What are the purposes of these items aboard the Voyager probes? • Low-energy particle detector: • Magnetometer boom: • High-gain antenna: • Photopolarimeter: • Cosmic ray:

Answer:

736 N

Explanation:

F =   75 kg * 9.81 m/s^2 = 736 Newtons

Answer:

Explanation:

To find the speed at which a 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J, you will need to use the formula for kinetic energy, which is:

KE = 1/2 * m * v^2

Where KE is the kinetic energy, m is the mass of the object, and v is the speed of the object.

To solve for v, you will need to rearrange the equation to solve for v:

v = sqrt(2 * KE / m)

Plugging in the values given in the problem, we get:

v = sqrt(2 * 209.3 J / 0.25 kg)

Solving this equation gives us a speed of approximately 29.3 meters per second. This is the speed at which the 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J.

I hope this helps!

To identify the factors influencing the associations between the variables, researchers must adopt a correlational design.

An investigator who carries out research, that is, a planned and methodical examination of something, is referred to as a researcher. As researchers, scientists are frequently referred to.

Researchers are employed by authors of books that require extensive information collection, such as those by Michael Crichton who write about biology, to assist them in compiling and analyzing data. Some authors conduct their own research by consulting friends who are doctors to find intriguing methods for their characters to pass away.

Research and development (R&D) of methods and systems for the expansion of human knowledge are the main goals of fundamental research (as opposed to applied research). These goals include documentation, discovery, interpretation, and R&D. Research methodologies rely on epistemologies, which differ greatly within the humanities and sciences as well as within each discipline. Science, the humanities, the arts, business, marketing, and social and economic research are some of the several types of research.

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Answer:

The acceleration of the rocket is 20 m/s².

Explanation:

This can be calculated by dividing the change in velocity by the time it took to achieve that change in velocity. In this case, the change in velocity is 250 m/s - 50 m/s = 200 m/s, and it took 10 seconds, so the acceleration is 200 m/s / 10 s = 20 m/s².

This query calls for the use of Newton's second law of motion. Mass is equal to the product of acceleration and net force. Mass = 32 N / 4 m/s2 = 8 kg when the values are entered into the formula.

We can obtain a=F/m by adopting the formula F=m*a and rearranging the subject. Then, using the provided numbers as substitutes, we can determine that a=30/10=3. The item will accelerate at 3ms-2 because acceleration is measured in ms-2.

Newton's second law of motion provides the definition of the force formula: An object's force is equal to its mass times its acceleration. F = m ⨉ a. To apply this formula, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).

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The frequency and wavelength are indirectly proportional to each other. More is the wavelength, lesser is the frequency and vice-versa.

What is a wavelength?

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Answer:

Below

Explanation:

Circumference of tires = 2 pi * r=2.28079 m

rpm   * 2pi   =   (23.9  m/s )/ (2.28079 m)  * 2pi = 65.8 R/s

(a) Angular velocity in Degrees per second = [tex]720^0[/tex] per second

(b) Angular velocity in radians per second = 4[tex]\Pi[/tex] radians per second.

Number of rotations = 10

Total time = 5

So, the value of frequency will be =(Number of rotations)/Total time

That will be = (10/5) = 2

Angular velocity is defined as the speed at which an item rotates or revolves around an axis.

The Greek letter omega (occasionally ω, sometimes Ω) stands for angular velocity.

The SI unit for angular velocity is radians per second because it is expressed as an angle per unit of time.

(a) Angular velocity in Degrees per second

[tex]$=360^{\circ} \mathrm{f}=720^{\circ}$[/tex] degree per second.

(b) Angular velocity in radians per second

[tex]$\omega =2 \pi f=2 \pi(2)=4 \pi$[/tex] radians per second.

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The golf ball has a wavelength of 2.3281034m. The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or along a wire is defined as the wavelength.

This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

A matter wave is connected with all moving particles with mass. These matter waves are referred to as deBroglie waves.

