-by-step explanation:

Which of these inequalities are equivalent to r > -11? Check all that apply. -r < 11 3r < -33 3r > -33 -3r < 33 -3r > 33

For the inequality -r < 11

Multiplying both sides by -1 will reverse the sign to have;

-1(-r) > -1(11)

r > -11

for the inequality 3r> -33

Divide bith sides by 3 will not reverse the sign because we are divideing by a positive number

3r/3 > -33/3

r > -11

For the inequality -3r < 33

Divide both sides by -3 will reverse the sign

-3r/-3 > 33/-3

r > -11

Hence the required inequalities are -3r < 33, 3r> -33 and  -r < 11

Answer:

-3r < 33, 3r> -33 and  -r < 11

Step-by-step explanation:

i just took the test

Answer:41.8

Step-by-step explanation:

Answer:

y=3x+5

Step-by-step explanation:

Given:

The selling price of a ratio set = 72.00

Profit percent = 8%

To find:

The cost price for the radio set.

Solution:

Let x be the cost price for the radio set.

Radio set is sold at 8% profit.

[tex]\text{Selling price}=x+\dfrac{8}{100}x[/tex]

[tex]\text{Selling price}=x+0.08x[/tex]

[tex]\text{Selling price}=1.08x[/tex]

The selling price of a ratio set is 72.00.

[tex]72=1.08x[/tex]

[tex]\dfrac{72}{1.08}=x[/tex]

[tex]x=66.666...[/tex]

[tex]x\approx 67[/tex]

Therefore, the cost price for the radio set is 67.

Answer:

170 [tex]cent.^{3}[/tex]

Step-by-step explanation:

If the height is 3 times the radius you can find that by: 3r

r = 3.

So: 3 x 3 = 9

The height is 9 centimeters

Volume of a cylinder (can):

[tex]V= 2\pi rh[/tex]

Plug in what we know

[tex]V = 2 \pi (3) (9)\\V = 54\pi \\V = 169.646\\[/tex]

Rounds to: 170

angle DCF = angle DCE + angle ECF

angle DCF = 75° + 54°

angle DCF = 129°

Measure of < DCF is  [tex]129^{0}[/tex].

A figure which is formed by two rays or lines that shares a common endpoint is called an angle.

According to the figure

< DCE = [tex]75^{0}[/tex]

< ECF = [tex]54^{0}[/tex]

Measure of < DCF = < DCE + < ECF

=  [tex]75^{0}[/tex] +  [tex]54^{0}[/tex]

= [tex]129^{0}[/tex]

Hence, measure of < DCF is  [tex]129^{0}[/tex].

Find out more information about angle here

https://brainly.com/question/7116550

#SPJ2

Answer:

(2, 5) is the correct answer.

Answer:

15000

Step-by-step explanation:

Answer:

15kg = 15,000 grams

Step-by-step explanation:

hope this helped if it did mark brainlest

and let me know

Answer:

Step-by-step explanation:

radius r = 10/2 = 5 ft

height h = 5 ft

Volume = πr²h = π(5²)(5) = 125π ≈ 392.7 ft³

Answer:

A = (9)(12)

Step-by-step explanation:

Answer: [tex]17^{\circ}[/tex]

Step-by-step explanation:

Given

[tex]\angle A=(x+8)^{\circ}[/tex]

[tex]\angle B=(8x+1)^{\circ}[/tex]

Angle A and B are complementary i.e. sum of the two must be [tex]90^{\circ}[/tex]

[tex]\Rightarrow \angle A+\angle B=90^{\circ}\\\Rightarrow x+8+8x+1=90^{\circ}\\\Rightarrow 9x=90-9=81^{\circ}\\\Rightarrow x=9^{\circ}[/tex]

[tex]\therefore \angle A=x+8^{\circ}=9+8\\\Rightarrow \angle A=17^{\circ}[/tex]

Answer:

Step-by-step explanation:

Triangle inequality:

Sum of side lengths of any two sides must be greater than the third side

Option 2

Answer:

2) 7,18,11

Step-by-step explanation:

Because it is the "Correct Answer"

Answer:

210 Hope it helps! if you have any other questions I can help

Answer:

−5.6<−4.2, and −5.6 is located to the left of −4.2

Step-by-step explanation:

Given the statements :

−5.6<−4.2, and −5.6 is located to the left of −4.2 (True) because - 5.6 located to the left of the number line and numbers are arranged from right to left in decreasing order.

