Given the expression :
[tex]16.2-3\mleft(4\mright)+\frac{14}{2}[/tex]so, the result will be as following:
[tex]\begin{gathered} 16.2-3\mleft(4\mright)+\frac{14}{2} \\ \\ =16.2-12+7 \\ \\ =11.2 \end{gathered}[/tex]the term 16.2 is a constant
Hey there!
Whenever, you hear or see the word “constant” think of the definition ‘a specific number or value that never changes in a particular equation’
16.2 - 3(4) + 14/2
= 16.2 - 12 + 14/2
= 16.2 - 12 + 7
= 4.2 + 7
= 11.2
Now, that we have that information out the way, we can answer your equation
Your CONSTANTS aren’t:
• -3(4) because we had to simplify it and convert it to: -12
• 14/2 because we had to simplify that as well and it converted it to: 7
(That’s how we figured out to make the equation much easier to breakdown)
(By the way, you can use PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, & Subtraction) to solve for the overall problem, like how I did for you :))
This leaves the constant to: 16.2 because we didn’t have to anything to it.
Therefore, your answer should be:
16.2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
What is the area of the triangle 9 2 12
The given diagram is a traingle with base 12 units, height 4 units, and one side 9 units.
Since base (b) and height (h) are known, we can use the following formula for the area (A) of the triangle,
[tex]A=\frac{1}{2}bh[/tex]Substitute the values and simplify the expression,
[tex]\begin{gathered} A=\frac{1}{2}\times12\times4 \\ A=6\times4 \\ A=24 \end{gathered}[/tex]Thus, the area of the given triangle is 24 square units.
Simplify completely.a.4x212 xwhen x +0.b. (2t)(3t)(t)c. (3x² - 4x +8)+(x² +6x-11)d. (3x² + 4x – 8) - (x² + 6x +11)
The expression in 4a) is given below
[tex]\frac{4x^2}{12x}[/tex]Collecting similar terms using the division rule of indices, we will have
[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]The above expression therefore becomes
[tex]\begin{gathered} \frac{4x^2}{12x} \\ =\frac{4x^2}{12x^1} \\ =\frac{1}{3}\times x^{2-1} \\ =\frac{1}{3}\times x \\ =\frac{x}{3} \end{gathered}[/tex]Hence,
The final answer = x/3
The wholesale price for a chair is 194$ . A certain furniture store marks up the wholesale price by 35%. Find the price of the chair in the furniture store.
The price of the chair will be 261.9 $ .
One percent (symbolized 1%) is a hundredth part; thus, 100 percent represents the entirety and 200 percent specifies twice the given quantity. For example, 1 percent of 1,000 chickens equals 1/100 of 1,000, or 10 chickens; 20 percent of the quantity is 20/100 1,000, or 200.
If we say, 5%, then it is equal to 5/100 = 0.05.
To solve percent problems, you can use the equation, Percent · Base = Amount, and solve for the unknown numbers. Or, you can set up the proportion, Percent = , where the percent is a ratio of a number to 100. You can then use cross multiplication to solve the proportion.
Based on given conditions formulate
x = 194 ×(35%+1)
x= 194 ×1.35
x = 261.9 $ .
Thus The price of the chair will be 261.9 $ .
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Two cars start moving from the same point. One travels south at 24 mi/h and the other travels west at 18 mi/h. At what rate (in mi/h) is the distance between the cars increasing four hours later?
mi/h
The rate at which the distance between the two cars increased four hours later is 30 mi/h.
How to determine the rate?First of all, we would determine the distances travelled by each of the cars. The distance travelled by the first car after four (4) hours is given by:
Distance, x = speed/time
Distance, x = 24/4
Distance, x = 6 miles.
For the second car, we have:
Distance, y = speed/time
Distance, y = 18/4
Distance, y = 4.5 miles.
After four (4) hours, the total distance travelled by the two (2) cars is given by this mathematical expression (Pythagorean theorem):
z² = x² + y²
Substituting the parameters into the mathematical expression, we have;
z² = 6² + 4.5²
z² = 36 + 20.25
z² = 56.25
z = 7.5 miles.
