Using appropriate technology, you determine that Earth's magnetic field at your location has a magnitude of 5.88 10-5 T and is directed north at an angle of 56° below the horizontal. You charge a metallic projectile and fire it north with a speed of 663 m/s and at an angle of 14° above the horizontal. Determine the sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west.
C

Answers

Answer 1

The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as

q=+1.11524613*10^{−4}C

What is the sign (+ or −) and charge?

Generally, the equation for Force is  mathematically given as

[tex]F=Bqvsin\theta[/tex]

Therefore

[tex]3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}[/tex]

q=+1.11524613*10^{−4}C

In conclusion, the sign (+ or −) and charge

q=+1.11524613*10^{−4}C

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Related Questions

A ball of mass m is dropped. What is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time τ later? Ignore air resistance.

Answers

The formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.

Impulse exerted on the ball

The impulse exerted on the ball at any given instant is calculated as follows;

J = ΔP

J = Pf - Pi

where;

J is impulse exerted on the ballpf is final momentumpi is the initial momentum

Thus, the formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.

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A container of PS5s with a mass of 451kg is loaded onto a Walmart truck using a ramp. The ramp is 6.12m long and
the bed of the truck is 1.53m above the ground. A force of 2025N applied parallel to the ramp moves the precious
consoles at a constant speed up the ramp. Find the efficiency of the ramp..
a) 54.6%
b) 32%
c) 46.4%
d) 54.65%

Answers

A. The efficiency of the ramp is 54.6 %.

Velocity ratio of the ramp

V.R = distance moved by effort/distance moved by load = L/h

V.R = (6.12)/(1.53) = 4

Mechanical advantage of the ramp

M.A = Load/Effort

M.A = (451 x 9.8)/(2025)

M.A = 2.183

Efficiency of the ramp

E = (M.A / V.R) x 100%

E = (2.183 / 4) x 100%

E = 54.6 %

Thus, the efficiency of the ramp is 54.6 %.

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A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?

Answers

Answer:

The value of work being done on the object is 958J.

Explanation:

Work done is equal to force multiply by distance, but when the angle is between the force and distance work done=Force (cos theta) × distance

Work done = Force(cos theta) × distance

Work done = 25N(cos 40.0°) × 50m

Work done = 25N(0.7660) × 50m

Work done = 19.15N × 50m

Work done = 957.5J = 958J

Therefore the value of work being done on the object is 958J.

find the x-component of this vector.

Answers

The x-component for the vector given in the image is : [tex]B_{x}[/tex] = 18.3m

Meaning of a Vector

A Vector can be defined as a quantity that possesses both magnitude and direction thereby giving more details.

A vector is very important when it comes to dealing with forces.

Analysis

[tex]B_{x}[/tex] = B cos(Θ)

Θ = 180° - 170° = 10°

[tex]B_{x}[/tex] = B cos(10°) = 18.3m

In conclusion, The x-component for this vector is : [tex]B_{x}[/tex] = 18.3m

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calculate the pressure of water in a well if the depth of the water is 10m​

Answers

Answer:

P= phg

so:- the height is 10m

density of water 1000 kg/m3

gravity is 9.8m/s2

P=1000 kg/m3*10m*9.8m/s2

=98000Pa

=98KPa

A rock of mass 200 g is attached to a 0.75 m long string and swung in a vertical plane.
a) What is the slowest speed that the rock can travel and still maintain a circular path?
b) What is the tension in the string at the bottom of the swing?

Answers

Hello!

a) Assuming this is asking for the minimum speed for the rock to make the full circle, we must find the minimum speed necessary for the rock to continue moving in a circular path when it's at the top of the circle.

At the top of the circle, we have:

- Force of gravity (downward)

*Although the rock is still connected to the string, if the rock is swinging at the minimum speed required, there will be no tension in the string.

Therefore, only the force of gravity produces the net centripetal force:

[tex]\Sigma F = F_g\\\\F_c = F_g\\\\\frac{mv^2}{r} = mg[/tex]

We can simplify and rearrange the equation to solve for 'v'.

[tex]\frac{v^2}{r} = g\\\\v^2 = gr\\\\v = \sqrt{gr}[/tex]

Plugging in values:

[tex]v = \sqrt{9.8 * 0.75} = \boxed{2.711 m/s^}[/tex]

b)
Let's do a summation of forces at the bottom of the swing. We have:
- Force due to gravity (downward, -)

- Tension force (upward, +)

The sum of these forces produces a centripetal force, upward (+).

