Answer:
electrons
Explanation:
because it electrons
what is the prmary source of energy inside of the earth
A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº
Applying Charles law
[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]
[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]
[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]
what are the three elements that can be used to make a magnet?
Answer:
Iron, cobalt, and nickel are the only three naturally occurring elements that are magnetic.
Explanation:
hope it helps
correct me if I'm wrong thank you
brainliest please
Answer:
The three elements that can be used to make a magnet are :
Aluminum, nickel and cobalt
how to put in velocity into a graphing calculator
Answer:
You need a graphing calculator that implemented vectors. I don't know any that have it. Sorry.
Answer:
Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps:
Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds ,
Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .
Explanation:
How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
The weak nuclear force causes:
(A). Lightning
(B). Combustion
(C). Radiation
D). Protons and neutrons to form the nuclear of atoms
Answer:
(C) Radiation
Explanation:
The weak nuclear forces causes radiation to form.
A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s
Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]
Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.
Let M = 1kg and m = 3 kg
Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.
When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,
M( g + a) = m(g - a)
1(9.8 + a) = 3( 9.8 - a)
9.8 +a = 29.4 - 3a
collect the like terms
4a = 19.6
a = 19.6/4
a = 4.9 m/[tex]s^{2}[/tex]
Therefore, the cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]
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When the mass of the cylinder increased from 3. 0 kg to 6. 0 kg, what happened to the amount of heat generated in the system? It decreased by a factor of 3. It decreased by a factor of 2. It increased by a factor of 2. It increased by a factor of 3.
When the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.
The given parameters:
Initial mass of the cylinder, m₁ = 3.0 kgFinal mass of the cylinder, m₂ = 6.0 kgThe amount of heat generated in the system is calculated as follows;
Q = mcΔT
where;
m is the massc is the specific heat capacityΔT is the change in temperatureIf we keep every other parameters constant and change the mass from 3.0 kg to 6.0 kg, the increase in the heat generated is calculated as follows;
[tex]Q_1 = 3c \Delta T\\\\Q_2 = 6c\Delta T\\\\Q_2 = 2(3c \Delta T)\\\\Q_2 = 2Q_1[/tex]
Thus, when the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.
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Please HELP
6. A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed
of 10.0-m/s.
a.
If the rope can only tolerate 400-N of force, what is the maximum speed the bucket can
experience before the rope snaps? {Hint: Let the centripetal force be 400-N and solve for the speed)
Answer:
Explanation:
hope this helps
The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.
What is force?Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.
Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.
Given:
The mass of the bucket, m = 3.4 kg,
The length of the rope, r = 1 m,
The speed of the bucket, v = 10 m / s,
The force of the rope, F = 400 N,
Calculate the maximum speed by the formula given below,
[tex]F_c = mv^2 / r[/tex]
400 = 3.4 v² / 1
v² = 400 / 3.4
v² = 117.6
v = 10.85 m / s
Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.
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A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
4) What process produces carbon dioxide?
a) photosynthesis
b) replication
c) mutation
d) respiration
5) What happens during cytokinesis?
a) a spindle forms
b) chloroplasts release energy
c) the cytoplasm divides
d) chromosomes
plz answer asap
Answer:
d and c are the answers :)
A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?
By Newton's second law, the car slows down with an average acceleration a such that
-7100 N = (1500 kg) a ⇒ a ≈ -4.7 m/s²
If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that
0² - (25 m/s)² = 2a ∆x ⇒ ∆x ≈ 66 m
The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The acceleration is found as;
F=ma
-7100 N = (1500 kg) a
a= -4.7 m/s²
If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;
v²=u²+2as
v²-u²=2as
0² - (25 m/s)² =2×(-4.7) s
s=66 m
Hence,the car slide before it comes to rest will be 66 m.
