According to the given data The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol.
What is enthalpy ?Enthalpy is a characteristic or state function which resembles energy; it has the same dimensions as energy and is thus measured in joules or ergs. The value of enthalpy is entirely determined by the temperature, pressure, and content of the system, not on the history.
Briefing:Calculate the change in enthalpy for the reaction
CH₄(g) + NH₃(g) → HCN(g) +3H₂(g)
From the given reactions
Reaction 1: N₂(g) + 3H₂(g) → 2NH₃(g) Change in enthalpy: -91.8 kJ/mol
Reaction 2: C(s, graphite) + 2H₂(g) → CH₄(g) Change in enthalpy: -74.9 kJ/mol
Reaction 3: H₂(g) +2C(s, graphite) +N₂(g) → 2HCN (g) Change in enthalpy: +270.3 kJ/mol
Reactions 1 and 2 to get reaction 4 and 5 respectively
Reaction 4: 2NH₃(g) → N₂(g) + 3H₂(g) ΔHo : 91.8 kJ/mol
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Now, multiply reactions 4 and 3 by half (1/2) to get 6 and 7 respectively
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN (g) ΔHo : +135.15 kJ/mol
Now,
Add reactions 5, 6, and 7 together
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN(g) ΔHo : +135.15 kJ/mol
----------------------------------------------------------------------------------------------------------
CH₄(g) + NH₃(g) → HCN(g) + 3H₂(g) ΔH rxn = 255.95 kJ/mol
The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol
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Hydrazine, N2H4 , reacts with oxygen to form nitrogen gas and water.
N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)
If 3.35 g of N2H4 reacts with excess oxygen and produces 0.350 L of N2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?
Taking into account definition of percent yield, the percent yield of the reaction if 3.35 g of N₂H₄ reacts with excess oxygen and produces 0.350 L of N₂ is 13.82%.
Reaction stoichiometryIn first place, the balanced reaction is:
N₂H₄ + O₂ → N₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂H₄: 1 moleO₂: 1 moleN₂: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
N₂H₄: 32 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂H₄: 1 mole ×32 g/mole= 32 gramsO₂: 1 mole ×32 g/mole= 32 gramsN₂: 1 mole ×28 g/mole= 28 gramsH₂O: 2 moles ×18 g/mole= 36 gramsIdeal gas lawThe pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield= (actual yield÷ theoretical yield)× 100%
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Actual yield of N₂In this case, you know:
P= 1 atmV= 0.350 LT= 295 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?Replacing in the ideal gas law:
1 atm×0.350 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K
Solving:
n= (1 atm×0.350 L) ÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K)
n= 0.01447 moles
Finally, the actual yield of N₂ is 0.01447 moles.
Theoretical yield of N₂Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 1 mole of N₂, 3.35 grams of N₂H₄ form how many moles of N₂?
moles of N₂= (3.35 grams of N₂H₄× 1 moles of N₂)÷ 32 grams of N₂H₄
moles of N₂= 0.1047 moles
Finally, the theoretical yield of N₂ is 0.1047 moles.
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 0.01447 molestheorical yield= 0.1047 molesReplacing in the definition of percent yield:
percent yield= (actual yield÷ theoretical yield)× 100%
Solving:
percent yield= (0.01447 moles÷ 0.1047 moles)× 100%
percent yield= 13.82%
Finally, the percent yield for the reaction is 13.82%.
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Draw the net force arrow on the diagram and state the direction. Net force direction =
The magnitude of the net force is 20.12 N in a direction 26.56° South of East.
What is the net force and the direction of the force?The net force in the given forces in the diagram s given below as follows:
Force 1, F₁ = 18 N force acting in a direction to the east
Force 2, F₂ = 9 N force acting in a direction south of the object.
