A self-storage center has many storage rooms that are 6 feet wide, 10 feet deep, and 12 feet high. What is the volume of the room?
Answer:
720 ft^3
Step-by-step explanation:
6 * 10 *12
v = l * w * h
6 * 10 * 12 = 720
Volume is a three-dimensional scalar quantity. The volume of the self-storage centre room is 720 ft³.
What is volume?A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of a room or box that is the shape of a rectangular prism is calculated by multiplying the length, width, and height of the prism.
Volume = Length × Width × Height
Given that the self-storage centre room's are 6 feet wide, 10 feet deep, and 12 feet high. Therefore, the dimension of the room can be written as,
Length = 10 ft
Width = 6 ft
Height = 12 ft
Now, the volume of the room can be written as,
Volume of the room = 10ft × 6ft × 12ft
= 720 ft³
Hence, the volume of the self-storage centre room is 720 ft³.
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A bakery sold a total of 500 cupcakes in a day, and 190 of them were vanilla flavored. What percentage of cupcakes sold that day were vanilla flavored?
Answer: 50/19
Step-by-step explanation:
I'm no math genius however I believe this is division.
500/190 gave me a fraction which is 50/19.
Helpppppppp me …………………..
Answer:
first let's solve for x
x + (x + 30) + 2x = 180
4x + 30 = 180
-30 -30
4x = 150
/4 /4
x = 37.5
Now solve for the angle measures:
(x + 30) = (37.5 + 30) = 67.5
2x = 2(37.5) = 75
x = 37.5
Answer:
X= 37.5
Step-by-step explanation:
a prisms base has a perimeter of 12cm and a height of 2 cm. the area of the base was 5cm. what is the surface area of the prism.
[tex]\text{Surface Area of Prism} = (2 \times \text{Base Area}) + (\text{Base perimeter} \times \text{height})\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(2 \times 5)+(12\times 2)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=10+24\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=34~~ \text{cm}^2[/tex]
If f (x) = 3x + 2 and g(x) = x2 – x, find the value.
-
f (2)+1
Answer:
......
Step-by-step explanation:
find the derivitive of f(x)=(x+9)/(x+1)
[tex]\dfrac{d}{dx} \left(\dfrac{x+9}{x+1}\right)\\\\\\=\dfrac{(x+1)\dfrac{d}{dx}(x+9) - (x+9) \dfrac{d}{dx}(x+1)}{(x+1)^2}\\\\\\=\dfrac{(x+1) - (x+9)}{(x+1)^2}\\\\\\=\dfrac{x+1-x-9}{(x+1)^2}\\\\\\=-\dfrac{8}{(x+1)^2}[/tex]
Which of the following is the graph of y=x+3
Answer:ITS THE SECOND ONE
Step-by-step explanation:
Henry used his GPS to measure the distances from his house to two locations to the thousandth mile. Then, he rounded both values to the nearest hundredth. Which pair of distances could be the actual distances Henry measured?
school: 3.26 miles
piano lessons: 5.84 miles
-2(x-6)=6 help me out
Answer:
x = 9
Step-by-step explanation:
i took the quiz
[tex]\mathfrak{-2(x-6)=6} [/tex]
[tex]\mathfrak{-2x+12=6} [/tex]
[tex]\mathfrak{-2x=6-12} [/tex]
[tex]\mathfrak{-2x=-6} [/tex]
[tex]\boxed{\mathfrak{x=3} }[/tex]
Can someone help me please?
Answer:
put your equation into fractions and then see what or which 1mathces with the image
Step-by-step explanation:
sin(83)cos(7) + cos(83)sin(7)
Answer:
1
Step-by-step explanation:
correct on edge
sin(83 radians) * cos(7 radians)) + (cos(83 radians) * sin(7 radians)) =
0.893996664
Answer:
hope it helps
The function v(t) is the velocity in m/sec of a particle moving along the x-axis. Use analytic methods to do each of the following: (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particle's displacement for the given time interval. If s(0) = 3, what is the particle's final position? (c) Find the total distance traveled by the particle. v(t) = 5 (sint)^2(cost); 0 ≤ t ≤ 2π
Answer:
(a) The particle is moving to the right in the interval [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].