Next, we would differentiate both sides of the mathematical expression (Pythagorean theorem) with respect to time, we have:
2z(dz/dt) = 2x(dx/dt) + 2y(dy/dt)
Therefore, the rate of change of speed (dz/dt) between the two (2) cars is given by:
dz/dt = [x(dx/dt) + y(dy/dt)]/z
dz/dt = [6(24) + 4.5(18)]/7.5
dz/dt = [144 + 81]/7.5
dz/dt = 225/7.5
dz/dt = 30 mi/h.
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Answer:
30 mi / hr
Step-by-step explanation:
First find out how far the cars are apart after 4 hours
24 * 4 = 96 mi = y
18 * 4 = 72 mi = x
Now use the pythagorean theorem
s^2 = ( x^2 + y^2 ) shows s = 120 miles apart at 4 hours
Now s^2 = x^2 + y^2 Differentiate with respect to time ( d / dt )
2 s ds/dt = 2x dx/ dt + 2y dy / dt
ds/dt = (x dx/dt + y dy/dt)/s
= (72(18) + 96(24)) / 120
ds/dt = 30 mi/hr
Write and solve an equation that represents the following math sentence.
Twenty-nine equals the sum of 11.5 and the quotient of a number and 2.5.
29 equals 11.5 plus m over 2.5; m = 43.75
29 equals 11.5 plus m over 2.5; m = 7
29 = 11.5 + 2.5m; m = 43.75
29 = 11.5 + 2.5m; m = 7
The algebraic expression which correctly represents the word phrase and it's solution are respectively; 29 equals 11.5 plus m over 2.5; m = 43.75.
What is the algebraic expression which correctly represents the given word phrase?It follows from the task content that the algebraic expression of which represents the word phrase is to be determined.
First, the quotient of a number, m and 2.5 can be represented algebraically as; m/2.5.
Therefore, since; Twenty-nine equals the sum of 11.5 and the quotient of a number and 2.5, we have;
29 = 11.5 + (m/2.5)
The solution is therefore as follows;
29 -11.5 = (m/2.5)
17.5 = (m/2.5)
m = 2.5 × 17.5
m = 43.75.
Therefore, the correct answer choice is; 29 equals 11.5 plus m over 2.5; m = 43.75.
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A parents' evening was planned to start at
15h45. There were 20 consecutive
appointments of 10 minutes each and a
break of 15 minutes during the evening. At
what time was the parents evening due to
finish?
C O 19h15
O 19h20
O 19h00
O 20h00
O 19h30
The time on which parents evening was due to finish was 19 hour 20 minutes.
What is time and its unit?
Time is the ongoing pattern of existence and things that happen in what seems to be an irreversible order from the past, through the present, and into the future.
It is a component quantity of various measurements used to order events, compare the length of events or the time gaps between them, and quantify rates of change of quantities in objective reality or in conscious experience. Along with the three spatial dimensions, time is frequently considered a fourth dimension.
The International System of Units is built upon the seven base units of measurement stipulated by the Système International d'Unités (SI), from which all other SI units are derived. The primary unit of time is the second. The second can be shortened using either the letter S or the letter sec.
20 consecutive appointments of 10 mins = 20 × 10 mins
= 200 min
= 3 hours 20 mins
A break of 15 mins = 3 hours 20 mins + 15 min
= 3 hours 35 mins
The time that the parents evening due to finish = 15h 45 min +3h 35 mins
= 19h 20min
Thus, the time on which parents evening was due to finish was 19h 20min.
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What needs to occur for a geometric series to converge?
Given a Geometric Series:
[tex]\sum_{n\mathop{=}1}^{\infty}a\cdot r^{n-1}[/tex]Where "r" is the ratio.
By definition:
[tex]undefined[/tex]A student rolled 2 dice. What is the probability that the first die landed
on a number less than 3 and the second die landed on a number
greater than 3?
I really need help please!