The two forces form two sides of a right-angle triangle
Net force is determined using Pythagoras' rule as follows:
Net force, F = √(F₁² + F₂²)
Net force = √ (18² + 9²)
Net force = √ (324 + 81)
Net force = √ 405
Net force = 20.12 N
The direction of the Net force, θ, is determined as follows;
θ = tan⁻¹ (9 / 18)
θ = tan⁻¹ 0.5
θ = 26.56° South of East
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What is the Mass for a statue with a volume of 120cm3 made from ceramic which has a density of 2g/cm3
All matter possesses the fundamental property of inertia, which can be quantified by mass. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the application of a force. A body's ability to resist change from applied forces increases with its bulk.
A three-dimensional space's volume can be calculated. Various imperial units or SI-derived units are routinely used to quantify it numerically. The link between length and volume is reciprocal.
The density of a substance is its mass per unit of volume. Density's sign - ρ, although it can alternatively be represented as the Latin letter D, is most usually written as. Density can be mathematically defined by dividing mass by volume.
Mass = Density * Volume
Mass = 2 * 120
Mass = 240g
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Convert 75 ML to GL
Problems
What is the density of an object with a mass of 250 g and a volume of 300 mL?
The definition of density is the mass of a substance per unit of volume. The Latin letter D may also be used, however the symbol is most usually employed to denote density. Mass divided by volume gives the density value:
D = m/v
= 250/300
= 0.833 g/ml
A physical body's mass is its overall amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured using this phrase. The strength of a body's gravitational pull on other bodies depends on its mass. The kilogram serves as the foundational mass unit in the SI.
The amount of three-dimensional space that is occupied is measured in volume. Imperial or SI-derived units are frequently used in its mathematical expression. The concepts of volume and length are related.
Typically, there are two forms of density: absolute density and relative density. Relative density, also known as specific gravity, is the ratio of a substance's density to the density of a reference material. Water is frequently used as the reference material.
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Pb(C₂H3O2)2 (s) + H₂S (g) --> PbS (s) + HC₂H302 (8)
[unbalanced equation]
Balance this equation, and then calculate how many grams of lead (II) sulfide form when you use 55.11
g of lead (II) acetate and excess (an unlimited amount of) H₂S?
40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .
Given,
balanced chemical equation is ,
Pb(C2H3O2)2 (s) + H2S (g) ⇒ PbS (s) + HC2H3O2 (g)
to making the chemical equation balanced , we have to make sure that all the molecules on the left hand side and in the right hand side should be equal .
thus to making it equal 1st see that the number of carbon , oxygen and hydrogen is doubled in the left side than that of right side .
so we have to multiply HC2H302 by 2 .
Pb(C2H3O2)2 (s) +H2S(g) ⇒ PbS(s) + 2 HC2H3O2 (g)
so now the given chemical equation is balanced that we can say , 1 mol of Pb(C2H3O2)2 produces 1 mol of PbS .
It is given that , we can take H2S is in excess means the Pb(C2H3O2 )2 acts as limiting agent .
We know , molecular mass of Pb(C2H3O2)2 is 325.29g
325.29g contains 1mole
55.11g contains 55.11/325.29 = 0.169 moles
thus ,the mole of PbS formed from 55.11g of Pb(C2H3O2)2 is 0.169moles.
We know ,
molecular mass of PbS is 239.3g
1mole of PbS is 239.3g
0.169moles pf PbS is 239.3×0.169 = 40.4417 g
Hence , 40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .
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x gm of metal (E=12) was completely dissolved in 100 ml of N/2 HCl. The solution was then made upto 500 ml. 2.5 ml of this diluted acid required 12.5 ml of N/10 NaOH for complete neutralization. Find the valency of x.
When a potent acid, like hydrochloric acid, HCl, is combined with a potent base, such sodium hydroxide, NaOH, the result can be complete neutralization. Strong bases and acids dissociate entirely into their individual ions when they dissolve in water.
An element's valency is its capacity for combination. The periodic table groups have identical elements with the same valency.. How many electrons make up the outer shell of an element determines its valency. The group number.
Valency is simply the amount of electrons that an element's atom gains, loses, or shares to obtain the closest configuration to that of a noble gas. The valency of sodium (Na), magnesium (Mg), chlorine (Cl), and other elements, for instance, is 1.
