Weights of 2000 male students follow a normal distribution with a mean of 200 and standard deviation of 20. Find the number of students with weights (1) between 120 and 130 pounds, (ii) at most 250 pounds, fiin between 150 and 175 and (iv) at least 200 pounds

Answer:

1. The set of whole numbers contains the set of rational numbers.  FALSE.

The set of integers contains the set of rational numbers

2. Every terminating decimal is a rational number.       TRUE

3. Every square root is a rational number.       FALSE

Many square roots are irrational numbers, meaning there is no rational number equivalent.

4. The integers are closed under addition.      TRUE

Answer:

[tex]L^{2} + W^{2} = d^{2}[/tex]

d = 31.6

Step-by-step explanation:

[tex]L^{2} + W^{2} = d^{2}[/tex]

[tex]30^{2} + 10^{2} = d^{2}[/tex]

[tex]d^{2}[/tex] = 900 + 100

   =  1000

d = [tex]\sqrt{100}[/tex] = 31.6

Answer:

27,29,38,39,42,52,53

Step-by-step explanation:

The probability that a randomly selected person will have a white blood cell count of between 2000 and 10,000 is 0.9223 approximately.

The given mean, standard deviation, and the range of values are as follows:

Mean = 7500

Standard deviation = 1750

Range of values = Between 2000 and 10000

We are required to calculate the probability of a random person having a white blood cell count between 2000 and 10000.

Let's find the Z values for 2000 and 10000.Z1 = (2000 - 7500) / 1750 = -3Z2 = (10000 - 7500) / 1750 = 1.43

The required probability is the sum of the probability of the given range of values.

The probability of the first value is:P(X < 2000) = P(Z < -3) = 0.00135

The probability of the second value is:P(X > 10000) = P(Z > 1.43) = 0.0764

To find the probability for the given range, we will subtract the probability of the second value from the probability of the first value.

P(2000 < X < 10000) = 1 - P(X < 2000) - P(X > 10000)P(2000 < X < 10000)

= 1 - 0.00135 - 0.0764P(2000 < X < 10000) = 0.9223

The probability that a randomly selected person will have a white blood cell count between 2000 and 10,000 is 0.9223, approximately.

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Answer:

here, i can help you out!

Step-by-step explanation:

Answer:

For 1. 2/5 is less full then 1/2

The inverse of the given function is represented by Data Table B.

A function is a law that relates a dependent and an independent variable.

The Inverse of the function is determined by interchanging the values of a and y in an f(x,y) function and then express the equation of y in terms of x.

Th table of the function is

Miles to go             Miles Travelled

0                                       0

100                                  310

200                                  450

340                                   550

650                                   650

The inverse of this data table will be

 Miles Travelled             Miles to go

650                                        650

340                                        550  

200                                       450

100                                        310

0                                             0

This is represented by Data Table B.

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Answer:

it 10000

Step-by-step explanation:

79ib dlndokveik dinfl. kwbfb

Answer:

14 mm

Step-by-step explanation:

Just write down the answer.

Answer:

28mm

Step-by-step explanation:

is the right answer

Answer:

Here's a calculator that should help

Step-by-step explanation:

https://www.calculatorsoup.com/calculators/algebra/completing-the-square-calculator.php

Answer:

9.6

Step-by-step explanation:

Answer:

[tex]9.6[/tex]

Step-by-step explanation:

1) Simplify 3 × 0.2 to 0.6.

[tex]0.6 + 9[/tex]

2) Simplify.

[tex]9.6[/tex]

Hence, the answer is 9.6

When a triangle is dilated by a scale factor, the area of the dilated triangle is equal to the scale factor squared times the area of the original triangle. The area of the dilated triangle is 828 cm².

In this case, the original triangle has an area of 23 cm². The triangle is dilated by a factor of 6, so the scale factor is 6.

To find the area of the dilated triangle, we use the formula:

Area of Dilated Triangle = (Scale Factor)^2 * Area of Original Triangle

Plugging in the values:

Area of Dilated Triangle = 6^2 * 23 cm²

                       = 36 * 23 cm²

                       = 828 cm²

Therefore, the area of the dilated triangle is 828 cm².

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Step-by-step explanation:

Given

- 72 = 8 ( y - 3 )

or - 72 / 8 = y - 3

or, - 9 = y - 3

y = - 9 + 3

Therefore X = - 6

Hope it will help :)❤

Answer:

Step-by-step explanation:

-72=8y-24

-72+24=8y

-48=8y

-48/8=y

-6=y

Answer:

4:1 ratio

Sugar: 1 cup

Butter: 3/4 cups

Eggs: 2

Baking powder: 3/8 tsp

Flour: 5/8 tsp (you need way more flour for cookies)

Salt: 1/8 tsp (original # was hard to make out but I think it was 1/2 tsp)

Answer:

x = 24

Step-by-step explanation:

x = .4(60)

x = 24

40% of 60 can be found by converting 40% to a decimal and multiplying it by 60.

40% = 0.4

60x0.4=2.4

Now move the decimal point right one.

So x is 24.