A particle's deBroglie wavelengths is given by, where h is the Planck's constant, m is the mass of the ball, and v is its velocity.

Calculate the deBroglie wavelength of a moving golf ball by substituting 6.6261034J s for h, 45.9103kg for m, and 62.0 m/s for v.

The golf ball has a wavelength of 2.3281034m.

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Answer:

0.875 miles/minute

Explanation:

The formula for velocity if final position - initial position divided by final time - initial time. Here, the final position

of the van was 49 km away from house, and its initial was 0, because you didn't travel anywhere initially. The final time was 56 minutes because that was how long it took to get home, and the initial was 0, because you were 0 minutes into travel at the beginning.

It is true that no photoelectrons are released when ultraviolet radiation strikes a surface.

It was discovered that certain metals, such as zinc, cadmium, magnesium, etc., only emitted electrons from their surfaces when exposed to ultraviolet light with a short wavelength. Lithium, sodium, potassium, caesium, and rubidium are examples of alkali metals that can be sensitive to visible light.

If the frequency of the light is less than a specific level, no photoelectrons are released. The threshold frequency is referred to as such. For many materials, the threshold frequency varies. Alkali metals, calcium, and barium lose their photoelectron content when exposed to visible light.

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Electrical voltage can be found in cable, cables, circuit breakers, light fixtures, outlets, and switches using voltage testers and receptacle analyzers.

How do you determine whether there is electricity present?

Simply place one tester probe against a hot wire, screw terminal, or outlet slot to utilise a neon voltage tester. Connect the second probe to a ground or neutral contact. If there is current, the small neon bulb at the tool's tip will light up.

Which test is performed to detect whether a piece of equipment contains electricity?

test bulbA piece of electrical test equipment called a test light, test lamp, voltage tester, or mains tester is used to determine whether electricity is present in a piece of equipment that is being tested

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Answer:

An object being fired from a cannon is also a collision where momentum must be conserved

The acceleration due to gravity on asteroid X is approximately  0.5 meter/secon^2. Hence, option (D) is correct.

The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s^2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The letter g stands for gravitational acceleration.

Given that:  An astronaut weighs 500 Newtons on Earth and 25 newtons on asteroid X.

Hence,  The acceleration due to gravity on asteroid X is :

= acceleration due to gravity on Earth × (25 N/500N)

= 10 meter/secon^2 × (1/20)

= 0.5 meter/secon^2 ( approx.)

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Answer:

0

Explanation:

Displacement is the distance between the start and end point of your travel. If you start in your seat, and end up in your seat, your displacement is 0.

The rotational kinetic energy of the earth on its axis is 2.08 x 10^29 Joules and the rotational kinetic energy of the earth in its orbit around the sun is 2.17 x 10^33 Joules.

(a) To calculate the rotational kinetic energy of Earth on its axis, we can use the formula:

where KE is the rotational kinetic energy, I is the moment of inertia of the object, and ω is the angular velocity.

The moment of inertia of Earth can be calculated using the formula:

where m is the mass of Earth and r is the radius of Earth.

Using these formulas, we can calculate the rotational kinetic energy of Earth as follows:

KE = 0.5 * [(2/5) * m * r^2] * (ω^2)

     = 0.5 * [(2/5) * 5.97 x 10^24 kg * 6371 km^2] * (7.29 x 10^-5 rad/s)^2

     = 2.08 x 10^29 Joules

(b) To calculate the rotational kinetic energy of Earth in its orbit around the sun, we can use the formula:

where KE is the rotational kinetic energy, m is the mass of Earth, and v is the velocity of Earth in its orbit around the sun.

The velocity of Earth in its orbit around the sun can be calculated using the formula:

where G is the gravitational constant, M is the mass of the sun, and r is the distance of Earth from the sun (also known as the semimajor axis of Earth's orbit).