When there are equal moles of strong acid and strong base, the strong acid and strong base completely neutralize one another. An aqueous solution with a pH of 7 is the end product.
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which of the following reactions is balanced and shows complete combustion
The following reactions is balanced and shows complete combustion are
A)2C₅H₁₂ + 11O₂ -----> 10CO + 12H₂O
D) C₅H₁₂ + 8O₂ -----> 5CO₂ + 6H₂O
A) 2C₅H₁₂ + 11O₂ -----> 10CO + 12H₂O
In this reaction,
Reactants products
C 10 10
H 24 24
O 22 22
Reactants and products have same no. of atoms .
therefore this reaction is balanced and shows complete combustion.
B) 2C₅H₁₂ + 11O₂ -----> 12CO + 10H₂O
Reactants Products
C 10 12
H 24 20
O 22 22
this reaction is not balanced.
C) C₅H₁₂ + 8O₂ -----> 6CO₂ + 5H₂O
Reactants Products
C 5 6
H 12 10
O 16 18
This reaction is not balanced,
D) C₅H₁₂ + 8O₂ -----> 5CO₂ + 6H₂O
Reactants Products
C 5 5
H 12 12
O 16 16
Reactants and products have same no. of atoms .
therefore this reaction is balanced and shows complete combustion.
Thus, The following reactions is balanced and shows complete combustion are
A)2C₅H₁₂ + 11O₂ -----> 10CO + 12H₂O
B) C₅H₁₂ + 8O₂ -----> 5CO₂ + 6H₂O
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Answer:
D
Explanation:
I got the answer right
Example 1: A gas is expanded from an initial volume of 20.5 L at 0.92 atm at room temperature (23.0°C) to a
final volume of 340.6L. During this expansion, the gas cools to 12.0°C. What is the new pressure?
The new pressure is .67 atm (atmospheric pressure at sea level)
What is pressure?
The force applied perpendicularly to an object's surface per unit area over which that force is distributed is known as pressure (symbol: p or P). : 445 The pressure relative to the surrounding air is known as gauge pressure, also spelled gauge pressure. Pressure is expressed using a variety of units. Some of these come from dividing a unit of force by a unit of area; the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi), which is equivalent to one newton per square metre (N/m²) in the SI. The atmosphere (atm), which is equal to this pressure, can also be used to describe pressure. The torr is defined as 1/760 of this.
PV = nRT
P₁V₁ = P₁V₁
P₁ = 0.92 atm
V₁ = 20.5 L
T₁ = 23.0°C
P₂ = ?
V₂ = 340.6L
T₂ = 12.0°C
P₂ = (P₁V₁/T₁)(T₂/V₂)
P₂ = .92(20.5/23)(12/340.6)
P₂ = .67 atm
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IF 23 g of FeCl2 reacts with 41g Na3PO4 what is the limiting reactant?
First, we need to figure the reaction out.
Both reactants are ionic compounds, so their reaction is probably a double displacemente reaction.
The Cl has a charge of 1-, so Fe has a charge of 2+. Na has a charge of +1 and PO₄ has a charge of 3-.
To combine Fe²⁺ with PO₄³⁻, we will need 3 Fe²⁺ and 2 PO₄³⁻, so the compound becomes neutral.
Both Na and Cl have single charge, so their combination is simply 1 Na and 1 Cl.