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How much energy has 4x 1010 m³ of water collected in a reservoir at a 2. 3. height of 100 m from the power house? What kind of energy is that? (Given, mass of 1 m³ of water = 1000 kg)
Explanation:
[tex] \rule{999pt}{66646pt}[/tex]
why does polishing the surface of a metal extend fatigue life
Answer:
they are machined with shape characteristics which maximize the fatigue life of a metal.
Explanation:
they are highly polished to provide the surface characteristics which enable the best fatigue life.
SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.
Answer:
1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time
2. 36÷4= 9
(formula) Speed = distance ÷ time
3. Meter (M) centimeter (cm) kilometers (km)
4. Seconds , Hour, Minute
5. 65÷13=5 (object A)
125÷ 25= 5 (object B)
their both Equal of the amount of speed, so they are travelling at the same speed
Hope I helped
An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground
Answer:
20 ft/sec / 32 ft/sec^2 = .625 to reach top
2 * .625 = 1.25
It will be on the ground at t = 0 and t = 1.25
You can also solve the equation:
H = 0 = V0 t - 1/2 g t^2
Obviously, at t=0 h = 0
V0 = 1/2 g t is a solution
t = 20 * 2 / 32 = 1.25 sec
which is the correct relationship among pressure, flow, and resistance?
Answer:
Flow is proportional to change in pressure and inversely proportional to resistance.
Anyone please help thank you
Answer:
A) earth
B) live
C) live
D) earth
Explanation:
hope i help
what is the theory relativity by Einstein?
:MAIN ANSWER:
determined that the laws of physics are the same for all non-accelerating observers
Explanation:
Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.
HOPE IT HELPS
#CARRY ON LEARNING
HAPPY HOLIDAYS DEC 2021
Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30
Answer:
here's your answer below
Explanation:
sorry something went wrong
.
What type of bond is found in pure gold?
A) Metallic
B) Ionic
C)Covalent
D)Diatomic
The type of bond found in pure gold is metallic bonding, indicated by metallic bonds. Therefore option A is correct.
Metallic bonding occurs between metal atoms, such as gold, and is characterized by the sharing of electrons among a sea of delocalized electrons.
In metallic bonds, the valence electrons of metal atoms are not strongly bound to any particular atom but are free to move throughout the metal lattice.
This sharing of electrons gives rise to properties such as high electrical and thermal conductivity, malleability, and ductility, which are characteristic of metals like gold.
Unlike ionic or covalent bonds, metallic bonds do not involve the transfer or sharing of electrons between different elements.
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A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
[tex]\large\boxed{F_D = \mu N}}[/tex]
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
calculate the resultant force acting on the object and state its direction
[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]
Direction is east.Assume ideal behavior. How many moles of are needed to fill a 2000L weather balloon at 210K and 1atm pressure? Round your answer to the nearest mole (use R = 0.082057 L atm mol-1K-1)
Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.
In this case, you know:
P= 1 atmV=2000 Ln= ?R= 0.082057 [tex]\frac{atmL}{molK}[/tex]T= 210 KReplacing in the ideal gas law:
1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K
Solving:
[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]
n=116.06 moles
Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
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https://brainly.com/question/4147359?referrer=searchResultswhy does rhododendron not grow well in the terai region of nepal give reason
Answer:
Tge Rhododendrob is the national flower of Nepal. The hills and mountain sides ranges of Nepal are decorated with diff colours and shapes
Can someone help with 25 to 28 it’s multiple-choice!
Answer:
25:speed
26:acceleration
27:scalar
28:kinetic
What are the three different social perspectives on sport
Answer:
functionalist theory,feminist theory. discipline of sociology
the gravitational force acts on all objects in proportion to their mass. neglecting air resistance, why don’t heavy objects fall faster than light ones?
Answer:
Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)
0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle
Answer:
0.60N along the line tangent to the circle
Answer:
A is the answer
Explanation:
Just got finished with the quiz! Hope this helps <3
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]
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Answer:
6.983 km/hr
Explanation:
The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr
Mejor yo por favor