What do we call the part of the wave labeled with the letter
D in the image below?
B
MONO
A. Compression
B. Rarefaction
D. Wave speed
C. Frequency

Answer:

  the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

Explanation:

For this exercise we use the definition moment of inertia

          I = ∫ r² dm

for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are

at one end

           I₁ = ⅓ mL²

in in center

           I₂ = [tex]\frac{1}{12}[/tex] m L²

There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder

           I₃ = [tex]\frac{1}{2}[/tex] m r²

remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small

when examining the different moments of inertia:

     the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

Answer:

μ = mg/kx

Explanation:

Since the bock does not slip, the frictional force equals the weight of the block. So, F = mg. Now, the frictional force, F = μN where μ = coefficient of static friction and N = Normal force.

Now, the normal force equals the spring force F' = kx where k = spring constant and x = compression of spring.

N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

Answer:

while ice is made by water again it melts and becomes water. water is colourless and odourless and has no taste but ice is only cold and hard. water is used for drinking and other things. but is for freshness and it never flows

Explanation:

so ice reflect more energy compared to water

Answer:

500 m/s

Explanation:

From the question,

V = √(T/m')................. Equation 1

Where V = Speed with which the wave travels on the string, T = Tension of the string, m' = Mass per unit length of the string.

Given: T = 1200 N, m' = 4.80×10⁻³ kg/m

Substitute these values into equation 1

V = √(1200/4.80×10⁻³)

V = √(250000)

V = 500 m/s

Hence the speed of the wave in the string is 500 m/s

Answer:

5.4 m/s

Explanation:

Given that

Mass of the safe, m1 = 1000 kg

Distance to lower the safe, d = 3 m

Mass of furniture, m2 = 500 kg.

Speed of the safe, v = ?

To get the final speed by the time that the safe hits the truck, we first find its acceleration.

The total mass of the system is M = 1000 + 500 kg = 1500 kg

One of the forces acting on the system is that of gravity, and it acts on the safe friction acting on the furniture. Using the formula, we have

= m1*g - mu*m2g

= 1000 * 9.81 - 0.5 * 500 * 9.81

= 7357.5 N

From this calculated weight, we find the acceleration.

Acceleration, a = F/m

Acceleration, a = 7357.5 / 1500

Acceleration, a = 4.905 m/s²

From the question, we know that the Initial speed = 0 m/s

So, employing the use of one of the equations of motion, we have

v² - u² = 2aS

v² - 0 = 2 * 4.905 * 3

v² = 29.43

v = √29.43

v = 5.4 m/s

Answer:

Acceleration = Δv/Δt or change in velocity over change in time

Explanation:

Answer:

72 J

Explanation:

Use the Work formula

W= F x d

Given:

F - 48 N

d - 1.5 m

Solution:

W= F x d

W=  48 N x 1.5 m

W= 72 J

Answer:

v' = -18 m/s

Explanation:

       [tex]p_{o} = p_{f} (1)[/tex]

       [tex]m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)[/tex]

        [tex]-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)[/tex]

       [tex]-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)[/tex]

       [tex]m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)[/tex]

Answer:

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Explanation:

By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.

From top of the first hill to the bottom

[tex]m\cdot g \cdot h_{1} = \frac{1}{2}\cdot m\cdot v_{1}^{2} +W_{1, loss}[/tex] (1)

From the bottom to the top of the second hill

[tex]\frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2}+W_{2,loss}[/tex] (2)

Where:

[tex]m[/tex] - Mass of the roller coaster car, in kilograms.

[tex]v_{1}[/tex] - Speed of the roller coaster car at the bottom between the two hills, in meters per second.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h_{1}[/tex] - Height of the first top of the hill with respect to the bottom, in meters.

[tex]W_{1, loss}[/tex] - Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.

[tex]v_{2}[/tex] - Speed of the roller coaster car at the top of the second hill, in meters per seconds.

[tex]h_{2}[/tex] - Height of the second top of the hill with respect to the bottom, in meters.

[tex]W_{2, loss}[/tex] - Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.

