A rectangle has a length of (2.5 ± 0.2) m and a width of (1.5 ± 0.2) m. Calculate the area and the perimeter of the rectangle, and give the uncertainty in each value.
(a)Calculate the area and give its uncertainty. (Enter your answers in m2.)
(b)Calculate the perimeter of the rectangle and give its uncertainty. (Enter your answers in m.)
The area of the rectangle obtained is (3.75 ± 0.03) m². The perimeter of the rectangle obtained is (8 ± 0.64) m.
Given dimensions:
Length (L) = (2.5 ± 0.2) m
Width (W) = (1.5 ± 0.2) m
(a) Area of the rectangle (A) is given by:
A = L × W
A = (2.5 ) × (1.5 )
A = 3.75 m²
The relative uncertainty in area = ΔA / A
ΔA = (ΔL / L) × A + (ΔW / W) × A
ΔA = (0.2 / 2.5) × 3.75 + (0.2 / 1.5) × 3.75
ΔA = 0.03 m²
Therefore, the area of the rectangle is (3.75 ± 0.03) m².
(b) Perimeter of the rectangle (P) is given by:
P = 2 × (L + W)
P = 2 × (2.5 + 1.5)
P = 2 × 4
P = 8 m
Relative uncertainty in perimeter = ΔP / P
ΔP = (ΔL / L) × P + (ΔW / W) × P
ΔP = (0.2 / 2.5) × 8+ (0.2 / 1.5) × 8
ΔP = 0.64 m
Therefore, the perimeter of the rectangle is (8 ± 0.64) m.
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How do the Sun, Earth, and Moon systems interact
The sun is the mother star of the solar system, which only emits light to half of the planet, while the other part is always dark.
The sun emits light towards the earth, which dominates all life on earth. The movements of the Moon around the Earth and of the Earth around the Sun are complex. Movements of rotation around their own axes are superimposed on movements of orbital translation. The Earth and the Moon rotate around their own axes: This is rotation.
Refer to Chapter 10 in the textbook which discusses externalities. Specifically, reference section 10-2, which details public policies towards externalities.
Additionally, find an article using your subscription to the Wall Street Journal detailing one proposed solution to pollution.
In your post, summarize the selected article and discuss the following:
Explain which of the public policies detailed in section 10-2 of the textbook best describes the proposed solution in the selected article.
Which of the public policy approaches outlined in section 10-2 would work best to resolve this pollution problem and why?
You are required provide a link to the article and support your answer with relevant ideas, facts, and examples.
An externality, sometimes called a spillover, occurs when an exchange between a buyer and seller has an impact on a third party who is not part of the exchange. Externalities can be positive or negative
What are Externalities?Externalities refers to situations when the effect of production or consumption of goods and services imposes costs or benefits on others which are not reflected in the prices charged for the goods and services being provided.
Externalities Private markets offer an efficient way to put buyers and sellers together and determine what goods are produced, how they are produced, and who gets them. The principle that voluntary exchange benefits both buyers and sellers is a fundamental building block of the economic way of thinking. But what happens when a voluntary exchange affects a third party who is neither the buyer nor the seller?
Externalities can be negative or positive. If you hate country music, then having it waft into your house every night would be a negative externality. If you love country music, then what amounts to a series of free concerts would be a positive externality.
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calculate the pressure of water in a well if the depth of the water is 10m
Answer:
P= phg
so:- the height is 10m
density of water 1000 kg/m3
gravity is 9.8m/s2
P=1000 kg/m3*10m*9.8m/s2
=98000Pa
=98KPa
importance of states of matter
Answer:
STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.
Explanation:
What is it called when data are arranged in rows and columns?
O A. Interpolation
O B. Correlation
O C. Table
OD. Bar graph
Answer:
C. Table
What is a Database table?
A organized collection of records is called a database table. The main key that uniquely identifies each row in the table. Since no two rows may have the same instantaneous value thanks to a unique key, it is simple to choose a row by its main key. A table can also contain several columns, each of which can hold a distinct kind of data. The information stored is verified using the column name and data type.
The table name is the linguistic component of a database table. It can represent expressions or variable items, and it must be typed exactly. Square brackets denote a need for the item, whereas curly braces denote an optional element. An alternate choice is indicated by a vertical bar. A main key is a single field, and a secondary key might be a combination of many fields. This kind of information is crucial.
