What does n equal?
EASY

Answer:

Exact form: p= 3/2

Decimal form: p= 1.5

Mixed Number: p=1 [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Answer:

Hello your question is poorly written attached below is the complete question

answer :  attached below

Step-by-step explanation:

To Prove: Z is located 2/3 of the distance from each vertex of ΔABC to the midpoint of the opposite side. we will apply ; property of bisecting a line , equality theorem , transitive property and similarity theorem

Attached below is the proof

Answer:

15 hours

so, 8 x y = 120

Step-by-step explanation:

[tex]8\sqrt{120} =[/tex] 15

Answer:

24 square kilometers

Step-by-step explanation:

Well, this is a trapezoid. The formula for the area of a trapezoid is 1/2 the height times base one plus base two. In other words, 1/2 h x (base 1 + base 2)

So in this case, the two bases are 4 and 12. So we would add the two bases to get 16. Now, we have to half the height. 3 divided by 1/2 is 1.5. So we then do the last step which is multiplying the height by the two bases. So in other words, 1.5 times 16. And 1.5 times 16 is 24. Therefore, the answer is 24 sqaure kilometers.

Answer:

Step-by-step explanation:

Answer:

Equate the divisor to 0

2x-1=0

2×=1

×=1/2

Putting onto the polynomial

f(1/2) = (1/2)³-1/2)²+3(1/2)-2

=-5/8

Answer:

214 seconds

Step-by-step explanation:

3 times 60 is 180. 180 plus 34 is 214.

Answer:

85.80

Step-by-step explanation:

85.82 is closet to 85.80 snice 2 is a low number

Answer:

No.

Step-by-step explanation:

Well at first glance it might seem so but there are two points particularly that can tell you that these points cannot be within a function.

The points (3,2) and (3,-2) will yield an undefined slope (a straight vertical line). There is no possibility that the other points can be in this line (as their y - values are different) and there is no possibilty that this is a function at all according to the vertical line test (the test is that if you draw a vertical line that there shouldn't be more than one point on it).

Answer:

Step-by-step explanation:

Given that:

a)

[tex]f(x,y) = e^{3x} + y^3 - 3ye^x \\ \\ \implies \dfrac{\partial f}{\partial x} = 0 = 3e^{3x} -3y e^x = 0 \\ \\ e^{2x}= y \\ \\ \\ \implies \dfrac{\partial f}{\partial y } = 0 = 3y^2 -3e^x = 0 \\ \\ y^2 = e^x[/tex]

[tex]\text{Now; to determine the critical point:}[/tex]- [tex]f_x = 0 ; \ \ \ \ \ f_y =0[/tex]

[tex]\implies e^{2x} = y^4 = y \\ \\ \implies y = 0 \& y =1 \\ \\ since y \ne 0 , \ \ y = 1, \ \ x= 0\\\text{Hence, the only possible critical point= }(0,1)[/tex]

b)

[tex]\delta = f_xx, s = f_{xy}, t = f_{yy} \\ \\ . \ \ \ \ \ \ \ \ D = rt-s^2 \\ \\ i) Suppose D >0 ,\ \ \ r> 0 \ \text{then f is minima} \\ \\ ii) Suppose \ D >0 ,\ \ \ r< 0 \ \text{then f is mixima} \\ \\ iii) \text{Suppose D} < 0 \text{, then f is a saddle point} \\ \\ iv) Suppose \ D = 0 \ \ No \ conclusion[/tex]

[tex]Thus \ at (0,1) \\ \\ \delta = f_{xx} = ge^{3x}\implies \delta (0,1) = 6 \\ \\ S = f_{xy} = -3e^x \\ \\ \implies S_{(0,1)} = -3 \\ \\ t = f_{yy} = 6y \\ \\[/tex]

[tex]\implies t_{0,1} = 6[/tex]

[tex]Now; D = rt - s^2 \\ \\ = (6)(6) -(-3)^2[/tex]

[tex]= 36 - 9 \\ \\ = 27 > 0 \\ \\ r>0[/tex]

[tex]\text{Hence, the critical point} \ (0,1) \ \text{appears to be the local minima}[/tex]

c)

[tex]\text{Suppose we chose x = 0 and y = -3.4} \\ \\ \text{Then, we have:} \\ \\ f(0,-3.4) = 1+ (-3.4)^3 + 3(3.4) \\ \\ = -28.104 < -1[/tex]

[tex]\text{However, if f (0,1) = 1 +1 -3 = -1 \\ \\ f(0,-3.4) = -28.104} < -1} \\ \\ \text{This explains that} -1 \text{is not an absolute minimum value of f(x,y)}[/tex]

Answer:

-18

Step-by-step explanation:

2x²-7xy+3y²

2(3²)-7(3)(4)+3(4²)

2(9)-84+3(16)

18-84+48

18+48-84

-18

Answer:

697.5 ft squared

Step-by-step explanation:

Divide into top two squares and rectangle on bottom so...

