When we calculate a function's average rate of change over a certain interval, we are computing the average number of units that the function moves up or down per unit along the xx-axis.
Given the function and interval of interest (f(x)f(x) and [x ₁,x₂]), [x\s₁,x₂ ]), our first step is to compute the value of our function at both ends of the interval. Then we plug those numbers and the interval's ends into our algorithm to calculate the average rate of change.
The average rate of change formula is
{x₂-x₁}
x f = x₂ x 1 f(x₂ )
within the interval [x₁,x ₂][x ₁,x ₂ ].
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Find the area of the region that lies inside both curves.
r^2 = 2 sin(2θ), r = 1
The area of the region that lies inside both curves r² = 2sin(2θ), r = 1 is -0.1287 square units.
Since the curves are:
r² = 2sin(2θ) and
r = 1.
We find their point of intersection.
So, r² = r²
= 2sin(2θ) = 1²
= 2sin(2θ) = 1
= sin(2θ) = 1/2
= 2θ = sin⁻¹(1/2)
= 2θ = π/6
= θ = π/12
Thus, we integrate the area from θ = 0 to θ = π/12
Now the area A of the region between two curves between θ = α to θ = β is =
= A = ∫ (r²-r'²) dθ [from 0 to π/12]
So, the area between the curves r² = 2sin(2θ), r = 1 between θ = 0 to θ = π/12 is =
= A = ∫ (r²-r'²) dθ [from 0 to π/12]
= A = (2sin2θ dθ - 1²) dθ [from 0 to π/12]
= A = 0.1278
So, the area of the region that lies inside both curves r² = 2sin(2θ), r = 1 is -0.1287 square units.
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the weight of a satellite on a planet's surface is w. which is closest to the weight of the satellite when it's in orbit?
The closest to the weight of the satellite when it's in orbit is 0
Because the surface does not apply any force to the body, it appears to have no weight.
All positions are comfortable since a body in a satellite requires no support to be at rest. We refer to this condition as weightlessness.
It will be challenging to control one's movement because, without weight, he will likely tend to drift aimlessly. He will have to push himself away from the walls or other permanent things in order to go from one place to another.
Because everything is falling freely, things are at rest in relation to one another. For example, if a table is removed from underneath an object, the object will stay in place without any support.
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how might it be helpful to know the difference between force and energy to understand the physics underlying a crash?
Work is the transmission of energy over a specific distance in one direction with the aid of a force. The force that operates at a specific distance is another name for energy.
Both of them fit the definition of a scalar unit. There must be a force and movement from one location to another for labor to take place.
Energy can be transmitted to or from an object when two things interact because of the forces that each one of the items applies to the other. For instance, the gravitational field energy of a system including the Earth and an object grows as energy is transmitted to the system when the object is raised. Power is the amount of work completed in a given amount of time. In order to learn new information and achieve higher exam scores, studying requires a lot of energy.
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true or false: for a star moving away from you, you would observe the light to be shifted toward the blue end of the spectrum.
The given statement that a star moving away from us, we observe the light to be shiftest towards the blue end of spectrum is a false statement.
This phenomenon is called doppler effect. Doppler effect of light can be described as the apparent change in the frequency of the light observed by the observer due to relative motion between the source of light and the observer
In the given situation, the source of the waves is the star, which emits light (the waves). The observer is on Earth, and the star (the source of the waves) is moving away from the observer, so, wavelength of the light observed by us is shifted with respect to the original wavelength of the light emitted by the star.
when the star moves away, the wavelength increases, so it shift towards the red end of spectrum. This effect is called red-shifted.
In the given case, the star is moving away from us, so light will shift towards red end of spectrum.hence, The given statement is false.
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compared to when the cosmic microwave background was first released, the radiation of the cosmic microwave background today is blank and has most of its photons at blank wavelengths.
The radiation of the cosmic microwave background today is blank and has most of its photons at longer wavelengths.