Answer:
n < -15/4
Step-by-step explanation:
You want to use the discriminant to find the values of n for which the quadratic 3z² -9z = (n -3) has only complex solutions.
DiscriminantThe discriminant of quadratic equation ax²+bx+c = 0 is ...
d = b² -4ac
The given quadratic can be put in this form by subtracting (n-3):
3z² -9z -(n -3) = 0
This gives us ...
a = 3b = -9c = -(n -3)and the discriminant is ...
d = (-9)² -4(3)(-(n-3)) = 81 +12(n -3)
d = 12n +45
Complex solutionsThe equation will have only complex solutions when the discriminant is negative:
d < 0
12n +45 < 0 . . . . . use the value of the discriminant
n +45/12 < 0 . . . . . divide by 12
n < -15/4 . . . . . . . subtract 15/4
There will be two complex solutions when n < -15/4.
help pleaseeeeeeeeeeeeeeee
Answer:
(b) f(2) = 28
(c) f(-2) = -20
Step-by-step explanation:
f(2) = -2^3 + 7 x 2^2 - 2 x 2 + 12 f(-2) = -2^3 + 7 x -2^2 - 2 x -2 + 12
1. Calculate Exponents
-2^3 = -8 -2^3 = -8
2^2 = 4 -2^2 = -4
-8 + 7 x 4 - 2 x 2 + 12 -8 + 7 x -4 - 2 x -2 + 12
2. Multiply (left to right)
7 x 4 = 28 7 x -4 = -28
2 x 2 = 4 2 x -2 = -4
-8 + 28 - 4 + 12 -8 - 28 - (-4) + 12
3. Add (left to right)
-8 + 28 = 20 -8 + -28 = -36
20 - 4 = 16 -36 - (-4)= -32
16 + 12 = 28 -32 + 12 = -20
Would the inverse of this graph be a function? Why or why not?
We will have the following:
*First: We would determine the piecewise function that describes the graph.
Since we can see that the function increases by a factor of 2 and decreases by the same factor we would have:
[tex]f(x)=\begin{cases}2x\colon x\ge0\land x\le4 \\ \\ -2x+16\colon x>4\land\le8\end{cases}[/tex]This is:
*Second: We calculate the inverse of the piecewise function:
[tex]f^{-1}(x)=\begin{cases}\frac{x}{2}\colon x\ge0\land x\le4 \\ \\ -\frac{x-16}{2}\colon x>4\land x\le8\end{cases}[/tex]That is:
From this we can see that the inverse of that graph would in fact represent a function, a non-continuous function. [It will represent a function as long as it follows the parameters stablished in the first point]
15 Which of the digits from 2 to 9 is 5544
divisible by?
Answer:
All of em, except 5
Step-by-step explanation:
5544 / 2 = 2772
5544 / 3 = 1848
5544 / 4 = 1386
5544 / 6 = 924
5544 / 7 = 792
5544 / 8 = 693
5544 / 9 = 616
Find all the values of x where the tangent line is horizontal.3f(x) = x³ - 4x² - 7x + 12X=(Use a comma to separate answers as needed. Type an exact answer, using radicals
Given the function:
[tex]h(x)=x^3-4x^2-7x+12[/tex]Find the first derivative:
[tex]h^{\prime}(x)=3x^2-8x-7[/tex]The first derivative gives us the slope of the tangent line to the graph of the function. When the tangent line is horizontal, the slope is 0, thus:
[tex]3x^2-8x-7=0[/tex]This is a quadratic equation with coefficients a = 3, b = -8, c = -7.
To calculate the solutions to the equation, we use the quadratic solver formula:
[tex]$$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$ [/tex]Substituting:
[tex]x=\frac{-(-8)\pm\sqrt{(-8)^2-4(3)(-7)}}{2(3)}[/tex]Operate:
[tex]\begin{gathered} x=\frac{8\pm\sqrt{64+84}}{6} \\ \\ x=\frac{8\pm\sqrt{148}}{6} \end{gathered}[/tex]Since:
[tex]148=2^2\cdot37[/tex]We have:
[tex]\begin{gathered} x=\frac{8\pm2\sqrt{37}}{6} \\ \\ \text{ Simplifying by 2:} \\ \\ x=\frac{4\pm\sqrt{37}}{3} \end{gathered}[/tex]There are two solutions:
[tex]\begin{gathered} x_1=\frac{4+\sqrt{37}}{3} \\ \\ x_2=\frac{4-\sqrt{37}}{3} \end{gathered}[/tex]Please help! I can also change the vent graph to different kinds as well.