So, the products are Fe₃(PO₄)₂ and NaCl, so the unbalanced reaction is:
[tex]FeCl_2+Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]To balance it, We can start by putting a coefficient of 2 on Na₃PO₄, so we have two PO₄³⁻ anions on both sides:
[tex]FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]Now, we put a coefficient of 3 on FeCl₂ and 6 on NaCl to get the balanced equation:
[tex]3FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+6NaCl[/tex]Now, we first need to calculate the number of moles of each reactant, using their molar masses:
[tex]\begin{gathered} M_{FeCl_2}=1\cdot M_{Fe}+2\cdot M_{Cl}=(1\cdot55.845+2\cdot35.453)g/mol=126.751g/mol \\ M_{Na_3PO_4}=3\cdot M_{Na}+1\cdot M_P+4\cdot M_O=(3\cdot22.98976928+1\cdot30.973762+4\cdot15.9994)g/mol=163.94066984g/mol \end{gathered}[/tex]So:
[tex]\begin{gathered} M_{FeCl_{2}}=\frac{m_{FeCl_2}}{n_{FeCl_{2}}} \\ n_{FeCl_2}=\frac{m_{FeCl_2}}{M_{FeCl_{2}}}=\frac{23g}{126.751g/mol}=0.181458\ldots mol \end{gathered}[/tex][tex]\begin{gathered} M_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{n_{Na_{3}PO_{4}}} \\ n_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{M_{Na_{3}PO_{4}}}=\frac{41g}{163.9406698g/mol}=0.250090\ldots mol \end{gathered}[/tex]Now, if the coefficient of FeCl₂ is 3, for each 3 FeCl₂ that reacts, one reaction occurs, so the number of reactions that will need to occur to consume all its number of moles is that amount over 3:
[tex]n_{\text{reaction}}=\frac{n_{FeCl_2}}{3}=\frac{0.181458\ldots mol}{3}=0.060486\ldots mol[/tex]Similarly, we get the number of reactions that would occur if all Na₃PO₄ reacts by dividing its number of moles by its coefficient, that is 2:
[tex]n_{\text{reaction}}=\frac{n_{Na_3PO_4}}{2}=\frac{0.250090\ldots mol}{2}=0.125045\ldots mol[/tex]This means that the amount we have of FeCl₂ is enough for only about 0.0605 mol of reactions while the amount we have of Na₃PO₄ is enought for about 0.1250 mol of reactions, which is more than the other reactant.
This means that the reactant that limits the amount of reaction that can occur is FeCl₂, so the limiting reactant is FeCl₂.
Question 1
Concentrated HCl(aq) is 37.2% HCI by mass. If the density of the solution is
1.19g/mL, how many grams of HCI is in 1.75 L of concentrated HCI?
438 m g l of HCI is in 1.75 L of concentrated HCI .
What does concentration of acid means?A specific amount of solution's concentration relates to the amount of acid or basic that is present. If there is a lot of acid or base in a little amount of solution, it is said to be concentrated. If there is little acid or base in a given volume of solution, it is said to be diluted. Acidic is defined as having a pH below 7. Once the pH reaches 7, it is referred to as basic. Hydronium concentrations in acidic solutions are high, while hydroxide concentrations are low. Hydroxide concentrations in basic solutions are high, while hydronium concentrations are lower. The stronger an acid is, the lower the pH is for a given concentration in aqueous solution. Acid solutions have a pH that decreases with increasing concentration.
the quotient….
Molality = moles of solute/kilograms of solvent .
Whereas…
Molarity = moles of solute/volume of solution in liters.
It's only an estimate, but 1.18 g/mL x 1000 mL x 0.37 = around 437 g.
Then, mols in that 1 L = grams/molar mass
= approximately 437/36.5
= roughly 12 M, according to a different calculation.
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Calculate the molarity of an acetic acid solution if 38.9 mL of an HC2H3O2 solution is titrated with 26.7 mL of a 0.114 MKOH solution:HC2H3O2(aq)+ KOH(aq)→H2O(l)+ KC2H3O2(aq) Express your answer with the appropriate units.
Explanation
Given:
CH₃COOH(aq) + KOH(aq) → H2O(l)+ KC2H3O2(aq)
Volume of acetic acid = 38.9 mL = 0.0389 L
Voume of KOH = 26.7 mL = 0.0267 L
Molarity of KOH = 0.114 M
Required: The molarity of an acetic.
