Uppoe that a phone i dropped from a light pole 70. 0 meter high. How far will the phone have fallen after 3. 00 econd

In a px orbital, the subscript x denotes the axis along which the orbital is aligned of the electron.

'What is atomic orbital?'

The area closest to an atomic nucleus where an electron is most likely to be found is called an atomic orbital. An atom's orbitals can be classified as either s, p, d, or f orbitals. The Px, Py, and Pz orbitals are three of the p orbitals that exist.

The Px, Py, and Pz orbitals all have two lobes, but the Py orbital has two lobes directed along the y-axis, and the Pz orbital has two lobes oriented along the z-axis. This is the main distinction between the three orbitals. Because of how they are oriented in space, the Px Py and Pz orbitals differ from one another.

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The moment of the force about A will be 14150.97 N-m Force = 200 N

A force's moment is determined by its magnitude and distance from the rotating axis. The moment of a force around a point measures the force's strength (the perpendicular distance of the line of action of the force from the point). The turning effect of a force is known as its moment. The moment of force, sometimes referred to as the torque. A moment must develop because of a force F, which prevents the line of action from passing through the location where the moment is to be taken. If the line of action does not travel through that location, the moment is zero since the magnitude of the moment arm is 0.

[tex]amp; \vec{F}=200\left(-\cos 30^{\circ} \hat{j}+\sin 30 \hat{k}\right) M \\& \vec{F}=200 \cdot\left(\frac{-\sqrt{3} \hat{\imath}+\hat{k}}{2}\right)=100(-\sqrt{3} \hat{\jmath}+\hat{k}) M \\& \overrightarrow{r_A}=-50 \hat{\jmath}, \quad \vec{r}_C=60 \hat{i}+25 \hat{1} \\& \Rightarrow \quad \vec{r}_{C A}=\vec{r}_e-\vec{r}_A=60 \hat{\imath}+755[/tex]

Moment of F about A -

[tex]amp; \vec{M}_A=\vec{\pi} A \times \vec{F}=(60 \hat{+}+75 \hat{1}) \times(100(-\sqrt{3} \gamma+\hat{k}) \\& \vec{M}_A=100\{-\sqrt{3} .60 \hat{k}-60 \hat{\imath}+0+75 \hat{\jmath}\}[/tex]

[tex]\vec{MA}=7500 i-6000 i-6000 \sqrt{3} \hat{N} N-m\\\\\mid \vec{MA}|_A=14150.97 N-m[/tex]

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Answer: The force of kinetic friction is smaller than the maximum force of static friction due to the fact that the coefficient of kinetic friction is less than that of static friction.

When the voltage and resistance is doubled the current will remain constant.

The voltage and resistance are inversely correlated, and the current is directly proportional to both. Any change in voltage will have an equal and opposite effect on current. Therefore, doubling or tripling the voltage will result in doubling or tripling the current.We know that I = V/R where I = current V = voltage and R = resistance such that

Given voltage is doubled so v2 = 2V

and resistance is also doubled so R2= 2R

I2 = V2/R2 = 2V/2R = V/R = I

Hence I2 = I

Therefore the current will remain same when both voltage and resistance are doubled.

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Answer: The answer should be Erosion

Explanation: Erosion removes and transports rock and soil. Additionally, it also moves sediment through water, ice, and wind.

The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.

The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.

Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,

F = (c+v/c-v)f

c = Speed of waves in the medium

u = Speed of the receiver relative to the medium

v = Speed of the source relative to the medium

f = emitted frequency

Our values are given,

Beat frequency = 7Hz

Reflective Doppler frequency = 225+7=232Hz

Putting values,

232 =  (c+v/c-v)225

solving further,

v = 5.286 m/s.

So, the speed of the platform shoud be 5.286m/s.

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The frequency at which it is broadcasting is 875 KHz for a local am radio station broadcasts at an energy of kj/photon

Given,

Energy of a photon = 5.80 x 10-31 kJ x ( 1000 J / 1kJ) = 5.8 x 10-28 J

We know,

E = hv

Here,

"h" is the plank's constant = 6.626 x 10-34 J.s

v = frequency in Hz

Now, rearranging the formula,

v = E / h

Substituting the values,

v = 5.8 x 10-28 J / 6.626 x 10-34 J.s

v = 875340 s-1 or Hz

Now, converting Hz to kHz,

Given, 1kHz = 103 Hz

= 875340 Hz x ( 1 kHz / 103 Hz)

= 875.3 kHz

Frequency = 875 kHz [3S.F]

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Answer:

ALL OF THE ABOVE

Explanation:

A vehicle undergoes acceleration when what three things happen?