Answer:
See below and attached Venn Diagram3
Step-by-step explanation:
No need to change Venn diagrams It is perfectly clear
We will represent the different sets of people using letters A and B for convenienceThat total number of people who "Had Drowsiness" is represented by the maroon circle to the left. )Note some of those participants also belong to the category had Nausea)We will represent the set of all people who had drowsiness as A and the number of people in that set as n(A) = 95 (given)Similarly, the total number of people who had nausea is represented by the aquamarine circle to the right. (Note that some of these people also had drowsiness) We will represent the set of all people who had nausea as B and the number of people in that set as n(B) = 77 (given)The number of people who had both drowsiness and nausea is the intersection area of the two i.e. the Venn diagram area in the middle which overlaps both the circles. This is represented as A and B and we are given that this number n(A and B) = 58The completed Venn Diagram is attached for your convenience
If the Manufacturing Overhead account is closed proportionally to Work in Process, Finished Goods, and Cost of Goods Sold, the related entry will include a ________.
If the Manufacturing Overhead account is closed proportionally to Work in Process, Finished Goods, and Cost of Goods Sold, the related entry will include a Credit to cost of goods sold for $12000
How to solve for the costThe cost of a good is the total amount that was used in the purchase of a particular good form the market.
we have the manufacturing overhead to be = 30000 dollars
the work in progress = 30000 x 25 %
= 30000 x 0.25
= 7500
The finished goods = 30000 x 35 %
= 30000 x 0.35
= 10500
The cost of good sold = 30000 - 10500 - 7500
= 12000
Hence the cost of good sold is 12000
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complete questionManufacturing overhead applied $ 150,000
Actual amount of manufacturing overhead costs 120,000
Amount of overhead applied during the year that is in:
Work in Process $ 37,500 25 %
Finished Goods 52,500 35 %
Cost of Goods Sold 60,000 40 %
Total overhead applied $ 150,000 100 %
If the Manufacturing Overhead account is closed proportionally to Work in Process, Finished Goods, and Cost of Goods Sold, the related entry will include a ________.
debit to Cost of Goods Sold for $12,000
credit to Cost of Goods Sold for $12,000
credit to Cost of Goods Sold for $30,000
debit to Work in Process for $7,500
How many gallons of the water are in the filled tank? You must show work with dimensional analysis using the above fact.
From the question, we can deduce the following:
Length = 5.6 meters
Width = 7.3 meters
Height = 4.5 meters
Where:
1 ft = 0.3048 m
1 cubic foot = 7.48 gallons
Let's find the amount of gallons of water in the tank if the tank is filled to 1 foot below the top of the tank.
Let's first sketch the tank.
We have:
Now, let's find the volume of the tank(total amount of water it can carry).
Apply the formula:
[tex]V=l\times w\times h[/tex]Thus, we have:
[tex]\begin{gathered} V=5.6\times7.3\times4.5 \\ \\ V=183.96m^3 \end{gathered}[/tex]Now, to find the amount of water presently in the tank since it is filled 1 ft below the top of the tank, we have:
[tex]\begin{gathered} V=5.6\times7.3\times(4.5-0.3048) \\ \\ V=5.6\times7.3\times4.1952 \\ \\ V=171.5m^3 \end{gathered}[/tex]Therefore, the volume of the water in the tank is 171.5 cubic meters.
Now, let'c convert from cubic meters to gallons.
Where:
1 foot = 0.3048 m
[tex]1meter=\frac{1}{0.3048}=3.28\text{ feet}[/tex]Thus, we have:
[tex]\begin{gathered} 1\text{ cubic meter = 3.28}^3=35.29\text{ cubic f}eet \\ \\ 171.5\text{ cubic meters = 171.5 x 35.29 = }6052.235\text{ cubic fe}et \end{gathered}[/tex]Now, to convert from cubic feet to gallons, where:
1 cubci foot = 7.48 gallon
We have:
[tex]6052.235\times7.48=45273.86\text{ gallons}[/tex]Therefore, there are 45273.86 gallons of water filled in the tank.
you pick a marble and flip a coin how many outcomes are possible
Solution
A coin has two possible outcome
We have 5 marbles
[tex]2\times5=10[/tex]The final answer
[tex]10[/tex]Solve the system [tex]\left \{ {{5x1 + 5x2 = 5} \atop {2x1 + 3x2 = 4}} \right.[/tex]
The solution for the given system of equations is x[1] = -1 and x[2] = 2.
What is system of equations?A system of linear equations (or linear system) is a collection of one or more linear equations involving the same variables.
Given are the following equations as -
5 x[1] + 5 x[2] = 5
2 x[1] + 3 x[2] = 4
Assume that -
x[1] = a
x[2] = b
Then, we can write the equations as -
5a + 5b = 5
2a + 3b = 4
Now -
5a + 5b = 5
5(a + b) = 5
a + b = 1
a = 1 - b
So, we can write -
2a + 3b = 4
as
2(1 - b) + 3b =4
2 - 2b + 3b = 4
b = 4 - 2
b = 2 = x[2]
Then
a = 1 - 2
a = -1 = x[1]
Therefore, the solution for the given system of equations is x[1] = -1 and x[2] = 2.
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A baseball team has home games on Wednesday and Saturday. The two games together earn $4920.00 for the team. Wednesday's game generates $880.00 less than Saturday's game. How much money did Wednesday's game generate?
Wednesday's game generated $2020
Explanations:Let the amount generated by Wednesday's game be x
Let the amount generated by Saturday's game be y
The two games together earn $4920 for the team. That is,
x + y = 4920....................(1)
Wednesday's game generates $880 less than Saturday's game
x = y - 880.................(2)
Make y the subject of the formula in equation (2)
y = x + 880..................(3)
Substitute equation (3) into equation (2)
x + x + 880 = 4920
x + x = 4920 - 880
2x = 4040
Divide both sides by 2
2x/2 = 4040/2
x = 2020
Wednesday's game generated $2020
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If angle a measures 42 degrees, then what other angles would be congruent to angle a and also measure 42 degrees?
If angle "a" measures 42° the the other angles that will be congruent to angle "a" and also measure 42° will be angle d, angle e and angle h .
In the question ,
a figure is given ,
From the figure we can see that 2 parallel lines are cut by a transversal .
So ,
angle a = angle d .......because vertically opposite angles .
angle a = angle e ...because corresponding angles are equal in measure
also
angle e = angle h .... because vertically opposite angles .
Therefore , If angle "a" measures 42° the the other angles that will be congruent to angle "a" and also measure 42° will be angle d, angle e and angle h , the correct option is (a) .
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7Lines a and bare parallel cut by transversal line t solve for the value of x25x + 4a3x + 14
These angles measure the same they are interior alternate angles.
3x + 14 = 5x + 4
Solve for x
3x - 5x = 4 - 14
Simplify like terms
-2x = -10
x = -10/-2
Result
x = 5
John took 30 minutes to bicycle to his grandmother’s house, a total of 2.5 kilometers. What was his speed in km/hr?
Answer:
5(km)/1(hr)
Step-by-step explanation:
You multiply the 30 minutes to make one hour, and with that, you also multiply the 2.5 kilometers to get 5. You multiply the 2.5 because we multiply both sides of an equation.
Uniform line movement.
We have that the data is:
Time (t) = 30 m = 0.5 h
Distance (d)= 2.5 km
Speed (v) = ?