Any field in the data table can be referenced by the secondary key. A database's data field may be a string, a number, a date, or a time. A table's first field should always be the main key, followed by any foreign keys. Actual data should never be present in a primary key. Since the immediate key value is derived from external sources, it is crucial to use it properly. Otherwise, data input mistakes may occur.
The information kept in the database table is referred to as a secondary key. This kind is a primary key, which implies it is a secondary key. A primary key can be used as an alternate key to distinguish between different records in a table and to uniquely identify a record inside a database. Multiple fields that can be either main or alternative make up a composite key.
Depending on the type of data being stored and its intended use, a database table may have a single row or several. The main key determines the number of rows, which might be 50 or more. A secondary key can be used to establish connections between various tables and to distinguish between various data types in a database. A data table also includes a secondary key, which is essential for data retrieval and is separate from the primary key.
You can have local or global database tables. The two types of tables differ in terms of names, availability, and visibility. A global table is accessible to all users and may be utilized by any other user, while a local table is only visible to the present user. It is distinct from a typical table and requires more effort to build than a straightforward one does. Its main function is to maintain a database and store data.
Rows in a database table can be of any size. A table's rows can include any number of columns. A database table's rows can be arranged in any way. The number of rows on a data page might range from one to thousands. Each row may consist of a clustered index, a row, or both. A list of columns may also be present in a row. A clustered index can only contain information in a particular sequence.
A table can be set up in two different ways. The information-containing row of data is its main key. The data column that contains the values for a row is known as a secondary key. A database that employs rows is the third form of table. Multiple primary keys are possible for a data row, and a secondary key is a secondary key that refers to a row column. A database will have a foreign key if it is formed with a single primary key.
There is no limit to the amount of rows and columns in a database table. Up to 1,024 rows are allowed in a typical user-defined table. The server's storage capacity determines how many rows can fit in a database table. A table can have characteristics added to it in addition to the column and row. A restriction can stop a row from having empty fields. The connection between two tables can be established via an important control.
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Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?
Answer:
[tex]\huge\boxed{\sf a = 0.7 \ m/s^2}[/tex]
Explanation:
Given Data:Initial velocity = [tex]V_i[/tex] = 0.5 m/s
Final velocity = [tex]V_f[/tex] = 4 m/s
Time = t = 5 s
Required:Acceleration = a = ?
Formula:[tex]\displaystyle a =\frac{V_f-V_i}{t}[/tex]
Solution:Put the givens in the formula.
[tex]\displaystyle a=\frac{4-0.5}{5} \\\\a = \frac{3.5}{5} \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}[/tex]
Which of the following describes a velocity vs. time graph that looks like this?
HURRY PLEASE
Explanation:
the velocity has decreasing velocity. this is my answerA 12kg object is pushed with a horizontal force of 6N due east across a horizontal table. If the force of friction between the two surfaces is 2N, what is the acceleration of the object?
The acceleration of the body is obtained as 0.33 m/s^2.
What is the acceleration of the body?Now we know that the object is acted upon by a system of forces. The net force is the effective force that acts on the body.
Hence;
ma = F -Ff
The applied force is F while the frictional force is Ff. The net force is represented as ma
Thus;
12 * a = 6 - 2
a = 4/12
a = 0.33 m/s^2
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A rod of length 58.0 cm and mass 1.10 kg is suspended by two strings which are 35.0 cm long, one at each end of the rod.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.
a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
b)ω = [tex]\frac{3g}{2l}[/tex]
c)14.7 the magnitude of the initial acceleration of the end B when the string is cut.
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time.
Given
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
When the string is cut rod rotates about other end.
Let's take momentum equation about that end:
mg*[tex]\frac{1}{2}[/tex] = Iω [I = [tex]ml^\frac{2}{3}[/tex]]
a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
Angular acceleration:
b)ω = [tex]\frac{3g}{2l}[/tex]
c)Acceleration of end B:
a = lω= [tex]\frac{3g}{2}[/tex] =[tex]\frac{3*9.8}{2}[/tex]
a = 14.7 [g=9.8]
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Q1) Write True or False for each statement:
Equal volumes of the two different substances have equal masses.
Answer:
True
Explanation:
it is true because blabla bla
find the x-component of this vector.