If there is acceleration, the velocity will change, either increasing or decreasing. The correct answer is D.

The rate of growth of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object is in motion in a circular track at a steady speed, it is still going to accelerate because its velocity direction changes.

Newton's Second Law states that an object's acceleration is the net result of all force applied to it. Acceleration is measured in meters per second squared.

The formula is given as,

a = Δv / Δt

If acceleration exists, the change of the velocity will be there and it may be increasing or decreasing. Then the correct option is D.

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-144 V is the calculated value. The difference in charge carriers' energy between two places in a circuit is known as the potential difference.

Voltage is another name for potential difference, which is measured in volts (V). A simple measure of how much potential energy is gained or lost per coulomb when it moves from one location to another is the potential difference or voltage.

A = (2, 3) m = 2 I + 3 j

B = (5, 7) m = 5 I + 7 j

Displacement vector: (3 I + 4 j) m = AB = B - A

E = (4 I + 3 j) N/C for the electric field.

V = - E . AB

V = - (4 I + 3 j) . (3 I + 4 j)

V = - (12 + 12) = - 144 V

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Answer:

3×x for both .they did the same amount.

Answer:

2.5 m/s²

Explanation:

F = ma (Newton's 2nd Law)

a = F/m = 3,000 N /  1,200 kg = 2.5 m/s²

A. The original momentum of the fullback is 450 Kg.m/s

B. The impulse imparted on the fullback is 450 Ns

C. The force exerted on the fullback is 900 N

D. The force exerted on the tackler is -900 N

A. How do I determine the original momentum?

The original momentum of the fullback can be obtained as follow:

Momentum = mass × velocity

Momentum of fullback= 90 Kg × 5 m/s

Momentum of fullback = 450 Kg.m/s

B. How do I determine the impulse imparted?

The impulse imparted, can be obtained as shown below:

Impulse = m(v + u) since the came to rest

Impulse = 90 × (0 + 5)

Impulse = 90 × 5

Impulse = 450 Ns

C. How to determine the force exerted on the fullback?

The force exerted on the fullback can be obtain as follow:

Impulse = force × time

450 = Force × 0.5

Divide both sides by 0.5

Force = 450 / 0.5

Force = 900 N

D. How to determine the force exerted on the tackler?

From Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.

Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N

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The torque due to the spring is τ = kx × (l/2).

The torque is a measure of the rotational force that can cause an object to rotate about an axis. It is defined as the product of the magnitude of the force and the perpendicular distance from the line of action of the force to the axis of rotation.

The torque due to a spring is the force of the spring multiplied by the distance from the spring's axis of rotation. This torque is also known as spring torque.

The torque due to the spring is given by:

τ = F × r

Where F is the force exerted by the spring and r is the distance between the pivot point and the point at which the spring is attached to the rod.

Since the spring is assumed to be massless and has a force constant k, then the force is given by:

F = kx

Where x is the displacement of the end of the rod to which the spring is attached.

Since the rod is pivoted at its midpoint, then the distance between the pivot point and the point at which the spring is attached is:

r = l/2

Therefore, the torque due to the spring is given by:

τ = kx × (l/2)

Where k is the force constant of the spring, x is the displacement of the end of the rod to which the spring is attached, and l is the length of the rod.

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Answer:

below

Explanation:

Vertical position = vo t + 1/2 at ^2

    where vo = 20 sin25 =8.45       and    a = -9.81 m/s^2

         Vertical position =  - 4.905 t^2 + 8.45 t

                  max will occur at  t = -b/2a =  -8.45 / (2* -4.905) = .861 s

      Plug in this value to find vertical height

   vertical position =  8.45(.861) - 1/2 (9.81)(.861)^2  = 6.92 m

b)   magnitude when it comes down = magnitude when it went up = 20 m/s

51 units of energy are absorbed by the earth's surface.

23 of the 51 solar radiation units that the Earth's surface absorbs are utilized to evaporate water, resulting in a 23-unit loss of heat. Convection and conduction, which both result in heat loss at the Earth's surface, employ 7 units each. The leftover units of the initial 51 units of solar energy are released as departing infrared radiation, commonly referred to as terrestrial radiation, from the surface of the Earth. However, instead of radiating 21 units (51-23-7 = 21), Earth emits 117 units away from the surface. This occurs because the Earth only receives solar radiation during the day and emits infrared radiation both during the day and at night. Of these 117 units, only 6 are sent into space past Earth's atmosphere. The 111 more units of infrared light that the Earth's surface released into the atmosphere are absorbed by clouds and greenhouse gases.