---

hope it helps

Answer:

try this link!

Step-by-step explanation:

https://www.wylieisd.net/cms/lib09/TX01918453/Centricity/Domain/783/Math%20Connections%20Key.pdf

(a) The parity check matrix H is:

1 1 1 0 1

0 1 0 1 1

0 1 1 0 0

To find the parity check matrix H, we can use the fact that H is the transpose of the generator matrix G with an identity matrix on the right side.

Given the generator matrix G:

1 0 0 1

1 1 1 0

1 0 1 1

0 1 0 0

1 1 0 1

We can rewrite G as:

1 0 0 1 1 1 0 0

1 1 1 0 0 1 1 0

1 0 1 1 1 0 1 1

0 1 0 0 1 1 0 0

1 1 0 1 0 1 1 1

Now, we can obtain the parity check matrix H by taking the transpose of G and removing the rightmost identity matrix:

H = Transpose(G without the rightmost identity matrix)

H =

1 1 1 0 1

0 1 0 1 1

0 1 1 0 0

Therefore, the matrix H is:

1 1 1 0 1

0 1 0 1 1

0 1 1 0 0

(b) The minimum distance of a linear block code is the smallest number of bit positions in which any two codewords differ. It determines the error detection and correction capability of the code.

To find the minimum distance of the code, we can examine the columns of the parity check matrix H. The number of non-zero entries in the smallest column gives us the minimum distance.

Looking at the parity check matrix H, we see that the smallest column has two non-zero entries in positions 1 and 2. Therefore, the minimum distance of the code is 2.

In conclusion, the minimum distance of the code is 2.

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Answer:

Your answers are correct

Step-by-step explanation:

Answer:

27,804

Step-by-step explanation:

28x993= 27,804

Answer:

C.

Step-by-step explanation:

Answer A and D are definitely incorrect.  Hope this helps Zoey. #Zoeyiscute:)

Answer:

(Disclaimer: all digits in the answers are in the measuring unit degrees)

1) 15

2) 16

3) 46

4) 59.

Step-by-step explanation:

The first one is said to add up to 89, so you have to do 89 subtract 44 and 30 as they are told. That = 15

The second one is a right angle, meaning it adds up to 90. You do 90 - 74 as that is the value told. That = 16

Angles on a straight line = 180 so you have to do 180 - 134 as that is the value told. This = 46

This is 54 as opposing angles on two lines are =. That means this = 59 too.

Correction in the Question:

A wooded area is in the shape of a a trapezoid whose bases measure 128 m and 92 m and its height is 40 m. A 4 m wide walkway is constructed which runs perpendicular from the two bases. Calculate the area of the wooded area after the addition of the walkway.

Answer:

The wooded area after the addition of the walkway is 4240 [tex]m^2[/tex].

Step-by-step explanation:

we are given

length of the two bases = 128m and 92m

height of the trapezoid = 40m

the approximate figure of the given trapezoid is given as:

             __ __ __ 92 __ __ _

          /  |               |  |                 \

       /     | 40         |4|                    \

    /__ _| __ __     |  |__ __ __ __ \

                           128

Area of a trapezoid = [(a + b)/2] * height, where a and b are representing the bases of the given trapezoid.

Area = [(92 + 128)/2] * 40

        = [220/2] * 40  

        = 110 * 40

        = 4400 [tex]m^2[/tex]

Now there is a 4m wide walkway is to be constructed in that trapezoid. The pathway will be a rectangle as it has 4m width and 40m height as it is perpendicular to both the bases.  

Area of a rectangle = length * width

Area = 40 * 4

        = 160

Since the walkway will reduce the area of the trapezoid as it is constructed upon it therefore the wooded area after the addition of the walkway is

4400 + (-160) = 4240 [tex]m^2[/tex].

In the given word problem, the rate of change is the change in the cost of the ice cream concerning the change in the number of scoops.

That is, the rate of change is the ratio of the change in the cost of ice cream and the change in the number of scoops. Let's first calculate the initial rate of change or slope of the given deal: When we buy a waffle cone, the cost is $3, and we can buy one scoop of ice cream for $1.50.So, for one scoop of ice cream, the total cost would be 3 + 1.50 = $4.50.

We can represent the cost of one scoop of ice cream with the help of a linear equation: y = mx + b. Here, the slope or the rate of change, m = Change in cost of ice cream/ Change in the number of scoops= 1.5/1= 1.5Therefore, the rate of change of the ice cream with respect to the number of scoops is $1.50/scoop.

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Answer: 0,2

Step-by-step explanation:

Eigenvalues and eigenvectors play a crucial role in the study of linear transformations and matrices. For a normal matrix A, it can be proven that eigenvectors corresponding to different eigenvalues are necessarily orthogonal.

To understand why eigenvectors corresponding to different eigenvalues are orthogonal for a normal matrix, we need to consider the properties of normal matrices. A matrix A is normal if it commutes with its conjugate transpose A* (i.e., A * A* = A* A).

Now, let's consider two eigenvectors v₁ and v₂ corresponding to different eigenvalues λ₁ and λ₂, respectively. We want to show that v₁ and v₂ are orthogonal, meaning their dot product is zero (v₁ · v₂ = 0).