(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].
(c) The total distance traveled by the particle is 9.67 (2 d.p.)
Step-by-step explanation:
(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).
Situation 1: When the particle stops.
[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].
Situation 2: When the particle moves to the right.
[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]
Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .
*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.
Situation 3: When the particle moves to the left.
[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]
Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].
(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.
[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]
To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where
[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].
[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]
Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].
The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].
(c)
[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]
[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]
[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].
The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].
A line has a slope of and passes through the point (4, 7). What is its equation in
slope-intercept form?
Answer:
y = (7/4)x + 0
Step-by-step explanation:
yeah-ya....... right?
The average of eight different numbers is 5. If 1 is added to the largest number, what is the resulting average of the eight numbers?
Answer:
Step-by-step explanation:
X/8 = 5
X = 40
Adding 1 to the largest number (or any other of the numbers, for that matter) makes the sum 41 and the average 41/8 or 5 1/8.
The average of a given number is the sum of the given numbers divided by the number of numbers in the given set.
The resulting average of the eight numbers after adding 1 to the largest number is 5.125.
What is a mean?It is the average value of the set given.
It is calculated as:
Mean = Sum of all the values of the set given / Number of values in the set
Example:
2, 3, 4, 5
The average number of 1, 2, 4, and 5 is 3.
i.e 12 ÷ 4 = 3
We have,
The average of eight different numbers is 5.
Let the sum of 8 different numbers be M.
Average = M / 8
5 = M / 8
M = 8 x 5
M = 40
Now,
If 1 is added to the largest number.
This means,
40 + 1 = 41
The resulting average of the eight numbers:
= 41/8
= 5.125
Thus,
The resulting average of the eight numbers after adding 1 to the largest number is 5.125.
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Help help math math math
Answer:
-3/7,0
Step-by-step explanation:
x-5y=16 , 4x-2y=-8 solve using elimination method
Answer:
x = -4
y = -4
Step-by-step explanation:
L1 x - 5y = 16
L2 4x - 2y = -8
4*L1 - L2
4x - 20y = 64
-4x + 2y = 8
-----------------------
-18y = 72
y = 72 / -18
y = -4
x - 5y = 16
x = 16 + 5y
x = 16 + 5(-4)
x = 16 - 20
x = -4
A group of pigs and ducks has a total of 40 feet. There are twice as many ducks as pigs. How many of each animal are there?
The question relates to the total number of pairs of feet ducks and a pigs
are known to have.
There are 5 pigs and 10 ducksReasons:
The length of the group of ducks and pigs = 40 feet
Number of ducks = Twice the number of pigs
Each duck has 2 feet.Each pig has 4 feet.Let x represent the number of pigs, and let y represent the number of ducks, we have;
y = 2 × x
4·x + 2·y = 40
Which gives;
4·x + 2 × (2·x) = 40
8·x = 40
x = 40 ÷ 8 = 5
The number of pigs, x = 5y = 2 × x
Therefore;
y = 2 × 5 = 10
The number of ducks, y = 10Learn more about solving word problems in mathematics here:
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How do I simplify the ratio of
42 : 28 : 21
Answer:
6:4:3
Step-by-step explanation:
each can be divided by 7
Answer:
6 4 3
Step-by-step explanation:
Given 2 angles that measure 50 and 80 and a side that measure 4 feet how many triangles if any can be condctuted
Answer:
The number of unique triangles that can be constructed from the given values is; Only one triangle
Step-by-step explanation:
We are given the 2 angles of a triangle as;
∠1 = 50°
∠2 = 80°
Now, we know that sum of angles in a triangle is 180°. This means that if the third angle is denoted as ∠3, then we have;
∠1 + ∠2 + ∠3 = 180°
Thus;
∠3 = 180 - (∠1 + ∠2)
∠3 = 180 - (50 + 80)
∠3 = 180 - 130
∠3 = 50°
Thus; ∠1 = ∠3 = 50°
A triangle with two equal angles is called an isosceles triangle. Which means that it will also have 2 of its' sides to be equal.