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For a particular process q=-17 kJ and w=21 kJ. The following statements are true:

(a) Heat flows from the system to the surroundings

(d) The process is exothermic

E=q+w, where q is the amount of heat flowing into or out of the system, is the first law of thermodynamics.

Heat enters the system when q is positive, and heat exits the system when q is negative.

Workflow into or out of the system,

Work is done on the system when w is positive, and the system performs work when w is negative.

E is the system's overall internal energy change.

Q+W = 17 kJ + 21 kJ = + 4 kJ

As a result, the statement in (c) is correct.

Since q is negative in this case at -17 kJ, the process is exothermic, releasing heat from the system generally into the environment.

Thus, the assertion in (d) is true.

As q has a negative value, this indicates that heat is transferred from the system into the environment.

Therefore, the assertion in (a) is true.

Now that w is a positive number, the system is receiving work. Therefore, the assertion in (b) is false.

Since statement b. is untrue, statement e. is also false.

As a result, the assertion in (e) is false.

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The complete question should be:

For a particular process q=-17 kJ and w=21 kJ. Which of the following statements is true?

Heat flows from the system to the surroundings

The system does work on the surroundings

E=+4 KJ

The process is exothermic

None of the above is true

"frequency" describes the amount of variation, over or under the required size, permitted on a piece of machined work.

the wave's frequency as well as its wavelength. The wave moves at the same speed no matter what the medium. However, pace varies depending on the medium. The characteristics of the medium affected how fast these waves traveled.

Note: The speed of sound is unaffected by changes in the wavelength of the sound wave. The amplitude of the sound wave diminishes as the distance from the source grows. The density of the medium affects how quickly sound travels.

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The velocity of canoe will be 27 m/s.

According to the rule of conservation of momentum, absent an external force, the combined momentum of two bodies operating upon one another in an isolated system kept static. As a result, momentum cannot be gained or lost.

Given, mass of the woman, m = 54 kg

mass of canoe, M = 48 kg

velocity of woman, v = 2 m/s

The principle of momentum conservation results in,

pi = pf

 0 = mv - Mu

mv = Mu

 u = mv/M

 u = 54×2/48

 u = 27 m/s

The velocity of canoe will be 27 m/s.

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If the frequency of ultrasound in increased from 0.77 mhz to 1.54 mhz, the propagation speed is remains same.

Since these are not modifications to the characteristics of the medium, changing the frequency or amplitude of the waves will not alter their speed. In a particular medium, the speed of propagation is constant; only the wavelength varies as the frequency does. Your physical, emotional, and mental bodies feel lighter as your energy or vibration frequency rises. More inner strength, clarity, tranquility, love, and joy are felt by you. Your physical body experiences little or no pain or suffering, and you can manage your emotions with ease.

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Answer:

The players feel equal force against one another.

Explanation:

This is known from Newton's Third Law of Motion which states that for every action/force there is an equal and opposite reaction/force. Therefore, even if one player is larger, the force exerted on each player from the other is the same.

(a). A circuit is just a path that ends and begins the same vertex, hence the yes answer. (b). In a graph, a route is a series of nearby sides who cross at the same vertices.

In electronics, a circuit is a completely circular conduit through which electricity travels. A simple circuit comprises a current provider, conductors, and a demand. The term "circuit" refers generally to any ongoing path for the transmission of energy, information, or a signal.

(a). Any method of moving over the graph's edges is a route. There is no restriction on the beginning or ending vertices, edges, etc. A path is any feasible path that connects two vertices.

(b). In a cycle, the start and end vertices are the same. As a result, a route can be a cycle if its start and end vertices are similar and a cycle is established during traversal.

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The potential energy decreases, converted to kinetic energy. velocity is increasing and potential energy is decreasing.

velocity is a term that describes the speed and direction of a point's motion. For example, a circular path's direction is always perpendicular to a lines from the point to the circle's center. A point always travels in a position that is tangential to its path (a radius). An object's ultimate velocity can be expressed as: v = u + at, where v is the final velocity. The ultimate velocity of an boody is equivalent to its original velocity with acceleration directly proportional to the displacement it traveled.

Speed is a scalar since it simply has a defined magnitude and no defined direction. A vector quantity with both magnitude and direction is velocity.

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When a skydiver is falling at a constant velocity with a not yet opened parachute, then the main force exerted on the object  gravity.

When a parachutist leaves the plane with the chute not open, then the main force acting is gravity. As speed through the air increases, then the air resistance also increases.