Gamma rays have extremely small wavelengths that are only a small portion of the size of atoms, whereas other wavelengths can extend as far as the universe because the relationship between wave frequency and wavelength is inverse. Although it isn't always stated explicitly, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, regardless of the medium they are traveling through. Electromagnetic radiation's behavior is influenced by its wavelength. wavelength x frequency equals the speed of light. Energy equals Planck's constant times frequency. Wave number in cm equals 1/wavelength. A rough estimate of the wavelength size is shown along with the wavelengths of various regions of the electromagnetic spectrum.
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explain the effects of scattering of visible light on optical effects such as sky color and darkness of shadows
The more the scattering of photons by small particles (such as molecules, microscopic water droplets, and dust particles), the shorter their wavelength.
Since short wavelengths dominate in dispersed light, the sky seems blue there while direct sunlight is more yellowish or even reddish when the sun is low in the sky. When light interacts with the environment to produce vivid and colorful displays, this is known as an optical effect. Tiny particles in the atmosphere cause optical phenomena. Sunlight is reflected, refracted, and scattered as it travels through the atmosphere by water droplets, ice crystals, and dust particles. Refraction of light waves can split white light into distinct colors and produce visual effects.
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Disregarding air resistance, what is the speed of a ball dropped from 12 feet just before it hits the ground? (Use 1 ft = 0.30 m, and use g = 9.8 m/s2.)
2.4 m/s
8.4 m/s
10.8 m/s
15.3 m/s
Answer:
[tex]8.4\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
Let [tex]x[/tex] denote the displacement of the ball. It is given that [tex]x = 12\; {\rm ft}[/tex]. Apply unit conversion and ensure that the displacement [tex]x\![/tex] of the ball is measured in meters:
[tex]\begin{aligned}x &= (12\; {\rm ft})\, \frac{(0.30\; {\rm m})}{(1\; {\rm ft})} = 3.6\; {\rm m}\end{aligned}[/tex].
Let [tex]u[/tex] denote the initial velocity of the ball, and let [tex]v[/tex] denote the velocity of the ball right before it hits the ground. Note that since the question states the ball was "dropped", assume that the ball was initially at rest with initial velocity [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex].
Under the assumptions, the acceleration [tex]a[/tex] of the ball will be constantly [tex]a = g = 9.8\; {\rm m\cdot s^{-2}[/tex].
Rearrange the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the final velocity [tex]v[/tex] of the ball right before landing:
[tex]\begin{aligned}v &= \sqrt{u^{2} + 2\, a\, x} \\ &= \sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (9.8\; {\rm m\cdot s^{-1}})\, (3.6\; {\rm m})} \\ &= 8.4\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
Answer: B (8.4 m/s)
Explanation:
find the volume of the solid that lies under the plane 4x+6y-2z+15=0 and above the rectangle
The solid that is located above the rectangle and beneath the plane 4x+6y-2z+15 has a volume of 51 liter.
The amount of space that a solid occupies is measured by its volume. The amount of unit cubes required to completely fill the solid serves as the measurement. There are 30 unit cubes total in the solid, hence the volume is 2 units. 3 units 30 cubic units from 5 units.
Formula for Solids Volume. Let's have a look at the volumes of all the three-dimensional solid shapes before we answer the problems based on the combination of solids. The formula for volume and surface area for a cuboid with dimensions of length (l), breadth (b), and height (h) is provided by: Volume = lbh.