[tex]\Sigma F = T - F_g\\\\F_c = T - F_g\\\\\frac{mv^2}{r} = T - mg[/tex]

Rearranging for 'T":
[tex]T = \frac{mv^2}{r} + mg\\\\[/tex]

Plugging in the appropriate values:
[tex]T = \frac{(0.2)(2.711^2)}{(0.75)} + 0.2(9.8) = \boxed{3.92 N}[/tex]

Hello!!
The correct answer would be number B)!! I took the test hope it helps

Q1) Write True or False for each statement:

Equal volumes of the two different substances have equal masses.

Answers

Answer:

True

Explanation:

it is true because blabla bla

Kim has her coffee cup on her car's dash when she takes a corner with radius 4 m and 20 km/h.
What is the minimum coefficient of static friction which would allow the coffee cup to stay there
without slipping?

Answers

The minimum coefficient of static friction is  0.807

What is static friction?

Static friction is friction between two or more solid objects that are not moving relative to each other.

According to the question,

When an object turns on a curve path at a specific speed, two forces will be acting on the object which balance each other:

Centripetal force and friction force.

The friction coefficient between the object and the path is independent of the object's mass.

Given,

The radius of a corner is, r=4.16m

The turning speed of the car is, v

[tex]20km/h * (\frac{\frac{5}{18}m/s }{1km/h} )[/tex]

= 5.72 m/s

To avoid slipping a coffee cup on the car's dashboard, the centripetal force would balance the friction force.

So,  Fc=Ff

[tex]\frac{mv^2}{r}[/tex]=μmg

μ=[tex]\frac{v^2}{rg}[/tex]

Here,

Fc represents the centripetal force.

Ff represents the friction force.

μ represents the coefficient of static friction.

g represents the gravitational acceleration whose value is 9.8m/s²

By Substituting the values in the above formula, we get:

μ =[tex]\frac{(5.72m/s)^2}{(4m)(9.8m/s^2)} \\[/tex]  ≈ 0.807

Therefore,

The minimum coefficient of static friction is  0.807

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Theory of uniform accelerated motion lab reports

Answers

The theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

What is the theory of uniform accelerated motion?

The theory of uniform accelerated motion is a scientific statement regarding the acceleration of an object in steady conditions.

This theory (uniform accelerated motion) is fundamentally applied in physic and astrophysics.

In conclusion, the theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

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importance of states of matter​

Answers

Answer:

STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.

Explanation:

The form of energy that can move from place to place across the universe is

Answers

Answer:kinetic energy

Explanation:

Answer: kinetic energy

You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
How much work do you perform during the lifting process?
If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?

Answers

The work done is 8427 J while the energy expended is  80.25 W.

What is work done?

Work done is defined as the product of the force and the distance. We know that the work done in a gravitational field is given as;

W = mgh

Total mass of the water bucket and chain = 13.9 kg +  19.3 kg = 33.2Kg

Distance covered =  25.9 m

W = 33.2Kg * 9.8 m/s^2 * 25.9 m

W = 8427 J

Recall that the work done = Energy expended

Power = Energy expended/ Time

Power = 8427 J/ 1.75 * 60 seconds

Power = 80.25 W

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The minimum takeoff speed for a certain airplane is 50 m/s. What minimum acceleration is required if the plane must leave a runway of length 2000 m? assume the plane starts from rest at one end of the runway.

Answers

Assuming constant acceleration, the requisite magnitude is [tex]a[/tex] such that

[tex]\left(50\dfrac{\rm m}{\rm s}\right)^2 - 0^2 = 2a (2000\,\mathrm m)[/tex]

Solve for [tex]a[/tex] :

[tex]a = \dfrac{\left(50\frac{\rm m}{\rm s}\right)^2}{4000\,\mathrm m} = \boxed{0.625 \dfrac{\rm m}{\mathrm s^2}}[/tex]

the sound of a lamb is ....... due to its pitch depending upon its ....... frequency?

Answers

The sound of a lamb is grave due to its high pitch depending on its low frequency. Option B is correct.

What is the frequency of the sound?

A sound pressure wave's frequency is the number of times it repeats itself every second.

The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.

Pitch and the frequency of sound are inverse to each other. A lamb's sound is grave because of its high pitch and low frequency.

The sound of a lamb is grave due to its high pitch depending on its low frequency.

Hence, option B is correct.

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In the first seconds of flight, the Saturn V rocket achieved an altitude of m, and a velocity of m/s. The rocket weighed approximately kg. What was the average power produced by the rocket?