The x-component for the vector given in the image is : [tex]B_{x}[/tex] = 18.3m
Meaning of a VectorA Vector can be defined as a quantity that possesses both magnitude and direction thereby giving more details.
A vector is very important when it comes to dealing with forces.
Analysis
[tex]B_{x}[/tex] = B cos(Θ)
Θ = 180° - 170° = 10°
[tex]B_{x}[/tex] = B cos(10°) = 18.3m
In conclusion, The x-component for this vector is : [tex]B_{x}[/tex] = 18.3m
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Two rocks of identical mass sit high above the river. One rock is 10 meters above the river, and the other is 20 meters above the river. Which rock has the greatest potential energy?
Answer:
Gravitational potential energy is greater for the rock [tex]20\; {\rm m}[/tex] above the river.
Explanation:
The gravitational field near the surface of the earth is approximately uniform. Let [tex]g[/tex] denote the strength of the gravitational field near the surface of the earth.
Let [tex]m[/tex] denote the mass of each rock. Assume that the gravitational potential energy of the two rocks is [tex]0[/tex] when the rocks are at the surface of the river.
When the rock is at a height of [tex]h[/tex] above the river, the gravitational potential energy ([tex]\text{GPE}[/tex]) of that rock would be [tex]\text{GPE} = m\, g\, h[/tex]. In other words, the [tex]\text{GPE}\![/tex] of the rock is proportional to its height relative to the ground.
Hence, among the two rocks, [tex]\text{GPE}[/tex] would be greater for the rock that is higher above the ground ([tex]20\; {\rm m}[/tex]) than the rock [tex]10\; {\rm m}[/tex] above the ground.
In each case below, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask.
Which image represents a gaining of a charge on the leaves of the electroscope by conduction?
Answer:
(B) (the leaves will separate when subjected to a net charge)
The image that represents a gaining of a charge on the leaves of the electroscope by conduction is image B.
What is electroscope?An electroscope is a device that detects the presence of an electric charge or ionizing radiation by suspending a pair of thin gold leaves from an electrical conductor that leads to the outside of an insulating container.
When an electrical charge is brought close to or in contact with a conductor, the leaves in an electroscope spread apart.
This occurs because the same charge, whether positive or negative, is received by the leaves, causing their repulsion (spreading apart).
A negatively charged rod is brought in close proximity to an uncharged electroscope. As a result, the electroscope leaves become further apart.
Thus, image B is representing the given scenario.
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A person of mass 100kg runs up a staircase with a vertical height of 10m. If the trips takes 5 seconds to complete, calculate the person's power ( acceleration due to gravity =10m/s²)
Answer:
Power = 2000J/s
Explanation:
Power= Total Work done/Time
Given
mass = 100kg
distance(height) = 10m
time = 5s
acceleration due to gravity = 10m/s²
Work done = force × distance
Finding Force
Force = mass × acceleration due to gravity
Force = 100kg × 10m/s²
Force = 1,000N
Finding work done
Work done = Force × distance
Work done = 1,000N × 10m
Work done = 10,000J
Finding Power
Power = work done/time
Power = 10,000J/5s
Power = 2,000J/s
Therefore Power is 2,000J/s
in order for work to be done wht must happen?
Answer asap please due soon
An object must move in the same direction as the force is applied for work to be accomplished. Option C is correct.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative. it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.
The work done is found as;
W= F × d
Where.
F is the force
d is the displacement
W is the work done
In order for work to be done, an object must move in the same direction, and the force is applied
Hence option C is correct.
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perpetual motion machines have fascinated people especially inventors for hundreds of years before the laws of thermodynamics became known. Ideally once energy is added to start a perpetual motion machine in motion, the machine would continue to operate indefinitely. Using a law of thermodynamics, explain why such a machine cannot be produced
HELP HELP HELP
Given the fact that energy conversion is not entirely efficient, it is impossible to produce a perpetual motion machine.
What is a perpetual motion machine?The perpetual motion machine in one that is able to work continuously without stopping. This would mean that the efficiency of this machine must that the machine is 100% efficient which violates the second law of thermodynamics.
Thus, given the fact that energy conversion is not entirely efficient and energy looses cause machines not function effectively, it is impossible to produce a perpetual motion machine.
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A ball of mass m is dropped. What is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time τ later? Ignore air resistance.
The formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
Impulse exerted on the ballThe impulse exerted on the ball at any given instant is calculated as follows;
J = ΔP
J = Pf - Pi
where;
J is impulse exerted on the ballpf is final momentumpi is the initial momentumThus, the formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
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A record of travel along a straight path is as follows:
1. Start from rest with constant acceleration of 2.10 m/s2 for 14.0 s.
2. Maintain a constant velocity for the next 1.90 min.
3. Apply a constant negative acceleration of −9.06 m/s2 for 3.25 s.
m/s
a) What was the total displacement for the trip?
b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip?
The total displacement for the trip is 5510 m
During part 1, the distance travelled is
(1/2) a t^2
= (1/2)(2.77)(225)
= 311.6 m
The final speed gotten is (2.77)(15)
= 41.55 m/s.
The average speed for that interval is half of that or 20.8 m/s
During part 2, the distance traveled is
41.55 m/s*2.05 min*60 sec/min
= 5110 m/s
During part 3, the speed drops from 41.55 m/s to
41.55 - (9.47)(4.39)
= 0
The average speed during this interval is
41.55/2 - 20.78 m/s
The distance travelled is 20.78*4.39
= 91.2 m/s
Total distance travelled = 312 + 5110 + 91 = 5513 m
The average speeds for legs 1,2,and 3 of the trip as well as for the complete trip are:
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Two blocks are connected by a massless rope over a massless, frictionless pulley, as shown in the figure. The mass of block 2 is 2=11.3 kg , and the coefficient of kinetic friction between block 2 and the incline is =0.200 . The angle of the incline is 31.5° . If block 2 is moving up the incline at constant speed, what is the mass 1 of block 1?
The mass of block 1 is 1.30176 kg.
What is tension in physics?A tension force in physics is a force developed in a rope, string, or cable when stretched under an applied force.
Tension is acted along the length of the rope/cable in a direction that is opposite to the force applied on it.
According to the question,
Mass of block 2= 11.3 kg
Kinetic friction μ=0.200
The component of the weight in the direction of the incline
W = m₂gsinθ
T = [tex]F_{f} - W[/tex]........(1)
When the force of friction
[tex]F_{f}[/tex] = μ[tex]_k[/tex]N
[tex]F_{f}[/tex] = μ[tex]_k[/tex](m₂gcosθ)
Here , Put the value in equation 1
T = m₂gcos 31.5° - μ[tex]_k[/tex]m₂gcos 31.5°
We know that ,
T - m₁g = 0
T = m₁g
So,
m₁g = m₂g (Sin 31.5° - 0.200 x cos 31.5°)
m₁ = 11.3 x (0.0840 - 0.2 x 0.996)
m₁ = 11.3 x (0.1152)
m₁ = 1.30176 kg
Hence, the mass of block 1 is 1.30176 kg.
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. In a common test for cardiac function (the “stress test”), the patient walks on an
inclined treadmill. Estimate the power required from a 75-kg patient when the
treadmill is sloping at an angle of 12° and the velocity is 3.1 km/h.
The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
Parallel force on the patient
The parallel force on the patient is calculated as follows;
F = mg sinθ
F = (75 x 9.8) x sin(12)
F = 152.82 N
Average power requiredP = FV
where;
V is speed = 3.1 km/h = 3.1/3.6 = 0.861 m/sF = 152.82 x 0.861
F = 131.58 W
Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
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What buoyant force is exerted on a 6,000-mL toy balloon by the air surrounding the balloon? The density of air is 0.0009 g/mL
The buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
How to calculate buoyant force?The buoyancy needed for an object can be calculated using the formula;
B = ρ × V × g
where;
ρ and V are the object's density and volume respectivelyg is the acceleration due to gravity (9.81m/s²)B = 6000 × 0.0009 × 9.81
B = 52.97N
Therefore, the buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
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A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?
The speed of the particle when it enters the magnetic-field region is 120,000 m/s.
Speed of the particle
Magnetic force on the particle is given as;
F = qvB
where;
q is magnitude of the chargev is speed of the particleB is magnetic field strengthFrom Newton's second law, force on an object is given as;
F = ma
where;
m is mass of the particlea is accelerationma = qvB
v = ma/qB
v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)
v = 120,000 m/s
Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.