−5.6<−4.2, and −5.6 is located to the right of −4.2. (Not true) only the first assertion is correct, - 5.6 < - 4.2, but 5.6 isn't located to the right of - 4.2

−5.6>−4.2, and −5.6 is located to the left of −4.2 (Not true) ; Though 5.6 is located to the left of 4 2, 5.6 is < 4.2

−5.6>−4.2, and −5.6 is located to the right of −4.2. (Not true) ; - 5.6 is < -4.2 and also located to the left of - 4.2

Answer:

exact form- 61/8

mixed number form-7 5/8

?

Step-by-step explanation:

Answer:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Exact Form:

61 /8

Decimal Form:

7.625

Mixed Number Form:

7

5/8

Step-by-step explanation:

Answer:

reeg

Step-by-step explanation:

Answer:

f(x) = 2*cos(4*x) + 4

Step-by-step explanation:

This is obviusly a sinusoidal function, which can be written as:

f(x) = A*cos( w*x ) + M

Where:

A = amplitude

w = angular frequency

M = midline.

Remember that the maximum of a cosine

cos(x) = 1, when x = (2*n)*pi      (for any integer n)

And the minimum is at:

cos(x) = -1, when x = (2*m + 1)*pi    (for any integer m)

Whit this in mind, we know that we have a maximum when:

x = pi

then we want:

w*pi = (2*n)*pi

and a minimum at:

x = -3*pi/4

Then we want

w*(-3*pi/4) = (2*m + 1)*pi

In the minimum case, we have a "4" in the denominator that is kinda unfortunate, so we woud want to take w = 4 in order to remove it, and this will work really well for wath we want, because:

w*pi = 4*pi = (2*2)*pi     (here we have n = 2)

w*(-3*pi/4) = 4*(-3*pi/4) = -3*pi = (2*-2 + 1)*pi   (here we have m = -2)

Then we can take w = 4.

So the function is something like:

f(x) = A*cos(4*x) + M

The amplitude is equal to half of the difference between the maximum and the minimum values of y.

The maximum is:

y = 6

the minimum is:

y = 2

Half of the difference is:

A = (6 - 2)/2 = 2

A = 2

Then our function is:

f(x) = 2*cos(4*x) + M

The value of the midline is equal to the maximum minus the value of the amplitude (or the minimum plus the value of the amplitude)

M = Maximum - A =  6 - 2 = 4

M = Minimum + A =  2 + 2 = 4

Then the function is:

f(x) = 2*cos(4*x) + 4

Answer:

2cos (4/7x - 4pi/7) + 4

Step-by-step explanation:

Answer:

░░░░░▐▀█▀▌░░░░▀█▄░░░

░░░░░▐█▄█▌░░░░░░▀█▄░░

░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░

░░░░▄▄▄██▀▀▀▀░░░░░░░

░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

▄░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take

░░░░░░░▀███▀█░▄░░ Over brainly

░░░░░░▐▌▀▄▀▄▀▐▄░░

░░░░░░▐▀░░░░░░▐▌░░

░░░░░░█░░░░░░░░█

Step-by-step explanation:

Answer:

$0.95

Step-by-step explanation:

Answer:

3 and 1/3

Step-by-step explanation:

Answer:

D. 702square inches

Step-by-step explanation:

1. V=78km^3

2. K=∛9

3. K^3=∛9^3

4.9 x 78=702

Rest of the Key for the test is here:

http://mrsaperez.weebly.com/uploads/1/1/0/5/110500127/t8_review_part_2_key.pdf