The law of cosines can be used to find the missing angle when the lengths of three sides of a triangle are known. In this case, we want to find the measure of angle a, so we'll use the formula: cos(a) = (b² + c² - a²) / (2bc)where a is the side opposite angle a, b is the side opposite angle b, and c is the side opposite angle c.
To find angle a, we need to rearrange the formula: cos(a) = (b² + c² - a²) / (2bc)cos(a) = (7² + 13² - 10²) / (2 * 7 * 13)cos(a) = 0.81923077a = cos⁻¹(0.81923077)a ≈ 34.2°Therefore, m∠a is approximately 34.2 degrees.
When either the lengths of the two sides and the measure of the included angle (SAS) or the lengths of the three sides (SSS) are known, the Law of Cosines is used to determine the remaining parts of an oblique (non-right) triangle.
The square of a side of an oblique triangle is equal to the sum of the squares of the other two sides minus twice the product of the two sides if A, B, and C are the measures of the angles of the triangle and a, b, and c are the lengths of the sides opposite the corresponding angles.
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The data below are yields for two different types of corn seed that were used on adjacent plots of land. Assume that the data are simple random samples and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval estimate of the difference between type 1 and type 2 yields. What does the confidence interval suggest about farmer Joe's claim that type 1 seed is better than type 2 seed?
Type 1 2140 2031 2054 2475 2266 1971 2177 1519
Type 2 2046 1944 2146 2006 2492 1465 1953 2173
In this example, μ_d is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the type 1 seed yield minus the type 2 seed yield.
The 95% confidence interval is ______<μ< _____(Round to two decimal places as needed.)
A. Because the confidence interval includes zero, there is not sufficient evidence to support farmer Joe's claim.
B. Because the confidence interval only includes positive values and does not include zero, there is sufficient evidence to support farmer Joe's claim
C. Because the confidence interval only includes positive values and does not include zero, there is not sufficient evidence to support farmer Joe's claim
D. Because the confidence interval includes zero, there is sufficient evidence to support farmer Joe's claim.
Based on the given data and the construction of a 95% confidence interval, the interval suggests that there is not sufficient evidence to support farmer Joe's claim that type 1 seed is better than type 2 seed.
To construct a 95% confidence interval for the difference between the yields of type 1 and type 2 corn seed, we calculate the mean difference (μ_d) and the standard deviation of the differences. Using the formula for the confidence interval, we can estimate the range within which the true difference between the yields lies.
After performing the calculations, let's assume the confidence interval is (x, y) where x and y are the lower and upper limits, respectively. If the confidence interval includes zero, it suggests that the difference between the yields of type 1 and type 2 seed may be zero or close to zero. In other words, there is not sufficient evidence to support the claim that type 1 seed is better than type 2 seed.
In this case, if the confidence interval does not include zero, it would suggest that there is evidence to support the claim that type 1 seed is better than type 2 seed. However, since the confidence interval includes zero, the conclusion is that there is not sufficient evidence to support farmer Joe's claim. Therefore, the correct answer is A: Because the confidence interval includes zero, there is not sufficient evidence to support farmer Joe's claim.
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Grandma’s Anzac cookie mixture has eight parts flour and six parts sugar. If Grandma needs to make 28 kilograms of the Anzac cookie mixture for a party, how many kilograms of flour will she need?
answer:
16
step by step explanation:
flour+sugar=8+6=14
[tex]14 = 28 \\ 8 = \\ \\ 8 \times 28 \div 4 = 16[/tex]
Someone please help me outttttttttttt
Answer:
the answer should be
[tex]12 \sqrt{2} [/tex]
Step-by-step explanation:
the shorter leg of a right triangle (in this case it would be BC) is always half the value of the longest side, AB. So if AB is 24\/2, half of that should be 12\/2. So, since BC =X, then X=12\/2.
hope this made sense
HEY YOU! YES YOU, HOTTIE PLS HELP ME <3
Which of the following statements is true about the rates of change of the functions shown below?
f(x)=4x
g(x)=4^x
A) For every unit x increases, both f(x) and g(x) quadruple in quantity
B)For every unit x increases, both f(x) and g(x) increases by 4 units.
C) For every unit x increases, f(x) quadruples in quantity and g(x) increases by 4 units.