Using these formulas, we can calculate the rotational kinetic energy of Earth in its orbit around the sun as follows:

KE = 0.5 * m * [√[(G * M) / r]]^2

     = 0.5 * m * [(G * M) / r]

     = 0.5 * 5.97 x 10^24 kg * [(6.67 x 10^-11 N * m^2 / kg^2) * (1.989 x 10^30

        kg) / (1.496 x 10^11 m)]

     = 2.17 x 10^33 Joules

Note that the rotational kinetic energy of Earth in its orbit around the sun is much greater than the rotational kinetic energy of Earth on its axis, due to the much larger velocity and mass involved in Earth's orbit around the sun.

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The maximum speed of the glider v = 4.75 m/s. the amplitude of the motion 2.12 cm. the angular frequency of the oscillations is approximately 2.86 rad/s.

To find the amplitude of the motion, we can use the equation for the potential energy of a spring:

Potential Energy = (1/2) * k * x^2

where k is the force constant of the spring, x is the displacement of the glider from its equilibrium point, and Potential Energy is the potential energy of the spring.

In this case, the force constant of the spring is 155 n/m, the displacement of the glider from its equilibrium point is 3.00 cm, and the potential energy of the spring is unknown. Plugging these values into the equation above, we get:

Potential Energy = (1/2) * 155 n/m * (3.00 cm)^2

This simplifies to:

Potential Energy = (1/2) * 155 n/m * 9.00 cm^2

This further simplifies to:

Potential Energy = 693.5 n cm

The potential energy of the spring is equal to the kinetic energy of the glider, so we can use the equation for kinetic energy to solve for the maximum speed of the glider:

Kinetic Energy = (1/2) * m * v^2

where m is the mass of the glider and v is its speed.

In this case, the mass of the glider is 175 g, and its speed is unknown. Plugging these values into the equation above, we get:

(1/2) * 175 g * v^2 = 693.5 n cm

This simplifies to:

v^2 = 693.5 n cm / (1/2) * 175 g

This further simplifies to:

v^2 = 3960.7 g cm / 175 g

This simplifies to:

v^2 = 22.60 g cm

To find the maximum speed of the glider, we can take the square root of both sides of the equation:

v = √(22.60 g cm)

This simplifies to:

v = 4.75 m/s

To find the angular frequency of the oscillations, we can use the equation:

ω = √(k/m)

where ω is the angular frequency, k is the force constant of the spring, and m is the mass of the glider.

In this case, the force constant of the spring is 155 n/m, and the mass of the glider is 175 g. Plugging these values into the equation above, we get:

ω = √(155 n/m / 175 g)

This simplifies to:

ω = 2.86 rad/s

we can use the equation for kinetic energy to find the amplitude of the motion:

Kinetic Energy = (1/2) * m * v^2

where m is the mass of the glider and v is its maximum speed.

In this case, the mass of the glider is 175 g, and its maximum speed is 4.75 m/s. Plugging these values into the equation above, we get:

(1/2) * 175 g * (4.75 m/s)^2 = 693.5 n cm

This simplifies to:

(1/2) * 175 g * 22.60 g cm = 693.5 n cm

To find the amplitude of the motion, we can solve for x:

x^2 = 693.5 n cm / (1/2) * 155 n/m

This simplifies to:

x^2 = 4.5 cm^2

To find the amplitude of the motion, we can take the square root of both sides of the equation:

x = √(4.5 cm^2)

This simplifies to:

x = 2.12 cm

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Answer:

Below

Explanation:

A VOLTAGE is induced across the coil.... if the ends of the coil are connected together or to a circuit, a current will flow

To reduce magnetic flux density, it is necessary to reduce the voltage to a motor when the frequency is reduced. This will resist lowering of inductive reactance and increase of rotor current

When we decrease voltage applied to the motor. The current in stator is winding as well as the magnetic flux density will decrease along with decrease in induced voltage.