By using (1) and (2), we reduce the system of equation into a sole expression:

[tex]m\cdot g\cdot h_{1} = m\cdot g\cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2} + W_{loss}[/tex] (3)

Where [tex]W_{loss}[/tex] is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.

If we know that [tex]m = 175\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h_{1} = 18\,m[/tex], [tex]h_{2} = 8\,m[/tex] and [tex]v_{2} = 11\,\frac{m}{s}[/tex], then the work done by non-conservative force is:

[tex]W_{loss} = m\cdot\left[ g\cdot \left(h_{1}-h_{2}\right)-\frac{1}{2}\cdot v_{2}^{2} \right][/tex]

[tex]W_{loss} = 6574.75\,J[/tex]

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Answer:

13/23 ydfffgggggggffttf

Explanation:

c willl fall fast then a and b

The three places where fresh water can be found is ice sheets, water vapor, and rivers.

A fresh water is any type of naturally occurring liquid or frozen water containing low concentrations of dissolved salts and other total dissolved solids.

Fresh water can be found in the following locations;

Thus, the three places where fresh water can be found is ice sheets, water vapor, and rivers.

Learn more about fresh waters here: https://brainly.com/question/4432187

Answer: B. Mechanical energy

Explanation: "Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position)."

"Potential and kinetic energy of an object as it is stored and moved. Examples of MECHANICAL ENERGY- roller coasters, hydraulic lift, bow and arrow, and helicopters. Helicopters, cars, roller coasters, all moving objects that are being acted on by a force."

Incorrect options: A. Thermal energy and B. Electromagnetic energy. (explanation on both below)

"Thermal energy (also called heat energy) is produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. The energy that comes from the temperature of the heated substance is called thermal energy."

"Electromagnetic radiation, in classical physics, the flow of energy at the universal speed of light through free space or through a material medium in the form of the electric and magnetic fields that make up electromagnetic waves such as radio waves, visible light, and gamma rays."

Answer:

Tor mata kobic furi‍♀️‍♂️‍‍‍❤

Answer:

rotational kinetic energy is 1156.81 J

Explanation:

Given the data in the question;

first we find the moment of inertia of the rod as axis passes through the middle or center;

[tex]I = \frac{1}{12}ml^2[/tex]

where m is the mass of the road( 3.0 kg)

[tex]l[/tex] is the length of the rod ( 2.6 m )

so we substitute

[tex]I = \frac{1}{12}[/tex] × 3 × (2.6)²

[tex]I[/tex] =   1.69 kg.m²

now, to calculate the rotational kinetic energy,

kinetic energy due to rotation is;

KE[tex]_R[/tex] = [tex]\frac{1}{2}Iw^2[/tex]

where [tex]I[/tex] is moment of inertia( 1.69 kg.m² ),

w is angular frequency ( 37 radians/s )

we substitute

KE[tex]_R[/tex] = [tex]\frac{1}{2}[/tex] × 1.69 × ( 37 radians/s )²

KE[tex]_R[/tex] = 1156.81 J

Therefore, rotational kinetic energy is 1156.81 J

The rotational kinetic energy will be 1156.81 J. It is half of the product of the moment of inertia and angular speed.

The rotational kinetic energy is the kinetic energy generated by an object's rotation and It is a component of its overall kinetic energy.

The given data in the problem is;

m is the mass = 3.0 kg

l is the length = 2.6 m

[tex]\rm \omega[/tex] is the angular speed = 37 radians/s

v is the speed = 13 m/s

[tex]\rm E_k[/tex] is the  rotational kinetic energy=?

The momentum of inertia is found by;

[tex]\rm I = \frac{1}{12} ml^2 \\\\ \rm I = \frac{1}{12} \times 3 \times (2.6)^2 \\\\\ \rm I = 1.69 \kg.m^2[/tex]

The rotational kinetic energy is found by;

[tex]\rm E_k= \frac{1}{2}I (\omega)^2 \\\\ \rm E_k= \frac{1}{2}\times 1.69 (37)^2 \\\\ \rm E_k=1156.81 \ J[/tex]

Hence the rotational kinetic energy will be 1156.81 J.

