URGENT!!
A golf ball is hit with an initial velocity of 80 feet per second. H= -16t^2 + 80t.
1) When will the ball reach 48ft?
2) When will the ball reach 110ft?

Answers

Answer 1

9514 1404 393

Answer:

t = 0.697 secondsnever (the maximum height is 100 ft)

Step-by-step explanation:

A graphing calculator provides a nice solution to this question.

__

1) Put 48 ft in for H and solve for t:

  48 = -16t^2 +80t

  -3 = t^2 -5t

  3.25 = t^2 -5t +6.25 = (t -2.5)^2

  t = 2.5 ±√3.25

The ball will first reach 48 feet at t = 2.5 -√3.25 ≈ 0.697224 seconds.

__

2) The equation tells us the maximum height occurs at t=2.5 seconds. That height is ...

  H = -16(2.5^2) +80(2.5) = 100

The maximum height is 100 feet. The ball will never reach 110 feet.

URGENT!!A Golf Ball Is Hit With An Initial Velocity Of 80 Feet Per Second. H= -16t^2 + 80t.1) When Will

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Answer:

What are the steps for using a compass and straightedge to construct a line through point X that is parallel to line r? Drag the steps and drop them in order from start to finish. Use the straightedge to draw a line s that passes through X and intersects line r. Label the point of intersection as point Y.

Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

....................

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Answer:

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Step-by-step explanation:

Here's the equation you can write:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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GangbbsnnanMmajajajnqj

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Answers

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