The voltage induced over rotor's conductor is defined here

,[tex]V_{R[/tex] = B.l.u

We can see things in other way also. Changing frequency has effect on  both the motor speed and the strength of the magnetic field. With the lowering of frequency motor speed becomes slow.

With reduction in voltage, magnetic field decreases and magnetic flux becomes constant. This keeps torque production stable, regardless of frequency.

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Answer:

To solve this problem, we need to use the equations of motion for an object undergoing uniformly accelerated motion. Specifically, we can use the equation for the displacement of an object in the vertical direction:

y = y0 + v0t + 1/2at^2

where y is the displacement of the object, y0 is the initial displacement (in this case, the height of the wall), v0 is the initial velocity (in this case, 10 m/s), t is the time elapsed, and a is the acceleration (in this case, the acceleration due to gravity, which is approximately 9.81 m/s^2).

To find the distance travelled in the last second of motion, we need to find the displacement of the object at t = 1 s, and subtract the displacement at t = 0 s (which is the initial displacement). Substituting these values into the equation above and solving, we get:

y1 = 2.2m + 10m/s * 1s + 1/2 * 9.81m/s^2 * 1s^2 = 12.61 m

y0 = 2.2m

The distance travelled in the last second of motion is therefore y1 - y0 = 12.61 m - 2.2 m = 10.41 m.

Explanation:

Answer: (A)

Explanation:

Constant speed = 0 ΣF = equilibrium

Apple, cart, and satellite* have imbalanced force of gravity

*gravity is acting as a centripetal force

The bus will go 2.788×10^14 meters far if the special detector placed on one of the bus's tires counts the number of rotations completed by the tire during the journey.

What is a circle?

It is described as a set of points, where each point is at the same distance from a fixed point called it's center.

wr are going on a field trip in a school bus. A special detector placed on one of the bus's tires counts the number of rotations completed by the tire during the journey.

It is given that diameter (D) of the tyre = 111 meters

circumference of the tyre = πD

circumference of the tyre = 3.14 × 111

= 348.5 m

In 800080008000 rotations, total distance covered = 348.5 × 800080008000 = 2.788×10^14

Thus, the bus will go 2.788×10^14 meters far if the special detector placed on one of the bus's tires counts the number of rotations completed by the tire during the journey.

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a) The expression for force needed to push the cylinder distance deeper into the liquid by a distance x is F = ρ × A × x.

b) The work done to push the cylinder 10 cm deeper into the water is 12.315 N-m.

The force required to push the cylinder by a certain distance is nothing but the weight of the liquid displaced by the same distance.

So, F = ρ × A × x

where, p is density

x is distance

A is area

We know the expression for work as, W = F × z

where, z is the work required to move through distance z

From a) we can write F = A × z² × ρ

Given that, d = 4 cm

So, r = 2 cm = 0.2 m

z = 10 cm = 0.10 m

ρ = 1000 kg/m³ = 9800 N/m³

Substituting the values in the above equation, we have,

W = π × 0.2² × 0.1² × 9800 = 12.315 N-m

The question is incomplete. The complete question is 'a.) Pressing down on the cylinder pushes it deeper into the liquid. Find an expression for the force needed to push the cylinder distance deeper into the liquid and hold it there.

'b.) A 4.0 cm diameter cylinder floats in water. How much work must be done to push the cylinder 10 cm deeper into the water?'

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The magnitude of the acceleration of the ball  applied at the bottom of the circle is expressed as FTension-FGravity/M.

You can write it down as FC = mv2 /r.

The centripetal force in a moving object attached to a string is equal to the product of the object's mass (mg) and the string tension (T).

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(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.068.

(b) The final kinetic energy of the neutron is 2.48 x 10⁻¹³ J.