Solution
Step 1: Find the moles of KOH
n = C x V where n is the moles, C is the concentration and V is the volume
n = 0.114 M x 0.0267 L
n = 0.00304 mol
Step 2: Find the moles of acetic acid using stoichiometry
The molar ratio between acetic acid and KOH is 1:1
Therefore the moles of acetic acid = 0.00304 mol
Step 3: Calculate the molarity of acetic acid
C = n/V
C = 0.00304/0.0389
C = 0.0781 M
Solution
Molarity of acetic acid = 0.0781
4)
If atom A bonds with atom B covalently, and atom A attracts electrons with
greater force, which of the following will be true?
O Atom A will have a greater share of electrons and will have a
slight positive charge.
Atom A will take all of the electrons and have a slight positive
charge.
Atom A will have a greater share of electrons and will have a
slight negative charge.
Atom B will lose its valence electrons and have a slight negative
charge.
с
Atom A will have a greater share of electrons and will have a slight negative charge according to Polar Covalent bond
What is Polar Covalent Bond ?
A specific type of covalent link is known as a polar bond. It is also the point at which an ionic bond and a pure covalent bond begin to form, according to another definition. A polar covalent bond, on the other hand, is a link that exists between two atoms and is made up of electrons that are scattered unevenly if we want to define it more precisely. The molecules have a tendency to have an electrical dipole moment in which the two ends are slightly positive or negative as a result of this state.
The many forms of covalent bonding are mostly determined by the electronegativity of the material. The propensity of an atom to draw a shared pair of electrons to itself is known as electronegativity. It is a trend and has no units. Polar covalent bonds are those created between two atoms in molecules with an electronegative difference.
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You have 2.2mol Xe and 2.0mol F2, but when you carry out the reaction you end up with only 0.25mol XeF4. What is the percent yield of this experiment?: Xe(g) + 2F2(g) -> XeF4(g)
If 2.2 mol Xe and 2.0 mol [tex]F_2[/tex] reacts to produce 0.25 mol [tex]XeF_4[/tex], the percent yield of the experiment will be 25%.
What is the percent yield of an experiment?The percent yield of an experiment is the amount of the actual yield of the experiment relative to the theoretical yield of the same experiment.
Mathematically; percent yield = actual yield/theoretical yield x 100%
In the illustrated experiment, the mole ratio of Xe and [tex]F_2[/tex] is 1:2. With 2.2 mol Xe reacting against 2.0 mol [tex]F_2[/tex] , it means [tex]F_2[/tex] is limited in availability with Xe being excessive.
The mole ratio of [tex]F_2[/tex] and [tex]XeF_4[/tex] is 2:1. Thus, the mole of [tex]XeF_4[/tex] that should be theoretically produced would be half of the mole of [tex]F_2[/tex] that reacts.
Thus, mole of [tex]XeF_4[/tex] = 2/1
= 1
But only 0.25 mol of [tex]XeF_4[/tex] were produced.
Percent yield = 0.25/1 x 100%
= 25%
The percent yield of the experiment is, therefore, a paltry 25%.
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What is the name of the molecule below?
• A. 2-pentyne
B. pentane
• C. 2-pentene
O D. 2-pentane
The molecule described below is known as :
2-pentene.
What exactly are alkenes?Alkenes are organic compounds that contain a double bond and are composed of carbon and hydrogen atoms.They can be used as starting materials in the synthesis of alcohols, plastics, lacquers, detergents, and fuels.In the diagram below:
Each corner and joint displays the carbon atoms, and the total number of carbon atoms is 5.In the second position, there is one double bond.As a result, the compound is 2 pentene.
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look at the picture
Answer:
I believe it is the last choice
Explanation:
Isotopes of a certain element must have the same atomic number(the # of protons). This is what differentiates the different elements. However, isotopes could have varying amounts of neutrons, therefore the atomic mass could vary as well.
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please crown me brainliest!!!
Aqueous hydrochloric acid (HCI) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O).Suppose 1.46 g of hydrochloric acid is mixed with 2.9 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.
PLEASE HELP SOLVE
The balanced chemical equation for this reaction is:
HCl + NaOH = NaCl + H2O
1.46 g of HCl is equal to 0.0400 moles of HCl. (1.46/36.458). (36.485 being the molar mass of HCl in grams/mole).