Answers

The average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

Average power produced by the rocket

The average power produced by the rocket is calculated as follows;

P = FV

where;

P is the average powerF is the force exerted by the rocketV is the velocity of the rocket

Thus, the average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

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A yoyo with a mass of m = 150 g is released from rest as shown in the figure.

The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is I[tex]_{cm}[/tex] = 1.01×10-4 kgm2.

1. Determine the linear acceleration of the yoyo.

2. Determine the angular acceleration of the yoyo.

3. What is the weight of the yoyo? (Hint: It's not 150 g)

4. What is the tension in the rope?

5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?

Answers

(1) The linear acceleration of the yoyo is 3.21 m/s².

(2) The angular acceleration of the yoyo is 80.25 rad/s²

(3) The  weight of the yoyo is 1.47 N

(4) The tension in the rope is 1.47 N.

(5) The angular speed of the yoyo is 71.385 rad/s.

Linear acceleration of the yoyo

The linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.

∑τ = Iα

rT - Rf = Iα

where;

I is moment of inertiaα is angular accelerationT is tension in the roper is inner radiusR is outer radiusf is frictional force

rT - Rf = Iα  ----- (1)

T - f = Ma  -------- (2)

a = Rα

where;

a is the linear acceleration of the yoyo

Torque equation for frictional force;

[tex]f = (\frac{r}{R} T) - (\frac{I}{R^2} )a[/tex]

solve (1) and (2)

[tex]a = \frac{TR(R - r)}{I + MR^2}[/tex]

since the yoyo is pulled in vertical direction, T = mg [tex]a = \frac{mgR(R - r)}{I + MR^2} \\\\a = \frac{(0.15\times 9.8 \times 0.04)(0.04 - 0.0214)}{1.01 \times 10^{-4} \ + \ (0.15 \times 0.04^2)} \\\\a = 3.21 \ m/s^2[/tex]

Angular acceleration of the yoyo

α = a/R

α = 3.21/0.04

α = 80.25 rad/s²

Weight of the yoyo

W = mg

W = 0.15 x 9.8 = 1.47 N

Tension in the rope

T = mg = 1.47 N

Angular speed of the yoyo

v² = u² + 2as

v² = 0 + 2(3.21)(1.27)

v² = 8.1534

v = √8.1534

v = 2.855 m/s

ω = v/R

ω = 2.855/0.04

ω = 71.385 rad/s

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In each case below, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask.

Which image represents a gaining of a charge on the leaves of the electroscope by conduction?

Answers

Answer:

(B)  (the leaves will separate when subjected to a net charge)

The image that represents a gaining of a charge on the leaves of the electroscope by conduction is image B.

What is electroscope?

An electroscope is a device that detects the presence of an electric charge or ionizing radiation by suspending a pair of thin gold leaves from an electrical conductor that leads to the outside of an insulating container.

When an electrical charge is brought close to or in contact with a conductor, the leaves in an electroscope spread apart.

This occurs because the same charge, whether positive or negative, is received by the leaves, causing their repulsion (spreading apart).

A negatively charged rod is brought in close proximity to an uncharged electroscope. As a result, the electroscope leaves become further apart.

Thus, image B is representing the given scenario.

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Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?

Answers

Answer:

[tex]\huge\boxed{\sf a = 0.7 \ m/s^2}[/tex]

Explanation:

Given Data:

Initial velocity = [tex]V_i[/tex] = 0.5 m/s

Final velocity = [tex]V_f[/tex] = 4 m/s

Time = t = 5 s

Required:

Acceleration = a = ?

Formula:

[tex]\displaystyle a =\frac{V_f-V_i}{t}[/tex]

Solution:

Put the givens in the formula.

[tex]\displaystyle a=\frac{4-0.5}{5} \\\\a = \frac{3.5}{5} \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}[/tex]  

physical properties of matter help describe a substance which of the following is not a physical property of a soil sample?
A. the container in which the soul is held
B. the color of the soil
C. the volume of the soil
D. the texture of the soil
Answer asap this is an exam il give brainlist

Answers

A the container the soil is held in is not a feature of the soil itself

An object moves in uniform circular motion at 50 m/s and takes 1.0 second to go a quarter circle. Calculate the
centripetal acceleration.

Answers

Answer:

The centripetal acceleration (ac)=314m/s²

Explanation:

look at the attachment ☝️

9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer

Answers

Answer:

Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.

Explanation:

How do the Sun, Earth, and Moon systems interact

Answers

The sun is the mother star of the solar system, which only emits light to half of the planet, while the other part is always dark.