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The form of energy that can move from place to place across the universe is
Answer:kinetic energy
Explanation:
9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer
Answer:
Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.
Explanation:
A concave mirror
light, whereas a concave lens
light.
Answer: Answer.
1)Concave lens is transparent whereas the concave mirror is opaque. 2)concave mirrors cause reflection whereas concave lense cause refraction of light.
3)concave mirror forms both real, inverted images of various sizes and virtual, erect, and enlarged images whereas a concave lens form only virtual images.
Explanation:
A yoyo with a mass of m = 150 g is released from rest as shown in the figure.
The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is I[tex]_{cm}[/tex] = 1.01×10-4 kgm2.
1. Determine the linear acceleration of the yoyo.
2. Determine the angular acceleration of the yoyo.
3. What is the weight of the yoyo? (Hint: It's not 150 g)
4. What is the tension in the rope?
5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?
(1) The linear acceleration of the yoyo is 3.21 m/s².
(2) The angular acceleration of the yoyo is 80.25 rad/s²
(3) The weight of the yoyo is 1.47 N
(4) The tension in the rope is 1.47 N.
(5) The angular speed of the yoyo is 71.385 rad/s.
Linear acceleration of the yoyoThe linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.
∑τ = Iα
rT - Rf = Iα
where;
I is moment of inertiaα is angular accelerationT is tension in the roper is inner radiusR is outer radiusf is frictional forcerT - Rf = Iα ----- (1)
T - f = Ma -------- (2)
a = Rα
where;
a is the linear acceleration of the yoyoTorque equation for frictional force;
[tex]f = (\frac{r}{R} T) - (\frac{I}{R^2} )a[/tex]
solve (1) and (2)
[tex]a = \frac{TR(R - r)}{I + MR^2}[/tex]
since the yoyo is pulled in vertical direction, T = mg [tex]a = \frac{mgR(R - r)}{I + MR^2} \\\\a = \frac{(0.15\times 9.8 \times 0.04)(0.04 - 0.0214)}{1.01 \times 10^{-4} \ + \ (0.15 \times 0.04^2)} \\\\a = 3.21 \ m/s^2[/tex]
Angular acceleration of the yoyoα = a/R
α = 3.21/0.04
α = 80.25 rad/s²
Weight of the yoyoW = mg
W = 0.15 x 9.8 = 1.47 N
Tension in the ropeT = mg = 1.47 N
Angular speed of the yoyov² = u² + 2as
v² = 0 + 2(3.21)(1.27)
v² = 8.1534
v = √8.1534
v = 2.855 m/s
ω = v/R
ω = 2.855/0.04
ω = 71.385 rad/s
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A ball is thrown directly downward with an initial speed of 8.75 m/s, from a height of 29.4 m. After what time interval does it strike the ground?
After time 1.74 seconds ball will strike the ground.
A ball is thrown directly downward and information we have-
Initial velocity of ball (u) = 8.75m/s
distance/height (s) = 29.4m
Ball is thrown downward means there are gravitation force also worked and the acceleration of ball is-
acceleration (a) = g = 9.8 m/s²
When ball strike the ground then it's velocity should be 0 means-
Final velocity of ball (v) = 0 m/s²
For getting time period we can use 2nd equation of motion as-
s = ut + (1/2)at²
Now, 29.4 = (8.75 × t) + (1/2× 9.8 × t²)
29.4 = 8.75t + 4.9t²
Now we have a quadratic equation as -
4.9t² + 8.75t - 29.4 = 0
After solving it we get two values of t -
time = 1.74 and time = -3.5
But time can not be negative so we will reject the negative values.
so t = 1.74 seconds
So to conclude that after applying the second equation of motion the time taken by the ball to reach ground is 1.74 seconds.
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A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?
Answer:
The value of work being done on the object is 958J.
Explanation:
Work done is equal to force multiply by distance, but when the angle is between the force and distance work done=Force (cos theta) × distance
Work done = Force(cos theta) × distance
Work done = 25N(cos 40.0°) × 50m
Work done = 25N(0.7660) × 50m
Work done = 19.15N × 50m
Work done = 957.5J = 958J
Therefore the value of work being done on the object is 958J.
Which prathogen is often controlled by beneficial bacteria
Answer:
antibiotics
Explanation:
im not sure if this is right hope this helps lol