[URGENT] A swimmer wants to end up at a dock due north of her starting position on the south shore of a river. In still water her maximum speed is 1.25m/s. The river has a current flowing 0.35m/s [E].

a.) calculate the direction that she must aim herself through the water to arrive at the dock.

b.) how long will it take for the swimmer to cross the river, if the distance from the starting point to the dock is 300 m?

Please show all your work, thanks

Answers

Answer 1

Explanation:

As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).

I'll let you do all the calculations, you just have to plug in values.

[URGENT] A Swimmer Wants To End Up At A Dock Due North Of Her Starting Position On The South Shore Of
Answer 2

a)The direction that she must aim herself through the water to arrive at the dock will be 73.7°.

b)The time it takes for the swimmer to cross the river will be 240 seconds.

What is speed?

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.

Given data;

The maximum speed of the swimmer In still water,v=1.25m/s.

Speed of river = 0.35m/s [E]

α is the direction that she must aim herself through the water to arrive at the dock.

t is the time it takes for the swimmer to cross the river

The distance from the starting point to the dock is,s = 300 m

If the swimmer were to swim straight, the water's speed along the x-axis would have to match that of the swimmer.

[tex]\rm v_w = v_x = 0.35 \ m/sec[/tex]

α is the angle between vx and v

The value of the

[tex]\rm cos \alpha = \frac{v_x}{v} \\\\ \alpha = cos ^{-1}(\frac{0.35}{1.25} )\\\\ \alpha = 73.7 ^0[/tex]

The time that the swimmer will use for reaching the dock;

s = V×t

t = s/(v)

t=300 m / 1.25 m/sec

t = 240 seconds

Hence, the direction that she must aim herself through the water to arrive at the dock. and it takes for the swimmer to cross the river will be 73.7° and 240 seconds respectively.

To learn more about the speed refer to the link;

https://brainly.com/question/7359669

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Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit

It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.

When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.

Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.

"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."

Effie had never heard her father say that about anything that she had any share in. She said: "What?"

The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.

"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."

"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."

The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.

But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"

The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.

"It is a new specimen," he said, "and finer than yours, Doctor."

It was a tiny lizard, about half an inch long—with scales and wings.

So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.

And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.

"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."

And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.

Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)

He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.

Answers

believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.

Explanation:

YOUR WELCOME :)

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its "calm and curious"

Explanation:

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Help me as soon as possible <3​

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Answer: ??? what the

Explanation:

Which of the balls will exert the greatest force on object A?Why?

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F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

8 million electrons per second through an ohmic gas

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you ask or answer?

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light of wavelength 633 nm from a distant source is incident on a slit 0.750 mm wide, and the resulting diffraction pattern is observed on a screen 3.50 m away.

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if a big person and a small person run up the stairs at the same time who has more force

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Answer:

a big person

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because the big person exerts more force over the same distance

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Can someone please give me the (Answers) to this? ... please ...

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1. Newton's second law states that the force on an object is equal to its mass times its acceleration. Equation: F = ma, or force is equal to mass times acceleration.

2.

a=F/ma= 120N/68kga=(120 kg x m/s^2)/ (68kg)a = 1.8 m/s^2

3. a = 0.25 m/s^2

4. a = 0.4 m/s^2

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By the gravity of the earth it is defined by the thermal efficiency

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s

Answers

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

Velocity = 30 m/sAngle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

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what equation do you use to calculate force from work to distance

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Answer:

Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.

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This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

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Read the excerpt from The Building of Manhattan.

A temporary, small narrow-gauge track system was installed on each floor as it was needed. This enabled the material to be moved from the truck at ground level onto dump carts, raised by elevator to the designated floor, wheeled onto the track, and moved quickly to the exact spot needed. Turntables built into the track allowed the carts to be shifted about in any direction.

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When was a track system installed on a floor?
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Explanation:

A bullet having mass of 120 g is fired. It its velocity is 40 m/s, calculate its kinetic energy​

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Happy Holidays!

Recall the equation for kinetic energy:

[tex]\large\boxed{KE = \frac{1}{2}mv^2}}[/tex]

KE = kinetic energy (J)

m = mass (kg)

v = velocity (m/s)

Begin by converting 120 g to kg:

1000g = 1 kg

120 g = .120 kg

Plug in the given values:

[tex]KE = \frac{1}{2}(.120)(40^2) = \boxed{96J}[/tex]

Answer:

96 Joules

Explanation:

[tex]E_k=1/2* mass*velocity^2\\E_k=1/2 * 0.12 kg * (40m/s)^2 = 96 J[/tex]

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Answers

Answer:

E.visible lights

Explanation:

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Answers

Answer:

Before collision:

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momentum to left = .62 * 4.81 = 2.98 kg m / s

Total momentum = .49 - 2.98 = - 2.49 to left

M V = -2.49    net momentum to left

V = -2.49 / (.14 + .62) = -3.28 m/s to left

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A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.

Answers

The force of impact of the softball at the given conditions is 8 N.

The given parameters:

Horizontal velocity of the ball, v = 32 m/sChange in time of motion of the ball, Δt = 0.8 sMass of the ball, m = 0.2 kg

The force of impact of the softball is calculated by applying Newton's second law of motion as follows;

[tex]F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N[/tex]

Thus, the force of impact of the softball at the given conditions is 8 N.

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A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is

Answers

Mass (m) = 2000 KgInitial velocity (u) = 15 m/sForce (F) = 10000 NTime (t) = 3 sLet the acceleration be a.We know, F = ma,Therefore, 10000 N = 2000 Kg × a or, a = 10000 N ÷ 2000 Kg = 5 m/s^2Let the final velocity be v.By using the equation of motion, v = u + at, we getv = 15 m/s + 5 m/s^2 × 3 sor, v = 15 m/s + 15 m/s = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Which statement describes earthquakes?

They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.

Answers

Answer:

A

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earthquakes release energy

Answer:

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i can remember

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D

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If your wanting to know how to talk to them, just act like you know them really well be very causal and be confident in what you say, they also like it when you make the first move to talk to them

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Answers

Answer:

Explanation:

Depends on the location of the two forces.  If they are aligned on the same side of the object, you would simply add.

X -----------F1 -------F2

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If they are are on either side of the object, you subtract.

F1 ---------X ---------F2

Fx = F1 - F2

Any other location of F1 and F2 is much more complicated by the use of trigonometry.

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