To learn more about the rotational kinetic energy refer to the link;

https://brainly.com/question/19305456

Answer: Because of the amount of energy

Explanation: Heat is an energy, and small amounts of it does not effect large areas, whereas a very large blast of heat energy can greatly effect the air

Explanation:

Its D. The warm air from the land moves towards the water

Answer:

a)   t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

        N₁-W₁ = 0

        N₁ = W₁

for the trailer

        N₂- W₂ = 0

        N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

         fr = (m₁ + m₂) a

the friction force equation is

        fr = μ N

we substitute

       μ N₁ = (m₁ + m₂) a

        μ m₁ g = (m₁ + m₂) a

        a = μ g    [tex]\frac{m_1}{m_1 + m_2}[/tex]

let's calculate

         a = 0.65 9.8    [tex]\frac{2000}{2000+8000}[/tex]

         a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

         Let's slow down the sI system

         v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

         v = v₀ - a t

when it is stopped its speed is zero

           0 = v₀ - at

           t = v₀ / a

           t = 25 / 1.274

           t = 19.6 s

b) the friction force is

           fr = 0.65 2000 9.8

          fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

Answer:

B

Explanation:

Where it shows on the map is B

Answer: 187.68 m

Explanation:

Given

Time period [tex]T=27.5\ s[/tex]

The time period of a pendulum is given by

[tex]\Rightarrow T=2\pi \sqrt{\dfrac{L}{g}}[/tex]

where L=height of tower

Put values

[tex]\Rightarrow 27.5=2\pi \sqrt{\dfrac{L}{9.8}}\\\\\Rightarrow L=\dfrac{27.5^2\times 9.8}{(2\pi )^2}=187.68\ m[/tex]

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

Answer:

[tex]1.5 \times 10^{-5} \mathrm{~T}[/tex].

Explanation:

Power carried by the line [tex]=P=450 \mathrm{MW}=450 \times 10^{6} \mathrm{~W}[/tex]

Voltage across the line Volts

Current flowing in the line =i

Size of magnetic field =B

Distance from the line

Formula Used:

Current flowing is given as

[tex]i=\frac{P}{\Delta V}[/tex]

Magnetic field by the current carrying wire is given as

[tex]B=\left(\frac{\mu}{4 \pi}\right)\left(\frac{2 i}{r}\right)[/tex]

Inserting the values

 [tex]B=\left(10^{-7}\right)\left(\frac{2(1500)}{(20)}\right) \\ B=1.5 \times 10^{-5} \mathrm{~T}[/tex]

Conclusion:

Thus, the magnetic field comes out to be [tex]1.5 \times 10^{-5} \mathrm{~T}[/tex].

Answer:

Δx = 2*d

Explanation:

        [tex]k*\Delta x = m*g (1)[/tex]

       [tex]F = k_{eff} * \Delta x_{eff} = m*g (2)[/tex]

       [tex]\Delta x_{1} = \frac{F}{\ k_{1} } (3)[/tex]

       [tex]\Delta x_{} = \frac{F}{\ k_{1} } + \frac{F}{\ k_{2} } (4)[/tex]

       [tex]\frac{F}{k_{eff} } = \frac{F}{\ k_{1} } + \frac{F}{\ k_{2} } (5)[/tex]

      Since k₁ = k₂ = k, we can find keff, as follows:

      [tex]k_{eff} = \frac{k^{2} }{2*k} = \frac{k}{2} (6)[/tex]

     [tex]F = \frac{k}{2} * \Delta x_{eff} = k*\Delta x = m*g (7)[/tex]

       [tex]\Delta x_{eff} = \frac{2*k*\Delta x}{k} = 2* \Delta x = 2*d (8)[/tex]

Answer:

Earth's gravity

Explanation:

hope this helps

Answer:

the earth gravity

Explanation:

Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. The Earth's gravity keeps the Moon orbiting us.

Answer:

B

Explanation: