The temperature T₂, in Celsius, that is needed to reach the pressure of 7350 torr is 2517 °C
How do I determine the temperature T₂?From the question given above, the following data were obtained:
Initial pressure (P₁) = 735 torr Initial temperature (T₁) = 6 °C = 6 + 273 = 279 KVolume = ConstantNew pressure (P₂) = 7350 torrNew temperature (T₂) =?Since the volume isconstant, we can determine the new temperature, T₂ as illustrated below:
P₁ / T₁ = P₂ / T₂
735 / 279 = 7350 / T₂
Cross multiply
735 × T₂ = 279 × 7350
Divide both side by 735
T₂ = (279 × 7350) / 735
T₂ = 2790 K
Subtract 273 to obtain answer in °C
T₂ = 2790 – 273 K
T₂ = 2517 °C
Thus, the temperature T₂ is 2517 °C
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pretend you are a journalist assigned to write about an atom from the prestigious periodic table.
The answer to the task from above about the an atom of element periodic table is given below:
The chlorine atom is one of the halogens in the periodic table.
Why the chlorine atom is an halogen of prestigious periodic tableRight from time immemorial, the indepth knowledge and understanding of how atoms are arranged in the periodic table and react with with each speaks volume of the identities of the properties of elements.
Chlorine is regarded as an halogen simply because they are salt formers when it atoms react with alkali metals.
So therefore, it can be deduced that the periodic table is the heart of chemistry.
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If I take my break at 3:48 and break our 30 mins what time is my break over
Answer:
Your break would end at 4:18
Explanation:
A light emitting diode will emit light when
A) A hole jumps to the conduction band.
B) A hole jumps to the valence band.
C) An electron hops between orbitals in the conduction band.
D) An electron gives up energy when it falls into the valence band to fill a hole.
The answer is D. When an electron falls into the valence band to fill a hole, it gives up energy in the form of light.
The diode in an LED bulb is a semiconductor device that allows electricity to flow in one direction only. It is made of two pieces of semiconductor material, one positive and one negative, that are joined together.
The diode in the process of electrolysis has two terminals, called the anode and the cathode. The anode is the positive terminal and the cathode is the negative terminal in the electrolysis. The anode is connected to the positive terminal of the power supply and the cathode is connected to the negative terminal of the power supply.
When the power is turned on, the diode allows electricity to flow from the anode to the cathode and lights up the LED bulb.
The light-emitting diode will emit light when an electron jumps from the conduction band to the valence band. This is because when the electron falls into the valence band, it will release energy in the form of light.
Therefore the correct option is d.
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Complete the following table
(H3O+) 2.0x10^-6 (OH-) ?
The value of hydroxide ion concentration, [OH⁻] in the table, given that [H₃O⁺] is 2.0×10⁻⁶ M, is 5.0×10⁻⁹ M
How do I determine the value of [OH⁻]?From the defininion of pH, we understood that the relationship between hydronium ion, H₃O⁺ and hydroxide ion, OH⁻ in a solution is given as:
[H₃O⁺] × [OH⁻] = 10¯¹⁴
With the above formula, we can determine the value of the hydroxide ion, OH⁻. Details below:
Hydronium ion concentration [H₃O⁺] = 2.0×10⁻⁶ MHydroxide ion concentration [OH⁻] =?[H₃O⁺] × [OH⁻] = 10¯¹⁴
2.0×10⁻⁶ × [OH⁻] = 10¯¹⁴
Divide both side by 2.0×10⁻⁶
[OH⁻] = 10¯¹⁴ / 2.0×10⁻⁶
[OH⁻] = 5.0×10⁻⁹ M
Thus, we can conclude that the hydroxide ion concentration, [OH⁻] is 5.0×10⁻⁹ M
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When sodium metal is placed in a flask full of chlorine gas, a violent reaction occurs. These dangerous non-charged elements, when mixed, produce the ionic compound sodium chloride, otherwise known as table salt. Explain how this happens in terms of nuclei, electrons, and charges.
In the formation of the sodium chloride, there is the loss of one electron from the sodium atom to the chlorine atom.
What is an ionic bond?An ionic bond is the kind of bond that is formed between a metal and a non metal. The metal is known to donate electrons to the non metal. In the actual sense, the compound that is formed is an ion pair because the metal is positively charged while the non metal is negatively charged.
In the case of the sodium chloride, we know that the both elements, sodium and chlorine are highly reactive. Hence the sodium atom would quickly loose electrons to the chlorine atom and then the sodium chloride compound is formed.
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A 0.7256 g mixture of KCN ( MW=65.116 g/mol ) and NaCN ( MW=49.005 g/mol ) was dissolved in water. AgNO3 was added to the solution, precipitating all of the CN− in solution as AgCN ( MW=133.886 g/mol ). The dried precipitate weighed 2.5874 g. Calculate the weight percent of KCN and NaCN in the original sample.
The weight percent of KCN and NaCN in the original sample are;
weight percent of KCN = 57%weight percent of NaCN = 43%What is the weight percent of KCN and NaCN in the original sample?The weight percent of KCN and NaCN in the original sample is calculated as follows:
The mass of the original mixture of KCN and NaCN = 0.7256 g
The dissociation equation of the ionic compounds in an aqueous solution is given below:
KCN ⇄ K⁺ + CN⁻
NaCN ⇄ Na⁺ + CN⁻
Mass of precipitate of AgCN = 2.5874 g
Moles of AgCN in a 2.5874 g sample = mass / molar mass
molar mass of AgCN = 133.886 g/mol
Moles of AgCN in the sample = 2.5874 / 133.886
Moles of AgCN in the sample = 0.01932 moles
Moles of CN⁻ in the sample = 0.01932 moles
Mass of CN⁻ present in the sample = 0.01932 * 26
Mass of CN⁻ present in the sample = 0.50232 g
Moles of Na⁺ present = 0.01932 / 2 moles
Moles of Na⁺ present = 0.009663 moles
Mass of Na⁺ present = 0.00966 * 23
Mass of Na⁺ present = 0.2222 g
Moles of K⁺ present = 0.01932 / 2 moles
Moles of K⁺ present = 0.00966 moles
Mass of K⁺ present = 0.009663 * 39
Mass of K⁺ present = 0.3768 g
Mass of sample = 0.50232 g + 0.2222 g + 0.3768 g
Mass of sample = 1.10132 g
weight percent of KCN = (0.3768 + 0.50232/2)/1.10132 * 100%
weight percent of KCN = 57%
weight percent of NaCN = (100 - 57)%
weight percent of NaCN = 43%
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The decomposition of KClO3 is generally used to prepare small amounts of O2 in the
laboratory. How many grams of O2 can be prepared from 8.50 g of KClO3?
The number of grams of oxygen that can be prepared from 8.50g of pottasium chlorate is 3.33grams.
How to calculate mass?Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).
According to this question, the decomposition of KClO₃ is generally used to prepare small amounts of O₂ in the laboratory.
2KClO₃ → 2KCl + 3O₂
Based on the above equation, 3 moles of oxygen is produced by the decomposition of 2 moles of pottasium chlorate.
8.50grams of KClO₃ is calculated in moles as follows: 8.50g ÷ 122.55 g/mol = 0.069mol of KClO₃.
This means that 0.069 × 1.5 = 0.104 moles of oxygen is produced.
mass of oxygen produced = 0.104 × 32 = 3.33grams.
Therefore, 3.33grams is the mass of oxygen formed.
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It takes a sample of CO₂ 23.3 seconds escape from a container. How long will it
take the same volume of NO₂(g) to escape from the same container?
Please show how to solve!!
It takes a sample of CO₂ 23.3 seconds escape from a container. it will take the same volume of NO₂(g) to escape from the same container is 23.4 sec.
The effusion rate gas is inversely proportional to the square root of molecular mass.
Rate ∝ √1/M
for the same volume of gases,
t1 / t2 = √ M1 / M2
molar mass of CO₂ = 44 g/mol
molar mas of NO₂ = 46 g/mol
23.3 / t2 = √ 44 / 46
23.3 / t2 = 6.6 / 6.7
23.3 / t2 = 0.9
t2 = 23.4 sec
Thus, It takes a sample of CO₂ 23.3 seconds escape from a container. it will take the same volume of NO₂(g) to escape from the same container is 23.4 sec.
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4.00g of iron was was heated from 25.0°C to 75.0°C. How much energy was used to heat the iron
The energy used to heat the iron from 25°C to 75°C will be 88J
Given,
m= 4 g
c, i.e, specific heat of Iron is 0.44 J°C⁻¹g⁻¹
The heat energy is given by formula,
q=mcΔT
where q is the amount of heat and m is the substance's mass.
T represents the temperature change, and c is the material's specific heat capacity. The addition of heat affects various substances in varying degrees. Different materials' temperatures rise by different amounts when a given amount of heat is applied to them.
q =4× 0.44× ΔT
ΔT= T₂₋ T₁
ΔT= 75- 25
= 50°C
q= 4×0.44×50
=88 J
So, the energy used to heat the iron will be 88J.
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Consider a weak base equilibrium as shown in the equation below. What is the effect on Kb if BH⁺ were added to the solution?
B (aq) + H2O (l) ⇌ BH⁺ (aq) + OH⁻ (aq)
A weak base equilibrium as shown in the equation below. the effect on Kb if BH⁺ were added to the solution; the equilibrium constants is remains unchanged.
The equation is given as :
B (aq) + H2O (l) ⇌ BH⁺ (aq) + OH⁻ (aq)
K = [ BH⁺ ] [ OH⁻] / [B]
the equilibrium constant for the given reaction is remain unchanged. the equilibrium constant will only depends on the temperature of the reaction.
Thus, A weak base equilibrium as shown in the equation below. the effect on Kb if BH⁺ were added to the solution; the equilibrium constants is remains unchanged.
B (aq) + H2O (l) ⇌ BH⁺ (aq) + OH⁻ (aq)
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this bohr model is showing what element
The image shows the Bohr model of the chlorine atom.
What is the Bohr model?We know that the Bohr model has to do with the model in which the electrons that are in the atoms are arranged in a definite order. The implication of this is that the electrons would be arranged in a certain specific energy level such that an electron can be moved from a lower to a higher energy level as we can see from the image that has been shown in the question that has been asked.
Having said that we have seventeen protons in the atom and the implication is that there are also seventeen electrons in the atom and this is going to correspond to the element chlorine atom which can be shown to be a member of the group seventeen of the periodic table of the elements.
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Calculate the final concentration of a solution created through the following process: 1.7 L of a 2.4 M NaF solution is diluted with water to 3.3 L of NaF solution.
The final concentration of the diluted solution of NaF is equal to 1.24 M.
What is the dilution law?The concentration and the volume of the stock solution or dilute solution can be determined from the following equation:
M₁V₁ = M₂ V₂
where M₁ and V₁ are the concentration and volume of the stock or concentrated solution respectively and M₂ and V₂ are the concentration and volume of the diluted solution.
Given, a stock solution of NaF of concentration, M₁ = 2.4 M
The concentration of the diluted solution of NaF is M₂.
The volume of the concentrated solution of NaF, V₁ = 1.7 L
The volume of diluted solution of NaF, V₂ = 3.3 L
Substitute the value of the concentration and volume of NaF in equation (1):
(2.4)× (1.7) = M₂ × (3.3)
M₂ = 1.24 M
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How many oxygen atoms are
present in one mole of
dinitrogen pentoxide?
N2O5
1.20 x 10^24
3.01 x 10^24
4.21 x 10^24
6.02 x 10^23
There are 5 oxygen atoms in one nitrogen pentoxide. The number of oxygen atoms in one mole of nitrogen pentoxide is 3.01 × 10²⁴.
What is one mole?Any substance containing 6.022 × 10²³ atoms is called one mole of the substance. This number is called Avogadro number. Hence, one mole of every element contains Avogadro number of its atoms.
One mole oxygen contains 6.022 × 10²³ oxygen atoms. Similarly one mole of a compound contains 6.022 × 10²³ number of its constituent molecules.
Now, the number of oxygen atoms in one mole of N₂O₅ will be 6.022 × 10²³ × 5 = 3.01 × 10²⁴. Therefore, option b is correct.
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Mole measure the number of elementary entities of a given substance that are present in a given sample. 6.02 x 10²³ oxygen atoms are
present in one mole of dinitrogen pentoxide N[tex]_2[/tex]O[tex]_5[/tex]. The correct option is option 4.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance.
One mole of any substance contains 6.02 x 10²³ number of atoms. 6.02 x 10²³ is called Avogadro number. Mole is inversely proportional to Avogadro number.
Therefore, 6.02 x 10²³ oxygen atoms are present in one mole of dinitrogen pentoxide. The correct option is option 4.
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It is popularly known that C1V1=C2V2 can be useful during reagent/solution preparation. Given that 8ml of 5.2m NaCL would be needed to prepared 0.231m NaCL . How would the formula above be used to determined the volume of flask for the preparation?
The volume of the flask for the preparation of 0.231M solution can be 200ml flask. The equation C1V1 = C2V2 is used for the dilution of the samples.
What is dilution?
Dilution is a process in which a solution is made less concentrated by adding some other constituent to it. To dilute a solution more solvent should be added than the solute. The number of ions of solute remains the same but the volume is increased so the concentration decreases.
For the dilution using,
C1V1 = C2V2
5.2M x 8ml = 0.231M x V2
V2 = 5.2M x 8ml / 0.231M
V2 = 180.08ml.
Therefore, 180.08ml of new solution is made through dilution for which me need 200ml flask or higher volume flasks.
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When 2 moles of H₂S(g) react with
O₂(g) to form H₂O(g) and SO₂(g)
according to the following equation,
1.04×10³ kJ of energy are evolved.
2H₂S(g) + 30₂(g)→→→→→→
2H₂O(g) + 2SO₂(g)
Is this reaction endothermic or
exothermic?
What is the value of q?
kJ
The reaction is exothermic in nature and the value of q in kJ is -1.12x10^3 kJ
The reaction is 2H₂S(g) + 3O₂(g)→→→→→→2H₂O(g) + 2SO₂(g)
The amount of heat evolved in the reaction = 1.12 X 103 KJ
2 moles of hydrogen sulphide react.
In an is In an endothermic reaction, energy is consumed. an exothermic reaction, energy evolved Thus, the given reaction is exothermic.
Exothermic reactions are those reactions in which the energy is evolved or released by the reaction.
And endothermic reactions are those reactions in which heat or energy is absorbed in the reaction.
Since the reaction is evolving energy.
Hence the reaction is an exothermic reaction.
The value of q is defined as the amount of heat transferred to the system.
Since the heat is going away from the system.
Hence the value of q will be -ve.
And the magnitude of q will be exactly the same as the amount of heat evolved by the reaction.
Hence q = -1.12 X 103 KJ (-ve sign shows that heat is being evolved i.e exothermic process)
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which of the following environmental effects is influenced by magnetic field strength
1. What is the new volume of a gas if 50 mL at 81.0 kPa has its pressure increased to 101.3 kPa? (Temperature is constant)
The new volume of a gas 40ml, if 50 mL at 81.0 kPa has its pressure increased to 101.3 kPa.
What is Boyle's Law?
Boyle's law is a gas law that states that the pressure exerted by a gas (with a given mass and constant temperature) is inversely proportional to its volume. In other words, as long as the temperature and amount of gas remain constant, the pressure and volume of a gas are inversely proportional to each other. Boyle's law was proposed in 1662 by the Anglo-Irish chemist Robert Boyle.
Any change in the volume occupied by a gas (at constant quantity and temperature) results in a change in the pressure exerted by it, according to Boyle's law.
In other words, the product of a gas's beginning pressure and volume is equal to the product of its end pressure and volume (at constant temperature and number of moles).
P1V1 = P2V2
Where,
P1 denotes the gas's initial pressure.
V1 denotes the gas's initial volume.
P2 denotes the gas's final pressure.
V2 denotes the gas's final volume.
The pressure-volume relationship provided by Boyle's law can be used to get this phrase. PV = k for a fixed amount of gas kept at a constant temperature. Therefore,
P1V1 = k (starting pressure * starting volume)
P2V2 = k (last pressure * last volume)
∴ P1V1 = P2V2
According to Boyle's Law
p1v1=p2v2
81x50= 101.3xv2
v2 = 140ml
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A maggot is another name for—-
another name for a maggot is a worm
6 The pressure of 8.06 L of an ideal gas in a flexible container is decreased to
one-third of its original pressure, and its absolute temperature is decreased by
one-half. What is the final volume of the gas?
The pressure of 8.06 L of an ideal gas in a flexible container is decreased to one-third of its original pressure, and its absolute temperature is decreased by one-half and the final volume of gas is 12.09 L
The volume of gas in a flexible container is 8.06 L
The pressure is P1=X atm
Temperature is T1=YK
Let us calculate the volume V2 if Pressure P2=X/3 atm
Temperature T2=Y/2 K
Using the ideal gas equation, we get
P1V1/T1=P2V2/T2
V2=V1P1T2/T1P2
V2=8.06LX atm×Y/2K/YK.X/3 atm
V2=8.06x3/2
V2=12.09 L
The combined gas law is an amalgamation of the three previously known laws which are- Boyle's law PV = K, Charles's law V/T = K, and Gay-Lussac's law P/T = K.Applications of the combined gas law exist. This rule is applicable when the pressure, volume, and temperature are constant but the quantity of gas varies. The law can predict things like cloud formation, refrigerators, and air conditioners, for instance.To learn more about combined gas law visit:
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1. Target I1
Which list of elements all have the same number of valence electrons?
a. F, CI, O, N
b. Cr, Mn, Fe, Co
C. Ne, Ar, Kr, Xe
d. Na, Mg, Al, Si
Answer:
A
B that is Cr,MN,Fe,Co. is the correct answer
C
D
Calculate the molarity of 23.5 g of NaOH in 400. mL of an NaOH solution.
Answer:
1.468 M
Explanation:
What is the mass of 6.02 x 10^^24
molecules of hydrogen, H2? The molar
mass of H2 is 2.02 g/mol.
A- 2.02 g H2
B- 2.98 x 10^24 g H2
C- 10.0 g H2
D- 1.22 x 10^25 g H2
Mole measures the number of elementary entities of a given substance that are present in a given sample. The mass of hydrogen is 20.2gram.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance.
Given number of atoms= 6.02 x 10²⁴atoms
we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number
mole =given number of atoms ÷ 6.022×10²³(Avogadro number)
Substituting the values
mole=6.02 x 10²⁴÷ 6.022×10²³
mole = 10 mole
Mole = mass ÷Molar mass
Molar mass = 2.02 g/mol
Substituting the given values
10= mass ÷ 2.02 g/mol
Mass = 20.2gram
Therefore, mass of hydrogen is 20.2gram.
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A digital signal transmits energy in the form of waves. These waves can travel at the speed of light. Only digital information can be read and scratches or other imperfection are not read. Which conclusion would be best based on this information? Responses ADigital transmission of information is not likely to be replace other methods. Digital transmission of information is not likely to be replace other methods. BDigital transmission of information is the least expensive method. Digital transmission of information is the least expensive method. CDigital transmission of information is a fast and reliable method. Digital transmission of information is a fast and reliable method. DDigital transmission of information can easily be converted to analog.
Since the A digital signal transmits energy in the form of waves, the conclusion that would be best based on this information is option C: Digital transmission of information is a fast and reliable method.
All electromagnetic waves constitute digital signals?Signals, both digital and analog, are transferred via electromagnetic waves. The sound you hear or the graphics you see on a screen are the result of changes in frequency and amplitude. The continuous waves that make up analog signals can be of any frequency and amplitude.
Note that Data transfer, also known as digital transfer or digital communication, is the movement of data between two locations. Digital messages from a data source, such as a computer or keyboard, may be the source of the transmitted data. A phone call or a video signal are examples of analog signals that could also be present.
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please help!
For the reaction:
2H2 (g) + O2 (g) —-> 2H2O (l)
calculate the change S of system and the change of S of surroundings
+571.6 KJ and 1803.03 J/K are the entropy (S) of system and the change of S of surrounding.
2H2O(l) --->2H2(g) + O2(g)
first step is to get dHrxn = dHf(Products) - dHf(reactants)
take dHf of reactants and products from standard thermodynamic table
dHf(H2O) = -285.8 KJ/mol
dHf(H2) =0 kj/mol
dHf(O2)= 0 kj/mol
dHrxn = 2dHf(H2) + dHf(O2) - 2dHf(H2O)
= 2*0 + 0 - 2 [-285.8] kj = +571.6 KJ
this is for 2 mole of H2O
for 1.88 mols H2O, dHrxn = +571.6 KJ/2mol×1.88 mol = 537.304 kj
T =298 K
dS surrounding = - dHrxn/T = -537304 j/298 K = -1803.03 J/K
Entropy is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive labor. Entropy is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.
In an isolated system—one that does not exchange heat or work with its surroundings—spontaneous change for an irreversible process always moves in the direction of rising entropy, according to the Clausius form of the second law. For instance, the ice block and the stove are two components of a standalone system for which the overall entropy rises as the ice melts.
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What is the photon energy of a wave with a frequency of 6.7 x 1014 Hz?
Answer:
4.4 x 10⁻¹⁹ J
Explanation:
To find the energy of the photon, you need to use the following equation:
E = hf
In this equation,
-----> E = energy (J)
-----> h = Planck's Constant (6.626 x 10⁻³⁴ J·s)
-----> f = frequency (Hz)
You can plug the given value and constant into the equation and solve for "E". The final answer should have 2 sig figs like the given value (6.7 x 10¹⁴ = 2 sig figs).
E = hf <----- Given equation
E = (6.626 x 10⁻³⁴ J·s)(6.7 x 10¹⁴ Hz) <----- Insert values
E = 4.4 x 10⁻¹⁹ J <----- Multiply
.The isothermal compressibility of lead at 293 K
The pressure that must be applied to increase the dentisy by 0.10% is 453.48 atm.
What is isothermal compressibility?It's important to note that isothermal compressibility simply means the fractional differential change that can be seen in the volume as a result if the change in pressure.
It should be noted that the isothermal compressibility formula will be:
= 1/v (dv/dp)
where v = volume
p = pressure
dv = 0.10% = 0.001
This will be:
2.21 × 10^(-6) = 0.001/dp
dp = 0.001 / 2.21 × 10^(-6)
dp = 452.48 atm
New pressure = 1 atm + 452.48 atm
= 453.48 atm
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Complete question
The isothermal compressibility of lead at 293 K. Calculate the pressure that must be applied to increase the dentisy by 0.10%.
Morphine is used medicinally as a pain reliever. If an aqueous solution of morphine has [H3O+] = 1.1 x 10-10 M, what is the pH of this solution?
Morphine is used medicinally as a pain reliever. If an aqueous solution of morphine has [H3O⁺] = 1.1 x 10-10 M, the pH of this solution is 9.6.
given that :
[H3O⁺] = 1.1 x 10-10 M
the pH of the solution is given as :
pH = - log ( [H3O⁺] )
pH = - log ( 1.1 x 10-10 M )
pH = - (-9.6 )
pH = 9.6
the pH of the given solution is 9.6.
Thus, Morphine is used medicinally as a pain reliever. If an aqueous solution of morphine has [H3O+] = 1.1 x 10-10 M, the pH of this solution is 9.6.
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There are 4.9875 mol C, 7.9802 mol H,
and 2.00 mol O in the sample.
Divide each by the smallest number of
moles. What is the ratio for the C?
Do not round your answer
2.48925 C : ? H : ? O
The ratio of the carbon to the rest of the atoms in the compound would be 2.49375 to 3.9901 of hydrogen, and 1.00 of oxygen.
The ratio of atoms in a compoundThe ratio of an atom to the rest of the atoms in a compound can be determined by knowing the empirical or molecular formula of the compound.
Now, the compound in question contains C, H, and O.
Amount of C = 4.9875 molAmount of H = 7.9802 molAmount of O = 2.00 molLet's divide the mol f each atom by the mol of the smallest. the smallest in this case is 2.00 moles.
C = 4.9875/2.00 = 2.49375
H = 7.9802/2.00 = 3.9901
O = 2.00/2.00 = 1.00
Thus, the ratio for carbon is 2.49375 to 3.9901 of hydrogen, and 1.00 of oxygen.
The empirical formula of the compound is [tex]C_2H_4 O[/tex].
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The ratio of C if 4.9875 mol C, 7.9802 mol H, and 2.00 mol O are present in the sample is 2.5.
How to calculate empirical ratio?Empirical formula is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.
The empirical ratio to derive the empirical formula can be calculated by dividing the number of moles of each element by the smallest value.
According to this question, there are 4.9875 mol C, 7.9802 mol H, and 2.00 mol O in the sample. The smallest mole is 2 moles.
C = 4.9875mol ÷ 2 = 2.4938H = 7.9802 mol ÷ 2 = 3.9901O = 2 mol ÷ 2 = 1Therefore, the empirical ratio of carbon in the compound is 2.5.
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If you have 257.4 mL of a 0.7280 M potassium carbonate solution and you need 500.0 mL of a 0.2250 M potassium carbonate solution, how much concentrated solution?
The amount of the concentrated solution and water needed would be 154.5 mL and 345.5 mL respectively.
Dilution problemThe problem here can be solved using the simple dilution equation that is expressed as:
[tex]m_1v_1[/tex] = [tex]m_2v_2[/tex]
Where [tex]m_1[/tex] is the molarity of the undiluted solution, [tex]v_1[/tex] is the volume of the underlined solution needed, [tex]m_2[/tex] is the molarity of the solution to be prepared, and [tex]v_2[/tex] is the volume of the solution to be prepared.
In this case:
[tex]m_1[/tex] = 0.7280 M
[tex]v_1[/tex] = ?
[tex]m_2[/tex] = 0.2250
[tex]v_2[/tex] = 500.0 mL
Rearranging the equation to make [tex]v_1[/tex] the subject:
[tex]v_1[/tex] = [tex]m_2v_2/m_1[/tex]
Now, let's substitute the values:
[tex]v_1[/tex] = 0.2250 x 500.0/0.7280
= 154.5 mL
This means the volume of the concentrated solution needed is 154.5 mL out of 257.4 mL available. Since our final volume is 500.0 mL, the 154.5 mL stock solution will be made up to 500 mL with water.
Thus, the amount of water required would be:
500.0 - 154.5
= 345.5 mL
In other words, the volume of the concentrated solution needed is 154.5 while the volume of water needed is 345.5 mL.
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The complete question: If you have 257.4 mL of a 0.7280 M potassium carbonate solution and you need 500.0 mL of a 0.2250 M potassium carbonate solution, how much concentrated solution and how much distilled water do you need?
A gas evolved during a chemical reaction and has a volume of 651 mL at 38 °C and 869 torr. What was the volume of this gas in mL at 110 °C and 3.87 atmospheres?
Just put in the number. The assumption is the unit is mL.
1 atm = 760 torr = 760 mmHg = 101,325 pa = 101.325 kpa = 1.01325 barr = 14.696
p.s.i. = 29.921 inHg
(inHg and p.s.i. are approximations of the metric pressures and are subject to significant figures)
A gas evolved during a chemical reaction and has a volume of 651 mL at 38 °C and 869 torr. the volume of this gas in mL at 110 °C and 3.87 atmospheres was 238 mL.
given that :
volume V1 = 651 mL
temperature T1 = 38 °C = 38 + 273 = 311 K
pressure P1 = 869 torr = 1.14 atm
pressure P2 = 3.87 atm
temperature T2 = 110 °C = 110 + 273 = 383 K
volume V2 ?
using ideal gas equation , we get :
P1 V1 / T1 = P2 V2 / T2
(1.14 × 651 ) / 311 = (3.87 × V2 ) / 383
2.38 = 0.010 V2
V2 = 238 mL
Thus, A gas evolved during a chemical reaction and has a volume of 651 mL at 38 °C and 869 torr. the volume of this gas in mL at 110 °C and 3.87 atmospheres was 238 mL.
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