The sun emits light towards the earth, which dominates all life on earth. The movements of the Moon around the Earth and of the Earth around the Sun are complex. Movements of rotation around their own axes are superimposed on movements of orbital translation. The Earth and the Moon rotate around their own axes: This is rotation.

in order for work to be done wht must happen?
Answer asap please due soon

Answers

An object must move in the same direction as the force is applied for work to be accomplished. Option C is correct.

What is work done?

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative. it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The work done is found as;

W= F × d

Where.

F is the force

d is the displacement

W is the work done

In order for work to be done, an object must move in the same direction, and the force is applied

Hence option C is correct.

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Question Completion Status: 1 points QUESTION 1 The following excerpt is taken from the Governors Highway Safety Association (GHSA) website (https://www.ghsa.org): Setting speed limits has traditionally been the responsibility of states, except for the period of 1973-1994. During that time, the federal government enacted mandatory speed limit ceilings on interstate highways and similar limited access roads through a National Maximum Speed Limit. ✓ Sav Congress repealed the National Maximum Speed Limit in 1995. Since then, 41 states have raised speed limits to 70 mph or higher on some portion of their roadway systems. In many states, maximum speeds vary depending on vehicle type (car or truck), roadway location (urban or rural), or time of day. GHSA tracks state maximum speed limits for both urban and rural interstates, as well as other limited access roads. In a few states, speed limits are not set by law. Your textbook includes the following physics problem: If the speed of a car is increased by 50%, by what factor will its minimum braking distance be increased, assuming all else is the same? Ignore the driver's reaction time. To complete the Civic Engagement component of this course, write an essay about the National Speed Limit. In this essay, do the following: 1. Solve the above physics problem. 2. Use your solution to the above physics problem and the information contained in the above excerpt to argue for the reinstatement of a National Maximum Speed Limit. Your orrny should be 3000 to 5000 characters long (not including spaces) You are expected to format all variables/equations using the math editor, which you access​

Answers

There should be a reinstatement of the National Maximum Speed Limit for the safety of road users because the minimum braking distance is 2,25m.

Calculations and Parameters

Hence, we can see that the minimum braking distance for the car would be:

d'/d= (v'1/v1)^2 = (1.5/1)^2

= 2.25m

The speed limit ensures that drivers do not exceed a set speed limit in order to reduce road accidents and keep road users safe and also the pedestrians would be able to navigate easier.

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A person of mass 100kg runs up a staircase with a vertical height of 10m. If the trips takes 5 seconds to complete, calculate the person's power ( acceleration due to gravity =10m/s²)

Answers

Answer:

Power = 2000J/s

Explanation:

Power= Total Work done/Time

Given

mass = 100kg

distance(height) = 10m

time = 5s

acceleration due to gravity = 10m/

Work done = force × distance

Finding Force

Force = mass × acceleration due to gravity

Force = 100kg × 10m/

Force = 1,000N

Finding work done

Work done = Force × distance

Work done = 1,000N × 10m

Work done = 10,000J

Finding Power

Power = work done/time

Power = 10,000J/5s

Power = 2,000J/s

Therefore Power is 2,000J/s

A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 80.9 kg, including her space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
HINT

Answers

Answer:

Approximately [tex]4.61\times 10^{3}\; {\rm N}[/tex] upwards (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

External forces on this astronaut:

Weight (gravitational attraction) from the earth (downwards,) andNormal force from the floor (upwards.)

Let [tex](\text{normal force})[/tex] denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

[tex]\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}[/tex].

Let [tex]m[/tex] denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be [tex](\text{weight}) = m\, g[/tex].

Let [tex]a[/tex] denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be [tex](\text{net force}) = m\, a[/tex].

Rearrange [tex]\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}[/tex] to obtain an expression for the magnitude of the normal force on this astronaut:

[tex]\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}[/tex].

A rod of length 58.0 cm and mass 1.10 kg is suspended by two strings which are 35.0 cm long, one at each end of the rod.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.

Answers

a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω

b)ω = [tex]\frac{3g}{2l}[/tex]

c)14.7  the magnitude of the initial acceleration of the end B when the string is cut.

What is Acceleration?

Acceleration is the rate of change of the velocity of an object with respect to time.

Given

A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.

When the string is cut rod rotates about other end.

