For the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
What is the magnetic quantum number?The magnetic quantum number takes on values between 0 to (n - l). It gives the orientations of the sublevels. The four types of quantum numbers are;
Principal quantum numberAzimuthal quantum numberMagnetic quantum numberSpin quantum numberFor the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
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Calculate the volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
C(s) + O2(g) ⇒CO2(g)
535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given:
[tex]C(s) + O_2(g)[/tex] ⇒[tex]CO_2(g)[/tex]
1 mole of [tex]CO_2(g)[/tex] is formed from 1 mole of charcoal, that means 1 mole of [tex]CO_2(g)[/tex] is formed from 12 g of charcoal.
1 lbs = 453.592 grams
6.75 lbs = 6.75 x 453.592 =3061.746g
So, [tex]CO_2(g)[/tex] formed from 3061.746g of charcoal is:
=[tex]\frac{1}{12}[/tex] x 3061.746g
=255.14 mol.
Now, at STP, the volume of 1 mol of gas =22.4 L
Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 255.14 x 22.4 L
Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 535.8 L
Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
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Question 10
A) True.
Sara's resting heart rate is 70 bpm. She goes for a run. Within one-minute post exercise, her heart rate is 100 bpm. Sara has
achieved homeostasis.
B) False.
Additional content
3 OF 10 QUESTIONS REMAINING
You can add text, images, and files here.
2 Points
False. Sarah has not achieved homeostasis.
What is homeostasis?It is the maintenance of a relatively unchanged internal process in the body of organisms.
Since the resting heart rate for Sarah is 70 bpm, a 100 bpm is a far cry from the normal resting heart rate.
Thus, it cannot be said that Sarah has achieved homeostasis.
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Select the option no explanation needed
Answer:
70.9 g/mol
Explanation:
To find the molar mass, you first need to convert molecules to moles via Avogadro's Number.
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
2.123 x 10²¹ molecules X₂ 1 mole
-------------------------------------- x ------------------------------------ = 0.00353 moles X₂
6.022 x 10²³ molecules
Now, you can plug the molar value and mass (given) into the molar mass ratio to find your final answer. Your answer should have 3 sig figs to reflect the given value with the lowest amount of sig figs (0.250 g).
Molar Mass (g/mol) = mass (g) / moles
Molar Mass = 0.250 g / 0.00353 moles
Molar Mass = 70.9 g/mol
The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
Answer: 1.466 g/mL
Explanation:
[tex]\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}[/tex]
I need help with the solution
Answer:
52.6 g C₆H₆O₂
Explanation:
Unfortunately, the problem does not specify which of the reactants is the limiting reagent. This means you must convert both starting amounts into the product to identify the final answer.
To find the mass of hydroquinone (C₆H₆O₂) produced, you need to (1) calculate the molar masses of the reactants and product, then (2) convert grams of the reactants to grams of the product (via the molar masses and the mole-to-mole ratio from equation coefficients), and then (3) determine the limiting reagent and the actual answer.
(Step 1)
Molar Mass (C₆H₅OH): 6(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol
Molar Mass (C₆H₅OH): 94.112 g/mol
Molar Mass (H₂O₂): 2(1.008 g/mol) + 2(15.998 g/mol)
Molar Mass (H₂O₂): 34.012 g/mol
Molar Mass (C₆H₆O₂): 6(12.011 g/mol) + 6(1.008 g/mol) + 2(15.998 g/mol)
Molar Mass (C₆H₆O₂): 110.11 g/mol
(Step 2)
It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given values.
45.0 g C₆H₅OH 1 g 1 mole C₆H₆O₂ 110.11 g
------------------------ x -------------- x ------------------------- x ----------------- =
94.112 g 1 mole C₆H₅OH 1 mole
= 52.6 g C₆H₆O₂
20.0 g H₂O₂ 1 mole 1 mole C₆H₆O₂ 110.11 g
------------------- x ----------------- x ------------------------- x --------------- =
34.012 g 1 mole H₂O₂ 1 mole
= 64.7 g H₂O₂
(Step 3)
The limiting reagent of the reaction is C₆H₅OH because it is not able to produce as much product as H₂O₂. As such, product stops being made as C₆H₅OH runs out, making the final amount 52.6 g C₆H₆O₂.
Answer:
See below
Explanation:
Mole weight of C6H5OH = 94 gm/mole (approx)
45 gm / 94 gm/mole = .479 Moles of phenol
Mole wt of H2O2 = 34 (approx)
20 gm / 34 gm /mole = .588 moles of hydrogen peroxide
From the equation.....it takes equal moles of these to react to produce the same number of moles of hydroquinone.....
there isn't enough phenol to match the peroxide....so phenol is limiting reactant and you will only get .479 moles of hydroquinone
hydroquinone mole weight = 110 gm / mole (approx)
.479 mole * 110 gm/mole = 52.69 gm produced
A compound has a molecular mass of 98.1861 g per mol. Its empirical formula is CH2. Determine its molecular formula.