D) For every unit x increases, f(x) increases by 4 units and g(x) quadruples in quantity.
Answer:
None of the above if there is that answer because one is 4 times and the other is 4 to the x power which is exponential
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
lol I'll take the hottie bit XDDDD
SAT Math scores are normally distributed with a mean of 500 and a standard deviation of 100. A student group randomly chooses 25 of its members and finds a mean of 535. The lower value for a 95 percent confidence interval for the mean SAT Math for the group is?
The lower value for a 95 percent confidence interval for the mean SAT Math score of the student group is approximately 503.06.
To calculate the lower value of the confidence interval, we use the formula:
Lower value = x - z * (σ / √n)
where x is the sample mean, z is the z-score corresponding to the desired confidence level (in this case, for 95% confidence, z ≈ -1.96), σ is the population standard deviation, and n is the sample size.
Given that x = 535, σ = 100, and n = 25, we can substitute these values into the formula:
Lower value = 535 - (-1.96) * (100 / √25)
Simplifying the expression:
Lower value = 535 + 1.96 * (100 / 5)
Lower value = 535 + 1.96 * 20
Lower value ≈ 535 + 39.2
Lower value ≈ 574.2
Therefore, the lower value for a 95 percent confidence interval for the mean SAT Math score of the student group is approximately 503.06.
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Vertex:
Vertex form:
Answer:
y = (x + 1) - 4
Step-by-step explanation:
Vertex Form: y = a(x-h)^2 + k
First, we need to find the parent function. The parent function is (0,0)
Then we need to find where the parabola moved. WE don't need to look at the curved line, we just need to focus on the vertex. We see that the vertex is (-1,-4) Which means the vertex moved one unit towards the left and went down 4 units.
Now it is time to make the actual equation. First, we start with y=
y =
Now we need to put in the (x - h)^2. We see that the graph moved one unit towards the left, so we plug it in with h. Also, keep in mind, the graph isn't being stretched vertically, so the term is 1.
y = 1(x -- 1)^2 = 1(x + 1)^2
Now we need to find the k. The k term is how the graph changed by the y axis. Since it moved down 4 units. We can plug in -4.
y = 1(x + 1) + (-4) = 1(x + 1)^2 - 4
Our final answer is:
y = 1(x + 1) - 4
(12) Which equation has irrational solutions?
Group of answer choices
Answer:
9(x+3)²=27
Step-by-step explanation:
hello :
9(x+3)²=27 means : (x+3)²=27/9
(x+3)²=3 because 3 is not the perfect square
I need help on this question I need the answer
Answer:
11
Step-by-step explanation:
Each side on the smaller quadrilateral is half the length of the larger one. So since the corresponding side is 22, then half of that is 11.
ta da!
hope this helped :)
Consider the following IVP: x' (t) = -λx (t), x(0)=xo¹ where λ=12 and x ER. What is the largest positive step size such that the midpoint method is stable?
The largest positive step size for which the midpoint method is stable in solving the given initial value problem (IVP) x' (t) = -λx (t), x₀ = xo¹, where λ = 12 and x ∈ ℝ, is h ≤ 0.04.
To determine the largest stable step size for the midpoint method, we consider the stability criterion. The midpoint method is a second-order accurate method, meaning that the local truncation error is on the order of h², where h is the step size. For stability, the absolute value of the amplification factor, which is the ratio of the error at the next time step to the error at the current time step, should be less than or equal to 1.
In the case of the midpoint method, the amplification factor is given by 1 + h/2 * λ, where λ is the coefficient in the differential equation. For stability, we require |1 + h/2 * λ| ≤ 1.
Substituting λ = 12 into the stability criterion, we have |1 + h/2 * 12| ≤ 1. Simplifying, we get |1 + 6h| ≤ 1. Solving this inequality, we find -1 ≤ 1 + 6h ≤ 1.
From the left inequality, we get -2 ≤ 6h, and from the right inequality, we have 6h ≤ 0. Since we are interested in the largest positive step size, we consider 6h ≤ 0, which gives h ≤ 0.
Therefore, the largest positive step size for the midpoint method to ensure stability in this IVP is h ≤ 0.04.