Let's take momentum equation about that end:

mg*[tex]\frac{1}{2}[/tex] = Iω [I = [tex]ml^\frac{2}{3}[/tex]]

a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω

Angular acceleration:

b)ω = [tex]\frac{3g}{2l}[/tex]

c)Acceleration of end B:

a = lω= [tex]\frac{3g}{2}[/tex] =[tex]\frac{3*9.8}{2}[/tex]

a = 14.7 [g=9.8]

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You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
How much work do you perform during the lifting process?

8427 J is Incorrect.

If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?

80.25 W is Incorrect.

Answers

The total work done is  5980 Joules and the power expended is 57 Watts.

What is work done?

The work done is the work done in the gravitational field as the bucket is raised up Thus work required to remove the bucket Wb;

Wb = 13.9 kg * 25.9 m * 9.8 m/s^2 = 3530 Joules

Height of the center of mass of chain = 25.9 / 2 = 12.95 m  

Work done by the chain Wc;

Wc = 12.95 * 19.3 * 9.8 = 2450 Joules  

Total work = 3530 + 2450 = 5980 Joules

Power expended = W / t = 5980 J / 105 sec = 57 J/s = 57 Watts

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What is the size of the image on the retina of a size object 1.5 cm, placed at a distance (120 cm) away? Take the .lens-to-retina distance to be 2 cm

Answers

Answer: 0.025 cm

Explanation:

The image distance must match the distance between the lens and the retina for clear vision. Consequently, the image distance is v = 2 cm

The magnification of the lens is given by

m = v/u = h'/h

Where h' is the height of the image

v/u = h'/ h

h' = ( v/u ) × h

h' = ( 2cm /-120cm ) × 1.5cm

h' = - 0.025cm

Therefore, the height of the image is 0.025 cm

Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
She jogs around the trail until she reaches a pond, where she stops briefly.
She then continues to follow the trail around the pond. Which reference point
should be used to describe her motion?
A. Her car
B. The trail entrance
C. The pond
D. The trail

Answers

The reference point that should be used to describe Melanie motion is the pond (option C).

What is reference point?

Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.

According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.

However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.

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I am not able to solve this question The value of n from the set {6, 7, 8, 9} that holds true for 4n 12 < 2n + 2 is? The belief held by many racial minorities that lighter skinned minority women are more attractive than those with darker skin is referred to as ________. An actor who approaches a role through the study of human behavior in its outward forms is using an: in what way does translation change information? How much did the government regulate business practices during the Gilded Age?It barely regulated businesses at all.It strictly regulated the railroad industry, but left other businesses alone.It regulated the steel industry and the railroad industry, but no other businesses.It strictly regulated all businesses. _____ refers to a contractual, strategic partnership between two or more separate business entities to pursue a business opportunity together. Which pair of uses of figurative language from The Caged Bird help support the extended metaphor of freedom versus oppression? You have prepared an aqueous solution of a monoprotic acid (formula mass = 153.483g/mol) by dissolving 26.816g of the acid in sufficient water to make 500.0mL of solution. The pH of the resulting solution is 4.274. What is Ka for this acid? The _______ effect means water can "climb" up thin tubes and water plants. This is due to the ______ nature of water. The numbers of customers entering each of two stores every hour wererecorded. The results are shown. Which statement about the number ofcustomers at the stores is not correct?4040HI50FStore A506070Store B6070808090490 In which of these ways is Islam similar to both Christianity and Judaism? If P = (-3,-2) and Q = (1, 6) are the endpoints of the diameter of a circle, find the equation of the circle.(x +?)^2 + (y - ?)^2 = ? Question 27 Mike is remodeling his kitchen. The countertop he wants costs $2.80 per square foot. How much will Mike have to spend on his remodeling project If you know that lithium reacts strongly with oxygen in a 2:1 ratio, which ofthe following properties would you predict about cesium After brushing, Fluffy's fur has a charge of +8.0 10-9 coulombs and her plastic brush has a charge of 1.4 10-8 coulombs. If the distance between the fur and brush is roughly 5.0 10-1 meters, what is the approximate magnitude of the force between them?(k = 9.0 109 newtonmeters2/coulomb2) A mobile veterinary business, Portable Paws, Inc., created a mission statement long before it opened its doors for business. The mission statement referred to the unique characteristic of the business: a traveling pet unit whose veterinarians went to the home of the pet owner, rather than the pet owner bringing the pet to the clinic. What other criteria should be considered for the mission statement how to estimate 11578995 to the nearest lakh A fish tank has a length of 12 cm a width of 15 cm and a depth of 25 cm find the volume of the fish tank Capacity planning requires demand forecasts for an extended period of time. Forecast accuracy tends to _______ as the forecasting horizon _______.