Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340

Answers

Answer 1

The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?

[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]

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Answer 2

Answer:

6.983 km/hr

Explanation:

The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr

Mejor yo por favor


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T1=40°C=313KT_2=-10°C=263K

Applying Charles law

[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]

[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]

[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]

Which of the following statements cannot be supported by Kepler's laws of planetary motion?


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Answers

the second
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Explanation:

Have a great day!

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Electromagnetic


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Answers

Gravitational Force

Explanation:-

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The gravity attracts the magma to do that.

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Hope it helps

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Answers

Time taken by the skydiver to land on the ground is 4.57 seconds

The applied force, F = 700 N

The mass of the skydiver, m = 80 kg

The velocity, v = 40 m/s

To calculate the time taken by the skydiver to fall to the ground will be calculated using the formula

[tex]F=\frac{mv}{t}[/tex]

Substitute F = 700, m = 80, and v = 40 to solve for t

[tex]700=\frac{80(40)}{t}\\\\700t=3200\\\\t=\frac{3200}{700}\\\\t=4.57 s[/tex]

Time taken by the skydiver to land on the ground is 4.57 seconds

Learn more here: https://brainly.com/question/25898421

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Answers

The galaxy is 7200 km/s moving away from us.

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The question can be solved using the formula below

⇒ Formula

v = Cd........................ Equation 1

⇒ Where:

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⇒ Given:

C = 72 km/s/mpcd = 100 mpc

⇒ Substitute these values into equation 1

v = 72(100)v = 7200 km/s.

Hence, the galaxy is 7200 km/s moving away from us.

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Answer:

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Answers

Answer:

hi your answer should be B

Explanation:

Hope this helps!

Answer:

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Answers

Answer:

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Explanation:

Answer:

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Answer:

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Hey there! I'll try to provide you with my best answer.

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Answer:

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