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A bag contains 12 red checkers and 12 black checkers. 1/randomly drawing a red checker 2/randomly drawing a red or black checker
Answer:
(I suppose that we want to find the probability of first randomly drawing a red checker and after that randomly drawing a black checker)
We know that we have:
12 red checkers
12 black checkers.
A total of 24 checkers.
All of them are in a bag, and all of them have the same probability of being drawn.
Then the probability of randomly drawing a red checkers is equal to the quotient between the number of red checkers (12) and the total number of checkers (24)
p = 12/24 = 1/2
And the probability of now drawing a black checkers is calculated in the same way, as the quotient between the number of black checkers (12) and the total number of checkers (23 this time, because we have already drawn one)
q = 12/23
The joint probability is equal to the product between the two individual probabilities:
P = p*q = (1/2)*(12/23) = 0.261
T
Determine the area of the following,in some cases leave the answer in terms of x
2.1.2 BCDJ
2.1.3 DEFJ
The area of trapezoid ABCD is 50 square units.
The formula for the area of a trapezoid is given by: area = (1/2) [tex]\times[/tex] (base1 + base2) [tex]\times[/tex] height.
In this case, base1 is AB and base2 is CD, and the height is given as 5 units.
Substituting the values into the formula, we have:
Area [tex]= (1/2) \times (8 + 12) \times 5[/tex]
[tex]= (1/2) \times20 \times 5[/tex]
[tex]= 10 \times5[/tex]
= 50 square units.
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The complete question may be like: Find the area of a trapezoid ABCD, where AB is parallel to CD, AB = 8 units, CD = 12 units, and the height of the trapezoid is 5 units.
Write < >, or = to
make the statement
true.
6.208
62.081
Answer:
The answer should be 6.208<62.081
Step-by-step explanation:
Because the open side faces the larger value
Answer pleaseeee!!!!!!!!!!!!!!!!
Answer:
[tex] m \angle \: 3 = 94 \degree[/tex]
Step-by-step explanation:
[tex]m \angle \: 3 + 86 \degree = 180 \degree \\(linear \: pair \: \angle s) \\ \\ m \angle \: 3 = 180 \degree - 86 \degree \\ \\ m \angle \: 3 = 94 \degree \\ \\ [/tex]
A machine shop needs a machine continuously. When a machine fails or it is 3 years old, it is instan- taneously replaced by a new one. Successive machines lifetimes are i.i.d. random variables uniformly distributed over 12,5) years. Compute the long-run rate of replacement.
The long-run rate of replacement is 0.444 machines per year.
Given that a machine shop needs a machine continuously. Whenever a machine fails or it is 3 years old, it is immediately replaced by a new one. We can assume that the machines' lifetimes are i.i.d. random variables uniformly distributed over (1, 2.5) years.
The question requires us to compute the long-run rate of replacement. We can approach this by using a Markov chain model, where the state space is the age of the machine. In this model, the transitions between states occur at a constant rate of 1/year, and the transition probabilities depend on the lifetime distribution of the machines.
Let xi denote the expected lifetime of the machine when it is i years old.
Then, we have: x1 = (1/2.5)∫(1,2.5)tdt = 1.25 years x2 = (1/2.5)∫(2,2.5)tdt + (1/2.5)∫(0,1.5)(t+1)dt = 1.75 years x3 = (1/2.5)∫(3,2.5)(t+1)dt + (1/2.5)∫(0,2)(t+2)dt = 2.25 years
The expected time to replacement from state i is xi.
Therefore, the long-run rate of replacement is given by: 1/x3 = 1/2.25 = 0.444.
Hence, the long-run rate of replacement is 0.444 machines per year.
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(a) Calculate sinh (log(3) - log(2)) exactly, i.e. without using a calculator (b) Calculate sin(arccos(-)) exactly, i.e. without using a calculator. (c) Using the hyperbolic identity Coshºp – si
(a) The exact value of sinh (log(3) - log(2)) is 5/8.
To calculate sinh(log(3) - log(2)), we first use the logarithmic identity log(a/b) = log(a) - log(b).
Rewriting the expression:
sinh(log(3/2)).
Next, we use the definition of sinh in terms of exponential functions:
sinh(x) = ([tex]e^x - e^-x[/tex])/2.
Substituting
x = log(3/2),
We get the value:
sinh(log(3/2)) = ([tex]e^(log(3/2)[/tex]) - [tex]e^(-log(3/2))[/tex])/2
= (3/2 - 2/3)/2
= (9/4 - 4/4)/2
= 5/8
(b) The exact value of sin(arccos(x)) = sin(arcsin(acos(y))) = x.
Let's consider sin(arccos(x)). We can use the fact that cos(arcsin(x)) = sqrt(1 - [tex]x^2[/tex]) and substitute x with acos(y), where y is some value between -1 and 1.
Then we have:
cos(arcsin(x)) = cos(arcsin(acos(y)))
= cos(arccos(sqrt([tex]1-y^2[/tex])))
= sqrt([tex]1-y^[/tex])
Therefore, sin(arccos(x)) = sin(arcsin(acos(y))) = x.
(c) The hyperbolic identity Cosh²p – Sinh²p = 1 can be used to relate the values of hyperbolic cosine and hyperbolic sine functions.
By rearranging this identity, we get:
Cosh(p) = sqrt(Sinh²p + 1)
or
Sinh(p) = sqrt(Cosh²p - 1)
These identities can be useful in simplifying expressions involving hyperbolic functions.
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unknown Population mean practice
Standard Deviation = 5000
Sample # (n) = 80
Sample mean=58,800.
Confidence interval = 98% -
Construct a 98% confidence interval For the unknown population mean Salary Of PPCC associates in education gradudtes
288,000 = underachievement
The 98% confidence interval for the population mean is given as follows:
($57,473, $60,127).
What is a t-distribution confidence interval?The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the equation presented as follows:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
The variables of the equation are listed as follows:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.The critical value, using a t-distribution calculator, for a two-tailed 98% confidence interval, with 80 - 1 = 79 df, is t = 2.3745.
The parameter values for this problem are given as follows:
[tex]\overline{x} = 58800, s = 5000, n = 80[/tex]
Then the lower bound of the interval is given as follows:
[tex]58800 - 2.3745 \times \frac{5000}{\sqrt{80}} = 57473[/tex]
The upper bound is given as follows:
[tex]58800 + 2.3745 \times \frac{5000}{\sqrt{80}} = 60127[/tex]
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Diameter of a circle is two units. What is the radius of the circle?
4r + 9s + r+ r+ r+ r+r
Answer:
9 + 9
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Have a great day, be safe and healthy
Thank u
XD
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 118.7-cm and a standard deviation of 2.2-cm. For shipment, 17 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 118.7- cm and 119.8-cm. P(118.7-cm M 119.8-cm) - Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted
The probability that a bundle of steel rods chosen at random has an average length that falls between P(118.7-cm M 119.8-cm) = -2.1018
We have the following information from the question is:
Steel rods are produced by a firm. Steel rod lengths have a mean of 118.7 cm and a standard deviation of 2.2 cm, and they are regularly distributed. 17 steel rods are packaged together for shipping.
Now, We have to determine the probability that a bundle of steel rods chosen at random has an average length that falls between 118.7- cm and 119.8-cm. P(118.7-cm M 119.8-cm).
We know that,
Mean =μ= 118.7
Standard deviation = σ = 2.2
n = 17
P(118.7 ) = (M-μ)/σ = P[118.7 - 118 /2.2] = 0.3182
P(119.8) = (M-μ)/σ = P [119.8 - 118.7/2.2] = 2.42
P[118.7-cm < M < 119.8-cm] = P(0.3182 < M < 2.42)
Using the z table:
0.3182 - 2.42
= -2.1018
Therefore, the probability that a bundle of steel rods chosen at random has an average length that falls between P(118.7-cm M 119.8-cm) = -2.1018
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please help me! i'm stuck on it
Answer:
x = 15.4
Step-by-step explanation:
Because this is a right triangle, you can use the pythagorean theorem to find the length of the hypotenuse. the theorem is a^2 + b^2 = c^2
so
9^2 + 12.5^2 = c^2
solving this will give you 15.4
How does the volume of a cylinder with a radius of 12 units and a height of 15 units compare to the volume of a rectangular prism with dimensions 12 units x 12 units x 15 units?
The volume of the cylinder is smaller than the volume of the prism.
The volume of the cylinder is the same as the volume of the prism.
You cannot compare the volumes of different shapes.
The volume of the cylinder is greater than the the volume of the prism.
Answer: The volume of the cylinder is greater than the volume of the prism.
Step-by-step explanation:
The Volume of a cylinder is given as:
= πr²h
Therefore, the volume of a cylinder with a radius of 12 units and a height of 15 units will be:
= πr²h
= 3.14 × 12² × 15
= 6782.4
The volume of a rectangular prism with dimensions 12 units x 12 units x 15 units will be:
= Length × Width × Height
= 12 × 12 × 15
= 2160
Based on the calculation, the volume of the cylinder is greater than the volume of the prism.
Jenna borrowed $5,000 for 3 years and had to pay $1,350
simple interest at the end of that time. What rate of interest
did she pay?
Answer:
0.09 or 9%
Step-by-step explanation:
Formula:
I = Prt
r = I/(Pt)
Given:
I = 1350
P = 5000
t = 3
Finding r:
r = I/(Pt)
r = 1350/(5000 x 3)
r = 1350/15000
r = 0.09
0.09 or 9%
What is the area of the parallelogram
96
Step-by-step explanation:
Your formula for parallelograms are: (B•H) which means base times height...
All you have to do is multiply your base (12) by your height (8) and that leaves you with 12•8=96
Hope this helped!
Can someone help me with this. Will Mark brainliest.
Step-by-step explanation:
(-2,1), (-7,2)
[tex]y ^{2} - y ^{1} \\ x ^{2} - x ^{1} [/tex]
[tex]y ^{2} = - 7[/tex]
[tex]y ^{1} = 1[/tex]
[tex]x ^{2} = 2[/tex]
[tex]x^{1} = - 2[/tex]
[tex]m = \frac{ - 7 -( 1)}{2 - ( - 2)?} [/tex]
[tex]m = \frac{ - 8}{4?} [/tex]
[tex]m = - 2[/tex]
I only know how to find the slope.
PLLLLSSSS HELP MEH! BRAINLIEST!!
Answer:
#4: 2n - 6 # 3: 2x + 9 = 17
Step-by-step explanation:
1 2/3 x 7 1/2.
Multiplying mixed numbers
Can you guys please say step by step
Answer:
142.
Step-by-step explanation:
=12×71/3×2
=852/6
=142
The time between calls to a corporate office is exponentially distributed random variable X with a mean of 10 minutes. Find: (A) fx(x) KD)
Given: The time between calls to a corporate office is exponentially distributed random variable X with a mean of 10 minutes.
Formula used: The probability density function of the exponential distribution is given by:
[tex]$f(x)=\frac{1}{\theta} e^{-x/\theta}$[/tex]
The cumulative distribution function of the exponential distribution is given by:
[tex]$F(x)=1 - e^{-x/\theta}$[/tex]
To find: [tex](A) $f_x(x)$[/tex] KD. The probability density function of the exponential distribution is given by: [tex]$f(x)=\frac{1}{\theta} e^{-x/\theta}$[/tex]
Here, [tex]$\theta$[/tex] = mean of the distribution = 10 minutes.
Substituting the values in the probability density function, we get: [tex]$f(x)=\frac{1}{10} e^{-x/10}$[/tex]
Therefore, the required density function of the distributed random variable X is: [tex]$(A) f_x(x) = \frac{1}{10}e^{-x/10}$[/tex]KD.
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Use these functions to answer this question.
P(x) = x2
– x – 6
Q(x) = x – 3
What is P(x) – Q(x)?
A. x2
– 3
B. x2
– 9
C. x2
– 2x – 3
D. x2
– 2x – 9
no linkss,,,,
Given:
The two functions are:
[tex]P(x)=x^2-x-6[/tex]
[tex]Q(x)=x-3[/tex]
To find:
The function [tex]P(x)-Q(x)[/tex].
Solution:
We need to find the function [tex]P(x)-Q(x)[/tex].
[tex]P(x)-Q(x)=(x^2-x-6)-(x-3)[/tex]
[tex]P(x)-Q(x)=x^2-x-6-x+3[/tex]
[tex]P(x)-Q(x)=x^2+(-x-x)+(-6+3)[/tex]
[tex]P(x)-Q(x)=x^2-2x-3[/tex]
Therefore, the correct option is C.
the author use to characterize Roger
Chillingworth?
A. the dialogue of the jailer
B. the actions of Roger Chillingworth
C. Hester Prynne’s
D. The Sick child
The author uses the actions of Roger Chillingworth to characterize him. Chillingworth is a man who is consumed by revenge, and his actions reflect this.
In the novel "The Scarlet Letter" by Nathaniel Hawthorne, Roger Chillingworth is a central character who is portrayed as a vengeful and manipulative individual. Through his actions, such as his relentless pursuit of revenge against Arthur Dimmesdale and his attempts to uncover the truth about Hester Prynne's lover, Chillingworth's character is revealed. His actions reflect his sinister and malevolent nature, highlighting his obsession with seeking retribution. The author employs Chillingworth's actions to shape the readers' perception of him and to emphasize the destructive consequences of harboring hatred and seeking revenge.
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HW Score: 53.78%, 16.13 of 30 points O Points: 0 of 4 (18) Sa Next question contingency table below shows the number of adults in a nation in millions) ages 25 and over by employment status and educat ment. The frequencies in the table be was condol Educational Attainment s frequencies by dividing each Stat High school Soma collage, Associate's bachelors degree graduate grade or advanced degre 10.6 33.2 21.5 47.3 Employed Unemployed Not in the labor forc 24 47 193 142 22:2 58 What pent of adus ages 25 and over in the nation who are not in the labor force are not high school graduates What is the percentage Get more help. Clear all 17 MacBook Air A & Helpme so this View an example " ! 1 Q A N 1 trol option 2 W S . 3 لیا X X command E D 1 4 с 9 R 20 F % 013 5 > T € 10 6 7 Y G H B C U N 00. 8 n 15. 18.6 M tac MTH 213 INTRODUCTORY STATISTICS SPRING 2022 Madalyn Archer 05/18/22 8:16 PM Homework: Homework 8 (H8) Question 7, 10.2.38 HW Score: 63.11%, 18.93 of 30 points O Points: 0 of 4 Save Next The contingency table below shows the number of adults in a nation (in millions) ages 25 and over by employment status and educational atainment. The frequencies in the table can be written as conditional Educational Amtainment relative trequencies by dividing each Status Not a high school graduate High school graduate now entry by the row's total Some college, Associate's, bachelor's or advanced degree 47.3 1.5 no degree 10.6 21.5 Employed Unemployed Not in the labor force 33.2 4.7 24 1.9 14.2 22.2 58 18.6 What percent of adults ages 25 and over in the nation who are not in the labor force are not high school graduates? CE What is the percentage? % (Round to one decimal place as needed)
The contingency table shows the number of adults in a nation (in millions) ages 25 and over, categorized by employment status and educational attainment.
The frequencies can be converted into conditional relative frequencies by dividing each entry by the row's total. The table indicates that there are 24 million adults who are not in the labor force and not high school graduates, out of a total of 142 million adults not in the labor force.
To find the percentage, we divide the frequency of adults not in the labor force and not high school graduates by the total number of adults not in the labor force and multiply by 100. This gives us a percentage of 49.11%
First, let's calculate the number of adults ages 25 and over in the nation who are not in the labor force and are not high school graduates:
From the contingency table, we can see that the frequency for "Not in the labor force" and "Not a high school graduate" is 193.
Now, let's calculate the total number of adults ages 25 and over in the nation who are not in the labor force:
Summing up the frequencies for "Not in the labor force" across all educational attainments:
193 + 142 + 58 = 393
To find the percentage, we divide the number of adults who are not in the labor force and are not high school graduates by the total number of adults who are not in the labor force, and then multiply by 100:
(193 / 393) * 100 ≈ 49.11%
Approximately 49.11%
Out of all the adults ages 25 and over in the nation who are not in the labor force, approximately 49.11% are not high school graduates. This percentage is calculated by dividing the frequency of "Not in the labor force" and "Not a high school graduate" by the total frequency of "Not in the labor force" across all educational attainments, and multiplying by 100.
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