Empirical formula mass
12+214g/molFind n
Molecular mass/Empirical mass98.1861/147Molecular formula
n×Empirical formula7(CH2)C_7H_14The molecular formula of the compound is C₇H₁₄.
What is the relationship between empirical formula and molecular formula?The empirical formula of a compound and the molecular formula is related as follows:
Molecular formula = n x empirical formulaThe empirical mass of the compound = 12 + 4 = 14
n = molecular mass/empirical mass
n = 98.1861/14 = 7
molecular formula will be n(CH2) = C₇H₁₄
In conclusion, the molecular formula is determined from the molecular mass and empirical mass.
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What is the change in temperature if 500 J of heat are added to a 23 g sample of silver? (Thespecific heat of silver is 0.24 J/g °C)
The change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.
How to calculate change in temperature?The change in temperature of a substance can be calculated using the following formula:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperature500 = 23 × 0.24 × ∆T
500 = 5.52∆T
∆T = 500/5.52
∆T = 90.58°C
Therefore, the change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.
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When magnesium chloride (MgCl2) dissolves in water, it dissociates into magnesium ions and chloride ions. How many moles of ions form when a 42.66-gram sample of magnesium chloride is dissolved in water?
A.0.448 mol
B.0.714 mol
C.1.34 mol
D.2.14 mol
0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water (option A).
How to calculate number of moles?According to this question, when magnesium chloride (MgCl2) dissolves in water, it dissociates into magnesium ions and chloride ions as follows:
MgCl2(aq) ⟶ Mg2+(aq) + Cl−(aq)
However, if a 42.66-gram sample of magnesium chloride is dissolved in water, this means that 42.66g/molecular mass of MgCl2 will be the number of moles of the ionic products.
molecular mass of MgCl2 = 95.3g/mol
moles = 42.66g ÷ 95.3g/mol = 0.448mol
Therefore, 0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water.
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A flask contains 0.545 mol of liquid bromine, Br2. Determine the grams of bromine molecules present in the flask.
Answer:
when asking this question they are looking for the number of Br2 therefore .5 mol
.5*6.022*1023 molecules which equals 3.011*1023 molecules
Explanation:
Its correct
Molar mass of Br_2=160g/mol
No of moles=0.545
Mass
moles×Molar mass0.545(160)87.2gFor the reaction: N2(g) + H2(g) → NH3(g)
If the rate of decrease of N2 is -0.11M/s what is the rate of increase of NH3?
I know I must first balance the equation, to which I get: N2+3H2 -> 2NH3
Where do I go from here? Please explain step by step
The rate of increase of NH3 is 0.22M/s.
What is the balanced equation of the reaction?The balanced equation of the reaction is given below:
N2(g) + 3 H2(g) → 2 NH3(g)The rate of decrease of N2 is half the rate of increase of NH3.
Rate of decrease of N2 = -0.11 M/s
Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.
In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.
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13 V
3 A
4V
3V
R=?
Calculate the resistance measured across the second light bulb.
Net potential
13V+4V+3V20VNet current=3A
Apply ohm's law
R=V/IR=20/3R=6.67OhmAmol has divided some substances into two groups as shown in the table below. He wants to further separate all the substances in Group 1 again into exactly two groups. Which of the following criteria will allow him to do so?
A. liquids and solids
B. mixtures and pure substances
C. naturally occurring and man-made substances.
D. substances completely soluble and insoluble in water.
The criteria that will allow Amol separate group 1 substances into two groups are mixtures and pure substances (option B).
What are mixtures and pure substances?Mixtures are substances that are made up of two or more substances that can be easily separated.
Pure substances, on the other hand, are elements and compounds that cannot be separated by chemical means.
In group 1 of the above table, the substances can be classified as follows:
Soil - mixtureTomato ketchup - mixtureSmoke - compoundMilk - mixtureHair shampoo - mixtureTherefore, the criteria that will allow Amol separate group 1 substances into two groups are mixtures and pure substances.
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Answer:
Explanation:
b is the right answer
Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the Henry's law constant is kH = 3.7 × 10^–2 mol/(L • atm), and the mole fraction of O2 in the atmosphere is 0.209
Calculate the solubility (in M) of O2 in the blood of a scuba diver at a depth of 100 feet, where Patm = ~3 atm
_______ M
The solubility (in M) of O2 in the blood of a scuba diver at a depth of 100 feet is 2.32 × 10^-3 mol.