The final velocity of the atom is calculated by applying the principle of conservation of linear momentum as follows;

initial momentum of the neutron = final momentum of the atom

m₁u₁  = m₂u₂

where;

The mass of the atom = 14.8m₁

u₂  = m₁u₁ / m₂

u₂  = m₁u₁ / (14.8m₁)

u₂  = 0.0676u₁

The initial kinetic energy of the neutron is calculated as;

K.Ei = ¹/₂m₁u₁²

The final kinetic energy of the atom is calculated as;

K.Ef =  ¹/₂m₂u₂²

K.Ef =  ¹/₂(14.8m₁)(0.0676u₁)²

K.Ef = 0.068 (¹/₂m₁u₁²)

K.Ef = 0.068 (K.Ei)

The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;

= 0.068 (K.Ei) / K.Ei

= 0.068

= 6.8 %

The final kinetic energy of the neutron is calculated as follows;

K.E.f (neutron) = (1 - 0.068) x (2.66 x 10⁻¹³ J)

K.E.f (neutron) = 2.48 x 10⁻¹³ J

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On a graph of galaxy colors and luminosities, spiral galaxies are usually found in the blue cloud.

any of the star systems and interstellar materials that make up galaxys. Hundreds of billions of stars can be found in several of these massive assemblages.

From dim, hazy dwarf objects to magnificent spiral-shaped giants, nature has created a vastly diverse assortment of galaxies. Almost all galaxies seem to have formed shortly after the universe started, and they can be found everywhere throughout space, even in the deepest regions that are beyond the reach of even the most potent contemporary telescopes. Galaxies typically exist in groups called clusters, some of which are then combined into larger clusters with a diameter of hundreds of millions of light-years. (A light-year is a distance traveled by light during one year at a speed of 300,000 km/sec or 650,000,000 mph.)

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The speed of male skater after the throw  will be  6.35 m/s.

The relationship between a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.

Given that 76.9kg male and 44.4kg female pair figure skating team gliding across the ice at 7.26 m/s.

the female skater is tossed forward with a speed 8.83 m/s .

Let the speed of male skater after the throw = v m/s.

From principle of conservation of momentum,

Total initial momentum = total final momentum

⇒ (76.9 + 44.4) × 7.26 = 76.9×v + 44.4×8.83

⇒  76.9×v  =  (76.9 + 44.4) × 7.26 -  44.4×8.83

⇒ v = 6.35 m/s.

Hence,  the speed of male skater will be  6.35 m/s.

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The root mean square voltage Vrms of the circuit is 15.49 V.

The voltage of the resistor vR is 10.4 V.

The voltage of the inductor vL is 11.49 V.

The voltage of the capacitor vC is 0.035 V.

RMS voltage of the circuit is calculated as follows:

Vrms = -V₀ sin ωt = -29 * sin (260* 22* 10⁻³) = 29 * 0.534 = 15.49 V

XI = ωL = 260* 0.85 = 221 ohms

Xc = 1/ωc = 1/(260 * 5.75* 10⁻³) = 10³/1495 = 0.67 ohm

Z = √[R² +(XI - Xc)²] = √[200² + (221 - 0.67)²] = √[200² + 220.33²]

= √[ 40000 + 48545.30] = 297.56 ohm

Current flowing in the circuit is

Irms = Vrms/Z = 15.49 / 297.56 = 0.052 A

vR = Irms * R = 0.052 * 200 = 10.4 V

vL = Irms * L =  0.052 * 221 = 11.49 V

vC = Irms * C = 0.052 * 0.67 = 0.035 V

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Therefore, even though Europa has a diameter that is only one-fourth that of Earth, her ocean may hold twice the amount of water as Earth's seas do.The immense and unfathomably depths ocean of Europa is regarded as the best area to look for life outside of Earth.

As a result of the liquid water's close proximity to the silicate mantle, Europe is one of the finest options for habitability.The amount of radiation that strikes the moons from Jupiter is a crucial component in determining whether or not they are habitable.

Europa would need to contain the necessary chemical components for life's chemistry in order to be potentially habitable.These include the frequently occurring elements carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur, which are thought to have been present on Europa at the time it originated.

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