Urgent and easy
Give an example where the following energy changes would take place:

7) Electrical to Thermal-
8) Chemical to Thermal-
9) Electrical to Mechanical-
10) Radiant to Chemical-

Answer:

Probably not my guy

Explanation:

Answer:

1. 7

2. Mass

3. (b) Distance

4. (b) Force

5. (a) ML⁻¹T⁻²

6. (c) M⁻¹LT²

7. (c) M⁻¹L³T⁻²

8. (c) Pressure

9. (c) Young's modulus

10. (b) zero

11. (c) Infinite

12. (d) 1:4

13. (b) 0.6 J

14. (c) 45 N

15. (a) 0.4 cc

16. (a) 176.7 °F

17. (a) 10°C

18. (c) 50 K

19. b. H

Explanation:

15. Whereby the compressibility = 4 × 10⁻⁵ Pa⁻¹

The compression ratio for 100 Pa = 4 × 10⁻⁵ × 100 = 4 × 10⁻³

The Change for 100 cc = 4 × 10⁻³ × 100 cc = 0.4cc

One frequent sign of gender inequality in the United States is that women do not earn as much as men in similar occupation. So, option (B) is correct.

Men and women are not treated equally in society, which social problem is referred to as gender inequality. Distinctions in genetics, psychology, or prevailing cultural norms in the society may be the cause of the treatment. While some of these distinctions are based on scientific research, others seem to be social constructs.

Numerous areas of study, such as education, life expectancy, personality, interests, family life, careers, and political affiliation, demonstrate the differences in gender experiences. Gender inequality impacts non-binary people and is experienced differently across cultural boundaries.

In the United States, One frequent sign of gender inequality is that women do not earn as much as men in similar occupations. So, option (B) is correct.

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Answer:

B

Explanation:

edge2020

Answer:       false

Explanation: on edg

It is false that reviewing old tests and quizzes will not help you determine what will be on a test because teachers don’t like to give students hints about what could be on future tests.

A test review verifies whether or not the modifications made to the code, data, or documentation are accurate.

In other words, it is an evaluation of the degree to which the stated goals have been attained that has been done at a set period.

Exam analysis might provide insights that can help you become a more self-sufficient learner.

You can improve your performance the next time you are tested by revising your strategy after reviewing returned examinations to learn why you made mistakes.

Thus, the given statement is false.

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Answer:

Tissue paper

Explanation:

Tissue paper is made from a synthetic material

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

Answer:

128

Explanation:

One clomiter is 1.06 multipled by 80

Answer:

(a). The change in electric potential energy is 8.3 μJ.

(b).  The second particle moves away from the source charge.

Explanation:

Given that,

Charge of first particle = -8.8 nC

Charge of second particle = -4.3 nC

Distance = 0.11 m

They are released and the second particle moves 0.030 m,

(a). We need to calculate the change in electric potential energy

Using formula of potential energy

[tex]U=\dfrac{Kq_{1}q_{2}}{d}[/tex]

Change in potential energy

[tex]\Delta U=\dfrac{kq_{1}q_{2}}{d_{2}}-\dfrac{Kq_{1}q_{2}}{d_{1}}[/tex]

Put the value into the formula

[tex]U=\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.030}-\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.11}[/tex]

[tex]\Delta U=0.000008256\ J[/tex]

[tex]\Delta U=8.3\ \mu J[/tex]

(B). We need to find the second particle move toward or away from the source charge

We know that,

Both charges are same, so the second particle will be repul from the source charge.

So, The second particle moves away from the source charge.

Hence, (a). The change in electric potential energy is 8.3 μJ.

(b).  The second particle moves away from the source charge.

Answer:

B

Explanation:

One object speeds up before it slows to a stop.

When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.

This then translates into that

The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.

then:

"One object speeds up before it slows to a stop "

Answer:

The three ways thermal energy is transferred are;

1) Conduction

2) Convection

3) Radiation

Explanation:

1) The conduction of the heat from the open flame to the marshmallow is through the direct contact of the flame with the marshmallow, such that the flame the region of the combustion reaction, that produces light and heat touches the marshmallow

2) The convection process is the transfer of heat from the rising heated combustion products, as well as the heated air that rises from the flame

3) The radiation heat transfer is the transfer of the heat from the fire to the marshmallows directly by the heat the moves in the form of electromagnetic waves at temperatures above 1000 K, without the need for a medium, such that the marshmallow can be heated by the heat coming from side of the flame.