2.9 g of NaOH is equal to 0.0725 moles of NaOH. (2.9/39.997). (39.997 being the molar mass of NaOH in grams/mole).
- From the reaction we can infer that it takes one mole of HCl and one mole of NaOH to form one mole of water. Therefore the limiting reactant in this case will simply be the one that we have the least amount of. So HCl is the limiting reactant.
- As stated previously, it takes one mole of HCl to produce one mole of H2O so that would mean that 0.0400 moles of HCl would produce 0.0400 moles of H2O.
0.0400*18.01 (18.01 being the molar mass of water in grams/mole) will give you the grams of H2O produced in this reaction.
Answer: 0.720 grams of H2O
According to the below equation, how many moles of P2H4 will be required to generate 1.76×1023 molecules of P4?
6P2H4→8PH3+P4
The number of the moles of the P₂H₄ is equal to 1.734 moles, which will generate 1.76×10²³ molecules of P₄.
What is the balanced chemical equation?The equation in which the total mass of substances on the reactant side is equal to the total mass of substances on the product side is known as a balanced chemical equation.
The law of conservation of mass must obey by a balanced chemical equation. The given balanced chemical reaction of the reaction of P₂H₄ is :
6 P₂H₄ → 8 PH₃ + P₄
The number of molecules of the phosphorous P₄ formed = 1.76 × 10²³
The number of moles of P₄ = 1.76 × 10²³/(6.022 × 10²³) = 0.292 mol
One of the phosphorous P₄ is formed from P₂H₄ = 6 mol
Then 0.292 mol of P₄ will form from P₂H₄ = 6× 0.292 = 1.734 mol
Therefore, the 1.734 moles of P₄ are required to form 1.76×10²³ molecules of P₂H₄.
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A weather balloon is designed to burst when the volume reaches
250.0 L. The balloon is filled with 32.0 L helium at sea level where the
pressure is 1.00 atm at 20.0 °C. The balloon expands and bursts after
ascending until the temperature is -35.0 °C. Determine the pressure
(in psi) at which the balloon bursts.
The pressure at which balloon bursts is 3.07 psi , when expands and bursts after ascending until the temperature is -35 degree celsius.
What is pressure and it is calculated out to be 3.07 psi?As we have already studied in earlier classes pressure is the force per unit perpendicular area.Here , is given initial volume 32 L and the initial pressure 1 atm , initial temperature 20 degree celsius and final temperature -35 degree celsius. The balloon burst when the volume of gas reaches 250 L, so final volume is 250 L .According to combined gas law : P1V1/T1 = P2V2/T2 , where P1 is the initial pressure , we know that T1 = 20+ 273 K = 293 K.T2 = -35 + 273 = 238 K , now using equation , 1 atm x 32/29 = P2 x 25/238, P2 = 0.209 atm , 1 atm = 14.69 psi , so 0.209 atm = 14.6956 x 0.209 = 3.07 psi.So the balloon bursts at 3.07 psi.To know more about pressure visit:
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How many degrees will 340 J raise the temperature of 6.8 g of water
The temperature raised is 11.9 degrees as the heat capacity is 340J
What is heat capacity ?
Heat Capacity is the quantity of energy needed to raise a substance's temperature by one degree Celsius. It can also be thought of as the proportion of energy transmitted to an item to the rise in temperature that follows.
The heat capacity measurement is in Joules per degree Celsius as well. Because it is based on the object's mass. Additionally, it is frequently stated in terms of 100 grammes in order to facilitate comparisons between objects of similar mass.
Q = m*c*T
Q = heat energy
m = mass of substance
c = specific heat capacity
T = temperature
Q = 6.8*4.2*T
T = 340/6.8*4.2
T =11.90 celsius
The temperature raised is 11.9 degrees as the heat capacity is 340J
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A 27.7 mL sample of a H3PO4 (triprotic) solution is titrated with a 0.609 M NaOH solution. The equivalence point is reached when 44.1 mL of NaOH solution is added. What is the concentration of the H3PO4 solution?