How to calculate the solubility?It should be noted that the partial pressure of oxygen will be:
= Mole fraction × Total pressure
= 0.209 × 3
= 0.627
According to Henry's law, the solubility will be:
= 3.7 × 10^-2 × 0.627
= 2.32 × 10^-3 mol
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What is the balanced equation of
H2 + Cl2 —-> HCl
Answer:
The balanced equation of H2 + Cl2 —-> HCl is 2H2 + 2Cl2 —-> 2HCl.
Explanation:
In a chemical reaction, the number of atoms of each element must be the same on both sides of the equation. In this case, there are two atoms of hydrogen on the left side and two atoms of chlorine. On the right side, there is one atom of hydrogen and one atom of chlorine. In order to balance the equation, we must add another chlorine atom to the right side so that there are two atoms of chlorine on both sides of the equation. The final balanced equation is 2H2 + 2Cl2 —-> 2HCl.
What is the molecular geometry of H2O?
A. Bent
B. Tetrahedral
C. Trifocals pyramid
D. Linear
Answer:
b option
Explanation:
H2O has a tetrahedral arrangement of molecules or an angular geometry. This is mainly because the repulsion from the lone pair combination is more than bond-pair repulsion.
Which of these ionic compounds have polyatomic ions? Check all that apply.
16. What volume of water vapor gas would be produced from the combustion of 535.55 grams of propane (C3H8) with 2,665.06 grams of oxygen gas, under a pressure of 0.96 atm and a temperature of 350. degrees C? Given:
C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g)
(OR C3 H8 ("g") + 5 O2 ("g") right arrow 3 C O2 ("g") + 4 H2O ("g")
Do not type units with your answer
The volume of water vapour gas that would be produced will be 2,581.73 L
Stoichiometric calculationsFrom the equation of the reaction, the mole ratio of propane to oxygen is 1:5.
Mole of 535.55 grams of propane = 535.55/44.1 = 12.12 moles
Mole of 2665.06 grams of oxygen = 2665.06/32 = 83.28 moles
Going by the mole ratio, it appears propane is limiting while oxygen is in excess.
From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:
12.12 x 4 = 48.48 moles.
Using the ideal gas equation: pv = nRt
v = nRT/p = 48.48 x 0.08206 x 623/0.96 = 2,581.73 L
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A sample of gas is at a pressure of 2.81 atm, 664 K, and a volume of 713 L. What will
be the pressure of the gas if its volume and temperature change to 126 L, and 368 K
respectively?
Answer:
8.81 atm
Explanation:
P1 V1 /T1 = P2 V2 / T2 T must be in Kelvin
re-rrange to :
P1 V1 / T1 * T2/V2 = P2
2.81 * 713 / (664) * 368 /126 = 8.81 atm
The new pressure of the gas given that its volume and temperature change to 126 L and 368 K respectively is 8.81 atm
Data obtained from the question Initial pressure (P₁) = 2.81 atmInitial volume (V₁) = 713 L Initial temperature (T₁) = 664 K New Volume (V₂) = 126 L New temperature (T₂) = 368 KNew pressure (P₂) = ?How to determine the new pressureThe new pressure of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
(2.81 × 713) / 664 = (P₂ × 126) / 368
Cross multiply
664 × 126 × P₂ = 2.81 × 713 × 368
Divide both side by 664 × 126
P₂ = (2.81 × 713 × 368) / (664 × 126)
P₂ = 8.81 atm
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5. When. 0.333g of a particular molecular compound dissolves in 33.3 grams of benzene, the freezing point was observed to drop by 0.485 °C. (In actual practice this is absurdly precise for a temperature measurement, but it makes the problem easier to solve.) What is the molecular weight of the molecular compound?
The molecular weight of the molecular compound is
x= 105.57 g/mol
What is the molecular weight of the molecular compound?Generally,a the equation for Mole of molecular compound is mathematically given as
Mm= mass / molar mass
Therefore
Mm= 0.333 g / x
the equation for Morality
M = mole of solute / mass of solvent
[tex]M = \frac{(0.333 g / x )}{33.3 g / 1000 }[/tex]
M= 10 / x
the equation for change in temp dt
dt= K* morality
Therefore
[tex]0.485 = \frac{5.12}{ * 10/ x}[/tex]
x = (5.12 *10) / 0.485
x = 105.57 g/mol
In conclusion, molecular mass of molecular compound
x= 105.57 g/mol
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What change would shift the equilibrium system to the left?