[tex]4x+6y-2z+15=0\\2z=4x+6y+15\\z=2x+3y+ \frac{15}{2}\\[/tex]
The volume for the given solid is,
[tex]\\V= \int_{-1}^{1 } \int_{-1}^{2} \left ( 2x+3y+ \frac{15}{2} \right ) dy/dx\\V= \int_{-1}^{1 } \left [ \frac{2x^2}{2}+3xy+\frac{15x}{2} \right ]_{-1}^{2}\\V= \int_{-1}^{1 } \left [ x^2+3xy+\frac{15x}{2} \right ]_{-1}^{2}\\V= \int_{-1}^{1 } \left [ 2^2+3*2y+\frac{15*2}{2}-\left ( (-1)^2+3*-1y+\frac{15*-1}{2} \right ) \right ]\\[/tex]
[tex]V= \int_{-1}^{1 } \left [ 4+6y+\15-\left ( 1-3y-\frac{15}{2} \right ) \right ]\\V= \int_{-1}^{1 } \left [ 4+6y+\15- 1+3y+\frac{15}{2} \right ]\\V= \int_{-1}^{1 } \left [ 3+9y+\frac{45}{2} \right ]\\V= \int_{-1}^{1 } \left [ 9y+\frac{51}{2} \right ]\\V= \left [ \frac{9y^2}{2}+\frac{51 y}{2} \right ]_{-1}^{1 }\\V= \left [ \frac{9*1^2}{2}+\frac{51 *1}{2}-\left ( \frac{9*(-1)^2}{2}+\frac{51 *-1}{2} \right ) \right ]\\[/tex]
[tex]V= \left [ \frac{9}{2}+\frac{51 }{2}-\left ( \frac{9}{2}-\frac{51}{2} \right ) \right ]\\V= \left [ \frac{9}{2}+\frac{51 }{2}- \frac{9}{2}+\frac{51}{2} \right ]\\V= \left [ \frac{51 }{2}+\frac{51}{2} \right ]\\V= 51[/tex]
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an object is placed just inside the focal point of a converging lens. describe the image (mark all that apply).
As you move the object closer and closer to the focal point, the image will become further and further away kind of image results from putting anything in front of the focal
A converging lens's focal point is just outside the image result for an item. explain the picture (mark all that apply).
In reality, it is possible to generalize that the image will always be situated behind the mirror whenever the item is situated between the focal point (F) and the mirror. In certain circumstances, the image will be larger than the thing and upright (not inverted).
Kind of image results from sandwiching an object between No image is created when the object is at the focal point. although the refracted beams do not converge or diverge. The light rays cannot create an image since they are moving parallel to one another after refractive error.
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when electromagnetic energy travels from air into water, the waves are bent due to the density differences between the air and water. what is this bending called?
When a wave travels from one medium to another, its velocity (speed) changes, causing it to bend. This is known as refraction. The wave's frequency remains constant.
Refraction is the bending (and slowing down) of electromagnetic radiation's propagation direction as it passes through two denser substances. Electromagnetic waves transfer energy from one location to another through radiation. Starlight that is going through space could be this energy. Or perhaps your hands are being warmed by a campfire. A molecular substance's surface will curve when it comes into contact with another substance, creating a meniscus. Light slows down and somewhat changes direction as it passes through water from air.
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when making your turn you should accelerate at the apex of the turn. group of answer choices true false
The statement "when making your turn you should accelerate at the apex of the turn" is false.
It is generally not advisable to accelerate at the apex of a turn. In fact, it is generally recommended to slow down or maintain a constant speed while turning, in order to maintain control and avoid oversteering.
Accelerating at the apex of a turn can cause the vehicle to lose traction and potentially lose control. This is especially true if the surface is slippery or the vehicle is traveling at a high speed.
Instead of accelerating at the apex of a turn, it is generally recommended to gradually increase speed as the vehicle exits the turn, once it is back on a straight stretch of road. This allows the vehicle to maintain stability and control while turning, and helps to prevent accidents.
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the field of science that deals with the practical application of a liquid in motion is called .
The field of science that deals with the practical application of a liquid in motion is called fluid mechanics.
The fluid mechanics is the branch of science that deals with the practical application of a liquid when it is in motion or in rest.
Pascal's law, equation of continuity and Bernoulli's equation all comes under the study of fluid mechanics.
Fluid mechanics is the field of science because of which we are able to make the break of the vehicles hydraulic lift hydraulic press and many more things. We are able to make the Barometer, thermometer and many other things because of the practical applications of fluid mechanics.
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A proton follows the path shown in (Figure 1). Its initial speed is v0 = 2.2×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.
The proton's speed as it passes through point P is 1.6×10⁶ m/s.
The proton's speed at point P can be determined by the equation:
KE = PE + ( mv²/2 )
where,
KE= kinetic energy
PE = potential energy
m = mass of the proton
v = speed of the proton.
Given
Proton's initial speed is v₀ = 2.2×10⁶ m/s
By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:
v = √(2KE/m)
= √(2 ×2.2 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)
= 1.6 × 10⁶ m/s
Therefore, the proton's speed as it passes through point P is 1.6×10⁶ m/s.
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the white dwarf at the center of the helix nebula has a mass three times the mass of our sun.
Three times as massive as the Sun is the white dwarf star in the heart of the Helix planetary nebula. False The Chandrasekhar mass, or 1.4 solar masses, is the white dwarf's maximum mass.
White dwarf stars typically last between 100,000 and 10 billion years and have masses between 0.1 and 1.4 that of the Sun. To balance their mass, white dwarf stars no longer produce energy. White dwarf stars, like Sirius B, Procyon B, or Van Maanen, are limited in mass theoretically to 1.4 solar masses.
A star core remnant known as a white dwarf is primarily made up of electron-degenerate materials. A white dwarf is extremely dense; it has a mass similar to that of the sun.
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a motorcycle has a mass of 250 kg. it goes around a 13.7 m radius turn at 96.5 km/h. what is the centripetal force on the motorcycle?
A motorcycle has a mass of 250 kg. it goes around a 13.7 m radius turn at 96.5 km/h. 9720 N is the centripetal force on the motorcycle.
To find the centripetal force on the motorcycle, we can use the formula for centripetal force:
F = m * a
where F is the centripetal force, m is the mass of the object, and a is the centripetal acceleration. To find the centripetal acceleration, we can use the formula for centripetal acceleration:
a = v^2 / r
where a is the centripetal acceleration, v is the velocity, and r is the radius of the curve. In this case, we know that the mass of the motorcycle is 250 kg, the velocity is 96.5 km/h, and the radius of the curve is 13.7 m. To find the centripetal acceleration, we need to convert the velocity from km/h to m/s. Since 1 km/h is equal to 1000 m/3600 s = 0.2778 m/s, the velocity in m/s is 96.5 km/h * 0.2778 m/s/km/h = 26.7 m/s.
For centripetal force and centripetal acceleration, we get:
F = m * a
= 250 kg * (v^2 / r)
= 250 kg * (26.7 m/s)^2 / 13.7 m
= 9720 N
Therefore, the centripetal force on the motorcycle is 9720 N.
Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics. The tension of the rope provides the centripetal force on an object that is swinging around on the end of a rope in a horizontal plane. The rope illustration is a pull-related example. In some situations, such as when a wall's natural reaction serves as the centripetal force for a wall of death or a Rotor rider, the centripetal force can also be provided as a "push" force.
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Santa Claus entered the North Pole Annual Elf Throwing Competition. He fired his elf with a
horizontal speed of 25 m/s from the top of an iceberg of height 110 m. What was the elf's range and
time of flight?
Answer:
To find the range and time of flight of the elf, we need to use the equations of motion under the influence of gravity. The range is the horizontal distance covered by the elf and the time of flight is the total time that the elf is in the air.
The initial velocity of the elf in the x-direction (horizontal direction) is 25 m/s and the initial velocity in the y-direction (vertical direction) is 0 m/s, since the elf is thrown horizontally from the top of the iceberg. The acceleration due to gravity is -9.8 m/s^2 in the downward direction.
Using these values, we can find the range and time of flight of the elf using the following equations:
Range:
x = x0 + v0x*t
Where x is the range, x0 is the initial position (in this case, x0 is 0 since the elf is thrown from the top of the iceberg), v0x is the initial velocity in the x-direction (25 m/s), and t is the time of flight.
Time of flight:
y = y0 + v0y*t + (1/2)at^2
Where y is the vertical position of the elf, y0 is the initial position (in this case, y0 is 110 m since the elf is thrown from the top of the iceberg), v0y is the initial velocity in the y-direction (0 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight.
We can solve for t in the second equation and then substitute it into the first equation to find the range.
Solving for t in the second equation:
t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)
Where y is the vertical position of the elf (0 m since the elf lands on the ground), y0 is the initial position (110 m), v0y is the initial velocity in the y-direction (0 m/s), and a is the acceleration due to gravity (-9.8 m/s^2).
Substituting this expression for t into the first equation:
x = x0 + v0x*((-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a))
Plugging in the values:
x = 0 + 25*((-0 + sqrt(0^2 - 4*(-9.8)(110))) / (2(-9.8)))
Simplifying:
x = 25*(sqrt(5832) / -19.6)
x = 25*(sqrt(5832) / -19.6)
x = (25*74.6) / -19.6
x = 1865.4 / -19.6
x = -95.1 m
So, the range of the elf is approximately -95.1 m. This means that the elf lands 95.1 m to the left of the starting point (the top of the iceberg).
The time of flight can be found by solving for t in the second equation:
t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)
Plugging in the values:
t =
Explanation:
What is the best response that shari’s friend could make? she could agree with shari because the pendulum is at the same height and would have the same gravitational potential energy at both positions. she could agree with shari because the pendulum has the same amount of mechanical energy throughout its swing. she could disagree with shari because the pendulum converts kinetic energy into gravitational potential energy, then back into kinetic energy. she could disagree with shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.
The best response that shari’s friend could make was that She could disagree with Shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.
What is the pendulum's greatest potential?The ball is momentarily immobile at the height of the swing. Due to its elevated position above the surface, it possesses the maximum potential energy. The system of the ball on the pendulum string has the same overall quantity of energy at every point in the swing.
The pendulum's energy is continuously transformed from gravitational potential to kinetic, and vice versa. The pendulum on the left swings more quickly than the pendulum on the right because shorter pendulums swing more quickly than larger ones do.
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If stormy weather were approaching, the pressure tendency would probably be ______. answer choices. falling. rising. steady. none of these.
Option A - Falling is the pressure tendency ,If stormy weather were approaching .
Stormy weather, namely when it includes components like dark clouds, strong winds, thunder, lighting, and rain, is defined as weather that has generated storms or that indicates storms are imminent. It's frequently used in sentences that refer to stormy weather. Low pressure causes active weather. As a result of air rising because it is lighter than the air masses around it, the atmosphere becomes unstable. When the air pressure increases, vapour in the condenses, creating clouds and rain, among other things. Both violent storms and active weather, such as wind and rain, are produced by low pressure systems.
Low-pressure areas have relatively thin atmospheres. Inward winds are a factor in these locations. Low-pressure storms are frequently well-organized.
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Please Help me! Please show all work!
Jeremiah the Bullfrog rode a roller coaster around a loop. Being a good friend, he took some measurements for you during his journey. The 1.5kg amphibian noted that at the bottom of the loop, the speed of the roller coaster was 33m/s. You know from the informational poster next to the entrance that the loop has a radius of 22m. How much force did the seat exert on Jeremiah at the bottom of the loop?
74.25 N much force did the seat exert on Jeremiah at the bottom of the loop.
What is centripetal force?This is an acceleration technique. When an item is moving in a circle, it is moving ahead while being turned by a consistent force that is directed inward. The Centripetal Force is the name given to this internal resultant force.
Given that,
Mass (m) = 1.5 kg
speed (v) = 33 m/sec
radius (r) = 22m
As we know,
centripetal force (F) = mv²/r
or, F = [1.5 × (33)²] / 22
or, F = 74.25 N
So, 74.25 N much force the seat exert on Jeremiah at the bottom of the loop.
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where in the universe do we see young galaxies? in the local group in the local supercluster in all regions of space billions of light-years away
The Milky Way is a member of the Laniakea Supercluster, which is a member of the Virgo Supercluster, which is a member of the Local Group galaxy group (which includes more than 54 galaxies).
Are the Local Group galaxies relocating away from us?Does the Local Group grow together with the universe as a whole? (Intermediate) The Local Group of Galaxies (Andromeda, Milky Way, etc.) is moving in the direction of the Local Supercluster.
Where can one find young stars in our galaxy?While the cooler red star predominates the bulge, hot young stars are mostly found in the spiral arms of the disk. The galaxy as a whole undergoes a dramatic change in appearance as we go through the various star populations.
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SOMEONE PLEASE HELP ME!!!
The velocity-time graph for an object is shown. How can the total displacement of the object be determined?
Answer:
Below
Explanation:
The area under the graph will represent the displacement .
Remember displacement = velocity * time
so the total displacement will be Area 1 - Area 2
in an average human, basic life processes require energy to be supplied at a steady rate of 100 w .What daily energyintake, in Calories, is required to maintain these basic processes?This is the minimum daily caloric intake needed to avoidstarvation.
The daily equivalent of 6.27 106 joules is 1500 calories, which the average person consumes daily. This is roughly equivalent to the energy needed to drive a car for 15 minutes.
Even while sleeping, a creature still needs energy. This is because our bodies continue to go through a variety of energy-intensive biological processes when we sleep.
Even when we are asleep, our hearts continue to beat in order to circulate blood throughout the body. Additionally, the heart requires energy to beat. As a result, the heart requires a constant flow of energy to function.
Therefore, 1 watt = 1 joule/second, so 100 w there needs to be 100 joules.
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in bohr’s model, the energy of a photon absorbed or emitted by the electron will be equal to:
in Bohr’s model, the energy of a photon absorbed or emitted by the electron will be equal to "The difference in orbital energies associated with the transition".
The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.
Bohr's model helped to explain how electrons could only change orbits by exchanging or absorbing energy in fixed quanta. For instance, if an electron jumps into an orbit that is one orbit closer to the nucleus, it will have to expel energy equal to the energy difference between the two orbits.
The energy of energy level is connected to the energy photon that an electron absorbs or emits.
∆E = hf, where f is the frequency of radiation received or released during the electronic transition and h is the plank constant
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is there an angle of incidence between 0∘ and 90∘ such that all of the light will be reflected?
A beam of light in the air encounters a transparent block with index of refraction n=1.53. Some of the light is reflected and some is refracted. There will be no such angle of incidence between [tex]$0^{\circ}$[/tex] and [tex]$90^{\circ}$[/tex] such that all of the light will be reflected.
In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the normal, or line perpendicular to the surface at the point of incidence. Any type of wave, including microwave, X-ray, optical, and acoustic, may create a ray.
The refractive index of an optical medium is a dimensionless quantity that indicates how well that medium bends light in optics. The refractive index controls how much light is refracted or twisted when it enters a substance.
[tex]\begin{aligned}\mu & =\frac{1}{\sin c} \\c & =\sin ^{-1}\left(\frac{1}{\mu}\right) \\& =\sin ^{-1}\left(\frac{1}{1.53}\right) \\& =40.83\end{aligned}[/tex]
First condition it should be remembered that if the incident angle is from denser medium to rarer medium at or greater than [tex]$40.33^{\circ}$[/tex], all light will be reflected but in this Question, the condition is the opposite.
Hence, there should not be such an angle.
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The complete question should be:
A beam of light in the air encounters a transparent block with index of refraction n=1.53. Some of the light is reflected and some is refracted.
Is there an angle of incidence between [tex]$0^{\circ}$[/tex] and [tex]$90^{\circ}$[/tex] such that all of the light will be reflected?
(a) Yes, at an angle greater than [tex]50^{\circ}[/tex]
(b) Yes, at an angle less than [tex]50^{\circ}[/tex]
(c) No.
sound waves have a speed of 340 m/s in room-temperature air. what is the wavelength of the sound waves for the musical tone concert a, which has a frequency of 440 hz?
The wavelength of the sound waves for the musical tone concert is 0.772m if frequency of wave is 440Hz.
Wavelength is defined as the distance between two consecutive crest and troughs. Wavelength is measured in meters and it is represented by λ. Frequency is defined as the number of vibrations completed by the wave in per second time. Frequency is measured in Hertz.
We know that for electromagnetic wave, we know that
c=v×λ
where c is the defined as the speed of the light wave
v is defined as the frequency of light wave and
λ is defined as the wavelength of light wave
We have c=340m/sec, v=440Hz and λ=?
So, on putting the values, we get
=>340=440 ˣ λ
=>λ=340/440
=>λ=34/44
=>λ=0.772m
Hence, wavelength of the sound waves is 0.772m
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A 34.5kg tree branch falls off of a cliff for a total of 12.09 s. What was the displacement of the tree branch?
Answer:
Assuming air resistance is neglected and the only force acting on the branch is the acceleration due to gravity, the answer is 716.709768 meters.
Explanation:
Since the initial velocity is 0, the displacement s, is simply written as :
s = (1/2)gt².
where g is the acceleration due to gravity.
if the distance of a galaxy is 5 mpc, what is its recessional velocity if the hubble constant is 70 km/s/mpc?
The distance of galaxy is given as 5Mpc. and the Hubble's constant is 70(km/s)/Mpc.
To find the recessional velocity of the galaxy
Hubble found that the tendency of recessional velocity is to increase with the distance of galaxy, therefore recessional velocity is directly proportional to the distance of the galaxy
The relation between recessional velocity and the distance of the galaxy can be expressed using Hubble's law.
substituting the values we get
V=70 (km/s)/ mpc [tex]\times[/tex]5Mpc
V = 350km,
Therefore the recessional velocity will be 350 km/s.
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Which phrase describes a risk associated with producing energy in a nuclear power plant?
Answer:
Production of wastes needing long-term storage
Explanation:
two identical cylinders, a and b, contain the same type of gas at the same pressure. cylinder a has twice as much gas as cylinder b. which is true?
If both of cylinders contains same type of gas at same pressure, then a)
([tex]T_A < T_B[/tex]). So, correct option is a.
Gas regulation condition for any gas is as per the following .
PV = n×R×T (defined for n moles of gas )
Let the Pressure , volume , temperature and mole of gas in chamber A be P,V
T₁ and 2n . Pressure , volume , temperature and mole in chamber B will be
P , V , T₂ and n.
Applying Gas regulations , we get
For gas in chamber A
PV = 2n R T₁
For gas in chamber B
PV = n R T₂
Likening these conditions , we get
2n R T₁ = n R T₂
2 T₁ = T₂
or we can say that 2[tex]T_A[/tex]=[tex]T_B[/tex]
Hence, option a is correct.
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(Complete question) is:
Two identical cylinders, A and B, contain the same type of gas at the same pressure. Cylinder A has twice as much gas as cylinder B. Which is true? Two identical cylinders, A and B, contain the same type of gas at the same pressure. Cylinder A has twice as much gas as cylinder B. Which is true?
a)TA < TB
b)TA >TB
c) TA = TB
d)Not enough information to make a comparison.
suppose a particle moves back and forth along a straight line with velocity v(t), measured in feet per second, and acceleration a(t). a) what is the meaning of integral 60^120 v(t) dt? b) what is the meaning of integral 60^120 |v(t)| dt? c) what is the meaning of integral 60^120 a(t) dt?
a) In this part of the problem, we are calculating the integral of the velocity function from t = 60 seconds to t = 120 seconds.
b) Next, we have a similar integral. The velocity function is now, however, contained by absolute value bars. Our velocity function will only equal to positive values as a result.
c) The acceleration function is the subject of our last integral.
a) When we integrate a velocity function, we return to the position function. As a result, this integral is determining the particle's displacement by determining the difference in location between these two points.
b) The result of this integration will treat all traveled distances as positive values as well, even if the particle moves backwards. This integral will determine the overall distance travelled during this period, rather than the displacement between 120 and 60 seconds.
c) When we integrate an acceleration function, we return to the velocity function. Thus, this integral will calculate the total change in the velocity between 60 seconds and 120 seconds.
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