Let's denote the conjugate transpose of A as A*, and the eigenvalues and eigenvectors as follows:

A * A = A * A*   (1)

Multiplying both sides of equation (1) by v₂* (the conjugate transpose of v₂) from the left gives:

v₂* A * A = v₂* A * A*   (2)

Since v₂ is an eigenvector of A, we can express it as:

A * v₂ = λ₂ v₂    (3)

Substituting equation (3) into equation (2) gives:

v₂* λ₂ A = v₂* A * A*    (4)

Now, let's multiply equation (4) by v₁ from the right:

v₂* λ₂ A v₁ = v₂* A * A* v₁    (5)

Since v₁ is an eigenvector of A, we can express it as:

A * v₁ = λ₁ v₁    (6)

Substituting equation (6) into equation (5) gives:

v₂* λ₂ λ₁ v₁ = v₂* λ₁ A* v₁    (7)

Notice that λ₁ and λ₂ are scalars, so we can move them around. Taking the conjugate transpose of equation (7), we get:

(λ₂ λ₁) v₁* v₂ = (λ₁ v₁)* A v₂    (8)

Now, we have v₁* v₂ on the left-hand side and (λ₁ v₁)* A v₂ on the right-hand side. If v₁ and v₂ are not orthogonal (v₁ · v₂ ≠ 0), then v₁* v₂ ≠ 0. However, the right-hand side of equation (8) is proportional to (λ₁ v₁)* A v₂, which is proportional to A v₂. This implies that A v₂ is a scalar multiple of v₁, which contradicts the assumption that v₁ and v₂ correspond to different eigenvalues.

Therefore, we conclude that eigenvectors corresponding to different eigenvalues for a normal matrix are necessarily orthogonal.

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Given collinear points A, B, and M, with M dividing AB internally in the ratio of 7:5, and a point P not on the line AB, it can be shown that PM is equal to the sum of PA and PB.

Let's consider the line segment AB, where M is a point that divides it internally in the ratio of 7:5. This means that the ratio of AM to MB is 7:5.

Now, let's consider the triangle PAB, where P is a point not on the line AB. We want to show that PM is equal to the sum of PA and PB.

Since M divides AB internally in the ratio of 7:5, we can express AM and MB in terms of their lengths. Let's assume the length of AM is 7x and the length of MB is 5x.

Using this information, we can express the lengths of PA and PB in terms of x as well. Let's denote the length of PA as y and the length of PB as z.

Since M divides AB internally in the ratio of 7:5, we can write:

AM/MB = 7x/5x = 7/5

Similarly, we can express the ratios of PM to PA and PM to PB:

PM/PA = 7x/y

PM/PB = 5x/z

We need to show that PM is equal to PA + PB:

PM = PA + PB

Substituting the ratios we derived earlier:

(7x/y) = (5x/z) + 1

To simplify the equation, we can multiply both sides by yz:

7xz = 5xy + yz

Next, we can factor out the common factor of y:

7xz = y(5x + z)

Now, we can divide both sides by (5x + z):

PM = y

Therefore, we have shown that PM is equal to PA + PB.

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Answer:

sin(4x) = sin(2x) is unsolvable.

Step-by-step explanation:

The two sides are not equal.

1. The value of x is:

180° - 40° - 30° = 110°

2. The value of x is:

90°- 38° = 52°

Answer:

Step-by-step explanation:

180 = 40 + x + 30

110 = x

90 = 38 + x

52 = x

The exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3

To verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5], we need to check if the following conditions are satisfied:

Let's check each condition:

f(x) = x³ - 10x² + 31x - 30 is a polynomial function and is continuous for all real values of x. So, it is continuous on [2, 5].

To check the differentiability, we need to find f'(x):

f'(x) = 3x² - 20x + 31.

The derivative f'(x) exists and is continuous for all real values of x. So, f(x) is differentiable on (2, 5).

Now, let's evaluate f(2) and f(5):

f(2) = (2)³ - 10(2)² + 31(2) - 30 = -10

f(5) = (5)³ - 10(5)² + 31(5) - 30 = 95

Since f(2) = -10 is not equal to f(5) = 95, we can conclude that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5] after differentiable.

To find the values of c in the interval (2, 5) such that f'(c) = 0, we need to solve the equation f'(c) = 3c² - 20c + 31 = 0.

Using quadratic formula:

c = (-(-20) ± sqrt((-20)² - 4(3)(31))) / (2(3))

c = (20 ± sqrt(400 - 372)) / 6

c = (20 ± sqrt(28)) / 6

c = (20 ± 2sqrt(7)) / 6

c = (10 ± sqrt(7)) / 3

The values of c in the interval (2, 5) such that f'(c) = 0 are:

c = (10 + sqrt(7)) / 3

c = (10 - sqrt(7)) / 3

Therefore, the exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3.

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Incomplete question:

Verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² +31x-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.

Enter the exact answers in increasing order.

To enter √a, type sqrt(a)

c = ?