At 'terminal velocity', which is around 200 km/h, air resistance force balances gravitational force and parachutist stops accelerating and falls at constant velocity. When the parachute is open, then air resistance is greater due to the greater surface area.

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The Mass Increase the thrust force and increase the mass of the rocket  between the earth and the rocket .

At full throttle, the net thrust of a rocket motor increases somewhat with altitude because the pressure thrust term increases as atmospheric pressure lowers with height. The rocket accelerates more quickly the faster its fuel is burned. The acceleration increases with decreasing rocket mass.

Similar to the horizontal example, a rocket with more mass will accelerate more slowly, but there is also another result. Because gravity is now forcing the rocket downward rather than up, there is less force pushing the rocket upward as a result.

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When we go 19113 Km above the surface of earth, the weight of the person will become half.

The weight of the person is given by

W = Mg

Where,

M is mass of the person and g is the gravitational acceleration.

The gravitational acceleration of the earth varies with the height from the surface of the earth as,

g' = g(R/(R+H))²

Where,

R is the radius of earth,

g' is the gravitational acceleration at height H,

For g' = g/2,

g/2 = g(R/(R+H))²

1/√2 = (R/(R+H))²

Solving further,

H = 3R

So, when we go to a distance 3R above the surface of earth the weight of the person will become half.

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Explanation:

If you apply a force on a box and push it across a surface, you are doing work on the box. The amount of work done is equal to the force applied multiplied by the distance the box moves in the direction of the force. This means that if you apply a greater force or move the box a greater distance, you will do more work on the box.

Once you let go of the box, the work that you did on the box is no longer being applied, and the box will come to a stop unless there are other forces acting on it (such as gravity or friction). If the box is on a horizontal surface and there is no friction, it will not move at all after you let go, and the work you did on it will be completely converted into kinetic energy (the energy of motion). If the box is on a sloping surface or there is friction, the kinetic energy will be converted into other forms of energy, such as heat, and the box will slow down and eventually stop.

Answer:

1/2 m v^2 = E        conservation of energy

Both will have the same speed.

v = (s2 - s1) / t     holds for both coins

The coin that slides down the frictionless track will take longer to reach the bottom - the speed for both at the bottom will be the same

The percentage of our total energy output is attributable to the thermic effect of food up to 10%.

Decreased thermic effects of food are observed differently in the elderly and may predispose them to fat gain. Increased energy expenditure is very important for weight loss efforts.

Types of vigorous activity that can boost your metabolism include brisk walking 2 miles or biking uphill. Total Energy Expenditure The amount of energy you expend per day includes not only the calories you expend during physical activity but also the calories expended at rest the calories expended when digesting food and heat generation.

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The energy stored by c2 is =0.00144478

As per the details share in the above question are as bellow,

The value of the capacitor is ,c1 = 25µf, c2 = 20µf, c3 = 10µf.

While the potential difference is ∆v0 = 21v.

We have to determine the energy stored by c2?

In order to accomplish labor and to produce heat and light, energy must be transmitted to a body or to a physical system. Energy is the quantitative attribute that does this.

When the capacitors are connected in parallel then,

Ceq'= c2+c3= 20+10=30

When the capacitors are connected in series then

Capacitors in series (1/Ceq)=(1/c1)+(1/ceq')= (1/25)+(1/30)

Ceq=13.63μF

Now Energy is equal to one by two into c into v square,

[tex]E=\frac{1}{2} CV^2[/tex]

Substitute the value in above equation we get,

Energy[tex]=\frac{1}{2} (13.63 \times 10^{-6})\times (212)[/tex]

E=0.00144478

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Note:- The correct question would be as follow,

if c1 = 25µf, c2 = 20µf, c3 = 10µf, and ∆v0 = 21v , determine the energy stored by c2.

Potentially, optical scattering can be employed to create a solids content assessment instrument that is useful for managing and monitoring tailings ponds.

This bench-scale study looked into the best laser wavelengths for real-time in situ use in oil sands tailings in the visible (405, 520, and 658 nm) and near infrared (980, 1310, and 1550 nm) ranges. In comparison to the visible wavelengths, the near infrared wavelengths generally showed greater sensitivity across the full test range. Additionally, oil sands tailings' remaining bitumen has a tendency to absorb visible wavelengths, interfering with the scattering light signals and resulting in unreliable results. The 1550 nm wavelength in particular demonstrated an almost linear sensitivity of the light scattering with the change in solids concentration due to a sufficiently strong water absorption.

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