Answer:

If we compare 270 J and 2 380.5 J the higher is 2 380.5 J which is A 9 kg object traveling at 23 m/s

Explanation:

A 60 kg object traveling at 3 m/s

Given:

m = 60 kg

v = 3 m/s

Unknown:

KE or kinetic energy

Formula and solution:

KE = 1/2 mv²

KE = 1/2 (60kg) (3m/s)²

KE = (30kg) (9m²/s²)

Final Answer:

KE = 270 kg·m²/s² or simplify as 270 J

A 9 kg object traveling at 23 m/s

Given:

m = 9kg

v = 23m/s

Unknown:

KE or kinetic energy

Formula and solution:

KE = 1/2 mv²

KE = 1/2 (9kg) (23m/s)²

KE = (4.5kg) (529m²/s²)

Final Answer:

KE = 2 380.5 kg·m²/s² or simplify as 2 380.5 J

First answer is Muscle tissue. Second answer is Nervous tissue. Third answer is Epithelial tissue. And last answer is Connective tissue.

Answer:

d

Explanation:

Answer:

in electric lamp

Electric Energy to Heat and Light Energy

Explanation:

Answer:

Ex: an electric fan transforms electric energy to kinetic energy

Or

Chemical energy to heat and light energy

Explanation:

Hope this helps

Answer:

The package strikes 207 m at the ground relative to the point.

Explanation:

Given that,

Speed = 46 m/s

Height = 101 m

Acceleration = 9.8 m/s²

We need to calculate the time

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value in the equation

[tex]101=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t=\sqrt{\dfrac{2\times101}{9.8}}[/tex]

[tex]t=4.5\ sec[/tex]

We need to calculate the distance where the package strikes

Using formula of distance

[tex]x=vt[/tex]

Put the value into the formula

[tex]x=46\times4.5[/tex]

[tex]x=207\ m[/tex]

Hence, The package strikes 207 m at the ground relative to the point.

Answer:

-ide

Explanation:

the second element is names by taking the stem of the element name and adding -ide. a system if numerical prefixes is used to specify the the number if atoms in a molecule.

Answer:

A. -ide

Explanation:

Answer:

D

Explanation:

Splitting water into hydrogen and oxygen***

Answer:

Basketball has a mass of 0.1kg

m = 0.1 kg

The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero

a = 0m/s²

The constant speed is 6m/s

v = 6m/s

So, force to keep it moving with this constant speed can be calculated using Newton second law of motion

F = ma

F = m × 0

F = 0N

So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

Answer:

8 x 10^-12

Explanation:

Radius = 4 x 10^-3nm = 4 x 10^-12 m

by the formula,

                        diameter = 2 x radius

                        diameter = 2 x (4 x 10^-12)

                        diameter = 8 x 10^-12 m

Answer:

Energy is found only in moving objects : False

Energy is never created : True

Energy can move matter : True

Energy is the same as force : False

Energy is never destroyed : True

Explanation:

Plato

Energy can neither be created nor be destroyed. Energy is generated by both moving and stationary objects but in different forms. Energy can move matter. Hence, options 2, 3 and 5 are correct.

According to the law of conservation of energy, energy can neither be created nor be destroyed. However, it can be transformed from one state to the other. For example electrical energy can be converted to light energy.

Energy is generated in both stationary and moving object. The energy for a particle gained by its motion is called its kinetic energy. The energy stored on an object at rest is called potential energy.

Energy can move matter as well. The energy used to displace an object is called work done on the object. The unit of energy and work done  is joule. Therefore, options 2, 3 and 5 are correct.

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Answer:

c. The magnitude of vertical velocity is at a maximum value.

Explanation:

I think this is correct I'm not entirely sure though

Answer:

Explanation: ns along perpendicular axes are independent and thus can be analyzed separately. This fact was discussed in Kinematics in Two Dimensions: An Introduction, where vertical and horizontal motions were seen to be independent. The key to analyzing two-dimensional projectile motion is to break it into two motions, one along the horizontal axis and the other along the vertical. (This choice of axes is the most sensible, because acceleration due to gravity is vertical—thus, there will be no acceleration along the horizontal axis when air resistance is negligible.) As is customary, we call the horizontal axis the x-axis and the vertical axis the y-axis. (Figure) illustrates the notation for displacement, where \mathbf{s} is defined to be the total displacement and \mathbf{x} and \mathbf{y} are its components along the horizontal and vertical axes, respectively. The magnitudes of these vectors are s, x, and y. (Note that in the last section we used the notation \mathbf{A} to represent a vector with components {\mathbf{A}}_{x} and {\mathbf{A}}_{y}. If we continued this format, we would call displacement \mathbf{s} with components {\mathbf{s}}_{x} and {\mathbf{s}}_{y}. However, to simplify the notation, we will simply represent the component vectors as \mathbf{x} and \mathbf{y}.)

Review of Kinematic Equations (constant a)

x={x}_{0}+\stackrel{-}{v}t

\stackrel{-}{v}=\frac{{v}_{0}+v}{2}

v={v}_{0}+\text{at}

x={x}_{0}+{v}_{0}t+\frac{1}{2}{\text{at}}^{2}

{v}^{2}={v}_{0}^{2}+2a\left(x-{x}_{0}\right)\text{.}

The total displacement \mathbf{s} of a soccer ball at a point along its path. The vector \mathbf{s} has components \mathbf{x} and \mathbf{y} along the horizontal and vertical axes. Its magnitude is s, and it makes an angle \theta with the horizontal.

A soccer player is kicking a soccer ball. The ball travels in a projectile motion and reaches a point whose vertical distance is y and horizontal distance is x. The displacement between the kicking point and the final point is s. The angle made by this displacement vector with x axis is theta.

Given these assumptions, the following steps are then used to analyze projectile motion:

Step 1.Resolve or break the motion into horizontal and vertical components along the x- and y-axes. These axes are perpendicular, so {A}_{x}=A\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {A}_{y}=A\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\theta are used. The magnitude of the components of displacement \mathbf{s} along these axes are x and \mathrm{y.} The magnitudes of the components of the velocity \mathbf{v} are {v}_{x}=v\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {v}_{y}=v\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\mathrm{\theta ,} where v is the magnitude of the velocity and \theta is its direction, as shown in (Figure). Initial values are denoted with a subscript 0, as usual.

Step 2.Treat the motion as two independent one-dimensional motions, one horizontal and the other vertical. The kinematic equations for horizontal and vertical motion take the following forms:

\text{Horizontal Motion}\left({a}_{x}=0\right)

x={x}_{0}+{v}_{x}t

{v}_{x}={v}_{0x}={v}_{x}=\text{velocity is a constant.}

\text{Vertical Motion}\left(\text{assuming positive is up}\phantom{\rule{0.25em}{0ex}}{a}_{y}=-g=-9.\text{80}{\text{m/s}}^{2}\right)

y={y}_{0}+\frac{1}{2}\left({v}_{0y}+{v}_{y}\right)t

{v}_{y}={v}_{0y}-\text{gt}

y={y}_{0}+{v}_{0y}t-\frac{1}{2}{\mathrm{gt}}^{2}

{v}_{y}^{2}={v}_{0y}^{2}-2g\left(y-{y}_{0}\right)\text{.}

Step 3. Solve for the unknowns in the two separate motions—one horizontal and one vertical. Note that the only common variable between the motions is time t. The problem solving procedures here are the same as for one-dimensional kinematics and are illustrated in the solved examples below.

Step 4.Recombine the two motions to find the total displacement\mathbf{\text{s}} and velocity \mathbf{\text{v}}. Because the x – and y -motions are perpendicular, we determine these vectors by using the techniques outlined in the Vector Addition and Subtraction: Analytical Methods and employing A=\sqrt{{A}_{x}^{2}+{A}_{y}^{2}} and \theta ={\text{tan}}^{-1}\left({A}_{y}/{A}_{x}\right) in the following form, where \theta is the direction of the displacement \mathbf{s} and {\theta }_{v} is the direction of the velocity \mathbf{v}:

Total displacement and velocity

s=\sqrt{{x}^{2}+{y}^{2}}

\theta ={\text{tan}}^{-1}\left(y/x\right)

v=\sqrt{{v}_{x}^{2}+{v}_{y}^{2}}

{\theta }_{v}={\text{tan}}^{-1}\left({v}_{y}/{v}_{x}\right)\text{.}

(a)

Answer:

Energy moves from one place to another through the wave. answer A

A wave is a disturbance that transmit energy. Thus, the correct statement is energy moves from one place to another through the wave.

A wave is a disturbance that transfers energy as it moves from one point to another.

Different terminologies are used to characterise a wave as it travels. Some of these include

Considering the question given above, we see clearly from the definition of wave that the energy is transferred as the wave is moving.

Thus, we can conclude that the correct answer to the question is energy moves from one place to another through the wave

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Answer:

1) Skis have a large area to reduce the pressure on the snow. This ensures that the skis do not sink into the snow too far.

2) The pressure under the studs on the soles of football shoes is high enough for them to sink into the ground, which gives extra grip.

3) A vacuum cleaner has a fan inside that creates a low pressure inside the device. Consequently, air and dirt particles are sucked into the device.

Answer:

Echolocation

- sound waves are being used and once they hit an object they are bounced back (that's how an echo is created)

- it's useful since it can tell you where something is

Answer:

expansion

Explanation:

all metals are conductors of heat and this heat can wear down the tracks as trains go by. this extra spacing allows the tracks to expand and contract so that the tracks do not wear down

Answer:

1) The forces acting on the puck are the forces applied by the two players in their bid to push the puck in the opposite direction

2) The puck does not move because the forces applied by the two players are equal and opposite

3) A player can get the puck to move in the direction they want by increasing the force acting in the direction they want the puck to move

Explanation:

Answer:

Hope this help

Explanation:

Specific heat capacity,c of a substance is the quantity of heat needed to raise the temperature of 1 kg mass of the substance by 1°C

Unit for c is J/kg/°C or J/kg/K