Since it asks us for the speed in Km/h, we make a time conversion, from minutes to hours. Knowing that 1 hr = 60 minutes, then
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{30 \not{m}*\left(\frac{1 \ h}{60 \not{m})\right)=0.5 \ h } } \end{gathered}$}}[/tex]
To calculate the speed, divide the distance by the time. We apply the following formula:
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{Speed=\frac{Distance}{Time} } \end{gathered}$}}[/tex]
We substitute our data in the formula and solve:
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V=\frac{d}{t} } \end{gathered}$}}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V=\frac{2.5 \ km}{0.5 \ h} } \end{gathered}$}}[/tex]
[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V=5 \ km/h} \end{gathered}$} }}[/tex]
Juan's speed was: 5 km/h.Use the rules of significant figures to answer the following question:43.5694 * 22.07A. 961.58B. 961C. 961.577D. 961.7
we have that
43.5694 * 22.07=961.576658
therefore
the answer is
961.577 -----> 6 figures
(remember that 43.5694 has 6 figures)
option C
For people over 50 years old, the level of glucose in the blood (following a 12 hour fast) is approximately normally distributed with mean 85 mg/dl and standard deviation 25 mg/dl ("Diagnostic Tests with Nursing Applications", S. Loeb). A test result of less than 40 mg/dl is an indication of severe excess insulin, and medication is usually prescribed.
What is the probability that a randomly-selected person will find an indication of severe excess insulin?
Suppose that a doctor uses the average of two tests taken a week apart (assume the readings are independent). What is the probabiltiy that the person will find an indication of severe excess insulin?
Repeat for 3 tests taken a week apart:
Repeat for 5 tests taken a week apart:
Using the normal distribution and the central limit theorem, it is found that:
There is a 0.0359 = 3.59% probability that a randomly-selected person will find an indication of severe excess insulin.Considering the mean of two tests, there is a 0.0054 = 0.54% probability that the person will find an indication of severe excess insulin.Three tests: 0.0009 = 0.09%.Five tests: 0% probability.Normal Probability DistributionThe z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is given by the following rule:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean, depending if the z-score score is positive or negative.From the z-score table, the p-value associated with the z-score is found, which represents the percentile of the measure X in the distribution of interest.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].The mean and the standard deviation of the glucose levels are given, respectively, by:
[tex]\mu = 85, \sigma = 25[/tex]
The probability of a reading of less than 40 mg/dl(severe excess insulin) is the p-value of Z when X = 40, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (40 - 85)/25
Z = -1.8.
Z = -1.8 has a p-value of 0.0359.
For the mean of two tests, the standard error is:
s = 25/sqrt(2) = 17.68.
Hence, by the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (40 - 85)/17.68
Z = -2.55.
Z = -2.55 has a p-value of 0.0054.
For 3 tests, we have that:
s = 25/sqrt(3) = 14.43.
Z = (40 - 85)/14.43
Z = -3.12.
Z = -3.12 has a p-value of 0.0009.
For 5 tests, we have that:
s = 25/sqrt(5) = 11.18.
Z = (40 - 85)/11.18
Z = -4.03
Z = -4.03 has a p-value of 0.
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Write the equation of a Circle with the given information.End points of a diameter : (11, 2) and (-7,-4)
The form of the equation of the circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where (h, k) are the coordinates of the center
r is the radius
Since the endpoints of the diameter are (11, 2) and (-7, -4), then
The center of the circle is the midpoint of the diameter
[tex]\begin{gathered} M=(\frac{11+(-7)}{2},\frac{2+(-4)}{2}) \\ M=(\frac{4}{2},\frac{-2}{2}) \\ M=(2,-1) \end{gathered}[/tex]The center of the circle is (2, -1), then
h = 2 and k = -1
Now we need to find the length of the radius, then
We will use the rule of the distance between the center (2, -1) and one of the endpoints of the diameter we will take (11, 2)
[tex]\begin{gathered} r=\sqrt[]{(11-2)^2+(2--1)^2} \\ r=\sqrt[]{9^2+3}^2 \\ r=\sqrt[]{81+9} \\ r=\sqrt[]{90} \\ r^2=90 \end{gathered}[/tex]Now substitute them in the rule above
[tex]undefined[/tex]The sum of the squares of three consecutive odd numbers is 83. Find the numbers.