The concentration of the 27.7 mL H₃PO₄ solution is 0.323 M
We'll begin by writing the balanced equation for the reaction. This is given below:
H₃PO₄ + 3NaOH —> Na₃PO₄ + 3H₂O
From the balanced equation above, we obatined:
The mole ratio of the acid, H₃PO₄ (nA) = 1The mole ratio of the base, NaOH (nB) = 3How to determine the concentrationThe concentration of the H₃PO₄ can be obtained as follow:Volume of acid, H₃PO₄ (Va) = 27.7 mLConcentration of base, NaOH (Cb) = 0.609 M Volume of base, NaOH (Vb) = 44.1 mLConcentration of acid, H₃PO₄ (Ca) =?CaVa / CbVb = nA / nB
(Ca × 27.7) / (0.609 × 44.1) = 1 / 3
(Ca × 27.7) / 26.8569 = 1 / 3
Cross multiply
Ca × 27.7 × 3 = 26.8569
Ca × 83.1 = 26.8569
Divide both side by 83.1
Ca = 26.8569 / 83.1
Ca = 0.323 M
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When Tabitha was testing a substance she thought might be heroin, she added the Marquis reagent chemical to the substance. It turned purple, so she was able to verify it was heroin. What does this BEST demonstrate?
A.
demonstrative evidence
B.
individual characteristics
C.
physical properties
D.
chemical properties
Answer:
Demonstrative evidence
look at the picture
Answer: The correct option is ○ O₂
Explanation:
All the other options denote that they are not a single element theyare
in compound form. Only the oxygen is in element form.
Based on the balanced chemical equation shown below, what volume of 0.250 M K2S2O3(aq), is needed to completely react with 37.32 mL of 0.125 M KI3(aq)?
Based on the balanced chemical equation, the volume of 0.250 M K₂S₂O₃ (aq) needed to completely react with 37.32 mL of 0.125 M KI₃ (aq) is 37.32 mL.
What is the balanced equation for the reaction of K₂S₂O₃ (aq) and KI₃ (aq)?The reaction between K₂S₂O₃ (aq) and KI₃ (aq) is a redox reaction.
The balanced chemical equation of the reaction is given as follows:
2 S₂O₃²⁻ (aq) + I₃⁻ (aq) ---> S₄O₆²⁻ (aq) + 3 I⁻ (aq)
Based on the balanced equation of the reaction:
2 moles of K₂S₂O₃ (aq) are required to react with one mole KI₃ (aq).
Moles of KI₃ (aq) in 37.32 mL of 0.125 M solution;
moles = molarity * volumeMoles of KI₃ (aq) = 37.32 * 0.125 M
Moles of KI₃ (aq) = 4.665 mmoles
Moles of K₂S₂O₃ (aq) required = 2 * 4.665 mmoles
Moles of K₂S₂O₃ (aq) required = 9.33 mmoles
Volume of K₂S₂O₃ (aq) required =moles / molarity
The volume of K₂S₂O₃ (aq) required = 9.33 / 0.25
The volume of K₂S₂O₃ (aq) required = 37.32 mL
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Consider the following ionic
compounds and determine which
has the higher melting point.
A. BeCl₂
B.Al₂S3
Answer:
Al2S3
Explanation:
Al2S3 has ions which have a higher magnitude of charge compared to BeCl2. This higher charge creates stronger attractive forces between molecules, holding them together even at high temperatures. Another simple way to compare the melting points is to multiply the charges of the ions together and compare those values. BeCl2 would be 2*1 because of Be2+ and Cl (1)-. Al2S3 would be 2*3 because of S2- and Al3+. Since 2*3 is more than 2*1, Al2S3 has a higher melting point. I think this is a repeat question
The radius of a nickel atom is 125 pm. How many nickel atoms would have to be laid side by side to span a distance of 2.65 mm?
The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is 1.06 x 10⁷ atoms of nickel.