(10×7.5)+(8×7.5)×(12.5×45)=area

75+60+562.5=697.5 ft squared

Answer:

LN = 4 units

Step-by-step explanation:

Since M is on LN , then

LN = LM + MN , that is

4x = 3 + x ( subtract x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Then

LN = 3 + x = 3 + 1 = 4

The required length of the line LN = 4.

Given that,
Point M is on the line segment LN. Given LN=4x, MN= x, and LM=3,  to determine the numerical length of LN.

The line is a curve showing the shortest distance between 2 points.

LN = LM + MN
4x = 3 + x
4x - x = 3
3x = 3
x = 3 / 3
x = 1

Length of LN
LN = 4x
     = 4 * (1)
     = 4

Thus the required length of the line LN = 4.

Learn more about lines here:

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#SPJ5

Answer:

12 students

Step-by-step explanation:

CLEAN THAT IPAD FOR HIM

Answer:

12 students went to the beach fewer than 2 times.

Step-by-step explanation:

Just count the total number of dots that come before 2.

Answer:

Equivalent fraction of a given fraction is got by multiplying or dividing its numerator and denominator by the same whole number. For example, if we multiply the numerator and denominator of 2/3 by 4 we get. 2/3 = 2×4 / 3×4 = 8/12 which is an equivalent fraction of 2/3.

Step-by-step explanation:

Answer:

[tex]t \approx 2.639[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}[/tex]

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}[/tex]

So, we have:

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}[/tex]

[tex]t = \frac{-2.9}{\sqrt{1.2083}}[/tex]

[tex]t = \frac{-2.9}{1.099}[/tex]

[tex]t \approx -2.639[/tex]

The absolute value is:

[tex]t \approx 2.639[/tex]

Answer:

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{1.3}{\sqrt{1384}} = 0.1[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 3 - 0.1 = 2.9 pounds

The upper end of the interval is the sample mean added to M. So it is 3 + 0.01 = 3.1 pounds

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Answer:

x=5, y=3

Step-by-step explanation:

7x-11=24: 7x=35: x=5

3(5)+9=8x: 24=8x: x=3

Answer:

12:45

Step-by-step explanation:

Step One: An hour after 11:20 is 12:20, plus 15 minutes is 12: 35.

Step Two: Just add 10 minutes, because it doesn't matter when you add the ten minutes.

Answer:

$43.20

Step-by-step explanation:

20% of $50.00 is $10.00. $50 - $10 is $40. 8% of $40 is $3.20. Since this is tax, you must add it. $40+$3.20 = $43.20

Answer:

Average of Gilbert in last 5 test = 86.6

Step-by-step explanation:

Given:

Score earned by Gilbert in last 5 test = 94, 72, 83, 94, 90

Find:

Average of Gilbert in last 5 test

Computation:

Average value = Sum of all events / Total number of events

Average of Gilbert in last 5 test = Sum of all last results / Number of results

Average of Gilbert in last 5 test = [94 + 72 + 83 + 94 + 90] / 5

Average of Gilbert in last 5 test = [433] / 5

Average of Gilbert in last 5 test = 86.6

Answer256pi

Step-by-step explanation:

Area=pi*r^2

=pi*16^2

256pi

Answer:

4th one its negative,linear association

Step-by-step explanation:

The option that best describes the relationship between the variables on the scatter plot is negative, linear association.

Variables have a negative association when the line of best fit is downward sloping. Variables have a linear association when the line of best fit is a straight line. Variables have a positive association when the line of best fit is upward sloping.

To learn more about linear functions, please check: https://brainly.com/question/26434260

Answer: 123.05

Use annuity formula

Answer:

Step-by-step explanation:

Since we're talking about making a deposit of a certain amount every month rather than just one big deposit, we are talking about an annuity. The formula for the value of an annuity is A(t)=d[(1+rn)nt−1](rn) where A(t) is the value of the annuity, d is the amount of each deposit, n is the number of deposits per year, t is the number of years, and r is the rate of interest. In this case we know we want the value of the annuity to be A(t)=$150,000, we want to make deposits every month, or 12 times a year, so n=12, we want to reach our desired value in 30 years, so t=30, and our account earns 7% interest, so r=0.07. We can plug in all of these values and solve for d to find the amount we need to deposit each month:

A(t)150,000150,000150,000d=d[(1+rn)nt−1](rn)=d[(1+0.0712)12⋅30−1]0.0712≈d[(1.00583)360−1]0.00583≈1,219.97d≈122.95

The amount you need to deposit each month is approximately $122.95.