In order to represent three consecutive odd numbers, we can use the expressions "x", "x+2" and "x+4".
If we add the square of each number, the result is 83, so we can write the following inequality:
[tex]\begin{gathered} x^2+(x+2)^2+(x+4)^2=83\\ \\ x^2+x^2+4x+4+x^2+8x+16=83\\ \\ 3x^2+12x+20=83\\ \\ 3x^2+12-63=0\\ \\ x^2+4x-21=0 \end{gathered}[/tex]Let's solve this quadratic equation using the quadratic formula, with a = 1, b = 4 and c = -21:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4a}c}{2a}\\ \\ x=\frac{-4\pm\sqrt{16+84}}{2}\\ \\ x=\frac{-4\pm10}{2}\\ \\ x_1=\frac{-4+10}{2}=\frac{6}{2}=3\\ \\ x_2=\frac{-4-10}{2}=\frac{-14}{2}=-7 \end{gathered}[/tex]If we assume the numbers are positive, the numbers are 3, 5 and 7.
(The other result, with negative numbers, would be -7, -5 and -3).
Andre was trying to write 7^4/7^-3 with a single exponent and write 7^4/7^-3= 7^4-3=7^1 Exploit to Andre what his mistake was and what the answer should be...PLEASE THE ANSWER IS URGENT!!
Here, we want to get what Andre's mistake was and correct it
To answer this, we are supposed to use the division law of indices
We have this as;
[tex]\frac{a^x}{a^y\text{ }}=a^{x-y}[/tex]Now, in the case of this question, x is 4 and y is -3
So, we have the expression as;
[tex]7^{4-(-3)}=7^{4+3}=7^7[/tex]His mistake is thus adding the exponents instead of subtracting
Solve for a.5a== ✓ [?]2aPythagorean Theorem: a2 + b2 = c2=
ANSWER
a = √21
EXPLANATION
This is a right triangle, so we have to apply the Pythagorean Theorem to find the value of a.
We know the length of the hypotenuse which is 5, and the length of one of the legs, which is 2. The Pythagorean Theorem for this problem is,
[tex]a^2+2^2=5^2[/tex]Subtract 2² from both sides,
[tex]\begin{gathered} a^2+2^2-2^2=5^2-2^2 \\ a^2=25-4 \end{gathered}[/tex]And take the square root to both sides,
[tex]\begin{gathered} \sqrt[]{a^2}=\sqrt[]{25-4} \\ a=\sqrt[]{21} \end{gathered}[/tex]Hence, the value of a is √21.
A local video game store sells used games and new games. A new game costs$64, including tax. A used game costs $43, including tax. Luis bought 3 more used games than new games. Luis spent $343. How many used games did Luis purchase?
Given:
new game cost - $ 64
used game cost - $ 43
Luis spent $ 343
Required:
Number of used games Luis purchased
Solution
Let: x be the number of new games Luis bought
x + 3 be the number of used games Luis bought
Total cost = $ 343
Total Cost = (No. of new games bought)(Cost of new games) + (No. of used games bought)(Cost of used games)
$ 343 = ( x ) ( $ 64 ) + ( x + 3 ) ( $ 43 )
343 = 64x + 43 ( x + 3 )
343 = 64x + 43x + 129
343 - 129 = 107x
214 = 107x
2 = x
x = 2
x be the number of new games Luis bought 2
x + 3 be the number of used games Luis bought 2 + 3 = 5
Answer:
Luis purchased 5 used games
To check:
Substitute x into the equation,
343 = x ( 64 ) + (x + 3 ) (43)
343 = 2 ( 64 ) + (2 + 3)(43)
343 = 2 (64) + (5) (43)
343 = 128 + 215
343 = 343
The computed value of x satisfies the equation, Our answer is correct.
Solve-2x-16=2x-20.
Ox=1
O no solutions
○ * = −1
all real numbers