What is the diameter of the nickel atom?The diameter of the nickel atom is the line that divides the nickel atom into two equal halves. The diameter of an object is always double of the radius when the radius of the atom is known.
The diameter of the nickel atom is calculated as follows;
d = 2r
where;
d is the diameter of the nickel atomr is the radius of the nickel atomd = 2 x 125 pm
d = 250 pm
d = 2.5 x 10⁻¹⁰ m
The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is calculated as follows;
n(2.5 x 10⁻¹⁰ m) = 2.65 mm
n(2.5 x 10⁻¹⁰ m) = 2.65 x 10⁻³ m
n = (2.65 x 10⁻³) / (2.5 x 10⁻¹⁰)
n = 1.06 x 10⁷ atoms of nickel
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Consider the reaction: 2Al + 3S = Al2S3If you have 45 grams of aluminum...a. How many grams of aluminum sulfide are produced? (Theoretical)b. When the rxn is performed in the lab, 114 grams of aluminum sulfide is produced. What is the percent yield?
The reaction they give us is balanced. We must determine the moles of aluminum that are equivalent to that 45 g, for this, we will use the molar mass of aluminum equal to 26.98g/mol
[tex]\begin{gathered} \text{Mol of Al}=GivengAl\times\frac{1molAl}{MolarMass,gAl} \\ \text{Mol of Al}=45gAl\times\frac{1molAl}{26.98gAl}=1.67molAl \end{gathered}[/tex]Now, in the reaction, we can see that for every 2 moles of aluminum, 1 mole of aluminum sulfate is produced. We can also use the molar mass of aluminum sulfate (101.96g/mol) to calculate the grams of aluminum sulfide produced.
[tex]\begin{gathered} gAl_2O_3=GivenMolAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{MolarMass,gAl_2O_3}{1molAl_2O_3} \\ gAl_2O_3=1.67molAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{101.96gAl_2O_3}{1molAl_2O_3}=85gAl_2O_3 \end{gathered}[/tex]The grams of aluminum sulfate produced is 85g
The percent yield is calculated with the next equation:
[tex]\begin{gathered} \text{Percent yield=}\frac{\text{Actual yield}}{Theoretical\text{ yield}}\times100\% \\ \text{Percent yield=}\frac{\text{1}14g}{85g}\times100\%=134\% \end{gathered}[/tex]Percent yield=134%
This is not experimentally possible
What might happen if your lab group had such a cluttered lab area
Answer:
depending on what you guys are doing someone could get hurt or knock something over and break it
Explanation:
Please help me with question 6!!The neutralization of a weak base and a strong acid should product a solution that is:a. basicb. neutralc. all of aboved. acidic
INFORMATION:
We have the neutralization of a weak base and a strong acid, and we must determine what should be the product of the reaction
STEP BY STEP EXPLANATION:
To determine it, we need to know that:
- The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.
In our case, we have the neutralization of a weak base and a strong acid, so our product would have a pH of less than 7. Then, knowing that a pH less than 7 represents an acidic, we can state that the product of the reaction will be an acidic.
A strong acid and a weak base yield a weakly acidic solution, not because of the strong acid involved, but because of the conjugate acid of the weak base.
ANSWER:
d. acidic
This is the correct Lewis structure for the molecule C2H2Cl2?
True or false
Answer: It is false
Explanation:
Write the ionic and net ionic equations for the following reaction:
Co(NO3)2(aq) +Na2CO3(aq)->
Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH->
The ionic and net ionic equations for the following reaction is
Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3
Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O
What is ionic equation?Ionic equation is defined as a chemical equation that expresses electrolytes in aqueous solution as dissociated ions.
An ionic equation can also be defined as one that solely depicts the atoms and ions that really participate.
Net ionic equation is defined as only those elements, molecules, and ions actually involved in the chemical process are shown in the chemical equation.
It can also be defined as an equation that simply includes the components that are really involved in the reaction.
Thus, the ionic and net ionic equations for the following reaction is
Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3
Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O
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