Thus, in conclusion, only one unique triangle can be drawn.
Some one help me? ill give 50 points
Answer:
v=[tex]\frac{(w+v)/t}{2}[/tex]
Step-by-step explanation:
just inverse operations and you will always get your answer :)
Match each shape with its area formula.
square: A=s^2
triangle: A=(1/2)bh
rectangle: A=lw
parallelogram: A=bh
What is the solution to the equation −6z+1=−4−7z , given the replacement set {−5, −3, −1} ?
−5
−3
−1
I don't know.
the solution to the system of equation from the replacement set is -5
Given the equation −6z+1=−4−7z, we are to find the value of z from the given equation:
Given
−6z+1=−4−7z
Collect the like terms;
-6z + 7z = -4 - 1
Simplify the result
z = -4 -1
z= -5
Hence the solution to the system of the equation from the replacement set is -5
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Answer:
-5
Step-by-step explanation:
I took the quiz in k12
According to the website www.olx.uz, monthly rent for a two-bedroom apartment has a mean of
$250 and a standard deviation of $100 in the city of Andijan. The distribution of the monthly rent does not
follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample
of 40 two-bedroom apartments and finding the mean to be at least $275 per month?
Using the normal distribution and the central limit theorem, it is found that there is a 0.0571 = 5.71% probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.In this problem:
The mean is of $250, hence [tex]\mu = 250[/tex].The standard deviation is of $100, hence [tex]\sigma = 100[/tex].The sample is of 40 apartments, hence [tex]n = 40, s = \frac{100}{\sqrt{40}}[/tex].The probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month is the p-value of Z when X = 275, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{275 - 250}{\frac{100}{\sqrt{40}}}[/tex]
[tex]Z = 1.58[/tex]
[tex]Z = 1.58[/tex] has a p-value of 0.9429.
1 - 0.9429 = 0.0571
0.0571 = 5.71% probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month.
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Ron wants to make money painting portraits of people at the local mall. The mall
charges Ron $22.00 a day for Ron to set up his materials to sell his portraits. He
charges $15.50 a portrait, but it costs him $3.25 in materials to make that portrait.
If x represents the number of portraits that Ron sells at the mall, which of the
following expressions would represent Ron's profit (how much money Ron will walk
away with at the end of the day)? (There is more than one answer)
12. 25x – 22.00
15.50x – 22.00
0-22.00 + 15.50x – 3.25x
15.50x
3. 25x – 22.00
22.00x – 3.25x
15.50
Answer:
A and CStep-by-step explanation:
With the amount x of portraits the daily balance is:
- $22.00+ $15.50x- $3.25xThe total is:
15.50x - 3.25x - 22.00 ⇒ 12.25x - 22.00Correct choices are A and C
With the amount x of portraits the daily balance is:
- $22.00
+ $15.50x
- $3.25x
The total is:15.50x - 3.25x - 22.00 ⇒ 12.25x - 22.00
Correct choices are A and CPlease help with this question !!
Answer:
c) i^337 is equivalent to the expression i^137
#13) Mrs. Frye says that the following triangles are congruent. Is she correct? Why or why not?
Answer: The following triangles are congruent.
Which of the following is a rational number?
Omar needs at least $8 to buy lunch. Which number line represents this scenario?
Answer:
I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.
negative eight i multiplied by five i
Which of the following is equal to 2,952 ÷ 24?
A.
(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)
B.
(2,400 + 24) ÷ (480 + 24) ÷ (72 + 24)
C.
(2,400 + 24) + (480 + 24) + (72 + 24)
D.
(2,400 ÷ 24) - (480 ÷ 24) - (72 ÷ 24)
Answer:
A
Step-by-step explanation:
After doing long division we then know that 2,952 ÷24 = 123
We 1st follow pemdas knowing this we solve the equations in parenthesis 1st
(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)
2,400 ÷ 24 = 100
480 ÷ 24 = 20
72 ÷ 24 = 3
We can then rewrite the equation as
100 + 20 + 3 We then solve left to right
100 + 20 = 120
120 + 3 = 123