A(g) + B(s) + Energy ⇌ 3C(g) (3 points)
Adding more of gas C to the system
Heating the system
Increasing the volume
Removing some of gas C from the system
Answer:
A.) Adding more of gas C to the system
Explanation:
A.) is correct because the reaction wants to keep the same amount of reactants and products that sustain equilibrium. If you are increasing the amount of gas C, this will push the reaction to make more of the reactants to restore the balance.
B.) is incorrect because heat is a form of energy. As previously stated, when you add more material to the reactants side, the equilibrium shifts to the product side to restore equilibrium.
C.) is incorrect because when the volume is increased, the equilibrium will shift to the side with the greater amount of moles of gas. There is 1 mole of gas on the reactant side (from A (g)) and 3 moles of gas on the products side (from 3 C (g)). Therefore, the reaction will shift to the product side.
D.) is incorrect because if the material on the product side is decreasing, the equilibrium will want to make up that difference by shifting to the product side.
Remember,
reactants ---> products
Anybody know the answer to this
An atom's mass is determined by its protons and neutrons.
An atom's charge is determined by its number of protons minus it number of electrons.
Atoms become cations, or positively charged when they lose an electron, and since electrons have a negative charge, they become anions, or negatively charged.
Water is a universal solvent.
Carbohydrates (carbs) are used by the body for energy.
Steroids and triglycerides are lipids.
Proteins that catalyze chemical reactions are called enzymes.
Given: t = 8.5 minutes, A = 1.50 for electroplating copper from copper (II);
what is the mass copper plated on to the key?
A(n). Is an electrically charged atom
An ion is an electrically charged atom. Details about ions can be found below.
What is an ion?Ion in chemistry refers to an atom or group of atoms bearing an electrical charge.
An example is the sodium (Na+) and chlorine (Cl-) atoms in a salt solution.
Therefore, it can be said that an ion is an electrically charged atom.
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20. What happens to the wavelength of a wave if the frequency is increased?
A wavelength's frequency and energy (E) drop as it becomes longer. You may conclude from these equations that the wavelength grows shorter as the frequency rises. The wavelength lengthens as the frequency drops.
Since frequency and wavelength are inversely related to one another, the wavelength of the wave falls as frequency increases.
(9) An element which is used to observe the physical property brittlness
1.Magnesium. 2.Copper
3.Aluminum. 4.Sulphur
A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa.
The pressure increases to 304 kPaand the temperature remains constant.
What will the volume be?
0.66 L
1.51 L
2.26 L
4.50 L
The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).
How to calculate volume?The volume of a substance can be calculated using the following formula:
P1V1 = P2V2
Where;
P1 = initial pressureP2 = final pressureV1 = initial volumeV2 = final volume153 × 3 = 304 × V2
459 = 304V2
V2 = 459/304
V2 = 1.51L
Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.
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A boy wants to throw a can straight up and then hit it with a second can. He wants the
collision to occur 4.0 m above the throwing point. In addition, he knows that the time
he needs between throws is 3.0 s. Assuming he throws both cans with the same speed,
What must the initial speed be?
The initial speed of the boy's thrown is determined as 16.03 m/s.
Initial speed of the boy's throwThe initial speed of the throw is calculated as follows;
h = vt - ¹/₂gt²
4 = 3t - (0.5)(9.8)(3)²
4 = 3t - 44.1
3t = 48.1
t = 48.1/3
t = 16.03 m/s
Thus, the initial speed of the boy's thrown is determined as 16.03 m/s.
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Samantha wants her team however she needs to make a decision to feel excited about compounding a new medication
Samantha wanting her team however she needs to make a decision to feel excited about compounding a new medication is ideal.
What is Medication compounding?This is the process of changing or mixing ingredients in order to suit the needs of an individual.
This technique should be best employed so as to ensure prompt and accurate treatment of her illness.
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H2O2+CLO2====CLO-2+O2. Balance the equation using half reaction
Answer:
I have the explanation.
Explanation:
Assume that matter does not consist of atoms. Show by example how this assumption leads to
hypothetical predictions which contradict the Law of Multiple Proportions. Do these hypothetical
examples contradict the Law of Definite Proportions? Are both observations required for
confirmation of the atomic theory?
If matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because compound would have random composition.
What is the law of definite proportions and law of multiple proportions?The law of definite proportions states that all pure samples of a compound contains the same element in a fixed mass ratio.
The law of multiple proportions states that if an element combines with another element to form more than one compound, the mass of the element combines with a fixed mass of the other element in whole number multiples ratios.
Assuming matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because, their will be no definite ratio or composition in compounds.
The law definite proportions and law of multiple proportions are required for the atomic theory as they help prove that matter consists of definite unique particles called atoms.
In conclusion, the existence of atoms is proved true by the law definite proportions and law of multiple proportions.
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